Using the equation pH = -log [H+], determine the pH of a solution with a hydrogen ion concentration, or [H+], of 1x10-5. HINT: look at his HCl example!


pH = 7


pH = 1


pH = 5


pH = 2

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Answer:

Solar energy, geothermal energy. Wind energy. Hydropower, Biomass.

Explanation:

Answer:

B.Cu

Explanation:

n the reaction H2 is oxdized since it has lost electrons and Cu is reduced since it has gained electrons

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Here are some questions on Personal Care services on E2020 are:

An infection is the entrance and growth of dangerous microorganisms in the body that harm the host, such as bacteria, viruses, fungus, or parasites.

Infections can be systemic (affecting the entire body) or localized (affecting a particular area of the body), and they can be moderate to severe.

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Answer: C(2)H(5)OH + 3O(2) —> 3H(2)O + 2CO(2)

Explanation:

*The number in parentheses or

( ) represents the subscript of the element

Carbon-2

Hydrogen-6

Oxygen-7

I hope this is helpful.

Answer:

2H2O + O2 -- 2H2O

FeCl3 + 3NaOH -- Fe(OH)3 + 3NaCl

4P + 5O2 -- 2P2O5

2Na + 2H2O -- 2NaOH +H2

2Ag2O -- 4Ag + O2

K + MgBr -- KBr + Mg

Explanation:

the moles of each element should be the same in both reactant reaction and product reaction

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Answer:

11

Explanation:

Answer:

How do amoeba respire.

How do plants respire.

Answer:

Health education is a profession of educating people about health. Areas within this profession encompass environmental health, physical health, social health, emotional health, intellectual health, and spiritual health, as well as sexual and reproductive health education

The mass of water driven off during popping can be calculated by subtracting the mass of the popped corn and the dish from the mass of the dish and kernel before heating.

Heating is the process of increasing the temperature of a substance or object, typically using an external energy source such as heat, radiation, or electrical current. The heat energy is transferred to the object or substance, causing its particles to vibrate and move faster, which results in an increase in temperature. Heating is commonly used in a wide range of applications, including cooking, chemical reactions, industrial processes, and space heating.

Cooking is the process of preparing food by applying heat, typically using methods such as baking, roasting, grilling, frying, boiling, simmering, steaming, or microwaving. The aim of cooking is to make food more palatable and easier to digest, as well as to kill harmful bacteria and other microorganisms that may be present in raw food. Cooking can also enhance the nutritional value of some foods by making certain nutrients more bioavailable.

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Answer:

Mixture is combination of two or more substances

Explanation:

The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.

The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Answer:

The molar mass of water is 18 grams per mole. So in 18 grams of water, there are 6.02 x 1023 molecules.

One gallon of water is equal to 3.7854118 liters. If we assume that the water is at 4 °C (to keep things simple), the density of water is exactly 1 gram per milliliter, or 1 kilogram per liter. So 1 gallon of water at 4 °C weighs exactly 3.7854118 kilograms, or 3785.41118 grams.

If one mole of water weighs 18 grams, then there are 210.30 moles of water in a gallon. Since one mole of water is made up of 6.02 x 1023 molecules, in one gallon of water there are 1.266 x 1026 molecules.

That is: 126600000000000000000000000 molecules!

If we multiply that by the number of atoms in a single water molecule -- 3 atoms -- then we get:

379800000000000000000000000 atoms!

The number of ionized water molecules at any given time in 2.86 gallons of pure water is approximately 2.08 x 10¹¹ molecules.

In pure water, only a small portion of water molecules are capable of self-ionization, which causes them to separate into hydronium ions (H3O+) and hydroxide ions (OH-). This procedure can be reversed.

The self-ionization of water can be represented as:

H₂O ⇌ H₃O+ + OH⁻

The concentration of each ion can be calculated using the equilibrium constant for water, Kw.

Kw = [H₃O⁺][OH⁻] = 1.0 x 10⁽⁻¹⁴⁾ at 25°C

Since the concentration of H³O⁺ ions is equal to the concentration of OH⁻ ions in pure water, let's assume that each concentration is x.

So, x² = 1.0 x 10⁽⁻¹⁴⁾

Taking the square root of both sides,

x = √(1.0 x 10⁽⁻¹⁴⁾)

  ≈ 1.0 x 10⁽⁻⁷⁾ M

The concentration of H₃O⁺ and OH⁻ ions in pure water is approximately 1.0 x 10^(-7) M.

To find the number of  ionized water molecules,

= concentration x Avogadro's number x volume

= (1.0 x 10⁽⁻⁷⁾ M) x (6.022 x 10²³ molecules/mol) x (2.86 gallons) x (3.78541 liters/gallon)

≈ 2.08 x 10¹¹ molecules.

So, approximately 2.08 x 10¹¹ molecules of water are ionized.

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Answer:

Argon

Explanation:

It has more electron than chlorine

Explanation:

Number of molecules: 4.30×10²⁵

We need to find out the total number of moles.

Now, as per Avogadro's law, 6.02×10²³ of anything (Avogadro's number) constitutes a unit called one mole. Just like 12 is a dozen, 6.02×10²³ is a mole.

If you were given 24 bananas and you had to find out the number of dozens, you would divide the total number of bananas (24) by the number of bananas in one dozen (12).

We do exactly the same here: divide the total number of molecules (4.30×10²⁵) by the number of molecules in one mole (6.02×10²³) to get the number of moles.

4.30×10²⁵ / 6.02×10²³ = number of moles

Solving, we get number of NH3 moles = 71.4 which is your final answer!

Hope this helps :D

Explanation:

Please, if I may ask, what is the exact question?

Answer:

1177.88g of C3H8

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Next we shall determine the number of mole of C3H8 required to produce 80.3 moles of CO2. This is illustrated below:

From the balanced equation above,

1 mole of C3H8 reacted to produce 3 moles of CO2.

Therefore, Xmol of C3H8 will react to produce 80.3 moles of CO2 i.e

Xmol of C3H8 = 80.3/3

Xmol of C3H8 = 26.77 moles

Finally, we shall convert 26.77 moles of C3H8 to grams.

Molar mass of C3H8 = (3x12) + (8x1) = 44g/mol

Mole of C3H8 = 26.77 moles

Mass of C3H8 =..?

Mass = mole x molar mass

Mass of C3H8 = 26.77 x 44

Mass of C3H8 = 1177.88g

Therefore, 1177.88g of C3H8 are needed for the reaction

Answer:

0.00500M of Na₂C₂O₄

Explanation:

When are dissolved in 150 mL of 1.0 M H2SO4.

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

The concentration of the solution is 0.005 M.

From the information available in the question;

We know that;

Mass of  Na2C2O4 = 0.1005 g

Volume of solution = 150 ml

To obtain the number of moles of Na2C2O4;

Number of moles = mass/molar mass

Molar mass of Na2C2O4  = 134 g/mol

Number of moles =  0.1005 g /134 g/mol = 0.00075 moles

Concentration = number of moles/volume

Volume of solution = 150ml or 0.15 L

Concentration =  0.00075 moles/0.15 L

= 0.005 M

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Missing parts

An acidic solution of sodium oxalate (Na2C2O4) was prepared by dissolving ~0.100 g of Na2C2O4 in 150 mL of 1.0 M H2SO4 in a 250 mL Erlenmeyer flask. Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.

When acid-base reacts together then, a neutralization reaction happens. A neutralization reaction is commonly used in antacid tablets.

By stoichiometric calculations, we can calculate the molarity of the unknown if the molarity of added chemical and volume are known. When KOH reacts with H2SO4 it forms Potassium sulfate.

0.650 L of 0.400 M

H2SO4 is 0.650 L×0.400 mol/L

=0.260 moles of H2SO4

.0.600 L of 0.280 M

KOH is 0.600 L×0.280 mol/L

=0.168 moles of

KOH.

We know that the mole ratio of

KOH to H2SO4 is 1:2, so, to fully react with the 0.168 moles of KOH, 0.1682=0.084 moles of H2SO4 are needed. 0.260 moles.

This means that only 0.084 moles out of 0.260 moles of H2SO4 react. 0.260−0.084=0.176  moles of H2SO4

H2SO4 is left sitting there in the solution (0.176), we can use that to calculate its concentration in molarity.

molarity =moles/ volume (L)

The number of moles is 0.176 and the volume is 0.650 L + 0.600 L = 1.25 L

molarity

= 0.176 moles/ 1.25 L

=0.141 M

Therefore, When acid-base reacts together then, a neutralization reaction happens. A neutralization reaction is commonly used in antacid tablets.

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In a spectrophotometer, both absorbance and transmítanse indicate the amount of light passing through a sample. A high absorbance corresponds to a low transmittance.

What is absorbance?

It is a measure of a substance's ability to absorb light of a specific wavelength. It is equivalent to the reciprocal of the logarithm of the transmittance. The amount of light absorbed by a solution, also known as optical density.

What is Transmittance?

It is the proportion of light energy falling on a body to light energy transmitted through it. In other words, it is the proportion of light flowing through to light incident on the sample, whereas the reflectance is the proportion of light reflected to light incident.

In a spectrophotometer, both absorbance and transmittance indicate the amount of light passing through a sample. A high absorbance corresponds to a low transmittance.

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In a case whereby A bath bomb is a solid sphere made of a weak base and a weak acid and you add it to a bathtub, it mixes with the water to create a soapy solution. If you want it to completely and quickly dissolve a large bath bomb, then  C. Increase the water temperature, which increases the solubility of the bath bomb - dissolving it more quickly.

Solubility can be described as the maximum amount of a substance  which candissolve when subjected to given amount of solvent at a specified temperature.

It should be noted that the Solubility i serves as the characteristic property  that can be associated to a specific solute–solvent combination and there is a differing solubilities, hence from the case aboive when the tempertaure is been increased , this will  increases the solubility of the bath bomb .

Therefore, option C is correct.

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Answer:

2.4 M

Explanation:

1. Suppose you have 100 mL solution:

Use density to find grams of solution:

100 mL solution x (1.10 g / 1 mL) = 110 g solution

2. FInd the amount of sodium chloride pure:

110 g solution x(13 g NaCl / 100 g solution) = 14.3 g NaCl

3. Change grams to mol:

14.3 g NaCl x ( 1 mol NaCl/ 58.44 g NaCl) = 0.24 mol NaCl

4. Molarity:

M = mol NaCl / L solution

M = 0.24 mol NaCl / 0.1 L = 2.4 M

Answer:

Air will Float

Ice will Float.

aluminium will sink

Lead. has to sink

Gold will sink

Ethanol it will nor sink or float. it is like neutral.

methanol will Float.

Explanation:

may it helps you.

The bullet would have more kinetic energy if it were heated because it would get hotter.

Kinetic energy, which may be seen in an object, particle, or group of particles moving, is the energy of motion. Kinetic energy is used by any moving item, such as a person walking, a baseball being thrown, a piece of food falling from a table, or a charged particle in an electric field.

An object in motion has energy called kinetic energy. Kinetic energy can be found in the motion of molecules in space, you walking down the street, and the earth rotating around the sun. Kinetic energy (K.E.) is directly proportional to an object's mass and the square of its velocity: K.E. = 1/2 m v2.

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There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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Answer:

4 or 3 atoms; leaning towards 4 more

Explanation:

Answer:

3 atoms

Explanation: