The length of each side of the square is (2x + 5)² units.
To determine the length of each side of the square, we need to factor the given area expression completely. The area of a square is equal to the square of the length of its side.
Given area expression: 4x² + 20x + 25
To factor this expression, we look for two binomials that multiply together to give the original expression. The first and last terms are perfect squares, which suggests that the expression may be factored as a perfect square binomial.
The perfect square binomial is given by: (a + b)^2 = a² + 2ab + b²
a²= (2x)²= 4x²
b² = (5)² = 25
2ab = 2(2x)(5) = 20x
the factored expression:
4x² + 20x + 25 = (2x + 5)²
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Can someone answer this soon please
Answer:
the last one i think
Step-by-step explanation:
What is the scale factor from ABC to XYZ?
6
scale factor:
new image ÷ original image
Here:
24 ÷ 4 = 618 ÷ 3 = 630 ÷ 5 = 6Answer: A: 6
Step-by-step explanation:
How do you write 652% as a fraction, mixed number, or whole number?
HELP HELP ILL GIVE U KISS
Answer:
I believe your correct! :)
Harper, inc., acquires 40 percent of the outstanding voting stock of kinman company on january 1, 2020, for $334,900 in cash. the book value of kinman's net assets on that date was $625,000, although one of the company's buildings, with a $70,800 carrying amount, was actually worth $135,550. this building had a 10-year remaining life. kinman owned a royalty agreement with a 20-year remaining life that was undervalued by $147,500. kinman sold inventory with an original cost of $77,700 to harper during 2020 at a price of $111,000. harper still held $18,750 (transfer price) of this amount in inventory as of december 31, 2020. these goods are to be sold to outside parties during 2021. kinman reported a $51,800 net loss and a $26,600 other comprehensive loss for 2020. the company still manages to declare and pay a $15,000 cash dividend during the year. during 2021, kinman reported a $57,200 net income and declared and paid a cash dividend of $17,000. it made additional inventory sales of $120,000 to harper during the period. the original cost of the merchandise was $75,000. all but 30 percent of this inventory had been resold to outside parties by the end of the 2021 fiscal year. prepare all journal entries for harper for 2020 and 2021 in connection with this investment. assume that the equity method is applied. (if no entry is required for a transaction/event, select "no journal entry required" in the first account field. do not round intermediate calculations.)
In 2020, Harper, Inc. acquired 40% of the outstanding voting stock of Kinman Company for $334,900 in cash.
The book value of Kinman's net assets was $625,000, but there were certain adjustments needed. One of Kinman's buildings was undervalued by $64,750 ($135,550 - $70,800), and there was an undervaluation of $147,500 for the royalty agreement. Harper also purchased inventory from Kinman for $111,000, out of which $18,750 was still held in inventory by the end of the year. Kinman reported a net loss of $51,800 and other comprehensive loss of $26,600 in 2020, but it still paid a $15,000 cash dividend.
To record these transactions, Harper would make the following journal entries in 2020:
1. To record the investment in Kinman's stock:
Investment in Kinman Company Stock 334,900
Cash 334,900
2. To adjust the building's carrying amount and recognize the related depreciation:
Investment in Kinman Company Stock 64,750
Depreciation Expense 6,475
Accumulated Depreciation 6,475
3. To adjust the undervalued royalty agreement:
Investment in Kinman Company Stock 147,500
Royalty Agreement 147,500
4. To record the purchase of inventory from Kinman:
Inventory 111,000
Investment in Kinman Company Stock 111,000
5. To recognize the equity in Kinman's net loss and comprehensive loss:
Equity in Net Loss 20,720
Equity in Other Comprehensive Loss 10,640
Investment in Kinman Company Stock 31,360
6. To record the receipt of the cash dividend:
Cash 15,000
Dividend Income 15,000
In 2021, Kinman reported a net income of $57,200 and paid a cash dividend of $17,000. Harper purchased additional inventory worth $120,000 from Kinman, out of which 70% ($84,000) was sold to outside parties by year-end. Harper would make the following journal entries in 2021:
1. To recognize the equity in Kinman's net income:
Equity in Net Income 22,880
Investment in Kinman Company Stock 22,880
2. To record the receipt of the cash dividend:
Cash 17,000
Dividend Income 17,000
3. To record the purchase of additional inventory from Kinman:
Inventory 120,000
Investment in Kinman Company Stock 120,000
4. To eliminate the unrealized profit in inventory:
Investment in Kinman Company Stock 8,400
Equity in Net Income 8,400
Overall, these journal entries reflect the investment in Kinman Company, adjustments for undervalued assets, recognition of income or loss, and dividend payments. The equity method is used to account for the investment, where Harper recognizes its share of Kinman's net income or loss and adjusts the investment account accordingly.
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A random variable follows a binomial distribution with a probability
of success equal to 0.66. For a sample size of n = 6, find the
values below.
a. the probability of exactly 4 successes
b. the probability of 5 or more successes
c. the probability of exactly 6 successes
d. the expected value of the random variable
a. The probability of exactly 4 successes is approximately 0.2967.
b. The probability of 5 or more successes is approximately 0.5332.
c. The probability of exactly 6 successes is approximately 0.1399.
d. The expected value of the random variable is 3.96
To solve these problems, we'll use the binomial probability formula:
P(X = k) = C(n, k)× \(p^{k}\)× \((1-p)^{(n-k)}\)
where:
P(X = k) is the probability of getting exactly k successes,
n is the sample size,
p is the probability of success,
C(n, k) is the number of combinations of n items taken k at a time.
Now let's solve each part of the problem:
a. The probability of exactly 4 successes:
P(X = 4) = C(6, 4) × (0.66)⁴ × (1 - 0.66)⁽⁶⁻⁴⁾
C(6, 4) = 6! / (4! × (6 - 4)!) = 6! / (4! × 2!) = (6 × 5) / (2 × 1) = 15
P(X = 4) = 15 × (0.66)⁴ × (0.34)² ≈ 0.2967 (rounded to four decimal places)
b. The probability of 5 or more successes:
P(X ≥ 5) = P(X = 5) + P(X = 6)
P(X = 5) = C(6, 5) × (0.66)⁵ × (1 - 0.66)⁽⁶⁻⁵⁾ = 6 × (0.66)⁵ × (0.34)¹ ≈ 0.3933
P(X = 6) = C(6, 6) × (0.66)⁶ × (1 - 0.66)⁽⁶⁻⁶⁾ = 1 × (0.66)⁶× (0.34)⁰ = 0.1399
P(X ≥ 5) = P(X = 5) + P(X = 6) = 0.3933 + 0.1399 ≈ 0.5332 (rounded to four decimal places)
c. The probability of exactly 6 successes:
P(X = 6) = C(6, 6) × (0.66)⁶ × (1 - 0.66)⁽⁶⁻⁶⁾ = 1 × (0.66)⁶ × (0.34)⁰= 0.1399
d. The expected value of the random variable:
The expected value (mean) of a binomial distribution is given by:
E(X) = n × p
E(X) = 6 × 0.66 = 3.96
Therefore:
a. The probability of exactly 4 successes is approximately 0.2967.
b. The probability of 5 or more successes is approximately 0.5332.
c. The probability of exactly 6 successes is approximately 0.1399.
d. The expected value of the random variable is 3.96
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PLEASE HELP!!
The diagram shows the cross-section ABCD of a sculpture in the shape of
a prism
with perpendicular height 9 cm.
AB = 14 cm, CD = 8cm, AD = 12cm and BC = 10cm
The height of the prism is also 9 cm.
What is the total surface area of the sculpture in cm2?
Type each step of your working on a separate line.
Answer:
99 (cm^2)
Step-by-step explanation:
Perpendicular to the AB segment at points D and C, the graph is divided into two triangles and a rectangle.
The area of the middle rectangle is equal to 8*9=72. The hypotenuse of the right triangle is 10cm, and one of the right sides is 9cm, so the other side is SQRT (10^2-9^2) = SQRT (19).
One side of the left triangle is 9cm long and the other side is 14-8-sqRT (19) = 6-sqRT (19) cm.
Then, add the area of the three parts.
72+9*sqrt(19)/2+9*(6-sqrt(19))/2=99 (cm^2)
Mr. Smith started the school year with 26 students in his class. If x students moved out of his class, which expression represents the number of students left in the class?
The answers:
x + 26
x - 26
26 - x
26 + x
Please help me quickly before 11
Answer:
26-x
Step-by-step explanation:
If he started with 26 learners he lost x. Imagine x was a value of 5. To get the learners left you will have to subtract the numbers he lost from 26
Consider the following regression model: Yit = Xit B + Eit Xit = Zit8 + Vit where yit is a scalar dependent variable for panel unit į at time t; Xit is a 1×1 regressor; Zit is a kx1 vector of variables that are independent of Eit and Vit; Eit and Vit are error terms. The error terms (Eit, Vit)' are i.i.d. with the following distribution: Σε Σεν (Bit) ~ -N (CO). ( E.)). You can use matrix notation and define Y, X, and Z as the vectors/matrices that stack yit, Xit, and Zit, respectively. Assume that Ev,e is non-zero.
a. (15 points) Derive the OLS estimator for ß and its variance.
b. (10 points) Is the OLS estimator for ß consistent? Clearly explain why. c. (30 points) Suggest an estimation procedure (other than two-stage least squares and GMM) which can be used to obtain consistent ß estimates. Clearly explain how this can be done. What can you say about the standard errors obtained from this procedure? [Hint: &; can be re-written as it nvit + rit where n is a parameter and r; is a normally distributed random variable which is independent of v₁.] d. (10 points) What happens to the ß estimates (i.e., is it consistent?) if you estimate y₁ = x; β + ε; by OLS when Σνε = 0 (a zero matrix)?
e. (20 points) Derive the two-stage least squares estimator for B and its variance. f. (15 points) Now, assume that Σv,e = 0 and
Yit = a₁ + xit ß + Eit Xit = Zits + Vit
but a; is correlated with it. Suggest an estimation procedure which would give you a consistent estimate for ß and provide the estimates for ß.
a. The variance of the OLS estimator of β is given by:\($$\frac{1}{\sigma_{\epsilon}^2\sum\limits_{i=1}^{N}\sum\limits_{t=1}^{T}X_{it}^2}$$\)
b. Yes, the OLS estimator of β is consistent.
c. The standard errors obtained from this procedure will be consistent.
d. The OLS estimator will be unbiased and consistent.
e. Two-stage Least Squares (2SLS) Estimator for β
a. OLS Estimator for β and its variance The OLS estimator of β is obtained by minimizing the sum of squared residuals, which is represented by:\($$\hat{\beta}=\frac{\sum\limits_{i=1}^{N}\sum\limits_{t=1}^{T}X_{it}Y_{it}}{\sum\limits_{i=1}^{N}\sum\limits_{t=1}^{T}X_{it}^2}$$\).
The variance of the OLS estimator of β is given by:\($$\frac{1}{\sigma_{\epsilon}^2\sum\limits_{i=1}^{N}\sum\limits_{t=1}^{T}X_{it}^2}$$\)
b. Consistency of OLS Estimator for βYes, the OLS estimator of β is consistent because it satisfies the Gauss-Markov assumptions of OLS. OLS estimator is unbiased, efficient, and has the smallest variance among all the linear unbiased estimators.
c. Estimation Procedure for Consistent β Estimates.
The instrumental variable estimation procedure can be used to obtain consistent β estimates when the errors are correlated with the regressors. It can be done by the following steps:
Re-write the error term as: \($$E_{it} = nZ_{it} + r_{it}$$\), where n is a parameter and r is a normally distributed random variable that is independent of V_1.
Estimate β using the instrumental variable method, where Z is used as an instrument for X in the regression of Y on X. Use 2SLS, GMM or LIML method to estimate β, where Z is used as an instrument for X. The standard errors obtained from this procedure will be consistent.
d. Effect of Estimating y1 = xβ + ε by OLS when Σνε = 0When Σνε = 0, the errors are uncorrelated with the regressors. Thus, the OLS estimator will be unbiased and consistent.
e. Two-stage Least Squares (2SLS) Estimator for β. The 2SLS estimator of β is obtained by: Estimate the reduced form regression of X on Z: \($$X_{it}=\sum_{j=1}^k \phi_jZ_{it}+\nu_{it}$$\) Obtain the predicted values of X, i.e., \($${\hat{X}}_{it}=\sum_{j=1}^k\hat{\phi}_jZ_{it}$$\).
Estimate the first-stage regression of Y on \($\hat{X}$\): \($$Y_{it}=\hat{X}_{it}\hat{\beta}+\eta_{it}$$\) Obtain the predicted values of Y, i.e., \($${\hat{Y}}_{it}=\hat{X}_{it}\hat{\beta}$$\).
Finally, estimate the second-stage regression of Y on X using the predicted values obtained from the first-stage regression: \($$\hat{\beta}=\frac{\sum_{i=1}^N\sum_{t=1}^T\hat{X}_{it}Y_{it}}{\sum_{i=1}^N\sum_{t=1}^T\hat{X}_{it}^2}$$.\)
The variance of the 2SLS estimator is given by:\($$\frac{1}{\sigma_{\epsilon}^2\sum_{i=1}^N\sum_{t=1}^T\hat{X}_{it}^2}$$f\).
Estimation Procedure to obtain Consistent
Estimate for β when Σv,e = 0To obtain consistent estimate for β when Σv,e = 0 and a is correlated with X, we can use the Two-Stage Least Squares (2SLS) method. In this case, the first-stage regression equation will include the instrumental variable Z as well as the correlated variable a. The steps for obtaining the 2SLS estimate of β are as follows:
Step 1: Obtain the predicted values of X using the first-stage regression equation: \($$\hat{X}_{it}=\hat{\phi}_1Z_{it}+\hat{\phi}_2a_{it}$$w\),
here Z is an instrumental variable that is uncorrelated with the errors and a is the correlated variable.
Step 2: Regress Y on the predicted values of X obtained in step 1:\($$Y_{it}=\hat{X}_{it}\hat{\beta}+\eta_{it}$$\)
where η is the error term.
Step 3: Obtain the 2SLS estimate of β: \($$\hat{\beta}=\frac{\sum_{i=1}^N\sum_{t=1}^T\hat{X}_{it}Y_{it}}{\sum_{i=1}^N\sum_{t=1}^T\hat{X}_{it}^2}$$\).
The standard errors obtained from this procedure will be consistent.
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A trip to St. Louis from Atlanta will take 7¾ hours. Assuming you're two-thirds of the way there, how much longer, in hours, will the trip take?
Answer:
5 and 1/6 hours
Step By Step Explanation:
Find the measure of the arc. C D 146 B F E A DE=?
In the given diagram, the measure of arc DE, mDE, is 90°
Calculating the measure of an arcFrom the question, we are to find the measure of the given arc.
The angle measure of an arc is the angle subtended by the arc at the center of the circle.
From the given diagram, we are to determine the measure of arc DE.
In the given diagram, we can observe that the angle subtended by arc DE is a right angle. That is, the measure of arc DE is a right angle.
The measure of a right angle is 90°.
Hence, the measure of arc DE is 90°
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given the function f(x) = -2(x+4)+5 which of the following is the graphical representation
Answer:
The solution of the equation is f(x)=-2x+3. Go into desmos graphing calculator and there is your answer.
Step-by-step explanation:
Hope this helps!
The graphical representation of f(x) = - 2(x + 4) + 5 is plotted. The slope of the line is -2 and y - intercept is -3.
What is the general equation of a straight line?The general equation of a straight line is -
y = mx + c
where -
m is the slope of line
c is the y - intercept
Given is a function → f(x) = - 2(x + 4) + 5
In order to plot the graph of this function, we will simplify the expression.
f(x) = - 2(x + 4) + 5
f(x) = -2x - 8 + 5
f(x) = -2x - 3
f(x) = (-2)x + (-3)
Now, we can plot this function on graph. Its slope will be -2 and y - intercept will be -3. Refer to the graph attached.
Therefore, the graphical representation of f(x) = - 2(x + 4) + 5 is plotted. The slope of the line is -2 and y - intercept is -3.
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(3x + 5.3) + (7 - 1.5x) =
Answer: 1.5x + 12.3
Step-by-step explanation:
(3x + 5.3) + (7 - 1.5x)
Since this is not multiplication, try arranging the equation so like terms are together.
3x - 1.5x + 5.3 + 7 =
Combine like terms by adding or subtracting.
3x - 1.5x + 5.3 + 7 = 1.5x + 12.3
can someone help me with these 3 questions ASAP
Answer:
1. x=20 so 2x=40 3x=60 4x=80
2. I don't know
3. x=42 180-45-93=42
Find the Dy/Dx of y=7/x using first principle
By using first principle, the value of Dy/Dx is,
⇒ Dy/Dx = - 7 / x²
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
We have to given that;
The expression is,
⇒ y = 7 / x
Now, Differentiate the function with respect to x, we get;
⇒ y = 7 / x
⇒ Dy/ Dx = D / Dx (7 / x)
= 7 D/Dx (1/x)
= 7 (- 1 × x⁻¹⁻¹ )
= 7 (- x⁻²)
= - 7 / x²
⇒ Dy/Dx = - 7 / x²
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Which technique most clearly minimizes the likelihood that any outcome differences between the experimental and control conditions can be attributed to age or personality differences in research participants?.
The technique that most clearly minimizes the likelihood that any outcome differences between the experimental and control groups is e. random assignment.
What is random assignment?A methodology used to divide research participants into two groups—the treatment group, also known as the experimental group, and the control group—by randomization is known as random assignment, also known as random placement.
Every research volunteer has an equal chance of being assigned to any of the groups thanks to this randomization mechanism.
In studies, random assignment is a method used to divide participants into different research groups with similar characteristics so that the groups are equal at the start of the investigation.
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Which technique most clearly minimizes the likelihood that any outcome differences between the experimental and control groups can be attributed to age or personality differences in research participants?
a. the double-blind procedure
b. statistical measurement
c. replication
d. operational definitions
e. random assignment
Find the geometric mean of 24 and 45.
The geometric mean of 24 and 45 is equal to 32.86.
Given the following data:
Numbers = 24 and 45.What is geometric mean?Geometric mean is an average value that is used to indicate the central tendency of a data set containing a group of numbers, especially by determining the product of their values.
Mathematically, geometric mean is given by this formula:
\(G=\sqrt[n]{x_1x_2...x_n}\)
Substituting the given parameters into the formula, we have;
\(G = \sqrt[2]{24 \times 45} \\\\G = \sqrt{1080}\)
G = 32.86.
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An initial investment of $1000 is appreciated for 2 years in an account that earns 9% interest,compounded annually. Find the amount of money in the account at the end of the period. A)$1090. 00B)$1295. 03C)$1188. 10D)$188. 1
Answer:
Letter C: 1188
Step-by-step explanation:
$1000 plus the interest earned the first year = 1000 x 9%
Calculated like this $1000 x ( 1.09 interest) = 1090
then
that amount 1090 plus the interest earned the second year on that already compounded amount:
1090 x 9% interest =
Calculated like this 1090 x ( 1.09 interest) = 1188.1
rounding down to 1188 to match the answers
Patty buys a new car and gets it appraised every few years. After owning the car for 3 years, it’s value is $15,000. After owning the car for 5 years, it’s value is $9,000. What is the constant of proportionality in this inverse variation?
Answer: $3,000 per year
Step-by-step explanation: 15,000 divided by 9,000 is 6,000, 5 minus 3 is 2 6,000 divided by 2 equals 3,000.
What is the correct slope-intercept form of the equation y+4=2(x−3)?
Answer:
y = 2x - 10
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
y + 4 = 2(x - 3) ← distribute the parenthesis
y + 4 = 2x - 6 ( subtract 4 from both sides )
y = 2x - 10 ← in slope- intercept form
find the value of y. round to the nearest tenth, if necessary
Answer:
8.9
Step-by-step explanation:
according to the Pythagorean theorem:
c^2=a^2+b^2
Where c is the longest side, the hypotenuse, and a and b are the sides.
Substitute the numbers in:
12^2=8^2+y^2
144=64+y^2
144-64=y^2
80=y^2
Y= square root of 80
Y= 8.944
After rounding to the nearest tenth, that would be 8.9
Which is 0.54 delete converted to a simplified fraction
As a fraction it would be 54/100
Alessia uses her bank card to buy lunch 3 times. Each time she buys lunch, it costs $12.50. She then deposits $30 in her bank account. What is the change in her bank balance in dollars as a result of these transactions?
Answer: She has a $-7.50 balance
Step-by-step explanation: A = 3*12.5
A= 37.5
37.5-30= -7.5
Answer:
Her balance will be $7.50 in the red.
Step-by-step explanation:
expenses: (12.50)*3 = 37.50
funds added: 30
$30 - $37.50 = -$7.50
a spinner can land on red, blue or green.
after 350 spins
relative frequency of red - 0.18
relative frequency of blue - 0.62
work out the number of times the spinner landed on green.
To determine the number of times the spinner landed on green, we need to calculate the relative frequency of green and subtract it from 1 since the sum of relative frequencies for all possible outcomes should equal 1.
Let's denote the number of times the spinner landed on green as "x." We know that the relative frequency of red is 0.18 and the relative frequency of blue is 0.62. The relative frequency of green can be calculated as:
Relative frequency of green = 1 - (Relative frequency of red + Relative frequency of blue)
Relative frequency of green = 1 - (0.18 + 0.62) Relative frequency of green = 1 - 0.80 Relative frequency of green = 0.20
Since relative frequency is a proportion, we can calculate the number of times the spinner landed on green by multiplying the relative frequency by the total number of spins:
Number of times spinner landed on green = Relative frequency of green * Total number of spins
Number of times spinner landed on green = 0.20 * 350 Number of times spinner landed on green = 70
Therefore, the spinner landed on green 70 times.
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One of the altitudes of the parallelogram shown is the square root of 22.5. What is the other altitude?
Answer:
Step-by-step explanation:
please help omg ♀️ !!
Answer:
first blank: 50-10=40
second blank: 50-20=30
third blank: 50-25=25
Step-by-step explanation:
hope this helps!
Answer:
Step-by-step explanation:
40 30 25
10 20 25
40 30 25
find all the expressions that are equal to 4*10^-3
Answer:
Attached to this answer are some of the ways you could rewrite \(4*10^{-3}\)
d. scatter plot QUESTION 23 A chart that is recommended as an alternative to a pie chart is a a. stacked column chart. b. line chart. c. bar chart. d. box plot. QUESTION 24 A data visualization tool that updates in real time and gives multiple outputs is called a. a data dashboard. b. the GIS.
A chart that is recommended as an alternative to a pie chart is a - stacked column chart. A chart that is recommended as an alternative to a pie chart is a stacked column chart. Question 24: A data visualization tool that updates in real time and gives multiple outputs is called - a data dashboard.
A data visualization tool that updates in real time and gives multiple outputs is called a data dashboard. What is a scatter plot? A scatter plot is a type of diagram used to display two variables on a two-dimensional plot. The positioning of data points on a scatter plot graphically depicts the correlation between the two variables. To construct a scatter plot, two variables (independent and dependent variables) are plotted on a graph.
The independent variable is plotted on the horizontal (x) axis and the dependent variable is plotted on the vertical (y) axis. A point is plotted for each pair of values, and the pattern of the points suggests a relationship between the two variables.A scatter plot is useful in displaying the correlation between two variables. The correlation is positive if the points are in an upward direction. The correlation is negative if the points are in a downward direction. A lack of correlation, or random points, is suggested by a scatter plot with no apparent pattern.
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The area of a parallelogram is 64 square feet. If the base is 10 square feet long, what is the height?
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
Area of parallelogram :
\(base \times height\)\(10 \times h = 64\)\(h = \dfrac{64}{10} \)\(h = 6.4\)Height of a parallelogram is 6.4 feet
.To Address − Laplace Transform Solution of the Wave Equation
A. Using the fact that
L = {d²u/dx² }=d²/dx² L{u}
show that U(x, s) satisfies the equation
s^2U(x, s) = α^2 d²u/dx² 0 < x < [infinity]
By utilizing the Laplace transform and the fact that L{d²u/dx²} = s²U(x, s) - su(0) - u'(0), we have shown that U(x, s) satisfies the equation ^2U(x, s) = α²d²u/dx².
To address the equation − Laplace Transform Solution of the Wave Equation, we start with the fact that the Laplace transform of the second derivative of a function u(x) with respect to x is given by L{d²u/dx²} = s²U(x, s) - su(0) - u'(0), where U(x, s) is the Laplace transform of u(x).
Now, let's apply this fact to the equation α²(d²u/dx²) = 0. By taking the Laplace transform of both sides, we have α²L{d²u/dx²} = 0. Using the property mentioned above, this simplifies to α²(s²U(x, s) - su(0) - u'(0)) = 0.
From this equation, we can see that α²s²U(x, s) - α²su(0) - α²u'(0) = 0. Rearranging terms, we obtain α²s²U(x, s) = α²su(0) + α²u'(0).
This equation shows that U(x, s) satisfies the equation s²U(x, s) = α²su(0) + α²u'(0), which is equivalent to ^2U(x, s) = α²d²u/dx².
In summary, by utilizing the Laplace transform and the fact that L{d²u/dx²} = s²U(x, s) - su(0) - u'(0), we have shown that U(x, s) satisfies the equation ^2U(x, s) = α²d²u/dx².
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