Using Hubble’s law, you can calculate the distance to a galaxy if you can

Answers

Answer 1


To calculate the distance to a galaxy using Hubble's Law, you need to know the galaxy's recessional velocity (the speed at which it is moving away from us) and Hubble's constant (H0), which relates distance and recessional velocity.

Hubble's Law formula is:
Recessional Velocity (v) = Hubble's Constant (H0) × Distance (d)

To find the distance (d), you can rearrange the formula:
Distance (d) = Recessional Velocity (v) / Hubble's Constant (H0)

Now, follow these steps to calculate the distance:
1. Obtain the galaxy's recessional velocity (v), usually measured in kilometers per second (km/s).
2. Use the current value of Hubble's constant (H0), which is approximately 70 km/s/Mpc (kilometers per second per megaparsec).
3. Divide the recessional velocity (v) by Hubble's constant (H0) to find the distance (d) in megaparsecs.

Remember to convert the distance from megaparsecs to the desired unit, such as light-years or parsecs, if necessary.

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Related Questions

1.Write the Schrodinger equation and general solution. What is the meaning of them? 2.Solve the Schrodinger equation when electron travels in potentials of below two cases. 3. Discuss the tunneling.

Answers

1. The Schrödinger equation is a fundamental equation in quantum mechanics that describes the behavior of particles. The general solution represents the wave function of a particle and provides information about its position and momentum.

3.Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically.

1. The Schrödinger equation is a partial differential equation that was developed by Erwin Schrödinger in 1925 as a mathematical formulation of quantum mechanics. It describes how the wave function of a particle evolves over time. The equation takes the form:

Ĥψ = Eψ

Where Ĥ is the Hamiltonian operator, ψ is the wave function, E is the energy of the particle, and Ĥψ represents the operation of the Hamiltonian on the wave function.

The general solution to the Schrödinger equation represents the wave function of a particle. The wave function provides information about the probability distribution of the particle's position and momentum. It contains both real and imaginary components and is typically represented as a complex-valued function.

The wave function, ψ, can be written as a product of a spatial part and a temporal part:

ψ(x, t) = Ψ(x) * Φ(t)

The spatial part, Ψ(x), represents the probability amplitude of finding the particle at position x, while the temporal part, Φ(t), describes how the wave function evolves over time.

The Schrödinger equation and its general solution are essential tools in quantum mechanics, as they allow us to predict the behavior of particles on a microscopic scale. By solving the equation, we can determine the wave function of a particle and calculate probabilities associated with its position and momentum.

2.Case 1: Particle in a Box

In the case of a particle confined to a one-dimensional box, the potential energy is zero within the box and infinite outside of it. This situation can be represented by the following potential function:

V(x) = 0,  0 < x < L

V(x) = ∞,  x ≤ 0 or x ≥ L

To solve the Schrödinger equation for this case, we need to find the wave function (Ψ) and the corresponding energy levels (E). The general form of the wave function inside the box is given by:

Ψ(x) = A * sin(kx)

Where A is a normalization constant, and k = (2π/L).

Applying the boundary conditions, we find that the wave function must go to zero at both ends of the box (x = 0 and x = L). This leads to the quantization of the wave vector k:

k = nπ/L,  where n = 1, 2, 3, ...

The corresponding energy levels are given by:

E = (ħ²π²/2mL²) * n²

Where ħ is the reduced Planck's constant and m is the mass of the particle.

Case 2: Harmonic Oscillator

In the case of a particle in a harmonic oscillator potential, the potential energy can be described by:

V(x) = (1/2)kx²

Where k is the spring constant. To solve the Schrödinger equation for this potential, we use the harmonic oscillator equation:

- (ħ²/2m) * (d²Ψ/dx²) + (1/2)kx²Ψ = EΨ

The solutions to this equation are given by Hermite polynomials, and the corresponding energy levels are quantized. The wave function for the harmonic oscillator potential can be expressed as a product of a Gaussian function and a Hermite polynomial:

Ψ(x) = (A/π)\(^{(1/4)\) * exp(-αx²/2) * Hₙ(√αx)

Where A is a normalization constant, α = (√(mk/ħ)), and Hₙ is the Hermite polynomial of degree n.

The energy levels in the harmonic oscillator potential are given by:

E = (n + 1/2)ħω

Where n = 0, 1, 2, ... and ω = (√(k/m)) is the angular frequency of the oscillator.

These solutions provide insights into the behavior of electrons traveling in these potential systems, including the quantization of energy levels and the spatial distribution of the wave functions.

3. Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically. This effect arises from the wave nature of particles, as described by the Schrödinger equation.

Tunneling has important implications in various areas of physics, such as nuclear fusion, quantum computing, and scanning tunneling microscopy. It allows for phenomena such as alpha decay, where alpha particles escape from atomic nuclei, and the operation of tunneling diodes in electronic devices.

Overall, tunneling is a fascinating quantum mechanical phenomenon that challenges our classical intuition and plays a crucial role in understanding the behavior of particles in the presence of potential barriers.

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the first bright fringe of an interference pattern occurs at an angle of 13.5° from the central fringe when a double slit is illuminated by a 422-nm blue laser. what is the spacing of the slits? m

Answers

The spacing of the slits is approximately 2851.9 nm.

The spacing of the slits can be found using the equation for the fringe spacing in a double-slit interference pattern. The equation is given by:

d * sinθ = m * λ

Where:
- d is the spacing of the slits
- θ is the angle from the central fringe (13.5° in this case)
- m is the order of the fringe (first bright fringe in this case)
- λ is the wavelength of the light (422 nm in this case)

To find the spacing of the slits, we rearrange the equation to solve for d:

d = (m * λ) / sinθ

Plugging in the values, we have:

d = (1 * 422 nm) / sin(13.5°)

Calculating the value, we find:

d ≈ 2851.9 nm

Therefore, the spacing of the slits is approximately 2851.9 nm.

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PLEASE ANSWER THE QUESTION AS SOON AS POSSIBLE

PLEASE ANSWER THE QUESTION AS SOON AS POSSIBLE

Answers

Answer: the answer is (1) B only

Explanation: In A the ball is being acted upon by the ground. In B in order for the ball to move upwards the ball had to have force acted upon at R. In C from U to V the ball has been acted upon by the ground

how do we change km/h to m/s​

Answers

Answer:

36km/h = 10m/s

Explanation:

That's the formula to convert

From km/h to m/s : do divided by 3,6
From m/s to km/h : do multiple by 3,6

Our solar system is 4.6 billion years old. Based on the age of the solar system, how many galatic years has planet Earth been around?

Answers

Therefore, based on the estimated duration of a galactic year, Earth has been around for approximately 18.4 to 20.4 galactic ye

A "galactic year" refers to the time it takes for our solar system to complete one orbit around the Milky Way galaxy. The exact duration of a galactic year is not precisely determined due to various factors, such as the varying speeds of stars within the galaxy. However, it is estimated to be roughly 225-250 million years.

To calculate the number of galactic years Earth has been around based on the age of the solar system (4.6 billion years), we can divide the age of the solar system by the estimated duration of a galactic year:

Number of Galactic Years = Age of the Solar System ÷ Duration of a Galactic Year

Number of Galactic Years = 4.6 billion years ÷ 225-250 million years

Number of Galactic Years ≈ 18.4 to 20.4 galactic years

Therefore, based on the estimated duration of a galactic year, Earth has been around for approximately 18.4 to 20.4 galactic years.

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Nêu 2 ví dụ cho mỗi trường hợp sau: vật chuyển động,đứng yên,chuyển động do với vật này đứng yên so với vật khác,chuyển động thẳng,chuyển động cong,chuyển động tròn.

Answers

Answer:

Hai ví dụ như sau:

a) Vật thể chuyển động - Phương tiện di chuyển, Người đàn ông đi bộ

b) ở trạng thái nghỉ - Xe đứng, người ngồi

c) Chuyển động vì một vật đứng yên so với một vật khác - Một người đàn ông ngồi trên sân ga đứng yên so với đoàn tàu đang chuyển động, Một ô tô chuyển động ngang qua những ngôi nhà đang đứng yên

d) chuyển động thẳng - Đi bộ trên đường, chuyển động lên trên

e) chuyển động cong - Chạy trên đường tròn, đạn bắn ra từ súng

f) chuyển động tròn đều - Xe chuyển động trên đường cong, êlectron chuyển động vuông góc với từ trường đều

Explanation:

Hai ví dụ như sau:

a) Vật thể chuyển động - Phương tiện di chuyển, Người đàn ông đi bộ

b) ở trạng thái nghỉ - Xe đứng, người ngồi

c) Chuyển động vì một vật đứng yên so với một vật khác - Một người đàn ông ngồi trên sân ga đứng yên so với đoàn tàu đang chuyển động, Một ô tô chuyển động ngang qua những ngôi nhà đang đứng yên

d) chuyển động thẳng - Đi bộ trên đường, chuyển động lên trên

e) chuyển động cong - Chạy trên đường tròn, đạn bắn ra từ súng

f) chuyển động tròn đều - Xe chuyển động trên đường cong, êlectron chuyển động vuông góc với từ trường đều

What rate do things fall to Earth?

Answers

Answer:

9.8 meters per square second

Explanation:

Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.

no atomic ___ is a picture of an atom but only helps explain the ___ of one

Answers

No atomic  model is a picture of an atom but only helps explain the behavior of one

What is the atom?

We know that the atom is the smallest particle of a substance that is able to take part in a chemical reaction. We know that in the atom there are certain smaller particles that we can be able to refer to as the subatomic particles.

In this case, we are talking about the different models that we can be able to use to show the atom. None of these models can be said to show the atom exactly but can approximate how the atom behaves.

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The gravitational acceleration on Earth is 9.8 m/s2. What is the weight of a car on Earth (to the nearest whole number) if it has a mass of 1360 kg? 14 N 139 N 1333 N 13,328 N

Answers

Weight = (mass) x (gravitational acceleration where the mass is)

Weight = (1360 kg) x (9.8 m/s²)

Weight = 13,328  kg-m/s²

That's 13,328 Newtons

Given:-

Mass (m) of the car = 1360 kgAcceleration due to gravity (g) = 9.8 m/

To Find: Weight (W).

We know,

W = mg

where,

W = Weight,m = Mass &g = Acceleration due to gravity.

Thus,

W = (1360 kg)(9.8 m/s²)

→ W = 13,328 N (D)

And object additionally addressed experience and acceleration of 9.8 m/s2 how much time will it take to achieve a velocity of 49 m/s

Answers

Answer:

YOU OR YOUR PARENTS VOTE BIDEN!

TRUMP KILLED 223,000 PEOPLE AND HE STILL DOES NOT CARE! HE SAYS WE ARE ROUNDING THE CORNER. HE CAN NOT EVEN HAND OUT STIMULUS TO DYING BUISNESSES AND AIRLINES!

Explanation:

YOU OR YOUR PARENTS VOTE BIDEN!

TRUMP KILLED 223,000 PEOPLE AND HE STILL DOES NOT CARE! HE SAYS WE ARE ROUNDING THE CORNER. HE CAN NOT EVEN HAND OUT STIMULUS TO DYING BUISNESSES AND AIRLINES!

A car drives 10km with a speed of 72 km/hr and then runs out of gas.

Answers

Answer:

Uh I'm guessing this isn't the complete question lol.

Explanation:

But I'll give you the data of the only information you gave me. The vi (Initial Velocity) has decreased so the car has decelerated. (opposite of acceleration).

Distance (S)=10 km. convert this to metre.

Speed= 72km/hr.

Vi=0: because the car ran out of gas, therefore it has stopped moving.

An object that weighs 75 N is pulled on a horizontal surface by a horizontal pull of 50 N to
the right. The friction force on this object is 30 N to the left. What is the acceleration of the
object?

Answers

Using the Newton Laws, the acceleration of the object is 2.67m/s²

Based on the problem, we can draw the diagram as below to help our understanding.

From the information provided we know that:

F = 50 N (horizontal pull)

W = 75 N

f = 30 N (friction force)

From the picture, we could focus first on the X-axis, where the horizontal force and the friction force work on the object. We would apply the second law of Newton for this axis since there is movement happening within this axis.

∑Fx = m.a

F - f = m.a

50 - 30 = m.a

m.a = 20N ... (i)

Next, we will focus on the Y-axis. In this axis neutral force and weight are working but not resulting to any movement within the axis. ence, we will be applying the first law of Newton:

∑F = 0

N - W = 0

N = W

N = 75N ... (ii)

Since we know that weight is the result of multiply between mass and gravity, we could find the mass of the object by assuming the gravity is 10m/s²

W = m.g

75 = m (10)

m = 7.5kg ... (iii)

We could subtitute the equation (iii) into equation (i) to find the acceleration of the object:

m.a = 20N

(7.5) a = 20N

a = 2.67m/s²

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An object that weighs 75 N is pulled on a horizontal surface by a horizontal pull of 50 N tothe right.

what happens to denstity of air as altitude decreases

I WILL GIVE BRAINLIEST

Answers

wasssssupp okay so i believe that i don’t know i’m sorry

A ball rolls in a horizontal direction off of a ledge. If the velocity of the ball was 11 m/s


and the ball traveled 46 m from the base of the ledge, how tall is the ledge? Explain please

Answers

the height of the ledge is 85.5 m.

The height of a ledge from which a ball rolls in a horizontal direction, given that the velocity of the ball was 11 m/s and it traveled 46 m from the base of the ledge can be calculated using the formula;

`H = 1/2g*t^2`where, H = height of the ledge

g = acceleration due to gravity

t = time taken by the ball to reach the ground

From the formula for distance,

`d = vt`

We know that time taken by the ball to reach the ground is given by;

t = d/v= 46/11t = 4.18s

Now substituting the value of t into the formula for height,

H = 1/2 * 9.8 * 4.18^2= 85.5 m

Therefore, the height of the ledge is 85.5 m.

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do electronics harm our mental physical and social health

Answers

Answer:

(I will talk in my opinion only)

electronics do harm our mental health but they are also helpful ones like mobile both a boon and a curse

physical health is greatly affected and it's something no need to explain

social ( for me ) my only place to be social and talk people is brainly so for me mobile is very important

Answer:

Just a little bit. You should not be on electronics all the time. I know some people that are so addicted to there electronics that they won't even hang out with people. If you are at the point where you think about things other than school, friends, and family...you should think about getting off of your electronics and go play with a neighborhood friend outside, or have a sleepover! Your whole life should not count on your phone, iPad, or your laptop.

Explanation:

Hope this helps! No recorces included in this writing.

A light, inextensible cord passes over a light, frictionless pulley with a radius of 4.8 cm. It has a(n) 15 kg mass on the left and a(n) 3.2 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 4.4 m apart. The acceleration of gravity is 9.8 m/s 2 At what rate are the two masses accelerating when they pass each other

Answers

The two masses are accelerating toward each other at a rate of approximately 7.78 m/s² when they pass each other.

When solving this problem, we can consider the system as a whole and apply Newton's second law to determine the acceleration. The tension in the cord is the same on both sides of the pulley. Let's denote the tension as T. For the 15 kg mass, the net force acting on it is T - (15 kg * g), where g is the acceleration due to gravity. For the 3.2 kg mass, the net force acting on it is (3.2 kg * g) - T. Since the masses are connected by a cord passing over the pulley, their accelerations are equal in magnitude but opposite in direction.

We can set up the following equations:

T - (15 kg * g) = (15 kg * a)    (1)

(3.2 kg * g) - T = (3.2 kg * a)    (2)

Simplifying equation (1), we get T = (15 kg * g) + (15 kg * a)

Substituting this value into equation (2), we have (3.2 kg * g) - [(15 kg * g) + (15 kg * a)] = (3.2 kg * a)

Simplifying further, we find:

3.2 kg * g - 15 kg * g - 15 kg * a = 3.2 kg * a

-11.8 kg * g = 18.2 kg * a

Finally, solving for a:

a = (-11.8 kg * g) / (18.2 kg) ≈ -7.78 m/s²

The negative sign indicates that the acceleration is directed toward the left. The magnitudes of the accelerations of both masses are the same, so when they pass each other, they are accelerating toward each other at a rate of approximately 7.78 m/s².

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The two masses are accelerating toward each other at a rate of approximately 7.78 m/s² when they pass each other.

When solving this problem, we can consider the system as a whole and apply Newton's second law to determine the acceleration. The tension in the cord is the same on both sides of the pulley. Let's denote the tension as T. For the 15 kg mass, the net force acting on it is T - (15 kg * g), where g is the acceleration due to gravity. For the 3.2 kg mass, the net force acting on it is (3.2 kg * g) - T. Since the masses are connected by a cord passing over the pulley, their accelerations are equal in magnitude but opposite in direction.

We can set up the following equations:

T - (15 kg * g) = (15 kg * a)    (1)

(3.2 kg * g) - T = (3.2 kg * a)    (2)

Simplifying equation (1), we get T = (15 kg * g) + (15 kg * a)

Substituting this value into equation (2), we have (3.2 kg * g) - [(15 kg * g) + (15 kg * a)] = (3.2 kg * a)

Simplifying further, we find:

3.2 kg * g - 15 kg * g - 15 kg * a = 3.2 kg * a

-11.8 kg * g = 18.2 kg * a

Finally, solving for a:

a = (-11.8 kg * g) / (18.2 kg) ≈ -7.78 m/s²

The negative sign indicates that the acceleration is directed toward the left. The magnitudes of the accelerations of both masses are the same, so when they pass each other, they are accelerating toward each other at a rate of approximately 7.78 m/s².

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Charge Q is distributed uniformly throughout a spherical insulating shell. The net electric flux through the outer surface of the shell is:

Answers

Electric flux is given by the equation:Φ=EAcosθwhere Φ is the electric flux, E is the electric field, A is the surface area, and θ is the angle between the electric field and the surface normal.An insulating spherical shell is a charged hollow sphere whose electric field is zero within it.

Inside the shell, there is no electric field since the field vectors point in opposite directions and cancel out. The electric field outside the shell is the same as the field caused by a point charge situated at the center of the shell. As a result, the charge is distributed uniformly throughout the spherical insulating shell. The electric field outside the shell's surface is E=kQ/r², where k is the Coulomb constant, Q is the charge in the shell, and r is the distance from the center to the point outside the shell.The net electric flux is calculated using Gauss's Law, which relates the electric flux through a closed surface to the charge inside the surface. For a closed surface around a point charge Q, Gauss's Law states that the net electric flux is proportional to the charge inside the surface.

Gauss's Law is

Φ=q/ε₀

where Φ is the net electric flux, q is the charge inside the surface, and ε₀ is the electric constant. In the case of a spherical insulating shell, the net electric flux through the outer surface of the shell is zero.

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atom X contains seven protons and seven neutrons. atom Z contains seven protons and eight neutrons. which of the following statements correctly describes the two atoms?
A.they are isotopes.
B.they are radioactive.
C they have the same mass number.
D they are atoms of different elements.

Answers

Answer:

The correct answer is option A: they are isotopes.

Explanation:

From atom X we know that the number of protons is 7 and the number of neutrons is 7 and from atom Z we know that the number of protons is 7 and the number of neutrons is 8.

Since the number of protons of atom X and atom Z is the same, we have that atom X and atom Z is the same element. The difference in the number of neutrons tells us that atom X and atom Z are isotopes. Remember that an isotope is one element that has atoms with different numbers of neutrons.            

The mass number is given by:              

\( A = p + n \)

Where n is the number of neutrons and p is the number of protons.

For atom X and atom Z we have:

\( A_{x} = 7 + 7 = 14 \)

\( A_{z} = 7 + 8 = 15 \)

Hence, they have a different mass number.  

We know that the element with 7 protons is nitrogen. The first isotope is \(^{14}_{7}N\) and the second isotope is \(^{15}_{7}N\). Both isotopes are stables (they are not radioactive).  

Therefore, the correct answer is option A: they are isotopes.

I hope it helps you!                                                          

Which characteristic is common to the four outer planets in our solar system?.

Answers

They are all gas giants.

Answer: They Are all gas giants.

Explanation:

When does an object moving in a straight line at constant speed have a non-zero angular momentum?
a) never
b) always
c) sometimes

Answers

Answer: Yes, it can be  possible that an object have non zero angular momentum.

Explanation:

There is a concept of frame of reference.

When your frame of reference is not on that straight line where the object is moving then the object will have non zero angular momentum .

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A ladder is at rest with Oct upper end against a wall and its lower end on the ground.A worker is about to climb it.When is it more likly to slip

Answers

Answer: When the worker is on the top rung

Explanation: When the ladder was initially resting on the wall, the torque from the normal reaction on ladder from the horizontal surface is equal to the torque from the vertical surface on ladder.

The weight of the worker produces a torque which is in the direction of the torque from the normal reaction on ladder, produced by the vertical surface. Therefore for the ladder to stay in rotational equilibrium, the torque on ladder from the normal reaction produced by the horizontal surface must increase.

This increase is possible when the worker is on the lower rung, but as the worker goes high, the magnitude of normal reaction from the vertical surface would increase, thereby increasing the risk of slipping of ladder.

if the moon is highest in the sky in the morning at 6:00am, what phase will the moon be after one week?

Answers

If the moon is highest in the sky in the morning at 6:00am, it means that it is in its waning phase. This is because the moon rises later and later each day during its waning phase, eventually reaching its highest point in the morning.

After one week, the moon will have gone through approximately half of its cycle and will be in its third quarter phase. This is when the moon appears as a half-circle in the sky, with the right half illuminated. During this phase, the moon rises around midnight and sets around noon, making it visible during the morning hours. As the moon continues to wane, it will appear smaller and smaller in the sky until it reaches its new moon phase, which marks the beginning of a new lunar cycle. Understanding the phases of the moon is important for astronomers and anyone who wants to track the moon's position and movements in the sky.

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NEED HELP!!! ANSWER THESE 5 QUESTIONS FOR 25 POINTS!!!! PLEASE ANSWER!! I WILL GIVE YOU BRAINEST

1. Ewan had a resting heart rate of about 110. What does this indicate?
A.
His heart rate is perfectly average.
B.
He probably has a high metabolism.
C.
He needs to work on raising his resting heart rate.
D.
His heart rate is high and could indicate a problem.

2. Why is acceptance an important part of building a healthy lifestyle?
A.
Exercise will probably not change much in your life.
B.
Healthy lifestyles often create a lot of disappointment.
C.
If you understand your limitations, you are less likely to be frustrated.
D.
Finding the energy to exercise can be hard, so you should limit your goals.

3. When you learn to lift weights with the proper body mechanics, good form becomes a habit.
A.
True

B.
False

4. There are many people who do not gain weight easily and can live their lives at a healthy weight without really exercising. Do these people still need to exercise?
A.
Yes, but only of their weight starts to increase when they age.
B.
No, if they feel healthy, they probably are healthy enough.
C.
No, weight is the most significant factor in determining health.
D.
Yes, low weight does not mean that their hearts and lungs are healthy.

5. Imagine that someone is injured, and their somatic nervous system is impacted. Would this be a life-threatening injury?
A.
Yes, that covers essential internal injuries.
B.
No, that is a minor part of how the body functions.
C.
Probably not since that system deals mostly with mobility.
D.
It is highly likely because that controls the brain and the spine.

PLEASE NO LINKS

Answers

Answer:

1. His heart rate is high and could indicate a problem.

2. If you understand your limitations, you are less likely to be frustrated.

3. When you learn to lift weights with the proper body mechanics, good form becomes a habit.

A.

True

4. Yes, low weight does not mean that their hearts and lungs are healthy.

5.Probably not since that system deals mostly with mobility.

Which quasar is most likely to have the highest number of hydrogen absorption lines in its spectrum?

Answers

A quasar with a lookback time of 13 billion years is most likely to have the highest number of hydrogen absorption lines in its spectrum

What is a quasar?

Quasar is an abbreviation for quasi-stellar radio source. Quasars were given that name because, when they were initially discovered by astronomers in the late 1950s and early 1960s, they resembled stars. Quasars are not stars, though. They are young galaxies that are far away from us and are becoming more numerous as they approach the outer reaches of the visible cosmos, according to science. How are they still visible despite being so far away? Quasars are up to 1,000 times brighter than our Milky Way galaxy, which is the reason why they are so luminous. As a result, we are aware that they are extremely active and produce astounding amounts of radiation throughout the whole electromagnetic spectrum.

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A tension of 35.0N is applied to the right on a 2.50kg mass. What is the acceleration of the mass?

Answers

The acceleration of the 2.50 kg mass when a tension of 35.0 N is applied to the right is 14.0 m/s²

To find the acceleration of a 2.50 kg mass with a tension of 35.0 N applied to the right, we will use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration (F = ma). In this case, the force (F) is the tension applied to the mass.
1. First, write down the given values:
Tension (F) = 35.0 N
Mass (m) = 2.50 kg
2. According to Newton's second law of motion, F = ma. We need to solve for acceleration (a). Therefore, we will rearrange the formula as follows: a = \frac{F}{m}

3. Plug in the given values into the formula: a = \frac{(35.0 N) }{ (2.50 kg)}
4. Calculate the acceleration:
a = 14.0 m/s²
So, the acceleration of the 2.50 kg mass when a tension of 35.0 N is applied to the right is 14.0 m/s². This means that the mass will increase its velocity by 14.0 meters per second every second in the direction of the applied force.

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complete question:

A tension of 35.0N is applied to the right on a 2.50kg mass. What is the acceleration of the mass?

A. 59.5m/s2 B. 4.20m/s2 C. 23.8m/s2 D. 14.0m/s2

When a tension of 35.0 N is applied to the right, the acceleration of the 2.50 kg mass is 14.0 m/s^2.

Use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration (F = ma), to calculate the acceleration of a 2.50 kg mass when 35.0 N of right-side tension is applied. The tension put on the mass in this situation constitutes the force (F).

1. First, write down the given values:

Tension (F) = 35.0 N

Mass (m) = 2.50 kg

2.F = ma, says Newton's second law of motion We need to solve for acceleration (a).So, we'll change the formula's order as follows.:  \(a = \frac{F}{m}\)

3. Add the specified values to the formula. \(: a = \frac{(35.0 N) }{ (2.50 kg)}\)

4. Calculate the acceleration:

a = 14.0 m/s²

Therefore, when a tension of 35.0 N is applied to the right, the acceleration of the 2.50 kg mass is 14.0 m/s^2. This indicates that the mass will accelerate in the direction of the applied force by 14.0 metres per second per second.

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complete question:

A tension of 35.0N is applied to the right on a 2.50kg mass. What is the acceleration of the mass?

A. 59.5m/s2 B. 4.20m/s2 C. 23.8m/s2 D. 14.0m/s2

what is the approximate length of an astronomical unit

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An astronomical unit (AU) is approximately 149.6 million kilometers (93 million miles), representing the average distance between the Earth and the Sun.

represent distances within the Solar System. It is approximately equal to the average distance between the Earth and the Sun.The current accepted value for the length of an astronomical unit is approximately 149.6 million kilometers (93 million miles) or about 8.3 light minutes. This value provides a useful reference for measuring distances within our Solar System.The AU is frequently used to express distances between planets, asteroids, and other celestial bodies in our solar system.

For example, the average distance from the Sun to Earth is approximately 1 AU, while the average distance from the Sun to Mars is about 1.5 AU.

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i GOT DISCONNECTED WITH A TUTOR THAT WAS EXPLAING, NEED HELPIna shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of −0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

Answers

Given that,

The mass of marble A, m₁=0.08 kg

The mass of marble B, m₂=0.05 kg

The initial velocity of marble A, u₁=0.5 m/s

As the marble B was at rest, the initial velocity of marble B is u₂=0 m/s

The final velocity of marble A, v₁=-0.1 m/s

Let the final velocity of marble B be v₂.

According to the law of conservation of momentum, the total momentum before the collision is equal to the total after the collision.

Therefore

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

On rearranging the above equation,

\(v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2}\)

On substituting the known values in the above equation,

\(\begin{gathered} v_2=\frac{0.08\times0.5+0.05\times0-0.08\times-0.1}{0.05} \\ =\frac{0.048}{0.05} \\ =0.96\text{ m/s} \end{gathered}\)

Therefore the

Answer:

See below

Explanation:

Use conservation of momentum (rather than Kinetic Energy ) for collision problems:

Momentum A  = mv = .08 * .5 = .04  km m/s

Momentum B = mv  = 0

    Total Momentum = .04 + 0 = .04  kg m/s

After collision the sum must be the same

A = mv = .08 ( -.1 ) = - .008 kg m/s

B = m vb   = .05 vb

    .04   =  - .008   +  .05 vb

      vb =  + .96 m/s      in the same direction as original A direction

If an object starts at rest, what is necessary to make it start moving?

Answers

it might be force but i don’t remember

It will need a force acceleration

How do data collected from tree rings provide evidence for climate
change?
Why isn’t this a answer when you search it

Answers

Answer:

Climate scientists compare the tree growth records to local weather records. For locations where a good statistical match exists between tree growth and temperature or precipitation during the period of overlap, the ring widths can be used to estimate past temperature or precipitation over the lifetime of the tree.

A Canadian college student who has taken an astronomy class goes home for the holidays and persuades his parents to let him borrow the family car. When he returns, he finds that his parents are very angry with him, claiming he left the garage door open. Yet he remembers that he carefully closed the garage door with the electronic remote control in the car. After consulting with his astronomy instructor, he comes up with an alternative explanation for why the garage door is open. Which of the following is PART of that explanation?

a. The Sun was so bright and high in the sky in December in Canada that it got into his
parents' eyes
b. There was an eclipse of the Sun
c. It was a time of solar maximum, and there had been a big flare on the Sun earlier
d. No aurorae had been seen in the sky for many months
e. The number of sunspots had reached an all-time minimum
c. It was a time of solar maximum, and there had

Answers

Answer:

Option C, It was a time of solar maximum, and there had been a big flare on the Sun earlier

Explanation:

It was solar maximum due to which the amount of magnetic flux on the sun's surface rises up

This causes high frequency radio blackouts and interrupt with the communication on earth

Some times they also cause ripple effect in the electronic items as in the remote control used by the college student. They can disrupt the electronic communications.

Hence, option C is correct

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