The horizontal force FP = 150 N force pushes the block 5.5 m up along a 32∘ incline. A coefficient of friction μk = 0.11 m= 18kg
An 18 kilogram block lies on a plane inclined at 32 degrees above the horizontal. A horizontal force F subscript P of 150 newtons pushes the block toward the incline.
Part A
How much work is done by the horizontal force FP ?
Express your answer to three significant figures and include the appropriate units.
Part B
How much work is done by the gravitational force on the block during this displacement?
Express your answer to three significant figures and include the appropriate units.
Part C
How much work is done by the normal force?
Express your answer to three significant figures and include the appropriate units.
Part D
How much work is done by the friction force?
Express your answer to three significant figures and include the appropriate units.
Part E
What is the speed of the block (assume that it is zero initially) after this displacement?
Express your answer to two significant figures and include the appropriate units.
Answers
(a) The amount of work done by the horizontal force is 825 J.
(b) The amount of work done by gravitational force during the displacement is 514.1 J.
(c) The amount of work done by the normal force is 822.78 J
(d) The amount of work done by the frictional force is 90.5 J.
(e) The speed of the block after the displacement is 9.03 m/s.
Work done by the horizontal forceThe work done by the horizontal force is calculated as follows;
W = Fd
W = 150 x 5.5 = 825 J
Work done by gravitational force during the displacementW = mgh
W = mg(Lsinθ)
W = (18)(9.8)(5.5 x sin32)
W = 514.1 J
Work done by the normal forceW = Fn x d
W = (mgcosθ) x d
W = (18)(9.8)(cos 32) x (5.5)
W = 822.78 J
Work done by the friction forceW = Ff x d
W = μFn x d
W = μmgcosθ x d
W = (0.11)(18)(9.8)(cos32) x (5.5)
W = 90.5 J
Acceleration of the block after the displacement∑F = ma
F - Ff = ma
F - μFn = ma
F - μmgcosθ = ma
150 - (0.11 x 18 x 9.8 x cos32) = 18a
150 - 16.456 = 18a
133.544 = 18a
a = 7.42 m/s²
Speed of the block after the displacementv² = u² + 2as
v² = 0 + 2(7.42)(5.5)
v² = 81.62
v = √81.62
v = 9.03 m/s
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Answer:
A) 700 J
B) -514 J
C) 0 J
D) -139 J
E) 2.3 m/s
Explanation:
The amount of work done on an object is the product of applied force and displacement. The work done on an object will be translated to potential energy, kinetic energy, and heat (due to friction).
Part AThe horizontal force applied to the block is 150 N. The displacement of the block is (5.5 m)cos(32°) ≈ 4.664 m. The work done by the horizontal force is ...
Wh = F·d = (150 N)(4.664 m) ≈ 700. J
Part BThe force due to gravity is given by the equation ...
F = mg
Using g = -9.8 m/s² and the given mass, the gravitational force applied to the block is ...
F = (18 kg)(-9.8 m/s²) = -176.4 N
The upward displacement of the block is (5.5 m)sin(32°) ≈ 2.915 m. As above, the work is the product of this and the displacement. (Upward displacement is positive.)
Wg = F·d = (-176.4 N)(2.915 m) ≈ -514 J
Part CThe normal force on the block is perpendicular to the direction of motion. It will be the sum of the forces due to gravity and the horizontal force in the direction normal to the incline. In the direction into the incline, the force normal to the incline is ...
(150 n)sin(32°) +(176.4 N)cos(32°) ≈ 79.488 N +149.596 N ≈ 229.083 N
There is no displacement normal to the incline, so the work done by the normal force is ...
Wn = (229.1 N)(0 m) = 0 J
Part DThe friction force is the product of the coefficient of friction and the normal force:
F = µk·(229.083 N) = (0.11)(229.083 N) ≈ 25.20 N
This force operates in the direction opposite to the displacement. The work it does is ...
Wf = (-25.20 N)(5.5 m) ≈ -139 J
Part EThe total of all work done on the block will result in the block having a certain kinetic energy. That energy is ...
KE = (700 J) +(-514 J) +(0 J) +(-139 J) ≈ 46.92 J
This translates to the final velocity using the formula ...
v = √(2·KE/m) . . . . . m is mass
v = √(2·46.92 J/(18 kg)) ≈ 2.3 m/s
__
Additional comments
• Per problem requirements, the results of calculations are shown to 3 (or 2) significant figures. Intermediate calculations are kept to a sufficient number of significant figures to ensure accuracy in all reported values.
• When displacement is in the direction opposite to the applied force, the work done by the force is negative.
• The attached diagram is intended to help visualization of the forces and their components.
Related Questions
____energy is from the movement of electrons.
A. gravitational
B. chemical
C. electrical
D. nuclear
Answers
Answer:
C. electrialExplanation:
I hope l helped you. Please follow me. ❤❤❤❤Seismic waves, known as P – waves, and S – waves can be use to study the earths interior, which otherwise would have be been impossible to explore. Which properties of P Dash and S – waves allow the study of earths interior.
(Multiple choice)
A. They travel at varying speeds, depending on the composition of layer.
B. They deflected while passing through layers of different compositions.
C. They are produced during earthquakes and volcanic eruptions.
D S – waves cannot pass through a layer of liquid composition
Answers
A. They travel at varying speeds, depending on the composition of layer.
B. They are deflected while passing through layers of different compositions.
D. S-waves cannot pass through a layer of liquid composition.
P-waves (primary waves) and S-waves (secondary waves) are two types of seismic waves generated by earthquakes and other sources of seismic activity. These waves travel through the Earth's interior and are affected by the physical properties of the different layers they pass through.
P-waves are compressional waves that travel through solid and liquid materials, and they move faster than S-waves. They can travel through the Earth's core and are refracted and reflected as they pass through layers of different densities, allowing scientists to study the interior of the Earth.
S-waves are transverse waves that can only travel through solid materials, and they move slower than P-waves. When they encounter a layer of liquid material, they are unable to pass through it and are reflected back to the surface, creating a shadow zone on the opposite side of the Earth from the earthquake. This allows scientists to determine the size and shape of the Earth's liquid outer core.
Thus, options A, B, and D are correct, and option C is incorrect because both P-waves and S-waves are produced during earthquakes and volcanic eruptions.
A spraying pump is used to spray water from a pool to a fountain.
a) Determine the power of the pump when the work done by the pump is 800Nm at 50ms to a distance of 20m
b) Determine the mass of the pump when the water is projected at acceleration of 10m/s?
Answers
The power of the pump is its work done by time. The power used for a work done of 800 Nm in 50 seconds is 16 J/s or W. The force acting here is 40 N. Then the mass of the body is 4 kg.
What is power ?Power of an object is the rate of work done or energy used.
power = work done/ time.
It has the unit watt which is equal to J/s.
a. Given work done by the pump = 800 Nm
time = 50 s
then power = 800 Nm or J / 50 s = 16 Watt.
b. Force F = Work done/ distance
F = 800 Nm/20 m = 40 N
c. Then force = m a
given acceleration a = 10 m/s²
m = f/ a
= 40 N/10 m/s²
= 4 kg.
Therefore, mass of the pump is 4 kg.
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USATESTPREP
Examine the image here showing the different characteristics of the components of the electromagnetic spectrum. Ultraviolet light is often used to sterilize water in a water treatment facility. Which characteristics of ultraviolet light allow it to sterilize water? Select ALL that apply.
A) It is not visible, so pathogens cannot detect its presence.
B) It has low enough energy to be safe to humans but harmful to pathogens.
C) Its energy level is high enough to cause ionizing damage to DNA and molecules.
D) It has wavelengths too large to cause molecular changes to the molecules of water.
E) Its wavelengths are small enough to interact with bacteria and viruses, which can be pathogenic in the water.
Answers
Answer:
C, D, and E
Explanation:
Answer:it’s C, D, E
Explanation:
1. Is there a relationship between the volume of water displaced and the total volume of the block that has anything to do with density? If so, what is it?
Answers
Answer:
The volume of the block is equal to the volume of water displaced by the block.
Explanation:
Volume refers to the amount of space occupied by a given object (in this case the block). When an object such as the block is immersed in water, it displaces its own volume of water. This volume of water displaced is equal to the volume of the block. Hence we can write;
Final Volume of water - Initial Volume of water= Water Displaced = Volume of the block
Recall that the density of a body is given by;
Density= mass/volume
If we obtain the volume of the block by measuring the volume of water displaced by the block, then we weigh the block using a weighing balance, we can obtain the density of the block easily from the relationship shown above.
https://photos.app.goo.gl/wAXjG9NxWP2Wb55YA
Answers
Our knowledge of the functioning of mirror neurons emphasizes the importance of in the classroom.
modeling
Answers
Mirror neurons are a distinct type of brain cell that are crucial for direct, automatic, and instinctive environmental understanding.
How can you properly role-play in the classroom?A clear GOAL, the positive DEMONSTRATION, the possibility to PRACTICE, and the chance to REFLECT are the four elements that make up effective modeling, which students can combine or match depending on their experience.
Why is it crucial to set an example in the classroom?Being a good teacher improves your ability to model.Models are enablers because they show pupils what possible or desirable outcomes could or ought to look like.Because frequent misconceptions are corrected when or before they arise, it enables your pupils can engage & succeed and reduces your workload.
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sean kicks a ball 25 yards across the field. What distance did the ball travel?
Answers
Answer:
I think The ball traveled 25 yards.
What is the unit of measure of work?
Select one:
a. Kilogram/meter
b. Newton/kilogram
c. Meter Kilogram
d. Newton meter
Answers
The unit of measure of work is (d) Newton meter, which is commonly abbreviated or acronym as Nm or Joule (J). Option D is correct.
The quantity of energy transferred by a force operating via a displacement is referred to as work. It is computed by dividing the amount of force applied in the displacement direction by the length of the force's application. The mathematical formula for work (W) is
W=f×d×cosФ
Theta is the angle between the force vector and the displacement vector. F is the force, d is the displacement, and d is the displacement.
The unit of work, also known as the Newton meter (Nm) or Joule (J), is created by multiplying the force, measured in Newtons, by the distance, measured in meters. In many branches of research and engineering, the Joule is the unit of labor and energy that is most frequently employed.
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PLEASE HELPPP!!!! i really need help with this report if anyone can!!!!
The U.S. Army is planning to drop supplies from a plane at a refugee camp. The supplies are divided into 700-kilogram parcels, and the parachutes have an area of 100 square meters. The only problem is that the parcels cannot hit the ground at a velocity of more than 5 meters per second without damaging the contents. Are these parachutes suitable for this task?
For the purposes of this exercise, assume that the for the drag coefficient of the parachute is 1.5 and that the air density is 1.22 kilograms per cubic meter. Write a report detailing why these parachutes are or are not suitable and determining the minimum size parachute that can be used in this situation.
Answers
Answer:
search it up
Explanation:
Using the formula for air resistance, we can calculate the force acting on the parachute:
Force = 0.5 x Drag Coefficient x Air Density x Velocity^2 x Area
Assuming that the terminal velocity of the parcels is 5 meters per second, we can calculate the force acting on the parachute as follows:
Force = 0.5 x 1.5 x 1.22 x 5^2 x 100
= 1822.5 N
The weight of the parcels is 700 kg x 9.8 m/s^2 = 6860 N. Therefore, the force acting on the parachute is much less than the weight of the parcels, indicating that the parachutes are suitable for this task.
To determine the minimum size parachute that can be used in this situation, we need to calculate the maximum weight that can be supported by a parachute with an area of 100 square meters. This is known as the payload capacity of the parachute and can be calculated as follows:
Payload Capacity = Area x Drag Coefficient x Air Density x Velocity^2 / 2 x 9.8
Assuming that the maximum weight of the parcels that can be dropped is 700 kg, we can solve for the minimum size parachute as follows:
100 x 1.5 x 1.22 x 5^2 / (2 x 9.8) = 240.9 kg
Therefore, the minimum size parachute required for dropping 700-kilogram parcels at a velocity of less than 5 meters per second is approximately 241 square meters. In conclusion, the 100 square meter parachutes are suitable for this task, and a larger parachute would be required if the weight of the parcels increased.
which of the following is not a latent heat gain source
Answers
A ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?
Answers
I know acceleration would be -9.8 m/s^2 (to assume free fall), the initial velocity would be 20, and that the final position would be 10, but I don't know how to find the max height to then use to find the final velocity.
Just set this up as a quadratic function. I assume that we start from a height of zero, since you don't say.
h(t) = 20t - 4.9t^2
Now, you want to solve
20t - 4.9t^2 = 10
t = 0.583, 3.498
Since v=20-9.8t, that would make
v(3.498) = 20-9.8*3.498 = -14.28
You don't need to find the max height for this problem, but that occurs when v=0. So, h(2) = 20.4
Anyways goodluck!
1. Objects become electrically charged as a result of the transfer of
Answers
Answer:
Electron
Explanation:
An object can become electrically charged when it gains or loses an electron. Because an electron is negatively charged, when an object gains an electron it becomes negatively charged. Also, when it gives up an electron, it becomes positively charged. This positive charge is because the atom has one proton more than electron. In a neutral atom, the number of the proton is equal to the number of the electron. An electron is negatively charged, and a proton is positively charged.
A daring squirrel runs toward a cat, then turns around to safety. A graph of its velocity over time is shown
below.
Answers
Answer:
it's 1.0
Explanation:
kahn academee
what is the friction
Answers
Explanation:
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in
Answer #49 please and thank you
Answers
when Force (N) is 10.0 Length (m) is 0.60
when Force (N) is 8.0 Length (m) is 0.40
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 2.0 Length (m) is 0.10
chatgpt
49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:
Period (T) = 2π√(Length (L) / g)
Substituting the given values:
2.3 = 2π√(L / 1.6)
To solve for L, we can rearrange the formula:
L = (2.3 / (2π))^2 * 1.6
L ≈ 0.781 meters (or 78.1 centimeters)
So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.
50. Ranking Task:
To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.
Ranking from least to greatest period:
1. A: 10 cm long, mass = 0.25 kg
2. C: 20 cm long, mass = 0.25 kg
3. B: 10 cm long, mass = 0.35 kg
There is a tie between pendulums A and C, as they have the same length but different masses.
Using Newtons second law of motion, calculate the acceleration of an object with a mass of 210kg and a force of 2.5N acting on it. Don't forget your units.
Answers
so the acceleration of the object will be 0.01190m/s².
Need help with this table
Answers
A. The momentum of the boat after the explosion is -50 Kg.m/s
B. The momentum of the ball after the explosion is 9 Kg.m/s
A. How do i determine the momentum of the boat after explosion?The following data were obtained from the question:
Initial momentum of kent = 50 Kg.m/sInitial momentum of boat = 100 Kg.m/sFinal momentum of kent = 200 Kg.m/sFinal momentum of boat =?Total initial momentum = Total final momentum
50 + 100 = 200 + Final momentum of boat
150 = 200 + Final momentum of boat
Collect like term
Final momentum of boat = 150 - 200
Final momentum of boat = -50 Kg.m/s
B. How do i determine the momentum of the ball after explosion?The following data were obtained from the question:
Initial momentum of cannon = 121 Kg.m/sInitial momentum of ball = 5 Kg.m/sFinal momentum of cannon = 117 Kg.m/sFinal momentum of ball =?Total initial momentum = Total final momentum
121 + 5 = 117 + Final momentum of ball
126 = 117 + Final momentum of ball
Collect like term
Final momentum of ball = 126 - 117
Final momentum of boat = 9 Kg.m/s
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Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. How long will you measure it to be if it flies past you at a speed of u=0.75c?
The spaceship from Part A has a large clock attached to its side. This clock ran at the same rate as your watch when you were in the same reference frame. How much time ?t will pass on your watch as 80 s passes on the clock attached to the ship?
If the captain of ship A fires a missile, counts 10.0 s on his watch, and then fires a second missile, how much time ?t will the captain of ship B measure to have passed between the firing of the two missiles?
The captain of ship B knows that ship A uses 2-m-long missiles. She measures the length of the first missile, once it has finished accelerating, and finds it to be only 0.872 m long. What is the speed u of the missile, relative to ship B?
Answers
Answer:
The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.
Explanation:
The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.
A stone of mass 1kg is thrown at 10m/s upwards making an angle of 37°with the horizontal from a building that is 20m high. Using the law of conservation of energy calculate the speed wjen the stone hits the ground.
Answers
Answer:
31.68 m/s
Explanation:
The law of conservation of energy states that energy is not lost or gained it is just converted, in this example, since it is not given any resistance from the wind, you'd have two variables Speed on the Y-axis and on the X-axis, since both of them would result in the same decrease and increase with against gravity, it doesn't matter the value of both.
As the stone continues to go upwards it will continue to lose speed due to de-acceleration from the gravity acting on it, similarly, it will continue to gain Potential energy, instead of kinetic energy, when it reaches its highest point the speed on Y will be "0" and the free fall will start, since the up and down movement will be equal in time the and acceleration would be equal -9.81 m/s and 9.81 m/s because the only acceleration you have is gravity, you only need to calculate how much speed will gain a rock accelerating at 9.81 m/s falling 20 m:
\(H=\frac{1}{2}g*t^{2} \\\frac{20}{1/2*9.81} =t^{2} \\\\t^{2} =4.08\\t=\sqrt{4.08} \\t=2.21\)
Now we just add the time accelerating:
\(Vf=Vo+at\\Vf=10 m/s+ 2.21*9.81\\Vf=10 m/s+21.68\\Vf=31.68 m/s\)
Which statement best defines constructive interference? O Energy reflects back toward the source of its power. O Two waves with identical crests and troughs meet. thing O A wave appears to be at a standstill and vibrates in place O The trough of one wave matches the crest of another.
Answers
Answer:
when the trough of one wave matches the crest of another
Explanation:
just took the test
Polly Protractor drives 15 kilometers North to go shopping at one mall, then drives
20 kilometers East to go shopping at another mall.
Answers
The resultant displacement of the Polly protractor is 25 km.
What is displacement?The displacement of an object is the change in the position of the object.
The displacement of the Polly protractor is calculated as follows;
d² = 15² + 20²
d = √(15² + 20²)
d = 25 km
Thus, the resultant displacement of the Polly protractor is 25 km.
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The complete question is below:
Find the resultant displacement of the Polly protractor.
the value of mass of a body is everywhere
Answers
Explanation:
The value of mass of a body is not same everywhere.
Because it depends on gravity and the gravity isn't same at every places.
Answer:
Mass is the quantity of matter contained in a body, while weight is the force by which the body is pulled to the earth's center. Mass is an intrinsic property of a body, as it remains the same everywhere in the universe. Weight is variable due to change in the magnitude of the gravitational force applied by the earth.
Two students are at the beach studying nature and see a pod of dolphins swimming by. student 1 decides the best way to study them is by diving under the water while student 2 observes from above the water. the two students hear sounds from dolphins that are in the water and jumping above the surface the same distance from the students. based on the information below, which dolphin would the studen hear first?
v=f * A
jumping dolphin frequency: 1200 Hz
wavelength: 0.285 m
swimming dolphin
frequency: 1800 Hz
wavelength: 0.833 m
show the work
which sound reaches the shore first? Use the numbers you have calculated to support your answer.
Answers
Answer:
abdulaziz Sharif mamad
Dogs keep themselves cool by panting, rapidly breathing air in and out. Panting results in evaporation from moist tissues of the airway and lungs, which cools the animal. Measurements show that, on a 35∘C day with a relative humidity of 50%, a 12 kg dog loses 1.0 g of water per minute if it is panting vigorously. What rate of heat loss, in watts, does this achieve?
Answers
The rate of heat loss, in watts, does this achieve is 37.66 W
Evaporation:It leads in cooling since water absorbs heat equivalent to mass times latent heat of evaporation to get converted into vapor .
So,
latent heat of evaporation of water = 2260 x 10³ J / kg or 2260 J / g
Now
in the evaporation of 1 g of water , heat lost = 2260 J
And,
heat lost per minute = 2260 J
So,
heat lost per second = 2260 / 60
= 37.66 J /s
= 37.66 W
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A 20.0-N box rests on a 50.0-N box on a perfectly smooth horizontal floor. When a horizontal 15.0-N pull to the right is exerted on the lower box (see figure), both boxes move together what is the net force on the top block
Answers
The net force on the top block is 33.54 N.
What is net force?
Net force is the sum or resultant of two or more forces acting on a body.
Also, the net force is the force which is the sum of all the forces acting on an object simultaneously.
The sum of the upward forces is calculated as follows;
F(upward) = 50 N - 20 N = 30 N
The sum of the horizontal forces is calculated as follows;
F(horizontal) = 15 N
The net force or resultant force on the top block is calculated as follows;
F(net) = √Fy² + Fx²
where;
Fy is the sum of the vertical forcesFx is the sum of the horizontal forcesF(net) = √Fy² + Fx²
F(net) = √[(30)² + (15)²]
F(net) = 33.54 N
Thus, the net force or resultant force on the top block is determined as 33.54 N.
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You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answers
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
Calculate the force between charges 4 x 10^-8 C and 1.8 x 10^-6 C if they are 3.5 m apart.
Answers
Explanation
Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.
\(F=k\frac{q_1\cdot q_2}{r^2}\)where k is the coulomb constant
\(k=8.9875\cdot10^9\text{ N }\frac{m^2}{C^2}\)Step 1
let
\(\begin{gathered} q_1=4\cdot10^{-8}C \\ q_2=1.8\cdot10^{-6} \\ r=3.5\text{ m} \\ k=8.9875\cdot10^9\text{ N }\frac{m^2}{C^2} \end{gathered}\)now, replace.
\(\begin{gathered} F=k\frac{q_1\cdot q_2}{r^2} \\ F=8.9875\cdot10^9\text{ N }\frac{m^2}{C^2}(\frac{4\cdot10^{-8}C\cdot1.8\cdot10^{-6}}{(3.5m)^2}) \\ F=5.2824\cdot10^{-5}\text{ N} \end{gathered}\)I hope this helps you
Which color of light is produced by mixing red light and blue light?1) white light2) yellow light3) magenta light4) cyan light
Answers
According to the additive light model:
When red and blue light are mixed, magenta is produced.
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
KE = one half.mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of
0.8 m will be 4 m/s, and use this speed for each calculation.
Record your calculations in Table A of your Student Guide.
When the mass of the bottle is 0.125 kg, the KE is
✔ 1
kg m2/s2.
When the mass of the bottle is 0.250 kg, the KE is
✔ 2
kg m2/s2.
When the mass of the bottle is 0.375 kg, the KE is
✔ 3
kg m2/s2.
When the mass of the bottle is 0.500 kg, the KE is
✔ 4
kg m2/s2.
Answer included in Question
Answers
Answer:
kinetic energy is given as KE = (0.5) m v²given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg KE = (0.5) m v² = (0.5) (0.125) (4)²
Explanation:
Answer:
1. 0.5 2. 2 3. 3.75 4. 5
Explanation: