Triangles geometry . I neeed help pls

As they vary from month to month, Luis's variable expenses are the utility bill, groceries, clothing and fuel.

Variable expenses is a concept in economics. They are costs that change due to an increase or decrease in the production volume, such as raw material costs.

The variable cost in money is obtained by multiplying, starting from a certain cost, the variable cost in kind by the price of the variable factor. The curves of average variable cost and marginal variable cost are deduced from the curve of variable cost in money according to geometric relationships.

Therefore, as they vary from month to month, Luis's variable expenses are the utility bill, groceries, clothing and fuel.

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By solving some linear equations we can see that:

The first missing number is 5.

The second missing number is 9

Here we have a decomposition of the number 360, this means that if we define x as the missing number, then we must have that:

2*x*2*2*3*3 = 360

So we just need to solve this linear equation.

x*72 = 360

x = 360/72 = 5

x = 5

The missing number in the tree is 5.

Similarly, for the second tree if the missing number is y, we should have:

2*5*4*y = 360

40*y = 360

y = 360/40 = 9

The missing number is 9.

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Answer:

Average speed = 100 km/h

Step-by-step explanation:

Given:

Total distance covered = 250 km

Total time taken = 8:30 am - 6:00 am = 2:30 hours = 2.5

Find:

Average speed.

Computation:

⇒ Average speed = Total distance covered / Total time taken

⇒ Average speed = 250 / 2.5

⇒ Average speed = 100 km/h

Answer:

No, because if you do the vertical line test, the line will hit that two times, Therefore it is not a function.

Step-by-step explanation:

Answer:

$12,760.13 (nearest cent)

Step-by-step explanation:

The formula to calculate the monthly payment for a loan with an APR is:

\(\sf PMT=\dfrac{Pi(1+i)^n}{(1+i)^n-1}\)

where:

Given values:

Substitute the given values into the formula to find the monthly payment:

\(\implies \sf PMT=\dfrac{10000 \cdot 0.006(1+0.006)^{84}}{(1+0.006)^{84}-1}\)

\(\implies \sf PMT = \dfrac{60(1.006)^{84}}{1.006^{84}-1}\)

\(\implies \sf PMT=151.9063658\)

To find the total paid, simply multiply the found monthly payment (PMT) by the term of the loan (in months):

\(\implies \sf Total\:paid=PMT \times 84\)

\(\implies \sf Total\:paid=151.9063658 \times 84\)

\(\implies \sf Total\:paid=12760.13473\)

Therefore, the total paid is $12,760.13 (nearest cent).

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Check the picture below.

so let's simply check about what's its vertex then

\(\textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+40}t\stackrel{\stackrel{c}{\downarrow }}{+6} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)\)

\(\left(-\cfrac{ 40}{2(-16)}~~~~ ,~~~~ 6-\cfrac{ (40)^2}{4(-16)}\right) \implies \left( - \cfrac{ 40 }{ -32 }~~,~~6 - \cfrac{ 1600 }{ -64 } \right) \\\\\\ \left( \cfrac{ -5 }{ -4 } ~~~~ ,~~~~ 6 +25 \right)\implies {\Large \begin{array}{llll} \stackrel{ ~~ seconds~\hfill feet ~~ }{\left( ~~ 1\frac{1}{4}~~ ~~ , ~~ ~~31 ~~ \right)} \end{array}}\)

dy/dx at the point (-1, 2) is 40/7.

To evaluate dy/dx at the point (-1, 2), we will use implicit differentiation on the equation 6x^5 + 6y^2 = -45xy.

Differentiating both sides of the equation with respect to x:

d/dx (6x^5 + 6y^2) = d/dx (-45xy)

Using the chain rule and the power rule for differentiation:

30x^4 + 12y(dy/dx) = -45y - 45x(dy/dx)

Now we will substitute the values x = -1 and y = 2 into the equation:

30(-1)^4 + 12(2)(dy/dx) = -45(2) - 45(-1)(dy/dx)

Simplifying further:

30 + 24(dy/dx) = -90 + 45(dy/dx)

Combining like terms:

24(dy/dx) - 45(dy/dx) = -90 - 30

-21(dy/dx) = -120

Solving for dy/dx:

(dy/dx) = -120 / -21

Simplifying the fraction:

(dy/dx) = 40/7

Therefore, dy/dx at the point (-1, 2) is 40/7.

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The evaluation of the implicit differentiation is -20/11

To evaluate the derivative dy/dx at the point (-1, 2) using implicit differentiation, we'll differentiate the equation 6x^5 + 6y^1 = -45xy with respect to x.

Differentiating both sides of the equation with respect to x:

d/dx(6x⁵ + 6y¹) = d/dx(-45xy)

Using the power rule for differentiation and the chain rule:

30x⁴ + 6(dy/dx)y = -45x(dy/dx) - 45y

Now we'll substitute the given point (-1, 2) into the equation to find the value of dy/dx:

30(-1)⁴ + 6(dy/dx)(2) = -45(-1)(dy/dx) - 45(2)

Simplifying:

30 + 12(dy/dx) = 45(dy/dx) + 90

Rearranging the equation:

12(dy/dx) - 45(dy/dx) = 90 - 30

-33(dy/dx) = 60

Dividing both sides by -33:

dy/dx = -60/33

Simplifying the fraction, we have:

dy/dx = -20/11

Therefore, at the point (-1, 2), the value of dy/dx is -20/11.

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To construct and store a 4 x 2 matrix filled row-wise with the given values in R, you can use the following code:

# Create the matrix

myMatrix <- matrix(c(4.3, 3.1, 8.2, 9.2, 3.2, 0.9, 1.6, 6.5), nrow = 4, ncol = 2, byrow = TRUE)

This code creates a matrix called "myMatrix" with 4 rows and 2 columns, filled row-wise with the provided values.

To overwrite the second column of the matrix with the numbers 8, 9, 11, and 17 in that order, you can use the following code:

# Overwrite the second column

myMatrix[, 2] <- c(8, 9, 11, 17)

This code selects the second column of the matrix using the indexing notation [, 2] and assigns the new values using the c() function. The second column is replaced with the numbers 8, 9, 11, and 17.

Finally, to save the updated matrix to an object named "BruceLee", you can use the following code:

# Save the updated matrix

BruceLee <- myMatrix

Now the updated matrix with the overwritten second column is stored in the object "BruceLee" for further use.

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Given that the drawer includes one pair of brown socks and one pair of white socks, the likelihood of selecting one sock, replacing it, and then selecting another sock is 1/16.

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Here,

n(s)=4

n(e)=1

Probability of choosing a sock, replacing it, and then choosing another sock,

=1/4*1/4

=1/16

Probability of choosing a sock, replacing it, and then choosing another sock will be 1/16 as the drawer contains one pair of brown socks and one pair of white socks.

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The dimensions of a building to be fenced off around a rectangular parcel of land are 10.5 meters and 21 meters.

The Latin word rectus, which meaning "right" or "straight," is the source of the English word "rectangle." The straight sides of a rectangle are a result of its right angles. Rectitude, which refers to moral uprightness, is another term with the same root.

Explanation:

The size of a rectangle

lw = area of rectangle

where,

= length

= width

Thus, perimeter equals 2w plus l.

42 = 2w + l

l = 42 - 2w

Hence,

area = w (42- 2w)

180 = 42w - 2w²

-2w² +42w - 180 = 0

-w² + 21w - 180 = 0

The following is where to find the dimension w;

w = - b / 2a

where

a = -1

b = 21

w = - 21 / 2 × -1

W=10.5 meters.

Then,

l = 42 - 2w

l = 42 - 2(10.5) (10.5)

l=21 meters .Consequently, the measurements are 10.5 meters and 21 meters.

The dimensions of a building to be fenced off around a rectangular parcel of land are 10.5 meters and 21 meters

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Answer:

300 nickels

Step-by-step explanation:

Reading the question, someone has 435 nickels and dimes.

The total is $28.50.

You're trying to find how many nickels he has.

All you need to do is set up a system of equations.

I'm going to use x as the number of nickels and y as the number of dimes.

Based on the question, you can say that

x + y = 435

(the number of nickels and dimes have t equal 435)

and 0.05x + 0.1y = $28.50

(nickels are 5 cents and dimes are 10 cents)

You want to solve for x, the number of nickels.

You can manipulate the first equation by subtracting x on both sides.

After you do that, you will get y = 435 - x. Now, you can substitute this equation into the second one.

First, you can distribute the 0.1.

0.05x  + 0.1(435 - x) = 28.50

Then, you can put the two x's together.

0.05x + 43.5 -0.1x = 28.50

Next, you can subtract 43.5 on both sides to isolate x.

-0.05x + 43.5 = 28.50

Finally, you can divide on both sides to get x, which is the number of nickels.

-0.05x = - 15

x = 300 nickels

the control limits for the x-bar chart are 9.7439 minutes (LCL) and 11.0561 minutes (UCL), and the control limits for the R chart are 0 minutes (LCL) and 2.0529 minutes (UCL).

To compute the control limits for the x-bar (mean) and R (range) charts, we'll use the following formulas:

For the x-bar chart:

Upper Control Limit (UCL) for x-bar = x-double-bar + A2 * R-bar

Lower Control Limit (LCL) for x-bar = x-double-bar - A2 * R-bar

For the R chart:

Upper Control Limit (UCL) for R = D4 * R-bar

Lower Control Limit (LCL) for R = D3 * R-bar

Where:

x-double-bar = Overall mean of the sample means

R-bar = Overall mean of the sample ranges

A2 = Constant from the control chart constants table

D4 = Constant from the control chart constants table

D3 = Constant from the control chart constants table

For sample sizes of 4, the control chart constants are as follows:

A2 = 0.729

D4 = 2.281

D3 = 0

Given the information you provided:

Overall mean (x-double-bar) = 10.4 minutes

Average range (R-bar) = 0.9 minutes

Let's calculate the control limits:

For the x-bar chart:

UCL for x-bar = 10.4 + 0.729 * 0.9

             = 10.4 + 0.6561

             = 11.0561 minutes

LCL for x-bar = 10.4 - 0.729 * 0.9

             = 10.4 - 0.6561

             = 9.7439 minutes

For the R chart:

UCL for R = 2.281 * 0.9

         = 2.0529 minutes

LCL for R = 0

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Answer:

f(x) = x² - 10x + 22

Step-by-step explanation:

Let's assume the quadratic polynomial as:

f(x) = ax² + bx + c

Now we know that if one of the zeroes is 5 + √3, then the other zero must be 5 - √3 (because complex roots always come in conjugate pairs).

So the sum of the zeroes will be:

(5 + √3) + (5 - √3) = 10

10 = 2 * 5

The product of the zeroes will be:

(5 + √3) * (5 - √3) = 25 - 3 = 22

Now, using the sum and product of zeroes, we can write:

b/a = 10

c/a = 22

Solving for b and c, we get:

b = -10a

c = 22a

Substituting these values in f(x), we get:

f(x) = a(x - 5 - √3)(x - 5 + √3)

Expanding the right-hand side:

f(x) = a[(x - 5)² - (√3)²]

f(x) = a(x² - 10x + 22)

Comparing the coefficients of f(x) with ax² + bx + c, we get:

a = 1, b = -10, c = 22

Therefore, the quadratic polynomial is:

f(x) = x² - 10x + 22

Answer:

the positive of 65 milion is 65 million and the negitive iis -65 mil i think

Step-by-step explanation:

Answer:

6.5*10^7

Step-by-step explanation:

65,000,000 and came up with the answer 6.5*10^7.

The height of the cup that can be made from the least amount of paper is 17 cm.

A cone-shaped paper cup is to hold 100 cubic cm of water. Find the height and the radius of the cup that can be made from the least amount of paper.

Use the volume of a cone formula: (1/3)*pi*r^2*h = V; to find h in terms of r.

(1/3)*pi*r^2*h = 100

multiply equation 3 to get rid of the denominator

pi*r^2*h = 300

h = 300/(pi * r^2)

:

Using the surface area equation: SA = pi*r^2 + (pi*r*L), find L using r and h

L = \(\sqrt{h^{2} +r^{2} }\)

Substitute above for L in the SA equation

:

\(SA = \pi r^{2} + \pi r\sqrt{\frac{300}{\pi r^{2} } + r^{2} }\)

:

Using this equation in my TI83, the graph showed the minimum radius to occur at appox 2.37 cm

:

Find the height using this value:

h = 17 cm

Check solution by finding the volume

V = (1/3) * pi * 2.37^2 * 17

V = 99.994 ~ 100 cm

Hence , the height of the cup that can be made from the least amount of paper is 17 cm.

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The formula to find the tangent line to a curve at a given point is y = f'(x) (x - x₀) + f(x₀).

The derivative of the function, f'(x) is calculated at the given point, x₀. Then, the equation of the tangent line is found by substituting the x₀ and f'(x) values into the formula.

To find the tangent line to a curve at a given point, the formula for the slope of the tangent line must be used. The slope of a tangent line is equal to the derivative of the function at that point. The resulting equation is a line with a slope equal to the derivative of the function at the given point, and a y-intercept equal to the value of the function at the given point. For example, if you want to find the tangent line to the function f(x) = 4x² + 3 at the point (2, 19), the derivative of the function at that point is f'(x) = 8x = 8(2) = 16. Then, the equation of the tangent line is y = 16(x - 2) + 19.

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Concurrent line segments are those that cross at least three other line segments at the same location.

Concurrent line segments are those that cross at least three other line segments at the same location. In geometry, if two lines intersect at a single point in a plane or higher-dimensional space, they are said to be concurrent. In contrast to parallel lines, they exist. Concurrent lines are those that cross more than one line at the same time through a single point in a plane. The point of concurrency is a location that each of those lines shares. Triangles provide another example where this concurrency characteristic can be observed.

Here,

Concurrent line segments are those where three or more line segments cross each other at the same location.

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Answer:

the answers is 160

you take 180-120=60

m<6= 60

Step-by-step explanation:

The value of y when x is 9 and the constant of proportionality(k) is 4 is 36.

A ratio is a comparison between two similar quantities in simplest form.

Proportions are of two types one is the direct proportion in which if one quantity is increased by a constant k the other quantity will also be increased by the same constant k and vice versa.

In the case of inverse proportion if one quantity is increased by a constant k the quantity will decrease by the same constant k and vice versa.

Given, x and y vary directly and y is 44 when x is 11.

Let, y ∝ x.

y = kx.

44 = 11k.

k = 44/11.

k = 4.

Now x = 9.

y = 4×9.

y = 36.

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Answer:

Step-by-step explanation:

The answer is C because t = 2 so 75x2=150 and 150 + 10= 160.

Answer:

I do have extra points I can give.

Step-by-step explanation:

The constraints are xy = 1 and y² + z² = 25.

To find the extreme values of f subject to the given constraints, we will use the method of Lagrange multipliers. This method allows us to optimize a function subject to constraints by introducing additional variables called Lagrange multipliers.

We start by defining the Lagrange function L, which combines the original function f with the constraints. The Lagrange function is given by:

L(x, y, z, λ, μ) = f(x, y, z) - λ(xy - 1) - μ(y² + z² - 25)

Here, λ and μ are the Lagrange multipliers associated with the two constraints. The first term f(x, y, z) is the original function, and the subsequent terms are the constraints multiplied by their respective multipliers.

Next, we need to find the partial derivatives of the Lagrange function with respect to all the variables: x, y, z, λ, and μ.

∂L/∂x = 0 (Partial derivative of L with respect to x)

∂L/∂y = 0 (Partial derivative of L with respect to y)

∂L/∂z = 0 (Partial derivative of L with respect to z)

∂L/∂λ = 0 (Partial derivative of L with respect to λ)

∂L/∂μ = 0 (Partial derivative of L with respect to μ)

We solve the system of partial derivative equations obtained in step 2 to find the values of x, y, z, λ, and μ that satisfy the equations.

Once we obtain the solutions, we need to analyze the critical points. We evaluate the original function f at these points to determine whether they correspond to maximum or minimum values.

After analyzing the critical points, we compare the values of f at these points to determine the maximum and minimum values that satisfy the given constraints.

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By applying the definitions of rigid transformation ((x, y) → (0.5 · x, 0.5 · y)) and dilation, we conclude that the coordinates of Q'(x, y) are (0.1).

Herein we must apply a rigid transformation into a given point to determine an image. Rigid transformations are transformations applied on a geometric locus such that Euclidean distance is conserved. Dilations are a kind of rigid transformations such that:

(x, y) → (k · x, k · y), for k > 0

If we know that Q(x, y) = (0, 2) and k = 0.5, then the coordinates of Q' are:

Q'(x, y) = (0.5 · 0, 0.5 · 2)

Q'(x, y) = (0, 1)

By applying the definitions of rigid transformation ((x, y) → (0.5 · x, 0.5 · y)) and dilation, we conclude that the coordinates of Q'(x, y) are (0.1).

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Answer: Q' = (0,1)

Step-by-step explanation: just did it on edge

Answer:

\(4(x - 9)(x - 7)\)

Step-by-step explanation:

...

The probability of Jack taking 2 red candies is 3/28.

What do you mean by a union in probability?
The letter "U" (union) stands for "or." Specifically, P(AB) represents the probability of that event A or event B occurring. The sample points that are present in both event A and event B must be counted in order to determine P(AUB).

The new probability set made up of all the elements from both sets is created when two sets are joined. When two sets intersect, a new set is created that includes every element from both sets.

Solution Explained:

Given in the question,

A bag contains 3 red and 5 green candies.

Total possibilities is 3 + 5 = 8  

Jack takes a candy at random and eats it  

A/Q there are 3 red candies out of 8, the probability is given by,

P(R) = 3/8

Now there are 2 red candies out of 7, so the probability is given by,

P(R') = 2/7

The probability of both events is given by,

P(2R) = P(R) × P (R') = 3/8 × 2/7 = 3/28

Therefore, the probability of Tim taking 2 red candies is P(2R) = 3/28

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The equation of circle is,

⇒ x² + y² = 100

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

Here is a point (6, 8) on a circle centered (0,0) at.

Now, Distance between the point (6, 8) and (0, 0) is,

⇒ D = √(6 - 0)² + (8 - 0)²

⇒ D = √36 + 64

⇒ D = √100

⇒ D = 10

We know that;

Distance between the point (6, 8) and (0, 0) is the radius of circle.

And, The equation of circle is,

⇒ (x - a)² + (y - b)² = r²

Where, (a, b) is center of circle and r is radius of circle.

Here, Center of circle = (0, 0)

And, Radius of circle = 10

So, We get;

The equation of circle is,

⇒ (x - a)² + (y - b)² = r²

⇒ (x - 0)² + (y - 0)² = 10²

⇒ x² + y² = 100

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Answer:

19. 188

20. 18

21. 5

21. 4

Step-by-step explanation:

634.58 would round up to 635 and 436.79 would round up to 437.

20. 37.86 would round up to 38 and 19.92 would round up to 20.

21. 14.49 would round to 14 and 8.59 would round up to 9.

22. 7.45 would round down to 7 and 2.93 would round up to 3.

Answer:

90

Step-by-step explanation:

9*6=54

54*5= 270

270/3=90

20 litres of water measures 44 pounds in pound measuring system.

What is pound?

The British imperial and American customary systems of measurement both utilise the pound as a unit of mass. The international avoirdupois pound, which is legally defined as exactly 0.45359237 kilogrammes and is divided into 16 avoirdupois ounces, is the definition that is currently most frequently used.

The litre is also a measuring unit for mass of liquids and fluids.

The value of 1 litre when converted to pounds is -

1 Litre = 2.2 pounds

The amount of water in litre is given as - 20 litre

To convert litre into pound use the formula -

Weight in pounds = Weight in litre × 2.2

Substitute the values in the equation -

Weight in pounds = 20 × 2.2

Weight in pounds = 44 pounds

Therefore, the weight in pounds is 44 pounds.

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