The author says “this is equivalent to taking a long shower every day for two-and- a half weeks” to

a Chevy camera engine exerts 650 hp to move the car. then  4.8 × 10⁵ Watt.of power does the engine exert .

Power is the rate of doing work. Power is also defined as work divided by time. i.e. Power = Work ÷ Time. Its SI unit is Watt denoted by letter W. Watt(W) means J/s or J.s-1. Something makes work in less time, it means it has more power. Work is Force times Displacement. Dimension of Power is [M¹ L² T⁻³].

Just multiply the horsepower with 745.7 that will convert into watt.

Watt =  650 hp × 745.7  = 4.8 × 10⁵ watt.

a Chevy camera engine exerts 650 hp to move the car. then  4.8 × 10⁵ Watt.of power does the engine exert.

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Question :-

Answer :-

\( \rule {180pt} {2pt} \)

Given :-

To Find :-

Solution :-

As per the provided information in the given question, we have been given that the Time take by the people to push the car is 3 seconds . The Force required is 200 N . And, we have been asked to calculate the Impulse .

For calculating the Impulse , we will use the Formula :-

Therefore , by Substituting the given values in the above Formula :-

⇒ Impulse = Force × Time

⇒ Impulse = 200 × 3

⇒ Impulse = 600

Hence :-

\( \underline {\rule {180pt} {4pt}} \)

Answer:

answer should be false

Answer:4

Explanation:

Trust me I'm a student

The rotational speed increases when the skater pulls her arms in because the moment of inertia decreases.

\(L = I \omega\)

Where,

\(L\) - Angular momentum

\(I\) - moment of inertia = \(mr^2\)

\(\omega\)- angular velocity

From the equation, the angular velocity of the body is inversely proportional to the moment of inertia.

When the skater pulls her arms in, the moment of inertia decrease due to a decrease in radius,

Therefore, the rotational speed increases when the skater pulls her arms in because the moment of inertia decreases.

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Answer:

Astronauts who are orbiting the Earth often experience sensations of weightlessness. These sensations experienced by orbiting astronauts are the same sensations experienced by anyone who has been temporarily suspended above the seat on an amusement park ride. Not only are the sensations the same (for astronauts and roller coaster riders), but the causes of those sensations of weightlessness are also the same. Unfortunately however, many people have difficulty understanding the causes of weightlessness.

The highest point on a wave is the crest

Number 3

Explanation:

Since the gravity is pushing down on potatoes and the bag because of weight, the force is balanced. The gravity makes the bag point downward.

Radio waves are more extensively utilized in communication than other electromagnetic waves, owing to their desirable propagation properties caused by their large wavelength.

The radio signal is a very fast electronic current moving back and forth. This field is radiated outward by a transmitter via an antenna; a receiver picks up the field and translates it to the sounds heard through the radio.

FM is an abbreviation for frequency modulation, which is a method of encoding an audio signal on the carrier frequency. The 88-108 MHz band is used by FM full power, low power, translator, and booster stations.

Radio waves can refract from the ionosphere at medium and shortwave frequencies (MF and HF bands).

This means that medium and short radio waves sent at an angle into the sky can be refracted back to Earth at great distances further than the horizon, even across continents.

Thus, this property enables a radio station signal to travel far from the source.

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The property that enables signal over great distance to travel from the source is radiation. Radiation is a mode of energy transfer through vacuum.

Wave are  disturbance in air or the propagation of energy. Electromagnetic waves are waves with an electric field associated with a magnetic field. Electromagnetic waves does not need a medium to propagate.

Practical radio transmission systems employ a variety of propagation types. Radio waves that propagate along a straight path from the transmitting antenna to the receiving antenna are said to be line-of-sight radio waves.

Medium-distance radio transmission, including that used by cell phones, cordless phones, walkie-talkies, wireless networks, FM radio, television broadcasting, radar, and satellite communication, is carried out using line of sight transmission.

Line-of-sight transmission on Earth's surface is only possible up to the height of the transmitting and receiving antennas, which is determined by the distance to the visual horizon.

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Answer:

Use the method on the image and solve it.

The train is accelerating with an initial velocity of 23 m/s, a final velocity of 190 m/s in the time period of 54 seconds, then the acceleration will be 3.09 m/s².

Velocity is the measurement of a particle's or object's displacement with relation to time. The recognized unit of magnitude for velocity is the meter per second (m/s) (also known as speed).

There are several ways to show a velocity vector's direction, depending on how many dimensions are provided.

The given values in the question are,

Initial velocity, u = 23 m/s

Final velocity, v = 190 m/s and,

Time, t =54 seconds.

By putting the formula of the equation of motion :

v = u + at

190 = 23 + (a)(54)

a = 167/54

a = 3.09 m/s².

Hence, the acceleration of the train is equal to 3.09 m/s².

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The required mechanical energy used to move this book is calculated by the summation of kinetic energy and potential energy.

Mechanical energy M.E is constant in a system that has only gravitational forces or in an otherwise idealised system.

Given that, the method for calculating kinetic energy K.E is,

K.E = 1/2 × m × v²

where,

m is mass

v is velocity

Potential energy P.E is given as mass times g times height, with g as a constant 9.8 m/s².

P.E = m × g × h

where,

m is mass

g is gravity

h is height

Potential and kinetic energies combine to form mechanical energy.

So, mathematically,

M.E = K.E + P.E

"M.E = 1/2 × m × v² + m × g × h"

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Answer:

a

Explanation:

Answer:

C

Explanation:

C

A pendulum's period is defined as the length of time it takes to complete one full oscillation, or the time it takes to swing back and forth from its starting point and then return to it.

A weight or bob suspended from a fixed position by a string, rod, or wire constitutes a pendulum, a basic mechanical device. The force of gravity will cause the weight to swing back and forth when it is moved from its resting position. Because to their very predictable and precise period, pendulums are frequently used in clocks to keep time. In physics experiments, pendulums have also been used to investigate matters like the characteristics of waves and the influence of gravity. They have contributed significantly to the advancement of science and engineering and are a prime example of simple harmonic motion.

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The ways in which Titan resembles early Earth are It has a thick atmosphere. It is rich in organic compounds. Its atmosphere is mostly nitrogen.

Titan, the largest moon of Saturn, shares several characteristics with early Earth. Firstly, Titan has a thick atmosphere, similar to Earth's early atmosphere. This atmosphere, primarily composed of nitrogen, is of particular interest in studying the evolution of planetary atmospheres. Secondly, Titan is rich in organic compounds, including hydrocarbons and complex organic molecules. This resemblance to early Earth suggests the potential for prebiotic chemistry and the formation of organic compounds that are essential for the emergence of life. Lastly, although Titan's surface differs significantly from Earth's, it does possess terrain features, such as lakes, rivers, and mountains, which provide some similarities to Earth's landscape.

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Wind is the most frequent cause of waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.

A wave exists an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

Wind is the most frequent cause of waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.

Waves are oscillations or vibrations that revolve around a resting point. As an illustration, sound waves force air molecules to oscillate. Water molecules vibrate up and down due to ripples.

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Answer:

Potential energy is energy that is stored in an object or system. It remains unaffected by the environment outside of the object or system. Kinetic energy is the energy of an object or a system's particles in motion.

Explanation:

Answer:

It’s D

Explanation:

Because I took the USA test prep and got it right

The bond with the highest bond dissociation energy is the triple bond between two nitrogen atoms (N≡N). The bond dissociation energy is the energy required to break a bond between two atoms and is a measure of the bond strength.

Since there are three covalent bonds involved, sharing a total of six electrons between the two atoms, the triple bond formed by two nitrogen atoms is extremely strong. The BDE for the NN bond is around 945 kJ/mol, which is much higher than the BDE for the majority of other covalent bonds, such as the double bond (N=N) between two nitrogen atoms and the single bond (N-N) between two nitrogen atoms, both of which have BDEs of roughly 418 kJ/mol. One way to measure how strong a chemical bond A–B is is by examining at the bond-dissociation energy. It may be described as the typical enthalpy shift that occurs when A and B, which are typically radical species, are split apart by homolysis.

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The moment which is corresponds to the maximum kinetic energy of the system: Part A = A, Part B = A and Part C = moving toward equilibrium, Part D = C, Part E = C, Part F = D, and Part G = 3/8kA².

For part A: The maximum PE is when the spring is fully compressed. D might look like the correct answer, but actually, A is when the spring is at amplitude. Even though it’s stretched, that still counts as compression: A

For part B: When PE is maximized, KE is minimized, so the correct answer is the same as from Part A: A

For part C: Kinetic Energy is maximized when PE is minimized. PE is most prominent at amplitude, and KE is most prominent at equilibrium. So choice F is correct: F. moving toward equilibrium.

For part D: KE is greatest at equilibrium: C

For part E: Minimum PE is when KE is greatest, i.e. at equilibrium: C

For part F: When U = KE, U = 1/2Umax (this is just a fact, which we won’t bother solving for here). So:

U = 1/2(U)

1/2kx² = 1/2(1/2kA²)

x² = 1/2A²

x = √(1/2A²)

x = A√(2)/2

if it isn’t obvious where the √(2)/2 came from, use 2/4 for the fraction above instead of 1/2:

x = √((2/4)A²)

x = A√(2)/2

The diagram doesn’t give this as an answer, but it does give -A√(2)/2, which is equivalent: D

For part G: Since total energy = KE + PE and we only have enough information to find PE, we can work backwards by first finding the maximum PE and then subtracting the PE at point B.

Maximum PE:

PE(max) = 1/2kA²

PE at Point B:

PE(B) = 1/2k(A/2)²

PE(B) = 1/2k(A²/4)

PE(B) = 1/8k(A²)

Now find the difference between the Potential energies, and that difference must be kinetic energy since there is no friction:

KE(B) = PE(max) – PE(B)

KE(B) = 1/2kA² – 1/8k(A²)

KE(B) = 3/8kA²

Complete Question:

Consider a harmonic oscillator at four different moments, labelled A, B, C, and D, as shown in the figure. Assume that the force constant k, the mass of the block, m, and the amplitude of vibrations, A, are given. Answer the following questions:

Part A

Which moment corresponds to the maximum potential energy of the system?

A

B

C

D

Part B

Which moment corresponds to the minimum kinetic energy of the system?

A

B

C

D

Part C

Consider the block in the process of oscillating. If the kinetic energy of the block is increasing, the block must be:

A. at the equilibrium position.

B. at the amplitude displacement.

C. moving to the right.

D. moving to the left.

E. moving away from equilibrium.

F. moving toward equilibrium.

Part D

Which moment corresponds to the maximum kinetic energy of the system?

A

B

C

D

Part E

Which moment corresponds to the minimum potential energy of the system?

A

B

C

D

Part F

At which moment is K = U?

A

B

C

D

Part G

Find the kinetic energy K of the block at the moment labelled B.

express your answer in terms of k and A."--

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Answer:

Explanation:

ave speed is always (frequency) x (wavelength)

Speed  =  (450 /sec) x (0.52 m)

=      234 m/sec .

Answer:

Golf ball (\(0.1\; {\rm kg}\)): approximately \((-19.506)\; {\rm m\cdot s^{-1}}\) (backwards).

Steel ball (\(8\; {\rm kg}\)): approximately \(0.49383\; {\rm m\cdot s^{-1}}\) (forward.)

Explanation:

Apply unit conversion and ensure that the unit of all mass are in kilograms: \(100\; {\rm g} = 0.1\; {\rm kg}\).

In an elastic collision, both momentum \(p = m\, v\) and kinetic energy \(\text{KE} = (1/2)\, m\, v^{2}\) are conserved. Momentum of the two balls before the collision are:

Hence, the total momentum of the two balls was \(2\; {\rm kg \cdot m\cdot s^{-1}}\) before the collision and (by conservation) will still be \(2\; {\rm kg \cdot m\cdot s^{-1}}\!\) after the collision.

Kinetic energy of the two balls before the collision are:

Thus, the total kinetic energy of the two balls will be \(200\; {\rm kg \cdot m^{2} \cdot s^{-2}}\) before and after the collision.

Let \(m_{a}\) and \(v_{a}\) denote the mass and velocity of the golf ball after collision; \(m_{a} = 0.1\; {\rm kg}\).

Let \(m_{b}\) and \(v_{b}\) denote the mass and velocity of the steel ball after collision; \(m_{b} = 8\; {\rm kg}\).

Total momentum after the collision shall be \(2\; {\rm kg \cdot m\cdot s^{-1}}\!\). Thus:
\(m_{a}\, v_{a} + m_{b}\, v_{b} = 2\; {\rm kg \cdot m\cdot s^{-1}}\).

Total kinetic energy after the collision shall be \(200\; {\rm kg \cdot m^{2} \cdot s^{-2}}\). Thus:
\(\displaystyle \frac{1}{2} \, m_{a}\, v_{a} + \frac{1}{2}m_{b}\, v_{b} = 200\; {\rm kg \cdot m^{2}\cdot s^{-2}}\).

Assume that the unit of \(v_{a}\) and \(v_{b}\) are both "meters per second" (\({\rm m\cdot s^{-1}}\).) Combine and solve this system of two equations and two variables:

\(\left\lbrace\begin{aligned}&0.1\, v_{a} + 8\; v_{b} = 2 \\ &\frac{1}{2}\, {v_{a}}^{2} + 4\, {v_{b}}^{2} = 200\end{aligned}\right.\).

Rewrite the first equation to obtain \(v_{a} = 20 - 80\, v_{b}\). Substitute this equation into the second one to eliminate \(v_{a}\):

\(\displaystyle \frac{1}{2}\, (20 - 80\, v_{b})^{2} + 4\, v_{b}^{2} = 200\).

Solve this equation for \(v_{b}\):

\(324\, {v_{b}}^{2} - 160\, v_{b} = 0\).

There are two solutions to this quadratic equation: \((40 / 81)\) and \(0\). Note that the velocity of the steel ball must be non-zero right after the collision. Hence, \(v_{b} \ne 0\). Therefore, the only possible value for \(v_{b}\) will be \((40 / 81)\!\), which is approximately \(0.49383\; {\rm m\cdot s^{-1}}\).

Substitute \(v_{b} = (40 / 81)\) back into the first equation of the system and solve for \(v_{a}\): \(v_{a} = 20 - 80\, v_{b} \approx (-19.506)\; {\rm m\cdot s^{-1}}\). Note that the velocity of the golf ball \(v_{a}\!\) is negative since the golf ball is travelling backwards, opposite to its initial direction of motion.

In other words, the velocity right after collision will be approximately \((-19.506)\; {\rm m\cdot s^{-1}}\) (backwards) for the golf ball and approximately \(0.49383\; {\rm m\cdot s^{-1}}\) (forwards) for the steel ball.

Answer:

the result of raising the temperature of the room in which a low-pressure chiller is located is a

Faster Refrigerant Recovery

On increasing the temperature, the pressure of chiller will increase, causing the blow of hot air in the condenser, which is quite harmful for mechanism of machine.

The given problem is based on the effect of raising temperature on low-pressure chiller.

Thus, we can conclude that on increasing the temperature, the pressure of chiller will increase, causing the blow of hot air in the condenser, which is quite harmful for mechanism of machine.

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Magnesium (Mg) has a higher atomic mass than the element sodium (Na). The correct option is B.

The periodic table arranges elements based on their atomic number, which is the number of protons in the nucleus of an atom of that element. The periodic table is arranged in such a way that elements with similar chemical and physical properties are placed in the same group or column.

Magnesium (Mg) has an atomic number of 12, while sodium (Na) has an atomic number of 11.

Option A is not true because Be has a lower atomic number and atomic mass than Mg.

Option C is not true because Ca has a higher atomic number and atomic mass than Mg.

Option D is not true because only option B is true.

Therefore, option B is true because Mg has a higher atomic number and thus a higher atomic mass than Na.

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The total energy of the system is 0.4 Joules.

To find the total energy of the system, we first need to determine the amplitude (A) and angular frequency (ω) of the simple harmonic motion. From the given equation, x = (0.20m)sin[(2π/2.0s)t], we can see that A = 0.20m and ω = (2π/2.0s).

The total energy of a system undergoing simple harmonic motion can be found using the formula E = (1/2)kA², where k is the spring constant. We can determine k from ω using the formula ω = √(k/m), where m is the mass of the cart. Plugging in the values, k = ω²m = (2π/2.0s)²(2.0 kg) = 39.478 N/m. Finally, we can calculate the total energy, E = (1/2)(39.478 N/m)(0.20m)² = 0.4 Joules.

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Answer:

c

Explanation:

The position vs. time graph of an object with constant acceleration is a parabolic curve. The curvature is upward for positive acceleration and downward for negative accelerations.

Answer:

C

Explanation:

The relationship between distance and acceleration is dependent of the square of the time the unit is accelerating:  (1/2)*a*t^2, where a is the acceleration and t is the time.  Since the time is squared, and it falls on the x axis, each increse in time produces a squared impact on distance.

Answer:

Look at the mirror from the positive axis and  suppose the incident ray is at angle at 40 from the y-axis

Incident ray at 50 deg

reflected ray at 130 deg

total angle of deflection = 130 - 50 = 80 deg

Now rotate the mirror by 20 deg

incident ray at 30 deg

reflected ray at 150 deg    (angle of incidence must equal angle of reflection)

total angle of deflection = 150 - 30 = 120 deg

the difference between 2 reflected rays = 120 - 80 = 40 deg

So if you increase (decrease) the incident angle the reflected ray will  be increased by twice the angle of rotation of the mirror - or the perpendicular to the mirror increases by X degrees the angles of incidence and reflection will each increase by X deg

Once installed, backward-curved centrifugal fans can significantly reduce your energy expenditures since they have a high static efficiency that is uncommon for other centrifugal fans.

In comparison to the backward curved impeller, the forward curved impeller is significantly quieter and, because of the increased number of blades, produces a noise spectrum with a much wider bandwidth and, as a result, lesser energy in any region of the spectrum.

The cylindrical design, numerous sizable curved blades, and conical input nozzle of a backward curved centrifugal fan are its distinguishing features. At high pressure, these centrifugal fans offer excellent cooling.

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Answer: 1500 seconds

Explanation:

E = 97.5 kJ = 97500 J

P = 65 W

t = ?

t = 97500/65

t = 1500 sec

Answer: Fourteenth Amendment,

Explanation:

No Person shall be c. . . ... Fourteenth Amedement

Section 1: All persons born or naturalized in the United States, and subject to the jurisdiction thereof, are citizens of the United States and of the State wherein they reside....

Answer:

\(\boxed {\boxed {\sf 50,000 \ Newtons }}\)

Explanation:

Force can be found by multiplying the mass by the acceleration.

\(F=m*a\)

The mass of the car is 5,000 kilograms and it's acceleration is 10 meters per square second.

\(m= 5,000 \ kg \\a= 10 \ m/s^2\)

Substitute the values into the formula.

\(F= 5,000 \ kg * 10 \ m/s^2\)

Multiply.

\(F= 50,000 \ kg*m/s^2\)

\(F= 50,000 \ N\)

A net force of 50,000 Newtons is required to accelerate a 5,000 kilogram car at 10 meters per square second.