The picture shows an object resting on a balance.

The object on the balance weighs 0.500 kilograms.

The weight of an object is given by F = mg, where g = 9.8 m/s2. With what force does the object push down on the balance?

Choose the correct answer.


9.3 kg⋅m/s2
9.3 kg⋅m/s, 2

9.8 kg⋅m/s2
9.8 kg⋅m/s, 2

4.90 kg⋅m/s2
4.90 kg⋅m/s, 2

0.500 kg⋅m/s2
0.500 kg⋅m/s, 2
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The time it takes the hockey player to catch his opponent is 8.2s and he has he traveled 130m in that time.

A defenseman's main goal is to keep the team with the puck from scoring into their net. Therefore, the defensemen will frequently step up and stop the puck-bearing team from moving it into their defensive zone when they are skating through the neutral zone. The dump and chase tactic is used in this situation.

a) The given data is:

v = 4 m/s

t = 2.8 s

d=?

Use the formula:

v = d/t....(i)

Put the value of given data in equation (i)

d = v × t

d = 4 m/s × 2.8 s

d = 130 m

Thus, distance will be 8.2 s

Ice hockey skates are typically used for leisure ice skating by themselves, but they can also be used for the sports of ice hockey and ringette. The components of each individual skate are the boot, laces, blade, and blade holder.

b)

d = 8.2 s

t = 2.80 s

Use the formula:

v = d/t....(i)

Put the value of given data in equation (i)

d = v × t

d = 4 m/s × 8.2 s

d = 8.2 s

Thus, distance will be 8.2 s

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Answer:

Yes

Explanation:

Yes. The momentum is the same when the speed of the tennis ball is 18 times greater than the speed of the basketball and the velocities of both objects are in the same direction.

Answer:

c

Explanation:

Answer:

c

Explanation:

im smart

Answer:

She can make have 30 jars with raspberries in them with 50 left over.

Explanation:

1,700 divided by 55

30 equally

but 50 left over

This means that she can make have 30 jars with raspberries in them with 50 left over.

Answer:

(1) 1000 N (2) 1 m/s²

Explanation:

(1) Given that,

The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal force acting on the car. The magnitude of the centripetal force is given by :

\(F=\dfrac{mv^2}{r}\\\\F=\dfrac{1000\times (10)^2}{100}\\\\F=1000\ N\)

So, the correct option is (c) i.e. 1000 N

(2).The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal acceleration of the car. The magnitude of the centripetal acceleration is given by :

\(a=\dfrac{v^2}{r}\\\\a=\dfrac{(10)^2}{100}\\\\a=1\ m/s^2\)

So, the correct option is (b) i.e. \(1\ m/s^2\)

Answer:

E_{total} = -1.13 10² N / C

the sign indicates that the electric field points to the left

Explanation:

Let's start this exercise by looking for the electric field created by an infinite leaf, for this let's use Gauss's law

       \(\Phi_E\) = ∫ E. dA = \(q_{int}\) /ε₀

Let's define a Gaussian surface that is a cylinder, the normal to the faces of the cylinder is parallel to the field created by the face inside the surface, the normal of the cylinder walls is perpendicular to the electric field so its scalar product is zero

            \Phi_E = E (2A) = q_{int} /ε₀

the number 2 is due to having two faces

            E =    \(\frac{q_{int} }{A} \ \frac{1}{2 \epsilon_0 }\)

the surface charge density is

            σ= Q / A

we substitute

             E = \(\frac{\sigma }{2 \epsilon_o}\)

we can see that the field is independent of the distance.

Let's write the field for each leaf, remember that the field is salient for positive charges

sheet 1

           E₁ = \(+ \frac{\sigma_1}{2 \epsilon_o}\)

sheet 2

           E₂ = \(- \frac{\sigma_2}{2 \epsilon_o}\)

sheet 3

           E₃ = \(+ \frac{\sigma_3}{2 \epsilon_o}\)

at the point the Field of sheet 1 points to the right,

the field on sheet 2 points to the left and the field on sheet 3 points to the left.  Tthe electric field at the midpoint is

           E_ {total} = E₁ - E₂ - E₃

            E_ {total} = \(\frac{1}{2 \epsilon_o}\)  (σ₁ - σ₂ -σ₃)

calculate

             E_total = \(\frac{1}{2 \ 8.85 \ 10^{-12}}\)   (8.00 -4.00 -6.00) 10⁻⁹

             E_total = -1.13 10² N / C

the sign indicates that the electric field points to the left

Answer:

See Explanation

Explanation:

Temperature affects the amount of sugar that will be dissolved in a liquid. It is general knowledge in chemistry that solutes tend to dissolve in hot solvents compared to cold solvents.

Hence, there is a positive relationship between dissolution of sugar in a liquid and increase in temperature.

To test this hypothesis, the variables are temperature and amount of solute. The volume of solvent and type of solvent must be held constant.

Different amounts of solute are dissolved in the same volume of solvent and heated to a constant temperature and the extent of dissolution of the sugar is observed for each experimental unit.

A control experiment is also set up in which different amount of sugar is dissolved in the same volume of solvent as above without heating and the results are compared.

The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

A hiker approaches a region with many enormous, mature trees and just a variety of other mature bushes and plants. The ecosystem is best describe by the "climax community."

In ecology, the term "climax" refers to the last stage that biotic succession that a plant community can reach in a region depending on the environmental factors in place at the time.

A hiker approaches a region with many enormous, mature trees and just a variety of other mature bushes and plants.

Thus, this ecosystem is best describe by the "climax community."

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The correct question is-

A hiker enters an area where there are large mature trees and a diverse population of other mature plants and shrubs.

Which statement best describes this ecosystem?

It is a climax community.

It is populated with pioneer plants.,

It features many opportunists.,

Answer: c

Explanation:

The period of oscillation of a torsional pendulum is T = 2π √(1/2 * MR^2 / k).

The period of oscillation of a torsional pendulum can be expressed as:

T = 2π √(I / k)

where;

The moment of inertia of the pendulum depends on its shape and mass distribution. For a simple pendulum consisting of a uniform disk of radius R and mass M suspended from a torsional spring at a distance L from its center, the moment of inertia can be expressed as:

I = 1/2 * MR^2

The torsion constant of the pendulum, k, is a measure of the resistance of the spring to twisting and can be determined experimentally.

Substituting the moment of inertia and torsion constant into the expression for the period of oscillation, we get:

T = 2π √(1/2 * MR^2 / k)

Therefore, the period of oscillation of a torsional pendulum depends on the moment of inertia of the pendulum and the torsion constant of the spring.

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The change in the internal energy of the gas is 49.8 J.

The work done in compressing the gas by the force applied on the piston is calculated as follows;

W = Fd

where;

W = 62 N x 0.9 m

W = 55.8 J

The change in the internal energy of the gas is calculated as follows;

ΔU = - Q + W

where;

ΔU = -6 J  +  55.8 J

ΔU = 49.8 J

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Answer:

heat energy is transferred from the arm iron to the cooler room. BRAINLIEST ANSWER

The total distance of Bella's trip through the jungle is 24 kilometers.

To find the total distance of Bella's trip, we need to calculate the distance traveled during each leg of her journey and then sum them up.

Let's calculate the distance traveled in each segment:

Trekking in the thick jungle:

Bella trekked for 1 hour at an average speed of 6 km/h.

Distance = Speed × Time

Distance = 6 km/h × 1 hour

Distance = 6 km

Crossing the lake by boat:

Bella rode a boat at an average speed of 20 km/h for 0.5 hours.

Distance = Speed × Time

Distance = 20 km/h × 0.5 hour

Distance = 10 km

Hiking for the remaining part:

Bella hiked for 2 hours at an average speed of 4 km/h.

Distance = Speed × Time

Distance = 4 km/h × 2 hours

Distance = 8 km

Now, let's calculate the total distance:

Total distance = Distance of trekking + Distance of crossing the lake + Distance of hiking

Total distance = 6 km + 10 km + 8 km

Total distance = 24 km

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When a ball is dropped from a height, its velocity increases linearly due to gravity.

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Answer:

it make your immune system build up from the strain your puting on you body

Explanation:

excercise is good for you  and builds muscle and blood cells

The boy's speed as he passes through the lowest point of the swing is 8.8 m/s.

To solve this problem, we can use the conservation of energy. At the lowest point of the swing, the boy has the maximum gravitational potential energy and no kinetic energy. At the highest point of the swing, he has the maximum kinetic energy and no gravitational potential energy.

Since the energy of the system is conserved, the sum of the gravitational potential energy and kinetic energy must remain constant throughout the swing. Let's call the speed of the boy as he passes through the lowest point of the swing "v".

At the lowest point, the gravitational potential energy is given by:

mgh = (1/2)mv²

where m is the mass of the boy, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height of the lowest point above the ground (6 m - 2 m = 4 m).

Solving for v:

v = √(2gh) = √(2 x 9.8 x 4) = √(77.76) = 8.8 m/s

So the boy's speed as he passes through the lowest point of the swing is approximately 8.8 m/s.

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Answer:

proton and neutrons

Explanation:

electron has negligible mass

Answer:

Explanation:

The mass of the ball can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

We have

\(m = \frac{15}{5} = 3 \\ \)

We have the final answer as

Hope this helps you

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Ender's initial velocity was approximately 61.43 m/s, and Shen's initial velocity was approximately -100 m/s

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. We can write the equation as follows:

m1v1 + m2v2 = (m1 + m2)vf

where m1 and m2 are the masses of Ender and Shen, respectively, v1 and v2 are their initial velocities, vf is their final velocity after the collision, and we assume that the collision is perfectly elastic, which means that no kinetic energy is lost.

Substituting the given values, we get:

(70 kg)(v1) + (60 kg)(-v2) = (70 kg + 60 kg)(5 m/s)

Simplifying and solving for v1, we get:

v1 = [(70 kg + 60 kg)(5 m/s) + (60 kg)(-v2)] / 70 kg

v1 = (650 m/s + 60 kg v2) / 70 kg

Since we don't know the initial velocity of Shen, we cannot solve for v2 directly. However, we can use the fact that the two hold onto each other after the collision, which means that they move with the same final velocity vf. Thus:

vf = (m1v1 + m2v2) / (m1 + m2)

5 m/s = (70 kg v1 + 60 kg v2) / (70 kg + 60 kg)

Substituting the expression we obtained for v1 in terms of v2, we get:

5 m/s = [70 kg ((650 m/s + 60 kg v2) / 70 kg) + 60 kg v2] / (70 kg + 60 kg)

Simplifying and solving for v2, we get:

v2 = -100 m/s

Substituting this value in the expression we obtained for v1, we get:

v1 = (650 m/s + 60 kg (-100 m/s)) / 70 kg

v1 = 4300 / 70 m/s

v1 = 61.43 m/s

Therefore, Ender's initial velocity was approximately 61.43 m/s, and Shen's initial velocity was approximately -100 m/s.

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Answer:

Option C.

Impulse = mass × change in velocity

Explanation:

Impulse is defined by the following the following formula:

Impulse = force (F) × time (t)

Impulse = Ft

From Newton's second law of motion,

Force = change in momentum /time

Cross multiply

Force × time = change in momentum

Recall:

Impulse = Force × time

Thus,

Impulse = change in momentum

Recall:

Momentum = mass x velocity

Momentum = mv

Chang in momentum = mass × change in velocity

Change in momentum = mΔv

Thus,

Impulse = change in momentum

Impulse = mass × change in velocity

Explanation:

5.4 m = 1s2

? = 784 s2

(5.4 * 784)/1

= 4,233.6 m/s2

Answer:

It is not possible to calculate the time it took to go up to 3 meters.

Explanation:

There are all forces that apply to this situation like gravity, friction, torque, and efficiency. To answer this question, I might need the specifications given before to answer this question.

Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

 Goodluck

Explanation:

The answer is m ≥ d μ g / v^2.

To keep the sled moving in a circular path, the force of tension in the string must be equal to the centripetal force on the sled. Let T be the tension in the string and v be the speed of the sled. Then, the centripetal force is:

F_c = m v^2 / d

Since the string passes through the center of the pole, the vertical component of tension T_v balances the weight of the snowman and sled, which is m g, where g is the acceleration due to gravity. Therefore:

T_v = m g

The horizontal component of tension T_h provides the centripetal force. The horizontal displacement of the bear is L - d, so the magnitude of T_h is:

T_h = F_c = m v^2 / d

The maximum value of static friction is μ times the normal force, which in this case is equal to T_v. Therefore, the maximum value of static friction is:

f_s = μ T_v

For the motion to be possible, the horizontal component of tension T_h must be less than or equal to the maximum value of static friction f_s. Therefore:

T_h ≤ f_s

Substituting the expressions for T_h and f_s, we get:

m v^2 / d ≤ μ m g

Solving for the minimum mass of the bear, m, we get:

m ≥ d μ g / v^2

The answer: m ≥ d μ g / v^2.

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A. The overpressure at the bottom of the tank is 297500 N/m².

B. The magnitude of the net force acting on the square access hatch at the bottom of the tank is 107100 N.

Multiplying the flow rate by the minimum operating time of the pump gives the descending capacity. As a rule of thumb for a minimum run time, a pump operating at 10 gallons per minute GPM or less should produce a run time of 1 gallon per minute. For example, 10 GPM flow rate x 1 = 10 gallon drawdown capacity.

This means that the gauge pressure is equal to the absolute pressure minus the atmospheric ambient pressure. If the absolute pressure is greater than the atmospheric pressure it is called positive overpressure. If the absolute pressure is lower than atmospheric pressure it is called negative overpressure. The hydrostatic pressure at any height below water is calculated by P = hdg. where h is the height below open water.

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Answer:

C is not true because Kinetic Energy is directly proportional to the Temperature

After separation, the pairs of spheres' total charges will be in the following order: Qa -> Qc -> Qb.

As specified in the query, here

Each pair is introduced, allowed to touch, and then separated.

which refers to payment via sharing.

The charge by sharing formula is Q = Q1 + Q2 / 2.

As a result, Pair A

Qa = +6+(+2)/2 = 4 represents the total charge for each pair.

Pair B

Qb = +6+(-2)/2 =2.

Pair C

Qc = +6+(0) / 2 =3.As a result, Qa -> Qc -> Qb will be the order of the total amount of charge on the pairs of spheres after separation, from greatest to least.

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Answer:

A

Explanation:

this is because 2×8×20=320