An unopened bag of chips expanding as one drives up a mountain is a good example of how volume _________. Question 11 options: decreases when pressure decreases increases when pressure increases decreases when pressure increases increases when pressure decreases.
An unopened bag of chips expanding as one drives up a mountain is a good example of how volume increases when pressure decreases.
What happens as An unopened bag of chips expanding as one drives up a mountainWhen driving up a mountain, the atmospheric pressure decreases due to the decrease in air density at higher altitudes. As the external pressure decreases, the air inside the bag of chips exerts a higher pressure relative to the lower external pressure.
This pressure difference causes the bag to expand, increasing its volume. Therefore, the volume increases when the pressure decreases in this scenario.
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the maximum displacement of molecules in a medium from their rest position is called
The maximum displacement of molecules in a medium from their rest position is called the "amplitude" of the wave.
In wave motion, the displacement of particles in a medium varies periodically around their equilibrium or rest position. The amplitude of a wave represents the maximum distance that a particle is displaced from its rest position during one complete oscillation. It can be thought of as the "height" or "strength" of the wave.
The amplitude of a wave is an important characteristic as it directly affects various properties of the wave. For example, in the context of a transverse wave, such as a wave on a string, the amplitude determines the maximum displacement of the string from its equilibrium position. The larger the amplitude, the more energy is associated with the wave, resulting in a more intense wave with greater motion.
In the case of a sound wave, the amplitude determines the loudness or intensity of the sound. Higher amplitude corresponds to a louder sound, while lower amplitude results in a softer sound. Amplitude plays a significant role in conveying the energy and strength of a wave, influencing how it interacts with its surroundings and the effects it produces.
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Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply.
Answer:
ch3sh + 4O2 are the products
The frequency of a wave does not change as it passes from one medium to another.
What will most likely happen if a light wave moves from the air into a solid?
The wavelength of the light wave will increase.
O The speed of the light wave will decrease
The wavelength of the light wave will remain the same.
O The speed of the light wave will remain the same.
Mark this and return
Save and Exit
Next
Answer:
The speed of the wave will decrease (due to a shorter wavelength after passing from air to a more dense medium)
what is magnetic field
the wavelength of visible light ranges from 400 nm to 700 nm . for related problem-solving tips and strategies, you may want to view a video tutor solution of laser light. part a find the ranges of this light's frequency.
According to the question the frequency range of visible light is 430 THz to 770 THz.
What is frequency?Frequency is a measure of how often a particular event or phenomenon occurs over a given period of time. It is usually expressed in terms of cycles per unit of time, such as seconds, minutes, hours, days, weeks, months, or years. Frequency can be used to measure anything from the frequency of electrical signals to the frequency of human behavior.
The frequency of visible light is measured in terahertz (THz). The frequency range of visible light is between 430 THz and 770 THz.
This can be calculated by using the formula frequency (f) = speed of light (c) divided by the wavelength (λ).
Therefore, f = 3 * 10⁸ m/s / λ (in meters).
For example, the frequency of light with a wavelength of 700 nm would be calculated as follows:
f = 3 * 10⁸ m/s / (700 * 10⁻⁹ m) = 4.29 * 10¹⁴ Hz = 4.29 THz.
Therefore, the frequency range of visible light is 430 THz to 770 THz.
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Some iron has a coefficient of linear expansion of 12 x 10-6 / o K . A 100 mm length of iron piping is heated through 20 K. The pipe extends by:
Given that the linear expansion of the pipe is 12×10¯⁶ K¯¹, the pipe extends by 0.024 mm
Data obtained from the question Original length (L₁) = 100 mmChange in temperature (ΔT) = 20 KCoefficient of expansion (α) = 12×10¯⁶ K¯¹Change in length (ΔL) =?How to determine the new diameter
α = ΔL / L₁ΔT
12×10¯⁶ = ΔL / (100 × 20)
12×10¯⁶ = ΔL / 2000
Cross multiply
ΔL = 12×10¯⁶ × 2000
ΔL = 0.024 mm
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if the temperature is constant and the pressure increases, then the volume will ____.
The ends of a rope are held in place at the top of two posts, 9m apart and each one 8m high. If the ropes assumes a parabolic shape and touches the ground midway between the two posts, how high is the rope 2m from one of the posts?
The rope is approximately 2.95m high at a distance of 2m from one of the posts.
To find the height of the rope at a distance of 2m from one of the posts, we can use the concept of a parabolic shape formed by the rope.
Given that the posts are 9m apart and each post is 8m high, we can imagine the parabolic shape formed by the rope connecting the tops of the posts. Since the rope touches the ground midway between the posts, we can determine the equation of the parabolic shape.
Let's consider the vertex form of a parabolic equation:
y = a(x - h)² + k
In this case, the vertex is the point (h, k) representing the midpoint between the two posts. The x-axis represents the distance from the midpoint, and the y-axis represents the height of the rope.
The midpoint is at (4.5, 0), so we have:
y = a(x - 4.5)² + 0
To find the value of 'a' and determine the equation of the parabola, we can use one of the known points on the parabola. In this case, we know that the rope is 8m high at each post, so we have the point (0, 8).
Substituting this point into the equation, we get:
8 = a(0 - 4.5)² + 0
8 = 20.25a
Solving for 'a', we find:
a = 8/20.25
a ≈ 0.395
Now we can substitute the distance of 2m into the equation to find the height of the rope:
y = 0.395(2 - 4.5)² + 0
y ≈ 2.95
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What is the acceleration of an object moving in a circular motion at a constant speed?
The velocity of an item traveling in a circle at a constant speed is changing, therefore the object is still accelerating.
Since its velocity is changing, an object traveling in a circle at a constant speed is still accelerating. Particularly, even if its speed doesn't change, the direction of motion does. The item is being pulled towards the center of the circular route by a centripetal force, which is the cause of the direction shift.
The acceleration of an object moving in a circular motion at a constant speed can be calculated using the following formula:
a = \(v^2 / r\)
where
a is the centripetal acceleration,
v is the speed of the object, and
r is the radius of the circular path.
The velocity of an item traveling in a circle at a constant speed is changing, therefore the object is still accelerating.
In particular, even while its speed is constant, its direction of motion is continually changing. A centripetal force, which is dragging the item towards the centre of the circular route, is to blame for this shift in direction.
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a spring with a spring constant of 400 n/m is compressed a distance of.4m what is the force that holds the spring compressed
The required force that holds the spring compressed of spring constant is 400 n/m.
How can the force necessary to compress a spring be determined?F = -kx. The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring applies a power F = - kx toward its harmony position when it is extended or packed to a length that contrasts by a sum x from its balance length.
How do you calculate force using the spring constant and distance?As per Hooke's Law, while a spring is extended, the power applied is relative to the protracting from the balance length. The accompanying recipe can be utilized to get the spring steady: The spring consistent, k, has the equation k = - F/x. F represents power, and x for change.
According to question:We have,
K = 400 n/m , x = 4m
So, F = -kx = -(400)(4) = -1600 N.
Negative sign means force is acting opposite direction of distance cover in spring.
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On that same 30. °C day, you blow the same whistle with a frequency of
3.5x10^4 Hz. What is the wavelength of the sound?
The sound would have a wavelength of about 9.8 * 10^-3 m.
What is the wavelength?The wavelength is a characteristic of a wave that describes the distance between two successive points in the wave that are in phase, or the distance over which the wave's shape repeats. It is typically denoted by the Greek letter lambda (λ) and is measured in meters (m) or other units of length.
Given that the speed of sound in air is 343 m/s
v= λf
λ = v/f
λ = 343 m/s/3.5x10^4 Hz
λ = 9.8 * 10^-3 m
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The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant after the batter hits the ball, the ball's velocity is 35 meters per second east. The bat and ball are in contact for 1.0 x 10-2 second.
1. find the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat.
2. calculate the magnitude of the average force the Bat exerts on the ball while they are in contact.
(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.
(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.
The given parameters:
Mass of the baseball, m = 0.14 kgInitial velocity of the baseball, u = 45 m/s west (negative direction)Final velocity of the baseball, v = 35 m/s east (positive direction)Time of contact, t = 0.01 sThe magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:
\(a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2\)
The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;
\(F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N\)
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What was the initial velocity of a robot that took 5 m to get to final velocity of 19 m/s at a rate of 3 m/s/s?
Answer:
4m/s
v=u+at
19=u+3*5
u=4m/s
A plane is dropping provisions to a village. If they drop a crate of supplies and are moving sideways at a speed of 180 mph, where is the most unsafe place for the villagers to stand if they want to avoid getting hit?
A.directly under the plane as it drops the supplies
B.ahead of the plane as it drops the supplies
C.behind the plane as it drops the supplies
D.inside of the plane as it drops the supplies
need a answer please
Answer: Ahead of the plane as it drops the supplies
Explanation: i got it right.
a square conducting plate 47.0 cm on a side and with no net charge is placed in a region, where there is a uniform electric field of 79.0 kn/c directed to the right and perpendicular to the plate.find the charge density (in nc/m2) on the surface of the right face of the plate.
The correct answer to find the charge density (in nc/m²) on the surface of the right face of the plate is 6.99*10⁻⁷ NC/m².
The charge density on the surface of the right face of the plate can be found by using the formula for the electric field in terms of charge density and the permittivity of free space. The formula is: E = σ/ε0, where E is the electric field, σ is the charge density, and ε0 is the permittivity of free space.
We can rearrange the formula to solve for charge density: σ = E*ε0
Given that the electric field E is 79.0 kN/C, and the permittivity of free space ε0 is 8.85*10⁻¹² C^2/N*m², we can plug these values into the formula and solve for charge density:
σ = (79.0*10³ N/C)*(8.85*10⁻¹² C^2/N*m²) = 6.99*10⁻⁷ C/m²
Since, 1 C/m² is equal to 1 NC/m², the charge density on the surface of the right face of the plate is 6.99*10⁻⁷ NC/m².
Therefore, the charge density on the surface of the right face of the plate is 6.99*10⁻⁷ NC/m².
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what is the difference between a girl chromosome and a boy chromosomes?
Explanation:
Girls have two X Chromosomes while boys have one X Chromosome and, as you now know, one Y Chromosome. So girls are XX and boys are XY.
Answer: The X and Y chromosomes, also known as the sex chromosomes, determine the biological sex of an individual: females inherit an X chromosome from the father for a XX genotype, while males inherit a Y chromosome from the father for a XY genotype (mothers only pass on X chromosomes).
Explanation:
If the platinum-based engine is run continuously at 300 k for 1 hour with 0.50 atm of h2 and 0.50 atm of o2 injected for each reaction, approximately what mass of water will be produced?
About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.
For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.
Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.
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a light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end of the string. if the block is released from rest at a distance of 1.60 m above the floor, what is its speed just before it strikes the floor? express your answer with the appropriate unit
When released from a height of 1.60 m, a 1.50 kg block suspended from a light string hits the floor with a speed of 5.06 m/s.
To take care of this issue, we really want to utilize preservation of energy. The underlying possible energy of the block is changed over into active energy as it falls, dismissing any misfortunes because of erosion or air opposition.
To start with, we should track down the underlying expected energy of the block:
U_i = mgh
where
m = 1.50 kg (mass of the block)
g = 9.81 \(m/s^2\) (speed increase because of gravity)
h = 1.60 m (range from which the block is delivered)
U_i = (1.50 kg)(9.81 \(m/s^2\))(1.60 m) = 23.5 J
Then, we should find the last motor energy of the block not long before it strikes the floor:
K_f = (1/2)\(mv^2\)
where
v = speed of the block not long before it strikes the floor
We can utilize protection of energy to relate the underlying likely energy to the last motor energy:
U_i = K_f
Subbing the qualities we viewed as above, we get:
23.5 J = (1/2)(1.50 kg)\(v^2\)
Settling for v, we get:
v = sqrt[(2*23.5 J)/(1.50 kg)] = 5.06 m/s
Thusly, the speed of the block not long before it strikes the floor is 5.06 m/s.
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a cylinder is pushing with a 3 square inch piston and a 1 square inch rod is pushing a 1,162 lb load up an inclined plane at an angle of 17 degrees. the initial speed is 60 ft/min and the deceleration distance is 0.25 in. the coefficient of friction between the load and the surface is 0.3. what force (in lbs) is required to decelerate the load and bring it to a stop when it is traveling up the hill?
The force required to decelerate the load and bring it to a stop when traveling up the hill is approximately 1,858.8 lbs.
To determine the force required, we need to consider the forces acting on the load. The main forces involved are the gravitational force, the force applied by the cylinder, and the frictional force opposing the motion.
First, let's calculate the gravitational force acting on the load. The weight of the load can be calculated using the formula: weight = mass × acceleration due to gravity.
Since the weight is given as 1,162 lbs, we can assume the mass is also 1,162 lbs (since weight = mass × acceleration due to gravity, and the acceleration due to gravity is approximately 32.2 ft/s²).
Next, we need to calculate the force due to the inclined plane. The force exerted by the inclined plane is equal to the weight of the load multiplied by the sine of the angle of the incline.
So, the force exerted by the inclined plane is 1,162 lbs × sin(17°).
The deceleration distance of 0.25 inches can be converted to feet (0.25/12 ft) and the initial speed of 60 ft/min can be converted to ft/s (60/60 ft/s).
Now, let's calculate the frictional force. The frictional force is equal to the coefficient of friction (0.3) multiplied by the normal force, which is the weight of the load multiplied by the cosine of the angle of the incline.
So, the frictional force is 0.3 × (1,162 lbs × cos(17°)).
The total force required to decelerate the load and bring it to a stop is the sum of the force exerted by the inclined plane and the frictional force, minus the force applied by the cylinder.
Therefore, the force required is approximately (1,162 lbs × sin(17°)) + (0.3 × (1,162 lbs × cos(17°))) - (3 square inches/1 square inch) = 1,858.8 lbs.
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50 joules of energy are transferred out of a system. The energy is lost through heat, mechanical, and electrical energy took up 15 j and electrical energy took up 10 j, how many joules were lost through heat energy?
Answer:
25 joules
Explanation:
Not sure I understood correctly but since 15 are taken up by mechanical energy and 10 are taken in by electrical, 50-10-15 would result in 25 joules which must belong to heat energy
An atom that contains 6 protons 6 neutrons and 6 electrons has a mass of approximately.
The mass of an atom that have six protons; six neutrons; and six electron is 12. The mass of an atom is the total of its protons and neutron
What is protons, neutrons and electrons?Atom is the smallest structure of the chemical element. Atom contain protons, neutrons and electrons. Protons is a subatomic that contains positive electric charge where the electrons is a subatomic that contains negative electric charge or the opposite of the protons. Neutrons is a subatomic that contain no electric charge. The mass number of an atom is formulated as mass number = protons + neutrons. Hence:
mass number = protons + neutrons.
mass number = 6 + 6
mass number = 12
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Rolls of foil are 304 mm wide and 0.017 mm thick. (the density of foil is 2.7 g/cm3 .) what maximum length of foil can be made from 1.34 kg of foil?
The maximum length of foil that can be made from 1.34 kg of foil is approximately 9575.045 cm. Steps are discussed below:
To calculate the maximum length of foil that can be made from a given mass, we need to consider the volume of the foil and its density.
First, let's calculate the volume of the foil using its width and thickness:
Volume = Width x Thickness x Length
Since we want to find the maximum length, we can rearrange the equation as:
Length = Mass / (Width x Thickness x Density)
Given:
Width = 304 mm
Thickness = 0.017 mm
Density = 2.7 g/cm³
Mass = 1.34 kg = 1340 g
Converting the width and thickness to centimeters:
Width = 30.4 cm
Thickness = 0.0017 cm
Now, we can calculate the maximum length of foil:
Length = 1340 g / (30.4 cm x 0.0017 cm x 2.7 g/cm³)
Simplifying the equation:
Length = 1340 / (30.4 x 0.0017 x 2.7) cm
Length ≈ 1340 / 0.14005608 cm
Length ≈ 9575.045 cm
Therefore, the maximum length of foil that can be made from 1.34 kg of foil is approximately 9575.045 cm.
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A EELS (ELECTRIC ERLS) HOW DO THEY PRODUCE SUCH A
BIg shOCK? WHAT Voltage AND CURRENT?
Answer:
these organs make up four fifth's of it's body, and gives the electric eel ablity to generate two types of electric organ discharges:low voltage and high voltage
Calculate the net force on particle q1.
In Coulomb's Law, the variable, r, is the distance
between the charges. What is r for F2?
ke
ke = 8.99 109
F1 = -14.4 N = [?] m F2 = + N
F2 = k. 19193)
=
p2
=
--
r =
+13.0 uC
+7.70 μC
-5.90 uC
+ 91
+92
43
0.25 m
0.30 m
By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
Distance between q₂ and q₃The distance between the second charge and the third charge is given as;
r = 0.3 m
Force on q₂ due to q₃\(F_{2} = \frac{kq_2q_3}{r^2} \\\\F_{2}= \frac{(8.99\times10^9) (7.7 \times 10^{-6})(5.9\times 10^{-6}) }{0.3^2} \\\\F_2 = 4.54\ N\)
Net force on particle q₁The net force on particle q₁ is determined by summing the individual forces together;
F(net) = F₁ + F₂
F(net) = -14.4 + 4.54
F(net) = -9.86 N
Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
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Answer:
0.25m -14.4
Explanation:
Acellus :)
To view an enlarged upright image of an object through a simple magnifier, where must the object be located?.
Answer:within the focal length of the lens, provided the focal length is shorter than the near point distance.
Explanation:Hope it helps
A 1 kg object at rest is hit by a 2 kg object moving at 3 m/s. If the collision is
elastic and the 2 kg object is now moving at 2 m/s, how fast is the 1 kg object
moving after they hit?
After the collision, the 2 kg object is moving at 2 m/s and the 1 kg object is moving at 4 m/s.
In an elastic collision, both the momentum and kinetic energy are conserved. Initially, the 1 kg object is at rest, so its initial momentum is zero. The 2 kg object has a momentum of (2 kg) x (3 m/s) = 6 kgm/s before the collision. After the collision, the 2 kg object has a momentum of (2 kg) x (2 m/s) = 4 kgm/s. Therefore, the total momentum after the collision is 6 kgm/s + 4 kgm/s = 10 kgm/s.
Since momentum is conserved, the momentum of the 1 kg object after the collision must be (10 kgm/s - 6 kgm/s) = 4 kgm/s. Therefore, the velocity of the 1 kg object after the collision is 4 m/s.
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what is python in programming.
Answer:
Python is a programming language uses code like java ,Css and HTML. it is uses in software and some application. It is use in coding website and application.
Using the Skygazer's Almanac for 2022 at 40 degrees. On what
date does Deneb transit at 9:00 PM?
To find the date when Deneb transits at 9:00 PM using the Skygazer's Almanac for 2022 at 40 degrees latitude, locate the transit time range for Deneb at 9:00 PM and determine the corresponding date within that range by considering the previous and following transit times.
The Deneb star's transit time can be calculated using the Skygazer's Almanac for 2022 at 40 degrees latitude. To determine the date when Deneb transits at 9:00 PM, follow these steps:
1. Locate the section in the Skygazer's Almanac that provides the transit times for Deneb at 40 degrees latitude.
2. Look for the date range in which Deneb transits at 9:00 PM.
3. Determine the specific date within that range by considering the previous and following transit times for Deneb.
4. Keep in mind that transit times may vary slightly depending on the specific latitude within the 40-degree range.
5. It's important to consult the Almanac for the correct year, as transit times can change from year to year.
Please note that I don't have access to the specific Skygazer's Almanac for 2022, so I cannot provide you with the exact date. I recommend referring to the Almanac directly to obtain the accurate information.
In conclusion, using the Skygazer's Almanac for 2022 at 40 degrees, you can find the date when Deneb transits at 9:00 PM by locating the specific transit time range and determining the corresponding date within that range.
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Use the diagram picture to complete and match the steps of the rock cycle.
The rock cycle involves different processes through which rocks transform and turn into different types: igneous, sedimentary, and metamorphic. a) Igneous rock, b) Sedimentary rock, c) Melting, d) Cooling, e) Weathering and erosion, f) Heat and pressure, g) Melting.
What is the rock cycle?The rock cycle, also known as the lithological cycle, is the geological process through which rocks transform.
During the cycle, rocks suffer transformations that lead them to change from one type to another, turning into igneous, sedimentary, and metamorphic rocks.
The cycle begins when magma rises to the Earth's surface, where it gets cold, solidifies, and turns into igneous rocks.
Igneous rocks can suffer three types of transformations,
If they remain on the Erth's surface, they can suffer erosion, breaking, and producing small rocky fragments that deposit as sediment. Eventually, these sediments gather and compact, turning into sedimentary rocks.
If they get buried under several layers on the ground, they can suffer a change of temperature and pressure, turning into metamorphic rocks.
If they get even deeper under the crust, they can melt and become magma again.
Sedimentary rocks are composed of rocky sediments from other rocks and the remains of living beings that get stuck within the sedimentary layers.
Sedimentary rocks can suffer the same three types of transformations,
If they remain on the surface, they suffer erosion and produce new sediment.
If they get buried, they turn into metamorphic rocks due to changes in temperature and pressure.
If they are transported under the crust, they can melt and become magma.
Finally, metamorphic rocks are produced underground when other rocks suffer changes.
Metamorphic rocks have two destinies,
If they remain on the surface, they suffer erosion and produce new sediment, turning into sedimentary rocks.
If they are transported under the crust, they can melt and become magma.
According to this framework, we can complete the diagram
a) Igneous rock
b) Sedimentary rock
c) Melting
d) Cooling
e) Weathering and erosion
f) Heat and pressure
g) Melting
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