Answer:
d=m/v
d=10g/4cm³
d=2.5g/cm³
after you push both the car and the truck for the same amount of time with the same force, what can you say about the momentum and kinetic energy (ke) of the car and the truck? ignore friction.
The car has more momentum and more KE than the truck the reason is car mass is lower so it moves fast as compared to the truck.
What is kinetic energy?Kinetic energy is a from of energy that an particle has by reason we must apply a force.We know that Kinetic energy is the energy due to the velocity of speed of the moving objects.
Momentum is the products of its mass and velocity. When we compared car with truck , car has a lowered mass so when the mass is lower the velocity will be higher so car has more momentum.
We also know that kinetic energy also depends on mass so less mass have more kinetic energy.
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9. A motorcycle accelerates from 10. m/s to 55. m/s in 5.0 seconds. What is the average acceleration of the bike (provide reason)
09.0 m/s/s
O 3.0 m/s/s
O 5 m/s/s
O 11 m/s/s
Answer:
9.0 m/s/s
Explanation:
Given the following data;
Initial velocity = 10 m/s
Final velocity = 55 m/s
Time = 5 seconds
To find the average acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
Substituting into the equation;
\(a = \frac{55 - 10}{5}\)
\(a = \frac{45}{5}\)
Acceleration, a = 9.0 m/s²
Therefore, the average acceleration of the motorcycle is 9 meters per seconds square because it's experiencing a uniform velocity or motion.
you are approaching a cyclist riding near the right edge of the lane on a two-lane country road. at the same time, you notice a large truck approaching from the distance in the oncoming lane. you accelerate to pass the cyclist using the oncoming lane and then move to the lane-right position before meeting the oncoming truck. what is this an example of?
According to the problem this is an example of wrong-way passing.
What is wrong-way passing?Wrong-way passing is when a driver passes another vehicle on the wrong side of the road. This is an incredibly dangerous and illegal maneuver, as it can lead to head-on collisions. Wrong-way passing often occurs when the driver is unfamiliar with the area, or is distracted by something else. It can also happen when the driver is under the influence of alcohol or drugs, or is in a rush to get to their destination. Drivers should always obey the rules of the road, and be aware of their surroundings to avoid this dangerous behavior.
Wrong-way passing is a dangerous maneuver in which a vehicle drives on the wrong side of the road to pass a slower vehicle. It is illegal in most countries, and carries a high risk of collision with oncoming traffic.
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A car has a kinetic energy of 4.33 × 10^5 J when
traveling at a speed of 23 m/s.
What is its mass?
Answer:
Explanation:
The kinetic energy of a moving object is given by:
KE = (1/2)mv²
where KE is the kinetic energy, m is the mass of the object, and v is the velocity.
We can rearrange this equation to solve for the mass of the car:
m = 2KE / v²
Substituting the given values, we get:
m = 2(4.33 × 10^5 J) / (23 m/s)²
m = 2(4.33 × 10^5 J) / 529 m²/s²
m = 1.641 kg
Therefore, the mass of the car is approximately 1.641 kg.
I need help on this question!! Please answer asap!
Answer:
hub moon merc saturn sun galaxy deep field
Explanation:
6. A student starts at the origin and walks 6 meters away taking a time of 3 seconds to do so. The student then stands still for 2 seconds, and walks back towards the origin a distance of 3 meters in the next 5 in seconds. The student stops for a 1 second break and then walks 7 meters back towards the origin and ends up passing the start point. What distance did this student travel? What was their displacement?
Answer: 16 meters; -4 meters
Explanation:
For this question, you can ignore the times that were given to you.
a.) Let's start with distance. Distance is a total sum, regardless of direction. This student walked 6 meters, stands still (0 meters), 3 meters, and 7 meters. Sum up these values: 6+0+3+7 = 16 meters
b.) Displacement adds direction. The student walks 6 meters away. We will give this the +x-direction. They then walk 3 meters back towards the origin (-x-direction) and pause for a second. They continue to walk 7 more meters toward the origin (-x-direction). This time when we sum these values we must include the signs: 6+(-3)+(-7) = -4 meters. We can test this by referring to the sentence where it says they passed their starting point. This means they are now in the -x-direction and we have a negative displacement.
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How many electrons are necessary to produce a charge of −1.2C ? Express your answer using two significant figures. Part B What is the mass of this many electrons? Express your answer using two significant figures
(a) The charge of -1.2C corresponds to approximately -7.5 × 10^19 electrons. (b) The mass of this many electrons is approximately 4.8 × 10^-17 kilograms.
(a) To determine the number of electrons necessary to produce a charge of -1.2C, we need to consider the elementary charge. The elementary charge represents the charge carried by a single electron, which is approximately -1.6 × 10^-19 coulombs. Dividing the given charge by the elementary charge, we find the number of electrons.
Number of electrons = -1.2C / (-1.6 × 10^-19C/electron) ≈ 7.5 × 10^19 electrons
(b) To calculate the mass of this many electrons, we utilize the mass of a single electron. The mass of an electron is approximately 9.1 × 10^-31 kilograms. Multiplying the number of electrons by the mass of a single electron, we obtain the mass.
Mass of electrons = (7.5 × 10^19 electrons) × (9.1 × 10^-31 kg/electron) ≈ 4.8 × 10^-17 kilograms
Therefore, the charge of -1.2C corresponds to approximately -7.5 × 10^19 electrons, and the mass of this many electrons is approximately 4.8 × 10^-17 kilograms.
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Q2. True or False? A force is a push or a pull that acts on
an object due to the interaction with another object.
Answer:
True
Explanation:
----------------
(b) In a steam power plant, steam is supplied at 10MPa and 500∘C and condenser pressure is 5kPa. The steam is reheated after passing through first Assume isentropic efficiency of each stage expansion as 85%. Find the efficiency of the plant and the stean in 100MW. Neglect the pump work. If there is no reheat and expansion is in one stage with 80% isentropic efficiency, then find the efficiency and steam consumption per hour. Compare with the one with reheat.
The configuration with reheat in a steam power plant achieves higher efficiency and lower steam consumption compared to the configuration without reheat.
In order to evaluate the performance of two steam power plant configurations, namely one with reheat and another without reheat, we will analyze their efficiencies and steam consumption rates. The efficiency of a power plant is a key parameter indicating its ability to convert thermal energy into useful mechanical work.
Let us consider the following assumptions for our calculations:
- First-stage turbine efficiency (η1) in the reheat configuration: 85%
- Second-stage turbine efficiency (η2) in the reheat configuration: 85%
- Enthalpy at the turbine inlet (h1): 3400 kJ/kg
- Specific entropy at the turbine inlet (s1): 6.5 kJ/kg·K
- Enthalpy at the end of the first-stage expansion (h2): 2800 kJ/kg
- Enthalpy at the end of the second-stage expansion (h3): 3000 kJ/kg
- Specific entropy at the end of the second-stage expansion (s3): 7.5 kJ/kg·K
Let us now proceed with the calculations to compare the two configurations:
For the configuration with reheat:
Step 1: Calculate the work done in each turbine stage.
The work done in the first-stage turbine (Wt1) can be determined as:
Wt1 = η1 * (h1 - h2) = 0.85 * (3400 - 2800) = 510 kJ/kg
The work done in the second-stage turbine (Wt2) can be determined as:
Wt2 = η2 * (h2 - h3) = 0.85 * (2800 - 3000) = -170 kJ/kg (Note: The negative sign indicates work extraction)
Step 2: Calculate the heat added in the reheat cycle.
The heat added in the reheat cycle (Q1) can be calculated as the difference in enthalpy between the initial and final states:
Q1 = h1 - h3 = 3400 - 3000 = 400 kJ/kg
Step 3: Calculate the overall efficiency of the plant with reheat.
The overall efficiency (η) of the plant with reheat can be determined as the ratio of the total work done in the turbines (Wt1 + Wt2) to the heat added in the reheat cycle (Q1):
Efficiency (η) = (Wt1 + Wt2) / Q1 = (510 - 170) / 400 = 0.85 (or 85%)
Step 4: Calculate the steam consumption per hour in the reheat configuration.
The steam consumption per hour can be determined by dividing the plant capacity (100 MW) by the efficiency:
Steam consumption = Plant capacity / Efficiency = 100 MW / 0.85 = 117.65 kg/s
For the configuration without reheat (single-stage expansion):
Step 1: Determine the state points in the cycle.
Using steam tables or properties calculators, we can find the corresponding values for the single-stage expansion without reheat.
Step 2: Calculate the work done in the turbine.
The work done in the turbine (Wt) can be calculated using the efficiency (η) for the single-stage expansion:
Wt = η * (h1 - h2)
Step 3: Calculate the heat added.
The heat added (Q) can be calculated as the difference in enthalpy between the initial and final states:
Q = h1 - h2
Step 4: Calculate the overall efficiency of the plant without reheat.
The overall efficiency (η) of the plant without reheat can be determined as the ratio of the work done in the turbine (Wt) to the heat added (Q):
Efficiency (η) = Wt / Q = (0.80 * (h1 - h2)) / (h1 - h2) = 0.80 (or 80%)
Step 5: Calculate the steam consumption per hour in the configuration without reheat.
The steam consumption per hour can be determined by dividing the plant capacity (100 MW) by the efficiency:
Steam consumption = Plant capacity / Efficiency = 100 MW / 0.80 = 125 kg/s
Upon comparing the two configurations, we observe that the reheat configuration achieves a higher efficiency (85% vs. 80%) and lower steam consumption per hour (117.65 kg/s vs. 125 kg/s) when compared to the single-stage expansion without reheat.
The introduction of reheat enables additional heat transfer, resulting in improved overall plant efficiency.
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The text states that luminous matter in the Milky Way seems to be much like the tip of an iceberg. This refers to the idea that ________. luminous matter emits white light, much like the light reflected from icebergs dark matter represents much more mass and extends much further from the galactic center than the visible stars of the Milky Way black holes are much more interesting than ordinary stars that give off light the luminous matter of the Milky Way is essentially floating on the surface of a great sea of dark matter
The idea that the luminous matter in the Milky Way is much like the tip of an iceberg refers to the fact that the visible stars and gas clouds in the galaxy only make up a small fraction of the total matter present. Just like the tip of an iceberg only represents a small portion of the ice below the surface, the luminous matter we can see in the Milky Way is only a small fraction of the total matter present.
This is because the majority of the matter in the Milky Way is made up of dark matter, which does not emit or absorb light and is therefore invisible to telescopes.
Scientists estimate that dark matter makes up around 85% of the total matter in the universe, and its presence is inferred from the gravitational effects it has on luminous matter. Dark matter is thought to be distributed throughout the galaxy, forming a halo around the visible stars and gas clouds. It extends much further from the galactic center than the luminous matter, which is essentially floating on the surface of a great sea of dark matter.
Although black holes are certainly interesting objects in the Milky Way, they do not play a significant role in the idea that luminous matter is like the tip of an iceberg. Instead, it is the presence of dark matter that dominates the total matter present in the galaxy and makes up the vast majority of its mass. Therefore, the idea that the luminous matter in the Milky Way is much like the tip of an iceberg emphasizes the importance of dark matter in shaping the structure and evolution of galaxies like our own.
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1. Explain what the frequency of a transverse wave is.
2. What happens to the wave when you set the amplitude to 0 mm?
3. What happens when you move the amplitude to 40 mm?
4. Explain what the amplitude of a transverse wave is.
Explanation:
I am not understanding your question
A Car goes from rest to a velocity of 108 m/s north in 10s whats the cars acceleration in m/s²
Answer:
the acceleration of the car is 10.8 m/s².
Explanation:
Initial velocity (u) = 0
Final velocity (v) = 108 m/s
time (t) = 10 sec
Acceleration(a) = ?
we know
a = (v-u) / t
= 108 / 10
= 10.8 m/s²
Answer:
answer
Explanation:
the law is :
a=vf-vi on t
vi=0
vf=108 m/s
t=10/s
108 - 0 on 10 = 10.8
What does DARE stand for in balanced and unbalanced forces
Answer:
Balanced Forces
But what exactly is meant by the phrase unbalanced force? What is an unbalanced force? In pursuit of an answer, we will first consider a physics book at rest on a tabletop. There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.
Since these two forces are of equal magnitude and in opposite directions, they balance each other. The book is said to be at equilibrium. There is no unbalanced force acting upon the book and thus the book maintains its state of motion. When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.
Consider another example involving balanced forces - a person standing on the floor. There are two forces acting upon the person. The force of gravity exerts a downward force. The floor exerts an upward force.
Since these two forces are of equal magnitude and in opposite directions, they balance each other. The person is at equilibrium. There is no unbalanced force acting upon the person and thus the person maintains its state of motion.
Unbalanced Forces
Now consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop. The book is in motion and at the moment there is no one pushing it to the right. (Remember: a force is not needed to keep a moving object moving to the right.) The forces acting upon the book are shown below.
The force of gravity pulling downward and the force of the table pushing upwards on the book are of equal magnitude and opposite directions. These two forces balance each other. Yet there is no force present to balance the force of friction. As the book moves to the right, friction acts to the left to slow the book down. There is an unbalanced force; and as such, the book changes its state of motion. The book is not at equilibrium and subsequently accelerates. Unbalanced forces cause accelerations. In this case, the unbalanced force is directed opposite the book's motion and will cause it to slow down.
To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.
What is the relationship between the sizes
of the planets and their distances from the sun?
Answer:
The inner, rocky planets are smaller than the outer, gaseous planets
Explanation:
The relationship between the sizes of the planets and their distances from the Sun is: The smaller planets are closer to the sun while the bigger planets are farther from the sun.
A solar system can be defined as a collection of both the inner and outer planetary bodies alongside the Moon in orbit (travel) around the Sun, in slightly elliptical orbits.
Basically, the nine (9) planets of the solar system orbiting (traveling) in order of their distance around the Sun are;
Mercury.Venus.Earth.Mars.Jupiter.Uranus.Neptune.Pluto.Venus.Saturn.Basically, the relationship between the sizes of the planets and their distances from the Sun is that the smaller planets are closer to the sun while the bigger planets are farther from the sun.
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Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of both objects was tripled, and if the distance between the objects was doubled, then what would be the new force of attraction between the two objects?
Answer:
The new force of attraction would be 36 units
Explanation:
Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
This statement can be expressed with the formula:
\(\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\)
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: \(6.67\cdot 10^{-11}~Nw*m^2/Kg^2\)
Now suppose two given objects attract with a force of F=16 units, thus:
\(\displaystyle G{\frac {m_{1}m_{2}}{r^{2}}}=16\)
And now the masses of both objects is tripled, i.e., m1'=3m1, m2'=3m2, and the distance between them is doubled, r'=2r. The new force is:
\(\displaystyle F'=G{\frac {3m_{1}3m_{2}}{(2r)^{2}}}\)
Operating:
\(\displaystyle F'=G{\frac {9m_{1}m_{2}}{4r^{2}}}\)
\(\displaystyle F'=\frac{9}{4}G{\frac {m_{1}m_{2}}{r^{2}}}\)
Substituting the value of the initial force:
\(\displaystyle F'=\frac{9}{4}\cdot 16\)
\(F'=36\ units\)
The new force of attraction would be 36 units
as a bowling ball that rolls off the edge of a table falls, its horizontal component of motion
a. remains constant.
b. decreases.
c.increases.
The horizontal component of motion of a bowling ball that rolls off the edge of a table a. remains constant. This means that the ball will continue to move in the same direction and at the same speed as it did before it fell off the table.
To further explain, the force of gravity acting on the ball causes it to accelerate downwards, but it does not affect its horizontal motion. This is because there are no horizontal forces acting on the ball, such as air resistance or friction, to slow it down or speed it up. Therefore, the ball will continue to move forward at a constant speed until it hits the ground.
In summary, the horizontal component of motion of a bowling ball that rolls off the edge of a table remains constant because there are no external horizontal forces acting on the ball.
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the internal energy of a system increased by 982 j when it was supplied with 492 j of energy as heat. (a) was work done by or on the system? (b) how much work was done?
490 j worth of work has been done on the system. When a system performs 2500 J of work when its internal energy is 2000 J, the internal energy of the system increases by 4500 Joules.
According to the scenario stated, "q =+701 J, w = -394 J." <br> DeltaU = q + w = + 701 + (-394) = + 307 J, according to the first law of thermodynamics. <br> As a result, internal energy rises by 307 J. A system receives 900 joules of additional heat and 200 joules of work. So what is AE? expands in opposition to a pressure of 1.0 atm. Energy inside the body changes by 5.8 x 10 J.
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What is the equivalent resistance (total resistance) of the series circuit shown?
Answer:
In a series circuit, the equivalent resistance is the algebraic sum of the resistances. The current through the circuit can be found from Ohm's law and is equal to the voltage divided by the equivalent resistance. The potential drop across each resistor can be found using Ohm's law.
Energy balance worksheet
When John reacts to his partner's complaints by cross-complaining, which form of miscommunication is he manifesting
When John reacts to his partner's complaints by cross-complaining, he is manifesting a form of miscommunication known as defensiveness.
Defensiveness is a defensive response that occurs when someone feels attacked or criticized and responds by counter-attacking or shifting the blame onto the other person. Instead of addressing the concerns or complaints raised by his partner, John deflects them by bringing up his own complaints or grievances. This form of communication can escalate conflicts and hinder effective problem-solving and understanding between partners. Complaints are expressions of dissatisfaction or grievances about a particular issue or situation. People may have complaints in various areas of life, such as relationships, work, customer service, or product quality. Complaints are a form of communication used to express discontent or raise concerns in the hopes of seeking resolution or improvement.
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Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.
sendo:
τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)
temos: τ = Q1 - Q2
O rendimento (η) é a razão do trabalho realizado pela energia fornecida:
η= τ/Q1
Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.
solução:
τ=3500 J
Q1=5000J
η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%
Energia dissipada será:
τ = Q1 - Q2
Q2 = Q1- τ
Q2=5000-3500
Q2= 1500 J
Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?
obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem
During a certain process, the linear momentum of a system is conserved. Which one of the following statements concerning this system is correct? A. The vector sum of any internal forces within the system results in an acceleration of one or more objects within the system. B. The vector sum of the momentum of the objects that make up the system is equal to zero kg. m/s. C. No internal or external forces are acting on the objects within the system. D. The principle of the conservation of mechanical energy automatically applies to the system. E. The vector sum of the average external forces acting on the system is equal to zero newtons.
In a system where the linear momentum is conserved, the correct statement among the options provided is E: The vector sum of the average external forces acting on the system is equal to zero newtons.
This means that the total momentum of the system remains constant when only considering the external forces acting on it. The other options (A, B, C, and D) do not accurately describe a system with conserved linear momentum.
Linear momentum is a vector quantity that depends on both the mass and velocity of an object. If the linear momentum of a system is conserved, it means that the total momentum of the system remains constant over time.
This conservation of momentum can occur in the absence of external forces or when external forces balance each other out. Option A states that the vector sum of any internal forces within the system results in an acceleration of one or more objects within the system.
This statement is not necessarily correct for a system with conserved linear momentum. Internal forces can still exist within the system, but their vector sum does not necessarily result in acceleration. The key factor is that the total momentum of the system remains constant.
Option B suggests that the vector sum of the momentum of the objects in the system is equal to zero kg·m/s. However, in a system with conserved momentum, the total momentum does not necessarily equal zero. It remains constant, but its value can be non-zero.
Option C states that no internal or external forces are acting on the objects within the system. This is not necessarily true, as internal and external forces can still exist in a system with conserved momentum.
The crucial aspect is that the vector sum of the average external forces acting on the system is zero. Option D mentions the principle of the conservation of mechanical energy, which is not directly related to the conservation of linear momentum.
Conservation of mechanical energy applies to systems where no net external work is done on the system, but it does not automatically apply to systems with conserved linear momentum. Option E correctly states that the vector sum of the average external forces acting on the system is equal to zero newtons.
This implies that the total momentum of the system remains constant when considering only the external forces acting on it. Internal forces may still exist within the system, but their effects cancel out on average, leading to the conservation of linear momentum.
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calculate the work done by 2N force directed at 30 degree to the vertical to move a 500g box a horizontal distance of 400 cm across a rough floor at constant speed of 0.5 m per second
Answer:
there is no picture :o?
Explanation:
:oo
On the planet Zarflax-beta-9z a book with a mass of 3kg weighs 51N. What is the strength of gravity on Zarflax-beta-9z?
The strength of gravity on Zarflax-beta-9z is 17 N/kg.
We can use the formula:
weight = mass x gravity
to determine the strength of gravity on Zarflax-beta-9z.
We know that the mass of the book is 3 kg and its weight is 51 N. So, we can rearrange the formula to solve for gravity:
gravity = weight / mass
gravity = 51 N / 3 kg
gravity = 17 N/kg
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A jump rope is shaken producing a wave with a wavelength of 4 m with the crest of the wave
passing a certain point 5 times per second. What is the velocity of the wave?
A) 20 m/s
B) 1.25 m/s
C) 0.8 m/s
D) 9 m/s
Answer:
A) 20m/s
Explanation:
v= wavelength*frequency
You have a wavelength of 4m and a frequency of 5, so you just multiply 4*5=20 v= 20m/s
Which of the following can be correct units for acceleration?
A. miles/hr/m
B. Km/s/hr
C. m/s/m
D. km/m/s
Answer:
B. Km/s/hr
Explanation:
In each hand you hold a 0.16-kg peach. What is the gravitational force exerted by one peach on the other when their separation is (a) 0.25 m and (b) 0.50 m?
The gravitational force exerted by one peach on the other can be calculated using the formula F = G(m1m2)/r²,
where F is the force, G is the gravitational constant (6.67 x 10^-11 Nm²/kg²), m1 and m2 are the masses of the two peaches, and r is the distance between their centers of mass.
(a) When the separation between the peaches is 0.25 m, the force exerted by one peach on the other is:
F = (6.67 x 10⁻¹¹ N×m²/kg²) × (0.16 kg × 0.16 kg) / (0.25 m)² = 1.07 x 10⁻⁹N
(b) When the separation between the peaches is 0.50 m, the force exerted by one peach on the other is:
F = (6.67 x 10^-11 N×m²/kg²) ×(0.16 kg × 0.16 kg) / (0.50 m)²= 2.67 x 10⁻¹⁰ N
Therefore, the gravitational force exerted by one peach on the other decreases as the distance between them increases. This is because the force of gravity is an inverse square law, meaning that the force decreases proportionally to the square of the distance between the objects.
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what is frictional force?
how to Express frictional force?
Answer:
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.
Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.
HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
HELP ASAP!!! 100 POINTS! NEED CORRECT ANSWER!! NO TROLLS!!
The focal distance for a convex lens is 80 cm. What kind of image is produced when the object distance is between 80 cm and 160 cm?
a) upright and larger
b) inverted and smaller
c) inverted and larger
d) upright smaller
Answer: B ) inverted and smaller
Explanation:
I Got It Right On my Quiz