What is the lateral area of the cone to the nearest whole number? The figure is not drawn to scale.
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Captionless Image
34311 m^2
18918 m^2
15394 m^2
28742 m^2

Answer:

x = 46°

Step-by-step explanation:

Angles on a straight line sum to 180°.

Therefore, the interior angle of the triangle that forms a linear pair with the exterior angle marked 130° is:

⇒ 180° - 130° = 50°

The interior angle of the triangle that forms a linear pair with the exterior angle marked 96° is:

⇒ 180° - 96° = 84°

The interior angles of a triangle sum to 180°. Therefore:

⇒ 50° + 84° + x = 180°

⇒ 134° + x = 180°

⇒ 134° + x - 134° = 180° - 134°

⇒ x = 46°

Therefore, the size of angle x is 46°.

Answer:

what the hecker is that.

okay so your simplifying it, 12? i think.

Answer:

49

Step-by-step explanation:70 x 0.7 = 49

Answer:

30 gingerbread cookies.

Step-by-step explanation.

100 x 0.3 = 30

Answer:

(15/4)4^x

Step-by-step explanation:

Substituting the x and y values of the first point, we get:

y = ab

60 = ab^(2)

Substituting the x and y values of the second point, we get:

y = ab

960 = ab^(4)

Now we can solve for a and b by eliminating one of the variables. One way to do this is to divide the second equation by the first equation:

960/60 = (ab^(4))/(ab^(2))

16 = b^(2)

Taking the square root of both sides, we get:

b = ±4

Since an exponential function can only have positive values for b, we choose b = 4. Now we can solve for a by substituting b = 4 into one of the original equations:

60 = a(4^(2))

60 = 16a

a = 60/16

a = 15/4

Therefore, the values of a and b are a = 15/4 and b = 4, and the exponential function is y = (15/4)4^x.

Answer:

6370 is the answer Hope this helps.

Answer:

6.37 x 10^3 in standard form is: 6370x

60 percent of the sandwiches were not pastrami with work showing.

What do you mean by percentage?

percentage, a comparative figure denoting one-hundredth of any quantity. One percent (symbolized as 1%), being the hundredth component, is represented as 100 percent, while 200 percent signifies twice the amount specified, percentage.

The total number of sandwiches sold by the deli owner is 90

total number of pastrami is 36.

total number of pastrami is 54.

so, the percentage of sandwiches sold that were NOT pastrami is,(54/90)×100

Hence, 60 percent pastrami with work showing.

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A firm experiences increasing returns to scale if inputs are doubled and output more than doubles.

When the firm's output grows at a faster rate than the growth in inputs, increasing returns to scale result. In this case, the company experiences economies of scale, which makes it more effective as it grows its production.

The firm is able to boost productivity and efficiency as it expands its scale of operations if inputs are doubled and output more than doubles.

This can be ascribed to a number of things, including specialisation, labour division, the use of capital-intensive technology, discounts for bulk purchases, and spreading fixed costs over a higher output. Lower average costs per unit of output result in higher profitability and competitiveness for the company.

The firm gains a number of benefits from growing returns to scale. First off, it lets the company to benefit from cost savings brought about by economies of scale, allowing it to manufacture goods or services for less money per unit. This may enable more competitive pricing on the market or result in larger profit margins.

Second, raising returns to scale can result in better operational effectiveness and resource utilisation. As the company grows in size, it will be able to use resources more wisely and profit from production volume-related synergies.market prices that are competitive.

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Janice will spend $3.00 on 3 pounds of potatoes. If she only has $3.00, she will spend it all on potatoes and purchase 3 pounds of potatoes.

a) 3 pounds of potatoes

b) 3 pounds of potatoes

A pound is defined as 16 ounces, 7,000 grains (or 0.45359237 kg) of avoirdupois weight and 12 ounces, 5,760 grains (or 0.37324171216 kg) of troy and apothecaries' weight. The initials "lb" come from the Latin word "libra," which was the Roman equivalent of the modern "pound."

Janice can get potatoes once the price is set. As a result, she will buy those potatoes whose value is less than her willingness to pay. Her disposition to pay is what she feels the pound of potatoes is "worth". If the worth of the primary, second, and third pounds exceeds the price of the potato ($1.50, $1.14, $1.05 > $1.00), Janice will not purchase these because the worth is less than the price. (0.30 USD 1.00 USD).

Thus, Janice will spend $3.00 on 3 pounds of potatoes. If she only has $3.00, she will spend it all on potatoes and purchase 3 pounds of potatoes.

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Given function:

a = 3

As a is positive the parabola opens upward. It has a minimum value.

To find the minimum:

1. Find the value of x where the parabola has the minimum value, use the next formula:

2. Use the value of x where the function has minimum value (step 1) to find the value of the function:

Answer:

1,000 lightbulbs that day were tested

Step-by-step explanation:

It would take about 36 minutes for the soup to cool to 100°F.

The rate at which an object's temperature changes when it comes into contact with a medium that has a different temperature is described by Newton's law of cooling. According to this, an object's rate of heat uptake or loss is directly correlated with the temperature difference between the object and its surroundings.

We know that;

T(t) = T(s) + (T(o) - T(s))\(e^-kt\)

130= 50 + (190 - 50)\(e^-20k\)

130 - 50 =  (190 - 50)\(e^-20k\)

80 =  (190 - 50)\(e^-20k\)

80/140 = \(e^-20k\)

0.57 = \(e^-20k\)

ln(0.57) = ln \(e^-20k\)

-0.56 = - 20 k

k = 0.028

Then the time taken to cool to  100°F

100 = 50 +  (190 - 50)\(e^-0.028t\)

50/140 =\(e^-0.028t\)

0.36 = \(e^-0.028t\)

t = ln(0.36)/-0.028

t = 36 minutes

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iam thick look that's all imma say

The abiotic factors are Sunlight, oxygen, Carbon Dioxide, Nitrogen, Clouds, Rain, Desert, Snow, Plastic, Dirt and Rock

Abiotic factors are non-living physical and chemical elements and conditions in the environment that influence the survival and growth of living organisms. The abiotic factors in the given list are:

Sunlight: The light energy from the sun that drives photosynthesis and provides energy to living organisms.

Oxygen: A colorless, odorless, tasteless gas essential for respiration in many organisms.

Carbon Dioxide: A colorless, odorless gas that is produced by respiration, combustion and decay of organic material and is used by plants during photosynthesis.

Nitrogen: An odorless, tasteless gas that makes up a major component of the Earth's atmosphere and is essential for plant growth as a component of amino acids and nucleic acids.

Clouds: A visible mass of water droplets or ice crystals suspended in the atmosphere.

Rain: Precipitation that falls from clouds as water droplets.

Desert: An area characterized by little rainfall and high temperature, often with limited vegetation.

Snow: Precipitation that falls from clouds as ice crystals.

Plastic: A synthetic or semi-synthetic material made from various organic polymers.

Dirt: The naturally occurring material that covers the surface of the earth, made up of organic and inorganic matter.

Rock: A naturally occurring solid composed of one or more minerals.

These are all abiotic factors, while the other items in the list are biotic factors, which are living or once-living elements in the environment.

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the answer is A

it is not B or C

Ignatius of Loyola, the Spanish priest and theologian who founded the Society of Jesus (Jesuits) in the 16th century, focused on several key issues during the period of the Counter-Reformation.

These issues can be broadly categorized into spiritual, educational, and institutional reforms.

Spiritual Reforms: Ignatius emphasized the importance of personal piety and spiritual discipline. He promoted the practice of spiritual exercises, including meditation, prayer, and self-examination, to cultivate a deep and intimate relationship with God. Ignatius encouraged individuals to reflect on their sins and seek forgiveness through confession and penance.

Educational Reforms: Ignatius recognized the power of education in shaping individuals and society. He established schools and universities to provide a comprehensive education that combined intellectual rigor with spiritual formation. The Jesuits placed great emphasis on academic excellence, encouraging critical thinking, the pursuit of knowledge, and the integration of faith and reason.

Pastoral Reforms: Ignatius focused on improving the quality of pastoral care and religious instruction. He trained his followers to be skilled preachers and spiritual directors, equipping them to guide and support individuals in their spiritual journey. Ignatius also emphasized the importance of catechesis, ensuring that people received proper religious education and understood the teachings of the Catholic Church.

Missionary Work: Ignatius and the Jesuits had a strong missionary zeal. They undertook extensive missionary endeavors, particularly in newly discovered territories during the Age of Exploration. They sought to bring Christianity to non-Christian lands and convert indigenous populations to Catholicism. The Jesuits established missions, schools, and hospitals in various parts of the world, playing a significant role in spreading Catholicism.

Overall, Ignatius of Loyola's reforms aimed to strengthen and revitalize the Catholic Church in response to the challenges posed by the Protestant Reformation. His focus on personal spirituality, education, pastoral care, and missionary work contributed to the renewal and expansion of the Catholic Church during the Counter-Reformation.

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The discriminant of this equation is 261

It has two solutions are they are -0.76 and 0.86

From the question, we have the following parameters that can be used in our computation:

5n^2-n=13

Rewrite as

5n^2-n - 13 = 0

The discriminant is

D = b^2 - 4ac

So, we have

D = (-1)^2 - 4 * 5 * -13

Evaluate

D = 261

In (a), we have the discriminant to be greater than 1

This means that it has two solutions

We have

5n^2-n - 13 = 0

Using the quadratic formula, the solution is

x = (-b ± √D)/4a

So, we have

x = (1 ± √261)/4 * 5

x = (1 ± 16.2)/20

So, we have

x = (1 - 16.2)/20 and (1 + 16.2)/20

Evaluate

x = -0.76 and 0.86

Hence, the solutions are -0.76 and 0.86

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The probability that a voter is either female or Democrat is 0.64 or 64%.

To calculate the probability, we need to determine the number of individuals who are either female or Democrat and divide it by the total number of voters.

From the table, we can see that there are 405 females and 253 Democrats. However, we need to be careful not to double-count the individuals who fall into both categories.

To find the number of individuals who are either female or Democrat, we add the number of females (405) and the number of Democrats (253), and then subtract the number of individuals who are both female and Democrat (150).

So, the number of individuals who are either female or Democrat is 405 + 253 - 150 = 508.

Now, we divide this number by the total number of voters, which is 802, to get the probability: 508 / 802 ≈ 0.64 or 64%.

Therefore, the probability that a voter is either female or Democrat is approximately 0.64 or 64%.

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The given undirected, weighted graph consists of various nodes connected by edges with corresponding weights. To draw the graph, we represent each node as a vertex and connect them with edges labeled with their respective weights.

To find the minimal spanning tree (MST) on the 5 by 5 square of nodes, we need to select the subset of edges that connect all the nodes with the minimum total weight.

a) Drawing the weighted graph: Based on the given edge list, we draw the graph by representing each node as a vertex and connecting them with edges labeled with their corresponding weights. We consider the nodes A, B, C, D, ..., and draw the edges with the respective weights between the corresponding vertices.

b) Drawing the minimal spanning tree (MST): To find the MST on the 5 by 5 square of nodes, we need to select the subset of edges that connect all the nodes with the minimum total weight. Starting from any node, we choose the edge with the minimum weight to connect it to another node. We continue this process, ensuring that we do not form cycles and include all the nodes until we have connected all the nodes with the minimum total weight.

By considering the weights and following the process described above, we draw the minimal spanning tree on the 5 by 5 square of nodes, connecting them with the minimum weight edges.

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Answer:

x=8      

Step-by-step explanation:

Answer:

divide

Step-by-step explanation:

the symbol means divide like for instance 1/2 you would divide 1 divided by 2 to get the decimal

Answer:

\(\dfrac{7+x}{(1+x)(1+x^2)}\equiv \dfrac{3}{1+x}-\dfrac{3x-4}{1+x^2}\)

Step-by-step explanation:

As the denominator has a linear factor and irreducible quadratic factor, the partial fraction form is:

\(\boxed{\dfrac{N(x)}{(ax+b)(x^2+bx+c)} \equiv \dfrac{A}{ax+b}+\dfrac{Bx+C}{x^2+bx+c}}\)

Therefore, the given algebraic fraction can be written as partial fractions of the form:

\(\dfrac{7+x}{(1+x)(1+x^2)}\equiv \dfrac{A}{1+x}+\dfrac{Bx+C}{1+x^2}\)

Add the partial fractions:

\(\dfrac{7+x}{(1+x)(1+x^2)}\equiv \dfrac{A(1+x^2)+(Bx+C)(1+x)}{(1+x)(1+x^2)}\)

Cancel the denominators from both sides of the original identity, so the numerators are equal:

\(7+x \equiv A(1+x^2)+(Bx+C)(1+x)\)

Substitute a value of x which make one of the expressions in the brackets equal zero to get rid of all but one of A, B and C.

\(\begin{aligned}x=-1 \implies 7+(-1) &=A(1+(-1)^2)+(Bx+C)(1+(-1))\\7-1&=A(1+1)+(Bx+C)(0)\\6 & =2A\\3&=A\end{aligned}\)

Substitute the found value of A:

\(7+x \equiv 3(1+x^2)+(Bx+C)(1+x)\)

Substitute x = 0 and solve for C:

\(\begin{aligned} x=0 \implies 7+0 &=3(1+(0)^2)+(B(0)+C)(1+0)\\ 7&=3(1)+C(1)\\7&= 3+C\\4&=C\end{aligned}\)

Substitute the found values of A and C:

\(7+x \equiv 3(1+x^2)+(Bx+4)(1+x)\)

Expand the right side:

\(\begin{aligned}7+x &\equiv 3(1+x^2)+(Bx+4)(1+x)\\7+x &\equiv 3+3x^2+Bx+Bx^2+4+4x\\7+x&\equiv(3+B)x^2+(4+B)x+7\end{aligned}\)

Compare the coefficients of the terms in x to solve for B:

\(\begin{aligned} 1&=4+B\\-3&=B\end{aligned}\)

Therefore:

Finally, replace A, B and C in the original identity:

\(\dfrac{7+x}{(1+x)(1+x^2)}\equiv \dfrac{3}{1+x}+\dfrac{-3x+4}{1+x^2}\)

\(\dfrac{7+x}{(1+x)(1+x^2)}\equiv \dfrac{3}{1+x}-\dfrac{3x-4}{1+x^2}\)

Answer:

1- 3(BDE)

2- 37.18 (83.36 - 46.18=64)

3- 64 (83.36 - 19.36)

4- 140.2  (56.84 + 83.36=140.2)

Answer:

r=85

Let's solve your equation step-by-step:

−6(r−98)=78

Step 1: Simplify both sides of the equation

−6(r−98)=78

(−6)(r)+(−6)(−98)=78(Distribute)

−6r+588=78

Step 2: Subtract 588 from both sides

−6r+588−588=78−588

−6r=−510

Step 3: Divide both sides by -6

−6r/−6=−510/−6

r=85

Answer:

r=85

Answer:

85

Step-by-step explanation:

–6(r − 98) = 78

expand:

-6r+588=78

588-78=510

6r=510

510÷=85

The total fixed costs for the event amount to £2,800, which includes the security costs and the cost of the main band. Fixed costs are expenses that do not change with the number of attendees or sales.

To calculate the total fixed costs for the event, we need to identify the costs that do not change with the number of attendees. Based on the given information, the fixed costs include the security costs and the cost of the main band. Let's break it down:

Security costs: The security costs of £300 are fixed and do not depend on the number of attendees. This means the cost remains the same regardless of how many tickets are sold.

Cost of the main band: The cost of the main band is £2,500. Similar to the security costs, this cost is fixed and does not vary based on the number of attendees.

Therefore, the total fixed costs for the event would be the sum of the security costs and the cost of the main band:

Total Fixed Costs = Security Costs + Cost of Main Band

Total Fixed Costs = £300 + £2,500

Total Fixed Costs = £2,800

However, it's important to note that the cost of the supporting band, ticket prices, and the cost of the water bottles are not fixed costs. The cost of the supporting band and the cost of the water bottles are variable costs as they depend on the number of attendees. The ticket prices represent revenue, not costs.

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In order to completely delta hedge 480 shares of ABC company with an option delta of 0.6, you would need 3 call options.

To completely delta hedge your holdings of 480 shares of ABC company, you would need to calculate the number of call options required based on the delta of the option. The delta represents the change in the option price relative to the change in the underlying stock price. In this case, since the delta is given as 0.6, it means that for every $1 increase in the stock price, the option price will increase by $0.6.

To calculate the number of call options needed for delta hedging, you can use the following formula:

Number of call options = (Delta * Number of shares) / 100

Plugging in the given values, we have:

Number of call options = (0.6 * 480) / 100

Number of call options = 2.88

Since you cannot have a fractional number of options, you would need to round up to the nearest whole number. Therefore, you would need 3 call options to hedge your 480 shares of ABC company.

In summary, to completely delta hedge 480 shares of ABC company with an option delta of 0.6, you would need to acquire 3 call options.

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Answer:

x+y=3;  graph is in word doc

Step-by-step explanation:

Answer:

the other leg would be 12