The density of mercury is 13. 6 g/cm³

Calculate the mass of :

a) 1 cm³ of mercury

b) 10 cm³ of mercury

Answers

Answer 1
Density=mass/volume
Mass=density*volume

a)Mass=13.6 g
b)Mass=136 g

Hope this helps :)
Answer 2

1). The mass of 1 cm³ of mercury is 13.6 g.

2). The mass of 10 cm³ of mercury is 136 g.

1) The mass of 1 cm³ of mercury can be calculated using the density formula:

density = mass / volume

Rearranging the formula to solve for mass, we get:

mass = density x volume

Plugging in the values:

density = 13.6 g/cm³

volume = 1 cm³

mass = 13.6 g/cm³ x 1 cm³

mass = 13.6 g

b) Similarly, to find the mass of 10 cm³ of mercury, we can use the same formula:

mass = density x volume

Plugging in the values:

density = 13.6 g/cm³

volume = 10 cm³

mass = 13.6 g/cm³ x 10 cm³

mass = 136 g

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Related Questions

The ____ is a line drawn at a right angle to a barrier. a. normal c. node b. ray d. wave front

Answers

Answer:

a. normal

Explanation:

In the field of physics the normal is a line drawn at a right angle to a barrier. In other words the normal line is the line that is drawn perpendicular (right angle, 90 degrees) to the reflective surface of a mirror, or the particular boundary in which refraction occurs at the point of incidence of a light ray. This can be seen in the picture attached below.

The ____ is a line drawn at a right angle to a barrier. a.normalc. node b.ray d. wave front

Why does an ice cube melt in your hand? Question 3 options: The ice remains in a solid state even though heat is applied The temperature of the ice is greater than the temperature of your hand Sound energy creates vibrations which make the ice melt Heat is transferred from your hand to the ice making it melt

Answers

Answer:

3rd choice

Explanation:

heat is transfered causing it to melt

Answer:

C

Explanation:

A force of 10 pounds acts north and a force of 20 pounds acts west. Find the resultant force

Answers

Answer:

oi

Explanation:

ilva is standing a few feet away from boiling water, and she feels the heat from the boiling water and the stove. what term describes this transfer of thermal energy?

Answers

The transfer of thermal energy that Ilva is experiencing is known as radiation. Radiation is the transfer of heat energy through electromagnetic waves that do not require a medium to travel through. In this scenario, the boiling water and stove are emitting infrared radiation which is absorbed by Ilva's body, causing her to feel the heat. Additionally, convection and conduction are two other methods of transferring thermal energy. Convection is the transfer of heat energy through the movement of fluids, while conduction is the transfer of heat energy through direct contact between two objects. However, in this scenario, radiation is the primary method of thermal energy transfer that Ilva is experiencing.
Ilva is standing a few feet away from boiling water, and she feels the heat from the boiling water and the stove. The term that describes this transfer of thermal energy is "radiation." Radiation is the process through which thermal energy is transferred through electromagnetic waves without the need for direct contact or a medium like air or water. In this scenario, the heat from the boiling water and the stove radiates outwards and reaches Ilva, allowing her to feel the warmth. This form of heat transfer is why you can feel the heat from a fire or a hot object without touching it directly.

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The term that describes the transfer of thermal energy that Ilva feels from the boiling water and the stove is radiation.


Radiation is the transfer of thermal energy through electromagnetic waves. Unlike conduction and convection, radiation does not require a medium (such as a solid, liquid, or gas) to transfer heat. Instead, it can transfer energy through empty space or air.

In Ilva's situation, the heat she feels from the boiling water and the stove is primarily due to the infrared radiation emitted by these hot objects. As the electromagnetic waves reach her, they transfer the thermal energy to her body, making her feel the warmth even though she is standing a few feet away from the heat source.

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If an object has a fast velocity, the dots on a ticker tape diagram will be _____.

very long
far apart
very short
close together

Answers

Answer:

If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.

I’m pretty sure the answer is “very long”

Một vật có khối lượng 2 kg rơi tự do xuống đất trong khoảng thời gian 0,5 s. Độ biến thiên động lượng của vật trong khoảng thời gian đó là bao nhiêu ? Cho g = 10 m/s2.

Answers

Answer: The change in momentum is +20 kg.m/s

Explanation:

To calculate the final velocity of object, we use the first equation of motion:

\(v=u+at\)

where,

v = final velocity

u = initial velocity = 0 m/s

a = acceleration = \(10m/s^2\)

t = time = 0.5 s

Putting values in above equation, we get:

\(v=0+(10\times 0.5)\\\\v=5m/s\)

Momentum is defined as the product of the mass and velocity of an object. It is given by the equation:

\(p=mv\)

where,

p = momentum

m = mass of object = 2 kg

Let the upward velocity be positive and the downward velocity be negative

When the object is dropped, the velocity is downward

v = -5m/s

Initial momentum = \(2kg\times (-5m/s)=-10kg.m/s\)

When the object is bounced back, the velocity is upward

v = +5m/s

Final momentum = \(2kg\times (+5m/s)=10kg.m/s\)

Change in momentum = Final - Inital

Change in momentum = [10 - (-10)] = +20 kg.m/s

Hence, the change in momentum is +20 kg.m/s

A car starts from rest with an acceleration of 5.0 m / s² and travels a distance of 1.0 km. What is the speed value of this car?

Answers

Answer:

100 m/s

Explanation:

We'll begin by converting 1 km to m. This can be obtained as follow:

1 km = 1000 m

Finally, we shall determine the final velocity of the car. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Acceleration (a) = 5.0 m/s²

Distance (s) = 1000 m

Final velocity (v) =?

v² = u² + 2as

v² = 0² + (2 × 5 × 1000)

v² = 0 + 10000

v² = 10000

Take the square root of both side

v = √10000

v = 100 m/s

Therefore, the speed value of the car is 100 m/s.

Suppose a spacecraft is orbiting 3.91* 10^5 meters above the surface of Mars. Calculate the magnitude of Mars' gravitational field and the approximate acceleration due to gravity experienced by the spacecraft (the mass of Mars is 6.39* 10^23 kg and its radius is 3.40* 10^6 m). [gravity, gravitational fields, gravitational acceleration]

Answers

The magnitude of Mars' gravitational field is 3.66 N/kg.

The approximate acceleration due to gravity experienced by the spacecraft is 3.66 m/s².

What is the  gravitational fields?

The gravitational fields of the Mars is calculated by applying the following equation;

E = F/m = GM/r²

where;

G is universal gravitation constantM is the mass of Marsr is the radius of Mars F is gravitational force

E = (6.626 x 10⁻¹¹ x 6.39 x 10²³) / (3.4 x 10⁶)²

E = 3.66 N/kg

The approximate acceleration due to gravity experienced by the spacecraft is calculated as follows;

F = mg = GmM/r²

g = GM/r²

where;

G is universal gravitation constantM is the mass of Marsr is the radius of Mars F is gravitational forceg is acceleration due to gravity

g = (6.626 x 10⁻¹¹ x 6.39 x 10²³) / (3.4 x 10⁶)²

g = 3.66 m/s²

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tyrell is playing marbles with his younger sister. a 6.63-g marble moving at 1.41 m/s has a head-on collision with a 2.86-g marble, initially at rest on the playing surface. the post-collision speed of the 6.63-g marble is 0.86 m/s. what is the speed (in m/s) of 2.86-g marble after the collision?

Answers

The speed of the 2.86 g marble after the collision is 1.05 m/s.

We can use the conservation of momentum to solve this problem:

Before the collision:

m1 = 6.63 g = 0.00663 kg (mass of the first marble)

v1 = 1.41 m/s (velocity of the first marble)

m2 = 2.86 g = 0.00286 kg (mass of the second marble)

v2 = 0 m/s (initial velocity of the second marble)

After the collision:

v1' = 0.86 m/s (final velocity of the first marble)

v2' = ? (final velocity of the second marble)

Using conservation of momentum:

\(m1v1 + m2v2 = m1v1' + m2v2'\)

Substituting the known values:

\(0.00663 kg * 1.41 m/s + 0.00286 kg * 0 m/s = 0.00663 kg * 0.86 m/s + 0.00286 kg * v2'\)

Solving for v2':

\(v2' = (0.00663 kg * 1.41 m/s - 0.00663 kg * 0.86 m/s) / 0.00286 kgv2' = 1.05 m/s\)

Therefore, the speed of the 2.86 g marble after the collision is 1.05 m/s.

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2 types of error and state how it is minimised when measuring the length of the object.

Answers

Two types of errors that can occur when measuring the length of an object are systematic errors and random errors. Systematic errors can be minimized by calibrating measuring instruments and ensuring proper alignment. Random errors can be reduced by taking multiple measurements and calculating the average value.

There are two types of errors that can occur when measuring the length of an object: systematic errors and random errors.
1. Systematic errors: These errors occur consistently and affect all measurements in the same way. They are usually caused by equipment calibration issues or incorrect measurement techniques. Systematic errors can be minimized by:
- Calibrating the measuring instrument regularly to ensure accurate readings.
- Using the appropriate measuring technique, such as aligning the object properly with the measuring device.
- Taking multiple measurements and averaging the results to reduce the impact of any systematic error.
2. Random errors: These errors are unpredictable and can occur due to various factors, such as human error or environmental conditions. Random errors can be minimized by:
- Taking multiple measurements and calculating the average, which helps to reduce the effect of random errors.
- Using a measuring instrument with high precision, as it reduces the likelihood of random errors.
- Ensuring consistent environmental conditions during measurements, such as stable temperature and lighting.
It's important to note that no measurement can be completely free from error.

However, by minimizing systematic and random errors, we can increase the accuracy and reliability of our measurements. Regular calibration, proper technique, and multiple measurements are key strategies to minimize errors when measuring the length of an object.

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A sock with a mass of 0.03 kg is stuck to the inside of a clothes dryer spins
around the drum once every 0.5 sec at a distance of 0.5 m from the center of
the drum. What is the linear speed if the sock could fly out?*

Answers

Answer:

15.71 m/s

Explanation:

We are given;

Time; t = 0.2 s

Radius; r = 0.5 m

The circumference will give us the distance covered.

Formula for circumference is 2πr

Thus; Distance = 2πr = 2 × π × 0.5 = π

Linear speed = distance/time = π/0.2 = 15.71 m/s


An object is thrown downward with an initial velocity of 6 feet
per second. The relationship between the distance s it travels and
time t is given by s=6t+16t2. How long does it take the object to
fal

Answers

The object does not fall or it takes no time to fall according to the given information.

To determine how long it takes for the object to fall, we need to find the time at which the distance traveled (s) becomes zero. This represents the point at which the object hits the ground.

Given: s = 6t + 16t^2

To find the time at which s becomes zero, we set the equation equal to zero and solve for t:

0 = 6t + 16t^2

This equation is a quadratic equation in terms of t. To solve it, we can factor out a common factor of t:

0 = t(6 + 16t)

Setting each factor equal to zero, we have:

t = 0 (from the factor t = 0)

or

6 + 16t = 0 (from the factor 6 + 16t = 0)

Solving the second equation for t:

16t = -6

t = -6/16

t = -3/8

We discard the negative solution since time cannot be negative in this context.

Therefore, the object takes t = -3/8 seconds to fall. However, this negative value doesn't make physical sense in this context. Therefore, we can conclude that the object does not fall or it takes no time to fall according to the given information.

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Low-energy lightbulbs currently cost $3.60, have a life of 9 years, and currently use $2.00 of electricity per year. Conventional lightbulbs are cheaper to buy; they currently cost only $0.60. On the other hand, they last only 1 year and currently use $7.00 of electricity per year. If the real discount rate is 4%, what are the EACs for each lightbulb? Which lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb? a. EAC( Low-energy lightbulb )=2.48 EAC( Conventional lightbulb )=7.62 Low-energy lightbulb is cheaper to operate b. EAC( Low-energy lightbulb )=3.60 EAC( Conventional lightbulb )=0.60 Conventional lightbulb is cheaper to operate c. EAC( Low-energy lightbulb) =2.00 EAC( Conventional lightbulb )=7.33 Low-energy lightbulb is cheaper to operate d. EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate

Answers

EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

Energy cost calculation

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

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What is the speed at 5s?

Answers

25 km/hr I hope this helps;)
25m/s
Here, the total distance is 10m , while the total time is 5s . ∴avg. speed=10m5s=2m/s .

PLEASE HELP WILL MARK AND 5 STARS I AM TIMED!!!!!!!!1

PLEASE HELP WILL MARK AND 5 STARS I AM TIMED!!!!!!!!1

Answers

Answer:

is there a better picture

Give reason:

colour, taste and smell can't be used to differentiate between water and oxygen gas​

Answers

Answer:

All three characteristics are common between the two

Explanation:

Both water and oxygen are odourless, tasteless, colourless substances and so it is not possible to tell the difference between the two just based off of these three characteristics.

How much energy does it take to raise the temperature of 2kg water from 10 Celsius to 26 Celsius? The specific heat capacity of water is 4.18kj/(kg C).

Answers

Answer:

Q = 133.76 KJ

Explanation:

The amount of heat energy required to raise the temperature of the water can be calculated by the following formula:

\(Q = mC\Delta T\)

where,

Q = Heat Energy Required = ?

m = mass of water = 2 kg

C = Specific Heat Capacity of Water = 4.18 KJ/kg°C

ΔT = change in temperature = 26°C - 10°C = 16°C

Therefore,

\(Q = (2\ kg)(4.18\ KJ/kg.^oC)(16^oC)\)

Q = 133.76 KJ

When we come out in the sun, we feel warm. How does the heat from the sun reach us?

Answers

Answer:

Radiation

Explanation:

Greetings !

The Sun reaches us by propagating through the vacuum of space. Sunlight reaches the Earth in about 8 minutes and 20 seconds. When this energy reaches the Earth's atmosphere, both conduction and convection play key roles to scatter it throughout the planet.

Answer: The heat from the sun reaches us through radiation and processes such as conduction and convection helps to scatter that heat on the surface of our planet.

Explanation:

The phenomenon behind the Sun's heat reaching us is radiation. It does this by propagating through the vacuum of space.

The amount of time it takes for the sunlight to reach us on Earth is approximately 8 minutes and 20 seconds. When it reaches our planet, conduction, the movement of heat or electricity through a medium or passage, as well as convection, the rising of hotter and less dense material and sinking of colder and more dense/denser material, helps to scatter the heat on Earth's surface.

A steel cable 3.00cm² in cross-sectional area has a mass of 2.40kg per meter of length. If 500m of the cable is hung over a vertical cliff, how much does the cable stretch under its own weight? Take Ysteel = 2.00 × 10¹¹ N / m² .

Answers

The steel cable will stretch Hooke's law approximately 2.76 meters under its own weight when 500 meters of it are hung over a vertical cliff.

The steel cable, with a cross-sectional area of 3.00 cm² and a mass of 2.40 kg per meter of length, stretches under its own weight when hung over a vertical cliff.

By applying Hooke's law and using the given Young's modulus (Ysteel = 2.00 × 10¹¹ N/m²), the amount of stretch can be calculated.

To calculate the stretch in the steel cable, we can use Hooke's law, which states that the stretch in a material is proportional to the applied force and inversely proportional to the material's stiffness. In this case, the applied force is the weight of the cable.

First, we need to calculate the weight of the cable. The weight is given by the mass per unit length multiplied by the length of the cable hanging over the cliff.

The mass per unit length is 2.40 kg/m, and the length of the cable is 500 m. Therefore, the weight of the cable is (2.40 kg/m) * (500 m) = 1200 kg.

Next, we can use Hooke's law to calculate the stretch. The formula for the stretch in a cable is ΔL = (F * L) / (A * Y), where ΔL is the change in length (stretch), F is the force (weight), L is the original length of the cable, A is the cross-sectional area of the cable, and Y is the Young's modulus.

Substituting the given values, we have ΔL = (1200 kg * 9.8 m/s² * 500 m) / (3.00 cm² * (2.00 × 10¹¹ N/m²)). Simplifying the units, we convert the cross-sectional area to square meters, resulting in ΔL ≈ 2.76 meters.

Therefore, the steel cable will stretch approximately 2.76 meters under its own weight when 500 meters of it are hung over a vertical cliff.

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if a parallelogram is a rhombus then the diagonals are

Answers

If a parallelogram is a rhombus then the diagonals are perpendicular bisectors of each other.

Also, the diagonals of a rhombus bisect each other at right angles. If a rhombus is a parallelogram, then it satisfies all the properties of a parallelogram which are as follows: Opposite sides are parallel Opposite angles are congruent The diagonals bisect each other .A rhombus is a type of parallelogram.

This is true for any rhombus. Let ABCD be a parallelogram and its diagonals intersect each other at O. Also, it is given that ABCD is a rhombus .In a parallelogram, opposite angles are congruent and adjacent angles add up to 180 degrees. Since ABCD is a rhombus, all of its sides are equal.

So, angle A = angle C and angle B = angle D.

Since opposite angles are congruent, angle A = angle C and angle B = angle D are congruent pairs.

So, angle A + angle B = angle C + angle D = 180 degrees .Since the diagonals bisect each other, this means that AO = CO and BO = DO. Since ABCD is a rhombus, all sides are equal. Therefore, AO = CO and BO = DO = a/2, where 'a' is the length of the side of the rhombus .

Using the Pythagorean Theorem in the right triangle AOB, we get:AO² + BO² = AB², substitute AO = CO and BO = DO we get:(CO)² + (DO)² = AB², Substitute DO = a/2, then we get:(CO)² + (a/2)² = a²Therefore,CO² = a² - (a/2)²CO² = (4a²)/4 - a²/4CO² = 3a²/4Therefore, CO = (a/2)√3Using the Pythagorean Theorem in the right triangle COD, we get:CO² + OD² = CD²Substitute CO = (a/2)√3 and DO = a/2 we get:(a/2)²(3) + (a/2)² = (2a/2)²a²/4 + a²/4 = a²/2a²/2 = a²So, CD = a Therefore, the diagonals of the rhombus bisect each other and are perpendicular to each other.

Therefore, the statement "If a parallelogram is a rhombus then the diagonals are perpendicular bisectors of each other" is true.

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Watt-hours is a measure of energy, just like kilowatt-hours. how can you convert this to joules? (hint: break this down into basic units and determine the required conversion factors.)

Answers

Watt-hours and kilowatt-hours are both measures of energy. To convert watt-hours to joules, we need to break down the units and use the appropriate conversion factors.

1 watt-hour is equal to 3600 joules. This conversion factor comes from the fact that power is equal to energy divided by time, and 1 watt is equal to 1 joule per second. Since there are 3600 seconds in an hour, we multiply the power in watts by the number of seconds in an hour to get the energy in joules.

To convert kilowatt-hours to joules, we first convert kilowatts to watts. 1 kilowatt is equal to 1000 watts. Then, we multiply the power in watts by the number of seconds in an hour (3600 seconds) to get the energy in joules.

Here are the conversion steps:

1. For watt-hours to joules:
  - Multiply the watt-hours by 3600 to get the energy in joules.

2. For kilowatt-hours to joules:
  - Multiply the kilowatt-hours by 1000 to convert to watts.
  - Multiply the result by 3600 to get the energy in joules.

Remember to always label your final answer with the correct units.

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During an all-night cram session, a student heats up a 0.858 liter (0.858 x10 −3
m 3
) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.2 ∘
C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 90.6 ∘
C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

Answers

approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.To calculate the volume of coffee that has spilled out of the beaker, we can use the concept of thermal expansion. The change in volume is given by the formula ΔV = βVΔT, where β is the coefficient of volume expansion, V is the initial volume, and ΔT is the change in temperature.

First, let's convert the initial volume to cubic meters: V = 0.858 x 10^(-3) m^3.
Next, we calculate the change in temperature: ΔT = 90.6 - 18.2 = 72.4 °C.
The coefficient of volume expansion for water (and coffee) is approximately β = 3.4 x 10^(-4) °C^(-1).
Plugging in these values into the formula, we get:
ΔV = (3.4 x 10^(-4) °C^(-1)) * (0.858 x 10^(-3) m^3) * (72.4 °C) = 2.093 x 10^(-6) m^3.

Therefore, approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.

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A 485 kg sphere sits at 14.0 km due north of an 852 kg sphere. What is the force of gravity on the first sphere
due to the second sphere? Compare this to the force of gravity on the second sphere due to the first sphere.

A 485 kg sphere sits at 14.0 km due north of an 852 kg sphere. What is the force of gravity on the first

Answers

Answer:

Explanation:

The answer is b i just did it have a good day

A 485 kg sphere sits at 14.0 km due north of an 852 kg sphere. What is the force of gravity on the first

A 485 kg sphere sits at 14.0 km due north of an 852 kg sphere. The force of gravity on the first sphere due to the second sphere is 1.41*\(10^{-13}\) N.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Given in the question a 485 kg sphere sits at 14.0 km due north of an 852 kg sphere,

F = Gm₁m₂/r²

Putting value of G = 6.6743 × 10-11 m³/ kg s²

we get force 1.41*\(10^{-13}\) N which is equal and opposite apply on both sphere.

A 485 kg sphere sits at 14.0 km due north of an 852 kg sphere. The force of gravity on the first sphere due to the second sphere is 1.41*\(10^{-13}\) N.

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An unstrained horizontal spring has a length of 0.40 m and a spring constant of 340 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.033 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.

Answers

Answer:

(a) Both the charges are positive or negative.

(b) Teh value of each charge is 1.53 x 10^-5 C.

Explanation:

Spring constant, K = 340 N/m

Natural length, L = 0.4 m

stretch, y = 0.033 m

(a) Let the charge on each sphere is q and they repel each other so the nature of charge of either sphere may be both positive or both negative.  

(b) The electrostatic force is balanced by the spring force.

\(\frac{kq^2}{(L + y)^2}=Ky\\\\\\\frac{9\times 10^9 q^2}{(0.4 +0.033)^2} = 340\times0.033\\\\q= 1.53\times 10^{-5} C\)

res Monocrystalline silicon is one of the most common types of Solar PV material used today. The conversion efficiency from solar radiation to electricity for this type of device in field applications is:

Answers

Answer:

yes

Explanation:

Malia has developed Type II Diabetes. When she eats, her body
does not release the proper amount of insulin needed to balance
her blood sugar (glucose) levels. Which life function is most
threatened by Malia's disease?
Select one:
a. Growth
b. Movement
c. Metabolism
d. Excretion

Answers

Answer:

The correct option is c.

Explanation:

Metabolism is a sum of anabolic and catabolic reactions. The body's inability to produce/synthesize enough insulin is the cause of type II diabetes. Generally, metabolism is the process in which most compounds (proteins, carbohydrates and lipids) are produced (anabolism) or broken down (catabolism) in the body. Insulin is a protein that can be produced in less amount due to metabolic disorder in the body.

Maria's disease means she already has an exponentially high amount of blood sugar against the required insulin to balance it out, hence the disease already slowed down her rate of metabolism (catabolism) of blood sugar EXCEPT she decides to increase of metabolism by medication and exercise.

an electric lamp is marked 240 volt 60 watt what is the resistor when it is operated at the correct voltage.b A. 1/960. B. 1/4 C. 4. D. 960. E. 14.400​

Answers

The resistor of the electric lamp is marked at 240 volts and 60 watts is 960 ohms. Thus, option D is correct.

The resistance is a property that gives obstruction the current flow.  It blocks the current flow in the circuit. The unit of resistance is the ohm.    

From the given,

The voltage of the electric lamp (E) = 240 volt

Power in the circuit (P) = 60 watt

Resistance =?

Power (P) = E² / R

R = E²/P

   = 240×240/60

  = 960 Ω

The resistance of the electric lamp with a given voltage and power is 960 Ω. Thus, the ideal solution is D.

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How do you calculate velocity?
a) Distance divided by time.
b) Displacement dided by time.
c) Speed multiplied by
time.
d) Displacement divided by velocity.

Answers

Answer:

A

Explanation:

Answer:

Distance divided by time

Explanation:

Why do atoms
have no electric charge even though most of
rticles have charges?

Answers

All atoms have the same number of electrons as protons, so the positive and negative charges "cancel out", making atoms electrically neutral. Unlike protons and neutrons, which are located inside the nucleus at the center of the atom, electrons are found outside the nucleus.

You are presented with several long cylinders made of different materials. Which of them are likely to be good conductors of electric current? Check all that apply - copper - aluminum - glass - quartz - plywood - table salt - gold

Answers

Copper, silver, aluminium, gold, steel, or brass are common good conductors. A most high conductivity metal are silver, copper, or gold.

Which metals are exceptionally able to conduct electricity?

A most high conductivity metal are silver, gold and copper. Copper, in example, is extremely conductive and widely used in metals wiring. Brass, on either hand, includes copper but some other components in its constitution limit conductivity. Pure silver is by far the most electromagnetic of all metals.

What's a good conductor for electricity Why?

Good conductors because their consist of lattice interconnected atoms with unbound electrons. The liberated electrons allow a fluid to pass through. Whenever a negative task is assigned around one end, all electrons were repelled from of the negative charge, but flow towards other end.

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