The frequency of a slinky spring wave is 5 hertz with a wavelength of 0.8 meters. What is its velocity?

Answer:

2nd one,

Its keep going, never return back

Answer:

The straight line.

Explanation:

I did this in an exam.

When cyclooctatetraene is treated with excess potassium metal dipotassium cyclooctatetraene dianion compound is formed.

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Answer:

False

Explanation:

Assuming the speed of the wave is taken as the speed of sound wave in air that is 340 m/s. The wavenumber for 262 Hz is 0.77 m⁻¹ and that for 294 Hz is 0.86 m⁻¹ .

The wave number of a wave is the number of wavelengths passing through unit length. It is the inverse of wavelength.

Wave number is directly proportional to the frequency.

The relation between frequency and wave number is written as:

wave number = ν/v

where v is the speed of the wave and ν is the frequency.

The wave number of the wave with the frequency of 330 Hz is then,

330 Hz/ 340 m/s = 0.97  m⁻¹

and for the remaining frequencies:

349 Hz /340 m/s =  1.052  m⁻¹

for 392 Hz,

392 Hz/340 m/s = 1.15  m⁻¹

For 440 Hz,

440 Hz/340 m/s = 1.29  m⁻¹.

for 494 Hz,

494 Hz/340 m/s = 1.45  m⁻¹

and  for 523 Hz,

523 Hz/340 m/s = 1.53  m⁻¹

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Answer:

w1:w2 = 16:1

Explanation:

As we know that ration of amplitude is equal to

\(\frac{a_1}{a_2} = \sqrt{\frac{w_1}{w_2} }\)

here w1 and w2 are the widths of the slit.

\(\frac{I _{min}}{I_{max}} = \frac{(a_1-a_2)^2}{(a_1+a_2)^2} \\\frac{9}{25} = \frac{(1-\frac{a_2}{a_1} )^2}{(1+\frac{a_2}{a_1} )^2} \\\frac{3}{5} = \frac{(1-\frac{a_2}{a_1} )}{(1+\frac{a_2}{a_1} )}\\8 \frac{a_2}{a_1} = 2\\\frac{a_1}{a_2} = 4\)

Again

\(\frac{a_1}{a_2} = \sqrt{\frac{w_1}{w_2} }\)

\(4 = \sqrt{\frac{w_1}{w_2} }\\\frac{w_1}{w_2} = 16\)

w1:w2 = 16:1

Answer:

The answer is A

Explanation:

Diane is not ranked because she did not record the change in frequency when increasing the tension in her low E string.

To rank the members based on the initial frequency of their low E string, we can compare the given beat frequencies. The larger the beat frequency, the larger the difference in frequency between the strings. Based on the given information, we can rank the members as follows:

Evita = 5 Hz

Buffy = 4 Hz

Aiko and Freja (tied) = 3 Hz

Chandra = 1 Hz

Note that Diane is not ranked because she did not record the change in frequency when increasing the tension in her low E string.

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Answer:

There would be a huge sound like an applause. At 200 decibels (the loudest possible sound ever created on Earth), it could shatter ear drums.

Explanation:

Hope this helps

If everyone on the planet screamed at the same moment, it would be a tremendously loud and chaotic event.

The particular impacts and repercussions, however, would be dependent on a variety of parameters such as the strength of the screams, the length, and the location of persons.

The cumulative cries of billions of individuals would produce a deafening loudness, perhaps reaching levels far beyond what the human ear can handle.

Thus, those in close proximity to people yelling may experience discomfort, confusion, and even bodily pain as a result of the loudness.

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Answer:

I guess it's force hope this answer helps

The answer is 86.4 degrees north of east. To arrive at the destination, the plane must fly in a direction that is a combination of its air speed and the wind direction.

Let's call the direction the plane must fly "x" degrees north of east. The plane's ground speed is the vector sum of its air speed and the wind speed. Since the wind is blowing due west and the plane is flying directly north, the wind will have no effect on the plane's northward speed. However, the wind will reduce the plane's eastward speed.

Using trigonometry, we can find that the plane's ground speed is approximately 424.3 km/hr. Since the plane needs to travel 500 km, it will take approximately 1.178 hours to reach its destination.

During that time, the wind will have pushed the plane 11.78 km to the west. We can use trigonometry again to find that the angle whose tangent is 11.78/500 is approximately 1.34 degrees.

Therefore, the plane must fly in a direction that is 90 degrees minus 1.34 degrees, or 88.66 degrees, north of east. Rounding to one decimal place, the answer is 86.4 degrees north of east.

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While the skin has the ability to block UV light which may cause damage, it also has the ability to absorb Drugs.

Skin is the largest organ of the body. It is usually soft, and flexible outer tissue. It is involved in Protection, Sensation and Regulation. It has the ability to Block UV light through Melanin and it has ability to absorb drugs through the Dermal Absorption through the skin. It is porous and hence has the ability to absorb:

Hair follicles and the pores absorbs the best present all over the body.

Substances can enter the skin through openings, getting absorbed into the dermis where blood vessels nourish the skin.

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The rocket should be launched about 12.3 meters to the left of the hoop to pass through it.

First, we need to calculate the time it takes for the rocket to reach the height of the hoop. We can use the kinematic equation:

y = v₁t + 1/2a*t²

Where y is the vertical displacement (20 m), v₁ is the initial vertical velocity (0 m/s), a is the acceleration due to gravity (-9.8 m/s²), and t is the time it takes to reach the height of the hoop.

Plugging in the values, we get:

20 m = 0 + 1/2*(-9.8 m/s²)*t²

Solving for t, we get:

t = √(40/9.8) ≈ 2.02 s

Now we can use the horizontal distance formula:

d = v₁t + 1/2a*t²

Where d is the horizontal distance, v₁ is the initial horizontal velocity (3.0 m/s), and a is the horizontal acceleration due to the rocket engine (unknown).

We know that the vertical thrust of the rocket engine (8.0 N) is equal to the weight of the rocket, so we can find the horizontal acceleration using:

a = F/m = 8.0 N / 0.5 kg = 16 m/s²

Plugging in the values, we get:

d = 3.0 m/s * 2.02 s + 1/2 * 16 m/s² * (2.02 s)²

d ≈ 12.3 m

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The electric field at a point between 2 points is given by

E = 4 k Qax/(a² - x²)² (-i^)

The formula for the electric field at a location on the x-axis is,

E =  k Q /r² ---(1)

where,

k is constant

q is magnitude of charge

r is the separation between the charge and the location of the electric field

So, we have to find the electric field at point (x,0) due to the both charges shown in the figure.

Due to point charge at point (-a,0) the electric field is in the positive x direction and due to charge at point (a,0) the electric field is in negative x direction.

E₁ be the electric field due to charge at point (-a,0)

E₂ be the electric field due to charge at point (a,0)

E₁ = k Q/(a + x)² i^

where the unit vector along the x-axis is i^

E₂ = k Q/(a - x)² (-i^)

E₁ + E₂ = k Q/(a + x)² i^ + k Q/(a - x)² (-i^) = -4 k Qax /(a² - x²)² i^

Thus, for a point between -a < x < a, electric field is given by E = 4 k Qax/(a² - x²)² (-i^)

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In order for the pilot to drop food packets over the entire terrain, he must fly in a specific pattern to ensure that no areas are missed.

One common pattern used for this type of operation is called the grid pattern. In the grid pattern, the terrain is divided into a grid of equal-sized squares. The pilot then flies over the terrain in a series of parallel lines, dropping food packets at regular intervals. Once the end of the terrain is reached, the pilot turns and flies back in the opposite direction, dropping packets at the same regular intervals. The distance between the parallel lines is determined by the size of the squares in the grid, and the regular intervals at which packets are dropped are determined by the desired coverage density. By flying in this pattern, the pilot can ensure that no areas of the terrain are missed, and that the food packets are distributed evenly throughout the entire area. This method is commonly used in agriculture and forestry applications, as well as in search and rescue operations.

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The service disconnecting switch for an installation consisting of a limited load on a single branch circuit should have a rating of not less than 15 ampere.

A service disconnecting switch is a device which disconnects all the conductors of the system from the main source of supply. The limitation of current is due to the high heat produce. As heat in a conductor is a function of current. Like: H = i²Rt

Where I is the current, R is the resistance of the device, and t is the time of current flow. We can see by the formula that heat is directly proportional to the square of the current. More is the current more will be the heat produced.

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On the receiver, a force of 375 Newton was applied.

What does one newton weigh?

In the walking (English, or customary) system, one newton is equivalent to around 0.2248 pounds of force or 100,000 dynes in the centimeter-gram-second (CGS) system.

What is a force unit of newton?

The newton, abbreviated N, is the Si derived unit of force. Base units that are pertinent to force are: The symbol for the length unit of a metre is m. the kilogramme (kg), a unit of mass. s stands for the second, a unit of time.

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 X-ray binaries are similar to another type of system, and that system is a progenitor of type Ia supernovae.

Type Ia supernovae is a type of supernova that occurs in binary systems (two stars orbiting one another) in which one of the stars is a white dwarf. The other star can be anything from a giant star to a smaller white dwarf. Beyond this "critical mass", they reignite and, in some cases, trigger a supernova explosion.

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Answer:

is sugar and water becouse sugar can solote the water

Answer:

please refer to the attachment.

Answer:

k and...

Explanation:

Answer:

no thank you.

explanation: Do not want to

Answer:the roller coaster cars

Explanation:

The universe had grown and cooled to the point where electrons could join nuclei to create neutral atoms.

Unknown is the true size of the cosmos. But by measuring the observable cosmos, we may determine that the universe is currently about 95 billion mild years long.

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Doppler effect is the shift in frequency as the object gets near an object/person or far away from an object or person.

Hope it helps!

Answer:

(i) Please see graph of the motion of the particles created with MS Excel and the calculations in the following sections

(ii) The time of collision is approximately 1.0 seconds

(iii) The common horizontal distance of point collision from the point of projection is approximately 25.2 meters

Explanation:

The velocity with which the first projectile was fired, v₁ = 21 m/s

The angle to the horizontal the particle is launched = 53.1°

The time at which the other particle was launched = 1 second later

The location from which the other particle was projected = 0.3 m below the first particle

The initial velocity of the second particle = 31.5 m/s

The angle to the horizontal at which the second particle was projected, θ = 36.9°

(i) The height reached, by each of the particle is given as follows;

y = u·t - 1/2·g·t²

For the first projectile, we have;

y = 21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3

For the second projectile, we have;

y= 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²

If the two projectiles collide, we get;

21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3  = 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²

Using a graphing calculator for simplifying, we get;

-11.93·t₁ + 12.2 = 0

t₁ = 12.2/11.93 ≈ 1.02

Therefore, at time t₁ = 1.02 seconds, after the launch of the second particle, the two particle will be at the same vertical height

However, whereby at the time, t₂, the particles collide, the horizontal distance travelled, 'x', will be equal;

We have;

x = u·cos(θ)·t₁

For the first particle, we have;

x₁₁ = 21 × cos (53.1°) × (t₂ + 1)

For the second particle, we have;

x₂₂ = 31.5 × cos (36.9°) × t₂

At the point of collision, we have;

x₁ = x₂

∴ 21 × cos (53.1°) × (t₂ + 1) = 31.5 × cos (36.9°) × t₂

31.5 × cos (36.9°) × t₂ - 21 × cos (53.1°) × t₂ = 21 × cos (53.1°)

t₂ = 21 × cos (53.1°)/(31.5 × cos (36.9°)  - 21 × cos (53.1°) ) = 1.00219236871

t₂ ≈ 1.0 seconds

Given that t₁ ≈ t₂, the particles reach the same height and the same horizontal distance at the same time, t₂ ≈ 1.0 and therefore, they collide.

(ii) The time of collision is found above as t₁ ≈ t₂ ≈ 1.0 seconds

(iii) The horizontal distance of the point of collision from the starting point, 'x', is given as follows;

x = 21 × cos (53.1°) × (1.0 + 1) ≈ 25.2

The horizontal distance of the point of collision from the starting point, x ≈ 25.2 meters

The vertical distance of the point of collision from the starting point of the second particle, 'y', is given as follows;

y = 21 × (1+1)×sin(53.1°) - 9.81 × (1+1)²/2 + 0.3 ≈ 14

The vertical distance of the point of collision from the starting point of the second particle, y ≈ 14 meters

The magnitude of the distance from the starting point of the second particle, r = √(25.2² + 14²) ≈ 28.8

The magnitude of the distance from the starting point of the second particle, r ≈ 28.4 meters.

Answer:

59g

Explanation:

The tennis ball with a velocity of 18 m/s and momentum of 1.06 kg m/s then the mass of the tennis ball in grams will be 59 grams (approx) two significant figures.

Regardless of the frame of reference, momentum is a conserved quantity in any inertial frame, which means that if an enclosed system is not subject to outside influences, its total linear momentum remains constant.

Additionally, momentum is preserved in general relativity, electrodynamics, quantum mechanics, quantum field theory, and special relativity (using a modified formula). It is a manifestation of translational symmetry, one of the basic symmetries of space and time.

According to the question, the given values are :

Velocity, v = 18 m/s

Momentum, p = 1.06 kg m/s

p = m × v

1.06 kg m/s = m × 18 m/s

m = 1.06 / 18

m = 0.0589 kg or

m = 58.9 grams or 59 grams approx in two significant figures.

So, the mass will be 59 grams.

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The amplitude of the function is 5/2Period. The phase shift is Phase shift is π/2Midline and the midline of the given function f(x) is Midline = 2Using the trig function sin(x), the equation for the graph of f(x) can be written as:f(x) = (5/2) sin (x - π/2) + 2

The amplitude, period, phase shift and midline of the given function f(x) is given below:

The given sinusoidal function oscillates between -5 and 5, which is a distance of 5 from the center line.

The amplitude is half of the distance between the minimum and maximum values, which is 5/2.

Hence the amplitude of the function is = 5/2Period:

The distance between the peaks on the graph of the given sinusoidal function is 4.

Hence the period of the function is Period = 4Phase shift:

The standard position of the graph of sin(x) is y = sin(x) where the graph passes through the origin (0,0).

The given function is also sin(x) shifted to the right by π/2 units.

Hence the phase shift is Phase shift = π/2Midline:

The midline is the average value of the function. For the sine function, the midline is y = 0.

The midline of the given function f(x) is Midline = 2Using the trig function sin(x), the equation for the graph of f(x) can be written as :f(x) = (5/2) sin (x - π/2) + 2

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Answer: Stored energy