Yes carbon dioxide is needed for photosynthesis while cellular respiration needs oxygen and dispurses carbon dioxide
Se dispara una bala con una velocidad de v = 300[m/s] contra un cascarón esférico de papel que gira con MCU respecto a un eje vertical. Sabiendo que el radio del cascarón es de 10[cm]. Calcular la rapidez angular mínima que deberá girar el cascarón para que el proyectil haga únicamente un agujero. La dirección del movimiento de la bala pasa por el centro de la esfera.
Answer:
w = 4.712 10⁻³ rad / s
Explanation:
For this exercise, the time it takes for the bullet to travel the distance of 2R must be equal to the time that the hole must travel half a circle.
Let's start by calculating the time it takes for the bullet, which is going at constant speed.
v = x / t
t = x / v
t = 2R / v
t = 2 0.10 / 300
t = 6.666 10⁻⁴ s
As they ask that a single hole is formed in this time, it must be rotated half a circle, that is, θ =π rad, for which we use the angular scientific relations, where the shell has constant angular velocity
w = θ / t
w = π / 6,666 10⁻⁴
w = 4.712 10⁻³ rad / s
A speed boat travels 200 miles at a speed of 20 miles/hr. How much time will it take to
travel the 200 miles?
Answer:it will take 10 hours
Explanation: The way we get this answer is if the boat travels 200 miles at 20 mph that means that every 20 miles the boat traveled an hour would pass. Using this we can see that 20 fits into 200, 10 times, meaning that the time it would take to travel would be 10 hours.
The time it will take to travel 200 miles is 10 seconds
The calculation can be done as follows
= 200/20
= 10 seconds
Hence the amount of time it will take the speed boat to travel 200 miles is 10 seconds
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Decide whether these are true or false. Type out the whole sentence in the space and type a "T" beside the letter. Retype the sentences that are not correct. A. An object has acceleration if its velocity is changing. B. Force is measured in joules. C. Gravity is a force.
Answer:
1. True.
2. False.
3. True.
Explanation:
A. True: An object has acceleration if its velocity is changing. In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
B. False: Force is measured in joules. Force is a product of the mass of an object and its rate of acceleration. Thus, force is actually measured in Newton.
C. Gravity is a force. Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.
A metal rod is 25.000 cm long at 25.0 degrees Celsius. When heated to 102.0 degrees Celsius, it is 25.054 cm long. What is the coefficient of linear expansion for this metal.
A 40 W motor pulled a crate of bananas 5 meters horizontally in 120 seconds. How many Joules of work are done lifting the crate of bananas?
The total work done on the crate of bananas is 4800 J (the work done to move it horizontally).
What is work done?Work done is defined as the product of displacement and force, w = FS.
Here,
There are two parts to the work done on the crate of bananas: the work done to move it horizontally and the work done to lift it vertically.
First, let's calculate the work done to move the crate horizontally. The formula for work is,
Work = Force x Distance x cos(Ф)
where theta is the angle between the force and the displacement. In this case, the force is the tension in the rope, and it is pulling horizontally. So, theta is 0 degrees, and cos(Ф) is 1.
The distance the crate is moved horizontally is 5 meters, and the force applied by the motor is,
Force = Power / Velocity = 40 W / (5 m / 120 s) = 960 N
So, the work done to move the crate horizontally is:
Work = 960 N x 5 m x cos(0) = 4800 J
The distance the crate is lifted vertically is not given in the problem, so we cannot calculate the work done to lift the crate without this information.
Therefore, the total work done on the crate of bananas is 4800 J (the work done to move it horizontally).
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when a desk is horizontally pushed across a floor at a steady speed in a straight-line direction, the amount of friction acting on the desk is
When a desk is horizontally pushed across a floor at a steady speed in a straight-line direction, the amount of friction acting on the desk is: equal to the applied force and in the opposite direction.
When an object is in motion, there are different types of friction that can act on it. In this case, as the desk is being horizontally pushed across the floor at a steady speed, the type of friction involved is kinetic friction.
Kinetic friction acts in the opposite direction to the motion of the object. In other words, when the desk is pushed forward, the kinetic friction force acts backward.
When the desk is moving at a steady speed, it means that the applied force pushing the desk is balanced by the kinetic friction force. This balance of forces allows the desk to maintain a constant velocity and not accelerate.
Therefore, the amount of friction acting on the desk is equal to the applied force and in the opposite direction, ensuring that the desk moves at a steady speed without accelerating.
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Two cars crash in a head-on collision and come to a stop. The crash analysts created the data table
below based on their observations from the scene. Based on their findings, what can be concluded
about the impact forces experienced by each vehicle?
Vehicle A
Vehicle B
Impact time
0.01 sec
0.01 sec
Mass of vehicle
3000kg
1000kg
velocity before impact
10 m/s
- 30 m/s
The impact force for Vehicle A was the same as the impact force for Vehicle B
The impact force for Vehicle A was greater than the impact force for Vehicle B
The impact force for Vehicle A was equal and opposite to the impact force for Vehicle B
The impact force for Vehicle A was less than the impact force for Vehicle B
The impact force for vehicle A was equal and opposite to the impact force for vehicle B.
The given parameters;
Vehicle A:
impact time of vehicle A, t = 0.01 smass of vehicle A, m = 3000 kgvelocity of vehicle A before impact, v = 10 m/sVehicle B:
impact time of vehicle A, t = 0.01 smass of vehicle A, m = 1000 kgvelocity of vehicle A before impact, v = -30 m/sThe impact force for vehicle A is calculated as follows;
\(F = ma = \frac{mv}{t} = \frac{3000 \times 10}{0.01} = 3,000,000 \ N\)
The impact force for vehicle B is calculated as follows;
\(F = ma = \frac{mv}{t} = \frac{1000 \times -30}{0.01} = - 3,000,000 \ N\)
Thus, we can conclude that the impact force for vehicle A was equal and opposite to the impact force for vehicle B.
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How can you show that pressure increases with the increase of the force?
To increase pressure, either force has to be in increased or area of contact has to be decreased. Pressure can be increased by decreasing the force. With neat diagram, describe an experiment to show that pressure increase if the surface area is decreased, keeping the applied force the same.
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Gauge pressure is the pressure relative to the ambient pressure. Various units are used to express pressure
This assumes that the force is directed perpendicularly toward the surface area. If you increased the amount of force but applied it over the same area, then the pressure would increase proportionally.
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Consider a force F = 80 N applied to a beam as shown in Fig. 8-37. The length of the beam is = 5.0 m, and 0 = 37°, so that x = 3.0m and y = 4.0 m. Of the following expressions, which ones give the correct torque produced by the force F around point P? (a) 80 N.(b) (80 N)(5.0 m).(c) (80 N)(5.0 m) (sin 37°).(d) (80 N)(4.0 m).(e) (80 N)(3.0 m).(f) (48 N)(5.0 m).(g) (48 N)(4.0 m) (sin 37°).
The math demonstrates that all three torques are equivalent.(80 N)(5.0 m)(sin 37∘)).(48 N)(5.0 m) (5.0 m).(80 N)(3.0 m) (3.0 m).
Three different approaches to express the torque are demonstrated by equations such. = rFsin. It can be the sine of the angle between them, the product of the force, the lever arm, and the response (c). It may be the result of the force and the part of the lever arm that is perpendicular to the force, as in answer (e). Another way to write it is as the sum of the force parallel to the lever arm and the lever arm, as in the following response (f). The math demonstrates that all three torques are equivalent.
(80 N)(5.0 m)(sin 37∘)).
(48 N)(5.0 m) (5.0 m).
(80 N)(3.0 m) (3.0 m).
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Why is an object’s mass, rather than its weight, used to indicate the amount of matter it contains?.
An object's mass rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force experienced by a body. The weight of a body can be different as it depends on where and under what conditions it is kept.
However mass is the measure of the amount of matter contained in a body and it is always constant.
Weight is defined as the amount of force exerted on a body by a moving gravitational field or any other field at the surface of the earth. It is measured in Newton (N)
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A basketball is dropped from top of the rim. It takes 1.3s to fall, what is the displacement?
a. 8.45 m
b. 8.321 m
c. 33.67 m
d. 33.8 m
Answer:
d = 8.45 m
Explanation:
Given that,
A basketball is dropped from top of the rim.
It takes 1.3s to fall.
We need to find the displacement of the basketball. Let the displacement is d. Using second equation of kinematics,
\(d=ut+\dfrac{1}{2}at^2\)
Where
u is the initial velocity, u = 0
a = g
So,
\(d=\dfrac{1}{2}\times 10\times 1.3^2\\\\d=8.45\ m\)
So, the displacement of the basketball is 8.45 m.
1. Two 500 g point masses are rotating on a light frame at a radius of 0.1 m from a vertical axis. The angular speed of the system is 20 rad s-1. a a) What is the moment of inertia of the system about the axis? b) What is the angular momentum of the system about the axis? c) If the masses were pulled into a radius of 0.05 m by an internal radial force, what would the angular momentum of the system now be? d) What is the new angular speed of each mass? e) By how much did the energy of the masses change?
(a) The moment of inertia of the system about the axis can be calculated using the formula for the moment of inertia of a point mass rotating about an axis.
(b) The angular momentum of the system about the axis can be determined by multiplying the moment of inertia by the angular speed.
(c) If the masses are pulled into a smaller radius, the moment of inertia will change, resulting in a new angular momentum for the system.
(d) The new angular speed of each mass can be calculated using the principle of conservation of angular momentum.
(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system.
(a) To calculate the moment of inertia of the system about the axis, we consider the two point masses rotating at a given radius. The moment of inertia for each point mass is given by the formula I = m * r², where m is the mass and r is the radius.
Since there are two masses, we can calculate the total moment of inertia by summing the individual moments of inertia.
(b) The angular momentum of the system is determined by multiplying the moment of inertia by the angular speed. Using the formula L = I * ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular speed, we can find the angular momentum of the system.
(c) If the masses are pulled into a smaller radius, the moment of inertia will change. We can calculate the new moment of inertia using the same formula as in (a) but with the new radius. With the new moment of inertia, we can determine the new angular momentum of the system.
(d) To find the new angular speed of each mass, we apply the principle of conservation of angular momentum. The initial angular momentum of the system is equal to the final angular momentum. By rearranging the equation L = I * ω and solving for ω, we can calculate the new angular speed.
(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system. The initial kinetic energy is given by (1/2) * I * ω², where I is the initial moment of inertia and ω is the initial angular speed.
Similarly, the final kinetic energy can be calculated using the new moment of inertia and angular speed. The difference between the initial and final kinetic energies represents the change in energy of the masses.
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a very large thin plate is centered in a gap of width 0.06 m with different oils of unknown viscosities above and below; one viscosity is twice the other. when the plate is pulled at a velocity of 0 3 m s, the resulting force on one square meter of plate due to the viscous shear on both sides is 29 n. assuming viscous flow and neglecting all end effects, calculate the viscositie
μ1 = 0.97 and μ2 = 1.93 (viscosities of fluid below and above plate respectively.)
We have to find the viscosities above and below the plate
Let us take the viscosities above the plate = μ1 ,and below the plate =μ2
Now the force applied due to top layer of the fluid
Т1 = μ (Δu / Δv )
Here Δu and Δv are the velocity of plate and gap between the plate and upper surface respectively.
Where Δu= 0.3
Δv = 0.03
So,
T1 = μ( 0.3/0.03)
=10μ
Now we have to find the force on plate due to bottom of the fluid
T2 = μ2 ×( Δu / Δv)
T2 = μ2 × (0.3/0.03)
T2= 10μ2
Total force per unit is = T1 + T2
i.e., the sum of two viscous shear .
F/ A = T1 + T2
It is given that sum of two viscous sheer is 29N.
So
T1 + T2 = 29
10μ1 + 10 μ2 = 29
10(μ1 + μ2) = 29
μ1 + μ2 = 2.9
μ2= 2μ1
Hence we get
μ1 + 2μ2 =2.9
3μ1=2.9
μ1 = 2.9/3
0.9667≈ 0.967
μ2 = 2μ1
= 2 × 0.9667
=1.9333 ≈1.93
Therefore the viscosities above and below the plate due to the top layer of the fluid are 0.967 and 1.93 respectively.
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A 3600 kg elephant is 400m away from a 822 kg giraffe. What is the force of gravity between the two animals? (Remember that G is 6.67*10^-11)
Set up the equation:
Force =
x
12
And solve it:
Given that,
Mass of an elephant, m₁ = 3600 kg
Mass of giraffe, m₂ = 822 kg
The distance between elephant and giraffe, d = 400 m
To find,
The force of gravity between two animals.
Solution,
The formula for the force of gravity is given by the formula as follows :
\(F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{3600\times 822}{(400)^2}\\\\=1.23\times 10^{-9}\ N\)
So, the force of gravity is \(1.23\times 10^{-9}\ N\).
Light energy with very low amplitude would be perceived as ________.
The correct option is D. Light energy with very low amplitude would be perceived as DIM.
Light energy is a form of electromagnetic radiation that can be detected by the human eye. It is a type of energy that travels in waves at the speed of light and has both particle-like (photons) and wave-like properties. Light energy can be produced by a variety of sources, such as the sun, light bulbs, and flames.
In physics, light energy is described in terms of its wavelength and frequency, which are related to the speed of light. This relationship is expressed by the equation E=hf, where E is the energy of a single photon of light, h is Planck's constant, and f is the frequency of the light.
Light energy has many applications, including in communication, medicine, and technology. It is used in optical fibers to transmit data, in medical imaging techniques such as X-rays and MRI, and in solar cells to convert sunlight into electricity.
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Complete Question:
Light energy with very low amplitude would be perceived as
a). blue
b). bright
c). red
d) dim
compare and contrast light independent and light dependent reactions.
The statement : Compare and contrast light independent and light dependent reactions is true.
Light-independent reactions, also known as the Calvin cycle or the dark reactions, occur in the stroma of chloroplasts. They do not require light energy directly and can occur in the absence of light.
These reactions utilize the products of the light-dependent reactions, such as ATP and NADPH, to convert carbon dioxide into glucose through a series of enzyme-catalyzed reactions. The light-independent reactions are responsible for the synthesis of carbohydrates and other organic compounds.
On the other hand, light-dependent reactions occur in the thylakoid membrane of chloroplasts and require light energy. They involve the absorption of light by chlorophyll and other pigments, which excite electrons and create an electron transport chain. The energy from the excited electrons is used to generate ATP and NADPH, which are utilized in the light-independent reactions. Additionally, light-dependent reactions produce oxygen as a byproduct through the splitting of water molecules.
In summary, light-dependent reactions capture light energy and convert it into chemical energy (ATP and NADPH), while light-independent reactions utilize that chemical energy to fix carbon dioxide and synthesize carbohydrates.
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Complete question :
Compare and contrast light independent and light dependent reactions. T/F
The length of a rectangular plot of land is 151.28 m, and its width is 72.35 m. What is the perimeter of this plot?
605.1 m
223.6 m
289.4 m
a.
b. 447.3 m
c.
d.
Please select the best answer from the choices provided
OA
OB
OC
OD
\( \large{ \boxed{ \tt{447.3 \: m}}}\)
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An airplane's speed increased from 100m/s to 160m/s, at the average rate of 15m/s^2. How long did it take for the plane to complete this increase in speed?
Answer:
4s
Explanation:
Using the formula of motion as follows:
V = u + at
Where;
V = final velocity (m/s)
U = initial velocity (m/s)
a = acceleration (m/s)
t = time (s)
Based on the provided information, v = 160m/s, u = 100m/s, a = 15m/s², t = ?
V = u + at
160 = 100 + 15t
160 - 100 = 15t
60 = 15t
t = 60/15
t = 4seconds.
Therefore, the time it takes for the plane to complete this increase in speed is 4s.
you try to turn on your laptop computer, but it will not turn on. you formulate the hypothesis that the battery needs to be charged. which of the following accurately describe ways to test the implications of this particular hypothesis? check all that apply. you do nothing and hope that the computer will turn on the next time you try. you replace the battery with one that is fully charged. you plug in the computer and try to charge the battery. you continue trying to type on the computer, even though the screen is black.
The following options accurately describe ways to test the implications of the hypothesis that the battery needs to be charged:
You plug in the computer and try to charge the battery.You replace the battery with one that is fully charged.The following options describe ways to test the hypothesis that the battery needs to be charged:
You do nothing and hope that the computer will turn on the next time you try.This option does not involve any testing of the hypothesis. It is merely waiting for the computer to work again, without any intervention to confirm or disprove the hypothesis.You replace the battery with one that is fully charged.This option is a valid way to test the hypothesis. If the computer turns on with a new, fully charged battery, then it is likely that the old battery needed to be charged.You plug in the computer and try to charge the battery.This option is also a valid way to test the hypothesis. If the computer turns on and charges the battery successfully, then it is likely that the old battery needed to be charged.You continue trying to type on the computer, even though the screen is black.This option does not involve any testing of the hypothesis. It is merely attempting to use the computer, without any intervention to confirm or disprove the hypothesis.In summary, options 2 and 3 are valid ways to test the hypothesis that the battery needs to be charged, while options 1 and 4 do not involve any testing of the hypothesis.
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What are the two missing words in this sentence? A ______ _______ camera detects infrared radiation and uses this information to create a picture
A thermal infrared sensor camera detects infrared radiation and uses this information to create a picture.
How does a thermal infrared sensor camera work?In thermal or infrared detection systems, sensors are used to detect radiation in the infrared region of the electromagnetic spectrum. The thermal energy or heat produced by the scene being watched is detected by an infrared camera, which then transforms it into an electrical signal. After that, this signal is processed to create an image. An infrared camera's ability to detect heat can be quantified very precisely. Infrared cameras can be used to assess thermal performance and gauge the intensity of heat-related issues. In general, bodies and objects produce more radiation when they are heated up. Walls and other solid things cannot be seen through infrared cameras. They are limited to measuring heat.
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a ball falls from height of 20.0 m, hits the floor, and rebounds vertically upward to height of 15.5 m. assume that mball=0.360 kg
what is the impulse (in kg.m/s) delivered to the ball by the floor?
The impulse delivered to the ball by the floor is approximately 13.4 kg⋅m/s using the height.
1. Calculate the initial velocity of the ball just before it hits the floor using the height it falls from (20.0 m):
- Use the equation: v² = u² + 2as, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration due to gravity (9.81 m/s²), and s is the height (20.0 m).
- Solve for v: v² = 0² + 2(9.81)(20.0) => v ≈ 19.8 m/s (downward).
2. Calculate the final velocity of the ball just after it rebounds using the height it rebounds to (15.5 m):
- Use the same equation, v² = u² + 2as, with u = 0 m/s, a = 9.81 m/s², and s = 15.5 m.
- Solve for v: v² = 0² + 2(9.81)(15.5) => v ≈ 17.4 m/s (upward).
3. Calculate the change in momentum of the ball, which is the impulse:
- Impulse = mΔv = m(v_final - v_initial), where m is the mass of the ball (0.360 kg), v_final is the final velocity (17.4 m/s upward), and v_initial is the initial velocity (19.8 m/s downward).
- Impulse = (0.360 kg)(17.4 + 19.8) = (0.360 kg)(37.2 m/s) ≈ 13.4 kg⋅m/s (upward).
So, the impulse delivered to the ball by the floor is approximately 13.4 kg⋅m/s.
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When a plane minor is placed horizontally on level ground at a distance of om from the foot of tower
the top of the tower and its image in the mirror subtend an angle of 90" at the eye. The height of the tower
a) 30m
b) 60m
c) 90 m
d) 120m
Answer:
b : 60m
Explanation:
when a plane mirror is placed horizontally on a level ground at a distance of 60m from the top of tower as shown in figure. a/c to question, The top of tower and its image in the mirror subtend an angle of 90° at the eyes. so, angle made by top of tower and horizontal line is 45° as
???whats the answers??
The answers is 30 miles per hour, the driver is speeding the car up, section-H, 12 minutes, section-D, and 65 miles per hour.
A skydiver with a mass of 70 kg accelerates to Earth at a rate of 9.8 m/s2 due to gravity. What is the force on the skydiver? Explain how you determined the answer and its units.
Explanation:
GIVEN DATA
Mass=70kgAcceleration =9.8m/s2RTF=Forcesince P(momentum)=Mass×Velocity
SOLUTIONFROM NEWTONS SECOND LAW OF MOTION ,F = △P(change in momentum) t(time)F = P2 -P1
t
F= Mv2-Mv1
t
F=M( v2-v1) ,(a=v2-v1)
t t
F= m×aF= 70 × 9.8F= 686 N
ANSWER EXPLANATION IN WORDS
That question is related to Newton's second law of motion, the question ask you to find the force it gives you a mass and a acceleration As we know that the SI unit of acceleration is newton per kilogram or metre per second square It is correct to write metre per second square instead of Newton Per kilogram because because all of them are the SI unit of acceleration so that is the answer we get 686 Newton by Force .
Differentiate between the resolving power and magnifiying power of a lens. What is meant by the term "parfocal"?
Resolving power refers to the ability of a lens to distinguish between two closely spaced objects. It is determined by the wavelength of light and the numerical aperture of the lens.
Magnifying power, on the other hand, refers to the ability of a lens to enlarge the size of an object. It is determined by the focal length of the lens.
The term "parfocal" refers to a type of lens system where multiple lenses have the same focal point when the focus is adjusted. This means that when switching between different lenses, the focus remains the same, making it easier for the user to switch between lenses without losing focus.
Differentiating between the resolving power and magnifying power of a lens involves understanding their respective functions. Resolving power refers to the ability of a lens to distinguish between two closely spaced objects, or in other words, the clarity with which the lens can produce an image. Magnifying power, on the other hand, refers to the degree to which a lens can enlarge the image of an object.
The term "parfocal" is used to describe a set of lenses that, when interchanged on a microscope or other optical instrument, maintain their focus on the same object. This means that when you switch from one parfocal lens to another, only minimal adjustments to the focus are needed, allowing for a seamless transition between lenses with different magnifying powers.
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Resolving Power: It is the ability of a lens to separate or distinguish between closely spaced objects, reflecting the detail that can be seen with the lens.
The magnifying powerMagnifying Power: It denotes how much larger an object appears through a lens compared to its actual size. High magnification doesn't necessarily mean better image quality.
Parfocal: This term refers to lenses that remain in focus even when the magnification or focal length changes. It enables swift adjustments in magnification without needing constant refocusing.
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The brakes of a lorry are in a poor condition
What effect will the condition of the brakes have on thinking distance and the braking
distance of the lorry?
Answer:
friction
Explanation:
Her brakes will squeak and possibly slide or skid on concrete due to her brakes.
BUT it really depends on the condition of the wheels. Now it matters on the surface as well. Has the road been eroded? what has happened with her brakes? and what texture are the wheels? can seismic waves travel through them?
Answer:
thinking distance stays the same and the braking distance increases
AQA Approved.✅
Explanation:
Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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Which of these consumers is an herbivore? *
1. lion
2. deer
3. spider
4. snake
Answer:
2. deer
Explanation:
The lion, spider, and snake eat meat or to an extent.
Deer don't eat meat
Answer:
deer :)
Explanation:
The rest are basically carnivores
q2. is it possible for the particle undergoing tunneling to be found within the barrier, rather than on either side of it?
Yes, it is possible for a particle to be found within the barrier while undergoing tunneling.
This phenomenon is known as quantum tunneling. Quantum tunneling occurs when a particle tunnels through a barrier that is normally too high to be crossed by the particle's kinetic energy. This occurs due to the wave-like nature of particles, which allows them to go through barriers that are otherwise impenetrable.
The wave-like nature of particles allows them to penetrate the barrier, often with a probability greater than zero. This phenomenon is used in many applications in science and technology, such as in quantum computing, where quantum tunneling is used to tunnel qubits through the barrier of a logic gate.
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Critics of the electoral college argue that the system can result in the selection of —
Answer:
President who did not win the popular vote
Explanation:
Critics of the Electoral college argue that the system can result in a selection of what?