Two polythene balls have the same charge. Each ball has an excess of N = 105 protons. The balls are initially separated by a distance, d = 1. 6 m. The Coulomb constant is k = 8. 988 × 109 N m2/C2.

Answer:

Chemical changes, such as rotting fruit and burning wood, are affected by temperature. More heat and energy causes a faster chemical change.

Explanation:

The best statement that Jacinta can add to her passage is:

Chemical changes, such as rotting fruit and burning wood, are affected by temperature. More heat and energy cause a faster chemical change.

This statement is correct because temperature is a factor that influences the rate of chemical reactions. Higher temperature means more kinetic energy for the molecules, which increases the chances of collisions and bond breaking. This leads to faster chemical changes and new substances being formed. The other statements are either incorrect or irrelevant to the topic of chemical changes.

By knowing how intensity relates to distance, we will see that at 4 meters of the engine the intensity is 80.

The sound spreads in a solid angle like all waves, so the intensity of the sound will decrease with the distance squared, this means that:

\(I = \frac{P}{4*pi*r^2}\)

Where P is the sound power, we know that when the student is at 8m from the engine, the intensity measured is 20 (it does not tell the units) so we have:

\(20 = \frac{P}{4*3.14*(8m)^2} \\\\P = 20*4*3.14*(8m)^2 = 16,078.8 m^2\)

Now, if you move 4 meters closer to the engine, your new position will be:

r = 4m

Then we have:

\(I = \frac{16,078.8 m^2}{4*3.14*(4m)^2} = 80\)

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Answer:

80 is the answer! 100% CORRECT!

Explanation:

~Hope this helps! :)

The experimental evidence led to the development of have gathered new evidence. One of the atomic models this atomic model from the one before it is the colors of light emitted from heated atoms had very specific energies.

As scientific knowledge about the structure of the atom has changed, so have models of the atom.

The Rutherford planetary model, which depicts electrons travelling around the nucleus like planets move around the sun in the solar system, is the direct precursor of the model illustrated in the figure attached.

This model was created as a result of the study of light hues released by heated atoms with highly particular energies.

The Bohr model of the atom is so named because Niels Bohr had a major role in developing it. The passage of electrons between energy levels caused the light hues released by heated atoms. Electrons are grouped in shells or energy levels.

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The parts found in an electric generator for the conversion of electric energy into other forms of energy such as mechanical or chemical energy are an armature, a permanent magnet, an electromagnet brushes, and slip rings.

An electric generator is a device that converts motive power into electric power for use in an external circuit.

Parts of electric generators include the following;

These parts of electric generator helps in the generation of electricity or conversion of electric energy into mechanical energy or light energy or chemical energy.

Thus, the parts found in an electric generator for the conversion of electric energy into other forms of energy such as mechanical or chemical energy are an armature, a permanent magnet, an electromagnet brushes, and slip rings.

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Answer:

armature

permanent magnet

electromagnet

brushes

slip rings

Explanation:

edge 2022-2023

The form of precipitation which may occur from this type of clouds is cumulus clouds.

Precipitation cloud is the cloud from which rain falls or looks likely to fall.

Below are some types of precipitation:

Precipitation refers to any or all of the forms of water particles, whether liquid or solid, that fall from the atmosphere such as; rain, hail, snow or sleet).

It is a major class of hydrometeor, but it is distinguished from cloud, fog, dew, rime, frost, etc., in that it must fall. It is distinguished from cloud and virga in that it must reach the ground.

Cloud refers to visible mass of water droplets suspended in the air.

In conclusion, the form of precipitation which may occur from this type of clouds is cumulus clouds

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The time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road is 7.73 seconds.

Mass of the engine = 1500 kg

Power rating = 75 kW = 75,000 W

Final speed = 100 km/hr =  = 27.78 m/s

v₁ = 0

Power = Work done ÷ Time

Work done = Final energy - Initial energy

=1/2 x 1560 x 27.78^2 = 1/2 x 1560 x 0^2\

= 578703.72 J

Thus,

75,000 = 578703.70 ÷ time=7.72 seconds.

Work is done every time a force moves something over a distance. By multiplying the force by the distance traveled in the direction of the force, you can calculate the energy transferred or the work done. Energy transmitted = work completed = force x distance traveled in the direction of the force.

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As the car accelerates from 10.0 m/s to 20.0 m/s, its kinetic energy increases, indicating that it has more energy due to its motion. Therefore, the initial kinetic energy of the car is 25,000 J and the final kinetic energy is 100,000 J .

The initial and final kinetic energies of the car can be determined using the formula KE = 0.5 x m x \(v^2\), where KE is the kinetic energy, m is the mass of the car, and v is the velocity.

For the initial kinetic energy, we can plug in the given values of m = 500 kg and v = 10.0 m/s into the formula:

KE(initial) = 0.5 x 500 kg x\((10.0 m/s)^2\)
KE(initial) = 25,000 J

This means that the car had a kinetic energy of 25,000 J before it started accelerating.

For the final kinetic energy, we can use the same formula but with the final velocity of 20.0 m/s:

KE(final) = 0.5 x 500 kg x \((20.0 m/s)^2\)
KE(final) = 100,000 J

This means that the car had a kinetic energy of 100,000 J after it finished accelerating.

The difference between the initial and final kinetic energies is 75,000 J. This difference represents the work done on the car by the engine to accelerate it from 10.0 m/s to 20.0 m/s.

It's important to note that kinetic energy is a scalar quantity, meaning it has magnitude but no direction. It's also a form of energy that an object possesses due to its motion. Therefore, as the car accelerates from 10.0 m/s to 20.0 m/s, its kinetic energy increases, indicating that it has more energy due to its motion.

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The train moves with common Velocity, then the velocity of 5 Car train is 2m/s

There are in total 5 identical train cars which collide with each other after some interval of time

Let the Train Cars be: A,B,C,D and E

So, Velocity of A,B and C = 2 m/s

Velocity of D = 4 m/s

Velocity of E = 0 m/s

Let's Assume that the mass of all the carts is 'x', as all are identical Coaches

The common Velocity of the 5 Car train (A+B+C+D+E) if they collide with each. other we have to find

We will use the law of conservation of momentum, which states that the initial momenta of objects = Final momenta of objects

m1u1 + m2u2 = m1V1 + m2v2

Given, Mass of Train Cars = x (Assumed)

Velocity of A,B,C = 2m/s

So, they are travelling on the track, so if they collide with D, their Initial momenta will be the same as final momenta.

As Given, their final velocity are equal. So,

a(ip) + b(ip) + C(ip) + d(ip) = a(vp) + b(vp) + C(vj)

Where, IP = Initial momentum

VP = final momentum

(2*x) + (2*x) + (2*x) + (4*x)

2x + 2x + 2x + 4x = v (x+x+x+x)

10x = 4xv

v = 10x/4x =

v = 2.5mps

Hence, The final velocity of (A,B,C,D) or Four Car train = 2.5 m/s

Now, After sometime travelling with same velocity, they collide with a stationary train car of same mass and it also start moving with same velocity.

aip + bip + Cip + dip + eip = avp + bvp

(10x) + (0*x) = (v*x) + (v*x) + (v*x) + (v*x)

(10x) + 0 = v(x+x+x+x+x)

10x = 5xv

v = 10x/5x

v = 2 mps

Hence, The speed of 5 Car train (A+B+C+D+E) = 2m/s

If the train moves with common Velocity, then the velocity of 5 Car train is 2m/s

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The era of nuclei, also known as the primordial nucleosynthesis or Big Bang nucleosynthesis, refers to the period in the early universe when the conditions were suitable for the formation of atomic nuclei. During the era of nuclei, the universe consisted mainly of hydrogen and helium nuclei.

This era occurred shortly after the Big Bang, when the universe was extremely hot and dense.

During this time, the temperatures were high enough for nuclear fusion to occur. The most abundant nuclei that formed were hydrogen (H) and helium (He). These two elements dominated the composition of the universe during the era of nuclei. Other elements, such as lithium and beryllium, were also formed in smaller quantities, but they were much less abundant compared to hydrogen and helium.

The era of nuclei lasted for a relatively short period, and it was followed by the era of atoms when the universe expanded and cooled further, allowing for the formation of neutral atoms. The nuclei formed during the era of nuclei provided the foundation for the subsequent evolution of the universe, leading to the formation of stars, galaxies, and the diverse range of elements observed today.

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The resistors are connected in parallel between the terminals of a battery.

Note: If those resistors are connected in parallel, then their equivalent resistance is already 5 ohms, even if they're still in the drawer or in a box on the shelf. They don't have to be connected to a source of voltage for that to happen.

The maximum height of the ball is approximately 6.096 m and the work done by gravity is -4.95 J.

Given information,

m = 0.071 kg

V₀ = 11 m/s

(a) Finding the maximum height:

The initial kinetic energy of the ball is converted into potential energy at its maximum height.

Initial kinetic energy = Potential energy at maximum height

(1/2)mv₀² = mgh

(1/2)(0.071 kg)(11 m/s)² = (0.071 kg)(9.8 m/s)h

h = (0.5)(11²)/(9.8) ≈ 6.096 m

Part (b) Calculating the work done by gravity:

The work done by gravity during the ball's flight to its maximum height is equal to the change in potential energy. Since the gravitational potential energy is defined as zero at the initial height, the work done by gravity is equal to the negative of the potential energy at the maximum height.

Wg = -mgh

Wg = -0.071 × 9.8 × 6.096

Wg ≈ -4.95 J

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Answer:

D

Explanation:

F=ma

F of 5 kg rock = 49N

F of 10 kg rock = 98 N

Divide by respective masses to get acceleration, and of course you will get 9.8 m/s^2 for both.

Now, use potential energy equals kinetic energy. mgh=(1/2)mv^2 mass cancels out of the equation, since it's on both sides, so we can stop right there. We have algebraically determined that mass does not affect acceleration or velocity!

Hope this helped.

Answer:

Selected answers A) and D)

Explanation:

Acceleration

According to the Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass:

\(\displaystyle a=\frac{F}{m}\)

We are given four situations, let's compute the acceleration on each case.

A) The block A has a mass of m=5 kg and a net force of F=20 N. The acceleration is:

\(\displaystyle a=\frac{20}{5}=4\ m/s^2\)

This option must be selected because the acceleration is the same as the option D. Correct option A

B) The block B has a mass of m=10 kg and a net force of F=25 N. The acceleration is:

\(\displaystyle a=\frac{25}{10}=2.5\ m/s^2\)

No other option has this value of acceleration, so this option is not correct.

C) The block C has a mass of m=20 kg and a net force of F=100 N. The acceleration is:

\(\displaystyle a=\frac{100}{20}=5\ m/s^2\)

No other option has this value of acceleration, so this option is not correct.

D) The block D has a mass of m=20 kg and a net force of F=80 N. The acceleration is:

\(\displaystyle a=\frac{80}{20}=4\ m/s^2\)

This option must be selected because the acceleration is the same as the option A. Correct option D

Block A (m = 5kg; F = 20 N) and Block D (m = 20 kg; F = 80 N) have the same acceleration.

Acceleration (a) is the change in velocity over time.

It is directly proportional to the force applied (F) and inversely proportional to the mass of the object (m).

We can calculate the acceleration of each block using Newton's second law of motion.

\(a = \frac{F}{m}\)

\(a = \frac{F}{m} = \frac{20N}{5kg} = 4m/s^{2}\)

\(a = \frac{F}{m} = \frac{25N}{10kg} = 2.5m/s^{2}\)

\(a = \frac{F}{m} = \frac{100N}{20kg} = 5m/s^{2}\)

\(a = \frac{F}{m} = \frac{80N}{20kg} = 4m/s^{2}\)

Block A (m = 5kg; F = 20 N) and Block D (m = 20 kg; F = 80 N) have the same acceleration.

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So velocity means speed (how fast something is moving) with a direction for math and science.

Example: Its the same thing as using the word like: Wow that car has a really high Velocity.

Hope this helps :D

Answer:

d) harvesting and threshing both.

Explanation:

Hope it helps you...

The applied force, F, and the friction force, f, act on the cabinet in the direction of motion (x-axis). Therefore,

F + (-f) = mg

Now, by using the formula for static friction :

f = mg

f = (0.80)(30)(9.8)

f = 235.2 kg m/s² or,

Therefore, the magnitude of the friction force is 235.2 N.

Static friction is a force that holds an object at leisure. It is the friction encountered when individuals try to move a fixed object on a surface without initiating any relative motion between the body and the surface on which it is.

A force acting on an object is static force if it does not change that particular object's size, position, or direction. The force involved in a structure acts as a load to that precise structure. This is why static force is also known as a static load.

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========================================

Work Shown:

To find the momentum, we multiply the mass and the velocity.

m = mass = 1500 kg

v = velocity = 3 m/s

p = momentum

p = m*v

p = (1500 kg)*(3 m/s)

p = (1500*3) kg m/s

p = 4500 kg m/s

The momentum of an object is the product of its mass and velocity. Thus momentum of the car with 1500 kg and velocity of 3 m/s is 4500  kg m/s.

Momentum is a physical quantity that measure the ability to keep the force which make an object moves faster. Momentum like force is a vector quantity and is characterized with magnitude and direction.

Momentum is the product of velocity and its mass. Hence as the mass or velocity increases, momentum also increases. Increase in momentum makes the object moves faster.

Given mass of car = 1500 Kg

velocity = 3 m/s

momentum = velocity × mass

= 1500 Kg × 3 m/s

= 4500 Kg m/s.

Therefore, the momentum of the car is 4500 kg m/s.

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Part (a) When r is less than a, the current inside the imaginary cylinder I can be expressed as I = J * pi * r^2, where r is the radius of the cylinder and J is the current density.

Part (b) Using Ampere's law, the magnitude of the magnetic field B at r can be expressed as B = (μ₀ * I) / (2 * pi * r), where μ₀ is the permeability of free space.

Part (c) Substituting the expression for I from part (a), we get B = (μ₀ * J * pi * r^2) / (2 * pi * r), which simplifies to B = (μ₀ * J * r) / 2.

Part (d) To calculate the numerical value of B in Tesla, we need the values for μ₀, J, and a. Please provide these values to calculate B for r = 0.5a.

Part (e)  When r is greater than a, the current inside the imaginary cylinder can be expressed as I = J * pi * a^2, since the entire cross-sectional area of the conductor is now enclosed by the cylinder.

Part (f) Using the expression for B from part (b), we have B = (μ₀ * I) / (2 * pi * r), with I from part (e) as J * pi * a^2.

Part (g) Substituting the expression for I from part (e), we get B = (μ₀ * J * pi * a^2) / (2 * pi * r), which simplifies to B = (μ₀ * J * a^2) / (2 * r).

Part (h) To calculate the numerical value of B in Tesla for r = 2a, we again need the values for μ₀ and J. Please provide these values to calculate B.

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Answer:

there is no picture :o?

Explanation:

:oo

A laser beam passes from air into a 25% glucose solution at an incident angle of 37°.

We can use Snell's Law to solve both parts of this question.

Part 1

Snell's Law states that

n1 sinθ1 = n2 sinθ2

Where n1 and n2 are the indices of refraction of the two media, θ1 is the incident angle, and θ2 is the refracted angle.

In this case, n1 = 1 (for air) and n2 = 1.33 (for the 25% glucose solution). We are given θ1 = 37°. Solving for θ2, we get

sinθ2 = (n1/n2) sinθ1

sinθ2 = (1/1.33) sin(37°)

sinθ2 = 0.516

θ2 = 31.7°

Therefore, the direction of the light in the glucose solution is at an angle of 31.7° relative to the normal.

Part 2

In this case, we are going from ethyl alcohol to air, so n1 = 1.36 and n2 = 1. We are given θ1 = 12°. Solving for θ2, we get

sinθ2 = (n1/n2) sinθ1

sinθ2 = (1.36/1) sin(12°)

sinθ2 = 0.188

θ2 = 11.0°

Therefore, the angle of the refracted beam in air is 11.0°.

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The One strategy implemented to address the drug epidemic in Philadelphia is the creation of Comprehensive User Engagement Sites (CUES). These sites aim to tackle the widespread issue of drug addiction and related energy health concerns.

The CUES are safe spaces where individuals battling addiction can energy access various harm reduction services, such as clean syringes, medical support, and overdose prevention. These sites provide connections to addiction treatment programs and mental health services, helping people on their path to recovery. By offering safe and supervised spaces, CUES work to reduce public drug use, discarded syringes, and other related issues in the community. CUES also serve as educational hubs, raising awareness and providing information about the dangers of drug addiction and available resources for support. Lastly, these sites foster community engagement and collaboration, uniting various stakeholders in the fight against the drug epidemic. In summary, Comprehensive User Engagement Sites play a significant role in addressing the drug epidemic in Philadelphia. They provide harm reduction services, treatment programs, and community support, all while promoting a safer and healthier environment for the city's residents.

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Answer:

Explanation:

Let the angle required be θ with direction opposite to current .

cos θ = 3 / 5

θ = 53° .

Resultant velocity towards the opposite side

= √ ( 5 ² - 3²)

= 4 km /h

distance covered = 1.2 km

time taken = 1.2 / 4 = .3 h

= 18 min .

Answer:

a) 50 rad/s

b) 39.8 rev

Explanation:

Given:

r = 0.36 m

v₀ = 0 m/s

a = 1.8 m/s

t = 10 s

a) Find: ω

v = at + v₀

v = (1.8 m/s) (10 s) + (0 m/s)

v = 18 m/s

ω = (18 m/s) / (0.36 m)

ω = 50 rad/s

b) Find: Δθ

Δx = v₀ t + ½ at²

Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²

Δx = 90 m

Δθ = (90 m) / (2π × 0.36 m)

Δθ = 39.8 rev

Answer:

c 0.10

Explanation:

V=IR

12.0V=I x 120.12ohms

I=0.099

I= 0.10

The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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b. We can Connect 3 cells in series to 3 lamps in parallel and place an ammeter on the circuit to measure the current through one of the lamps.

The image is attached.

c. In this  connection, we creates a series connection where the current flowing through each component is the same.

the two cells' positive and negative terminals must be connected in order to complete the circuit. As a result, a parallel connection is formed where the overall current capacity rises while the voltage across each cell stays the same.

The positive terminal of the first light would be connected to the negative terminal of the second lamp in order to link the two lamps and a motor in series. The second lamp's positive terminal would then be connected to one of the motor's terminals. Finally, you would attach the other motor terminal to the first lamp's negative terminal.

This establishes a series connection in which each component receives the same amount of current.

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Answer:

Joules, Kilogram Meters²/Seconds², and Kilojoules

Explanation:

Answer:  i think the best answer would be B.

Answer:

D. the magnetic field would collapse

Explanation:

The earth magnetic field is protecting the atmosphere from the solar wind any sudden changes will cause navigational disaster.

Without a specific circuit provided, it is difficult to estimate how the phase difference would change when the value of ω changes from zero to infinity.

The phase difference is dependent on the specific circuit components and their respective impedances.

In general, the phase difference between voltage and current in a circuit with inductive or capacitive elements can change significantly as the frequency (or angular frequency ω) changes.

For example, in a simple series circuit consisting of a resistor and an inductor, the phase difference between the voltage and current is zero at DC (ω=0) and approaches 90 degrees as ω approaches infinity.

In contrast, for a series circuit with a resistor and capacitor, the phase difference starts at 90 degrees at DC and approaches zero as ω approaches infinity.

Therefore, it is important to analyze the specific circuit and its components to determine how the phase difference would change as ω changes from zero to infinity.

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