What is the change in freezing point,
ATf, when the 0.195 m aqueous
solution of K2S dissolves into 3
particles?
Kf (water) = 1.86 °C/m
AT = [?] °C

Answer:

0.0036265350669622

Explanation:

Report if wrong

-Atlas-

Boyle's Law-

\(\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\\\)

(Pressure is inversely proportional to the volume)

Where-

As per question, we are given that -

Now that we have all the required values and we are asked to find out the final volume, so we can put the values and solve for the final volume -

\(\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\)

\(\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf 11.5 \times 36= 9.3\times V_2\\\)

\( \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 = \dfrac{11.5 \times 36 }{9.3}\\\)

\( \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 = \cancel{\dfrac{ 414}{9.3}}\\\)

\(\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf V_2 =44.5161.....\\\)

\( \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{V_2 = 44.52 \:L }\\\)

Therefore, the volume of the ammonia will become 44.52 L if its pressure is changed to 9.3 kPa while its temperature remains constant.

Answer:

D displacement

Explanation:

This is because removing metal means your displacing it

Answer:

99•g

Explanation:

Well, ONE mole of water has a mass of 18.01⋅g⋅mol−1. and 5.5⋅mol has a mass of approx. 99⋅g.

Answer:

what do u need help with?

Explanation:

What's the question

Answer:

Normal cells are either repaired or die (undergo apoptosis) when they are damaged or get old. Cancer cells are either not repaired or do not undergo apoptosis.

Explanation:

The  image that have been shown can be said to depict a weak base. Option A

A weak base is a material that, when exposed to water, partially ionizes or dissociates, producing hydroxide ions (OH-) and their conjugate acid. Weak bases only produce a minor concentration of hydroxide ions in an aqueous solution, in contrast to strong bases, which totally dissociate and produce a significant concentration of hydroxide ions.

Weak bases have a comparatively low affinity for protons because of their restricted capacity to receive protons (H+) from water.

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The correct term to complete your question is "path." A file path shows the location of a file or folder.

File path literally denotes the location of a specific file.

In other words, this indicates that a file's path determines or specifies location of a file or a folder.

Consider a text file named abc that is located on the desktop. Its file location might be C:UsersHPDesktopabc.txt.

Other options are file type, which refers to the kind of file—it might be a text file, an image, etc.—and file extension, which is a suffix that tells what kind of file it is (like jpg, txt, or png).

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Step 1

The reaction must be completed and balanced as follows:

C3H8 + 5 O2 => 3 CO2 + 4 H2O

-------------

Step 2

Information provided:

20.0 g of C3H8

10.0 g of O2

----

Information needed:

1 mole of C3H8 = 44.1 g

1 mole of O2 = 32.0 g

(use your periodic table please)

-------------

Step 3

By stoichiometry,

C3H8 + 5 O2 => 3 CO2 + 4 H2O

44.1 g C3H8 ---------- 5 x 32.0 g O2

20.0 g C3H8 ---------- X

X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8

X = 72.6 g O2

For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.

Therefore,

Answer:

The limiting reactant = O2

The excess = C3H8

Answer:

x

Explanation:

As you move from left to right on the periodic table, the atomic radius decreases. Using this, you can infer than the one with the biggest radius is an alkali metal since the alkali metals are on the furthest left.

The value of ΔG∘ for the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃ (g) is -57.63 kJ/mol.

The equation relating ΔG∘ and the equilibrium constant (K) is: ΔG∘ = -RTlnK
Where R is the gas constant (8.314 J/mol•K), T is the temperature in Kelvin, and ln represents the natural logarithm.
To solve for ΔG∘, we need to plug in the stated values:
K = 2.0×10^8
T = 25∘C + 273.15 = 298.15 K
ΔG∘ = -8.314 J/mol•K × 298.15 K × ln(2.0×10^8)
ΔG∘ = -57,630 J/mol = -57.63 kJ/mol
Therefore, the value of ΔG∘ for the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃(g) is -57.63 kJ/mol.
The second part of the question is incomplete as the equilibrium constant is not given. We cannot calculate ΔG∘ without the value of K.

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The triple point can be seen from the graph that has been attached here.

The triple point is a special combination of temperature and pressure where the equilibrium of a substance's three phases—solid, liquid, and gas—occurs. The transition between phases happens with no discernible net change in the substance because the solid, liquid, and gas phases are in perfect equilibrium at the triple point.

A crucial reference point in thermodynamics, the triple point is frequently used to specify temperature scales and calibrate thermometers. Each substance has a specified value for temperature and pressure.

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Answer:its b

Explanation:

Answer:

Se + 2e- => Se-2

Explanation:

Ions are electrically charged particles, formed due to the gain or loss of electrons by an atom.

There are two types of ions cations and anions. An element that loses their electrons and forms positive ions are cations while metals and element that gains one or more electrons and forms negative ions are anions.

Selenium is an atom with atomic number 34 and represented as Se. The electronic configuration of Se is  1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4. Selenium will gain 2 more electrons to complete it p orbital and form an ion Se-2.

The equation is as below:

Se + 2e- => Se-2

Aluminum sulfate can be used in water purification  by weighing some measurement. The measurement to that is \(342.3\)amu.

Formula weight = 2×27+3×(32.1+4×16)

        \(\mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 &=\) 342.30amu

As a result, aluminum sulfate can be used to purify water. The formula weight for this salt is 34.30amu. The final answer is (a).

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During muscle contraction, the cross-bridge cycle involves a series of events that occur between the myosin and actin filaments. The step of "energized" refers to the process where ATP (adenosine triphosphate) is split by the enzyme myosin ATPase, resulting in the detachment of ADP (adenosine diphosphate) and Pi (inorganic phosphate) from the myosin head.

Here's a detailed explanation of this step:

Resting state: The myosin head, also known as the cross-bridge, is in a low-energy state, with ADP and Pi attached to it. The myosin head is not bound to actin at this stage.

Calcium release: When a muscle is stimulated, calcium ions are released from the sarcoplasmic reticulum into the muscle cell. Calcium binds to troponin, leading to the exposure of the actin binding sites.

Cross-bridge formation: The energized myosin head binds to the exposed actin binding sites, forming a cross-bridge between the myosin and actin filaments.

Power stroke: Upon binding, the myosin head undergoes a conformational change, releasing the stored energy from the ATP hydrolysis that occurred in the previous muscle relaxation phase. This energy causes the myosin head to rotate, pulling the actin filament towards the center of the sarcomere.

ADP and Pi detachment: As the myosin head rotates, it releases ADP and Pi. This detachment allows the myosin head to remain firmly attached to actin in a high-energy state.

Rigor state: The myosin head is tightly bound to actin in a rigor state, waiting for a new ATP molecule to bind and initiate the next cycle.

It's important to note that the energized state is transient, and subsequent steps in the cross-bridge cycle, such as the power stroke and ADP and Pi detachment, follow quickly. This cyclic process of myosin-actin interaction drives muscle contraction, allowing for movement and force generation.

Overall, the step of "energized" in the cross-bridge cycle occurs when ATP is split by myosin ATPase, and ADP and Pi detach from the myosin head, preparing it for the subsequent events in the cycle.

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Answer:

number 6, sorry late answer

Option C: It is true for the majority of isotopes that the number of protons is less than the number of neutrons if the atomic mass is less than twice the atomic number.

An element is distinguished from another by its atomic number, which is based on how many protons it has. The total number of protons and neutrons determines an element's mass number.

The contemporary periodic table is set up so that each element has an increasing number of atoms, which leads to an increase in mass number. 

You see, electrons, protons, and neutrons make up one atom. The valency of the atom is determined by the number of electrons in the outermost shell. The atomic number and a mass number of the atom are also related to the number of protons and neutrons in an atom.

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Moles are the quantity of a substance that is found in the atom or the molecules. 0.85 moles of zinc iodide will be produced from the reaction between hydroiodic acid and zinc bromide.

What is the mole in chemistry?

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12; its symbol is “mol”.

The balanced reaction is  -

2HI + ZnBr2 → 2HBr + ZnI2.

Moles of hydroiodic acid = 1.7 moles

Moles of zinc bromide = 3.43 moles

From the reaction, it can be said that 2 moles of hydroiodic acid need 1 mole of zinc bromide.

So, the moles of zinc bromide that will react in the reaction are:

1.7/2 = 0.85 moles

Hence, hydroiodic acid is a limiting reactant, and zinc bromide will remain in the reaction as it is an excess reagent.

Moles of zinc iodide is calculated from the limiting reagent:

1.7/2 = 0.85 moles

Therefore, 0.85 moles of zinc iodide are formed.

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Answer: 1,200,659.79

Explanation:

Given that a blood test indicates the presence of a particular disease 93% of the time when the disease is actually present, and we want to find the probability of the presence of the disease when the test indicates the presence of the disease.We can solve the problem by using Bayes' theorem. The probability of the disease being present when the test indicates the presence of the disease would be 0.1167 (rounded to four decimal places).

Bayes' theorem states that:

P(A|B) = P(B|A) × P(A) / P(B)

Where;P(A|B) is the probability of A occurring given that B has occurred.

P(B|A) is the probability of B occurring given that A has occurred.

P(A) is the probability of A occurring.

P(B) is the probability of B occurring

.Using the above notation, let;

A = Presence of the disease.

B = The blood test indicates the presence of the disease.

P(A|B) = The probability of the disease being present when the test indicates the presence of the disease.

P(B|A) = The probability of the blood test indicating the presence of the disease when the disease is present.

P(A) = The probability of the disease being present.

P(B) = The probability of the blood test indicating the presence of the disease.

When the test indicates the presence of the disease, the possible outcomes are:

Presence of the disease when the test indicates the presence of the disease.Presence of the disease when the test indicates the absence of the disease.No presence of the disease when the test indicates the presence of the disease.No presence of the disease when the test indicates the absence of the disease.The probability of the blood test indicating the presence of the disease when the disease is present is 93% or 0.93.P(B|A) = 0.93

The probability of the disease being present is not given in the problem statement, but we can assume it to be a small probability. Hence, we will assume P(A) to be 0.01 or 1%.P(A) = 0.01

To find the probability of the blood test indicating the presence of the disease, we can use the law of total probability. The possible outcomes when the test indicates the presence of the disease are presence and absence of the disease, i.e.,P(B) = P(B|A) × P(A) + P(B|not A) × P(not A)P(not A) = 1 - P(A) = 1 - 0.01 = 0.99P(B) = 0.93 × 0.01 + P(B|not A) × 0.99

We know that the blood test indicates the presence of a particular disease 93% of the time when the disease is actually present. Hence, we can assume that the blood test indicates the presence of the disease 7% of the time when the disease is not present.

P(B|not A) = 0.07P(B) = 0.93 × 0.01 + 0.07 × 0.99 = 0.0796

Using Bayes' theorem:

P(A|B) = P(B|A) × P(A) / P(B)P(A|B) = 0.93 × 0.01 / 0.0796 = 0.1166 ≈ 0.1167

Hence, the probability of the disease being present when the test indicates the presence of the disease is 0.1167 (rounded to four decimal places).

Answer: 0.1167

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Answer:

Adaptations

Explanation:

Adaptation is simply defined as a specific characteristics of an animal or plant which can be a body part, body covering, or behavior that helps an animal or plant survive in its environment.

The common types of Adaptations includes Physical adaptation which entails a change to a part of the body and Behavioral adaptation which is simply what an animal does in response to an external stimulus.

Examples of Adaptation includes Hibernation, Camouflage, Mimicry, Whiskers, Beaks and others. In plants, seed colour, hard endocarp, secretions e. t. c helps them survive in their environment.

Answer: hydrogen bond

Explanation:

just becuase

The conclusions tell why the data support or reject the hypothesis. The correct option is A

The final step in the scientific method is to draw conclusions from an experiment. They provide a summary of the experiment's findings and a discussion of how the data confirm or refute the hypothesis.

The conclusions ought to go through the experiment's limitations and recommend any potential future studies.

Therefore, The conclusions tell why the data support or reject the hypothesis.

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Answer:

The net ionic equation for the reaction between manganese(II) sulfide (MnS) and hydrobromic acid (HBr) can be written as follows:

MnS(s) + 2HBr(aq) → MnBr₂(aq) + H₂S(g)

To write the net ionic equation, we need to identify the species that undergo a chemical change and exclude any spectator ions that remain unchanged throughout the reaction. In this case, manganese(II) sulfide (MnS) and hydrobromic acid (HBr) react to form manganese(II) bromide (MnBr₂) and hydrogen sulfide (H₂S).

The balanced molecular equation for the reaction is:

MnS(s) + 2HBr(aq) → MnBr₂(aq) + H₂S(g)

To obtain the net ionic equation, we focus on the species that undergo a chemical change. In this case, the sulfide ion (S²⁻) reacts with the hydrogen ion (H+) from the hydrobromic acid to form hydrogen sulfide gas (H₂S). The manganese(II) ion (Mn²⁺) and the bromide ion (Br-) remain unchanged in the reaction.

Thus, the net ionic equation for the reaction is:

S²⁻(aq) + 2H+(aq) → H₂S(g)

In this equation, the solid state of manganese(II) sulfide (MnS) is not included as it does not dissociate into ions in the reaction.

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Answer:

50.6g Al would be needed

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

4 moles of aluminium react with 3 moles of oxygen to produce 2 moles of Al₂O₃

To solve this question we need to find the moles of 45g of O₂. Then using the chemical equation find the moles of Al and its mass:

Moles O₂ -Molar mass: 32g/mol-:

45g O₂ * (1mol / 32g) = 1.41 moles O₂

Moles Al:

1.41 moles O₂ * (4mol Al / 3mol O₂) = 1.875 moles Al

Mass Al -Molar mass: 26.98g/mol-:

1.875 moles Al * (26.98g / mol) =

50.6g Al would be needed

The amount of aluminum that would be required to completely react with 45 grams of O2 would be 50.59 grams.

From the balanced equation of the reaction:

\(4 Al + 3 O_2 ---> 2 Al_2O_3\)

The mole ratio of Al to O2 is 4:3.

Mole of 45 grams of O2 = mass/molar mass

                                     = 45/32

                                           = 1.4063 moles

Equivalent mole of Al: 4 x 1.4063/3

                                    = 1.875 moles

mass of Al = mole x molar mass

                 = 1.875 x 26.98

                  = 50.59 grams

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Answer:

Uniformitarianism is the idea that the natural processes operating today are the same as the natural processes that operated in the past