what is scientific learning​

Answers

Answer 1

Answer:

the learning which is gained through observation and experimentation


Related Questions

Define simple harmonic motion. Write down the expressions for the velocity and aceraletion of such motion st different position along its path

Answers

Answer:

Simple harmonic motion is a special type of periodic motion or oscillation motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacemen

How do scientists use light years?to report report distances distances between between objects objects in in space space and and study study the the early early universeuniverseto to measure measure how how fast fast an an object object is is traveling traveling and and determine determine the the origins origins of of the the universeuniverseto to measure measure the the amount amount of of light light that that a a star star produces produces and and determine determine how how hot hot it it is is burningburningto to determine determine the the age age of of an an object object in in space space and and study study how how it it was was formedformed

Answers

Answer:to measure distances between objects and to study the early universe

Explanation:

I had this question and I got it right

A proton, moving north, enters a magnetic field. Because of this field, the proton curves downward. We may conclude that the magnetic field must have a component: _______

a. upward.
b. towards the west.
c. towards the east.
d. towards the north.
e. downward.

Answers

Answer:

towards the west

One can conclude that the magnetic field must have a component towards the east. The correct option is c.

What is magnetic field?

A magnetic field is a vector field that describes the magnetic influence on moving charges, currents, and magnetic materials.

A moving charge in a magnetic field is subjected to a force that is perpendicular to both its own velocity and the magnetic field.

Every magnet possesses a north as well as a south pole. The opposite poles attract each other, whereas the same poles repel each other.

When you rub a piece of iron against a magnet, the atoms' north-seeking poles line up in the same direction.

Moving north, a proton enters a magnetic field. The proton curves downward as a result of this field. We can conclude that the magnetic field must have an eastward component.

Thus, the correct option is c.

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You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515
lb and was traveling eastward. Car B weighs 1125
lb and was traveling westward at 41.0
mph. The cars locked bumpers and slid eastward with their wheels locked for 18.5
ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750
.

What speed
(in miles per hour) was car A traveling just before the collision? (This problem uses English units because they would be used in a U.S. legal proceeding.)

Answers

Answer:

Solve for force:

Ff = UFn

Ff = 0.75(Fn)

Ff = 0.75(1515 + 1225 * g)

Ff = 20550N

Solve for acceleration:

F= ma

20550N = (1515 + 1225) a

a = 7.5m/s^2

solve for time:

a = d / t^2  --->  7.5m/s^2 = 18.5/ t^2  ----> t = 0.85s

solve for velocity final

Impulse = F * t = 20550N * 0.85s

mv^2 = Impulse = 17467.5

(1515 + 1125)v^2 = 17467.5

vf = 2.5m/s

Plug in stuff:

1515 * v1 + 1125 * (-18.3m/s) = (1515 + 1125) * 2.5m/s

v1 = 9.23

Note: I converted 41mph(v2) to 18.3m/s, which is negative because "westward" is in the negative direction.

Explanation: Inelastic collision

I'm not sure but my guess is we can solve for the force of friction using the coefficient of friction. With that, we can solve for the acceleration in F = ma, and use that to solve for the time the two cars slide. And using that we can solve for the impulse, which is just the Force of friction times that time, which is also our momentum. Since we know the momentum, we can solve for the velocity of the two objects after the collision. Using that velocity, we can use the equation( m1v1 + m2v2 = (m1+m2)vf ), plug in the known quantities and solve for v1.(Note: don't forget to convert mph to mps and 18.5ft to meters)

Extra: I'm guessing because the two cars slide, the only force acting on them is the force of friction(so it's our net force), hence the Fnet = ma.

condition necessary for thermodynamic equilibrium​

Answers

Answer:

For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

hope it helps :)

Answer: For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

Refer to the Bohr model and the periodic table to answer the following
questions.
Element #2
00
O
o
00
21
What element does this Bohr Model representa
(A) Lithium
B Potassium
Magnesium
(D) Sodium

Refer to the Bohr model and the periodic table to answer the followingquestions.Element #200Oo0021What

Answers

The Bohr atom model represents the element called Sodium. Thus, the correct option is D.

An atom consists of protons, electrons, and neutrons. Protons and neutrons present inside the atom form the nucleus. The electrons are negatively charged and they revolve around the nucleus.

Atom has mass and atomic number. The mass number of an atom equals the sum of protons and neutrons. The atomic number is the number of protons or electrons. In the periodic table, the elements are arranged in the form of increasing order of protons or electrons.

From the given diagram, the number of electrons revolver around the nucleus is 11. Thus, the atom has 11 electrons or 11 protons is sodium. The Bohr atom model represents the element Sodium.

Hence, the ideal solution is option D.

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A spring has a spring constant of 53 N/m. How much elastic potential energy is stored in the spring when it is compressed by 0.21 m?

A. 2.33 J
B. 5.57 J
C. 11.1 J
D. 1.17 J​

Answers

Answer:

D. 1.17 J

Explanation:

The potential energy stored in a spring is given by the following:

U = (K•x²)/2

U -> elastic Potential energy

K -> spring constant

x -> compression

So:

U = (53•0.21²)/2

U = 1.17

Answer1.17:

Explanation:

Jennifer has taught her pet rat to run a maze. She thinks that the rat will
go faster if she puts its favorite treat at the end. She has the rat run the
maze ten times with the favorite treat and ten times with a regular food
pellet. She uses a stopwatch to measure how long it takes for the rat to get
to the reward.
O Replication
O Repetition

Jennifer has taught her pet rat to run a maze. She thinks that the rat willgo faster if she puts its

Answers

your answer would be i think repetition

Types of Forces:Question 4 Which statement best describes electromagnetism?
A.Electromagnetism is a compound of matter.
B.Electromagnetism is the forces and fields associated with charge.
C.Electromagnetism is the energy associated with charge
D.Electromagnetsim is the gravitation of two objects​

Answers

Answer:

B. Electromagnetism is the forces and fields associated with charge.

I need a super tragic past for my desired reality, the reality I'm going to is Naruto.

Thanks

Answers

To create a tragic past for your character, you would have to write a plot that shows a sad ending to a good story.

What is a Tragic Story?

This refers to a type of story that has negative emotions such as sadness, death, etc.

Hence, we can see that for example, you could write about two lovers and how despite all the struggles they faced, eventually died in mysterious circumstances.

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A bicycle wheel with a diameter of 24 inches is rotating 3 revolutions per second. What is the linear speed in feet/sec? Use 3.14 for pi and round to the nearest tenth

Answers

ANSWER

\(18.8ft\/s\)

EXPLANATION

We want to find the linear speed of the bicycle in feet per second.

First, we have to find the circumference of the bicycle wheel (in feet).

The circumference of a circle is:

\(C=\pi\cdot D\)

First, convert the diameter to feet:

\(\begin{gathered} 12in=1ft \\ \Rightarrow24in=\frac{24}{12}=2ft \end{gathered}\)

Hence, the circumference of the wheel is:

\(\begin{gathered} C=3.14\cdot2 \\ C=6.28ft \end{gathered}\)

This implies that each revolution is an equivalent linear distance of 6.28 ft i.e 6.28 feet per revolution.

To find the linear speed, we have to find the product of the circumference and the

rotational speed. That is:

\(\begin{gathered} s=6.28\frac{ft}{rev}\cdot3\frac{rev}{\sec } \\ s=18.84ft\/s \\ s\approx18.8ft\/s \end{gathered}\)

That is its linear speed.

Three boxes, A, B, and C, are placed on a frictionless surface as shown in the diagram below. If you push on box A with a force of 8.25 N, find the contact force (in N) between each pair of boxes. Here mA = 6.25 kg, mB = 3.25 kg, and mC = 1.50 kg. contact force between A and B N contact force between B and C N

Answers

The contact force (in N) between each pair of boxes is mathematically given as

F_{ab} = 3.56 N

F_{bc} = 1.2 N

What is the contact force (in N) between each pair of boxes.?

Generally, Any force that is generated as a consequence of two objects coming into touch with one another is referred to as a contact force. Contact forces are present everywhere and are the cause of the vast majority of macroscopic groupings of matter's obvious interactions with one another.

In conclusion, The equation for is  Acceleration of the system is mathematically given as

a = 8.25 / (5.85 + 2.95 + 1.50)

a= 0.8 m/s^2

Therefore

F_{ab} = (Mb + Mc)*a

F_{ab} = (2.95 + 1.50) * 0.8

F_{ab} = 3.56 N

F_{bc} = Mc * a

F_{bc}= 1.5 * 0.8

F_{bc} = 1.2 N

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Question : What is the relationship between Orbital Radius- a ) AU ) and Period- ( years )?

Answers

The relationship is , the square of the period of an orbit is proportional to the cube of its Orbital Radius.

What is the relationship between orbital radius?

The relationship between orbital radius and period is described by Kepler's Third Law of Planetary Motion, which states that the square of the period of an orbit is proportional to the cube of its semi-major axis.

In other words, if we denote the orbital radius (semi-major axis) by "a" in units of astronomical units (AU) and the period by "T" in years, then:

a³ = (T²)k

where;

k is a constant of proportionality that depends on the mass of the central body around which the object is orbiting.

For objects orbiting the sun, k is approximately equal to 1.

So, if you know the orbital radius of an object around the sun, you can use Kepler's Third Law to calculate its period, or vice versa.

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Calculate the change in momentum of a 0.5kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s

Answers

Answer:

The change in momentum is:  \(13.5\,\frac{kg\,m}{s}\)

Explanation:

Let's define that vectors pointing up are positive, and vectors pointing down negative.

Then we express the initial momentum of the ball as the product of its mass times the velocity, and include the negative sign since this momentum is pointing down (velocity vector is pointing down):

\(P_i=-0.5\,(15) \frac{kg\,m}{s} =-7.5\, \frac{kg\,m}{s}\)

the final momentum is positive (pointing up) and given by the product:

\(P_f=0.5\,(12) \frac{kg\,m}{s} =6\, \frac{kg\,m}{s}\)

Therefore, since the change in momentum is defined as the difference between the final momentum minus the initial one, we get:

\(P_f-P_i=6-(-7.5)\,\frac{kg\,m}{s} =13.5\,\frac{kg\,m}{s}\)

Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

The mass of an empty flask is 49.74 g. Filled with 120 cm 3 of acetone, the mass of the flask is found to be 144.78 g. What is the density of acetone?

Answers

Answer:

0.79g/cm³

Explanation:

Given parameters:

Volume of acetone = 120cm³

Mass of empty flask  = 49.74g

Mass of flask + acetone  = 144.78g

Unknown:

Density of acetone = ?

Solution:

Density is the mass per given volume of a substance. It is mathematically expressed as;

   Density  = \(\frac{mass}{volume}\)  

     Mass of acetone  =( mass of flask + acetone)   - mass of empty flask

     Mass of acetone = 144.78  - 49.74  = 95.04g

Now insert the parameters and solve;

 Density  = \(\frac{95.04}{120}\)   = 0.79g/cm³

after a great many contacts with the charged ball, how is any charge on the rod arranged (when the charged ball is far away)? select the best description. view available hint(s)for part b after a great many contacts with the charged ball, how is any charge on the rod arranged (when the charged ball is far away)?select the best description. positive charge on end b and negative charge on end a negative charge spread evenly on both negative charge on end a with end b remaining neutral both ends neutral positive charge spread evenly on both previous answers

Answers

After a great many contacts with a charged ball, the charge on the rod is arranged in such a way that the rod becomes neutral.

This is because of the process of electrical conduction, where electrons from the charged ball transfer to the rod, effectively neutralizing the charge on the ball and creating a charge distribution on the rod. Initially, the ball has an excess of electrons, which gives it a negative charge. When it comes into contact with the rod, some of these electrons transfer to the rod, creating a negative charge at one end and a positive charge at the other end. However, over time and with multiple contacts, the charges on the rod redistribute and balance out, effectively neutralizing the rod. The end result is that both ends of the rod become neutral, with no excess of electrons or shortage of electrons at either end. This process occurs because the electrons on the rod move freely and can move to any location on the rod where there is a shortage or excess of electrons.

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A spaceship hovering over the surface of Uranus drops an object from a height of 19 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases. [The acceleration due to gravity on Uranus is 88.9% of that on Earth, gUranus = (0.889)g.] answer in : s

Answers

h= height = 19 m

g.e = gravity on earth = 9.8 m/s^2

g.u = gravity on Uranus = 9.8 x (88.9/100) = 8.71 m/s^2

Apply :

h = vot + 1/2 gt^2

h= 1/2 g t^2

t = √(2h/g)

Earth:

t= √(2(19)/9.8) = 1.97 s

Uranus

t= √(2(19)/8.71) = 2.09 s

Tu - Te = 2.09 - 1.97 = 0.12 s

Answer : 0.12 s

A 7 N force and a 10 N force act on an object in opposite directions. What is the net force on the object?
70 N
17 N
3 N
1.43 N
0 N

Answers

Answer: 70N

Explanation:

'and'= multiply

7N*10N=70N

What is speed?

1)rate of motion

2)rate and direction of motion

3)the direction of motion

4)the force of motion

Answers

Answer:

1) rate of motion

Explanation:

Speed is the rate of motion. Whereas velocity is the rate and direction of motion.

Answer:

rate of motion is the correct answer because the rate is the speed in wich you are moving

An object that weighs 20 N encounters 20 N of air resistance. What is the acceleration in the y direction?

Answers

Answer:

Explanation:

F=ma.

a=m÷fcos 0

The answer is D can someone please explain why. Question 8 btw

The answer is D can someone please explain why. Question 8 btw

Answers

Answer:

Resistance, R = 60 Ohms

Explanation:

Given the following data;

For the first heater;

Voltage, V = 120 V

Resistance, R = 15 Ohms

For the second heater;

Voltage, V = 240 V

To find the resistance in the second heater;

First of all, we would determine the power rating of the heaters using the formula below;

Power = voltage²/resistance

Power = 120²/15

Power = 14400/15

Power = 960 Watts

Next, we find the resistance in the second heater;

Power = V²/R

960 = 240²/R

Cross-multiplying, we have;

960R = 57600

R = 57600/960

R = 60 Ohms

What is Gravity?
PLEASE ANSWER ​

Answers

Answer:

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

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Have a great day, be safe and healthy

Thank u  

XD

Answer:

GRAVITY:

In physics, gravity is the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.

A satellite of mass M2 orbits a planet of mass M1 in a uniform circular orbit with a constant tangential velocity, v. The distance between the satellite and the center of the planet is d. If the satellite is moved such that the distance between the satellite and the center is doubled, what is the new gravitational field strength compared to the original gravitational field strength?

Answers

The gravitational field strength of the moon at this new distance is gr/4

What is meant by  gravitational field ?

The gravitational field is the amount of gravitational force that would be applied to a little mass at that location per unit of mass. It is a vector field that is oriented in the mass's expected direction of force.

A gravitational field is the force field that surrounds any mass or collection of masses in space. Although this field spreads out in all directions, the gravitational force becomes weaker the further an object is from the source. This is a method of calculating the gravitational pull. Weight divided by mass equals the strength of the gravitational field. Strength of gravitational field = mass/weight in kilograms, or N/kg.

The complete question is : A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v.

The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?

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A baseball is thrown a distance of 20 m what is its speed if it takes 0.5 seconds to cover the distance

Answers

Answer:

40m/s

Explanation:

a camera employs _lens to form_images ​

Answers

Answer:

a camera employs camera lens to firm some images.

Explanation:

hope this helps.

how can you decrease the numbers
of calories you consume

Answers

Answer: by eating less of the recommendEd servings

Explanation:

Eating less or eating healthy

Help please

Charge is distributed uniformly along a long straight wire. The electric field 2 cm from the wire is 40N/C. The electric field 4 cm from the wire is ?
10 N/C or 20 N/C?

Answers

The electric field 4 cm from the wire is 10 N/C.

What is meant by electric field ?

Electric field at a point is defined as the force exerted per unit test charge placed at rest at that point.

Here,

The electric field at 2cm from the wire = 40 N/C

From the equation of electric field,

   E = (1/4\(\pi\)ε₀) q/r²

We know that,

E \(\alpha\) 1/r²

E₁ \(\alpha\) 1/r₁²

E₂\(\alpha\) 1/r₂²

E₂/E₁ = (r₁/r₂)²

E₂ = E₁ (r₁/r₂)²

E₂ = 40 x (2/4)²

E₂ = 10 N/C

Hence,

The electric field 4 cm from the wire is 10 N/C.

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1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.

2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.

1. A ball is at rest on the top of a hill (see the figure).At the top of the hill, the ball will have

Answers

1. At the top of the hill, the ball will have the maximum value of its gravitational potential energy and the minimum value of its kinetic energy. As the ball rolls down the hill, its gravitational potential energy is converted to kinetic energy when it gets to the ground.

2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.

4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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