What is the function of a comedone extractor?

Examples include weightlifting gloves, belts, wrist wraps, and other items that are together referred to as weightlifting gear.

No, using weightlifting hooks is not unethical. Weightlifting hooks can be a useful tool for lifters who need them if they are utilized properly and sparingly. Just be careful not to utilize them for exercises where they are not necessary.

Briefly, no. Given the aforementioned, we may conclude that sumo deadlifts are not simpler. We can also state without a doubt that sumo deadlifts are not cheating by referring to any powerlifting rulebook, which permits both conventional and sumo deadlifts in competition.

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The largest bandgap, often larger than 3 eV, is found in insulators due to the wide gap between the valence band and conduction band.

A substance that prevents free flow of electrical current is known as an electrical insulator. The electrons in the insulator's atoms are securely bonded and immobile. Electric current is easier to conduct through semiconductors and conductors made of other materials.

An insulator can be identified by its resistivity, which is higher than that of semiconductors or conductors. Non-metals are the most prevalent examples.

Because even insulators have minute amounts of mobile charges that can convey current, there is no such thing as a perfect insulator. Additionally, when a sufficiently high voltage is supplied to the point where the electric field separates electrons from the atoms, all insulators turn into electrically conductive materials. This is referred to as an insulator's breakdown voltage.

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Answer:

the first one is tire pressure gauge :)

Explanation:

Answer:

1) Corruption and weak governance

2) pandemic related economic slowdown 3) Weakened consumer spending (leading to rising unemployment and poverty)

4) Lower public investment and fiscal austerity

5) Security

B. Undeclared major. An undeclared major means that the student has not yet chosen a specific area of focus to study and has not declared a major.

What is an undeclared major?

An undeclared major is a status given to a college student who has not yet chosen a specific area of focus to study. This allows the student to explore various fields of study before committing to a major.

Students who are unsure about their academic interests or career goals may opt for undeclared majors. Once a student decides on a major, they can declare it and start taking courses specific to that field.

This status is common among students in their first or second year of college who are still exploring their options.

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Answer:

answer letter c

Explanation:

yun anserr hhehehe

Answer:

pakipic na lang po question nyo para masagot po

Explanation:

please po di ko masyado gets po e

it is simple the title name after all it is just asking your name

Answer:

Following are the solution to this question:

Explanation:

To copy 3.0 bits in 50 dollars or run at 50 dollars, it takes just 3.0 bits as well as other bits but masks, and 50 dollars.  

Instead of shifting the $ 50 by 3 bits to 6...3 bits of \(\$ \ 50, \$ \ 50,0*0000 0003,\) This procedure instead took place at $53 and $50  

AND \(\$ \ 50,\$ \ 50,0*0000 000f\), take 3..0  bits

SLL \(\$ \ 50, \$ \ 50,0*0000 0003,\)Shifts the bits to 6..3

O R \(\$ \ 53,\$ \ 53,\$ \ 50 ,\) coping to \(\$ \ 53\)

Answer:

As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.

Answer:

jwjehevrvbdbejd HB dbnwjsishrb t bxjwbkozkwnwn shxvbebhgvevhehjhr. jebn

Answer:

599.7 m

approximately 600 m

Explanation:

initial speed of the rocket = 0

net acceleration upwards = 7 m/s^2

the engine cuts out 10 sec after take off

maximum height reached = ?

we neglect air resistance

To get the velocity of the rocket at the point where the engine cuts off, we use the equation

v = u + at

where

v is the velocity at this point where the engine stops = ?

u is the initial velocity of the rocket from rest = 0 m/s

a is the net acceleration upwards = 7 m/s^2

t is the time the engine runs = 10 s

substituting, we have

v = 0 + (7 x 10)

v = 70 m/s

to get the distance from the ground to this point, we use the equation

\(v^{2}\) = \(u^{2}\) + 2as

where

v is the final velocity at the the height where the engine is cut out = 70 m/s

u is the initial speed at the ground = 0 m/s

a is the net acceleration on the rocket = 7 m/s^2

s is the distance from the ground to this point

substituting, we have

\(70^{2}\) = \(0^{2}\) + 2(7 x s)

4900 = 14s

s = 4900/14 = 350 m

After this point when the engine cuts out, the rocket experiences an acceleration proportional to the acceleration due to gravity 9.81 m/s^2 downwards, and slows down gradually before coming to a stop at the maximum height.

To get this height, we use the equation

\(v^{2}\) = \(u^{2}\) - 2gs   (the negative sign is due to the downward direction of the acceleration g)

where

v is the final velocity at the maximum height = 0 m/s (it comes to a stop)

u is the speed at the instance that the engine is cut out = 70 m/s

g is the acceleration due to gravity = 9.81 m/s^2

s is the distance from this point to the maximum height

substituting values, we have

\(0^{2}\) = \(70^{2}\) - 2(9.81 x s)

0 = 4900 - 19.62s

4900 = 19.62s

s = 4900/19.62 = 249.7 m

The maximum height that will be reached = 350 m + 249.7 m = 599.7 m

approximately 600 m

You were given the opportunity to be a project manager for Apple to work on a new product by Product control examples additionally consist of the branding and consumer conversation.

Good mission managers recognize and recognize their marketplace and the enterprise in their projects. They look at the opposition and compare alternatives. A desirable mission supervisor remains updated at the brand new developments withinside the enterprise in their mission, and they show off a stable knowledge and know-how in their enterprise.

Product control examples additionally consist of the branding and consumer conversation required to release a brand new product. Each product, in its nascent form, calls for right branding. This creates recognition approximately the product withinside the marketplace. Advertising and PR managing additionally fall beneath neath the umbrella of product control.

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Based on the present-worth criterion and a 14% MARR, Alternative A should be undertaken as it has a lower present worth compared to Alternative B.

Incremental To determine which alternative should be undertaken based on the present-worth criterion and a 14% MARR, we need to calculate the present worth of each alternative's costs.

For Alternative A:

Initial investment: -$29 million

Annual operating and maintenance costs: -$0.6 million per year for 25 years

Salvage value: +$0.8 million

For Alternative B:

Initial investment: -$13 million

Additional investments: -$17 million in the 10th year, -$10 million in the 15th year

Annual operating and maintenance costs: -$0.25 million for the first 10 years, -$0.35 million from the 11th to the 15th year, -$0.45 million for the final 10 years

Salvage value: +$1.2 million

Using the incremental cost approach, we calculate the present worth of costs for each alternative. We consider the difference in costs between the alternatives over their respective lifetimes.

For Alternative A:

Present worth = -29 + (0.6 * (1 - (1 + 0.14)^-25) / 0.14) + 0.8 / (1 + 0.14)^25

For Alternative B:

Present worth = -13 + (0.25 * (1 - (1 + 0.14)^-10) / 0.14) + (0.35 * (1 - (1 + 0.14)^-5) / 0.14) + (0.45 * (1 - (1 + 0.14)^-10) / 0.14) + 1.2 / (1 + 0.14)^25

Comparing the present worth values of the two alternatives, the alternative with the lower present worth should be undertaken.

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Explanation:

thermal expansion ∝L = (δL/δT)÷L ----(1)

δL = L∝L + δT ----(2)

we have δL = 12.5x10⁻⁶

length l = 200mm

δT = 115°c - 15°c = 100°c

putting these values into equation 1, we have

δL = 200*12.5X10⁻⁶x100

= 0.25 MM

L₂ = L + δ L

= 200 + 0.25

L₂ = 200.25mm

12.5X10⁻⁶ *115-15 * 20

= 0.025

20 +0.025

D₂ = 20.025

as this rod undergoes free expansion at 115°c, the stress on this rod would be = 0

Answer:

15psig

Explanation:

This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

\(x^2\) / Dt = constant

where D is constant

then

\(x^2\) / t = constant

\(x^2_1\) / t₁ = \(x^2_2\) / t₂

\(x^2_1\) t₂ = t₁\(x^2_2\)

t₂ = t₁\(x^2_2\) / \(x^2_1\)

t₂ = (\(x^2_2\) / \(x^2_1\))t₁

t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁

so we substitute

t₂ = \((\) 0.0049  / 0.0018  \()^2\) × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs

The maximum COP for a heat pump operating between 0°C and 20°C is  13.65.

d) The maximum level of the Coefficient of Performance (COP) for a heat pump operating between 0°C and 20°C would be the COP of a Carnot cycle.

The COP of a Carnot heat pump  formula is:

COP = Tc / (Th - Tc),

where:

Tc =the absolute temperature of the cold reservoir (0°C = 273 K)

Th = the absolute temperature of the hot reservoir (20°C = 293 K).

So putting in these values into the formula, we get:

COP = 273 K / (293 K - 273 K) = 273 K / 20 K

= 13.65.

UK Govt bans gas boilers in new homes by 2025 due to environment. Gas burning emits CO2 that causes global warming. Gov't bans natural gas boilers to cut emissions & move towards sustainable, low-carbon future. Heat pumps are a promising alternative for housing heating due to their ability to use different heat sources.

Two sources of low-grade heat for heat pumps are ground loops or heat exchangers that extract heat from the ground. Ground temp is stable year-round, reliable for low-grade heat. Air Heat: Heat pumps extract heat from low temperature air.

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The principal stresses are 9, 6, and -3, the maximum in-plane shear stress is 1.5, and the average normal stress is 4.

To determine the principal stresses, we need to find the eigenvalues of the stress tensor. The stress tensor for this problem can be represented by the following matrix:
[9  0  0]
[0  6  0]
[0  0 -3]
To find the eigenvalues, we need to solve the equation det(A-λI) = 0, where A is the stress tensor, I is the identity matrix, and λ is the eigenvalue. Solving this equation gives us the following eigenvalues:
λ1 = 9
λ2 = 6
λ3 = -3
The principal stresses are simply the eigenvalues, so the principal stresses for this problem are:
σ1 = 9
σ2 = 6
σ3 = -3
To find the maximum in-plane shear stress, we can use the formula:
τmax = (σ1 - σ2) / 2
Plugging in the values for σ1 and σ2 gives us: τmax = (9 - 6) / 2 = 1.5
Finally, to find the average normal stress, we can use the formula:
σavg = (σ1 + σ2 + σ3) / 3

Plugging in the values for σ1, σ2, and σ3 gives us:

σavg = (9 + 6 - 3) / 3 = 4

Therefore, the principal stresses are 9, 6, and -3, the maximum in-plane shear stress is 1.5, and the average normal stress is 4.

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Both technicians A and B are partially correct, because it's important to note that ABS is not a foolproof solution in all driving situations and should not be relied upon as a substitute for proper driving techniques and caution.Technician A is partially correct in that ABS (Anti-lock Braking System) can improve directional stability. Technician B is also partially correct in that ABS can improve braking performance on loose snow.

Both technicians are partially correct, but neither is entirely accurate.

Technician A is partially correct in that ABS (Anti-lock Braking System) can improve directional stability when the brakes are applied while turning a corner, especially on slippery or uneven road surfaces. The system can prevent the wheels from locking up and skidding, which can cause the vehicle to lose control. However, it's important to note that ABS does not necessarily guarantee superior directional stability in all situations, and the driver should still exercise caution and proper driving techniques when turning.

Technician B is also partially correct in that ABS can improve braking performance on loose snow, as the system can help prevent the wheels from locking up and losing traction. However, other factors such as tire type and condition, road gradient, and vehicle weight distribution can also impact braking performance on loose snow.

Therefore, both technicians are partially correct, but it's important to note that ABS is not a foolproof solution in all driving situations and should not be relied upon as a substitute for proper driving techniques and caution.

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Answer: hydraulic retention time,τ=28.67 hours

Explanation:

The hydraulic retention time  τ (tau),  is given as  The volume of the settling tank(V) divided by the influent flowrate(Q)

τ =V/Q

But Volume is not known  and is given as

Volume =  surface area  x depth of the tank

= 8000 ft² X 12 ft

= 96,000 ft³

Also, the influent flow rate is in mgd ( million gallons per day), we change  it to  ft³/sec so as to be in same unit with the volume in ft³

1 million gallons/day = 1.5472286365101 cubic feet/second

0.6mgd =  1.5472286365101 cubic feet/second  x 0.6

=0.93cubic feet/second

τ =V/Q

96,000 ft³/0.93 ft³/sec

τ=103,225.8 secs

changing to hours

103,225.8 /3600 =28.67 hours

The hydraulic retention time =28.67 hours

Answer:

Option 2, In seismic areas, the most crucial requirement for precast concrete is to tie elements together laterally

Explanation:

In seismic areas, the in-plane lateral  forces are very larger and hence in order to restrict the lateral movement governed by the lateral force, lateral ties are essential .

Specific design detailing such as interior and  perimeter ties in the floors causes diaphragm behavior and hence distribute the load evenly without any movement.

Hence, option 2 is correct

Answer:

fgfr

cg

Explanation:

xhrrhfdfghtrfgg

Answer:

A big hazard is falling, whether it be people or equipment. This is why OSHA requires that workers wear hard hats when doing certain jobs.

Answer: the design stage uncertainty is ±5.6 rpm

Explanation:

Given that;

machine with an analog display dial graduated in 5 revolutions per minute (rpm) increments; Q = 5 rpm

now lets calculate zero order uncertainty in this machine

⇒ ± 1/2Q =  1/2(5) = ± 2.5 rpm

given that accuracy is 0.1% of reading

0.1% of 5000 rmp = 0.1/100 × 5000 = 5 rpm

now the design stage uncertainty at 5000 rpm will be;

⇒ √((5)² + (2.5)²)

= √(25 + 6.25)

= √ 31.25

= ±5.59 ≈ ±5.6 rpm

Therefore the design stage uncertainty is ±5.6 rpm

Technician B is correct. To test fuses, both a voltmeter and a test light can be used. A voltmeter measures the voltage across the fuse, while a test light can be used to determine if there is continuity through the fuse.

A voltmeter is connected in parallel to the circuit being tested. This means that it is connected in a way that allows the voltmeter to measure the voltage without disrupting the flow of current.

On the other hand, a test light is also connected in parallel to the circuit. It consists of a light bulb and a probe. When the test light is connected to a circuit with continuity, the light bulb will light up, indicating that the fuse is functioning properly.

In conclusion, both a voltmeter and a test light can be used to test fuses. Technician B is correct in stating that a voltmeter and a test light are connected in parallel.

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kay flock accidents going crazy

Answer: B

Explanation:

trust yo, it's "be affordable"

The forwarding table will determine the appropriate link interface for the datagram with destination addresses in the following way:

Deine a datagram. What is its use?

A datagram is a fundamental transfer unit connected to a packet-switched network, or it can be described as a message delivered over the network whose arrival, arrival time, and content are not guaranteed. Header and payload portions are the typical organizational units of datagrams. A packet-switched network can use a datagram to communicate without establishing a connection.

A datagram is a self-contained message that is mostly used for wireless communication. Its source and destination addresses are listed in the header. A datagram is a short amount of data that can only be transferred once; unlike a packet, which is a connectionless protocol, a datagram cannot handle communication of any other data.

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Answer:

4 kWh

Explanation:

When a current I flows through a resistor R, the power dissipated across the resistor is

P = I2R

For time t, the energy consumed by the resistor is,

E = Pt = I2Rt

Calculation:

Given that, current (I) = 2 A

Resistor (R) = 100 ohm

Time (t) = 10 hours

Energy consumed (E) = 22 × 100 × 10 = 4 kWh