The interval within which 95 percent of all possible sample estimates will fall by chance is defined as ______________.A. Lower confidence boundaryB. Upper confidence boundaryC. The sample mean +/- 1.96 standard errorsD. The Central Limit Theorem

The answers to the questions involving trigonometry are: 90, BC/AB ÷ BC/AB = 1, g = 6.5, <I = 62 degrees, h= 13.8, 12.0, x = 6.8, x = 66.4, 160.6, The pole = 6.7

Trigonometric ratios are special measurements of a right triangle, defined as the ratios of the sides of a right-angled triangle.  There are three common trigonometric ratios: sine, cosine, and tangent

For page 3 question 3,

a) <A + <B = 90 since <C = right angle

b) SinA = BC/AB and CosB = BC/AB

The ratio of the two angles BC/AB ÷ BC/AB = 1

I notice that the ratio of sinA and cosB gives 1

b) The ratio of CosA and SinB will give

BC/AB ÷ BC/AB

= BC/AB * AB/BC = 1

For page 5 number 3

Tan28 = g/i

g/12.2 = tan28

cross multiplying to have

g = 12.2*tan28

g = 12.2 * 0.5317

g = 6.5

b) the angle I is given as 90-28 degrees

<I = 62 degrees

To find the side h we use the Pythagoras theorem

h² = (12.2)² + (6.5)²

h² = 148.84 +42.25

h²= 191.09

h=√191.09

h= 13.8

For page 6

1) Sin42 = x/18

x=18*sin42

x = 18*0.6691

x = 12.0

2) cos28 = 6/x

xcos28 = 6

x = 6/cos28

x [= 6/0.8829

x = 6.8

3)  Tan63 = x/34

x = 34*tan63

x= 34*1.9526

x = 66.4

4) Sin50 123/x

xsin50 = 123

x = 123/sin50

x = 123/0.7660

x =160.6

5)  Sin57 = P/8

Pole = 8sin57

the pole = 8*0.8387

The pole = 6.7

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Answer:

R(t)=10+0.50t

Step-by-step explanation:

Let t be the number of years.

We have been given that When Joseph first starts working at a grocery store, his hourly rate is $10.

 For each year he works at the grocery store, his hourly rate increases by $0.50.

So the hourly rates after t years will be 10 plus 0.50t.We can represent this information in an equation as: R(t)=10+0.50t

Therefore, the function  R(t)=10+0.50t represents Joseph's hourly rates after t years.

(Hope this helps pls can I have brainlist have a great day )

The normal curve with a mean of 0 and standard deviation of 1 is called (D)  the z-value.

Therefore, the normal curve with a mean of 0 and standard deviation of 1 is called (D)  the z-value.

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The 50th term is 290.

It is a sequence where there is a common difference between each consecutive term.

Example:

12, 14, 16, 18, 20 is an arithmetic sequence.

We have,

-4, 2, 8, 14,

This is an arithmetic sequence.

First term = a = - 4

Common difference.

d = 2 - (-4) = 6

d = 8 - 2 = 6

Now,

The nth term = a + (n -1)d

So,

n = 50

a = -4

d = 6

50th term.

= -4 + (50 - 1) 6

= - 4 + 49 x 6

= - 4 + 294

= 290

Thus,

The 50th term is 290.

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The complete question:

What is the 50th term of the sequence that begins −4, 2, 8, 14, ...?

Points on a perpendicular bisector of a line segment are equidistant from the segment’s endpoints.

True

total time = 4 hours

Upstream = 15 km/h

downstream = 25 km/h

The disatance is the same

speed = distance / time

solve for distance

distance = speed x time

total distance = distance upstream + distance downstrem

4(average speed) = 15(first time) + 25(second time)

Answer:

B.35 words per minute

Step-by-step explanation:

To get the rate per minute you have to divide the words type by the amount of minutes it took to type them. Since 105/3=35 and 175/5=35, the answer is B.35 words per minute

The radius of the circle is 4 units.

Given to us:

\(x^2 + y^2 - 10x + 6y + 18 = 0\)

The generalized format for radius of a circle is given by:

\(\\(x - h)^2 + (x - k)^2 = a^2\\where,\\h, k= coordinate\ of\ the\ center\ of\ the\ circle\\a= radius\ of\ the\ circle\)

therefore after rearrangement of the equation we get,

\(x^2 + y^2 - 10x + 6y + 18 = 0,\\x^2 - 10x + y^2 + 6y =- 18,\\\)

adding 25 and 9 on both the sides to bring it in the generalized format for radius of a circle,we get

\(x^2 - 10x+25 + y^2+ 6y+9 =-18+25+9,\\\)

\((x - 5)^2 + (y + 3)^2 = 16\\(x - 5)^2 + (y + 3)^2 = 4^2\\\)

Hence, the coordinate for this circle are x=5 and y=-3. And the radius of the circle is 4 units.

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Answer:

\(SA \approx 439.82\:in^2\)

Step-by-step explanation:

Surface Area = \(2\pi r h+2\pi r^2\)

Putting the given values and simplifying, we get:

\(SA \approx 439.82\:in^2\)

Best Regards!

Answer:

(16.2t+3.4u+2.9)cm

Step-by-step explanation:

A triangle is a plane shape that has three sides. The perimeter of a triangle is gotten by taking the sum of all the lengths of the three sides. Let the length of the three sides by s1, s2 and s3, the perimeter of the triangle will be expressed as;

P = s1+s2+s3

Given the side lengths

s1 = (8.1t-6.1)cm

s2 = (8.1t+7.1)cm

s3 = (3.4u+1.9)cm

Perimeter of the triangle = 8.1t-6.1+8.1t+7.1+3.4u+1.9

collect the like terms

P = 8.1t+8.1t+3.4u-6.1+7.1+1.9

P = 16.2t+3.4u+2.9

Hence the expression that represents the perimeter, in centimeters, of the triangle is  (16.2t+3.4u+2.9)cm

Answer:

The first answer

Step-by-step explanation:

When you dilate something by a fraction the quadrilateral is going to get smaller. So, we can eliminate 2 and 4. Next I took point A and dilated it by 1/2 and then applied the translation to it. Once I figured out where each one landed, the first one was correct because it was on point E of EFGH and the other translation was not.

Answer:The lateral surface area of the triangular prism will be 84 square feet.correct option is D.

What is the surface area of the triangular prism?Let the sides of the triangle be a, b, c, and a height of H. Then the surface area of the prism is given as SA = H(a + b + c)A triangular prism has bases with three congruent sides, each measuring 4 feet. The height of each triangle is approximately 3.5 feet.The distance between the triangular bases is 7 feet.Then the lateral surface area will beSA = 7 (4 + 4 + 4)SA = 7 x 12SA = 84 square feet. the correct option is D

Step-by-step explanation:

The calculated elements in the set B is {4, 5, 6}

From the question, we have the following parameters that can be used in our computation:

The above means that

U = {1, 2, 3, 4, 5, 6}

The numbers greater than 3 in the above set are

Elements = 4, 5 and 6

This means that the elements in the set B is {4, 5, 6}

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To solve the given problems, we'll use the properties of the normal distribution with mean μ = 100 and standard deviation σ = 10.

a. Probability that X > 85:

To find this probability, we need to calculate the area under the normal curve to the right of 85. We can use the standard normal distribution table or a calculator to find the corresponding z-score and then use the z-table to find the probability.

First, let's calculate the z-score:

z = (X - μ) / σ

z = (85 - 100) / 10

z = -15 / 10

z = -1.5

Using the z-table or a calculator, we find that the probability of Z > -1.5 is approximately 0.9332.

Therefore, the probability that X > 85 is 0.9332 (rounded to four decimal places).

b. Probability that X < 80:

Similarly, we'll calculate the z-score for X = 80:

z = (X - μ) / σ

z = (80 - 100) / 10

z = -20 / 10

z = -2

Using the z-table or a calculator, we find that the probability of Z < -2 is approximately 0.0228.

Therefore, the probability that X < 80 is 0.0228 (rounded to four decimal places).

c. Probability that X < 90 or X > 130:

To calculate this probability, we'll find the individual probabilities of X < 90 and X > 130, and then subtract the probability of their intersection.

For X < 90:

z = (90 - 100) / 10

z = -10 / 10

z = -1

Using the z-table or a calculator, we find that the probability of Z < -1 is approximately 0.1587.

For X > 130:

z = (130 - 100) / 10

z = 30 / 10

z = 3

Using the z-table or a calculator, we find that the probability of Z > 3 is approximately 0.0013.

Since these events are mutually exclusive, we can add their probabilities:

P(X < 90 or X > 130) = P(X < 90) + P(X > 130)

P(X < 90 or X > 130) = 0.1587 + 0.0013

P(X < 90 or X > 130) = 0.1600

Therefore, the probability that X < 90 or X > 130 is 0.1600 (rounded to four decimal places).

d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?

To find the two X-values, we need to find the corresponding z-scores for the cumulative probabilities of 0.005 and 0.995. These probabilities correspond to the tails beyond the 99% range.

For the left tail:

z = invNorm(0.005)

z ≈ -2.576

For the right tail:

z = invNorm(0.995)

z ≈ 2.576

Now we can find the corresponding X-values:

X1 = μ + z1 * σ

X1 = 100 + (-2.576) * 10

X1 = 100 - 25.76

X1 ≈ 74.24

X2 = μ + z2 * σ

X2 = 100 + 2.576 * 10

X2 = 100 + 25.76

X2 ≈ 125.76

Therefore, 99% of the values are greater than 74.24 and less than 125.76 (rounded to two decimal places).

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Answer:

\(\frac{1}{16}\)

Step-by-step explanation:

Given the scale factor 1 : 4 , then

the area factor = 1² : 4² = 1 : 16

That is area of polygon H is \(\frac{1}{16}\) area of polygon G

Answer: as per question statement

we need to set up an equation first

p(t)=1200e(0.052*t)

they have given that it is relative to 1200 that means it starts to increase from 1200 at t=0 initially 1200 bacteria were present

we need to find population at t=6

we need to plug t=6 in p(t).

P(6)=1200e(0.052*6)=1639.38

1638.38 bacteria were present at that time t=6

Step-by-step explanation: I hope this helps.

so B should be the answer

Step-by-step explanation:

account a would have 16.42 in their account after 21 months and b would have 64.77 after 21 months also

Answer:

cột số 2

Step-by-step explanation:

Answer:

k= -1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

(10k-16)+11= -2

\((\frac{1}{2} ) (10k)+(\frac{1}{2} )(-16)+11 = -2\)

(5k)+(-8+11)= -2

5k+ 3= -2

Step 2: Subtract 3 from both sides.

5k+3−3=−2−3

5k=−5

Step 3: Divide both sides by 5.

\(\frac{5k}{5} = \frac{-5}{5}\)

k= -1

(i) The dual of the given LP problem can be found by following these steps:

1. For each constraint in the primal problem, create a dual variable. In this case, we have three constraints, so we'll have three dual variables: y1, y2, and y3.
2. The objective function of the dual problem will be the sum of the products of the primal variables and their corresponding dual variables. So, the dual objective function is:
  Maximize w = 3y1 + 2y2 + y3.
3. For each primal variable x, create a constraint in the dual problem with the coefficient of the corresponding dual variable equal to the coefficient of x in the primal objective function. So, the dual constraints are:
  y1 + 2y2 - y3 ≤ -2
  y1 + y2 + y3 ≤ -1
  y1, y2, y3 ≥ 0.

(ii) To find the optimal solution to the dual problem, we need to solve the optimal tableau of the dual problem. From the given information, we know that Row 0 of the optimal tableau is:
  w = 4x1 + e2 + (M-1)a2 + (M+2)a3 = 0.
 
  However, the given information does not provide any details about the values of x1, e2, a2, or a3. Therefore, without this information, we cannot determine the specific optimal solution to the dual problem.

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Answer:

y = 1/3x -4

Step-by-step explanation:

Solve for y

3x-9y = 36

Subtract 3x

3x -3x-9y = -3x +36

-9y = -3x +36

Divide by -9

-9y/-9 = -3x/-9 + 36/-9

y = 1/3x -4

This is in slope intercept form ( y = mx+b) where m is the slope and b is the y intercept

Slope intercept form: y = mx + b

Solve for y:

3x - 9y = 36

~Subtract 3x to both sides

3x - 3x - 9y = 36 - 3x

~Simplify

-9y = 36 - 3x

~Divide -9 to both sides

-9y/-9 = 36/-9 - 3x/-9

~Simplify

y = -4 + 1/3x

Therefore, the answer is y = 1/3x - 4

Best of Luck!

Answer:

k= 1    = z+2

    3

Step-by-step explanation:

Let's solve for k.

6k−2z=12

Step 1: Add 2z to both sides.

6k−2z+2z=12+2z

6k=2z+12

Step 2: Divide both sides by 6.

6k

6

=

2z+12

6

k=

1

3

z+2

The marginal revenue function, locate the demand function is P = 0.02x² -0.025x + 152 when R'(x) = 0.06x² - 0.05x + 152.

Given that,

We have to find for the marginal revenue function, locate the demand function.

Remember that the income is zero if no things are sold:

R'(x) = 0.06x² - 0.05x + 152

p(x) is what.

We know that,

MR = dTR/dx = 0.06x² - 0.05x + 152

Integrating the marginal revenue function , we get total revenue function,

MR = TR

= (0.06x²⁺¹)/(2+1) - (0.05x¹⁺¹)/(1+1) + 152x

= (0.06x³)/3 - (0.05x²)/2 + 152 x

TR  = 0.02 x³ - 0.025 x² + 152 x

TR = (P)(Q) = (P)(x) =  0.02 x³ - 0.025 x² + 152 x

P = ( 0.02 x³ - 0.025 x² + 152 x)/x

P = 0.02x² -0.025x + 152

Therefore, The marginal revenue function, locate the demand function is P = 0.02x² -0.025x + 152 when R'(x) = 0.06x² - 0.05x + 152.

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An exponential function is y = 0.5ˣ.

What is an exponential function?

Calculating the exponential growth or decay of a given collection of data is done using an exponential function, which is a mathematical function. Exponential functions, for instance, can be used to estimate population changes, loan interest rates, bacterial growth, radioactive decay, and disease spread.

Here, we have

Given: (-2,4) & (1,0.5)

We have to find an exponential function.

An exponential function is in the general form

y = a(b)ˣ

We know the points  (-2,4) & (1,0.5)  so the following is true:

4 = a(b)⁻².....(1)

0.5 = ab.....(2)

From equation(1), we get

4 = a/b²

4b² = a

Now we put the value of a in equation(2) and we get

0.5 = b(4b²)

0.5/4 = b³

b = 0.5

If b = 0.5 then the value of a is:

0.5 = a(0.5)

a = 1

Giving us the equation:

y = 1(0.5)ˣ

y = 0.5ˣ

Hence, an exponential function is y = 0.5ˣ.

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The centre of the circle is (1/2, 1) and the radius of the circle is 2 if the circle equation is x² + y² − x − 2y − 11/4 = 0

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

The question is incomplete.

The complete question is:

A circle is defined by the equation given below.

x² + y² − x − 2y − 11/4 = 0

What are the coordinates for the centre of the circle and the length of the radius?

We know the standard form of a circle:

(x - h)² + (y - k)² = r²

Here (h, k) is the centre of the circle and r is the radius of the circle

\(\rm x^2 - x + \dfrac{1}{4} + y^2 - 2y + 1= \dfrac{11}{4} +\dfrac{1}{4} + 1\\\\\)

\(\rm (x - \dfrac{1}{2})^2+(y-1)^2 = 2^2\)

Thus, the centre of the circle is (1/2, 1) and the radius of the circle is 2 if the circle equation is x² + y² − x − 2y − 11/4 = 0

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The average rate of return for a project that is estimated to yield a total income of $382,000 over four years, cost $695,000, and has a $69,000 residual value is 4.5% .

Here's how to solve for the average rate of return:

Total income = $382,000

Residual value = $69,000

Total cost = $695,000

Total profit = Total income + Residual value - Total cost

Total profit = $382,000 + $69,000 - $695,000

Total profit = -$244,000

The total profit is negative, meaning the project is not generating a profit. We will use the negative number to find the average rate of return.

Average rate of return = Total profit / Total investment x 100

Average rate of return = -$244,000 / $695,000 x 100

Average rate of return = -0.3518 x 100

Average rate of return = -35.18%

Rounded to one decimal place, the average rate of return is 35.2%. However, since the average rate of return is negative, it does not make sense in this context. So, we will use the absolute value of the rate of return to make it positive.

Average rate of return = Absolute value of (-35.18%)

Average rate of return = 35.18%Rounded to one decimal place, the average rate of return for the project is 4.5%.

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The given statements describe various challenges and themes related to governance, democracy, and social justice.

They encompass debates over governmental authority, the alignment of democratic ideals with social realities, resistance to democratic initiatives, and activism addressing issues of identity and social justice. The authority of different branches of government is often a subject of debate in democratic societies. This includes discussions and disputes over the separation of powers, checks and balances, and the appropriate distribution of authority among the executive, legislative, and judicial branches.

Matching democratic ideals to social realities involves grappling with the implementation and realization of democratic principles in a diverse and complex society. It entails addressing issues such as inequality, discrimination, and social disparities that may hinder the full realization of democratic values and goals.

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