The three vertices of a triangle are (2, 1), (6, 1), and (3, 6).
What is the area of the triangle?

For a line with a slope a and a known point (h, k), the point-slope form is:

y = a*(x - h) + k

A general linear equation can be written in slope-intercept form as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we know that a line passes through a point (h, k), then the point-slope form of that line is:

y = a*(x - h) + k

Notice that particularly, the y-intercept can be written as (0, b), then the slope-intercept form is also a point-slope:

y = a*(x - 0) + b

y = a*x + b

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To now find the perimeter of ABC

AB + BC + AC

4.9 +6 +7 = 17.9 approximately 18

If there is a pair of parallel sides in the following shape. the area of the shape is:  21 unit².

Using this formula to determine or find  the area of the shape

Area  = (1/2)× (Area+ breadth )height

Where:

Area= 9

Breadth= 5

Height = 3

Now Let plug in the formula so as to find the area

Area of the shape = (1/2)× (9 + 5) ×3

Area of the shape = (1/2)× (14)×3

Area of the shape = (1/2)× 42

Area of the shape= 21 unit²

Therefore If there is a pair of parallel sides in the following shape. the area of the shape is:  21 unit².

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From the graph,

g(2) = 4 ( from the coordinate (2,4))

[ The green line represent the function g(x)]

f(2)= 0

[ The red line represent the function f(x)]

(g + ƒ)(2) = g(2)+f(2) = 4+0 = 4

OPTION A is the correct answer

Answer:

\(r=4.38\)

Step-by-step explanation:

Step 1: Arrange the equation so that you are calculating rate (divide both sides by t)

\(\frac{d}{t} = \frac{rt}{t}\)

\(t\) cancels out on the right side.

Step 2: Substitute in the numerals

\(r=\frac{d}{t}\)

\(r=\frac{5.7}{1.3}\)

Step 3: Divide

\(r=4.38\) \(mph\)

There's your answer!

Hope this helps you!

Multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, ...

The two digit numbers in that list above all have their digits adding to some other multiple of 3

and so on.

Therefore, the rule is: If the digits add to a multiple of 3, then the original number is a multiple of 3.

Answer:

A+S=22

A=S/2+4

Multiply second equation by 2 and rearrange.

2A-S=8

Add equations 1 and 3.

3A=30

A=10

Substitute for A in either of the first 2 equations to get

S=12

Step-by-step explanation:

Let the number her brother has = x

She has 5 times as many so she has 5x

Together they have 42:

X + 5x = 42

Add x and 5x to get 6x:

6x =42

Divide both sides by 6:

X = 7

The brother has 7

Carla has 5*7 = 35

Answer: Carla has 35 notebooks

Answer:

3043 (base 6)

Step-by-step explanation:

216      36    6    1

3           0      4  3

216* 3 = 648

6*4 = 24

1*3 = 3

648+24+3 = 675

Answer:

The sum of

74 and 35.6 is 109.6

Step-by-step explanation:

109.6

Now enjoy a free meme thing

Answer:

Step-by-step explanation:

If the question is - 7 - 131 = - 138

There are a total of 8 pieces on the outer edge with only one frosted side.

We have,

If Sally has frosted the top and all sides but not the bottom of the cake, then each piece will have one frosted side (the top) and three unfrosted sides (the bottom and two sides).

Out of the 9 pieces, only the pieces on the outer edge will have exactly one frosted side.

If we count the number of pieces on the outer edge, we can determine how many pieces are frosted on only one side.

For a cube-shaped cake, there are 8 pieces on the outer edge.

To see why, imagine slicing off the corners of the cube to create a smaller cube inside.

Each of the 6 faces of the smaller cube will have a piece missing from the corner.

Therefore, there are 6 pieces on the outer edge of the larger cube, and each of these pieces can be divided into two smaller pieces (with one frosted side each) by cutting along the diagonal.

This gives a total of 12 pieces, but we need to subtract the 4 corner pieces that have two frosted sides each.

So there are a total of 8 pieces on the outer edge with only one frosted side.

Therefore,

There are a total of 8 pieces on the outer edge with only one frosted side.

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There are a total of 8 pieces on the outer edge with only one frosted side.

We have,

If Sally has frosted the top and all sides but not the bottom of the cake, then each piece will have one frosted side (the top) and three unfrosted sides (the bottom and two sides).

Out of the 9 pieces, only the pieces on the outer edge will have exactly one frosted side.

If we count the number of pieces on the outer edge, we can determine how many pieces are frosted on only one side.

For a cube-shaped cake, there are 8 pieces on the outer edge.

To see why, imagine slicing off the corners of the cube to create a smaller cube inside.

Each of the 6 faces of the smaller cube will have a piece missing from the corner.

Therefore, there are 6 pieces on the outer edge of the larger cube, and each of these pieces can be divided into two smaller pieces (with one frosted side each) by cutting along the diagonal.

This gives a total of 12 pieces, but we need to subtract the 4 corner pieces that have two frosted sides each.

So there are a total of 8 pieces on the outer edge with only one frosted side.

Therefore,

There are a total of 8 pieces on the outer edge with only one frosted side.

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The line of music is refered to as the bracket

It should be noted that music simply means a vocal or instrumental sounds that are combined to produce beauty of harmony and expression if emotions.

When When both of these staves are connected with this symbol, it's called a brace.

Lastly, the things inside the box are voice, piano, and guitar.

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Answer:

Step-by-step explanation:

You know that all of the angles of a triangle have to add to equal 180°.

Therefore, (3x)+(2x+20)+(4x-20)= 180°

If you combine like terms you get:

9x=180°

Divide both sides by 9 to get:

X=20

Option A : The normality assumption is met for sample 1, and is only moderately violated for sample 2. Therefore, only option I suggests that it is safe to use t-procedures.

For the use of t-procedures, we need to check the normality assumption for each sample. A roughly symmetric dot plot with no outliers suggests normality, which means it is safe to use t-procedures. On the other hand, moderately skewed or strongly skewed dot plots, or dot plots with outliers, suggest non-normality, which means t-procedures should not be used.

In option I, the dot plot of sample 1 is roughly symmetric, while the dot plot of sample 2 is moderately skewed left, but there are no outliers. This suggests that the normality assumption is met for sample 1, and is only moderately violated for sample 2. Therefore, t-procedures can be used in this case.

Option II has a roughly symmetric dot plot for both samples, but sample 2 has an outlier. However, an outlier may affect the results of t-procedures, so it is not recommended to use t-procedures in this case.

Option III has strongly skewed dot plots for both samples with no outliers. This suggests that the normality assumption is violated for both samples, and therefore t-procedures should not be used.

Therefore, only option I suggests that it is safe to use t-procedures.

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You are constructing a 90% confidence interval for the difference of means from simple random samples from two independent populations. The sample sizes are = 6 and = 14. You draw dot plots of the samples to check the normality condition for two-sample t-procedures. Which of the following descriptions of those dot plots would suggest that it is safe to use t-procedures?

I. The dot plot of sample 1 is roughly symmetric, while the dot plot of sample 2 is moderately skewed left. There are no outliers.

II. Both dot plots are roughly symmetric. Sample 2 has an outlier.

III. Both dot plots are strongly skewed to the right. There are no outliers.

A) I only

B) II only

C) I and II

D) I, II, and III

E) t-procedures are not recommended in any of these cases.

The steps to visualize Newton's Method by using Matplotlib and PIL is mentioned below.

In calculus, the derivative is a fundamental concept that describes how a function changes with respect to its input variable. More specifically, the derivative of a function represents the instantaneous rate of change of the function at a particular point.

Geometrically, the derivative can be interpreted as the slope of the tangent line to the graph of the function at a specific point. If the derivative is positive, the function is increasing at that point; if it is negative, the function is decreasing. A derivative of zero indicates that the function has a stationary point at that location.

To create visualizations of Newton's Method, you will need to use a programming language like Python and some libraries such as Matplotlib, PIL, and NumPy.

Here are some steps you can follow:

By following these steps, you can create interesting visualizations of Newton's Method and explore the properties of this powerful numerical method.

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a. In interval notation, Increasing intervals: (12pm, 1pm) U (1pm, 2pm) U (2pm, 3pm). Decreasing intervals: (8am, 9am) U (11am, 12pm). Constant intervals: (9am, 10am) U (10am, 11am)

b. The increase in cost between 12 noon and 3 pm is $2.

c. Yellow Cab has a lower price per 1km than Swift ride at (8am, 9am) (9am, 10am) (2pm 3pm)

Interval notation is used to represent continuous intervals of numbers or values, like ranges on a number line.

The graph shows that from 8-9am, and 11-12pm, the cost from Swift Ride decreases.

We can represent it as (8am, 9am) U (11am, 12pm).

It increases at these times (12pm, 1pm) U (1pm, 2pm) U (2pm, 3pm).

And stays constant at : (9am, 10am) U (10am, 11am)

We simply deduct the 12pm's cost from 3pm's cost.

So, we have

Cost increase = $3.5 - $1.5

Evaluate the difference

Cost increase = $2

Hence, the cost increase is $2

When you plot the points provided for Yellow cab, you'll notice that Yellow Cab has a lower price per 1km than Swift ride at (8am, 9am) (9am, 10am) (2pm 3pm)

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Given :

An equation , \(a=mg-\dfrac{kv^2}{m}\) .

To Find :

The value of v in above equation if a = 2.8, m = 12, g = 9.8, k\(v=\sqrt{\dfrac{12(12\times 9.8-2.8)}{\dfrac{8}{3}}}\\\\v= \$22.73\) = 8/3 .

Solution :

Simplifying the given statement in terms of v = ..... .

\(\dfrac{kv^2}{m}=mg-a\\\\v^2=\dfrac{m(mg-a)}{k}\\\\v=\sqrt{\dfrac{m(mg-a)}{k}}\)      ...... 1 )

Putting all given values in above equation , we get :

\(v=\sqrt{\dfrac{12(12\times 9.8-2.8)}{\dfrac{8}{3}}}\\\\v= 22.73\)

Therefore , the value of v is 22.73 .

Hence , this is the required solution .

Answer:

26

Step-by-step explanation:

8 * 2 + 10 = 26

Answer:

45, 45 and 90 degrees

Step-by-step explanation:

Complete question

The measures of angles X and Y are the same, x degrees. The measure of angle Z is twice the measure of angle Y. Find the measure of each angle

Let the sum of the angles be 180 degrees

X = x

Y = x

If Z is twice the measure of angle Y, then;

Z = 2x

Taking the sum

<X + <Y + <Z = 180

x+x+2x = 180

4x = 180

x = 180/4

x = 45

since Z = 2z

Z = 2*45

Z = 90

Hence the measure of the angles X, Y and Z are 45, 45 and 90 respectively

Noah missed 7 points on the test. And Gabe missed 2x - 3 = 2(7) - 3 = 11 points on the test. So, Gabe missed 11 points on the test.

What is Algebraic expression ?

Algebraic expression can be defined as combination of variables and constants.

Let x be the number of points that Noah missed on the test.

Then, the number of points that Gabe missed is 2x - 3, according to the problem.

The total number of points missed by both of them is given as 18.

So, we can write an equation based on the problem statement:

x + (2x - 3) = 18

Simplifying the equation, we get:

3x - 3 = 18

Adding 3 to both sides of the equation, we get:

3x = 21

Dividing both sides of the equation by 3, we get:

x = 7

Therefore, Noah missed 7 points on the test. And Gabe missed 2x - 3 = 2(7) - 3 = 11 points on the test. So, Gabe missed 11 points on the test.

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1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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Answer:

122x12222 = 1491084

Answer:

It is a good app, when used the right way.

Step-by-step explanation:

Your question isn't properly described. 122x1,2222, is that 1.2222 or was it supposed to be 12,222?

The required radius of the circle is 10 cm.

The formula for the circumference C of a circle in terms of its radius r is given by:

C = 2πr

We are given that the circumference of the circle is 20π cm. So we can set this expression equal to 20π and solve for r:

20π = 2πr

Dividing both sides by 2π, we get:

r = 10

Therefore, the radius of the circle is 10 cm.

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Answer:

yes your correct

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

The original number is -22

Step-by-step explanation:

We'll label our mystery number x.

2x + 36 = 4x/11
Multiply both sides by 11
4x = 22x + 396
Isolate x to one side (for this I subtract 4x from both sides, but you can also subtract 22x if you'd like)
0 = 18x + 396
Isolate x pt 2
18x = -396
Divide both sides by 18 to find your answer!
x = -22

Plug in to confirm

-44 + 36 = -88/11S
8 = 8

The z-score related to the mean test scores achieved by the students is 0.33.

For the given question;

mean population; μ = 50.

standard deviation; σ = 15

Test score; x = 55.

The z-score is estimated as;

z = (x - μ)/σ

Put the values;

z = (55 - 50)/15

z = 0.33

Thus, the z-score related to the mean test scores achieved by the students is 0.33.

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it is given that,

the given ramp is a right angle ramp withe the angle 8 degrees,

it is given that

the ramp is used to access an 18-inch step to a door

so, the perpendicular of the ramp is P = 18 in

the length of the ramp is = hypotenuse,

so, the length of the ramp is approx 129 in.

thus, the correct answer is option D