The volume of an ideal gas is increased from 1m3 to
2m3 while maintaining a constant pressure of 1000 Pa.
How much work is done by the gas in this expansion?

Answer:

The time between the emission of the wave and it's reception was 0.4 seconds.

Explanation:

The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:

\(\text{speed} = \frac{\text{distance}}{\text{time}}\)

We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:

\(\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}\)

The time between the emission of the wave and it's reception was 0.4 seconds.

Answer:

w = 7.5 [J]

Explanation:

We must remember the definition of mechanical work, which tells us that work is equal to the product of force by distance. This force must be applied in the direction of movement. So we have the following equation:

w = F*d

where:

w = work [J]

F = force [N]

d = distance [m]

Now replacing we have:

w = 5*1.5

w = 7.5 [J]

The high temperature reservoir must transfer approximately 27.473 kJ of heat to the engine during each cycle.

In a carnot cycle engine that operates between a low temperature reservoir at 20°c and a high temperature reservoir at 800°c, if the engine is required to output 20.0 kJ of work per cycle, the amount of heat that the high temperature reservoir must transfer to the engine during each cycle can be calculated using the formula given below.

Qh = W/Ql + W

Where,Qh is the heat transferred to the engine from the high temperature reservoir, W is the work output per cycle, and Ql is the heat rejected by the engine to the low temperature reservoir.

Substituting the given values in the above formula,

Qh = 20 kJ/ (1 - (20+273)/(800+273))= 20 kJ/ (1- 293/1073) = 20 kJ/0.728 = 27.473 kJ (approximately)

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Answer:

D. They don't require a medium to travel through.

Explanation:

Electromagnetic waves and mechanical waves are both types of waves. Electromagnetic waves are waves that arise from the combination of electric and magnetic fields while mechanical waves are waves that arise as a result of transfer of energy via matter.

One major difference between these two types of waves is that electromagnetic waves such as light waves, radiowaves etc. do not need a medium to travel i.e. they can travel through a vacuum, while on the other hand, mechanical waves such as sound waves need a medium to travel.

Answer:

They don't require a medium to travel through

Explanation: hope this helps

Answer: Translation

Explanation:

Apex

Thanks

Answer:

RADIATION

Explanation:

JUST TOOK IT ON APEX

Considering the definition of pressure, force will have the same units of pressure is multiplied by area.

Pressure is defined as the force exerted per unit area.

In this way, for the same force, the pressure is inversely proportional to the surface: this means that, for the same force, the smaller the surface, the greater the pressure exerted and the more the body will be deformed.

That is, pressure is defined as the force exerted perpendicularly on a surface and is expressed mathematically as:

\(Pressure=\frac{Force}{Area}\)

In the International System of Units, the unit of pressure is the pascal (Pa). One pascal is the pressure exerted by a force of 1 N distributed over an area of ​​1 m².

Then, the definition of force can be expressed as:

Force= Pressure× Area

In summary, force will have the same units of pressure is multiplied by area.

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Formula for acceleration:

\(a=\dfrac{V^f-V^I}{t}\)

acceleration(measured in m/s^2) = Final velocity(measured in m/s) - Initial velocity(measured in m/s) / time(measured in seconds)

__________________________________________________________

Given:

\(V^I=0m/s\) (rest)

\(V^f=28m/s\)

\(t=20s\)

\(a=?\)

__________________________________________________________

Finding acceleration:

\(a=\dfrac{V^f-V^I}{t}\)

\(a=\dfrac{28-0}{20}\)

__________________________________________________________

Answer:

\(\boxed{a=1.4m/s^2}\)

a. Its a motion with constant movement. A liniear graph between time and distance shown the distance changes constantly over time.

b. The average velocity can be calculate by Δx / Δt = (35-5) / 4 = 7.5 m/s

c. \(\frac{y-y_{1} }{y_{2}-y_{1} } = \frac{x-x_{1} }{x_{2}-x_{1} }\) =   \(\frac{y-20}{35-20} = \frac{x-2}{4-2}\) = \(2y-40=15x-30\) = \(15x-2y=-10\)

d. By using equation above, the objects position at t=6s, is

\(15x6-2y=-10\)

\(y=50m\)

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Explanation:

i will use chainsaw to cut a tree and even if that doesn't work I will use axe to make my work easy.

hope this helps you

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The magnitude of the magnetic force on the proton is 4.31 × 10⁻¹¹ N.

Given values: B = 5.5 Tθ = 25°q = 1.602 × 10⁻¹⁹ VC = 1.00 × 10⁷ m/s Formula: The formula to calculate the magnetic force is given as;

F = qvBsinθ

Where ;F is the magnetic force on the particle q is the charge on the particle v is the velocity of the particle B is the magnetic field strengthθ is the angle between the velocity of the particle and the magnetic field strength Firstly, we need to determine the angle between the velocity vector and the magnetic field vector.

From the given data, The angle between velocity vector and x-axis;α = -15°The angle between magnetic field vector and x-axis;β = 25°The angle between the velocity vector and magnetic field vectorθ = 180° - β + αθ = 180° - 25° - 15°θ = 140° = 2.44346 rad Now, we can substitute all given values in the formula;

F = qvBsinθF

= (1.602 × 10⁻¹⁹ C) (1.00 × 10⁷ m/s) (5.5 T) sin (2.44346 rad)F

= 4.31 × 10⁻¹¹ N

Therefore, the magnitude of the magnetic force on the proton is 4.31 × 10⁻¹¹ N.

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It is possible to suspend an object at rest from its center of gravity, and gravity won't induce it to begin rotating no matter how it is positioned.  

Thus, The center of gravity of an object will be located somewhere along a vertical line that passes through the point of suspension if you suspend it from any point and allow it to come to rest.

The gravitational acceleration is (almost) constant near the surface of the earth, where the center of mass also lies.

A place that represents the average or typical location of an object's mass, as if all of the mass were contained there, is known as the center of mass (CM). The geometric center of a uniform sphere serves as its center of mass. The barycenter is another name for the CM.

Thus, It is possible to suspend an object at rest from its center of gravity, and gravity won't induce it to begin rotating no matter how it is positioned.  

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Most celestial bodies in our solar system, such as the Sun, planets, and asteroids, revolve against the clock i.e., counterclockwise. This is because of the early circumstances in the gas and dust cloud that gave rise to our solar system.

This gas and dust cloud started rotating as it started to disperse. After then, there will be a clockwise orbit. Not only do all of the rocky planets circle in a counterclockwise direction around the Sun, but so do all of the gas giant planets. Nearly all known asteroids, kuiper belt objects, and comets also orbit the Sun in the opposite direction! As far as we are aware, the collapse of gas clouds is what creates stars.

We will end up with a disc because one way will collapse sooner because it is shorter. (Or a pancake in our "complex scientific jargon. If you mention pancake to an astrophysicist, they will understand that you are referring to this process. The planets were created from a dust disc that encircled the sun, which explains why they are all lined up and orbiting on the same basic plane. Therefore, it makes sense that planets originated in the orbit or region where dust was present.

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Correct Question:

will the subsequent motion be a clockwise or counterclockwise orbit?

Answer:

Explanation: "Warming up and cooling down are good for your exercise performance — you’ll do better, faster, stronger — and for your heart since the increased work on the heart ‘steps up’ with exercise,” said Richard Stein, M.D., professor of cardiology.

Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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In order to solve this problem, there are a few assumptions and approximations that we will need to make:

The density of water is constant and equal to 1 g/cm^3. This is a reasonable approximation for most practical purposes, as the density of water is relatively constant over a wide range of temperatures and pressures.

The atmospheric pressure is constant and equal to 1 atm. This is also a reasonable approximation, as the atmospheric pressure at sea level is relatively constant and does not vary significantly over short distances.

The temperature of the water and the gas in the pipe is constant. This means that the temperature of the water and the gas does not change as the pipe is submerged or as the air column in the pipe changes in length.

The air in the pipe is an ideal gas, which means that it follows the ideal gas law. This means that the pressure, volume, and temperature of the gas are related by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature.

The process of submerging the pipe in the water is an adiabatic process, which means that no heat is transferred to or from the gas in the pipe as the process occurs. An adiabatic process is a process in which the internal energy of a system remains constant, and no heat is transferred between the system and its surroundings.

With these assumptions and approximations in mind, we can proceed to calculate the length of the air column in the pipe after it has been submerged. The volume of the air in the pipe is given by the formula:

V = pi * r^2 * l

Where V is the volume, r is the radius of the pipe, and l is the length of the air column.

Since the volume of the gas in the pipe is constant, we can set the initial volume of the gas (V0) equal to the final volume of the gas (Vf) and solve for l:

V0 = Vf

pi * r^2 * l0 = pi * r^2 * lf

l0 / lf = 1

lf = l0

This means that the length of the air column in the pipe after it has been submerged is equal to the initial length of the air column before it was submerged.

To calculate the work done on the gas in the pipe, we can use the formula:

W = P * deltaV

Where W is the work done on the gas, P is the pressure of the gas, and deltaV is the change in volume of the gas.

Since the process is adiabatic, the pressure and temperature of the gas remain constant. Therefore, the work done on the gas is equal to zero, since there is no change in volume of the gas as the pipe is submerged.

W = P * deltaV

W = 1 atm * 0

W = 0

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Answer:

122.76J

Explanation:

Given data

work done= 372 Joules

efficiency= 33%

Required

We want to compute the value of the work that is 33%

= 33/100* 372

= 0.33*372

= 122.76J

Hence 122.76J of work is transferred from the engine to the exhaust

Answer:

La presion a 40 °C es 1.05 atm.

Explanation:

Usando la ecuación ideal de los gases.

\(PV=nRT\)

Debemos recordar, que CNPT significa condiciones normales de presión y temperatura.

Para el primer estado tenemos:

\(P_{1}V_{1}=nRT_{1}\)

Donde:

Para el segundo estado:

\(P_{2}V_{2}=nRT_{2}\)

Donde:

Como ambas ecuaciones tienen el mismo valor de volumen podemos igualarlas:

\(\frac{nRT_{1}}{P_{1}}=\frac{nRT_{2}}{P_{2}}\)

n y R permanecen constantes, se puden cancelar.

\(\frac{T_{1}}{P_{1}}=\frac{T_{2}}{P_{2}}\)

Despejamos P(2).

\(P_{2}=\frac{P_{1}T_{2}}{T_{1}}\)

\(P_{2}=\frac{1*313}{298}\)

\(P_{2}=1.05\: atm\)

Espero te haya sido de ayuda!

resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N is \(20\sqrt{34}\) N

force is produced by a vertical force of 60.0N

force is produced by a horizontal force of 100N

force.- A force is a push or pull of an object.

It is a vector quantity which having magnitude and direction also.

its unit is newton. denoted by capital N.

To find out the resultant of force

R² = ( (60)² + (100)²

R= √(3600 + 10000)

R =\(\sqrt{13600}\)  N

\(R = 20\sqrt[]{34} N\)

resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N is \(20\sqrt{34}\)N  

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Explanation:

GIVEN DATA

since P(momentum)=Mass×Velocity

F = P2 -P1

t

F= Mv2-Mv1

t

F=M( v2-v1) ,(a=v2-v1)

t t

ANSWER EXPLANATION IN WORDS

That question is related to Newton's second law of motion, the question ask you to find the force it gives you a mass and a acceleration As we know that the SI unit of acceleration is newton per kilogram or metre per second square It is correct to write metre per second square instead of Newton Per kilogram because because all of them are the SI unit of acceleration so that is the answer we get 686 Newton by Force .

The correct answer is approximately 3.207 V. To find the potential difference between two points 100 m apart in a 1.0 mm diameter copper wire with resistivity 1.68 x 10^-8 Ωm carrying a current of 15 A, follow these steps:

1. Calculate the wire's cross-sectional area (A) using the diameter (d=0.001 m):
A = π(d/2)^2 = π(0.0005)^2 ≈ 7.854 x 10^-7 m².

2. Determine the wire's resistance (R) using resistivity (ρ=1.68 x 10^-8 Ωm), length (L=100 m), and cross-sectional area (A):
R = ρ(L/A) = (1.68 x 10^-8)(100/7.854 x 10^-7) ≈ 0.2138 Ω.

3. Find the potential difference (V) using Ohm's Law (V=IR) with current (I=15 A) and resistance (R):
V = 15 x 0.2138 ≈ 3.207 V.

None of the given options (12V, 23V, 32V, 41V) match the calculated potential difference. The correct answer is approximately 3.207 V.

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The answer that matches both trials is (A) Does not change - Does not change.

The speed of the two-cart system's center of mass during the collision in each trial can be analyzed using the principle of conservation of momentum. In both trials, the total momentum before and after the collision remains the same.
In Trial 1, the collision is elastic, meaning that both kinetic energy and momentum are conserved. The center of mass does not change during the collision since the total momentum remains constant. Therefore, for Trial 1, the correct answer is "Does not change."
In Trial 2, the carts stick together during the collision, and although kinetic energy is not conserved, the total momentum is still conserved. As a result, the center of mass of the two-cart system does not change during the collision.

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Answer:

Explanation:

Using the efficiency formula. Efficiency = MA/VR * 100%

MA = Mechanical Advantage

VR = velocity ratio = \(\frac{distance\ moved\ by\ effort}{distance\ moved\ by\ load}\)

Distance moved by effort = 4.5m

distance moved by load = 1.5m

VR = 4.5/1.5 =3

Assuming efficiency is 100% (since friction can be ignored)

100% = MA/3 * 100%

1 = MA/3

MA = 3*1

MA = 3

Mechanical Advantage of the ramp is 3

The item that most likely uses a concave lens to perform its typical function is a concave lens .

A concave lens is a lens that is thinner at the center and thicker at the edges, causing it to diverge parallel rays of light.

A concave lens is used in a camera to allow the photographer to adjust the focus of the camera by moving the lens closer to or farther away from the film or sensor. When the lens is moved closer to the film or sensor, it increases the distance between the lens and the object being photographed, causing the image to appear larger and bringing objects into focus that were previously blurry.

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Answer:

A continuous flow of negative charges (electrons) creates an electric current. The pathway taken by a electric current is a circuit.

Explanation:

Answer:

Copper, and aluminum

Explanation:

Answer:

False

Explanation:

A net force on an object causes acceleration or a change in direction....not 'neither'

It is false that if a net force acts on an object, the object may change speed, change direction or do neither. Details about motion can be found below.

Newton's first law of motion also called law of inertia states that an object will remain at rest until it is acted upon by an external force.

This law suggests that an object will change direction or speed when acted upon by a net force.

Therefore, it is false that if a net force acts on an object, the object may change speed, change direction or do neither.

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Explanation:

a variable In algebra, a symbol (usually a letter) standing in for an unknown numerical value in an equation.

a unit In math, the word unit can be defined as the rightmost position in a number or the one's place

A certain spring stretches 7.7 cm when it supports a mass of 0.51 kg . if the elastic limit is not reached, The string will go 150.80 cm  when it supports a mass of 10 kg

Force 1 = - k x1

mass * acceleration =  - k x1

0.51 * 9.8 = - k (7.7)

k = 0.65

Force 2 = - k x2

10 * 9.8 = - 0.65 x2

x2 = 150.80 cm

The string will go 150.80 cm  when it supports a mass of 10 kg

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Communications satellites would fly off in a straight line never to be see again if it were not for a force from the earth, The moon "falls" from a straight line because there IS some attraction toward the Earth.

The satellite will tend to move tangential to the initial orbit without the assistance of centripetal force at the same speed as it did just before the gravitational field vanishes. As a result, the spacecraft will veer off course and leave its orbit.

The combined gravitational force of acts on the mass in your body. What gives you weight is that. Additionally, you would weigh less than you do now if you were on a planet with a lower mass than Earth. You make the same gravitational force on Earth that it does on you.

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