What is the force between a 0.004 C charge and a -0.02 C charge separated by a distance of 6 m
Answers
We can solve this problem applying "Coulomb's Law" which states-
\(\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ \)
\( \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)
Where-
q₁ and q₂ are the two cahrges.r is the distance between the charges.\(\sf \epsilon_{0} \) is the permittivity of free space.K is the Coulomb's Constant.k = 9×10⁹ Nm²/C²As per question, we are given that -
q₁= 0.004Cq₂= -0.02 CDistance,r = 6 mNow that required values are given, so we can substitute the values into the formula and solve for Force -
\( \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)
\( \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= 9\times 10^9 \times \dfrac{0.004\times -0.02 }{(6)^2}\\ \)
\( \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{0.00008}{36}\\ \)
\( \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 2.2\times 10^{-6}\\ \)
\( \:\:\:\:\:\:\:\longrightarrow \sf \underline{Force_{(air)} = -19800\:N}\\ \)
Therefore, the force between two charges is -19800 N.Related Questions
value of the refractive index of lens is 2.5 The curved surfaces are having The radius of curvature 10 cm and -12cm Out The focal length of the lens respectively find out the focal length of the lens?
Answers
Answer:
4
dhsfb ffhgchbvffffggcg
Answer:
16.5
Explanation:
A force of 2700 N is exerted on a car by a tow truck. The car accelerated at a rate 1.63 m/s? What is the mass of the car?
Round the the 2nd decimal places!
Answers
Answer:
1656.44 kgExplanation:
The mass of the car can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{2700}{1.63} \\ = 1656.4417...\)
We have the final answer as
1656.44 kgHope this helps you
if you added 2500 pounds and 2 tons what would be the total weight?4,500 pounds4 1/2 tons3/4 ton6500poundsi need some help
Answers
ANSWER:
6500 pounds
STEP-BY-STEP EXPLANATION:
To know the answer, we must first know the equivalence between tons and pounds, since it is the only way they can be added.
We know that 1 ton equals 2000 pounds, therefore:
\(\begin{gathered} 2\text{ tons}\cdot\frac{2000\text{ pounds}}{1\text{ ton}}=4000\text{ pounds} \\ \text{then, } \\ 2500\text{ pounds + 4000 pounds }=\text{ 6500 pounds} \end{gathered}\)Strong accountability, increased flexibility and local control of schools, challenging academic standards, and expanded accountability for English language learners are components of which federal law
Answers
The components such as strong accountability, increased flexibility and local control of schools, expanded accountability for English language learners are all part of the Every Student Succeeds Act (ESSA).
This federal law was passed in 2015 and replaced the No Child Left Behind Act. ESSA aims to give states more control over education policy while still holding them accountable for student achievement. The law emphasizes the importance of ensuring that all students have access to a high-quality education and sets guidelines for schools to achieve this goal. The Every Student Succeeds Act is a federal education law in the United States that was enacted in 2015, replacing the previous No Child Left Behind Act (NCLB). ESSA aims to provide states with greater flexibility and control over their education systems while maintaining accountability for student achievement. It emphasizes the importance of challenging academic standards, improved assessment systems, and increased accountability for schools and districts.
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8. The position of a particle at time \( t \) is represented by \( f(t)=t^{3}\left(1-2 t^{2}\right) \). Then the speed of the particle at \( t=1 \) is A) 1 B) \( -1 \) C) 7 D) \( -7 \)
Answers
The given function is f(t)=t3(1−2t2)The velocity of a particle is represented by the derivative of the position of the particle with respect to time. Thus, we need to find the derivative of the given function f(t) to find the velocity of the particle.
Let us differentiate f(t) by using the product and chain rule of differentiation:f(t)=t3(1−2t2)⇒ f′(t)=3t2(1−2t2)+t3(−4t)⇒ f′(t)=3t2−6t4−4t4The velocity of the particle at any given time is the absolute value of the derivative of the position function at that time. Thus, to find the velocity of the particle at t = 1, we will substitute t = 1 in the derivative function:f′(1)=3(1)2−6(1)4−4(1)4=3−6−4=−7.
Therefore, the speed of the particle at t = 1 is 7, which is option C).The definition of speed and velocity:Speed is the magnitude of velocity. It can be calculated as follows:|v|=|dx/dt|Where v is velocity, and x is the position of the object. The absolute value of the velocity of the particle is the speed of the particle.
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In order to use the Pythagorean theorem to find the magnitude of a resultant vector, which must be true regarding the
two initial vectors?
They form a 90 degree angle.
O They are equal in magnitude.
They have the same directions.
They are parallel to one another.
Answers
Answer:A Ed 2020
Explanation:
In order to use the Pythagorean theorem to find the magnitude of a resultant vector, two initial vectors must form a 90 degree angle.
What is Pythagorean theorem?The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between a right triangle's three sides in Euclidean geometry.
In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse.
Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.
Hence, two initial vectors must form a 90 degree angle.
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A 70kg bicyclist (including the bicycle) is pedaling right with a constant speed despite
experiencing a 50N drag. Neglect any friction impeding her motion.
What is the magnitude of the net force on the bicyclist?
How much force is her pedaling generating?
Answers
Answer:There are total four forces acting on the bicyclist namely, gravitational force, normal force, pushing force and air drag.
The magnitude of net force acting on the bicyclist is 165 N.
The required magnitude of force generated for the pedaling is of 225 N.
Given data:
The mass of bicyclist is, m = 75.0 kg.
The magnitude of acceleration is, .
The magnitude of drag force is, F = 60.0 N.
(1)
There are in total 4 forces acting on the bicyclist:
The gravitational force on the bicyclist, acting vertically downward, of magnitude , where m is the mass of the bicyclist and g is the acceleration due to gravityThe normal force exerted by the floor on the bicyclist and the bike, N, vertically upward, and of same magnitude as the gravitational forceThe force of push F", acting horizontally forward, given by the push exerted by the bicyclist on the pedalsThe air drag, F, of magnitude F = 60.0 N, acting horizontally backward, in the direction opposite to the motion of the bicyclist
(2)
The magnitude of net force acting on the bicyclist is given as,
Thus, the magnitude of net force acting on the bicyclist is 165 N.
(3)
We need to find the forward force of push, F'', which is actually the force generated during pedaling.
Then the expression for the forward pushing force F" is given as,
Thus, we can conclude that the force generated for the pedaling is of 225 N.
Explanation:
The magnitude of the net force on the bicyclist was 0 N.
Her pedaling is generating a force of 50 N in opposite of the drag force .
What is force?Force is defined in physics as: the push or pull on an object with mass that causes it to change velocity. Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.
A spring balance can be used to calculate force.
As the bicyclist (including the bicycle) is pedaling right with a constant speed, the magnitude of the net force on the bicyclist was = mass × acceleration
= 70 kg × 0 m/s²
= 0 N.
Again her pedaling is generating a force = drag force = 50 N in opposite of the drag force . So that, net force on it becomes zero.
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A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes an angle θ = 30.0 ∘ with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 12.5 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.
A: The block moves up an incline with constant speed. What is the total work Wtotal done on the block by all forces as the block moves a distance L = 3.80 m up the incline? Include only the work done after the block has started moving at constant speed, not the work needed to start the block moving from rest.
B :What is Wg , the work done on the block by the force of gravity w⃗ as the block moves a distance L = 3.80 m up the incline?
C: What is WF , the work done on the block by the applied force F⃗ as the block moves a distance L = 3.80 m up the incline?
D: What is WN , the work done on the block by the normal force as the block moves a distance L = 3.80 m up the inclined plane?
Answers
a ) The total work Wtotal done on the block by all forces = 0
b ) The work done on the block by the force of gravity = - 47.5 J
c ) The work done on the block by the applied force F = 47.5 N
a ) The total work Wtotal done on the block by all forces,
Since, only the work done after the block has started is considered, the total work done is the change in kinetic energy. Since, the block is moving at a constant speed there is no change in kinetic energy and so total work Wtotal done is zero.
b ) The work done on the block by the force of gravity,
Wg = Fg * h * cos θ
Fg = W = 25 N
sin 30 = h / 3.8
h = 1.9 m
Wg = 25 * 1.9 * cos 180
Wg = - 47.5 J
c ) The work done on the block by the applied force F,
WF = F * d * cos θ
WF = 12.5 * 3.8 * cos 0
WF = 47.5 N
d ) The work done on the block by the normal force,
Normal force acts perpendicular to the surface. The movement is towards the right side of the surface. So cos θ will be cos 90 which is equal to zero. So the work done will be zero.
Therefore,
a ) The total work Wtotal done on the block by all forces = 0
b ) The work done on the block by the force of gravity = - 47.5 J
c ) The work done on the block by the applied force F = 47.5 N
d ) The work done on the block by the normal force = 0
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A frictionless pulley has a rope going over it the tension in the rope is 1- n on one side and 12 n on the other side what is the angular acceleration of the pulley?
Answers
The angular acceleration of the frictionless pulley that has a rope going over it the tension in the rope is 10 n on one side and 12 n on the other side is 16.06 rad/s²
The mass of the solid cylinder, m = 0.83kg and radius, r = 0.30 m
The moment of inertia = 1/2 mr²
I = 1/2 (0.83) (0.30)²
I = 0.03735 kg m²
The net torque = F₁r - F₂r = 12(0.3) - 10(0.3) = 0.6 Nm
Torque = moment of inertia (I) × angular acceleration (α)
Substituting the values,
α = 16.06 rad/s²
Therefore, the angular acceleration of the pulley is 16.06 rad/s².
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(complete question)
A frictionless pulley which can be modeled as a 0.83kg solid cylinder with a 0.30 m radius, has a rope going over it the tension in the rope is 10 n on one side and 12 n on the other side what is the angular acceleration of the pulley?
What is point c called?
Answers
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4. A microchip lets computers process information very quickly,
This statement is true
because???
Answers
Microchips are specifically designed to make computers process information much faster, and make the devices a lot more portable.
Hello people ~
A bird sitting on a high power line:
(a) gets killed instantly
(b) gets a mild shock
(c) gets a fatal shock
(d) is not affected practically
Answers
Answer:
(d) is not affected practically
Explanation:
A bird sitting on a high power line is not affected practically.
This is because both of its legs are at the same potential, and current cannot flow through its body.
Answer:
option D
Explanation:
The bird sitting on a high power line but the bird is not touching ground by its body parts .
Hence there is no way electricity can pass through its body to earth
Thus it won't get any shock .
what is the instantaneous speed at 5
Answers
Answer: 2m/s
Explanation: I’m not 100% sure if this is right, BUT I TRIED LOL
Convert 9/4 hours into minutes
Answers
Am guessing;
9/4 × 60/1 =135
HELP!! will sulfur and oxygen atoms most likely form an ionic bond or covalent bond?
Answers
Answer: covalent bond
Explanation:
since sulfur and oxygen are both non-metals it forms a covalent bond
Most likely, sulfur and oxygen atoms create a covalent bond.
What is an ionic bond?Ionic bonding includes an electron transfer, in which one atom acquires an electron and the other loses an electron.
One of the ions formed has a negative charge (anion), whereas the other has a positive charge (cation)
The atoms link together to create a molecule because their opposing charges attract one other.
The type of chemical bond that involves the transfer of electrons between atoms will be an ionic bond.
Covalent bonds are chemical bonds that keep atoms of different elements together while sharing electrons.
Hence, most likely, sulfur and oxygen atoms create a covalent bond.
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HEY CAN ANYONE PLS PLS PLS ANSWER DIS!!!!!!!!!!!!!!!
Answers
pressure exerted on a surface depends on________
(a) force and pressure
(b) density and area
(c) height and density
(d)Area and density of liquid
Answers
Answer:
(a) Force and Pressure
Explanation:
Acc to the formula,
Force = Pressure/Area
Therefore it depends on force and pressure
If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
Answers
When Earth is closer to the sun, there will be hotter climate. A little movement that takes one closer to the sun could lead to a huge impact.
Impact of the distance of the sun
If I put a planet in orbits 2, 6, and 75, all planets will orbit the sun successfully if the sun's mass is 1x, and at least one planet will fall inside the habitable zone.
If I put a planet in orbits 84, 1, and 5, at least one of them will fall into the habitable zone if the sun's mass is 2x, and all planets will orbit the sun successfully.
If I put a planet in orbits 672 and 7, at least one of them will fall into the habitable zone if the sun's mass is 3x, and all planets will orbit the sun successfully.
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when you shine a very narrow beam of white light on a grating in a dark room, what do you see on the screen behind the slits?
A) A sharp image of the grating's slits
B) A pattern of white and dark spots of approximately equal width
C) a colored stipe that contains rainbow colors
D) a set of rainbow-colored stripes separated by dark regions
E) a white spot in the center and a set of rainbow-colored stripes on each side of it, separated by dark regions
Answers
When you shine a very narrow beam of white light on a grating in a dark room, you will see a pattern of white and dark spots of approximately equal width on the screen behind the slits.
What is diffraction?
The bending of waves around the edges of an obstacle or the spreading of waves beyond a slit opening is referred to as diffraction. The amount of diffraction that occurs in waves is influenced by the size of the obstacle or opening as well as the wavelength of the waves.
The pattern of light created by slits:
The pattern created by light passing through slits or holes that are smaller than the light's wavelength is referred to as diffraction. When light is shone on a diffraction grating, which is a collection of slits or holes with regularly spaced spacing, an interference pattern is generated on a screen behind the grating. The pattern is a series of bright and dark spots that are distributed evenly along the screen, with the brightest spots corresponding to areas where constructive interference is taking place, and the darkest spots corresponding to areas where destructive interference is taking place. The answer is B) A pattern of white and dark spots of approximately equal width.
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I NEED ANSWERS ASAP!!!!! Suppose you apply a force of 75 N to a 25-kg object. What will the acceleration of the object b? (Remember a=F/m)
225 m/s2
25 m/s2
3 m/s2
25N
Answers
Answer:
C. 3m/s^2
Explanation:
A negative charge of -0.00040 C and a positive charge of 0.00092 C are separated by 0.4 m. What is the force between the two charges?
Answers
Answer:
20654 N
Explanation:
Applying
F = kqq'/r²........... equation 1
Where F = Force between the charge, q = First charge, q' = second charge, r = distance betweeen the charge, k = coulomb's constant.
From the question,
Given: q = -0.0004 C, q' = 0.00092 C, r = 0.4 m
Constanr: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( -0.0004×0.00092×8.98×10⁹)/(0.4²)
F = (3.30464×10³)/0.16
F = (3304.64)/0.16
F = 20654 N
Hence the force between the charges is 20654 N
Using the graph, describe what is happening between 4 and 6 seconds. The object is moving away from the origin at a constant velocity. The object is not moving. The object is moving toward the origin at a constant velocity. The object is changing velocity.
Answers
The position in the graph between 4 - 6 seconds is the region of constant velocity.
What is constant velocity?The term constant velocity refers to the period in the graph when the velocity is not changing with time. As such, the graph is shown to be a flat portion at such a point.
Hence, it follows that the position in the graph between 4 - 6 seconds is the region of constant velocity.
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12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answers
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts
Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.
b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:
F = 400 + k * 30^2
F = 12000 N
Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.
c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:
P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts
Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.
Which of the following provide electrical resistance in a simple circuit? *
a battery
a wall outlet
a voltage source
a light bulb
Answers
Answer:
A light bulb
Explanation:
Sorry of it wrong
an object experiences buoyant force of 15.9 n when immersed in a fluid of density 917 kg/m^3. what is the volume of the object?
Answers
Answer:
0.00176
Explanation:
Credit to the person above.
Part 1: How many "pathways" are in this circuit?
Part 2: Therefore, is this a series or parallel circuit?
Part 1: Zero pathways
Part 1: One pathway
Part 1: Two pathways
Part 1: Three pathways
Part 1: Four pathways
Part 1: Five pathways
Part 2: Series circuit
Part 2: Parallel circuit
Answers
Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.
There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.
Part 2: Determining whether the circuit is series or parallel requires more information.
In a series circuit, components are connected in a single path, and the current flows through each component sequentially.
If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.
However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.
To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.
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a uniform magnetic field of magnitude 1.7 t is directed perpendicular to the plane of a rectangular loop having dimensions 15 cm by 16 cm. find the magnetic flux through the loop.
Answers
A uniform magnetic field of magnitude B exists when the magnetic field strength and direction are the same at all points within the region of interest.
Given: Uniform magnetic field of magnitude 1.7 T Dimension of the loop = 15 cm × 16 cm = 0.15 m × 0.16 m = 0.024 m²
Formula used: Φ = BA, where Φ is the magnetic flux, B is the magnitude of magnetic field and A is the area of the loop perpendicular to the magnetic field, here B is perpendicular to the loop.
Φ = BA
where,B = 1.7 T (Given)
A = 0.024 m² (Given)
Φ = 1.7 × 0.024Φ = 0.0408 Wb
Hence, the magnetic flux through the loop is 0.0408 Wb.
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Jesse has 85 oreos. Becky has 50 less oeros than Jesse. how many oreos does Billy have if he has 20 more oreos than Becky?
Answers
Answer: 20 Oreos
Explanation:
A plane flying into a headwind travels 2000 miles in 5 hours. The return flight along the same route with a tailwind takes 4 hours. Find the wind speed and the plane's speed.
Answers
The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.
Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.
When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:
P - W = 2000 miles / 5 hours
P - W = 400 miles per hour (mph) ---(Equation 1)
When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:
P + W = 2000 miles / 4 hours
P + W = 500 miles per hour (mph) ---(Equation 2)
Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.
Adding Equation 1 and Equation 2 together, we eliminate the variable W:
(P - W) + (P + W) = 400 mph + 500 mph
2P = 900 mph
P = 450 mph
Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:
450 mph - W = 400 mph
W = 450 mph - 400 mph
W = 50 mph
Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.
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a car has a velocity of 87 km/hr to the east. What is its displacement if it travels at this velocity for 30 minutes?
Answers
Answer:
displacement = 43.5 km
Explanation:
displacement = velocity * time taken
Here speed is 87 km/hr, which is given in km per hour
So we need to change the given time to hours:
60 minutes = 1 hours
30 minutes = 0.5 hours
Then using the formula lets find displacement:
displacement = velocity * time taken
displacement = 87 km/hr * 0.5
displacement = 43.5 km