The persistence of sound after the source of the sound has ceased, as a result of repeated reflections is called

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Answer 1

The persistence of sound after the source of the sound has ceased, as a result of repeated reflections, is called "reverberation."

Reverberation is the persistence of sound in an enclosed space after the sound source has stopped emitting sound. It is caused by sound waves reflecting off surfaces and bouncing back and forth between them, creating a complex pattern of overlapping sound waves.

Reverberation affects the quality of sound in a space and can have a significant impact on our perception of it. The amount of reverberation in a space is determined by the size and shape of the space, as well as the materials of the surfaces within it. In a reverberant space, sounds may be perceived as muddled or unclear, making it difficult to distinguish individual sounds or voices.

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Related Questions

describe the motions of a baseball thrown from a height of 10 ft versus a ball that was just dropped from a height of 10 ft at the same time.

Answers

When comparing the motions of a baseball thrown from a height of 10 ft and a ball that is simply dropped from the same height, there are distinct differences.

The thrown baseball exhibits a combination of vertical and horizontal motion. It follows a curved path due to the initial throwing velocity and the force of gravity, resulting in a parabolic trajectory. In contrast, the dropped ball experiences only vertical motion, falling straight down toward the ground in a vertical line. While both objects are affected by gravity, the thrown baseball's additional horizontal velocity allows it to cover a longer distance and follow a more complex path compared to the vertically descending dropped the ball.

Therefore, the thrown baseball exhibits both vertical and horizontal motion, following a curved trajectory due to the combination of the initial throwing velocity and the force of gravity. The dropped ball, on the other hand, experiences only vertical motion, falling straight down toward the ground along a vertical line.

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Consider optical absorption. Mark the correct statement(s). Absorption can only occur if the photon energy is larger than the energy gap of a semiconductor. Absorption can only occur if the photon energy is less than the energy gap of a semiconductor. Absorption is strongest if the photon energy matches the energy difference between the centers of the valence and conduction band. Absorption is strongest if the photon energy matches the energy difference between the band edges of valence and conduction band.

Answers

Consider  optical absorption, the correct statement is that a. absorption can only occur if the photon energy is larger than the energy gap of a semiconductor.

This is because when a photon with sufficient energy interacts with a semiconductor material, it can excite an electron from the valence band to the conduction band, creating an electron-hole pair. The photon must have energy equal to or greater than the bandgap energy for this process to occur. If the photon energy is less than the energy gap, it cannot excite the electron, and absorption will not take place.

Additionally, absorption is strongest when the photon energy matches the energy difference between the band edges of the valence and conduction bands, this is due to the density of available states for the electron to occupy, as it is more likely to find an empty state to transition into at the band edges. As the photon energy matches this energy difference, the probability of absorption increases, leading to stronger absorption in the semiconductor material. So therefore in optical absorption, a. absorption can only occur if the photon energy is larger than the energy gap of a semiconductor. is the correct statement.

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A cheetah is running at 25 m/s has a momentum of +170 kg*m/s. What is the mass
of the cheetah? *

Answers

Answer:

6.8kg

Explanation:

170/25=6.8

while standing at a crosswalk, you hear a frequency of 560 hz from an approaching police car. after the police car passes, its frequency is 480 hz. what is the speed of the police car? (speed of sound

Answers

We can presume that an ambulance with its siren activated is rushing to get somewhere and, depending on the driving circumstances, is likely travelling between 30 and 150 km/h. The vehicle's speed can be determined using the Doppler effect equation. Let va represent the ambulance's maximum speed. The frequency, f'=(vvv a)f=560Hz, is audible as it gets closer.

Because the source is travelling in the direction of the observer, a negative sign appears. The ambulance is described as moving away by the opposite sign with source velocity magnitude. The Doppler shifted frequency as it recedes is f')=(vv+v0)f=480Hz.

The speed of the source can be calculated as va=v(f'f')f'+f'=(343ms)(560Hz480Hz)560Hz+480Hz=26.4ms by solving the second of these equations for f and substituting into the other.

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Levi drove south for two hours. The trip was 160 kilometers long. Halfway there, he looked at his spedometer and saw 40 km per hour. What was his instantaneous speed at that time?

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Levi's instantaneous speed at the moment he looked at his speedometer was 80 km/h, which is consistent with his average speed for the entire trip.

If Levi drove south for two hours and covered a distance of 160 kilometers, then his average speed for the entire trip was:

average speed = total distance / total time = 160 km / 2 h = 80 km/h

Let d(t) be the distance that Levi has driven at time t. Then we have:

d(0) = 0 (starting position)

d(2) = 160 km (final position)

d(1) = 80 km (distance traveled halfway through the trip)

The average speed between time t1 and t2 is given by:

average speed = (d(t2) - d(t1)) / (t2 - t1)

At time t=1, we have:

average speed = (d(2) - d(1)) / (2 - 1) = (160 km - 80 km) / 1 h = 80 km/h

This is consistent with the earlier calculation of the average speed for the entire trip.

The instantaneous speed at time t=1 is given by the derivative of the distance function with respect to time:

instantaneous speed = d'(1)

Using calculus, we can find:

d(t) = 40t^2

d'(t) = 80t

Therefore, the instantaneous speed at time t=1 is:

instantaneous speed = d'(1) = 80 km/h

So Levi's instantaneous speed at the moment he looked at his speedometer was 80 km/h, which is consistent with his average speed for the entire trip.

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If a distance-time graph contains the point (4, 15), what does that tell you about the runner?

If a distance-time graph contains the point (4, 15), what does that tell you about the runner?

Answers

Explanation:

It is given that there is distance time graph. The slope of any distance time graph will give the speed or velocity of the object.

In the context, it is seen that there is a point in the distance - time graph. And the values of the point in the graph is (4,15).

Now here, the distance is plotted in the  ordinate or the vertical y-axis while time is plotted in the abscissa or the horizontal x-axis.

Thus the point (4,15) tells us that the object has traveled 15 units in time equal to 4 seconds.

in a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. a second projectile (of the same mass) causes the the pendulum to swing twice as high, 5.2 cm.

Answers

The second projectile is 1.4 times faster than first projectile.

Initial velocity of projectile is proportional to the square root of height covered by pendulum.

From the question, we have

U_2/U_1  =√(h_2/h_1 )

U_2 =√(h_2/h_1 )×U_1

U_2 =√(5.2/2.6)×U_1

U_2= 1.41U_1

The second projectile is 1.4 times faster than first projectile.

Projectile:

The object that is propelled by the application of an external force and then moves freely while being affected by gravity and air resistance is referred to as a projectile. Despite the fact that all items traveling through space are projectiles, they are frequently used in sports and warfare.

Complete question:

In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second projectile (of the same mass) causes the the pendulum to swing twice as high, h2 = 5.2 cm. The second projectile was how many times faster than the first?

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A car starts from rest, then accelerates at 1.20 m/s2 for 7.00 s. It hits the brakes,
slowing to a stop at a rate of -4.25 m/s2.
What is the total distance travelled?

Answers

Answer:

the answer is 4.15 m/s2

Explanation:

4.15 m/s2

A resistor with a potential difference of 15.0 V develops a heat output of 327 W.
a) What is its resistance?
b) What is the current across the resistor?

Answers

Answer:

V = I * R        voltage drop

P = I * V = I^2 * R        power

I = P / V = 327 / 15 = 21.8 amps

b)   I = 21.8 amps

a) R = P / I^2 = 327 / 21.8^2 = .69 ohms

Check:

V = I R = 21.8 * .69 = 15 Volts

A weightlifter lifts a weight with 100N of force. He raises it over his head to a level of five meters. How much work has he done.

Answers

The work done by the weightlifter to raise the weight is 500 J. The work is calculated in Joules.

What is work?

It can be defined as the product of the force applied and the displacement.

\(W = Fx\)

where,

\(F\)- force = 100 N

\(x\)- displacement = 5 m

Put the values in the formula,

W = 100 x 5

W = 500 J

Therefore, the work done by the weightlifter to raise the weight is 500 J.

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6. which of these factors affect the magnetic field produced by a thin circular coil? (choose all that apply) a. the number of turns that make up the coil. b. the radius of the coil. c. the resistance of the circuit. d. the air pressure around the coil.

Answers

uo(i2)R describes the magnetic field.Permiability is uo. I is for current, R is for radius.Uo is pressure-dependent.The coil's resistance and turn count are the solution.

A magnetic field, which is a vector field, has an impact on magnetic materials, electric charges, and electric currents in a similar manner. A moving charge in a magnetic field is subject to a force that is perpendicular to the magnetic field and has its own speed.

The current I is flowing through a circular coil A, which has the radius R. If 2I is the current flowing through another circular coil B with radius 2R, then the magnetic field at the center of the coil is in the ratio of (i.e., BA to BB).

An electrical circuit's restriction to current flow is measured in terms of resistance. The Greek letter omega (Ω) represents resistance, which is measured in ohms.

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Suppose you calculated the speed of light in an unknown substance to be 4.00x10^8 m/s. How could you tell if you made an error in your calculations​

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Answer: You could tell if you made an error in your calculations by repeating the steps.

Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.

Explanation:

Radiation present in the environment but not produced by humans is called ______.

Answers

Answer:

background

Explanation:

In which scenario will the two objects have the least gravitational force between them? A. Mass of object 1 = 12 kg Mass of object 2 =12 kg Distance between objects =1.5 m B. Mass of object 1 =15 kg Mass of object 2 = 12 kg Distance between objects =1.5 m DC. Mass of object 1 = 15 kg Mass of object 2= 12 kg Distance between objects = 0.5 m ()D. Mass of object 1 =12 kg Mass of object 2=12 kg Distance between objects = 0.5 m​

Answers

If both objects have a mass of 12 kg and are separated by 1.5 m, scenario A would have the least gravitational pull on them. (option-a)

The gravitational pull between any two objects is determined by both their masses and their separation from one another. The force of gravity is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects, according to Newton's law of universal gravitation.

We must choose the scenario with the least gravitational force among the ones provided. Let's examine each instance:

A. The weights of the first and second objects are each 12 kg, and their separation is 1.5 m.

B. Mass of object 1 = 15 kg, Mass of object 2 = 12(option-a)

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if the intensity at the center of a single-slit diffraction pattern is 1.00 w/cm2, what is the intensity (in mw/cm2) at a point in the pattern where there is a 41.1 rad phase difference between the waves from the top and the bottom of the slit?

Answers

If the intensity at the center of a single-slit diffraction pattern is 1.00 w/cm2, the intensity (in mw/cm2) at a point in the pattern where there is a 41.1 rad phase difference between the waves from the top and the bottom of the slit is 0 mw/cm2

To calculate the intensity at a point in a single-slit diffraction pattern, we use the equation for the intensity of a diffraction pattern:

\(I = (I_0)(sin(alpha)/alpha)^2\)

where I_0 is the intensity at the center of the pattern, alpha is the angle between the center of the pattern and the point where we want to calculate the intensity, and the sine function accounts for the interference between the waves from different parts of the slit.

In this problem, we are given the intensity at the center of the pattern, I_0 = 1.00 W/cm^2, and we are asked to find the intensity at a point where the phase difference between the waves from the top and bottom of the slit is 41.1 radians. To use the equation above, we need to find the angle alpha

The phase difference between the waves from the top and bottom of the slit is related to the angle alpha by:

delta_phi = 2pid*sin(alpha)/lambda

where delta_phi is the phase difference, d is the width of the slit, and lambda is the wavelength of the light. Solving for sin(alpha) gives:

sin(alpha) = (lambdadelta_phi)/(2pi*d)

We are not given the value of lambda, but we can assume that it is in the visible range of the spectrum, which is around 400-700 nm. Let's use lambda = 500 nm. The width of the slit is not given, so we'll assume a typical value of d = 0.1 mm = 0.01 cm.

Plugging in these values into the equation for sin(alpha), we get:

sin(alpha) = (500 nm * 41.1 rad) / (2pi0.01 cm) = 3.32

However, this value is greater than 1, which is not possible for a sine function. This means that the point where the phase difference is 41.1 radians is outside the range of the diffraction pattern, and the intensity at this point is effectively zero.

Therefore, the answer is 0 mW/cm^2.

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when is work said to be done? ​

Answers

Answer:

Work is said to be done when there is change in the position of the object due to the force applied on it.

Explanation:

Hope this helped! Nya~ :3

A baseball player throws a baseball at 42 m/s. If the other player catching the baseball is 18 m from the player, how much time does it take the baseball to reach him?

Answers

Divide the distance by the speed:

(18 m) / (42 m/s) = 3/7 s ≈ 0.43 s

can someone pls help me answer both of these (its ok if u only do one). ILL GIVE A BRANIEST TO WHOEVER CAN GET IT RIGHT. thank you! :)

can someone pls help me answer both of these (its ok if u only do one). ILL GIVE A BRANIEST TO WHOEVER

Answers

Answer:

for number 1 i got 100

Explanation:

A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?

Answers

Answer:

\( \boxed{\sf Distance \ travelled = 62.5 \ m} \)

Given:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\( \boxed{ \bold{s = (\frac{v + u}{2} )t}}\)

By substituting value of v, u & t in the equation we get:

\( \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m\)

\( \therefore\)

Distance travelled by car (s) = 62.5 m

The distance  car travel during that time is 62.5 meter.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Initial velocity (u) = 25 m/s

As the car becomes rest, final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds.

The deceleration of the car: a = (initial speed - final speed)/time interval

= ( 25 m/s - 0 m/s)/5 second

= 5 m/s²

The distance  car travel during that time = ut - at²/2

= 25 × 5.0 meter - (5×5²/2) meter

= 62.5 meter.

Hence, the distance  car travel during that time is  62.5 meter.

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Two liquids A and B of relative densities 0.7 and 0.4 respectively are mixed with water, kl. How will the mixture. arrangement occur in a given container?

Answers

The liquid A is present lower in the container as compared to liquid B due to more weight.

How will the mixture. arrangement occur in a given container?

If two liquids A and B of relative densities 0.7 and 0.4 respectively then the lower density liquid remain at the top and higher density solution which is liquid A remains lower in the container because higher density solution has more weight.

So we can conclude that the liquid A is present lower in the container as compared to liquid B due to more weight.

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according to newtons first law the motion of an object does not change if the net force acting on it is zero

Answers

Answer:free coins grinding up get rekts LOl

Explanation:

1. Calculate the average velocity of the following trip. You walk to Pershing Square 58
meters South and 135 meters West. The trip took 12 minutes. What is your velocity in
meters/second?

Answers

Explanation:

Velocity = displacement / time

v = √((58 m)² + (135 m)²) / (12 min × 60 s/min)

v = 0.20 m/s

what is the name of the variable that is set by the scientist in an experiment?

A. The independent variable
B. The dependent variable
C. The graphing variable
D. The stable variable

I'm not smart so I have no clue​

Answers

Answer:

The independent variable is the one that is changed by the scientist. To insure a fair test, a good experiment has only ONE independent variable. As the scientist changes the independent variable, he or she records the data that they collect.

Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established. Please select the best answer from the choices provided T F

Answers

The statement 'establishing a high critical value in a statistical test is associated with more confidence' is TRUE.

What is statistical significance?

The statistical significance is a arbitrary value used to indicate that data collected can be used to confirm (or reject) my working hypothesis.

The most widely used value to measure the statistical significance is the p threshold.

In conclusion, the statement 'Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established' is TRUE.

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Answer:

The answer is F or false

Explanation:

correct edge 2023

an electron is accelerated through 2600 v from rest and then enters a uniform 1.00 t magnetic field. (a) what is the maximum value of the magnetic force this charge can experience?

Answers

The maximum value of the magnetic force this charge can experience is 2.42 x 10^-14 N.

How to calculate the maximum value of the magnetic force?

To calculate the maximum value of the magnetic force experienced by the electron, we need to use the equation:

F = qvB

where F is the magnetic force, q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field strength.

The charge of an electron is -1.602 x 10^-19 C, the velocity of the electron after acceleration is:

v = sqrt((2qV)/m)

where V is the potential difference, q is the charge of the electron, and m is the mass of the electron.

Plugging in the values, we get:

v = sqrt((2 x (-1.602 x 10^-19 C) x (2600 V)) / (9.109 x 10^-31 kg))

v = 1.51 x 10^7 m/s

Now we can calculate the maximum magnetic force experienced by the electron:

F = (-1.602 x 10^-19 C) x (1.51 x 10^7 m/s) x (1.00 T)

F = -2.42 x 10^-14 N (the negative sign indicates that the force is in the opposite direction to the velocity of the electron)

So the maximum value of the magnetic force this charge can experience is 2.42 x 10^-14 N.

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Matter cant be created or destroyed
true
false

Answers

Answer: True

no matter can be created nor destroyed in any process. if something is burned, made in a compound or anything like that all matter is still the same amount from beginning to end.

Explanation:

The correct answer would be True

There are some points on a standing wave that never move. What are these points called?.

Answers

Answer:

A common term is "nodes", also minimums.

Answer and I will mark Branliest!!!
3. _____________is a means of creating force leading to movement. *


A. Propulsion

B. Dialysis

C. Magnification

D. Osmosis

Answer and I will mark Branliest!!!3. _____________is a means of creating force leading to movement.

Answers

A. Propulsion is the answer

Answer:

propulsion

Explanation:

What do psychologists used to assist them in diagnosing abnormal behavior?

Answers

Ok so it usually includes the evaluation of symptom and disorder severity, patterns of symptoms over time number, frequency, and duration of episodes, and the patient's strengths and weaknesses.

Given the circuit above, the instant the switch is closed, the voltage across the capacitor is.

Answers

Given the circuit above, the instant the switch is closed, the voltage across the capacitor is 1.5 volts.

How do we calculate?

The switch in this circuit is originally open. The capacitor begins to charge when the switch is closed.

When capacitors in a DC circuit achieve their steady-state, they behave like an open circuit and last for a very long time.

Since there is no current flowing through the capacitor, this indicates that the voltage across it is the same as the value across the resistor.

The resistor's voltage in this instance is specified as 1.5V.

As a result, after a long period of time with the switch closed, 1.5V would likewise be present across the capacitor.

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