what does it mean standard unit?​

Answer:

The electric field strength 62.5 N/C.

Explanation:

The electric force (F) on an object with charge q in an electric field with strength E can be calculated using the formula:

F = qE

Rearranging this formula, we can solve for the electric field strength:

E = F / q

In this case, the object has a charge of q = 0.08 C and experiences an electric force of F = 5.0 N. Substituting these values into the formula, we get:

E = 5.0 N / 0.08 C

E = 62.5 N/C

So, the electric field strength is 62.5 N/C.

Answer:

3)No, it's speed is constant.

Answer:

The correct statement is A nondigital camera uses film to record images, and a digital camera uses sensors.

Explanation:

A non digital camera uses a film and it works on the basis of light which is either produced by the flash light or sunlight. On the other hand a digital camera has its own sensors which has the ability to provide an option of low light compensation and it also allows the user to adjust the light controls digitally with the help of existing sensors.

Answer:

The inverse of f equals the inverse of d Subscript o Baseline plus the inverse of d Subscript I Baseline.

Explanation:

The lens equation shows the relation among focal length of the lens, image distance and object distance. It can be expressed as:

  \(\frac{1}{f}\) = \(\frac{1}{d_{o} }\) + \(\frac{1}{d_{I} }\)

where: f is the focal length of the lens, \(d_{o}\) is the object distance to the lens and \(d_{I}\) is the image distance to the lens.

The lens equation can be used to determine the unknown value among the variables f , \(d_{o}\) and \(d_{o}\).

Answer:

\(D. \frac{1}{f} = \frac{1}{d_{0} } + \frac{1}{d_{i} }~~\)

Explanation:

We will have that the picture that shows the highest average kinetic energy is image B.

Answer:

Known variously as the Newcomb–Benford law, the law of anomalous numbers, or the first-digit law, Benford's Law is the observation that the first digit in many real-world collections of numerical data will be tiny, as shown by the example of the first-digit law.

Explanation:

Hope it helps:)

The difference is 920nm.

The wavelength can be defined as the separation between wave crests. Additionally, a wide variety of objects move in waves, including light, the earth or ground, water, strings, air, and sound waves. Furthermore, we use the Greek letter lambda to denote the wave's wavelength. In addition, the wave's wavelength is determined by dividing its velocity by its frequency. Additionally, we employ meters (m), which is the unit used to indicate wavelength in meters.

Positive interference is produced by a bright fringe, and the wavelength is always multiple.

The difference at the center fringe is (460 nm)(0) = 0.

The difference for the first maximum is (460 nm)(1) = 460 nm.

The difference for the second maximum is (460 nm)(2) = 920 nm.

As a result, the difference for maxima n is (460 nm) (n)

Since C is on the second maximum in the image that was submitted, the difference is stated as (460 nm)(2) = 920 nm.

Consequently, the screen's central dot on the fringe E to the left slit is 920 nm.

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Answer:

f=ma

mass of box =7kg

Explanation:

Answer:

Identify the formula to calculate velocity.

Explanation:

Sorry I have no explanation.

:(

But hope this helps!!!

Answer:-50 J

Explanation:

Answer: -50 N

Explanation:

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

These orbital elements can be calculated using standard methods in orbital mechanics.

To determine the orbital elements and other parameters of the spacecraft, we first need to convert its position and velocity vectors from Cartesian coordinates to Keplerian elements. We can do this using the following steps:

Calculate the specific angular momentum vector h:

h = ri x Vi

where ri and Vi are the position and velocity vectors, respectively, in Cartesian coordinates.

h = (3Ro + 5Ro) (-2.52c + 2y) - (-3.2c + 2y + 2.52 km/s) (5Ro)

h = 5.2 Ro c + 15.16 km/s y

Calculate the magnitude of the specific angular momentum:

| h | = sqrt(h^2)

| h | = sqrt[(5.2 Ro c)^2 + (15.16 km/s y)^2]

| h | = 15.94 km^2/s

Calculate the inclination angle i:

i = cos^-1(hz / | h |)

where hz is the z-component of the specific angular momentum vector.

hz = 15.16 km/s

i = cos^-1(15.16 km/s / 15.94 km^2/s)

i = 3.86°

Calculate the node vector N:

N = k x h / | k x h |

where k is the unit vector in the z-direction.

k = (0, 0, 1)

N = k x h / | k x h |

N = (-15.16 km/s, 5.2 Ro c, 0) / sqrt[(5.2 Ro c)^2 + (15.16 km/s)^2]

N = (-0.888, 0.306, 0)

Calculate the argument of periapsis w:

w = cos^-1(N · e / | N |)

where e is the eccentricity vector.

e = [1/μ ((V^2 - μ/| r |) r - (r · V) V)]

where μ is the gravitational parameter of the Earth, V is the velocity vector in Cartesian coordinates, and r is the position vector in Cartesian coordinates.

μ = 3.986004418 x 10^5 km^3/s^2

| r | = sqrt[(3Ro + 5Ro)^2] = 8Ro

V = (-3.2c + 2y + 2.52 km/s)

r = (3Ro + 5Ro)

e = [1/3.986004418 x 10^5 km^3/s^2 ((2.52 km/s)^2 - (3.986004418 x 10^5 km^3/s^2 / 8Ro)) (3Ro + 5Ro) - ((3Ro + 5Ro) · (-3.2c + 2y + 2.52 km/s)) (-3.2c + 2y + 2.52 km/s)]

e = (0.715, -0.439, 0)

w = cos^-1((N · e) / | N |)

w = cos^-1((-0.888 x 0.715) + (0.306 x -0.439))

w = 135.9°

Calculate the eccentricity magnitude e:

e = sqrt(e^2)

e = sqrt(0.715^2 + (-0.439)^2)e = 0.84

Calculate the semi-major axis a:

a = (2 / | r | - (V · V))^-1

a = (2 / 8Ro - (2

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Statement 1 and 3 are correct.

According to Ohm's law,

P = V I

V = I R

where,

P = Power

V = Voltage

I = Current

R =Resistance

Given that,

P = 250 * \(10^{-3}\) W

If R = 10 Ω

P = \(I^{2}\) R

\(I^{2}\) = P / R

\(I^{2}\) = 250 * \(10^{-3}\) / 10

I = 15.81 * \(10^{-2}\) A

V = 15.81 * \(10^{-2}\) * 10

V = 1.581 V < 50 V

So statement 1 is correct

If the same method is applied for 100 Ω, the voltage would be 50 V which is greater than 5 V. So statement 2 is wrong

V = P / I

V = P R / V

V = \(\sqrt{0.25*R}\)

According to this, statement 3 is correct and statement 4 is wrong.

Ohm's law states that, when two points have a potential difference, the current passing through the resistance is directly proportional to the voltage across the two points.

The given question is incomplete. The complete question is :

The power rating of the resistors in our kits are 1/4 watt. That means the power dissipated by any resistor of resistance R should not exceed 250 mW. Using the power formula P = Vxl and Ohm's law, which of the following is true? V is the voltage across the resistor and I is the current through it. (check all that apply)

Therefore, the statements 1 and 3 are true.

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The ratio of the tension Tt in the string when the ball is at the top of its path to Tb when the ball is at the bottom of its path is given by the expression TbTt = 1 - v²/gL. Therefore, the correct option is D.

When a ball of mass m is swung in a vertical circle with uniform speed, it follows a circular path with radius R, which is equal to the length of the string L. The gravitational force provides the centripetal force required to keep the ball moving in a circle.The tension T in the string can be calculated at the top and bottom of the circular path by resolving the forces acting on the ball. At the top, the weight of the ball acts downwards, and the tension acts upwards.

Hence, the net force is the centripetal force, which is given by

mv²/R - mg = mv²/L

The tension Tt can be calculated by resolving the forces vertically, which givesTt - mg = mv²/LTt = mv²/L + mg ------------ (1)

At the bottom of the path, the weight of the ball acts downwards, and the tension acts upwards. Hence, the net force is the centripetal force, which is given bymv²/R + mg = mv²/LThe tension Tb can be calculated by resolving the forces vertically, which gives

Tb + mg = mv²/LTb = mv²/L - mg ------------- (2)

Taking the ratio of equations (1) and (2), we get

TbTt = (mv²/L - mg)/(mv²/L + mg)

TbTt = (v²/gL - 1)/(v²/gL + 1) TbTt = 1 - v²/gL

The expression TbTt = 1 - v²/gL gives the ratio of the tension Tt in the string when the ball is at the top of its path to Tb when the ball is at the bottom of its path. Hence, the correct option is D.

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From the calculation, the activity of the isotope is 70.7 Bq.

We define the term half life as the amount of a radioactive isotope that is left after a given time. It is in fact the time that it takes for only half of the amount of the radioactive isotopes that is in a sample to remain.

Recall that if a substance is radioactive, this implies that the sample is capable of spontaneous disintegration. The amount of the sample that is present tends to diminish in the system as time increases.

Give the fact that;

Ao = initial activity = 100Bq

A = activity after time t = ??

Time taken = 5 minutes

Half life of the isotope = 10 minutes

Now we know that;

A/Ao = (1/2)^t/t1/2

A/100 = (1/2)^5/10

A/100 =  (1/2)^1/2

A =  (1/2)^1/2 * 100

A = 70.7 Bq

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Answer is c, they are equal:

Explanation:

The horizontal force that can pull the wheel over the curb is 16 N with the wheel 26 cm in diameter and weight is 10N.

Force is defined as the product of the mass and acceleration of the object and the unit of force is Newton. A horizontal force is defined as the force that makes the object move horizontally.  Acceleration is the rate of change of velocity per unit of time and the unit of acceleration is m/s².

From the given,

Diameter of wheel = 26 cm

Radius of the wheel = 26/2 = 13 cm

Weight = 10N

height of the curb = 8 cm

horizontal force =?

F (R - h ) = mg×h

F = mg × h / (R-h), Weight = mg

F = 10×8/(13-8)

  = 80/5

  = 16N

Thus, the horizontal force is 16 N.

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Answer: A rotating body or system can be in equilibrium if its rate of rotation is constant and remains unchanged by the forces acting on it.

hope this helped

Answer:

Kinetic energy = 5400000 J

Height, h = 45.91 m

Explanation:

It is given that,

Mass of the roller coaster train, m = 12,000 kg

Velocity of the train, v = 30 m/s

Kinetic energy is given by :

KE=\dfrac{1}{2}mv^2KE=

2

1

mv

2

KE=\dfrac{1}{2}\times 12000\ kg\times (30\ m/s)^2KE=

2

1

×12000 kg×(30 m/s)

2

KE=5400000\ JKE=5400000 J

So, the kinetic energy of the train at the top speed is 5400000 J.

For height

According to law of conservation of energy :

PEni+KE i=PE f+KE fPE i +KEi

=PEf +KE f

0+5400000\ J=mgh+00+5400000 J=mgh+0

5400000\ J=mgh5400000 J=mgh

h is the height.

5400000\ J=12000\ kg\times 9.8\ m/s^2\times h5400000 J=12000 kg×9.8 m/s

2

×h

h=45.91\ mh=45.91 m

Hence, this is the required solution.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{10}{5} \\ \)

We have the final answer as

Hope this helps you

Answer:

elastic

Explanation:

if you stretch it it will go back to its shape, and also it is the only one that makes sense.

Answer:

Elastic

Explanation:

I got it right

The initial moments after the Big Bang and the current universe have a few things in common like Expansion; Radiation; Structure formation; etc.

Expansion: The universe has been expanding since the Big Bang, and this expansion is still happening. The initial moments after the Big Bang were characterized by a period of rapid inflation, and this expansion has continued to shape the structure of the universe we see today.

Radiation: The universe was filled with intense radiation in the initial moments after the Big Bang, and this radiation still exists in the form of the cosmic microwave background (CMB) radiation.

This radiation is thought to have been produced about 380,000 years after the Big Bang and has been traveling through space ever since, providing us with valuable information about the early universe.

Formation of structure: The initial moments after the Big Bang set the stage for the formation of the large-scale structure of the universe we observe today, such as galaxies, stars, and planets. The tiny fluctuations in the density of matter in the early universe were amplified by gravitational attraction over time, leading to the formation of these structures.

However, there are also many differences between the early universe and the universe as it exists now. For example, the universe was much hotter and denser in the early moments after the Big Bang, and there were no stars or galaxies yet.

The universe has also undergone many complex physical processes over billions of years, such as the formation of black holes and the evolution of stars, that were not present in the early universe.

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Answer:

Saturn is almost as big as Jupiter despite its smaller mass because Jupiter is a more dense gas giant than Saturn.

Explanation:

Answer:

43.58 m/s

Explanation:

The final velocity, initial velocity, distance traveled and acceleration are related by the equation

v² = u² - 2ad  [1]

where

v = final velocity

u = initial velocity

a = acceleration

d = displacement

Given u = 10 m/s, a = 1.5 m/s², d = 600 m

v² = 10 ^2+ 2 x 1.5 x 600

v² = 100 + 1800

v² = 1900

v = √1900 = 43.58 m/s

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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For me: WASH OUR HANDS REGULARLY