the loop of wire shown in forms a right triangle and carries magntiude b = 3.00 t and the same direction as the current in side pq
Answers
The magnetic field of a wire loop can be calculated using Ampere's law and the equation B = μI/2R, where B is the magnetic field, I is the current, R is the radius of the loop, and μ is the permeability of free space.
We are given that a loop of wire shown in forms a right triangle and carries magnitude b = 3.00 T and the same direction as the current in side pq. We need to find the magnetic field at point P.
Using the right-hand rule, we can determine that the magnetic field at point P will be out of the page or towards the observer. Using the equation
B = μI/2R,
where μ is the permeability of free space and R is the radius of the loop, we can determine the magnetic field.
First, we need to determine the current. The current is equal to the magnitude of b, which is 3.00 T. Next, we need to determine the radius of the loop. From the diagram, we can see that the length of side PQ is equal to the radius of the loop. Side PQ is equal to 6.0 cm or 0.06 m.
Therefore, the radius of the loop is 0.06 m.Now we can plug in the values into the equation
B = μI/2R.μ is equal to 4π × 10-7 T m/A, so
B = (4π × 10-7 T m/A)(3.00 A)/(2(0.06 m)) = 3.98 × 10-5 T.
The magnetic field at point P is 3.98 × 10-5 T towards the observer.
The magnetic field at point P is 3.98 × 10-5 T towards the observer. The magnetic field of a wire loop can be calculated using Ampere's law and the equation B = μI/2R, where B is the magnetic field, I is the current, R is the radius of the loop, and μ is the permeability of free space.
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Related Questions
what is the magnitude of the force f⃗ on the -10 nc charge in (figure 1)? suppose that a = 2.4 cm.
Answers
The force is -7.81105 N in magnitude. The object is propelled by external forces. The object's overall motion is unaffected by an internal force.
In science, what exactly is a force?
The term "force" has a clear definition in science. It is perfectly acceptable to refer to a force at this level as a push or a pull. An object does not "have in it" or "contain" a force. One object is subject to a force from another.
What is an illustration of force?
A force is a push that has the power to accelerate something. This can literally mean pushing something to move it around the room, like a big piece of furniture.
F = Kq1q2/r^2
q1 and q2 = charges
K = electric constant
r = distance of separation
F = force
Then we have;
F = 9 * 10^9 * 5 * 10^-9 * (-10 * 10^-10)/(0.018)^2
F = -4.5 * 10^-8/3.24 * 10^-4
F = -7.81×10⁻⁵ N
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the force of gravity between two objects decreases rapidly when
Answers
The force of gravity between two objects decreases rapidly when the distance between them increases.
The force of gravity is the force of attraction between two objects with mass. Gravity holds the planets in orbit around the sun. It holds moons in orbit around their planets. It is also what brings apples falling from trees and makes objects land on the ground. Gravity is what keeps all of the planets in orbit around the sun. The sun's gravity is what keeps the planets in orbit around it. The planets are constantly moving in an oval-shaped orbit. That is what keeps each planet in a path that doesn't run into the others.
Gravity is a force of attraction between two objects with mass. It is proportional to the product of the masses of two objects and inversely proportional to the square of the distance between them. According to the law of gravity, the force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Therefore, the force of gravity between two objects decreases rapidly when the distance between the objects increases.
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It's possible to join, open, close, or reverse a path using the four buttons in the paths section of the pathfinder panel. question 1 options: true false
Answers
The statement "It's possible to join, open, close, or reverse a path using the four buttons in the paths section of the pathfinder panel" is true. In Adobe Illustrator, the Pathfinder panel offers various options to manipulate paths and shapes effectively. The four buttons in the paths section allow you to perform different operations on selected paths:
1. Join: This option connects two open paths, creating a continuous path.
2. Open: This allows you to open a closed path by selecting an anchor point, essentially splitting the path.
3. Close: This option connects the start and end anchor points of an open path, turning it into a closed path.
4. Reverse: This reverses the direction of a path, which can be useful for various design tasks, like creating compound paths or adjusting stroke direction.
By using these buttons, you can quickly and easily modify paths in your design to achieve the desired result.
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how much work is done by a person if he stand carrying a load of 50 kg at the height of 1 metre
Answers
heighth=20×0.2=4m
workdone=mgh=70×10×4
=2800
When an elevator suspended by a cable is descending at a constant velocity?
Answers
The change in velocity for an elevator hanging by a cable that is falling at a constant speed is zero. As a result, there is no net acceleration. The tensile force T exerted by the cable pulling the elevator upward.
when moving down an elevator shaft at a constant speed?Newton's second rule states that the net force is acting on all of us must be zero because we are descending in the elevator at a constant speed, or Fret =0 F n e t = 0. Our weight (working downward) plus the natural force from our touch with the elevator floor are the only forces at play during the process (acting upward).
If the elevator went up and down at a steady speed, would the tension change?If the force applied is equal to the gravitational force provided it already has the upward velocity, it will move up with uniform velocity. The tension force gradually builds as the lift slowly rises before returning to its initial amount.
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a 0.350 kg block at -27.5 °C is added to 0.217 kg of water at 25.0 °C. they come to equilibrium at 16.4 °C. what is the specific heat of the block?
Answers
Answer:
\(C_{pb}=0.501\ kJ/kg.K\)
Explanation:
Given that
\(m_1=0.35 kg\)
\(T_1=-27.5^oC\)
\(m_2=0.214 kg\)
\(T_2=25^oC\)
\(T=16.4^oC\)
We know that
\(C_{pw}=4.187 kJ/kg.K\)
By using energy conservation
Heat lost by water = Heat gain by block
\(m_2\times C_{pw}\times (T_2-T)=m_1\times C_{pb}\times (T-T_1)\)
\(0.214\times 4.187\times (25-16.4)=0.35\times C_{pb}\times (16.4+27.5)\)
\(C_{pb}=0.501\ kJ/kg.K\)
Therefore the specific heat of the block will be 0.501 kJ/kg.K
What is units and dimensions? what are dimensions less quantities?
Answers
Answer:
A dimension is a measure of a physical variable.
Unit is a way to assign a number or measurement to that dimension.
In dimensional analysis, a dimensionless quantity is a quantity to which no physical dimension is assigned, also known as a bare, pure, or scalar quantity or a quantity of dimension one, with a corresponding unit of measurement is the SI of the unit one, which is not explicity shown.
A copper wire has a circular cross section with a raduis of 1.25mm. If the wire carries a current of 3.70A, find the drift speed of electron in this wire.
Answers
Answer: 0.043mm/s
Explanation:
The drift speed of electron in this wire will ba calculated as:
= I/nqA
= I/nqπr²
= 3.7/[(1.1 × 1^29) × (1.6 × 10^19) × (3.14 × 0.00125²)
= 4.3 × 10^-5
= 0.043mm/s
The drift speed of the electron in this wire is 0.043mm/s.
A simply supported beam carries UDL of 40 kNm over the whole span. The rectangular section is having depth as 500 mm. If omax = 120 N/mm² and 1=7x108 mm.Find span of the beam.
Answers
The span of the simply supported beam is approximately 17.32 meters.
To determine the span of the simply supported beam, we can use the formula for maximum bending stress in a rectangular section subjected to a uniformly distributed load (UDL):
σ_max = (w * L^2) / (8 * I)
Where:
σ_max is the maximum bending stress
w is the UDL (40 kNm = 40,000 N/m)
L is the span of the beam (unknown)
I is the moment of inertia of the rectangular section
Depth of the rectangular section (d) = 500 mm = 0.5 m
Maximum stress (σ_max) = 120 N/mm² = 120 MPa = 120 * 10^6 N/m²
Moment of inertia (I) = (b * d^3) / 12, where b is the breadth of the section (unknown)
We can rearrange the equation for maximum bending stress to solve for the span L:
L = √((8 * I * σ_max) / w)
Substituting the given values:
L = √((8 * (b * 0.5^3) / 12) * (120 * 10^6) / (40,000))
Simplifying:
L = √((2 * b * 0.5^3 * 3 * 10^6) / (4 * 10^4))
L = √((b * 0.5^3 * 3 * 10^6) / (2 * 10^4))
Squaring both sides:
L^2 = (b * 0.5^3 * 3 * 10^6) / (2 * 10^4)
L^2 = (b * 0.5^3 * 3 * 10^6) / (2 * 10^4)
Simplifying further:
L^2 = (b * 3 * 10^3) / 2
L^2 = (1.5 * b * 10^3)
Assuming a breadth of 200 mm (0.2 m) for the rectangular section, we can substitute this value into the equation:
L^2 = (1.5 * b * 10^3)
L^2 = (1.5 * 0.2 * 10^3)
L^2 = 300
Taking the square root of both sides:
L = √300
L ≈ 17.32 m
Therefore, assuming a breadth of 200 mm for the rectangular section, the span of the simply supported beam is approximately 17.32 meters.
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Calculate the change in the gravitational potential energy store of the following objects.
A cat with a mass of 3 kg climbs a tree, reaching a final height of 4.5 m (g = 9.8 N/kg).
Silver
Change in gravitational potential energy store =
Answers
Explanation:
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. ... Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height to which it is lifted. PE = kg x 9.8 m/s2 x m = joules.
So, the PE is
3 x 9.8 x 4.5 = 132.3 J
the fall of a body on the earth's surface cannot be a complete free fall why ?
Answers
Explanation:
because the boy has larger surface area due to which he offers the larger air resistance which decreases the acceleration so, he will fall towards the earth's surface approximately with constant velocity.
what is the necessary condition on the path length difference between two waves that interfere as follows
Answers
The necessary condition on the path length difference between two waves that interfere is that the path length difference must be an integer multiple of the wavelength.
This condition leads to constructive interference, where the two waves add up and result in an increased amplitude.
Step-by-step explanation:
Consider two waves with the same frequency and wavelength traveling towards each other.The path length difference between the two waves is the difference in the distance each wave travels before they meet.If the path length difference is an integer multiple of the wavelength (e.g. 0, λ, 2λ, 3λ...), the waves will meet at points where their phases match, causing constructive interference.On the other hand, if the path length difference is an odd-integer multiple of half the wavelength (e.g. λ/2, 3λ/2, 5λ/2...), the waves will meet at points where their phases are opposite, causing destructive interference.In summary, the necessary condition on the path length difference between two waves that interfere is that it must be an integer multiple of the wavelength for constructive interference to occur.Learn more about conditions are necessary: brainly.com/question/3406634
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what is the objective lens used for on a microscope
Answers
The objective lens is one of the key components of a microscope. It's a tiny lens that magnifies the specimen and projects it onto the eyepiece for further enlargement. In comparison to the eyepiece lens, the objective lens is much closer to the object being viewed, allowing for increased magnification and resolution.
The objective lens on a microscope is one of the most critical components. It's the lens that is closest to the sample being viewed and is primarily responsible for producing the image that you see when looking through the eyepiece. It serves to magnify the specimen and project it onto the eyepiece for further enlargement. This lens's power is generally measured in magnification, with the most typical magnifications ranging from 4x to 100x.Each objective lens is unique in terms of its magnification, and it can also differ in other aspects such as its working distance, resolution, and aperture. Higher magnification is ideal for viewing smaller structures, but it comes with a smaller working distance, making it more difficult to operate. On the other hand, a lens with a shorter working distance will enable you to view larger specimens.
In conclusion, the objective lens is a critical component of a microscope. It plays a crucial role in producing the image that we see and can magnify a specimen from 4x to 100x. The objective lens's power is not the only factor to consider when selecting a lens for a particular experiment, as working distance, resolution, and aperture can all play a role in the final image quality.
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It takes a lot of energy to move amounts of dirt and rocks. What do you think is the source of this energy?
Answers
Explanation:
gravity cuz it moves things to earth's surface,,, maybe
Answer:
DENSITY!
Explanation:
Earth changes all the time making it a __ planet.
Answers
a 25-kg child is sliding on an icy surface toward her mother at 3.0 m/s . her 72-kg mother starts toward her at 2.0 m/s , intending to catch her. part a what percentage of the original kinetic energy is convertible? activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type kconvki
Answers
63.39% of the original kinetic energy is convertible in this scenario.
To calculate the percentage of the original kinetic energy that is convertible, we need to determine the initial kinetic energy of the system and compare it to the final kinetic energy after the mother catches the child.
The initial kinetic energy (KE_initial) of the child is given by:
KE_child = 1/2 * mass_child * velocity_child^2
Substituting the given values:
mass_child = 25 kg
velocity_child = 3.0 m/s
KE_child = 1/2 * 25 kg * (3.0 m/s)^2 = 112.5 J
Similarly, the initial kinetic energy (KE_initial) of the mother is given by:
KE_mother = 1/2 * mass_mother * velocity_mother^2
Substituting the given values:
mass_mother = 72 kg
velocity_mother = 2.0 m/s
KE_mother = 1/2 * 72 kg * (2.0 m/s)^2 = 144 J
The total initial kinetic energy of the system is the sum of the child's and mother's initial kinetic energies:
KE_initial_total = KE_child + KE_mother = 112.5 J + 144 J = 256.5 J
Now, let's consider the final kinetic energy (KE_final) of the system after the mother catches the child. In this case, the final velocities of both the child and the mother will be the same since they are now moving together.
Let's denote the final velocity as v_final.
The final kinetic energy (KE_final) of the system is given by:
KE_final = 1/2 * (mass_child + mass_mother) * v_final^2
Substituting the given masses and final velocity:
mass_child = 25 kg
mass_mother = 72 kg
v_final = ?
To find the final velocity, we can use the principle of conservation of momentum:
(mass_child * velocity_child) + (mass_mother * velocity_mother) = (mass_child + mass_mother) * v_final
(25 kg * 3.0 m/s) + (72 kg * 2.0 m/s) = (25 kg + 72 kg) * v_final
75 kg·m/s + 144 kg·m/s = 97 kg * v_final
219 kg·m/s = 97 kg * v_final
v_final = 219 kg·m/s / 97 kg ≈ 2.2577 m/s
Now we can calculate the final kinetic energy:
KE_final = 1/2 * (25 kg + 72 kg) * (2.2577 m/s)^2 ≈ 162.62 J
The percentage of the original kinetic energy that is convertible can be found by taking the ratio of the final kinetic energy to the initial kinetic energy and multiplying by 100:
percentage = (KE_final / KE_initial_total) * 100
percentage = (162.62 J / 256.5 J) * 100 ≈ 63.39%
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PLEASE HELP!!
A pendulum swings back and forth 24 times in 8 seconds. What is its period? What is its frequency? Make sure to include your work and units on your answers.
Answers
The time period is 0.3 s and frequency is 3 Hz
Step 1 :
Given:
No. of cycles N = 24
Total time take t = 8 s
Step 1 : Calculating the frequency:
The frequency of a wave or oscillation is defined as the number of cycles or completed alternations per unit time.
f = N/t
f = 24/8
f = 3 Hz
Step 2: Calculating the time period:
Frequency and time period are inversely proportional.
The amount of time it takes for something to complete one oscillation is called its time period.
Time period = 1/Frequency
Time period = 1/3 = 0.3 s
So, the time period is 0.3 s and frequency is 3 Hz.
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Select the positive statement that would BEST counteract this negative statement: "I do not have the time to exercise." A. I can exercise anywhere. B. I have to start somewhere. C. I will make it a priority. D. I will increase my energy. Please select the best answer from the choices provided. A B C D
Answers
Answer:The awnser would be C!
Explanation:
Hope this helped!
Answer:
C. I will make it a priority.
Explanation:
a 22 g particle is moving to the left at 13 m/s . how much net work must be done on the particle to cause it to move to the right at 37 m/s ?
Answers
To cause the particle to move to the right at 37 m/s, the direction of its velocity must be changed, which means that work must be done on the particle.
The net work required can be calculated using the work-energy theorem, which states that the net work done on an object is equal to the change in its kinetic energy. Initially, the particle has a kinetic energy of (1/2)mv^2 = (1/2)(0.022 kg)(-13 m/s)^2 = 11.23 J.
To move the particle to the right at 37 m/s, its final kinetic energy will be (1/2)(0.022 kg)(37 m/s)^2 = 30.31 J.
Therefore, the net work required is equal to the change in kinetic energy:
net work = final kinetic energy - initial kinetic energy
net work = 30.31 J - 11.23 J
net work = 19.08 J
Thus, a net work of 19.08 J must be done on the particle to cause it to move to the right at 37 m/s.
The magnitude of the vertical velocity rises, but the horizontal velocity remains constant. The Y component determines how a projectile moves. The vertical component of velocity varies depending on whether a projectile is moving up or down, but it is always constant. The projectile is accelerated by gravity. Things fall to the earth faster as a result of gravity. The word "acceleration" describes a change in velocity, which is a calculation of the speed and direction of the motion. When anything falls for a longer period of time, gravity pushes it towards the earth more quickly, increasing its speed.
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What are some changes that can be caused by electromagnetic energy?
Answers
Answer:
cause the changes is the interaction with something. ... So the electromagnetic energy will have increased it's ...
Wavelength and frequency. Explanation: Electromagnetic energy is determined by wavelength and frequency. These are dependent on each other, so anything ... More
A student driving home for the holidays starts at 7:00 AM to make the 700km trip, practically all of which is on nonurban interstate highways. If she wants to arrive home no later than 5:00 PM, what must be her minimum average speed?
Answers
The student must maintain a minimum average speed of 70 km/h to arrive home no later than 5:00 PM.
To determine the minimum average speed the student must maintain to arrive home no later than 5:00 PM, we need to consider the total time available for the trip and the distance to be covered.
The student starts at 7:00 AM and wants to arrive home by 5:00 PM. This means she has a total of 10 hours available for the trip (from 7:00 AM to 5:00 PM).
The distance to be covered is 700 km.
To find the minimum average speed, we divide the total distance by the total time:
Minimum average speed = Total distance / Total time
Minimum average speed = 700 km / 10 hours
Minimum average speed = 70 km/h
Therefore, the student must maintain a minimum average speed of 70 km/h to arrive home no later than 5:00 PM.
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Particles q₁ = -75.8 μC, q₂ = +90.6 μC, and q1 q3=-84.2 μC are in a line. Particles q₁ and q₂ are separated by 0.876 m and particles q2 and q3 are separated by 0.432 m. What is the net force on particle qз?
Answers
The net force on particle q₃ is approximately 2576.08 N.
To calculate the net force on particle q₃, we need to consider the forces exerted on it by particles q₁ and q₂ due to their electrostatic interactions.
The electrostatic force between two charged particles can be determined using Coulomb's law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the formula for the electrostatic force (F) is:
F = (k * |q₁ * q₂|) / r²
Where k is the electrostatic constant (k ≈ 8.99 × 10^9 N m²/C²), q₁ and q₂ are the charges of particles q₁ and q₂, and r is the distance between them.
First, let's calculate the force between q₁ and q₂:
F₁₂ = (8.99 × 10^9 N m²/C² * |-75.8 μC * 90.6 μC|) / (0.876 m)²
Plugging in the values:
F₁₂ ≈ (8.99 × 10^9 N m²/C² * 6.87508 μC²) / (0.876 m)²
≈ 563.78 N
Next, let's calculate the force between q₂ and q₃:
F₂₃ = (8.99 × 10^9 N m²/C² * |90.6 μC * -84.2 μC|) / (0.432 m)²
Plugging in the values
F₂₃ ≈ (8.99 × 10^9 N m²/C² * 7.62012 μC²) / (0.432 m)²
≈ 3139.86 N
To find the net force on q₃, we need to subtract the force F₁₂ from F₂₃:
Net Force = F₂₃ - F₁₂
= 3139.86 N - 563.78 N
≈ 2576.08 N
Therefore, the net force on particle q₃ is approximately 2576.08 N.
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What is the total distance travelled? What is the displacement of the object?
Answers
if not triangle then 1/2 x (x x b) x h
if none of these questions are there then multiply time by position
hope this helped
how wide is the central diffraction peak (the distance between the dark spots on either side) on a screen 2.30 m behind a 0.0348-mm-wide slit illuminated by 558-nm light?
Answers
The width of the central diffraction peak in Young's double-slit experiment can be determined using the formula:
w = (λ * D) / d
Where:
w is the width of the central diffraction peak,
λ is the wavelength of light (558 nm or 558 × 10^(-9) m),
D is the distance between the slit and the screen (2.30 m), and
d is the width of the slit (0.0348 mm or 0.0348 × 10^(-3) m).
Plugging in the given values, we get:
w = (558 × 10^(-9) m * 2.30 m) / (0.0348 × 10^(-3) m)
Calculating the result:
w ≈ 0.0368 m
Converting to millimeters:
w ≈ 36.8 mm
Therefore, the width of the central diffraction peak, or the distance between the dark spots on either side, is approximately 36.8 mm.
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Which of the following is commonly used to measure distances in space?
Kilometers
The speed of light
Megameters
The speed of sound
Answers
Answer:
Light years or the speed of light
Explanation:
Answer:
speed of light
Explanation:
Suppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s after 20.0 seconds have elapsed. How long after the initial time has the wheel undergone half of the angular displacement that it will have gone through during the entire 20.0 second interval?
a. 10.0 s
b. 12.4 s
c. 14.2 s
d. 15.0 s
The answer is B, according to the textbook but I don't know why
Answers
To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:
ωf = ωi + αt --(1)
θ = ωit + 0.5αt^2 --(2)
where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.
Using equation (1), we can find the angular acceleration of the wheel:
α = (ωf - ωi)/t
= (30.0 rad/s - 10.0 rad/s)/20.0 s
= 1.0 rad/s^2
Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:
θ = ωit + 0.5αt^2
= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2
= 400.0 rad
To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:
θ/2 = ωit + 0.5αt^2
Rearranging and solving for t, we get:
t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α
Since we are looking for a positive time, we take the positive root:
t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2
≈ 12.4 s
Therefore, the answer is B, 12.4 s.
All weather stations have to make weather observations at the same time of the day.
True
False
Answers
Answer:
false
Explanation:
Answer:
True
Explanation:
The answer is true do not listen to the other person they will get you wrong just look at the votes between mine and the other person's (hint like my answer and rate 5 stars so other people know what to pick)
Find the instantaneous rate of change of the position function y=f(t) in feet at the given time t in seconds. f(t)=3t−7,t=1
Find the instantaneous rate of change of the position function y=f(t) in feet at the given time t in seconds.
f(t)=3t−7,t=1
Answers
The instantaneous rate of change of the position function y=f(t) in feet at the given time t in seconds. f(t)=3t−7,t=1 is as follow:
The function is f(t) = 3t - 7 and t = 1.
Using the concept of derivatives, the instantaneous rate of change of the position function y = f(t) in feet at the given time t in seconds is given by;
f'(t) = lim (h → 0) [f(t + h) - f(t)]/h
Now, we have f(t) = 3t - 7 and t = 1.
Substitute t = 1 in the above formula to get the instantaneous rate of change of the position function.
f'(1) = lim (h → 0) [f(1 + h) - f(1)]/h
Using the given function f(t) = 3t - 7,f'(1)
= lim (h → 0) [f(1 + h) - f(1)]/h
= lim (h → 0) [3(1 + h) - 7 - (3(1) - 7)]/h
= lim (h → 0) [3h]/h= 3
Therefore, the instantaneous rate of change of the position function y = f(t) in feet at the given time t = 1 second is 3 feet per second.
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In the order of increasing frequency, the electromagnetic spectrum may be arranged as
A.Gamma rays, X-rays, visible light, radio waves
B.X-rays, gamma rays, visible light, radio waves
C.Radio waves, visible light, X-rays, gamma rays
D.Radio waves, visible light, gamma rays, X-rays
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In the order of increasing frequency, the electromagnetic spectrum may be arranged as radio waves, visible light, X-rays, gamma rays.
Among all electromagnetic waves, radio waves have the lowest frequency. They have the least energy and are the longest waves. Radio waves are utilised for navigation as well as communication, including radio and television broadcasts.
The next highest frequency is visible light, which is more energetic than radio waves. The only form of electromagnetic radiation that the human eye can detect is visible light. It's employed for a range of activities, including photography, entertainment, and communication.
X-rays are more energetic and have a greater frequency than visible light. In medical imaging, X-rays are used to identify illnesses and wounds. They can also be used to find things that the human eye cannot see.
Of all electromagnetic waves, gamma rays have the highest frequency and most energy. In both scientific inquiry and medical procedures like radiation therapy, gamma rays are employed. They can also be used to find things that the human eye cannot see.
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I WILL MARK AS BRAINLIEST!! HELP PLEASE!! I know that the correct answer is C, but can someone please explain it?
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Answer:
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