what is the extracellular matrix of connective tissue composed ofA) ground substance only.B) ground substance and intracellular fluid.C) cells and protein fibers.D) protein fibers and ground substance.E) cells and ground substance.

Answer: A, B, C or D

Explanation: its either those

Answer:

Static Model

Explanation:

Answer:

yrt a

Explanation:

Answer:

G = $37,805.65

Explanation:

I found this on another site:

475,000 = 25,000(P/A,10%,6) + G(P/G,10%,6)

475,000 = 25,000(4.3553) + G(9.6842)

9.6842G = 366,117.50

G = $37,805.65

The  gradient each year through at an interest rate of 10% per year is $37,805.65.

Investment refers to the money spend on the acquiring the assets and also to build up the capital for the businessmen and wealth for the individual. It involves saving of the money.

Investment is the collection of the money from other primary source of the income. It also includes profit gains from the investment over a specific period of time.

According to the question,  projected arithmetic gradient is $475,000 and estimated income for one year is $25,000.

Thus, the gradient for each year is calculated as follows:-

475,000 = 25,000(P/A,10%,6) + G(P/G,10%,6)

475,000 = 25,000(4.3553) + G(9.6842)

9.6842G = 366,117.50

Gradient  = $37,805.65

Therefore, it can be concluded that  gradient each year through at an interest rate of 10% per year is $37,805.65.

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The goal of Boeing, Inc is to determine whether an existing machine can mill an engine part that has a design specification of 5.0mm +- 0.10 mm. The process has a standard deviation of σ = 0.02 mm.

Given that the standard deviation of the process is σ = 0.02 mm. Now, we need to determine if the existing machine can produce a part that meets the design specification using the given standard deviation (σ).The tolerance limit (T.L) can be calculated as;

T.L = (Upper Limit – Lower Limit) / 2 where;

Upper Limit = 5.0 + 0.10 = 5.10 mm

Lower Limit = 5.0 – 0.10 = 4.90 mm

T.L = (5.10 – 4.90) / 2 = 0.10 / 2 = 0.05 mm

The value of T.L = 0.05 mm

The process standard deviation (σ) = 0.02 mm

Using the formula;

P = 0.6827, approximately 68.27% of the parts produced by the existing machine fall within the tolerance limit (5.0 ± 0.10)

With a process standard deviation of σ = 0.02 mm and a tolerance limit of 0.05 mm, approximately 68.27% of the parts produced by the existing machine fall within the tolerance limit (5.0 ± 0.10). It can, therefore, be concluded that the existing machine can produce parts that meet the design specification.

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Answer:

c

Explanation:

if someone is wrong that they can help with

Answer:

At x = 3m , Tw = 0.0176 N/m^2

At x = 6m , Tw = 0.056 N/m^2

Explanation:

Here in this question, we are concerned with calculating the boundary layer thickness and the wall shear stress at the center and the trailing edge of the plate , assuming a laminar boundary layer.

Please check attachment for complete solution

Answer:

d

Explanation:

yea

Answer:

D

Explanation:

The equilibrium, the pressure of SO₃ is equal to the square root of Kp times 6

You should understand that equilibrium pressure is the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases at a given temperature in a closed system.

It relates to the balance of particles escaping from the liquid or solid in equilibrium with those in a coexisting vapor phase.

A substance with a high vapor pressure at normal temperatures is often referred to as volatile

The gas phase reaction

SO₂(g) + O₂(g) ↔ 2SO₃(g), can be calculated if we know the equilibrium.

⇒Kp = P(SO₃)² / P(SO₂) x P(O₂)

Where P(SO₃), P(SO₂) and P(O₂) are the partial pressures of the respective gases at equilibrium.

Kp = P(SO₃)² / P(SO₂) x P(O₂)

Kp = (P)² / (2P) x (3P)

Kp = P² / 6

P = √(Kp x 6)

In conclusion,  the pressure of SO₃ will be equal to the square root of Kp times 6,  at equilibrium where Kp is the equilibrium constant for the reaction.

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The expression for the equilibrium constant (Kc) of the given reaction is, Kc = SO3²2/([SO2]²[O2])

At equilibrium, let the concentration of SO2 be ‘x.’ Thus, the equilibrium concentration of SO3 is ‘2x’ and that of O2 is also ‘x.’ Hence, substituting these values in the above expression, we get:

Kc = (2x)^2/[(x)^2(x)] = 4x^2/x^3 = 4/x.

We know that Kc = (P(SO3))^2/(P(SO2))^2(P(O2)). Here, the reaction is a gas-phase reaction at equilibrium. Hence, we can assume that the initial pressure of SO2, O2, and SO3 is ‘P atm.’ Thus, the equilibrium pressure of SO2 is ‘(1-x)P’ and that of O2 is also ‘(1-x)P.’ The equilibrium pressure of SO3 is ‘(2x)P.’

Substituting these values in the above expression, we get:

Kc = [(2xP)^2]/[(1-x)^2P^2.(1-x)P] = 4x^2P/(1-x)^2P^3 = 4x^2/(1-x)^2P^2

Given that the free energy of the reaction at 775 K is -2.8626 x 104 J.

ΔG° = - RTln(Kc)

-2.8626 x 10^4 = - (8.314 x 775)ln(4/x^2)/ln(1-x)^2P^2

Solving the above expression, we get the value of ‘x’ as 0.189.

Hence, the equilibrium pressure of SO2 is (1-x)P = (1-0.189)P = 0.811P.

Therefore, the equilibrium pressure required for 90% conversion of SO2

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Magnitude of average acceleration  \(a_{avg}\)=2.75 units

Average acceleration \(a_{avg}=\) \(2.265 i- 1.58j\)

We're given that \(s=\frac{t^2}{4}\)

And partice is at A at t=2 s and at B at t= 2.2s

Instantaneous velocity \(\frac{ds}{dt} =\frac{t}{2}\)

Velocity at A  (\(V_{a}\)) at 2s = \(\frac{t}{2}\) or  \(\frac{t}{2}Cos \frac{\pi}{3} i+ \frac{t}{2}Sin \frac{\pi}{3}j=\frac{i+\sqrt{3} j}{2}\)

Velocity at B  (\(V_{b}\)) at 2.2s =\(\frac{t}{2}\) or \(\frac{t}{2}Cos \frac{\pi}{6} i+ \frac{t}{2}Sin \frac{\pi}{6}j=\frac{\sqrt{3}i+j }{2}\)

Average acceleration = \(\frac{V_{b}-V{a}}{t}\) =\(2.265 i- 1.58j\)

magnitude = \(\sqrt{(2.265)^2- (1.58)^2}\) = \(2.75\)

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The method of bending segment that can be used to monitor each bend is a. an elapsed time method.

Using an elapsed time method to monitor each bend is an effective approach in bending segments. This method involves measuring the time it takes to complete each bend. By tracking the elapsed time, it becomes easier to ensure consistency and accuracy in the bending process.

When utilizing an elapsed time method, the operator starts a timer at the beginning of each bend and stops it once the bend is completed. This allows for precise measurement of the time taken for each bend. By establishing a benchmark time for a specific bend, operators can monitor subsequent bends and compare their times to the benchmark.

Any significant deviation from the benchmark can indicate a potential issue in the bending process, allowing for adjustments or corrections to be made promptly.

The elapsed time method is particularly useful when multiple bends need to be made consistently, such as in manufacturing or construction applications. It provides a reliable and objective measure to ensure that each bend meets the required specifications. This method can help reduce errors and variations in the bending process, resulting in improved overall quality and efficiency.

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On an engine with a separate fuel injector for each cylinder, cylinder power balance tests may involve measuring and comparing the power output of each individual cylinder by temporarily disabling the fuel injector for that specific cylinder. This helps identify any discrepancies in performance or potential issues within the engine.

On an engine with a separate fuel injector for each cylinder, cylinder power balance tests may involve checking the fuel injector function and fuel flow to each cylinder. The power balance test is a diagnostic procedure used to determine if each cylinder is producing the same amount of power as the other cylinders. This test is important in detecting any problems with individual cylinders, such as a faulty fuel injector, which can cause the engine to run poorly or even fail. By checking the fuel injector function and fuel flow to each cylinder, the technician can determine if any adjustments or repairs are necessary to ensure proper engine performance.

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Answer: Hooverville

Explanation:

Bud, not Buddy is a book about a ten years old boy who ran away from home where he stayed with his foster parents. He was treated unfairly and beaten.

He left home to seek a better living and hope that he will find his father as well. He met another orphan named Bugs and they decided to go to Hooverville so that they can get a train going to California.

Deep foundations are used when the surface soils are not capable of supporting the loads of a structure. Two common types of deep foundations are replacement and displacement foundations.

1. Replacement foundations:

Replacement foundations are created by removing the soil beneath a structure and replacing it with concrete or other materials. This creates a solid, stable foundation that can support the weight of the structure.

Illustration: The process of creating a replacement foundation begins by excavating the soil beneath the structure, leaving a large hole. The hole is then filled with concrete, which is allowed to cure and harden. The concrete provides a solid base for the structure to rest on, ensuring that it is stable and secure.

2. Displacement foundations:

Displacement foundations work by pushing soil aside as they are installed, creating a cavity in the ground that is then filled with concrete. These foundations are often used when soil conditions are too difficult to excavate or when a more efficient installation method is desired.

Illustration: The process of creating a displacement foundation involves driving a steel pile or tube into the ground. The pile is typically filled with concrete as it is being driven, creating a cavity in the soil. Once the pile has reached the desired depth, it is left in place, and the cavity is filled with concrete. This creates a solid, stable foundation that can support the weight of the structure.

In summary, both replacement and displacement deep foundations are effective methods for creating stable foundations for structures when the soil conditions are not suitable for shallow foundations. The choice of foundation type depends on the specific site conditions, load requirements, and project budget.

Answer:

What are you talking about? pls explain and then maybe I can help.

Answer:

A direct-current (DC) generator is a rotating machine that supplies an electrical output with unidirectional voltage and current.

Explanation:

Hope this helps

Answer:

what are the options available?

The should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.

Potential hazards refers to the active source for potential damage on a building, structure etc

It is important we know that the storage tanks are placed on a platform next to the building at the second-floor level but nothing beneath the tanks stands.

Hence, there should be no concerns about the space immediately below the tanks because there will be no damage to anything if any peril causes the tank to falls.

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Answer:

it’s IGS

Explanation:

because i read

Answer:

snap trap baits

Explanation: its kind of obvi, but i took the test and got it right.

Answer:

Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.

Explanation:

From Thermodynamics we remember that thermal efficiency of the ideal Otto cycle (\(\eta_{th}\)), dimensionless, is defined by the following formula:

\(\eta_{th} = 1-\frac{1}{r^{\gamma-1}}\) (Eq. 1)

Where:

\(r\) - Compression ratio, dimensionless.

\(\gamma\) - Specific heat ratio, dimensionless.

Please notice that specific heat ratio under cold air standard conditions is \(\gamma = 1.4\).

If we know that \(r = 8.2\) and \(\gamma = 1.4\), then thermal efficiency of the ideal Otto cycle is:

\(\eta_{th} = 1-\frac{1}{8.2^{1.4-1}}\)

\(\eta_{th} = 0.569\)

Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.

Answer:

Buyer is encouraged to obtain and read the booklet entitled "The Homeowners Guide to Earthquake Safety." In most cases a questionnaire within the booklet must be completed by Seller and the entire booklet given to the Buyer if the Property was built prior to 1960.

Answer:

The appropriate solution is "1481.76 N".

Explanation:

According to the question,

Mass,

m = 540 kg

Coefficient of static friction,

\(\mu_s\) = 0.28

Now,

The applied force will be:

⇒ \(F=\mu_s mg\)

By substituting the values, we get

       \(=0.28\times 540\times 9.8\)

       \(=1481.76 \ N\)

Answer:

A reactor is a piece of equipment in which the feedstock is converted to the desired product. Reactors are chosen such that they meet the requirements imposed by the reaction mechanisms, rate expressions, and the required production capacity. Other parameters that must be determined to choose the correct type of reactor are reaction heat, reaction rate constant, heat transfer coefficient, and reactor size. Reactors that are free of the effect of the macro-kinetic properties are classified as: batch isothermal perfectly stirred reactor, batch adiabatic perfectly stirred reactor, semi-batch perfectly stirred reactor, continuous isothermal perfectly stirred reactor flow reactor, continuous adiabatic perfectly stirred flow reactor, continuous isothermal plug flow reactor, and continuous adiabatic plug flow reactor.

Answer:

D would be correct because it maximizes it.

To design the circuit using a decoder and two external OR gates for the given To design the circuit using a decoder and two external OR gates for the given Boolean  functions F₁ and F₂, follow these steps:Start by analyzing each Boolean function and identifying the number of inputs and outputs.

F₁ has four inputs (A, B, C, D) and one output.F₂ also has four inputs (A, B, C, D) and one output.Use a 4-to-16 decoder, which has four inputs and sixteen outputs. Connect the inputs (A, B, C, D) to the decoder inputs.The decoder outputs will be sixteen individual lines. Assign each output line to a unique combination of input values according to the decoder's truth table.For F₁, connect the decoder outputs corresponding to the minterms ABC', A'BC', BC'D', and B'CD' to the inputs of the first OR gate.For F₂, connect the decoder outputs corresponding to the minterms A'B'C', ABC'D, and A'BCD to the inputs of the second OR gate.The outputs of the two OR gates will be the outputs for the Boolean functions F₁ and F₂, respectively.By following these steps and appropriately connecting the decoder outputs to the OR gates, you can design the combinational circuit that implements the given Boolean functions using a decoder and two external OR gates.

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(a) IS ≈ 2.5 × 10^(-16) A, V at 10% I = 0.568 V

(b) IS ≈ 3.9 × 10^(-15) A, V at 10% I = 0.607 V

(c) IS ≈ 3.9 × 10^(-15) A, V at 10% I = 0.607 V

(d) IS ≈ 2.5 × 10^(-16) A, V at 10% I = 0.568 V

To estimate IS, we can use the diode equation: I = IS * (e^(V/Vt) - 1), where Vt is the thermal voltage (approximately 26 mV at room temperature). By rearranging the equation and solving for IS, we can determine its value for each scenario.

To find the terminal voltage at 10% of the measured current, we can substitute the new current value into the diode equation and solve for V.

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Answer:

10

Explanation:

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

a) Air temperature at turbine exit

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) \((\frac{783.05-778.18}{800.13-778.18} )\) = 764.45K

b) The net work output

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

c) determine thermal efficiency

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

equation 1 becomes

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%