What is the area and perimeter of the shape below?

Answer:

a)

slope = (-4 cm) / (650 cm)

slope ≈ -0.00615

b)  the section of the road measured horizontally is approximately 3983.74 cm long.

Step-by-step explanation:

change in horizontal distance = (change in vertical distance) / slope

change in horizontal distance = (-24.5 cm) / (-0.00615)

change in horizontal distance ≈ 3983.74 cm

Answer:

\(8 {x}^{2} - 6x - 5 = x\)

\(8 {x}^{2} - 7x - 5 = 0\)

x = (7 + √((-7)^2 - 4(8)(-5)))/(2×8)

= (7 + √(49 + 160))/16

= (7 + √209)/16

= -.4661, 1.3411 (to 4 decimal places)

Answer:

40

Step-by-step explanation:

The LCM is forty.

PLEASE MARK AS BRAINLIEST!

Answer:

40

Step-by-step explanation:

2/5 = 16/40

1/8 = 5/40

Answer:

conduction its the answer

Answer:

Hay fracciones infinitas equivalentes a 3

7

. Vea algunos ejemplos:

3

7

, 6

14

, 9

21

, 12

28

, 15

35

, 18

42

, 21

49

, 24

56

, 27

63

, 30

70

, 33

77

, 36

84

, 39

91

, 42

98

, 45

105

, 48

112

, 51

119

, 54

126

, 57

133

, 60

140

...

Lista más fácil de copiar y pegar:

3/7, 6/14, 9/21, 12/28, 15/35, 18/42, 21/49, 24/56, 27/63, 30/70, 33/77, 36/84, 39/91, 42/98, 45/105, 48/112, 51/119, 54/126, 57/133, 60/140 ...

Step-by-step explanation:

Answer: Hello, There! your Answer is Below

6:14

Step-by-step explanation:

Equivalent equations are algebraic equations that have identical solutions or roots. Adding or subtracting the same number or expression to both sides of an equation produces an equivalent equation. Multiplying or dividing both sides of an equation by the same non-zero number produces an equivalent equation.

Hope this Helps!!

Plz explain your Question Better.

Answer:

Find the slope and the y-intercept

Step-by-step explanation:

To find slope, use the equation \(\frac{y-y}{x-x}\). First, find two points on the line that are near each other and are whole numbers. Then you substitute the points into the equation.  So for example, if I had the points (0,0) and (1,2), the substitution would be:

\(\frac{2-0}{1-0}\)

To find the y-intercept, find where the line crosses over the y-axis. Then put in the y value.

If you do not know where to put slope and y-intercept:

y=mx+b

m=slope

b=y-intercept

slope= output/input

Answer:

the answer may vary, seeing as you could use any of the coordinates, but in my case i got : y = -1/2 + 4

Step-by-step explanation:

formula : y = mx + b

to find your ' b ' you had to determine where the y intersects. in this case, it intersected on positive four.

to determine your m, you have to subtract two of the plotted coordinates from each other, in my case it was (-2,5) and (4,2)

y2 - y1

-----------

x2 - x1

2 - 5

--------

4 - ( -2 )

-3

-----

6

WHICH MEANS

m = -1/2

Answer:

Step-by-step explanation:

Remark

I nearly found the length of a chord PQ. Be careful you don't make the same mistake. It is an arc which is part of the circumference.

Equation

Length of arc PQ = angle/360  * 2* pi * r

Givens

Angle = 110

r = 4 in

Solution

Length of arc PQ = 110/360  * 2 * 3.14 * 4

Length of arc PQ = 0.305555 * 6.28 * 4

Length of arc PQ = 7.67555

Length of arc PQ = 7.68

The slope of Anya’s line is equal to 3.

Mathematically, the slope-intercept form of the equation of a straight line is given by this mathematical expression;

y = mx + c

Where:

Making y the subject of formula, we have the following:

y - 2 = 3(x - 1)

y = 3x - 3 + 2

y = 3x - 1

Therefore, the slope (m) is equal to 3.

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Answer:

Step-by-step explanation:

You want the amounts invested in each of two accounts, one earning 7% and the other earning 8% simple interest, when the total investment of $30,000 earns total interest of $2370.

Let x represent the amount invested at 8%. Then the amount invested at 7% is 30000-x. The total interest earned is ...

  0.08(x) +0.07(30000-x) = 2370

  0.01x +2100 = 2370 . . . . simplify

  0.01x = 270 . . . . . . . . subtract 2100

  x = 27000 . . . . . . . multiply by 100

  30000-x = 3000

Deshaun invested $27,000 at 8% and $3,000 at 7%.

Answer:

\(r = 1.34\)

Step-by-step explanation:

Given

Solid = Cylinder + 2 hemisphere

\(Volume = 10cm^3\)

Required

Determine the radius (r) that minimizes the surface area

First, we need to determine the volume of the shape.

Volume of Cylinder (V1) is:

\(V_1 = \pi r^2h\)

Volume of 2 hemispheres (V2) is:

\(V_2 = \frac{2}{3}\pi r^3 +\frac{2}{3}\pi r^3\)

\(V_2 = \frac{4}{3}\pi r^3\)

Volume of the solid is:

\(V = V_1 + V_2\)

\(V = \pi r^2h + \frac{4}{3}\pi r^3\)

Substitute 10 for V

\(10 = \pi r^2h + \frac{4}{3}\pi r^3\)

Next, we make h the subject

\(\pi r^2h = 10 - \frac{4}{3}\pi r^3\)

Solve for h

\(h = \frac{10}{\pi r^2} - \frac{\frac{4}{3}\pi r^3 }{\pi r^2}\)

\(h = \frac{10}{\pi r^2} - \frac{4\pi r^3 }{3\pi r^2}\)

\(h = \frac{10}{\pi r^2} - \frac{4r }{3}\)

Next, we determine the surface area

Surface area (A1) of the cylinder:

Note that the cylinder is covered by the 2 hemisphere.

So, we only calculate the surface area of the curved surface.

i.e.

\(A_1 = 2\pi rh\)

Surface Area (A2) of 2 hemispheres is:

\(A_2 = 2\pi r^2+2\pi r^2\)

\(A_2 = 4\pi r^2\)

Surface Area (A) of solid is

\(A = A_1 + A_2\)

\(A = 2\pi rh + 4\pi r^2\)

Substitute \(h = \frac{10}{\pi r^2} - \frac{4r }{3}\)

\(A = 2\pi r(\frac{10}{\pi r^2} - \frac{4r }{3}) + 4\pi r^2\)

Open bracket

\(A = \frac{2\pi r*10}{\pi r^2} - \frac{2\pi r*4r }{3} + 4\pi r^2\)

\(A = \frac{2*10}{r} - \frac{2\pi r*4r }{3} + 4\pi r^2\)

\(A = \frac{20}{r} - \frac{8\pi r^2 }{3} + 4\pi r^2\)

\(A = \frac{20}{r} + \frac{-8\pi r^2 }{3} + 4\pi r^2\)

Take LCM

\(A = \frac{20}{r} + \frac{-8\pi r^2 + 12\pi r^2}{3}\)

\(A = \frac{20}{r} + \frac{4\pi r^2}{3}\)

Differentiate w.r.t r

\(A' = -\frac{20}{r^2} + \frac{8\pi r}{3}\)

Equate A' to 0

\(-\frac{20}{r^2} + \frac{8\pi r}{3} = 0\)

Solve for r

\(\frac{8\pi r}{3} = \frac{20}{r^2}\)

Cross Multiply

\(8\pi r * r^2 = 20 * 3\)

\(8\pi r^3 = 60\)

Divide both sides by \(8\pi\)

\(r^3 = \frac{60}{8\pi}\)

\(r^3 = \frac{15}{2\pi}\)

Take \(\pi = 22/7\)

\(r^3 = \frac{15}{2 * 22/7}\)

\(r^3 = \frac{15}{44/7}\)

\(r^3 = \frac{15*7}{44}\)

\(r^3 = \frac{105}{44}\)

Take cube roots of both sides

\(r = \sqrt[3]{\frac{105}{44}}\)

\(r = \sqrt[3]{2.38636363636}\)

\(r = 1.33632535155\)

\(r = 1.34\) (approximated)

Hence, the radius is 1.34cm

The radius of the cylinder that produces the minimum surface area is 1.34cm and this can be determined by using the formula area and volume of cylinder and hemisphere.

Given :

The volume of a cylinder is given by:

\(\rm V = \pi r^2 h\)

The total volume of the two hemispheres is given by:

\(\rm V' = 2\times \dfrac{2}{3}\pi r^3\)

\(\rm V' = \dfrac{4}{3}\pi r^3\)

Now, the total volume of the solid is given by:

\(\rm V_T = \pi r^2 h+\dfrac{4}{3}\pi r^3\)

Now, substitute the value of the total volume in the above expression and then solve for h.

\(\rm 10 = \pi r^2 h+\dfrac{4}{3}\pi r^3\)

\(\rm h = \dfrac{10}{\pi r^2}-\dfrac{4r}{3}\)

Now, the surface area of the curved surface is given by:

\(\rm A = 2\pi r h\)

Now, the surface area of the two hemispheres is given by:

\(\rm A'=2\times (2\pi r^2)\)

\(\rm A'=4\pi r^2\)

Now, the total area is given by:

\(\rm A_T = 2\pi rh+4\pi r^2\)

Now, substitute the value of 'h' in the above expression.

\(\rm A_T = 2\pi r\left(\dfrac{10}{\pi r^2}-\dfrac{4r}{3}\right)+4\pi r^2\)

Simplify the above expression.

\(\rm A_T = \dfrac{20}{r} + \dfrac{4\pi r^2}{3}\)

Now, differentiate the total area with respect to 'r'.

\(\rm \dfrac{dA_T}{dr} = -\dfrac{20}{r^2} + \dfrac{8\pi r}{3}\)

Now, equate the above expression to zero.

\(\rm 0= -\dfrac{20}{r^2} + \dfrac{8\pi r}{3}\)

Simplify the above expression in order to determine the value of 'r'.

\(8\pi r^3=60\)

r = 1.34 cm

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1) The expression 2⁻ˣ⁺³ = 3 is matched with graph B.

2 The expression  3ˣ⁺¹=3 is matched with graph C.

3) The expression 4ˣ = 3 is matched with graph

4 ) The expression 1ˣ/4 = 3 is matched with graph

1) The graph of the expression 2⁻ˣ⁺³ = 3  represents an exponential function where the y-coordinate is 3 when the base 2 raised to the power of (-x+3).

2) The graph of the expression 3ˣ⁺¹=3represents an exponential function where the y-coordinate is 3 when the base 3 raised to the power of (x+1). This graph is a straight line with a slope of 1.

3)  The graph of the equation 4ˣ = 3 represents an exponential function where the base 4 raised to the power of x is equal to 3. This equation has a single solution, which can be determined using logarithms.

4) The graph of the expression 1ˣ/4 = 3 represents an exponential function where the base 1 raised to the power of (x/4) is equal to 3.

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It looks like the differential equation is

\(\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}\)

Factorize the right side by grouping.

\(xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)\)

\(xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)\)

Now we can separate variables as

\(\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx\)

Integrate both sides.

\(\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx\)

\(\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx\)

\(\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}\)

You could go on to solve for \(y\) explicitly as a function of \(x\), but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

Answer:

hi the anser might be 600$

Step-by-step explanation:

Answer:

832.5

Step-by-step explanation:

if you multiply the height by the base and then divide by 2 you will get this answer (it's the formula)

Answer:

27:9

Step-by-step explanation:

Answer:

----------------------------

Plot the points and connect.

See attached

As we can see this is a right isosceles triangle.

Prove by finding lengths and slopes:

Proved, as the slopes are negative reciprocals and distances are equal.

The triangle formed by the given vertices be acute angle triangle

The given vertices of triangle,

A(-3, -2), B(-1, 3), and C(2, -4)

We know that,

The distance between two points (x₁ , y₁) and (x₂, y₂) is,

⇒ d = √ [(x₂ - x₁)² + (y₂ - y₁)²]

Now calculate the length of each side using the distance formula:

AB = √[(3 - (-2))² + (-1 - (-3))²]

     = √(29)

AC = √[(-4 - (-2))² + (2 - (-3))²]

     = √(29)  

BC = √[(-4 - 3)² + (2 - 1)²]

     = √(50)

     = 5√2

Now use the Law of Cosines to find the measure of each angle,

cos(A) = (BC² + AB² - AC²) / (2 BC AB)

cos(B) = (AC² + AB² - BC²) / (2 AC AB)

cos(C) = (BC² + AC² - AB²) / (2 BC AC)

Plugging in the values we calculated, we get:

cos(A) =  5√(2) / 58

cos(B) =  1 / √(58)

cos(C) = 5√(2) / 58

Now we can find the measure of each angle using the inverse cosine function:

A = \(cos^{-1}\)(5√(2) / 58) = 70.53 degrees

B = \(cos^{-1}\)(1 / √(58)) = 56.31 degrees

C = \(cos^{-1}\)(5√(2) / 58) = 70.53 degrees

Since all three angles are less than 90 degrees,

Hence, triangle ABC is an acute angle triangle.

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Answer:

\(|\frac{x}{y} |\)

Step-by-step explanation:

We are given the following expression: \(\sqrt\frac{x^3y^5}{xy^7}\), where x > 0 and y > 0.

We want to simplify it.

To do that, we can first simplify what is under the radical, then take the square root of what is left.

Recall that when simplifying exponents, we don't want any negative or non-integer radicals left.

To simplify what is under the radical, we can remember the rule where \(\frac{a^n}{a^m} = a^{n-m}\).

So, that means that \(\frac{x^3}{x} = x^2\) and \(\frac{y^5}{y^7} = y^{-2}\) .

Under the radical, we now have:

\(\sqrt{x^2y^{-2}}\)

Now, we take the square root of both exponents to get:

\(|xy^{-1}|\)

The reason why we need the absolute value signs is because we know that x > 0 and y > 0, but when we take the square root of of \(x^2\) and \(y^{-2}\) , the values of x and y can be either positive or negative, so by taking the absolute value, we ensure that the value is positive.

However, we aren't done yet; remember that we don't want any radicals to be negative, and the integer of y is negative.

Recall that if \(a^{-n}\), that is equal to \(\frac{1}{a^n}\).

So, by using that,

\(|x * \frac{1}{y} |\)

This can be simplified to:

\(|\frac{x}{y} |\)

If we restrict the domain of the function to the portion of the graph with a positive slope, the domain of the inverse function will be the range of the original function for values of x greater than 4, and its range will be all real numbers greater than or equal to 4.

The given function f(x) = |x – 4| + 6 is a piecewise function that contains an absolute value. The absolute value function has a V-shaped graph, and the slope of the graph changes at the point where the absolute value function changes sign. In this case, that point is x=4.

If we restrict the domain of f(x) to the portion of the graph with a positive slope, we are essentially considering the piece of the graph to the right of x=4. This means that x is greater than 4, or x>4.

The domain of the inverse function, f⁻¹(x), will be the range of the original function f(x) for values of x greater than 4. This is because the inverse function reflects the original function over the line y=x. So, if we restrict the domain of f(x) to values greater than 4, the reflected section of the graph will be the range of f⁻¹(x).

The range of f(x) is all real numbers greater than or equal to 6 because the absolute value function always produces a positive or zero value and when x is greater than or equal to 4, we add 6 to that value. The range of f⁻¹(x) will be all real numbers greater than or equal to 4, as this is the domain of the reflected section of the graph.

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Answer:

1) B = 88°, a = 13.1, b = 26.9

2) C = 73°, a = 20.9, b = 12.6

Step-by-step explanation:

To solve for the remaining sides and angles of the triangle, given two sides and an adjacent angle, use the Law of Sines formula:

\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)

Given values:

As the interior angles of a triangle sum to 180°:

\(\implies A+B+C=180^{\circ}\)

\(\implies B=180^{\circ}-A-C\)

\(\implies B=180^{\circ}-29^{\circ}-63^{\circ}\)

\(\implies B=88^{\circ}\)

Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:

\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)

\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)

Solve for a:

\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)

\(\implies a=\dfrac{24\sin 29^{\circ}}{\sin 63^{\circ}}\)

\(\implies a=13.0876493...\)

\(\implies a=13.1\)

Solve for b:

\(\implies \dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)

\(\implies b=\dfrac{24\sin 88^{\circ}}{\sin 63^{\circ}}\)

\(\implies b=26.9194211...\)

\(\implies b=26.9\)

\(\hrulefill\)

Given values:

As the interior angles of a triangle sum to 180°:

\(\implies A+B+C=180^{\circ}\)

\(\implies C=180^{\circ}-A-B\)

\(\implies C=180^{\circ}-72^{\circ}-35^{\circ}\)

\(\implies C=73^{\circ}\)

Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:

\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)

\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)

Solve for a:

\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)

\(\implies a=\dfrac{21\sin 72^{\circ}}{\sin 73^{\circ}}\)

\(\implies a=20.8847511...\)

\(\implies a=20.9\)

Solve for b:

\(\implies \dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)

\(\implies b=\dfrac{21\sin 35^{\circ}}{\sin 73^{\circ}}\)

\(\implies b=12.5954671...\)

\(\implies b=12.6\)

Answer:

i think a.... sorry if im wrong

Step-by-step explanation:

Answer:

\( 1.76 \times {10}^{ - 13} \: m\)

Step-by-step explanation:

\( \because \: 1 \: pm = {10}^{ - 12} \: m \\ \therefore \: 0.176 \: pm = 0.176 \times {10}^{ - 12} \: m \\ = 1.76 \times {10}^{ - 13} \: m\)

The baker can only make peanut butter cookies and cannot make any chocolate chip cookies with the given amount of ingredients.

Let's denote the number of batches of peanut butter cookies as "x" and the number of batches of chocolate chip cookies as "y."

From the given information, we can set up the following system of equations:

For the flour:

2x + 3y = 26

For the butter:

34x + y = 9

To solve this system of equations, we can use the substitution method or the elimination method. Let's use the elimination method:

Multiply the first equation by 17 (to make the coefficients of x in both equations the same):

34x + 51y = 442

Now we have the system of equations:

34x + y = 9

34x + 51y = 442

Subtract the first equation from the second equation:

34x + 51y - (34x + y) = 442 - 9

50y = 433

Divide both sides by 50:

y = 433/50

Since the number of batches of cookies cannot be fractional, we need to find a whole number solution for y. However, in this case, y is a fraction, indicating that the given amount of butter is not sufficient to make even one batch of chocolate chip cookies.

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Answer:

Step-by-step explanation:

You want the monthly payment, total paid, interest paid, and the fractions of the total paid that are principal and interest for a 12-year loan of $20,000 at 9%.

The loan payment formula applies. P = 20000, APR = 0.09, n = 12, T = 12.

  \(\text{pmt}=\dfrac{P\left(\dfrac{\text{APR}}{n}\right)}{\left[1-\left(1+\dfrac{\text{APR}}{n}\right)^{-nT}\right]}\\\\\\\text{pmt}=\dfrac{20000\left(\dfrac{\text{0.09}}{12}\right)}{\left[1-\left(1+\dfrac{\text{0.09}}{12}\right)^{-12\cdot20}\right]}=\dfrac{20000(0.0075)}{1-1.0075^{-240}}\approx 179.95\)

The monthly payment is $179.95.

The sum of 240 payments of 179.95 is ...

  240 · $179.95 = $43,188

The total amount repaid will be $43,188.

The amount of interest paid is the difference between the total repaid and the principal amount of the loan:

  interest = total - principal

  interest = $43,188 -20,000 = $23,188

The amount of interest paid is $23,188.

The fraction that goes to the principal is ...

  20,000/43,188 × 100% ≈ 46.3%

About 46.3% of the amount repaid goes to principal.

The remaining amount goes to interest:

  100% -46.3% = 53.7%

About 53.7% of the amount repaid goes to interest.

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a.) The value of pulses exported by US in billion would be=30 billion.

b.) The ratio of wheat export of UK to maize export of IND would be= 6:5

For question a.)

To calculate the pulses, the following steps should be taken as follows:

From the bar chart, the value of pulses in billions = 30 billions.

For question b.)

The ratio of wheat export at UK and maize export at IND would be calculated as follows:

The quantity of wheat export at UK = 24

The quantity of maize export at IND = 20

Therefore, the ratio of wheat to maize = 24:20= 6:5

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Answer:

0.4470 = 44.70% probability of a random person on the street having an IQ score of less than 98.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

What is the probability of a random person on the street having an IQ score of less than 98?

This is the pvalue of Z when X = 98. So

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{98 - 100}{15}\)

\(Z = -0.1333\)

\(Z = -0.1333\) has a pvalue of 0.4470

0.4470 = 44.70% probability of a random person on the street having an IQ score of less than 98.

Take 2 points

Slope:-

\(\\ \sf\longmapsto m=\dfrac{0-4}{-6}=\dfrac{4}{6}=\dfrac{2}{3}\)

Equation in point slope form

\(\\ \sf\longmapsto y-y_1=m(x-x_1)\)

\(\\ \sf\longmapsto y-4=\dfrac{2}{3}(x-0)\)

\(\\ \sf\longmapsto 3(y-4)=2x\)

\(\\ \sf\longmapsto 3y-12=2x\)

\(\\ \sf\longmapsto 3y=2x+12\)

\(\\ \sf\longmapsto 2x-3y+12=0\)

Answer: -37%

Step by Step Sol: 100=x

10% of 100 equals 10

100-10 = 90

30% of 90 equals 27

90-27 = 63

63-100 equals -37

The temperature decreased by 37% if the temperature changed if; at first it decreased by 10%.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

The temperature change if; at first, it decreased by 10 % and then decreased by 30%

Let x be the initial temperature

= (100 - 10) = 90%   (first it decreased by 10%)

= 90% of x

= 0.90x

Then decrease by 30 percent,

= 100 - 30 = 70%

= (0 .90x)× 0.70

= 0.63x

The original percentage left 63%

= 100 - 63 = 37

Thus, the temperature decreased by 37% if the temperature changed if; at first it decreased by 10%.

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