What is happening in the picture?


A)
Sunlight is reacting with waste gases produced by cellular respiration from the trees to produce chemical smog.


B)
Sunlight is reacting with waste gases produced by cellular respiration from the trees and by vehicles burning fossil fuels to produce chemical smog.


C)
Sunlight is reacting with water vapor produced by vehicles burning fossil fuels to produce photochemical smog.


D)
Sunlight is reacting with waste gases produced by vehicles burning fossil fuels to produce photochemical smog.

Answer: Oxygen

Explanation: Its found on the periodic table as an element.

Answer:

a) ammonium ion

b) amide ion

Explanation:

The order of decreasing bond angles of the three nitrogen species; ammonium ion, ammonia and amide ion is NH4+ >NH3> NH2-. Next we need to rationalize this order of decreasing bond angles from the valence shell electron pair repulsion (VSEPR) theory perspective.

First we must realize that all three nitrogen species contain a central sp3 hybridized carbon atom. This means that a tetrahedral geometry is ideally expected. Recall that the presence of lone pairs distorts molecular structures from the expected geometry based on VSEPR theory.

The amide ion contains two lone pairs of electrons. Remember that the presence of lone pairs causes greater repulsion than bond pairs on the outermost shell of the central atom. Hence, the amide ion has the least H-N-H bond angle of about 105°.

The ammonia molecule contains one lone pair, the repulsion caused by one lone pair is definitely bless than that caused by two lone pairs of electrons hence the bond angle of the H-N-H bond in ammonia is 107°.

The ammonium ion contains four bond pairs and no lone pair of electrons on the outermost nitrogen atom. Hence we expect a perfect tetrahedron with bond angle of 109°.

Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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Answer:

\(2.54\ \text{mg/L}\)

Explanation:

C = Allowable concentration = 1.1 mg/L

\(Q_1\) = Flow rate of river = \(130\ \text{m}^/\text{s}\)

\(Q_2\) = Discharge from plant = \(37\ \text{m}^3/\text{s}\)

\(C_1\) = Background concentration = 0.69 mg/L

\(C_2\) = Maximum concentration that of the pollutant

The concentration of the mixture will be

\(C=\dfrac{Q_1C_1+Q_2C_2}{Q_1+Q_2}\\\Rightarrow C_2=\dfrac{C(Q_1+Q_2)-Q_1C_1}{Q_2}\\\Rightarrow C_2=\dfrac{1.1(130+37)-130\times 0.69}{37}\\\Rightarrow C_2=2.54\ \text{mg/L}\)

The maximum concentration that of the pollutant (in mg/L) that can be safely discharged from the wastewater treatment plant is \(2.54\ \text{mg/L}\).

The expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P\(r^4\))/(8ηl) ∆t.

To derive an expression for the volume of liquid flowing per unit time through a cylindrical tube, we can apply the principles of fluid mechanics, considering the pressure gradient, viscosity coefficient, and tube radius.

The volume flow rate (Q) is defined as the volume of fluid passing through a cross-sectional area per unit time. In this case, we will consider the flow through a cylindrical tube of radius r and length l.

The Hagen-Poiseuille equation describes the flow rate in terms of the pressure gradient (∆P), viscosity coefficient (η), and tube dimensions:

Q = (π∆P \(r^4\))/(8ηl)

where k = π/8 is a constant.

To derive the expression for the volume of liquid flowing per unit time (∆V/∆t), we need to multiply the flow rate (Q) by the time interval (∆t):

∆V/∆t = Q ∆t

= (π∆P \(r^4\))/(8ηl) ∆t

Now, if we assume a constant pressure difference (∆P) and substitute k = π/8, the expression becomes:

∆V/∆t = (k∆P \(r^4\))/(ηl) ∆t

Simplifying further:

∆V/∆t = (π∆P\(r^4\))/(8ηl) ∆t

So, the expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P \(r^4\))/(8ηl) ∆t.

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Answer:

1. Some combination of ions form a solid precipitate because it is not favorable for the ions to become solvated (dissolved). Large and lowly charged ions tend to form precipitates, especially metals such as lead, barium, and silver.

2.
a. Pb(NO3)2 + 2KI -> 2KNO3 + PbI2

b. PbI2 is a precipitate because no other combinations of cations and anions will make an insoluble compound. KI, KNO3, and Pb(NO3)2 are all soluble.

c.

\(Pb^{2+}(aq) + 2NO_3^{-}(aq) + 2K^+(aq) + 2I^-{aq} = > PbI_2(s) + 2NO_3^{-}(aq) + 2K^+{(aq)}\\\\\)

is the ionic equation. Spectator ions are NO3- and K+

d.

\(Pb^{2+}(aq)+ 2I^-{aq} = > PbI_2(s) \\\)  is the net ionic equation

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The information from diagram shows the energy requirements needed in order for a reaction to

occur.

The collision theory states that each and every chemical reaction can occur between particles when the molecules collide each other.

The collision between particles is necessary but it is not sufficient for a reaction to take place. The collisions must be effective.

It is necessary to know the exact nature of an effective collision since this indicates whether particles react with each other and form new products.

According to collision theory, the reaction occur when molecules collide and molecules have sufficient activation energy to cross energy barrier.

Greater the energy, greater will be number of collision. Lesser energy, lesser will be number of collision.

Thus, the given energy diagram shows about the energy required for a reaction to take place.

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Answer: D) it shows the energy requirements needed in order for a reaction to occur.

The volume of carbon dioxide produced is approximately (d) 11.9 liters.

To determine the amount of carbon dioxide (C\(O_2\)) produced when 37.8 grams of carbon disulfide (C\(S_2\)) reacts with excess oxygen gas (\(O_2\)), we need to use stoichiometry and the given balanced chemical equation:

C\(S_2\)(l) + 3\(O_2\)(g) → C\(O_2\)(g) + 2S\(O_2\)(g)

First, we calculate the number of moles of C\(S_2\) using its molar mass:

Molar mass of (C\(S_2\)) = 12.01 g/mol (C) + 32.07 g/mol (S) × 2 = 76.14 g/mol

Number of moles of (C\(S_2\)) = mass / molar mass = 37.8 g / 76.14 g/mol ≈ 0.496 mol

From the balanced equation, we can see that the stoichiometric ratio between (C\(S_2\)) and C\(O_2\) is 1:1. Therefore, the number of moles of C\(O_2\) produced will also be 0.496 mol.

Now we can use the ideal gas law to calculate the volume of C\(O_2\) at the given temperature and pressure. The ideal gas law equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

Converting the temperature from Celsius to Kelvin:

T(K) = 28.85°C + 273.15 = 302 K

Using the ideal gas law:

V = nRT / P = (0.496 mol) × (0.0821 L·atm/mol·K) × (302 K) / (1.02 atm) ≈ 11.9 L

The correct answer is 11.9 liters.

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

a. NH3

b.

c. NaCl

d.

e. HCl

f.

Answer:

The actual yield is 268g.

Explanation:

1st) It is necessary to balance the chemical reaction:

From the balanced reaction we know that 1 moles of Fe2(SO4)3 is formed from 2 moles of Fe and 3 moles of H2SO4.

2nd) With the molar mass of Fe2(SO4)3, we have convert the mole to grams:

- Fe2(SO4)3 molar mass: 400g/mol

So, 1 mole of Fe2(SO4)3 is equal to 400g. This will be the Theroretical yield.

3rd) Now, with the Theoretical yield and the Percent yield, we can calculate the Actual yield of Fe(SO4)3:

Finally, the actual yield is 268g.

Answer:

it's liquid

Explanation:

because liquid has no shape as it travels and cannot be stopped

The uncertainty in the velocity of the car is 7.85×10⁻³¹

Velocity is the directional speed of an object n motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time

Here given data is

Mass of automobiles = 2190 lb = 993.26kg

Speed of car = v = 85.5 mph = 38.2 m/s

Uncertainty in the position of car = Δx =  5 f = 1.52m

the uncertainty in the velocity of the car is determined by heinsberg uncertainty principle

ΔPΔx ≥ h/4π

mΔvΔx ≥ h/4π

Δv ≥ h/4π×mΔx

Δv ≥ 6.626×10⁻³⁴/4π× 993.26kg× 1.52m

Δv ≥ 7.85×10⁻³¹

The uncertainty in the velocity of the car is 7.85×10⁻³¹

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Answer:

she musty

Explanation:

Following are the effects of acid rain.

What is Acid Rain?

Acid rain is caused by the accumulation of nitric and sulfuric acids in the atmosphere. These compounds are strong acids and are very soluble in water, dissolving in droplets in clouds.

Limestone effect:

Calcium carbonate, [Ca][CO3], is a very common mineral. A limestone is a well-known form of calcium carbonate. The acid contained in acid rain reacts with carbonate ions and promotes the dissolution of calcium carbonate.

This will create a bicarbonate solution. The presence of limestone and other calcium carbonates in lakes and streams helps maintain a constant pH as the mineral reacts with excess acidity. However, acid rain can eventually exceed the buffering capacity of surface waters.

How does acid rain affect buildings made of marble and limestone?

It is mainly affected in 2 ways: dissolution and alteration. Calcite dissolves when sulfuric, sulfuric and nitric acids in polluted air react with calcite in marble and limestone. Exposed areas of buildings and statues show rough surfaces, worn materials, and loss of sculptural detail. Stoneface material can be lost anywhere or only in more reactive areas.

Hence, this is how acid rain affects.

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The half-life of Po-210 is 140 days. If the initial mass of the sample is 5 kg, 3.5g will remain after 280 days.

Chemical kinetics is a subfield of physical chemistry that studies the speeds of chemical processes. The rate of the reaction may be used to classify it as quick, moderate, or sluggish. Reaction mechanism also enables us to study the effects of temperature and catalyst on reaction rate and rate constant. It informs us about reaction processes and enables us to apply particular rate constants to certain mechanistic stages.

The rate law for first order kinetics is

K=(2.303/T)×log(a/a-x)

half life=0.693/K

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

K=0.693/half life

K=0.693/140

=0.086

0.086=(2.303/ 280)×log( 5 /a-x)

0.086=0.07×log( 136/a-x)

1.22=log( 136/a-x)

136/a-x=16.5

a-x=3.5g

Therefore, 3.5g will be left after 280 days.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

\(161.9gZn\)

Explanation:

Hello there!

In this case, according the given balanced chemical reaction:

\(Zn + 2HCl\rightarrow H_2 + ZnCl_2\)

It is possible to evidence the 1:1 mole ratio of hydrogen (molar mass = 2.02 g/mol) to zinc (atomic mass = 65.41 g/mol) which is used to calculate the grams of the latter needed for the production of 5 grams of the former via stoichiometry:

\(5gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molZn}{1molH_2} *\frac{65.41gZn}{1molZn}\\\\=161.9gZn\)

Best regards!

Answer:

See explanation

Explanation:

Electron affinity is the energy released when an extra electron is added to a neutral gaseous atom. A negative value of electron affinity indicates that energy is given out and vice versa.

Metals have positive electron affinity since electrons rarely accept electrons, so;

Na(g)+ 1e^- → Na^-(g)      positive

Mg(g)+1e^- → Mg^-(g)      positive

For the last case; Br(g)+ 1e^- → Br^-(g), the electron affinity for the non-metals is negative. hence the answer

In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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Answer:

Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change.

Answer: Goldfish. :p

Explanation:

The rate of percolation of water into the soil will be 0.125 mL per second

The rate of percolation of water into the soil is determined by the volume of water that enters the soil per unit of time under specific conditions.

In this case, 750 mL of water percolated in 100 minutes.

100 minutes = 100 x 60 = 6,000 seconds

Percolation rate = 750/6000 = 0.125 mL per second

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Answer:

Clouds

Explanation:

Because I just got it right

Answer: c????????

Explanation: