the sum of her test scores 88+80=168 also she took 2 tests. her average would be?

the answer should be written in the form of coordinates.

Asap pls

Answer:

2/8 which simplifies to 0.111111

Step-by-step explanation:

Answer:

100. ~113

x ~ 5763(assume that X is price without VAT)

100×5763=113×x

X. =(5763×100)/113. (5763/113=51)

X= 51×100

X =5100

VAT=5763-5100

=RS.663

Given:

Interest rate,

Object price,

The value added tax will be:

→ \(\frac{13 \ percent}{100+13} = \frac{VAT}{5763}\)

→       \(VAT = 5763\times \frac{0.13}{1.13}\)

                 \(= 663\)

Thus the approach above is right.  

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Answer:

Step-by-step explanation:

12 kg of flour for 3 kg of baking powder

so 1 kg of flour = 3/12 or 1/4 of baking powder

180 kg of flour = \(\frac{1}{4}\) × 180 kg of baking powder

= 45 kg of baking powder for 180 kg of flour

please give me a brainliest answer

Step-by-step explanation:

Step-by-step explanation:

12 kg of flour for 3 kg of baking powder

so 1 kg of flour = 3/12 or 1/4 of baking powder

180 kg of flour = 14\frac{1}{4}

4

1

× 180 kg of baking powder

= 45 kg of baking powder for 180 kg of flour

please give me a brainliest answer

Answer:

the answer is 3

Step-by-step explanation:

b will be used to determine how many books he bought since he is only buying one movie ticket the equation would be 3b + 10 = 35

It is important to check for multicollinearity in a regression model and take steps to reduce it, such as removing one of the highly correlated independent variables or using regularization techniques.

Multicollinearity is a statistical phenomenon where two or more independent variables in a regression model are highly correlated with each other. This can cause problems in the regression model as it becomes difficult to distinguish the individual effects of the independent variables on the dependent variable.
When multicollinearity is present in a regression model, the p-values of the slopes of the independent variables are affected. The p-value measures the probability of obtaining a result as extreme or more extreme than the observed result, assuming that the null hypothesis is true. The null hypothesis in a regression model is that the slope of the independent variable is zero, meaning that there is no relationship between the independent variable and the dependent variable.
Multicollinearity can cause the standard errors of the slopes to increase, leading to inflated p-values. In other words, the significance of the relationship between the independent variable and the dependent variable may be underestimated. This is because the highly correlated independent variables are both trying to explain the same variation in the dependent variable, leading to an unreliable estimate of the effect of each independent variable on the dependent variable.
Therefore, it is important to check for multicollinearity in a regression model and take steps to reduce it, such as removing one of the highly correlated independent variables or using regularization techniques. This can help to ensure that the regression model produces reliable estimates of the effects of the independent variables on the dependent variable.

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The slopes of the secant lines are listed below:

Case I: m = 0

Case II: m = - √3  (aprox. 1.7321)

Case III: m = 0

Case IV: m = 2.2103

Case V: m = 5√3 / 2 (approx. 4.3301)

Case VI: m = 7.5570

Case VII: m = 0

Case VIII: m = - √3  (aprox. 1.7321)

Case IX: m = 0

Case X: m = 5

Case XI: m = - 9.8480

In this problem we find eleven cases of two pairs of points lying on a sinusoidal curve, each of which we need to determine the slope of the secant line by means of the following formula:

m = [f(a) - f(b)] / (b - a)

Where the definition of the sinusoidal function is f(x) = sin (14π / x).

Now we proceed to determine the slope of each secant line:

Case I

m = [f(2) - f(1)] / (2 - 1)

m = (0 - 0)

m = 0

Case II

m = [f(1.5) - f(1)] / (1.5 - 1)

m = (- √3 / 2 - 0) / 0.5

m = - √3  (aprox. 1.7321)

Case III

m = [f(1.4) - f(1)] / (1.4 - 1)

m = (0 - 0) / 0.4

m = 0

Case IV

m = [f(1.3) - f(1)] / (1.3 - 1)

m = (0.6631 - 0) / 0.3

m = 2.2103

Case V

m = [f(1.2) - f(1)] / (1.2 - 1)

m = (√3 / 2 - 0) / 0.2

m = 5√3 / 2 (approx. 4.3301)

Case VI

m = [f(1.1) - f(1)] / (1.1 - 1)

m = (0.7557 - 0) / 0.1

m = 7.5570

Case VII

m = [f(0.5) - f(1)] / (0.5 - 1)

m = (0 - 0) / (- 0.5)

m = 0

Case VIII

m = [f(0.6) - f(1)] / (0.6 - 1)

m = (- √3 / 2 - 0) / (- 0. 4)

m = - √3  (aprox. 1.7321)

Case IX

m = [f(0.7) - f(1)] / (0.7 - 1)

m = (0 - 0) / (- 0. 3)

m = 0

Case X

m = [f(0.8) - f(1)] / (0.8 - 1)

m = (- 1 - 0) / (- 0.2)

m = 5

Case XI

m = [f(0.9) - f(1)] / (0.9 - 1)

m = (- 0.9848 - 0) / (- 0.1)

m = - 9.8480

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The probability value of (m, n) is (1, 2^1005).

Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.

We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.

Thus, the probability is:

P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004

We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.

Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|

where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.

By the inclusion-exclusion principle:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)

where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.

This simplifies to:

(1/2) ⋅ (2^1004 + (-1)^1005)

Thus, the probability is: P = (1/2^1004) ⋅ (1/2) ⋅ (2^1004 + (-1)^1005) = 1/2 + 1/2^1005. Hence, (m, n) = (1, 2^1005).

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Complete question:

If m/n is the probability that the reciprocal of a randomly selected positive odd integer less than 2010 gives a terminating decimal, with m and n being relatively prime positive integers. what is probability value of m and n?

The probability value of (m, n) is (1, 2^1005).This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.

We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.

Thus, the probability is:

P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004

We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.

Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|

where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.

By the inclusion-exclusion principle:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)

where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.

This simplifies to:

\((1/2) * (2^{1004} + (-1)^1005)\)

Thus, the probability is: P = \((1/2)^{1004}* (1/2) *(2^{1004} + (-1)^{1005}) = 1/2 + 1/2^{1005}.\)

Hence, (m, n) = (\(1, 2^{1005\)).

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the original number Juan started with was 6.

Let "x" represent the original number. Juan first adds 2 to the original number, which can be expressed as (x + 2). He then multiplies this by 2, resulting in 2(x + 2). Next, he subtracts 2 from this product: 2(x + 2) - 2. Finally, he divides the resulting number by 2, giving us the equation [(2(x + 2) - 2) / 2] = 7.
Now, let's solve for the original number, x:
1. Simplify the equation by distributing the 2: [2x + 4 - 2] / 2 = 7
2. Combine the constants: (2x + 2) / 2 = 7
3. Multiply both sides by 2 to remove the denominator: 2x + 2 = 14
4. Subtract 2 from both sides: 2x = 12
5. Divide both sides by 2: x = 6

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Answer:

24

Step-by-step explanation:

18 * 4 /3 = 72/3 = 24

By using Chebyshev's Inequality with K=3, we can determine that at least 88.89% of the days had temperatures between "F and "F, where "F represents the mean temperature of 76.4°F.

Chebyshev's Inequality provides a lower bound on the proportion of data that falls within a certain number of standard deviations from the mean. In this case, K=3 means that we are considering a range of three standard deviations from the mean.

The inequality states that for any dataset, the proportion of data falling within K standard deviations of the mean is at least 1 - (1/K^2). So, for K=3, we have 1 - (1/3^2) = 1 - (1/9) = 8/9 ≈ 0.8889. Therefore, at least 88.89% of the data falls within three standard deviations of the mean.

In the context of the temperature data, we can conclude that at least 88.89% of the days had temperatures between the mean temperature of 76.4°F minus three standard deviations (76.4 - 3 * 7.3) and the mean temperature plus three standard deviations (76.4 + 3 * 7.3). This range represents a relatively high proportion of the dataset, indicating that the temperature observations are fairly concentrated around the mean with limited extreme values.

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Answer:

I hope this helps!

To argue why the liberal arts are so important in education and leisure, one must discuss its Greek origin and how it is received today.

The term "liberal arts" comes from the Latin word "liberalis," which means free. It was used in the Middle Ages to refer to topics that should be studied by free people. Liberal arts refers to courses of study that provide a general education rather than specialized training. It encompasses a wide range of topics, including literature, philosophy, history, language, art, and science.The liberal arts curriculum is based on the idea that a broad education is necessary for individuals to become productive members of society. In ancient Greece, education was focused on developing the mind, body, and spirit.  

The study of the liberal arts is necessary to create well-rounded individuals who can contribute to society in meaningful ways. While the importance of the liberal arts has been debated, it is clear that they are more important now than ever before. The study of the liberal arts is necessary to develop the skills that are required in a rapidly advancing technological world.

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The relative frequency distribution of the values of the mean of these 15,504 different samples would specify the sampling distribution of the mean.

The sampling distribution of the mean refers to the distribution of sample means obtained from repeated sampling from the same population.

In this case, we have 15,504 different samples of size 5 drawn from a population of 20 hospitals.

Each sample has its own sample mean. The relative frequency distribution of these sample means would specify the sampling distribution of the mean.

The sampling distribution of the mean is important in statistics because it allows us to make inferences about the population mean based on the distribution of sample means.

It helps us understand the variability of sample means and provides a basis for constructing confidence intervals and conducting hypothesis tests.

Therefore, the relative frequency distribution of the mean values from the different samples would describe the characteristics of the sampling distribution of the mean..

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Answer:

b; 1/6

Step-by-step explanation:

Answer:

Annually cumulating interest can be determined by the following formula:

W=P(1+r)^y

r represents the interest rate as a decimal, and P represents the starting amount of money.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Since there is no single number we can add to one number in the sequence to get to the next one, this is not arithmetic. That means it's geometric, if it's a sequence at all. To get from 2 to 6 we multiply by 3. To get from 6 to 18 we multiply by 3. To get from 18 to 54 we multiply by 3. Therefore, this is in fact geometric and the common ratio is 3. The standard form of a geometric explicit formula is

\(A_n=a_1(r)^{n-1\) where n is the position of a number in the sequence, a1 is the first number in the sequence, and r is the common ratio. We have then

a1 = 2 and r = 3. Therefore, the explicit formula is

\(A_n=2(3)^{n-1\) and you can use this to find the value of any number in the sequence. Very handy; much more so than the recursive formula, which requires that all the numbers in a sequence be found in order in order to get to a desired value.

The total cost of manufacturing the commodity is C(x,y)=2x²+xy+8y²+3000 and the company's aim is to produce 1,900 units per month. The aim is to produce these units at a minimum cost of production. The production units at Factory X is given by x and the production units at Factory Y is given by y.

Let's solve for one of the variables, say y: y=1,900-xLet's substitute this equation in the total cost equation;

C(x, y) = 2x²+ xy + 8y² + 3000

C(x) = 2x² + x(1,900 - x) + 8(1,900 - x)² + 3000

C(x) = 2x² + 1,900x - x² + 8(3,610,000 - 3,800x + x²) + 3000

C(x) = 2x² + 1,900x - x² + 28,880,000 - 30,400x + 8x² + 3000

C(x) = 9x² - 28,500x + 28,880,000 + 3000

C(x) = 9x² - 28,500x + 28,910,000

The above equation is a quadratic equation. Let's find the minimum value of the equation by using the formula for finding the vertex of a quadratic equation;

x = (-b)/(2a)=-(-28,500)/2(9)

=1,583.33.

x has to be an integer, we round this to the nearest whole number. Therefore, x = 1583. Substituting x=1583 in the equation for y, we have;

y=1,900 - 1583

= 317

The company should produce 1,583 units at Factory X and 317 units at Factory Y.The total cost will be;

C(1,583, 317) = 2(1583)² + 1583(317) + 8(317)² + 3000

C(1,583, 317) = 10,924,440

The minimum cost of production is $10,924,440.

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Answer:

c by 3 minutes a day your answer is c

Thomas's total commission for last month is $1,255.

Thomas sold merchandise worth $13,000. He earns 3.5% on the first $3,000, which is $105. He earns 9% on the next $5,000, which is $450. The remaining amount is $5,000, and he earns 14% on it, which is $700. Therefore, his total commission is $1,255. WORD COUNT: 69.
To calculate Thomas's total commission on his $13,000 worth of merchandise sales, we will use the commission rates provided. He earns 3.5% on the first $3,000, 9% on the next $5,000, and 14% on sales over $8,000.
First $3,000: $3,000 * 0.035 = $105
Next $5,000: $5,000 * 0.09 = $450
Sales over $8,000: $13,000 - $8,000 = $5,000; $5,000 * 0.14 = $700
Now, add the commission amounts: $105 + $450 + $700 = $1,255.
Thomas's total commission for last month is $1,255.

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Answer: 3/4 of a cup is 0.75

Step-by-step explanation:

The income level that results in the maximum test score is approximately $45.63.. The correct answer is not provided among the given options.

To find the income level that results in the maximum test score, we need to determine the maximum point of the function represented by the equation: 607.3 + 3.85Income - 0.0423Income^2.

To find the maximum point, we can take the derivative of the function with respect to Income and set it equal to zero. Then we solve for Income.

Let's differentiate the function:

d/dIncome (607.3 + 3.85Income - 0.0423Income^2) = 3.85 - 2 * 0.0423 * Income

To find the maximum point, we set the derivative equal to zero:

3.85 - 2 * 0.0423 * Income = 0

Simplifying:

3.85 = 2 * 0.0423 * Income

Dividing both sides by 2 * 0.0423:

Income = 3.85 / (2 * 0.0423)

Income ≈ 45.63

Therefore, the income level that results in the maximum test score is approximately $45.63.

Among the given answer choices:

A. 607.3 is the constant term in the equation and does not represent an income level.

B. 91.02 is not the income level that results in the maximum test score.

C. 45.50 is close to the correct answer, but the correct approximation is $45.63.

D. The correct answer has been determined using calculus.

So, the correct answer is not provided among the given options.

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Answer:

4q + 16

Step-by-step explanation:

4 × q = 4q

4 × 4 = 16

4q + 16

The following volumes of fluid can be added to 0.40 mL of liquid for the level of precision of 0.01 mL: a) 0.2 mL, b) 6 mL, c) 2.02 mL. The amounts 0.154 mL and 8.8331 mL are not possible due to given level of precision.

If the measuring has a level of precision of 0.01 ml, this means that the measured quantities are only sensible to the smallest hundreths. Any change less than 0.01 ml and any decimal less than a hundreths are "invisible" for measuring processes.

Hence, the following volumes of fluid can be added to 0.40 mL of liquid for the level of precision of 0.01 mL: a) 0.2 mL, b) 6 mL, c) 2.02 mL. The amounts 0.154 mL and 8.8331 mL are not possible due to given level of precision.

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Answer:

B,D,E

Step-by-step explanation:

The required answer is the -

Part a: cos 300° = 0.5.

Part b:  sin 300° = -0.866.

Part a: To determine cos 300° using the cosine sum identity,  write 300° as the sum of two angles: 180° + 120°. The cosine sum identity states that cos(A + B) = cosAcosB - sinAsinB.

Now,  substitute A = 180° and B = 120° into the cosine sum identity equation:
cos(180° + 120°) = cos180°cos120° - sin180°sin120°.

Since cos180° = -1 and sin180° = 0,  simplify the equation to:
cos(180° + 120°) = -1 * cos120° - 0 * sin120°.

Simplifying further:
cos(180° + 120°) = -cos120°.

Finally, substitute cos120° with its value on the unit circle, which is -0.5:
cos(180° + 120°) = -(-0.5) = 0.5.

Therefore, cos 300° = 0.5.

Part b: To determine sin 300° using the sine difference identity, we can write 300° as the difference of two angles: 330° - 30°. The sine difference identity states that sin(A - B) = sinAcosB - cosAsinB.

Now,  substitute A = 330° and B = 30° into the sine difference identity equation:
sin(330° - 30°) = sin330°cos30° - cos330°sin30°.

Since sin330° = -0.5 and cos330° = 0.866, and sin30° = 0.5 and cos30° = 0.866, simplify the equation to:
sin(330° - 30°) = -0.5 * 0.866 - 0.866 * 0.5.

Simplifying further:
sin(330° - 30°) = -0.433 - 0.433.

Finally, adding the terms:
sin(330° - 30°) = -0.866.

Therefore, sin 300° = -0.866.

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Answer: The plane is 246.4 kilometres from Dryden (approximately)

Step-by-step explanation: Please refer to the picture attached for further details.

The pilot was meant to fly from Thunder Bay which is marked as point T to Dryden which is marked as point D. The distance is given as approximately 320 kilometres as shown.

However upon departure, the pilot goes off course at an angle of 20 degrees and flies for 80 kilometres. When he has traveled for exactly 80 kilometres, he would find himself at point P as shown in the diagram. The plane which is now at point P, is t kilometres from Dryden (point D). To calculate the distance t, we shall apply the cosine formula, having been given two sides and an angle between.

The cosine rule states as follows;

c² = a² + b² - 2abCosC

Substituting for the given variables in this question, the formula can be expressed as follows;

t² = d² + p² - 2dpCosT

Substituting for the known values, we now have,

t² = 80² + 320² - 2(80*320)Cos20

t² = 6400 + 102400 - 2(25600)0.9396

t² = 108800 - (51200) * 0.9396

t² = 108800 - 48107.52

t² = 60692.48

Add the square root sign to both sides of the equation

√t² = √60692.48

t = 246.3584

t ≈ 246.4

Therefore, the plane is approximately 246.4 kilometres from Dryden.

Answer:

19

Step-by-step explanation:

A' represents everything out A

B' represents everything out B

C' represents everything out C

So only the outside is left hope this helps

Answer:

20 lawns

Step-by-step explanation:

Answer:

Hey I’m a friend of Carson’s, do u know what Ari‘s acc name is?

Step-by-step explanation:

Answer:

hi thanks for the question

Step-by-step explanation: