A student rides a bicycle 240 meters in 4 minutes to get to school what is the student's speed?
Answer:
The student's speed is 60 mph.
Explanation:
All you have to do is divide: 260/4 = 60 mph.
A geologist measures the height of a mountain.the height is 5.3489km what is the height in meters write your answer in decimal
Height of a mountain is 5348.9 meter.
1 kilometer is equal to 1000 meter.
The meter, symbol m, is the primary unit of period in the international system of gadgets, although its prefixed paperwork also are used relatively regularly.
A meter is a general metric unit identical to about three feet 3 inches. This means that a meter is part of the metric gadget of dimension. Guitars, baseball bats, and backyard sticks are examples of items which might be approximately one meter lengthy. Meters also are used to measure distances in races, inclusive of strolling and swimming.
Meter readings tell power suppliers how a lot gasoline and energy you are the use of. In case you do not give your provider meter readings they may have to guess your usage. You typically turn out to be paying too much or too little while this occurs.
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The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compound.
\(K_{sp}\) of the compound is found to be 5.04 ×\(10^{-10}\).
Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.
Solubility equilibrium
Ksp = \([A^{+} ]^{a}\) \([B^{-} ]^{b}\)
Ksp = solubility product constant
A+ = cation in an aquious solution
B- = anion in an aqueous solution
a, b = relative concentrations of a and b
Given,
Solubility = s = 3.60 × \(10^{-2}\) g/L
molar mass = 288 g/ mol
∴ s= 3.60 × \(10^{-2}\) g/L ÷ 288 g/ mol = 1.25 ×\(10^{-4}\) mol/ L
Reaction:
MX3 ⇄ M + 3X
s 3s
\(K_{sp}\) =[ \(M^{+3}\)] [ \(X^{-1}\)\(]^{3}\) = solubility product
∴ \(K_{sp}\) =\([s]^{} [3s]^{3}\)
∴ \(K_{sp}\) = 3 \(s^{4}\)
∴ \(K_{sp}\) = 3 × (3.60 × \(10^{-2}\) \()^{4}\)
∴ \(K_{sp}\) = 503.8848 ×\(10^{-8}\) = 5.04 ×\(10^{-10}\)
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A benzoic acid pellet weighing 6.54 g is placed in a bomb calorimeter along with 0.35 g fuse wire. The benzoic acid is ignited, and the temperature rise is 3.6°. What is the heat capacity of this calorimeter?
Percent yield is very important in terms of money. The higher the percent yield, the more of a product you can make. If you are working for a drug company and your theoretical yield is 120 kg, but you actually made 105 kg, what is your percent yield?
A. 8.75%
B. 114%
C. 87.50%
D. 15.00%
Answer:
87.5 %
Explanation:
Step 1: Given data
Theoretical yield: 120 kgReal yield: 105 kgStep 2: Calculate the percent yield
When working with chemical reactions, we can determine the efficience in obtaining a product measuring the percent yield. The theoretical yield is the maximum amount of product that we could obtain according to the stoichiometry, whereas the real yield is the amount of product that we actually obtain when we carry out the process. We can calculate the percent yield usign the following expression.
%yield = real yield / theoretical yield × 100%
%yield = 105 kg / 120 kg × 100%
%yield = 87.5 %
Proton, Neutron and Electron of 23 13 Aluminum
The atomic mass of Aluminum is 23, which means it has a total of 23 particles in its nucleus, including protons and neutrons.
Aluminum has an atomic number of 13, which means it has 13 protons in its nucleus.
To find the number of neutrons, we subtract the atomic number from the atomic mass. So, Aluminum has 23 - 13 = 10 neutrons in its nucleus. Electrons are the negatively charged particles that orbit around the nucleus of an atom.
Aluminum, being a neutral atom, has an equal number of electrons to the number of protons in its nucleus, which is 13. These electrons are distributed in different energy levels or shells around the nucleus.
Aluminum is a widely used metal in different applications due to its unique properties such as low density, high strength, and resistance to corrosion. It is used in the manufacturing of cans, foils, and aircraft parts. The number of protons and electrons determines the atomic number and chemical properties of an element. The number of neutrons affects the stability and isotopes of an element.
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What is the molecular formula of each of the following
compounds?
(a) empirical formula CH₂, molar mass = 84 g/mol
(b) empirical formula NH₂Cl, molar mass = 51.5 g/mol
(a) the molecular formula of the compound is C₆H₁₂.
(b) the molecular formula of the compound is NH₂Cl.
(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.
The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).
To find the factor, we divide the molar mass by the empirical formula mass:
Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6
Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:
CH₂ × 6 = C₆H₁₂
Thus, the molecular formula of the compound is C₆H₁₂.
(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.
The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).
To find the factor, we divide the molar mass by the empirical formula mass:
Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1
Therefore, the molecular formula is the same as the empirical formula: NH₂Cl
Hence, the molecular formula of the compound is NH₂Cl.
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What volume of CO2 gas is
produced at STP when 2.00 mol
C2H5OH reacts?
Answer:4.00 Moles CO2
Explanation:
1) write a balanced equation I am assuming this is combustion)
C2H5OH + 3O2 ---> 2CO2 + 3H2O
2) do stoichiometry
2.00 mole C2H5OH X ( 2 mole CO2 / 1mole C2H5OH) =4.00 Mole CO2
2 moles of C2H5OH produce 2 moles of CO2 gas at STP, which occupies 44.8 liters.
Explanation:The balanced equation for the reaction between C2H5OH and CO2 is:
C2H5OH + O2 → CO2 + H2O
From the balanced equation, we can see that 2 moles of C2H5OH produce 2 moles of CO2.
At STP, 1 mole of an ideal gas occupies 22.4 liters. Therefore, in this reaction, 2 moles of CO2 gas occupy 44.8 liters at STP.
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What is the coordination number for each of the following complexes or compounds?
a. [Co(NHs).Ch|+
b. [Ca(EDTA)12-
c. Pt(NH:)412+
d. Na[Au(CI)2|
The coordination number of [Co(NH3)6]3+ is 6, [Ca(EDTA)]2- is 8, Pt(NH3)4 2+ is 4, and Na[Au(CI)2] is 2.
a. [Co(NH3)6]3+: The coordination number of this complex is 6. Each ammonia molecule has a lone pair of electrons that can form a coordinate covalent bond with the cobalt ion. Therefore, the cobalt ion is surrounded by six ammonia molecules in an octahedral arrangement. b. [Ca(EDTA)]2- : The coordination number of this complex is 8. The EDTA molecule has four carboxylic acid groups and two amine groups that can form coordinate covalent bonds with the calcium ion. Therefore, the calcium ion is surrounded by eight atoms or groups in a square antiprismatic arrangement. c. Pt(NH3)4 2+ : The coordination number of this complex is 4. Each ammonia molecule has a lone pair of electrons that can form a coordinate covalent bond with the platinum ion. Therefore, the platinum ion is surrounded by four ammonia molecules in a square planar arrangement. d. Na[Au(CI)2] : The coordination number of this compound is 2. The gold ion is coordinated by two chloride ions in a linear arrangement. The sodium ion is not involved in the coordination sphere of the gold ion
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How many moles of aluminum ions al3+ are present in 0.42 mol of al2so43
There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.
The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.
Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:
Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)
Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2
Moles of Al3+ = 0.84 mol Al3+
Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.
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A 5.40 mol sample of solid A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B and C.
The concentration of B steadily increased until it reached 1.40 M, where it remained constant.
A(s)↽−−⇀B(g)+C(g)
Then, the container volume was doubled and equilibrium was re‑established. How many moles of A remain?
The number of moles of A remaining at the new equilibrium is 1.93 mol.
What is the meaning of partial pressure?Partial pressure is the pressure exerted by a single gas component in a mixture of gases, assuming that the other gas components are absent or ideal. In other words, it is the pressure that the gas would exert if it were the only gas in the container at the same volume and temperature.
In a mixture of gases, each gas contributes to the total pressure of the system, which is the sum of the partial pressures of each gas. This is meant to refer to as Dalton's law of partial pressures. The partial pressure of a gas is proportional to its mole fraction in the mixture, which is the ratio of the number of moles of the gas to the total number of moles of all gases in the mixture.
The balanced equation for the reaction is:
A(s) ⇌ B(g) + C(g)
Let's denote the initial amount of A as nA. Since the molar mass of A is not given, we cannot determine its mass directly from the number of moles. However, we know that the initial amount of A is 5.40 moles, so we can write:
nA = 5.40 mol
At equilibrium, the concentration of B is given as 1.40 M. Using the ideal gas law, we can relate the concentration of B to its partial pressure:
PV = nRT
where P is the partial pressure of B, V is the volume of the container, n is the number of moles of B, R is the gas constant, and T is the temperature. Assuming that the volume of the container does not change during the reaction, we can write:
P = nBRT/V
where nB equals the number of moles of B. Since the concentration of B is given as 1.40 M, we have:
nB/V = [B] = 1.40 M
Substituting into the previous equation, we obtain:
P = nBRT/V = (1.40 M)(R)(T)
At equilibrium, the partial pressures of B and C must be equal, so we have:
P = PB = PC
Let's denote the number of moles of B and C as nB and nC, respectively. Since the total number of moles in the system is conserved, we have:
nA = nB + nC
At equilibrium, the number of moles of B is equal to the number of moles of C, so we have:
nB = nC = 0.5(nA)
Substituting into the ideal gas law expression for P, we obtain:
P = PB = PC = nBRT/V = (0.5nA)(R)(T)/V
We can use this equation to calculate the value of P at equilibrium. Then, when the volume of the container is doubled, the new pressure will be:
P' = P/2
At the new equilibrium, the partial pressures of B and C must be equal, so we have:
P' = PB' = PC'
We can use the same logic as before to write:
PB' = PC' = (0.5nA')(R)(T)/(2V)
where nA' is the number of moles of A remaining at the new equilibrium. Setting PB' equal to P' and solving for nA', we obtain:
nA' = nA(P')/(2P) = (5.40 mol)(1/2)/(P/P') = (5.40 mol)(1/2)/(1.40/2) = 1.93 mol
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6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
An unstable nucleusA-increases its half-lifeB - emits energy when it decaysC- increases its nuclear mass by fissionD- expels all of its protons
Explanation:
A nucleus consists o both electrons and proton. Therefore, an unstable nucleus undergoes radiation. And this causes a formation of a new atom. This is known as radioactive decay. Therefore, an unstable nucleus emits energy as it decays.
Answer:
The correct answer is B.herefore, an unstable nucleusherefore, an unstable nucleusR
- Preparation of NaPO4 solution (So): A solution (So) of sodium phosphate is to be prepared of molar concentration 0.1 mol/L. mL. 100 Given M(Na3PO)=164 g/mol. and a volume 1.1- Calculate the mass of sodium phosphate needed to prepare this solution. Deduce its mass concentration (Cm). 1.2 - Write the materials and glassware needed. 1.3- Write the equation of dissolution of sodium phosphate. 1.4- Determine the molar concentration of Na ions in this solution
Answer:
Explanation:
1.1 we have to find mass of Na3PO4;
for that we have to Calculate the moles of Na3PO4 needed:
volume is 100mL = 0.1L
Molar concentration = Moles of solute / Volume of solution in L
0.1 mol/L = Moles of Na3PO4 / 0.1 L
Moles of Na3PO4 = 0.1 mol/L * 0.1 L
Moles of Na3PO4 = 0.01 mol
Now, Calculate the mass of Na3PO4 needed:
so, Mass = Moles of Na3PO4 * Molar mass of Na3PO4
Mass = 0.01 mol * 164 g/mol
Mass = 1.64 g of Na3PO4.
1.2 materials and glassware needed:
1.64 g Sodium phosphate (Na3PO4)
100 mL volumetric flask
weighing balance
Distilled water
Glass rod
Pipette and burette
Do you think sexual reproduction or mutations are more important to increasing biodiversity?
Answer:
Sexual Reproduction
Explanation:
With sexual reproduction biodiversity increases slightly every time that a new child is created. However mutations can be more drastic, the chances of it happening are very seldom.
Carbon 14 has a half-life of 5,730 years. If a sample contained 70 mg originally, how much is left after 17,190 years.
Answer: Mass after three decay is 8.75 mg
Explanation: if you divide 17190 by 5730 you see three decays has happened.
So you divide mass by two three times. 70 mg :2 = 35 mg, 35 mg :2 = 17.5 mg
And 17.5 mg:2 = 8,75 mg
What is final volume if 3.4L of nitrogen gas at 400k is cooled to 300k and kept the same pressure
So,
The Charles law states that, at a constant pressure, the initial and final volume and temperature of a gas is described with the following equation:
\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)In this question, we're asked to find the value of V2.
Replacing our values:
\(\begin{gathered} \frac{3.4L}{400K}=\frac{V_2}{300K} \\ \\ V_2=\frac{(3.4L)(300K)}{400K} \\ \\ V_2=2.55L \end{gathered}\)Therefore, the final volume is 2.55L.
If your front lawn is 25.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1350 new snowflakes every minute, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snowflake has a mass of 1.90 mg.
Answer:
19.17 kgExplanation:
calculate area of lawn
25 * 20 = 500 sq ft
calculate how many flakes fall per minute
500 * 1150 = 575 , 000 flakes/minute
convert per minute rate to per hour rate
575 , 000 * 60 = 34 ,500 , 000 flakes/hour
now you know how many flakes feel in that one hour so we can now weigh them
34 , 500 , 000 / 1.8 = 19 , 166 , 667 mg (rounded)
convert to kilograms
19 , 166 , 667 / 100 , 000 = 19.17 kg (rounded)
5.
Which statement is false?
Chemistry explains many aspects of nature.
Knowledge of chemistry allows the public to make informed decisions.
what is enthalpy of formation.
Answer:
The change in enthalpy when one mole of a material is created from its pure components under the same conditions—1 atm of pressure and 298.15 K—is known as the standard enthalpy of formation.
Explanation:
The energy released or absorbed when one mole of a material is formed under typical circumstances from its pure constituents is measured by the standard enthalpy of formation.
The symbol of the standard enthalpy of formation is ΔHf. Δ = A change in enthalpyThe symbol o = A denotes a typical enthalpy shift.f = The f denotes that the material is made up of its constituent components.
The following equation represents the typical use of the standard enthalpy change of formation (originating from the fact that enthalpy is a state function):
\(\Delta H_{reaction}^o = \sum {\Delta H_{f}^o(products)} - \sum {\Delta H_{f}^o(Reactants)}\)
The standard enthalpy shift of formation is determined by subtracting the total of the conventional enthalpies of formation of the reagents from the total of the normal enthalpies of formation of the constituents.
The standard enthalpy of formation is defined as the change in enthalpy when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.
Enthalpy is the heat energy that is being absorbed or evolved during the progression of a chemical reaction.
The enthalpy is given the symbol H. H indicates the amount of energy. The change of enthalpy is given as ∆H, and the symbol ∆ indicates the change of enthalpy.
The heat of formation is a form of enthalpy. heat of formation is the amount of energy either absorbed or released during the formation of a compound
A student mixes 50 mal of 1.00M Ba(OH)2 with 88.7 mL of 0.475M H2SO4.
A) calculate the mass of BaSO4 formed
B) calculate the pH of the mixed solution
Answer:
A. 9.83g
B. 13.06
Explanation:
A) To calculate the mass of BaSO4 formed, you need to first write the balanced equation for the reaction:
Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O
Then, you need to find the limiting reactant, which is the one that runs out first and determines how much product is formed. You can do this by converting the volumes and concentrations of the solutions to moles and comparing them with the stoichiometric coefficients.
50 mL of 1.00 M Ba(OH)2 = 0.050 L x 1.00 mol/L = 0.050 mol Ba(OH)2 88.7 mL of 0.475 M H2SO4 = 0.0887 L x 0.475 mol/L = 0.0421 mol H2SO4
According to the equation, 1 mol of Ba(OH)2 reacts with 1 mol of H2SO4, so Ba(OH)2 is in excess and H2SO4 is the limiting reactant.
Next, you need to use the mole ratio between the limiting reactant and the product to find how many moles of BaSO4 are formed:
0.0421 mol H2SO4 x (1 mol BaSO4 / 1 mol H2SO4) = 0.0421 mol BaSO4
Finally, you need to multiply the moles of BaSO4 by its molar mass to get its mass:
0.0421 mol BaSO4 x 233.39 g/mol = 9.83 g BaSO4
So, the mass of BaSO4 formed is 9.83 g.
B) To calculate the pH of the mixed solution, you need to first find the concentration of OH- ions that remain after the reaction. You can do this by subtracting the moles of OH- that reacted with H+ from the initial moles of OH- and dividing by the total volume of the solution.
The initial moles of OH- are equal to the moles of Ba(OH)2:
0.050 mol Ba(OH)2 x (2 mol OH- / 1 mol Ba(OH)2) = 0.100 mol OH-
The moles of OH- that reacted with H+ are equal to the moles of H2SO4:
0.0421 mol H2SO4 x (2 mol H+ / 1 mol H2SO4) = 0.0842 mol H+
The remaining moles of OH- are:
0.100 mol OH- - 0.0842 mol H+ = 0.0158 mol OH-
The total volume of the solution is:
50 mL + 88.7 mL = 138.7 mL = 0.1387 L
The concentration of OH- is:
0.0158 mol OH- / 0.1387 L = 0.114 M
Next, you need to use the relationship between pH and pOH to find the pH:
pOH = -log[OH-] = -log(0.114) = 0.94 pH + pOH = 14 pH = 14 - pOH = 14 - 0.94 = 13.06
So, the pH of the mixed solution is 13.06.
Describe the AIR MASSES that would affect the climates of
Florida.
Maine.
Montana.
texas
The AIR MASSES that would affect the climates of Florida : are maritime tropical air mass and the maritime polar air mass,
Maine : maritime polar air mass and maritime tropical air mass,
Montana : continental polar and maritime polar air masses.
Texas : maritime tropical air masses and continental tropical air masses
What is known as AIR MASSES?An air mass is described as a large body of air with generally uniform temperature and humidity.
An air mass's properties are determined by the region from which it originates. The likelihood that the air mass will take on characteristics of the surface below increases with the amount of time it spends over its source region.
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what is triavalent monovilant divalent ?
Answer:
I HOPE IT HELPED THANKS
5. If a beaker contains 15.6 moles of water, H2 O, how many molecules does this represent?
6. How many formula units of PbO are contained in 0.317 moles of lead (II) oxide?
7. 6.01 x 10 25 atoms of cesium, Cs, are equivalent to how many moles of cesium?
8. Determine the number of moles that are represented by 3.54 x 10 21 molecules of sulfur dioxide, SO2 .
If a beaker contains 15.6 moles of water, H\(_2\) O, 9.3×10²⁴ are the number of molecules this represent.
The smallest recognisable unit into that a pure substance may be divided while retaining its composition & chemical properties is a molecule, which is a collection of more than one atom.
Until parts made up of individual molecules are reached, splitting of a sample of an item smaller progressively smaller parts does not result in a change regarding its composition as well as its chemical properties.
5.number of molecules= 15.6 × 6.022×10²³
=9.3×10²⁴
6. .number of molecules=0.317 × 6.022×10²³
=1.89×10²³
7. number of moles =6.01 x 10 25/ 6.022×10²³
= 100 moles
8. number of moles =3.54 x 10²¹/ 6.022×10²³
= 0.005moles
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How many liters of hydrogen gas can form at STP when 0.500 L of 2.00M HCl solution reacts with excess magnesium?
The answer is 11.2 L but can someone show the process
Taking into account the reaction stoichiometry, 11.2 liters of hydrogen gas can form at STP when 0.500 L of 2.00M HCl solution reacts with excess magnesium.
Reaction stoichiometryIn first place, the balanced reaction is:
Mg + 2 HCl → H₂ + MgCl₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg: 1 moleHCl: 2 molesH₂: 1 moleMgCl₂: 1 moleDefinition of molarityMolarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Liters of H₂ formedFirst of all, you know that react 0.500 L of 2.00M HCl. Taking into account the definition of molarity. It is possible to calculate the number of moles that react as follows:
moles of HCl= 0.500 L× 2 M
moles of HCl= 1 mole
To calculate the number of moles H₂ formed, the following rule of three can be applied: if by reaction stoichiometry 2 moles of HCl form 1 mole of H₂, 1 mole of HCl form how many moles of H₂?
moles of H₂= (1 mole of HCl× 1 mole of H₂)÷ 2 moles of HCl
moles of H₂= 0.5 moles
Finally, to calculate the liters of H₂ formed, you can apply the following rule of three: if by definition of STP conditions 1 mole of H₂ occupies a volume of 22.4 liters, 0.5 moles occupies how much volume?
volume= (0.5 moles× 22.4 L)÷ 1 mole
volume= 11.2 L
In summary, 11.2 liters of hydrogen gas can be formed at STP.
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Samantha AS
Which of the following compounds is ionic but yet it is expected to
contain covalent bonds as well in the form of a polyatomic ion?
NH3
KBr
CO2
NaF
Fe(NO2)3
Answer:
Fe(NO2)3
Explanation:
A poly atomic ion is an ion that contains more than one atom.
If we look at all the compounds that have been mentioned among the options; KBr and NaF are both ionic but do not contain any covalent poly atomic ion.
However, Fe(NO2)3 contains NO2^+ which is a poly atomic ion that contains the covalent bond.
Question 2
A proton and an electron move further apart from each other. Does the electrostatic
potential energy associated with their interaction increase or decrease?
O Increase
O Decrease
Answer:
decrease
Explanation:
because they're not the same
What are the two main properties of matter?
physical and chemical
physical and mechanical
chemical and electrical
mechanical and electrical
Answer:
physical and chemical.
Solve for Voltage
The current through a lightbulb is 0.5 A. The resistance of the
lightbulb is 220 2. What is the voltage across the lightbulb?
Answer:
110V
Explanation:
Given parameters:
Current in the lightbulb = 0.5A
Resistance = 220Ω
Unknown:
Voltage = ?
Solution:
To solve this problem, we apply the equation derived from ohm's law;
V = IR
So,
V = 0.5 x 220 = 110V
Which is the formula for dinitrogen pentoxide?
Answer:
N2O5
Explanation:
IUPAC ID: Dinitrogen pentoxide
Molar mass: 108.01 g/mol
Density: 1.64 g/cm³