Answer:
(-2,9)
Step-by-step explanation:
-7 plus 5 and 5 plus 4 gives you the answer.
Answer:
The image point of (-7,5) after a translation right 5 units and up 4 units is (-2,9)
Step-by-step explanation:
So we need to know that x is left and right and y is up and down and the form is like this, (Also right is positive and left is negative and Up is positive while down is negative) (x,y) so for (-7,5) right 5 is (-2,5) since right is positive and up 4 is (-2,9) since 4 is positive. So the final answer is (-2,9)
What's 12+89+75+54+43+23=?
LOL!!!
Answer:
296
Step-by-step explanation:
Make 'P' the subject in the formula A = P(1+r)T
P=A/(1+r)T
Step-by-step explanation:
1) p(1+r)=A/T
2)P=A/(1+r)T
Answer:
P=A/(T+Tr)
Step-by-step explanation:
A = P(1+r)T
Multiply P and T
A=PT(1+r)
Clear the bracket by multiplying all bracketed terms by PT
A=PT+PTr
A=P(T+Tr)
Divide both sides by (T+Tr)
A/(T+Tr)=P(T+Tr)
P=A/(T+Tr)
4. What should be the minimum yield value of the key material for the key to smoothly transmit the torque of the shaft? However, the yield stress (Oc) of the shaft is 36kg/m². the diameter of the shalts 80mm, and the safety factor is 2. The dimensions of the key are 20x20x120mm De 2T
The minimum yield value of the key material should be determined based on the yield stress of the shaft, which is 36 kg/m², the dimensions of the key, and the safety factor of 2.
To ensure that the key smoothly transmits the torque of the shaft, it is essential to choose a key material with a minimum yield value that can withstand the applied forces without exceeding the yield stress of the shaft.
The dimensions of the key given are 20x20x120 mm. To calculate the torque transmitted by the key, we need to consider the dimensions and the applied forces. However, the specific values for the applied forces are not provided in the question.
The safety factor of 2 indicates that the material should have a yield strength at least twice the expected yield stress on the key. This ensures a sufficient margin of safety to account for potential variations in the applied forces and other factors.
To determine the minimum yield value of the key material, we would need additional information such as the expected torque or the applied forces. With that information, we could calculate the maximum stress on the key and compare it to the yield stress of the shaft, considering the safety factor.
Please note that without the specific values for the applied forces or torque, we cannot provide a precise answer regarding the minimum yield value of the key material.
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What is the effect on the graph of f(x) = x2 when it is transformed to
h(x) = 1/5x^2 +12?
O A. The graph of f(x) is horizontally compressed by a factor of 5 and
shifted 12 units up.
O B. The graph of f(x) is horizontally stretched by a factor of 5 and
shifted 12 units to the left.
C. The graph of f(x) is vertically compressed by a factor of 5 and
shifted 12 units up.
O D. The graph of f(x) is vertically compressed by a factor of 5 and
shifted 12 units to the left.
PREVIOUS
As per transformation of graph, h(x) = (\(\frac{1}{5}\))x² + 12 represents that the graph of f(x) is horizontally compressed by a factor of 5 and shifted up 12 units.
What is the transformation of a graph?"Graph transformation is the process by which an existing graph, or graphed equation, is modified to produce a variation of the proceeding graph. It's a common type of problem in algebra, specifically the modification of algebraic equations.
Given, the graph is f(x) = x².
We know that, at the time of horizontally compressing a graph we need to multiply it by a factor of (\(\frac{1}{a}\)).
Again, at the time of shifting a graph up we need to add a positive number of (b).
Therefore, a = 5 and b = 12.
Now, if we horizontally compress f(x) it by a factor of (\(\frac{1}{5}\)) then it be (\(\frac{1}{5}\))x².
Again, if we shifted up f(x) by 12 units, then it be (\(\frac{1}{5}\))x² + 12.
Therefore, h(x) = (\(\frac{1}{5}\))x² + 12 represents that the graph of f(x) is horizontally compressed by a factor of 5 and shifted 12 units up.
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8. Which pair of lines must be parallel?
108°
84
106
72°
t
A. p and r
B. q and s
C. p and s
D. q and r
P 9
r
S
Answer:
A) p||r
Step-by-step explanation:
Answer:
q || r
Step-by-step explanation:
4(х – 1) = 3х – 1
what is x
Answer:
x=3 hope I helped you! :)
HELP QUICK! Find the value of x such that the data set 31.7, 42.8, 26.4, and x has a mean of 35
Answer:
39.1
Step-by-step explanation:
((31.7+ 42.8+26.4+x))/(4)=35
There are four things that you add, so you have to divide by 4. Your end result is 35, so set your equation equal to 35.
4 times 35 is 140.
The stuff remaining is 100.9 + x = 140
140-100.9 is 39.1
find an interval, of length 1 and having integer endpoints, on which the function has a root.
In summary, to find an interval of length 1 and having integer endpoints on which the function has a root, we can use a trial-and-error method to identify intervals that satisfy the given criteria. The choice of interval may depend on the specific function and there may be multiple intervals that satisfy these conditions.
To find an interval on which the function has a root, we need to consider the function's behavior and identify any potential zero crossings. An interval of length 1 with integer endpoints can be represented as [a, a+1] where a is an integer.
One approach to finding a root is to plot the function and visually identify where it crosses the x-axis. Another approach is to use algebra and solve for when the function equals zero. However, without knowing the specific function, we cannot use these methods.
Instead, we can use a trial-and-error method to identify an interval that satisfies the given criteria. For example, we can start by choosing an integer a and evaluating the function at a and a+1. If the function has opposite signs at these two endpoints, then by the Intermediate Value Theorem, the function must have at least one root in the interval [a, a+1].
We can continue this process until we find an interval that satisfies the given criteria. Note that there may be multiple intervals that satisfy these conditions, and the choice of interval may depend on the specific function.
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if p = 2-5 and q = 8x3 find 3p-q
Answer:
3p - q = 3(2-5) - (8x3) = -9 - 24 = -33. Therefore, 3p-q=-33.
HELP ME!!!!!!!!!! ANSWER 2-5
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2. (4,0)
3. (6,1)
4. (-1,-3)
5. (2,0)
6. (-3,0)
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HOPE IT HELPS
PLEASE MARK ME BRAINLIEST ☺️
The x-intercepts of a parabola are 5 and -7.
What is the equation of the axis of symmetry?
a) x = 12
b) x = - 1
c) x= -2
d) x = 1
e) x =2
Answer:
b) x = - 1
Step-by-step explanation:
You want the equation of the axis of symmetry for a parabola with x-intercepts of 5 and -7.
SymmetryThe given x-intercepts are symmetrical about the axis of symmetry, so its x-intercept is the midpoint of the segment between (5, 0) and (-7, 0).
That midpoint is ...
((5, 0) +(-7, 0))/2 = (-2, 0)/2 = (-1, 0)
The vertical line through this point has equation ...
x = -1
A shark is cruising at a depth of 32.9 meters below sea level. If it
ascends 15.5 meters, what is the shark's new depth?
a seamstress has 35 of a box of buttons left in her kit. after doing some mending, she used 14 of another box. if both boxes contained 200 buttons when they were originally bought, how many buttons did the seamstress use for her recent mending?
Therefore, the seamstress used 200 + 200 - 179 = 221 buttons for her recent mending.
As per the data given in the above question are as bellow,
The data provided are as bellow,
There are 35 buttons remaining in a package in the equipment of a seamstress.
She repaired some things and used 14 of another box.
How many buttons did the seamstress use for her most recent repair if both boxes initially had 200 buttons?
The seamstress had
200 - 35 = 165 buttons
left in her first box after using some of them.
So she had
165 + 14 = 179 buttons in total.
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Grade 7 Unit 4 District Assessment 2020-21 Question: 1 Jacob saw a model of a building that will be built in his city. The model has a height of 40 centimeters and will be built to a scale of 1:50. What is the actual height of the building? (1 m = 100 cm)
Answer:
123334
Step-by-step explanation:
Please help! I’ll give brainliest!!!
HELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLO
Answer:
hi
Step-by-step explanation:
what’s the answer for this question
Answer:
1pi or approximately 3.14
area of a Circle is: (pi)(r)^2
so of you plug the formula in for this equation you get
(pi)(1)^2= 1pi or approximately 3.14 which ever your teacher prefers.
question 2. the company wishes to adjust the dispenser so that the probability that a new cup will overflow is .006. at what value should the mean amount dispensed by the machine be set to satisfy this wish? (use 2 decimal places in your answer and use 0.39 ounces for the standard deviation). ounce
The mean amount dispensed by the machine should be set to approximately 0.50 ounces in order to achieve a desired probability of 0.006 for a cup overflowing.
Identify the given information:
Desired probability of cup overflowing (P) = 0.006
Standard deviation (σ) = 0.39 ounces
Use the Z-score formula:
Z = (X - μ) / σ
Rearrange the formula to solve for the mean (μ):
X = Z * σ + μ
Look up the Z-score value that corresponds to a cumulative probability of 0.006 in a standard normal distribution table. In this case, the Z-score is approximately -2.69.
Substitute the values into the formula:
μ = Z * σ + X
μ = -2.69 * 0.39 + X
Solve the equation P(X > X) = 0.006 using the given probability of overflowing.
Using a statistical software or calculator, find that X is approximately 0.50 ounces.
Therefore, based on the calculations, the mean amount that the dispenser should be set to in order to achieve a desired probability of 0.006 for a cup overflowing is approximately 0.50 ounces. This means that by setting the mean amount to 0.50 ounces, the probability of a cup overflowing will be approximately 0.006 or 0.6%.
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write each equation in vertex form. then identify the vertex, axis of symmetry and direction of opening. y=x^2+8x+\:18 , y=-\:x^2\:\:12x\:-\:36 and y=2x^2\:+\:12x\:+\:13
The equation in vertex form is y = 2(x+3)² + 1. The vertex is (-3,1), the axis of symmetry is x = -3, and the direction of opening is upwards.
The vertex form of the equation is y = a(x-h)^2 + k, where (h, k) is the vertex. The axis of symmetry is x = h, and the direction of opening is determined by the value of a.
Using this formula, let us write each equation in vertex form and then identify the vertex, axis of symmetry, and direction of opening.
1. y = x² + 8x + 18
To write this equation in vertex form, we need to complete the square. y = x² + 8x + 18 is equivalent to y = (x+4)² - 2. Therefore, the equation in vertex form is y = (x+4)² - 2.
The vertex is (-4,-2), the axis of symmetry is x = -4, and the direction of opening is upwards.2
. y = -x² - 12x - 36To write this equation in vertex form, we need to complete the square. y = -x² - 12x - 36 is equivalent to y = -(x+6)² - 12. Therefore, the equation in vertex form is y = -(x+6)² - 12.
The vertex is (-6,-12), the axis of symmetry is x = -6, and the direction of opening is downwards.3. y = 2x² + 12x + 13To write this equation in vertex form, we need to complete the square. y = 2x² + 12x + 13 is equivalent to y = 2(x+3)² + 1.
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Felipe calculated that he uses about 545 gallons of fuel each year. His car's owner's manual says that it is approved to use regular fuel. How much money can he save each year by switching from premium fuel, at $4.59 per gallon, to regular fuel at $4.18 per gallon?
$0.41
$2,501.55
$223.45
$2,278.10
$4,779.65
Answer:
$223.45
Step-by-step explanation:
premium fuel: 4.59 x 545
= 2501.55
regular fuel: 4.18 x 545
=2278.1
2501.55-2278.1 = 223.45
-3x+y=-3
How do I write this in y=Mx+b form?
Answer:
y=3x-3
Step-by-step explanation:
all you need to do is get the -3x to the other side of the equal sign
There are 15 boys in a class with 14 girls. Find the probability of selecting a girl then a boy
Answer:
14/29
Step-by-step explanation:
Answer:
total numbers of class = 15+14 =29
and number of girls in the class is 14girls
while probability = number of possible outcome
number of required outcome
therefore 14/29 is the probability of selecting
a girl than a boy
A biased coin is tossed n times, and heads shows with probability p on each toss. A run is a sequence of throws which result in the same outcome, so that, for example, the sequence HHTHTIH contains five runs. Show that the expected number of runs is 1 + 2(n 1) p ( 1 p). Find the variance of the number of runs
The expression is \(Var(X) = 2n[p(1-p) - (n-1)p^2(1-p)^2]\). The probability of this happening is either p(1-p) or (1-p)p, depending on whether the (i-1)-th toss was heads or tails.
Let's start by defining some notation. Let X be the random variable representing the number of runs in n tosses of the coin, and let Xi be the indicator variable that is 1 if the i-th toss is the start of a new run, and 0 otherwise. Then we have:
\(X = X1 + X2 + ... + Xn\)
where each Xi is independent.
Now, let's calculate E(Xi). A new run starts at the i-th toss if and only if the i-th toss is not the same as the (i-1)-th toss. The probability of this happening is either p(1-p) or (1-p)p, depending on whether the (i-1)-th toss was heads or tails. So we have:
\(E(Xi) = p(1-p) + (1-p)p = 2p(1-p)\)
By linearity of expectation, we have:
\(E(X) = E(X1 + X2 + ... + Xn) = E(X1) + E(X2) + ... + E(Xn) = n * 2p(1-p) = 2n(p-p^2)\)
Therefore, the expected number of runs is 1 + 2(n-1)p(1-p).
To find the variance, we can use the formula Var(X) = E(X^2) - [E(X)]^2. We already know E(X), so let's calculate E(X^2):
\(X^2 = (X1 + X2 + ... + Xn)^2\)
\(= X1^2 + X2^2 + ... + Xn^2 + 2(X1X2 + X1X3 + ... + X(n-1)Xn)\)
The expectation of each Xi^2 is the same as its probability P(Xi=1), which we already know to be 2p(1-p). For the cross terms, we have:
\(E(XiXj) = P(Xi=1, Xj=1)\)
\(= P(Xi=1) * P(Xj=1 | Xi=1)\)
\(= 2p(1-p) * (1-p) if |i-j| = 1\)
\(= 2p(1-p) * p if |i-j| > 1\)
Therefore,
\(E(X^2) = n2p(1-p) + 2(n-1)2p(1-p)(1-p) + 2*sum[1 < =i < j < =n]{2p(1-p)p}\)
\(= n2p(1-p) + 2(n-1)p(1-p)(2-2p)\)
Now we can find Var(X):
\(Var(X) = E(X^2) - [E(X)]^2\)
\(= n*2p(1-p) + 2(n-1)p(1-p)(2-2p) - [2n(p-p^2)]^2\)
Simplifying this expression gives the final answer:
\(Var(X) = 2n[p(1-p) - (n-1)p^2(1-p)^2]\)
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A triangle has two sides of lengths 6 and 9. What value could the length of
the third side be? Check all that apply.
OA. 7
B. 2
C. 4
OD. 15
□E. 10
O F. 12
SUBMIT
B. 2 and OD. 15 are not possible lengths for the third side of the triangle.
To determine the possible values for the length of the third side of a triangle, we need to consider the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Given that two sides have lengths 6 and 9, we can analyze the possibilities:
6 + 9 > x
x > 15 - The sum of the two known sides is greater than any possible third side.
6 + x > 9
x > 3 - The length of the unknown side must be greater than the difference between the two known sides.
9 + x > 6
x > -3 - Since the length of a side cannot be negative, this inequality is always satisfied.
Based on the analysis, the possible values for the length of the third side are:
A. 7
C. 4
□E. 10
O F. 12
B. 2 and OD. 15 are not possible lengths for the third side of the triangle.
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in a school, 56% of the 850 students are girls. work out the number of girls in the school
Answer:
476 girls
Step-by-step explanation:
total students : 850
56% of 850 = 476
Which is equal to 1/58^8 ? a.58^-8 b.-1/58^-8 c.58^8 d.1/(58)^-8
a) 58^-8 is the same as 1/58^8. we can also simplify the expression by applying the rule for negative exponents to the entire fraction.
How to evaluate this expression ?To evaluate this expression, we can use the rule that any number raised to a negative exponent is equal to the reciprocal of the same number raised to the same positive exponent. In other words, x^-n = 1/x^n.
Applying this rule to the expression 1/58^8, we get:
1/58^8 = 1/(58^8) = 58^-8
Therefore, the correct answer is 58^-8.
It is important to note that the exponentiation operator (^) has higher precedence than the division operator (/), so we need to use parentheses to indicate that the exponent should be applied to the entire denominator before the division is performed. In this case, we can also simplify the expression by applying the rule for negative exponents to the entire fraction:
1/58^8 = (1/58)^8 = 58^-8
This simplification shows that the correct answer is still 58^-8.
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What is the volume of the solid figure?
A rectangular prism on top of another longer rectangular prism. The top prism measures 5 inches by 5 inches by 5 inches. The bottom prism measures 20 inches by 5 inches by 5 inches.
Answer:
The volume of the solid figure is 625 cubic inches.
Step-by-step explanation:
The volume of a rectangular prism is found by multiplying its length, width, and height.
For the top prism, the volume is:
5 inches x 5 inches x 5 inches = 125 cubic inches
For the bottom prism, the volume is:
20 inches x 5 inches x 5 inches = 500 cubic inches
To find the total volume of the solid figure, we need to add the volumes of the two prisms together:
Total volume = 125 cubic inches + 500 cubic inches = 625 cubic inches
Therefore, the volume of the solid figure is 625 cubic inches.
Regenerate response
h(x)=6x Find x if h(x) = 60
Answer:
x=10
Step-by-step explanation:
h(x)= 6x= 60
6x/6= 60/6
x= 10
the product of a rational and irrational number is always
The product of a rational and an irrational number can be either rational or irrational, depending on the specific numbers involved.
To illustrate this, let's consider an example:
Let's say we have the rational number 2/3 and the irrational number √2.
Their product would be (2/3) * √2.
In this case, the product is irrational.
The square root of 2 is an irrational number, and when multiplied by a rational number, the result remains irrational.
However, it's also possible to have a product of a rational and an irrational number that is rational. For example, if we consider the rational number 1/2 and the irrational number √4, their product would be (1/2) * 2, which equals 1. In this case, the product is a rational number.
Therefore, we cannot make a definitive statement that the product of a rational and an irrational number is always rational or always irrational. It depends on the specific numbers involved in the multiplication.
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When studying the formation of mountain ranges, geologists estimate the amount of work required to lift a mountain from sea level. Consider a mountain that is essentially in the shape of a right circular cone. Suppose that the weight density of the material in the vicinity of a point P is g(P) and the height is h(P).
(a) Find a definite integral that represents the total work done in forming the mountain.
(b) Assume that Mount Fuji in Japan is in the shape of a right circular cone with radius 62,000 ft, height 12,400 ft, and density a constant 200 lb/ft3. How much work was done in forming Mount Fuji if the land was initially at sea level?
a, The definite integral that represents the total work done is ∫∫∫R g(P) * h(P) dV. b, The work done in forming Mount Fuji, assuming a right circular cone shape with given dimensions and a constant density of 200 lb/ft³, is approximately 8.216 × 10¹³ lb·ft.
(a) To find the definite integral that represents the total work done in forming the mountain, we need to integrate the product of the weight density and the height over the volume of the mountain.
Let's denote the weight density as g(P) and the height as h(P), and assume the mountain is formed within a region R. The total work done in forming the mountain can be expressed as
Work = ∫∫∫R g(P) * h(P) dV
Here, dV represents an infinitesimal volume element within the region R.
(b) Let's calculate the work done in forming Mount Fuji using the given information. We have
Radius of the cone, r = 62,000 ft
Height of the cone, h = 12,400 ft
Density of the material, g(P) = 200 lb/ft³
The region R is the volume of the cone formed by Mount Fuji. The volume of a right circular cone is given by
V = (1/3) * π * r² * h
Substituting the values, we get:
V = (1/3) * π * (62,000 ft)² * (12,400 ft)
Now, we can calculate the work done using the definite integral
Work = ∫∫∫R g(P) * h(P) dV
= ∫∫∫R (200 lb/ft³) * h(P) dV
= (200 lb/ft³) * ∫∫∫R h(P) dV
Since the density is constant, we can pull it out of the integral:
Work = (200 lb/ft³) * ∫∫∫R h(P) dV
= (200 lb/ft³) * V
Substituting the value of V, we get:
Work = (200 lb/ft³) * (1/3) * π * (62,000 ft)² * (12,400 ft)
Calculating this expression, we get:
Work = (200 lb/ft³) * (1/3) * π * (62,000 ft)² * (12,400 ft)
≈ 8.216 × 10¹³ lb·ft
Therefore, the work done in forming Mount Fuji, assuming the given values and the land initially at sea level, is approximately 8.216 × 10¹³ pound-feet (lb·ft).
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