With the SR protocol, it is possible for the sender to receive an ack for a packet that falls outside of its current window.
In response to the specific question, the answer is False.
With the SR Protocol , it is not possible for the sender to receive an ACK (Acknowledgment) for a packet that falls outside of its current window.
The Selective Repeat protocol is a flow control method that is used in computer networks. It allows the sender to transmit a number of packets to the receiver before receiving an acknowledgment.
The sender maintains a window of packets that it has sent but has not yet received an acknowledgment for. The receiver, on the other hand, maintains a window of packets that it expects to receive.
As packets are received by the receiver, an acknowledgment is sent back to the sender to confirm that the packet was received successfully. If the sender does not receive an acknowledgment for a particular packet within a certain period of time, it will retransmit that packet.
However, it is not possible for the sender to receive an ACK for a packet that falls outside of its current window.
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how does the interstellar medium affect our view of most of the galaxy?
Answer: It prevents us from seeing most of the galactic disk with visible and ultraviolet light.
(hope this helps) :)
A standing wave has points of constructive interference called _________ and points of destructive interference called ___________.
A. troughs, crests
B. nodes, antinodes
C. antinodes, nodes
D. crests, troughs
Answer:
The answer is nodes because nodes stay in a fixed position.
Explanation:
hope it help
srry if wrong
A standing wave has points of constructive interference called antinodes and points of destructive interference called nodes
What are constructive and destructive interferenceThis position, where the resulting wave is larger than either of the two original, is called constructive interference.
When the first wave is leading, the second wave is down and the addition of the two is zero. This is called destructive interference.
A standing wave occurs when two waves with the same properties moving in the opposite direction, in the same media, interfere with one another.
Nodes are points where the waves interact destructively, causing an appearance of the wave standing still. The opposite of nodes is antinodes where they are points of maximum displacement due to constructive destruction.
Thus the standing wave has points of constructive interference called antinodes and points of destructive interference called nodes
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A ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest. What expression shows the change in momentum as observed by the ground observer?.
From the question, we can see that the momentum is a vector thus the change in the momentum with respect to the ground observer ought to be zero.
What is momentum?The term momentum has to do with the product of the mass and the velocity of a body. Let us recall that the momentum of a body is a vector quantity thus we have to consider the magnitude as well as the direction of the vector.
With this said, we are going to consider the question more critically. We are told that; a ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest.
Looking at the fact that the momentum of the body is a vector and we have seen told that the ball bounces off the wall and returns with the same magnitude of momentum the it follows that the change in the momentum is zero.
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Missing parts;
A ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest. What expression shows the change in momentum as observed by the ground observer?
a. 0
b 0.5p
c 2p
d 1.5p
give examples of bottom-up processing from your everyday life
bottom-up processing is a cognitive process that involves perceiving and understanding information based on individual sensory stimuli. examples of bottom-up processing in everyday life include recognizing objects based on their color, shape, and texture, identifying sounds based on their pitch, volume, and timbre, and perceiving tastes and textures based on individual flavors and tactile sensations.
bottom-up processing is a cognitive process that involves perceiving and understanding information based on the individual sensory stimuli. It refers to the way our brains make sense of the world by analyzing the basic features of stimuli and building up a complete perception.
In everyday life, we encounter numerous examples of bottom-up processing. For instance, when we see a new object, our brain processes its individual features such as color, shape, and texture, and then combines them to form a complete perception of the object. This allows us to recognize and understand the object without prior knowledge or expectations.
Similarly, when we hear a new sound, our brain analyzes its pitch, volume, and timbre to recognize and understand the sound. This enables us to differentiate between different sounds and identify their sources.
Bottom-up processing is also involved in other sensory experiences. When we taste a new food, our brain processes the individual flavors and textures to form a perception of the taste. Similarly, when we touch different textures, our brain analyzes the tactile sensations to understand the texture.
In summary, bottom-up processing plays a crucial role in our everyday lives by allowing us to perceive and understand the world around us based on the individual sensory stimuli we encounter.
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An effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.19 m apart are powered by the same function generator producing sine waves at 1,163 Hz frequency. Assume that the speed of sound is 340 m/s. A student walks along a line 12.5 m away and parallel to the line from one speaker to the other speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is the distance between the central maximum and the first maximum (loud) position along this line in m
Answer:
3.04 m
Explanation:
The interference by diffraction of waves is noticeable only when the dimension of the opening through which the wave is passing through is comparable to the wavelength of the passing wave.
It is given that :
Distance between two speakers, d = 1.19 m
Speed of sound, v = 340 m/s
The frequency is f = 1163 Hz
Distance the student walk along the line of the speaker, D = 12.5 m
We know the wavelength of the sound produced by the speakers is given by :
\($\lambda=\frac{v}{f}$\)
\($=\frac{340}{1163}$\)
= 0.29 m
Now the distance between the central maximum and the first maximum position is given by :
\($y=\frac{\lambda D}{d}$\)
\($=\frac{0.29 \times 12.5}{1.19}$\)
= 3.04 m
14. What is the mass of a 250 N bag of groceries?
Answer:
mass = 25.5kg
Explanation:
The gravitational force equivalent, or, more commonly, g-force, is a measurement of the type of force per unit mass – typically acceleration – that causes a perception of weight, with a g-force of 1 g equal to the value of gravitational acceleration on Earth, g, of about 9.8 m/s².
Mass, m = \(\frac{Force}{acceleration due to gravity}\)
\(mass,m=\frac{F}{g} = \frac{250}{9.8}= 25.5 kg\)
Which source of evidence did Wegener use to support his theory of continental drift?
fossils found on Earth
magnetic fields of Earth
satellite mapping of the tropical islands
glaciers found near the poles
Answer:
fossils found on Earth
Explanation:
i just did the test 100%
Answer:
Fossils on Earth
Explanation:
Fossils can show that the continents were all together by putting them together on a map you can see the fit. and when you look where fossils were, they would be right next to each other.
A student drops a ball from the top of a 24 m tall building. Ignoring air resistance, how long did it take for the ball to hit the ground?
Answer:
1.11111 century mother duck
A loaded railroad car of mass 6000 kg is rolling to the right at 2. 0 m/s when it collides and couples with an empty freight car of mass 3000 kg, rolling to the left on the same track at 3. 0 m/s. What is the velocity of the pair after the collision? (let right be positive, left be negative)
The final velocity of the coupled freight cars after the collision is -1.0 m/s, which means that they are moving to the left with a speed of 1.0 m/s.
To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system of objects is conserved if there are no external forces acting on the system. In this case, the two freight cars are the system, and the collision is assumed to be perfectly elastic, which means that the total kinetic energy of the system is conserved as well.
Let the positive direction be to the right, and the negative direction be to the left. Then, the initial momentum of the system is:
p_initial = m1v1 + m2v2
= 6000 kg * 2.0 m/s + (-3000 kg) * 3.0 m/s
= 6000 kgm/s - 9000 kgm/s
= -3000 kg*m/s
where m1 and v1 are the mass and velocity of the loaded car, and m2 and v2 are the mass and velocity of the empty car. The negative sign indicates that the momentum of the empty car is in the opposite direction to that of the loaded car.
After the collision, the two freight cars will move together as a single unit with a common velocity v_final. Since the total momentum of the system is conserved, we can write:
p_final = (m1 + m2) * v_final
where m1 + m2 is the total mass of the system. Setting the initial and final momenta equal and solving for v_final, we get:
v_final = p_initial / (m1 + m2)
= (-3000 kg*m/s) / (6000 kg + 3000 kg)
= -1.0 m/s
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describe the phases of the moon along with a picture.
Answer:
The eight Moon phases:
Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.
The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.
The 8 phases (in order) are:New moon.Waxing Crescent.First Quarter.Waxing Gibbous.Full moon.Waning Gibbous.Third Quarter.Waning Crescent.Explanation:
Hope it is helpful....
Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon
Don't forget to drop a heart have a happy friday
It is easier to lift the load as the load is pushed towards the wheel in a wheelbarrow
a 88-kg box, initially at rest on a frictionless surface, accelerates for 2.1 s over a distance of 96 m while acted on by a constant horizontal force . find the magnitude of .
The magnitude of the constant horizontal force is 1830.4 N.
To find the magnitude of the force, we can use the equation:
F = ma
Where,
F is the force,
m is the mass of the box and
a is its acceleration.
We are given the mass of the box, 88 kg, and the time and distance over which it accelerates. We can use the kinematic equation:d = (1/2)at^2
where,
d is the distance,
a is the acceleration, and
t is the time.
Rearranging the equation gives:
a = (2d) / t^2
Substituting the given values gives:
a = (2 * 96 m) / (2.1 s)^2
a = 20.8 m/s^2
Now we can use the equation for force to find its magnitude:
F = ma
F = 88 kg * 20.8 m/s^2
F = 1830.4 N
Therefore, the magnitude of the constant horizontal force is 1830.4 N.
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plsssssss i need help Which source of law is most like common law: statutes, case law, or administrative law? Explain
Answer:
The answer is "case law".
Explanation:
This law is not based on law, but on legislatures, statutes, or legislation, on judgments. Its also used as a different term with common law, which is the collection of precedents as well as power on a specific subject established in previous judicial decisions that are a part of Common law, which is also recognized as case law to establish by the court system based on legal case law.
In the diagram of the earth’s interior, which part causes the diffraction of P waves made by earthquakes?
Answer:
D
Explanation:
A ball-rolling down a ramp for 5 econd ha an acceleration of 4 mile per econd quared at the ball ha an initial velocity of 2 m/ when it tart down the incline what i it final velocity
The final velocity of the rolling ball when it starts down to incline is 34m/s.
The ball is rolling down of a ramp for 5 second and it has an acceleration of 4 mile per second square and it was a initial velocity of 2 m per second.
According to the work energy conservation principle the total energy of the rolling ball will always remain same so at the bottom of the ramp.
We can write the relation,
V = u + gt
Where,
u the initial velocity, v is the initial velocity, g is the acceleration due to gravity and t is the time taken.
Putting all the values,
V = 2 + 6.4(5)
V = 34m/s.
So, the final velocity of the rolling ball will be 34m/s.
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A 15 kg child slides down a 5 m tall (vertical) slide that is inclined to the horizontal 34°. Her velocity is 5 m/s at the bottom of the sled. How much mechanical energy was lost to friction?
ANSWER
547.5 J
EXPLANATION
Given:
• The child's mass, m = 15 kg
,• The height of the slide, h = 5 m
,• The velocity of the child at the bottom of the slide, v = 5 m/s
Find:
• The loss of mechanical energy due to friction
The loss of mechanical energy due to friction is the difference between the child's gravitational potential energy at the top of the slide, and the child's kinetic energy at the bottom of the slide,
\(PE-KE=mgh-\frac{1}{2}mv^2\)Replace the known values and solve,
\(PE-KE=15kg\cdot9.8m/s^2\cdot5m-\frac{1}{2}\cdot15kg\cdot5^2m^2/s^2=735J-187.5J=547.5J\)Hence, 547.5 Joules of energy were lost due to friction.
Solid Gas Liquid Fastest Speed drag and drop answer here Medium Speed drag and drop answer here Slowest Speed drag and drop answer here
Answer:
Gas has the fastest moving particles. Liquid has the second fastest. Solid's particles cannot move.
Explanation:
Gas's molecules are spread apart and have space to move. Liquids have loosely held molecules. Solid's molecules don't move because they are tighly packed.
A mass suspended from a spring bobs up and down one complete cycle every 2 s. its period is?
The period is 2 seconds.
A period is a time taken to make one simple harmonic motion. It can be described as time divided by how many waves do. We can write the period formula as
T = t / n
where T is period, t is time and n is the amount of simple harmonic motions.
From the question above, we know that the mass travel up and down, it means that the cycle is one simple harmonic motion.
n = 1
t = 2s
Hence
T = t / n
T = 2 / 1
T = 2 second
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The graph above shows the motion of two runners in a race. Which runner was moving faster? How do you know?
A
Kathy is moving faster because the slope of her line is steeper.
B
Rachel is moving faster because the slope of her line is steeper.
C
Kathy is moving faster because the slope of her line is less steep.
D
Rachel is moving faster because the slope of her line is less steep.
Based on the data, we can infer that Rachel is moving faster because the slope of her line is steeper (option B).
How to identify the runner who was going faster?To identify the runner who was going faster we must take into account the information in the graph. In this case, Rachel's line shows that she has covered more distance in less time than Kathy.
Therefore, Rachel's line is steeper than Kathy's. In this case, Kathy has taken about 70 minutes to cover 7 kilometers. While Rachel has taken 50 minutes to travel about 90 km.
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Select all correct description about dielectrophoresis a does not require the particles to be charged b the particle size is irrelevant when determining the strength of the force c the force direction and magnitude can change as a function of frequency
d applications include cell sorting, enrichment, and separation.
Dielectrophoresis is a physical phenomenon that occurs when the particles suspended in a medium experience a non-uniform electric field. Dielectrophoresis (DEP) is a phenomenon in which particles suspended in a medium migrate towards regions of higher or lower electric field strength depending on their polarizability.
The following are some of the correct descriptions of dielectrophoresis: Dielectrophoresis (DEP) is a physical phenomenon that occurs when particles suspended in a medium experience a non-uniform electric field. DEP does not require the particles to be charged. The particle size is relevant when determining the strength of the force. The force direction and magnitude can change as a function of frequency. Applications of DEP include cell sorting, enrichment, and separation. Thus, the correct options are A, B, C and D.
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What do all electromagnetic waves have in common?
They can travel at the speed of light.
They have the same wavelengths.
They travel only through matter.
They have nonmoving magnetic fields.
Answer:
A. they travel at the speed of light
Explanation:
All electromagnetic waves can travel at the speed of light. The speed of light is 3×10⁸ m/sec.
What is an electromegnetic wave?Electromagnetic waves are waves that are formed when an electric field and a magnetic field vibrate together. It is made up of oscillating magnetic and electric fields.
Electromagnetic waves may alternatively be defined as the combination of oscillating electric and magnetic fields.
Electrically charged particles experiencing acceleration create electromagnetic waves, which can then interact with other charged particles and exert force on them.
All electromagnetic waves can travel at the speed of light. The speed of light is 3×10⁸ m/sec.
Hence option A is correct.
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A student conducts three experiments to determine how certain quantities influence the centripetal force responsible for an object to spin in a horizontal circle. The student uses one end of a string to attach the object while the other end is connected to a force sensor that allows the student to change the tension on the string, as shown in the figure. The student records data from the three experiments in the table above. Which of the following experiments, if any, collected data that do not agree with the expression for the net centripetal force on the object?
A)The experiment in which mass was changed
B)The experiment in which the radius of the circular path was changed
C)The experiment in which the speed of the object was changed
D)All the data are expected.
Option C) The experiment in which the speed of the object was changed
is only statement that doesn't satisfy the given data as shown below:
The above statement can be verified using the calculation:
Formula for centripetal force(F) = \(\frac{mv^2}{r}\)
where m is mass of object , v is speed of object and r is radius of the circular motion.
For option A) when only mass of object is changed and rest all are same.
so F = k*m where k = \(\frac{v^2}{r}\) as both are constant
=> \(\frac{F_1}{F_2}\) = 4.04/8.08 = 0.5
and \(\frac{m_1}{m_2}\) = 0.1/0.2 =0.5
so \(\frac{F_1}{F_2} = \frac{m_1}{m_2}\)
similary \(\frac{F_2}{F_3} = \frac{m_2}{m_3}\) and hence data is correct for option A)
For option B) when only radius of object is changed and rest all are
same.
so F = k/r where k = \(m*v^2\) as both are constant
=> \(\frac{F_1}{F_2}\) = 4.04/8.08 = 0.5
and \(\frac{r_2}{r_1}\) = 0.3/0.6 =0.5
so \(\frac{F_1}{F_2} = \frac{r_2}{r_1}\)
so both are same , similary \(\frac{F_2}{F_3} = \frac{r_3}{r_2}\) and hence data is correct for option B
For option C) when only speed of object is changed and rest all are
same.
so F = k*\(v^2\) where k = \(\frac{m}{r}\) as both are constant
=> \(\frac{F_1}{F_2}\) = 4.04/9.09 = 0.44444
and \(\frac{v_1^2}{v_2^2}\) = 4.08/9.181 =0.44439
so ,\(\frac{F_1}{F_2}\) ≠ \(\frac{v_1^2}{v_2^2}\)
and hence data is not correct for option C
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Complete question:
A student conducts three experiments to determine how certain quantities influence the centripetal force responsible for an object to spin in a horizontal circle. The student uses one end of a string to attach the object while the other end is connected to a force sensor that allows the student to change the tension on the string, as shown in the figure. The student records data from the three experiments in the table above. Which of the following experiments, if any, collected data that do not agree with the expression for the net centripetal force on the object?
A)The experiment in which mass was changed
B)The experiment in which the radius of the circular path was changed
C)The experiment in which the speed of the object was changed
D)All the data are expected.
Which of the following is NOT used to classify soils? Depth, Texture, Color,
Structure
Answer: Depth does not classify soils. Soil color and other properties including texture, structure, and consistence are used to distinguish and identify soil layers.
Happy to help! (0.<)
Explanation:
The depth parameter is does not used to classify the soil in different region. Texture, color and structure are used to characterize the soil type.
What is soil classification?The method of classifying soil involves dividing it into groups where the behaviors of the soils within each group are the same under a certain set of physical conditions.
Engineers can use soil classification to comprehend and evaluate a particular soil's performance and determine whether the soil is suitable for particular engineering applications.
The classification of soli include based on grain size textural classification, AASHTO classification system, Unified soil classification system. AASHTO classification system is developed by Bureau of Public Roads for the classification of soil for the highway subgrade use.
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Electric current is a flow of electric __________. What one word completes the sentence?
Answer:charge
Explanation:
So the electric current is a flow of electric charge
Explain why when water is at the boiling process in a pot it represents convection instead of conduction?
Answer:
When boiling water, the temperature of molecules within the water increases
Explanation: and they slowly begin to move at a rapid rate, upwards. ... The hot water molecules become less dense, and they rise above the denser cooler molecules. This movement of molecules creates convection currents.
How are stars important to the Milky Way?
How has the knowledge and perception of the universe changed over the past century?
What effect does dark energy have on the universe?
What is another metaphor (aside from the fact that a piano can only produce certain notes) that could help someone understand energy quantization at the atomic level? Explain your answer.
What do scientists believe may be the fate of the universe? Which theory do you feel is the better explanation of what may happen? Why?
Stars are important because it gives direction to the people.
We know that our universe is constantly changing.
The effect of dark energy have on the universe is that it accelerate the expansion of the universe.
The stars and galaxies will eventually exhaust their energy and the end will be in the 'Big Chill'.
How are stars important?The stars are so important because they have helped humans navigate. When it was dark these stars would light up the sky giving light to people. Stars are very important for human survival because they make possible life on Earth.
The perception of the universe has changed over the past century because 100 years ago the universe was viewed as unchanging but now we understand that our universe is changing constantly.
The dark energy does not have any gravitational effects, but it has a global effect on the universe which leads to a repulsive force that tends to speedup the expansion of the universe.
As the Universe continues to expand, all the stars and galaxies will eventually loses their energy and the Universe will eventually cool down results in the 'Big Chill'.
So we can conclude that stars beautifies the universe with its lightening effect.
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Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.
The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.
The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].
Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.
Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).
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John added 150 grams of salt to 2.5 liters of water. what is the concentration of the salt solutions
a
plastic tube which has been rubbed with animal fur and gained 3.8x10 electrons.
A vector is 253 m long andpoints in a 55.8 degreedirection.Find the y-component of thevector.
The components of the vector v are given as:
\(\begin{gathered} v_x=v\cos \theta \\ v_y=v\sin \theta \end{gathered}\)where v is the magnitude of the vector and theta is the angle.
In this case we have v=253 and theta=55.8°, plugging this values into the y component we have:
\(\begin{gathered} v_y=253\sin 55.8 \\ v_y=209.25 \end{gathered}\)Therefore the y component is 209.25 meters.