There is a step missing from the equation below. Which equation is the missing step

Answer:

b= 1 / 2

Step-by-step explanation:

divide both sides by 12 so 12b/12 and 6/12

b = 1 / 2

Answer: True

Step-by-step explanation: This statement is true because when clusters are heterogeneous they are a "scaled-down version" of the population sampled. I hope this helped!

Answer:true

Step-by-step explanation:

Answer: 4 cm

You take the surface area formula and substitute “x” for the width. Then it becomes a simple algebra problem.

The expected number of cards Henry needs to turn up to get the third ace is 31.8

Given: We need to find what is the expected number of cards Harry needs to turn up to get the third ace and Harry has a standard deck of 52 cards.

Now, we know there are 4 ace cards. Let’s consider the ace cards and non-ace cards separately.

There are (52-4) = 48 non-ace cards.

Let us consider that the non-ace cards will be cut by an ace card.

So, there are 5 possible ways in which the ace cards can cut the division, provided

We are having an equal number of non-ace cards in between the appearance of each ace card which means the setup is symmetric among the non-ace cards.

So let us name the spaces between ace cards as s1, s2, s3, s4, and s5.

Therefore, the position of the third ace card is equal to s1 + s2 + s3 + 3.

The expected value of this position is E[s1 + s2 + s3 + 3].

By linearity of expectation, E[s1 + s2 + s3 + s4] is E[s1] + E[s2] + E[s3] + 3.

As the setup is symmetric between the five places, E[s1] = E[s2] = E[s3] = E[s4] = E[s5]

And since E[s1 + s2 + s3 + s4 + s5] = E[s1] + E[s2] + E[s3] + E[s4] + E[s5] = 48

Therefore, E[s1] = E[s2] = E[s3] = E[s4] = E[s5] = 48 / 5

The expected value of position is E[s1] + E[s2] + E[s3] + 3

   = 48 / 5 + 48 / 5 + 48 / 5 + 3

   = 3 * 48 / 5 + 3

   = 31.8

Hence, the expected number of cards Henry needs to turn up to get the third ace is 31.8

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Answer:

Therefore any set of data that satisfies the 5-Number summary: 16,18,22,26 and 28 can be represented with the box plot.

Step-by-step explanation:

Interpreting Box Plots

We use a box plot to present the 5-Number summary of a set of data.

The values contained in the 5-Number summary are:

In the box plot, the following rules apply:

Using these, we interpret the given box plot

A left whisker extends from 16 to 18, therefore:

The box extends from 18 to 26 and is divided into 2 parts by a vertical line segment at 22.

The right whisker extends from 26 to 28.

Therefore any set of data that satisfies the 5-Number summary: 16,18,22,26 and 28 can be represented with the box plot.

Box plot has boxes with some lines ( called whiskers ).

Box plot on the graphical level tells about 5 points:

There is starting whisker or left whisker denoting point minimum (Q0) and extends from there the line to Q1 ( first quartile).

Then the box starts which starts from Q1 and touched Q3. In the middle it passes through Q2 ( The median of the data ), and thus has a line in it.

At last, there is end whisker or right whisker denoting end quantile or Q4 (the maximum point).

Given data:

Left whisker extends from 16 to 18.

     Thus Q0 = 16

              Q1 = 18

Box plot starts from 18 and extends to 26, and is split by a vertical line segment at 22.

    Thus Q2 = 22

             Q3 = 26

The right whisker or end whisker extends from 26 to 28

    Thus Q4 = 28.

Thus the description of data is given as:

\(Q_0 = Minimum = 16\\Q_1 = First\: quartile = 18\\Q_2 = Second \:quartile = Median= 22\\Q_3 = Third\: quartile = 26\\Q_4 = Maximum = 28\\\)

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Answer: $5.15

Step-by-step explanation: Add all the candy, then subtract how much he gave the cashier ($20) and the amount for the candy (14.85).

The given two-way Frequency table, there are 33 left-handed students who are not in the music program.

The number of left-handed students who are not in the music program, we need to examine the data presented in the two-way frequency table.

From the table, we can see that the number of left-handed students in the music program is 15, and the total number of left-handed students is 48.

the number of left-handed students not in the music program, we subtract the number of left-handed students in the music program from the total number of left-handed students.

Number of left-handed students not in the music program = Total number of left-handed students - Number of left-handed students in the music program

Number of left-handed students not in the music program = 48 - 15

Calculating this, we find that the number of left-handed students not in the music program is 33.

Therefore, there are 33 left-handed students who are not in the music program, based on the data provided in the two-way frequency table.

In conclusion, based on the given two-way frequency table, there are 33 left-handed students who are not in the music program.

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The probability that more than 7 of them weigh 65 lb or more is 0.0123.

A polynomial with only terms is a binomial. An illustration of a binomial is x + 2, where x and 2 are two distinct terms. Additionally, in this case, x has a coefficient of 1, an exponent of 1, and a constant of 2. As a result, a binomial is a two-term algebraic expression that contains a constant, exponents, a variable, and a coefficient. When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Given,

The Australian sheep dog is a breed renowned for its intelligence and work ethic. it is estimated that 40% of adult Australian sheep dogs weigh 65 pounds or more. a sample of 10 adult dogs is studied.

Let x be the number of sheep having 65 lb or more weight out of n;

Binomial function:

P(X = x) = ⁿCₓ Pˣ qⁿ⁻ˣ

When x = 0,1 2,..n

q = 1-p

n = 10

So,

P(X>7) = P(X = 8) + P(X = 9) +P(X = 10)

P(X >7) = ¹⁰C₈ (0.40)⁸ q¹⁰⁻⁸ + ¹⁰C₉(0.40)⁹ q¹⁰⁺⁹ + ¹⁰C₁₀ (0.40)¹⁰

P(X>7) = (0.40)⁸ (45× 0.36 + 10× 0.24+0.16)

P(X>7) = (0.40)⁸ (16.2 +2.4 + 0.16)

P(X>7) = 0.40⁸ × 18.76

P(X>7) = 0.0123

The probability that more than 7 of them weigh 65 lb or more is 0.0123.

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The system of equations 6x+4y=14 and 9x+6y=c are linear equations

The value of c that makes the system have infinitely many solutions is 21

The system of equations are given as:

6x+4y=14

9x+6y=c

Divide through the second equation by 3

3x + 2y = c/3

Multiply through by 2

6x + 4y = 2c/3

Subtract the first equation from the above equation

6x - 6x + 4y - 4y = 2c/3 - 14

Evaluate the differences

2c/3 - 14 = 0

Add 14 to both sides

2c/3 = 14

Multiply by 3/2

c = 21

Hence, the value of c that makes the system have infinitely many solutions is 21

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To calculate the moment of inertia of an object, you need to know its mass and the distance it is from the axis of rotation. In this case, the object has a mass of 12 kg and is distributed 4 meters from the axis of rotation. The formula to calculate the moment of inertia is I = mr^2, where the moment of inertia, m is the mass, and r is the distance from the axis of rotation.

Using this formula, we can calculate the moment of inertia of the object:

I = 12 kg x (4 m)^2

I = 192 kgm^2

Therefore, the moment of inertia of the object is 192 kgm^2.
To calculate the moment of inertia for an object, you can use the following formula:

Moment of Inertia (I) = Mass (m) × Distance² (r²)

Given the object's mass is 12 kg and the mass is distributed 4 meters from the axis of rotation, we can plug these values into the formula:

I = 12 kg × (4 m)²

Now, we'll square the distance:

I = 12 kg × 16 m²

Finally, multiply the mass and the squared distance:

I = 192 kg·m²

So, the moment of inertia of the object is 192 kg·m².

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Solving a system of equations we can see that each pair of pants costs €82.94 and each coat costs €26.37

Let's define the variables:

x = cost of a pant

y = cost of a coat.

First, we know that:

3x + 2y = 245

And then there are discounts of 20% and 5%, and the cost of one of each is 100.75, then:

0.8x + 0.95y = 100.75

Then we have a system of equations:

3x + 2y = 245

0.8x + 0.95y = 100.75

We can isolate x on the second equation to get:

x = (100.75 - 0.96y)/0.8

x = 125.9 - 1.2y

Replace that in the other equation:

3*(125.9 - 1.2y) + 2y = 245

Solving for y:

3*125.9 - 3*1.2y + 2y = 245

y*(2 - 3*1.2) = 245 - 3*125.9

y = (245 - 3*125.9)/(2 - 3*1.2)

y = 82.94

Then the value of x is:

x = 125.9 - 1.2*82.94

x = 26.37

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you won't get a proper answer, but once you find out, what height did the plane start at?

Step-by-step explanation:

To solve the equation:

6(sin(x))^2 + 7cos(x) - 3 = 0

We can use the identity:

sin^2(x) + cos^2(x) = 1

Rearranging the equation, we get:

6(1-cos^2(x)) + 7cos(x) - 3 = 0

Expanding and rearranging, we get:

6cos^2(x) + 7cos(x) - 9 = 0

This is now a quadratic equation in terms of cos(x).

Using the quadratic formula, we get:

cos(x) = [-7 ± √(7^2 - 4(6)(-9))]/(2(6))

cos(x) = [-7 ± 13]/12

cos(x) = 1/2 or -3/2

Now we use the inverse cosine function to find x for each solution for cos(x).

When cos(x) = 1/2, we get:

x = π/3 + 2πk or x = 5π/3 + 2πk

When cos(x) = -3/2, we get:

there are no solutions for this case.

Therefore, the general solution to the equation is:

x = π/3 + 2πk or x = 5π/3 + 2πk where k is an integer.

The vector x whose image under T is b is [5/2, -3/2, -1].

We can use matrix multiplication to find a vector x whose image under T is b. We can find x by solving the equation Ax = b. Whether x is unique or not depends on whether A is invertible. Given that T is defined by T(x) = Ax. Here, A is a matrix and x is a vector. We need to find a vector x whose image under T is b. In other words, we need to find x such that T(x) = b.

To find x, we can solve the equation Ax = b. We can do this by using the inverse of A if it exists. If A is invertible, then the solution is unique. If A is not invertible, then there are either no solutions or infinitely many solutions. Now, let's use this method to find a vector x whose image under T is b. We are given A and b as follows:
A = [0 -4 2][4 1 -3][1 -3 2]
b = [2][-9][4]

We need to solve the equation Ax = b. To do this, we can multiply both sides of the equation by A inverse (if it exists). This gives us:
x = A inverse * b

To find A inverse, we need to calculate the determinant of A. We can do this by using cofactor expansion along the first row of A. This gives us:
det(A) = 0 - (-4)*(-3) + 2*1 = 6

Since det(A) is not equal to zero, A is invertible. Therefore, we can calculate A inverse using the formula:
A inverse = (1/det(A)) * adj(A)

Here, adj(A) is the adjugate matrix of A. We can calculate adj(A) by taking the transpose of the matrix of cofactors of A. This gives us:
adj(A) = [5 -6 -14][-2 2 4][-4 5 6]

Therefore, we have:
A inverse = (1/6) * [5 -6 -14][-2 2 4][-4 5 6]

Multiplying A inverse by b, we get: x = [5/2][-3/2][-1]
Therefore, the vector x whose image under T is b is [5/2, -3/2, -1].

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(a) To calculate the permeate composition, yp, we can use the formula:

yp = (P * x * (Ph - p₁) * t * 0) / (q * (Ph - p₁) + P * x * t * 0)

Given:

x = 0.5 (mole fraction of gas A)

Ph = 80 cm Hg (feed-side pressure)

p₁ = 20 cm Hg (permeate-side pressure)

P = 400 x 10^(-10) cm³(STP) cm/(s cm² cm Hg) (permeability)

t = 2 x 10³ cm (membrane thickness)

0 = 0.25 (fraction of feed permeated)

q = feed flow rate (to be determined)

Substituting the given values into the formula:

yp = (400 x 10^(-10) * 0.5 * (80 - 20) * 2 x 10³ * 0) / (q * (80 - 20) + 400 x 10^(-10) * 0.5 * 2 x 10³ * 0)

Since 0 * anything equals zero, we can simplify the formula to:

yp = 0

Therefore, the permeate composition, yp, is zero.

(b) To calculate the reject composition, xo, we can use the formula:

xo = 1 - yp

Since we found in part (a) that yp = 0, we can conclude that:

xo = 1 - 0

xo = 1

Therefore, the reject composition, xo, is 1.

(c) To calculate the feed flow rate, q, we can rearrange the formula from part (a) and solve for q:

q = (P * x * (Ph - p₁) * t * 0) / (yp * (Ph - p₁) + P * x * t * 0)

Substituting the given values into the formula:

q = (400 x 10^(-10) * 0.5 * (80 - 20) * 2 x 10³ * 0) / (0 * (80 - 20) + 400 x 10^(-10) * 0.5 * 2 x 10³ * 0)

Again, since 0 * anything equals zero, we can simplify the formula to:

q = 0

Therefore, the feed flow rate, q, is zero.

In conclusion:

(a) The permeate composition, yp, is zero.

(b) The reject composition, xo, is 1.

(c) The feed flow rate, q, is zero.

Please note that the calculations resulted in a feed flow rate of zero, which may suggest an inconsistency in the given values or equations. Double-checking the values and equations is recommended to ensure accuracy.

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Hexadecimal and binary are two numbering systems that are commonly used in computing. Binary is a base-2 numbering system, which means it uses only two digits, 0 and 1, to represent all numbers. Hexadecimal, on the other hand, is a base-16 numbering system, which means it uses 16 digits, from 0 to 9 and A to F, to represent numbers.

One hexadecimal digit can represent 16 different values, while one binary digit can represent only two values (0 or 1). This means that one hexadecimal digit can represent 16 times as many values as one binary digit.

To understand this better, let's consider an example. The binary number 1111 is equivalent to the hexadecimal number F. In binary, 1111 can represent only one value, which is 15 in decimal. However, in hexadecimal, the digit F can represent 16 different values, from 0 to 15 in decimal.

Therefore, using hexadecimal notation can be more efficient and compact than using binary notation, especially when dealing with large numbers. In addition, hexadecimal is often used in computing to represent memory addresses, color codes, and other values that need to be represented in a compact and easily readable format.

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Answer:

BB

Step-by-step explanation:

BBBBBBBBBB BBBBBBBBBBBBBBBBBBBBBBBBBBB

ITS B I GOT IT RIGHT ON THE EXAM

Answer:

b Yes, because the number of wheels is specific to the number of cars in the parking lot

Step-by-step explanation:

because i did this quiz and got it right

Answer:

-12m-6n

Step-by-step explanation:

Let's break this down systematically

Start:

8m + 2n - 4(5m - 2n)

Use the distributive property

8m + 2n - 4(5m - 2n)

8m + 2n - 20m - 8n

Match like terms m and n

8m - 20m = -12m

2n - 8n = -6n

-12m-6n

Answer:

Most likely B.

Step-by-step explanation:

A. When being compared to each other, they're not alternate interior angles.

B. I think so...?

C. Angle 3 is the only interior angle.

D. Pretty sure that they have to be on the same line to count as "supplementary".  

Answer:

a= -c-3h/h

Step-by-step explanation:

Answer:

so subtract -2v to the left side add 5 to the right side so your left with

v = 15

Answer:

15 = v

Step-by-step explanation:

First start by grouping like terms,

=> - 5 - 10 = 2v - 3v

evaluate the LHS and RHS

=> - 15 = - v

Divide through by the coefficient of v, which in this case is - 1

=>

\( \frac{ - 15}{ - 1} = v\)

Therefore, 15 = v

Answer:

The price of one sweater is $11 and the price of one shirt is $8.

The required length of one of the longest sides is 29 in the given pentagon.

The pentagon has 3 sides of length (2x - 1) and 2 sides of length (x + 5) and the perimeter of the pentagon is 127.

We know that the perimeter of the pentagon is the total length of all its sides, so we can set up the following equation:

3(2x - 1) + 2(x + 5) = 127

Apply the distributive property of multiplication,

6x - 3 + 2x + 10 = 127

Combine the likewise terms of the equation,

8x + 7 = 127

Finally, we can solve the equation by subtracting 7 from both sides and dividing both sides by 8:

8x = 120

x = 15

Therefore, the length of one of the longest sides is (2 × 15 - 1) = 29.

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The chi-square statistic should not be used under certain circumstances, specifically when the expected frequencies in any cell of the contingency table meet certain criteria.

The two conditions that indicate when the chi-square statistic should not be used are if the expected frequencies are greater than 5 for any cell or if the expected frequencies are less than 5 for any cell. When the expected frequencies are greater than 5, it implies that the sample size is large enough, and the chi-square test can be considered valid and reliable. However, when the expected frequencies are less than 5, it may lead to unreliable results and less accurate statistical inference. In such cases, the assumptions underlying the chi-square test may not hold, and alternative methods or tests should be considered, such as Fisher's exact test or Monte Carlo simulation. Using the chi-square test with expected frequencies that do not meet these criteria can lead to inflated type I error rates and unreliable conclusions. Therefore, it is important to assess the expected frequencies in each cell of the contingency table before applying the chi-square test and consider alternative approaches if the conditions are not met.

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Answer:

option a 0.06 bared

Answer:

-6.95 x 10^10

Step-by-step explanation:

Answer: The sign of the product is negative because a positive multiplied by a negative is a negative.

Step-by-step explanation:

hope it helped xx

The given problem is asking for a test to see if the sample mean is significantly different from 85 at the 0.05 level. To solve the problem, we can use the following formula:$$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$$where$\bar{x}$ = sample mean$\mu$ = population mean$s$ = sample standard deviation$n

$ = sample sizeTo calculate the t-value, we need to calculate the sample mean and the sample standard deviation. The sample mean is calculated as follows:$$\bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}$$where $x_i$ is the score of the $i$th student and $n$ is the sample size.

Using the given data, we get:$$\bar

{x} = \frac{78+89+67+85+90+83+81+79}{8}

= 81.125$$The sample standard deviation is calculated as follows:$$

s = \sqrt{\frac{\sum_{i=1}^{n} (x_i - \bar{x})^2}{n-1}}$$Using the given data, we get:$$

s = \sqrt{\frac{(78-81.125)^2+(89-81.125)^2+(67-81.125)^2+(85-81.125)^2+(90-81.125)^2+(83-81.125)^2+(81-81.125)^2+(79-81.125)^2}{8-1}}

= 7.791$$Now we can calculate the t-value as follows:$$

t = \frac{\bar{x} - \mu}{\frac{s}

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The probability that a second call will not arrive in the next 20 seconds is approximately 0.2636 or 26.36%.

Poisson probability is a mathematical concept that describes the probability of a certain number of events occurring in a fixed interval of time or space, given a known average rate of occurrence. The Poisson probability distribution is named after French mathematician Siméon Denis Poisson, who introduced it in the early 19th century to model the occurrence of rare events, such as errors in counting or measurement, accidents, or phone calls.

The Poisson probability distribution is a discrete probability distribution that gives the probability of a certain number of events (x) occurring in a fixed interval (t), when the average rate of occurrence (λ) is known. The Poisson probability distribution assumes that the events occur independently and at a constant average rate over time or space. The formula for Poisson probability is:

P(x; λ) = (\(e^{-\lambda}\)) * λˣ) / x!

where:

P(x; λ) = the probability of x occurrences in a given interval, when the average rate is λ

e = a mathematical constant e (approximately 2.71828)

λ = it is the average rate of occurrence in the given interval

x = it is number of occurrences in the given interval

Given that calls for dial-in connections arrive at an average rate of four per minute and follow a Poisson distribution, we can use the Poisson probability formula to solve this problem. The Poisson probability formula is:

P(x; λ) =  (\(e^{-\lambda}\)) * λˣ) / x!

where:

P(x; λ) = the probability of x occurrences in a given interval, when the average rate is λ

e = a mathematical constant e (approximately 2.71828)

λ = the average rate of occurrence in the given interval

x = it is the number of occurrences in the given interval

In this problem, we are interested in finding the probability that a second call will not arrive in the next 20 seconds, given that a call has already arrived at the beginning of a one-minute interval. Since we are given the average rate of calls per minute, we need to adjust the interval to 20 seconds, which is 1/3 of a minute. Therefore, the average rate of calls per 20 seconds is:

λ = (4 calls/minute) * (1/3 minute) = 4/3 calls/20 seconds

Using the Poisson probability formula, we can calculate the probability of no calls arriving in the next 20 seconds:

P(0; 4/3) = ( \(e^{-4/3}\)* (4/3)⁰) / 0! = \(e^{-4/3}\) ≈ 0.2636

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