What is the most specific name for the figure? I NEED THE ANSWER

Given the equation:

Answer:

Daisies flower grows the slowest

Step-by-step explanation:

We are given;

Rate of growth of rose bush; 12 inches in 1 month.

1 month = 4 weeks.

Thus, we have; 12 inches in 4 weeks.

In 1 week, it grows; 12/4 = 3 inches per week

Rate of growth of daisies; 5 inches in 2 weeks. Thus, in 1 week, it grows by; 5/2 = 2.5 inches per week.

Rate of growth of tulips; 8 inches in 3 weeks. In one week, it grows by; 8/3 = 2.67 inches per week

Rate of growth of daffodils; 3 inches in 1 week = 3 inches per week

Looking at all the rates above, the slowest is 2.5 inches per week. This is for daisies.

The missing terms in the sentence are "Inclination" and "Vertical."

Inclination is the angle of tilt below the imaginary horizontal plane oriented 90-degrees to the vertical direction. It refers to the angle at which an object or surface deviates from being perfectly horizontal or flat. It measures the slope or tilt of the object or surface in relation to the vertical direction.

The vertical direction is the imaginary line or axis that points directly up or down, perpendicular to the horizontal plane. It is oriented at a 90-degree angle to the horizontal direction, which is typically considered the direction parallel to the ground or any other reference plane.

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The impulse response is absolutely summable and hence, the system is stable. Therefore, the system is stable.

The given signal x[n] is;

\($$x[n] = u[n] - u[n-3]$$\)

The impulse response of the system is given as:

\($$h[n] = \left(\frac{1}{2}\right)^nu[n]$$\)

Now, the output of a linear time-invariant (LTI) system is given by;

\($$y[n] = x[n] * h[n]$$\)

Where, * represents the convolution operation. Hence, we need to find the convolution of the input signal x[n] with the impulse response of the system h[n].

(a) Convolution of the given input signal x[n] with the given impulse response h[n] is given as:

\($$\begin{aligned} y[n] &= x[n] * h[n] \\ &= \sum_{k=-\infty}^{\infty} x[k]h[n-k] \\ &= \sum_{k=-\infty}^{\infty} (u[k] - u[k-3]) \left(\frac{1}{2}\right)^{n-k} u[n-k] \end{aligned}$$\)

Now, let's break this equation into two parts, one for \($0 \leq n < 3$\) and other for \($n \geq 3$\).

For \($0 \leq n < 3$\), the above equation can be simplified as:

\($$\begin{aligned} y[n] &= \sum_{k=0}^{n} \left(\frac{1}{2}\right)^{n-k} \\ &= \frac{1}{2^n} \sum_{k=0}^{n} \left(\frac{1}{2}\right)^k \\ &= \frac{1}{2^n} \cdot \frac{1 - \left(\frac{1}{2}\right)^{n+1}}{1 - \frac{1}{2}} \\ &= 1 - \frac{1}{2^{n+1}} \end{aligned}$$\)

For\($n \geq 3$\), the above equation can be simplified as:

\($$\begin{aligned} y[n] &= \sum_{k=n-2}^{n} \left(\frac{1}{2}\right)^{n-k} \\ &= \frac{1}{2^3} + \frac{1}{2^2} + \frac{1}{2^1} \\ &= \frac{7}{8} \end{aligned}$$\)

Therefore, the output of the given system is:

\($$y[n] = \begin{cases} 1 - \frac{1}{2^{n+1}} & \text{for } 0 \leq n < 3 \\ \frac{7}{8} & \text{for } n \geq 3 \end{cases}$$\)

(b) The system is said to be stable if the impulse response is absolutely summable, that is,

\($$\sum_{n=-\infty}^{\infty} |h[n]| < \infty$$\)

Now, let's check whether the given system is stable or not:

\($$\sum_{n=-\infty}^{\infty} |h[n]| = \sum_{n=0}^{\infty} \left(\frac{1}{2}\right)^n = \frac{1}{1 - \frac{1}{2}} = 2 < \infty$$\)

Since the above sum is a finite quantity, the impulse response is absolutely summable and hence, the system is stable. Therefore, the system is stable.

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Answer:

15%Explanation:24.00 increased by 15% is 27.60The increase is $3.60.Step-by-step explanation:

The distance covered is 36 km and the original rate is 4 km/hr

From the question, we have the following parameters that can be used in our computation:

Let speed be y and distance be x

The equation of time is

time = x/y

So, we have the following equations

x/(y + 1/2) = x/y - 1

x/(y - 1) = x/y + 3

So, we have

x/y - x/(y + 1/2) = 1

x/(y - 1) - x/y = 3

When solved graphically, we have

x = 36 and y = 4

This means that

The distance covered is 36 km and the speed is 4 km/hr

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Answer:

Tyler practiced piano = 48 minutes

Step-by-step explanation:

Missing;

Hen practiced piano = 75 minutes

Given:

Tyler practiced piano = 64 % of Hen

Find:

How long Tyler practiced

Computation:

Tyler practiced piano = 64 % of Hen

Tyler practiced piano = 64 % x 75

Tyler practiced piano = 48 minutes

The probability that exactly four of the selected bulbs from the pack of 10 bulbs is defective is 1/120.

For the given question;

Thus, the probability that exactly four of the selected is defective.

P = ⁴C₄  / ¹⁰C₃

P = 1/120

Thus, the probability that exactly four of the selected is defective is 1/120.

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(3) Add: Under applied overhead 34,000

(4) Adjusted cost of goods sold 364,000

1 and 2 RAW MATERIAL INVENTORY

Beginning balance 75,000

a 225,000 150,000 b, Ending Balance 150,000

WORK IN PROGRESS INVENTORY

Beginning balance 140,000

b 125,000 352,000 g

c 60,000

f 105,000

j Ending Balance 78,000

FINISHED GOODS INVENTORY

Beginning balance -

g 352,000 330,000 h

Ending Balance 22,000

FACTORY OVERHEAD

b 25,000

c 40,000 105,000 f

d 74,000

Ending Balance 34,000

COST OF GOODS SOLD

h 330,000

Ending Balance 330,000

Factory overhead applied on the basis of direct labor cost .

Hence applied overhead = 60,000 x 175% = $105,000Step: 2

3)

Computation of under /(over) applied OH

Actual OH($) Applied OH ($) Under /(over) applied OH ($)

139,000 105,000 34,000

Actual manufacturing overhead:

$

Indirect material 25,000

Indirect Labour 40,000

Other manufacturing overhead 74,000

139,000

4)

Cost of goods sold (Unadjusted) 330,000

Add: Under applied overhead 34,000

Adjusted cost of goods sold 364,000

Actal manufacturing overhead is more than applied overhead,it means factory overhead under applied and it will be added in unadjusted cost of goods sold to ascertain adjused cost of goods sold.

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Answer:

b

Step-by-step explanation:

From eqn 1

12x - y = - 4

y = 12x + 4

Substituting y into eqn 2

4x - 3y = - 6

4x - 3(12x + 4) = - 6

Answer:

abby

frisk

mimi

Step-by-step explanation:

Answer:

Mochi, Athena, and Oreo ^^

Step-by-step explanation:

Congrats! :D

Answer:

i think the answer may be (2,infinity)

(1, 2)​ and (-∞, 0)​

===========================================================

Explanation:

The function curve is increasing when going uphill as you move to the right. This happens on the interval (-∞, 0)​ aka -∞ < x < 0​ aka x < 0. This is why choice D is one of the answers.

The function is also increasing when 1 < x < 2 which translates to the interval notation (1,2). This is why choice B is the other answer.

Choices A and C are eliminated since they describe decreasing intervals.

Option 2: 9 km seems to be the most likely answer if the hiker's motion is along a straight line.

Displacement refers to the distance between an initial point and a final point of an object's motion, measured in a straight line. In other words, it is the shortest distance between the starting point and ending point of an object's motion, regardless of the path taken.

I would need the position-time graph to accurately determine the displacement of the hiker after 4 hours. However, assuming that the hiker's motion is along a straight line, I can make an educated guess based on the options provided.

Option 1: 8 km - If the hiker's displacement after 4 hours is 8 km, it means that the hiker traveled at a constant speed of 2 km/h (since 2 km/h x 4 hours = 8 km). This would result in a straight line on the position-time graph with a constant slope of 2 km/h.

Option 2: 9 km - If the hiker's displacement after 4 hours is 9 km, it means that the hiker traveled at an average speed of 2.25 km/h (since 2.25 km/h x 4 hours = 9 km). This would result in a straight line on the position-time graph with a constant slope of 2.25 km/h.

Option 3: 6 km - If the hiker's displacement after 4 hours is 6 km, it means that the hiker traveled at an average speed of 1.5 km/h (since 1.5 km/h x 4 hours = 6 km). This would result in a straight line on the position-time graph with a constant slope of 1.5 km/h.

Option 4: 7 km - If the hiker's displacement after 4 hours is 7 km, it means that the hiker traveled at an average speed of 1.75 km/h (since 1.75 km/h x 4 hours = 7 km). This would result in a straight line on the position-time graph with a constant slope of 1.75 km/h.

Without the position-time graph, it is difficult to determine the correct answer. However, based on the options provided.

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Alex's statement that 3.2(x - 5) has infinitely many solutions is correct

From the question, we have the following parameters that can be used in our computation:

3.2(x - 5)

The above is an expression

This means that it can take any value depending on the value of x

Taking any value implies that it has infinitely many solutions

Hence, Alex's statement about the solutions is correct

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Answer:

(5x - 4) = 2(2x + 1)

Step-by-step explanation:

Since Ancilla is twice as old as Christabel

Ancilla's age (5x - 4) is twice Christabel (2x + 1) so,

(5x - 4) = 2(2x + 1)

The largest possible volume of this box is 1687.5 cm³ with a base edge of 15 cm and a height of 7.5 cm

Let w = length of the base edge

h = height of the box

A box with a square bottom and an open top is to be made from 675 cm² of material. Hence,

675 cm² = w² + 4wh

4wh = 675 cm² - w²

h = (675 cm² - w²)/4w

The volume of the box is the product of the area of the square base and its height. Hence,

V = w²h

Substitute the expression of h to the equation of volume.

V = w²(675 cm² - w²)/4w

V = (675/4)w - (1/4)w³

To obtain the largest volume possible, the first derivative of the volume should be equal to zero.

V'(w) = 0

V = (675/4)w - (1/4)w³

675/4 - (3/4)w² = 0

Simplify and solve for the value of w.

675/4 - (3/4)w² = 0

(3/4)w² = 675/4

w² = 225

w = 15

length of the base edge = 15 cm

Solve for the value of h.

h = (675 cm² - w²)/4w

h = (675 cm² - (15)²)/4(15)

h = 7.5 cm

height of the box = 7.5 cm

Solve for the volume of the box.

V = w²h

V = (15 cm)²(7.5 cm)

V = 1687.5 cm³

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The Prove that the triangle formed by the points A (0,0), B (1, sqrt3), and C (2,0) is equilateral is given below

An  equilateral triangle is aid to be a triangle that is known to have all its three sides to be of the same length.

Note that:

AB=  \(\sqrt{(0-0)^ 2 +(1.73-1)^ 2}\)    

​=\(\sqrt{}\)0.5329

= 0.73

BC=  \(\sqrt{(1.73-1)^ 2 +(0-2)^ 2}\)    

​=\(\sqrt{}\)0.5329

= 0.73

CA=  \(\sqrt{(0-2)^ 2 +(0-0)^ 2}\)    

​=\(\sqrt{}\)0.5329

= 0.73

So therefore, AB=BC=CA

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Answer:

4x-5y=3

-3=4x-5y

Step-by-step explanation:

4x-5y = 3

4x-5y = -3

both statements have different answers but has the same problem making the statement x=x and 0=0 making it have no solution

227 18-inch cubes can fit inside the rectangular prism.

You may calculate how many 18-inch cubes can fit within a rectangular prism by dividing the rectangular prism's overall volume by the volume of a single 18-inch cube.

A rectangular prism's volume can be calculated using the formula length x width x height. In this instance, the dimensions are 312 inches long, 212 inches wide, and 3 inches high. As a result, the rectangular prism has a volume of 1,326,720 cubic inches (312 x 212 x 3).

A single 18-inch cube has a volume of 18 x 18 x 18 = 5832 cubic inches.

We divide the volume of the rectangular prism by the volume of a single 18-inch cube to get the number of 18-inch cubes that can fit inside: 1,326,720 / 5832 = 227.

Therefore, the rectangular prism can accommodate 227 18-inch cubes.

Please take note that this is an estimate and that there will not be enough room in the prism to fit 227 cubes exactly.

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The kinematic equation of the motion of the paintbrush dropped 35 feet height from the ground and the 1.85 seconds reaction time of the 6 feet person standing directly below, indicates that they will be hit  by the paintbrush before they can move out of the way.

The kinematic equation of motion describe the motion of a body that moves under constant acceleration, without consideration of the forces causing the body to move.

The height from which the paintbrush is dropped from the roof to the ground = 35 feet

Height of the person standing directly below where the brush falls = 6 feet

The reaction time of the person = 1.85 seconds

The kinematic equation of motion of free fall of an object is presented as follows;

s = u·t + 0.5·g·t²

Where; s = The height through which the paintbrush falls

u = The initial velocity of the paintbrush = 0

g = The acceleration due to gravity ≈ 32.1741 ft/s²

The height the paintbrush falls before meeting the 6 feet tall person, s = 35 feet - 6 feet = 29 feet

Therefore, we get;

29 = 0 × t + 0.5 × 32.1741 × t²

t² = 29 ÷ (0.5 × 32.1741) ≈ 1.803

The time it takes the paintbrush to fall 29 feet, t, is therefore;

t = √(29 ÷ (0.5 × 32.1741)) ≈ 1.343

It takes the paintbrush to reach the height of the person standing directly below in just about 1.3 seconds after it is dropped, before the person can react to move away in 1.85 seconds, therefore, they will be hit by the paintbrush before they can move out of the way.

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The first condition to satisfy the principle of mathematical induction is "the statement is true for the natural number 1".

Use the principle of mathematical induction to show that the given statement is true for all natural numbers n:

1. 9 + 2.10 + 3.11 + … + n(n + 8) = n/6(n + 1)(2n + 25)To prove: 9 + 2.10 + 3.11 + … + n(n + 8) = n/6(n + 1)(2n + 25) is true for all natural numbers.

The first step is to check for the base case.

When n = 1LHS = 9 + 2.10 = 29RHS = 1/6(2 x 1 + 25) = 27/6 = 9/2

The LHS is equal to RHS when n = 1.

Let us assume that the equation is true for n = k.i.e., 9 + 2.10 + 3.11 + … + k(k + 8) = k/6(k + 1)(2k + 25)

If we add (k + 1)(k + 9) to both sides of the equation, then we get,

9 + 2.10 + 3.11 + … + k(k + 8) + (k + 1)(k + 9) = k/6(k + 1)(2k + 25) + (k + 1)(k + 9)

LHS: We can write the above equation as,

9 + 2.10 + 3.11 + … + k(k + 8) + (k + 1)(k + 9)= 1/6[(6k² + 65k + 198) + 6(k + 1)(k + 9)](simplifying the above expression)

RHS: Substituting n = k + 1 in the RHS expression,

we get(k + 1)/6(k + 2)(2k + 27)(simplifying the above expression)

Since the LHS = RHS, the equation is true for n = k + 1.

Therefore, by mathematical induction, 9 + 2.10 + 3.11 + … + n(n + 8) = n/6(n + 1)(2n + 25) is true for all natural numbers n.

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The values of x and y are obtained as 12.99 and 7.5 respectively.

The trigonometric ratios are defined for a right angled triangle.

The example of these ratios are sin, cos, tan, cosec, sec and cot.

The trigonometric ratios are useful in determining the heights and distances of the large objects.

For the given triangle, the trigonometric ratios are used as follows,

Cos(30°) = x/15

=> √3/2 = x/15

=> x = 15√3/2

=> x = 15 × 0.866

       = 12.99

And,

Sin(30°) = y/15

=> 1/2 = y/15

=> y = 15/2

       = 7.5

Hence, for the given triangle the values of x and y are given as 12.99 and 7.5 respectively.

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An equation to model the relationship between the number of weeks, x, and the number of site visits, f(x) is 4800 = a(1.5)^x.

He found that before launching the new marketing plan, there were 4,800 visits.

Over the course of the next 5 weeks, the number of site visits increased by a factor of 1.5 each week.

Over the course of the next 5 weeks, initial visitor at x = 0, 4800

Increasing factor = 1.5

Equation of the model is given as:

f(x) = a(b)^x

From the question b = 1.5

Now the equation of model is:

f(x) = a(1.5)^x

At x = 0, f(x) = 4800

Now the equation of the model is:

4800 = a(1.5)^x

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2.1 The volume in ml of one can of cold drink is 83 ml.

2.2 The height of the cooler bag is 18 cm.

2.3 The volume in ml of the cooler bag if the breadth of the bag is 12 cm and the length 18 cm is 3,888 ml.

2.4 The circumference of the can is 18.84 cm.

In Mathematics and Geometry, the volume of a cylinder can be calculated by using this formula:

Volume of a cylinder, V = πr²h

Where:

By substituting the given side lengths into the volume of a cylinder formula, we have the following;

Volume of can = 3.14 × (6/2)² × 8.84

Volume of can = 83.27 cm³.

Note: 1 cm³ = 1 ml

Volume of can in ml = 83.27 ≈ 83 ml.

Part 2.2.

For the height of the cooler bag, we have:

Height of cooler bag = 2 × height of can

Height of cooler bag = 2 × 8.84

Height of cooler bag = 17.68 ≈ 18 cm.

Part 2.3

Volume of cooler bag = length × breadth × height

Volume of cooler bag = 18 × 12 × 18

Volume of cooler bag = 3,888 ml.

Part 2.4

The circumference of the can is given by:

Circumference of circle = 2πr

Circumference of can = 2 × 3.14 × 3

Circumference of can = 18.84 cm.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

Step-by-step explanation:

x = 70 degree (being vertically opposite angles)

y + 70 degree =180 degree (being linear pair)

y = 180 - 70

y = 110 degree

In triangle,

x + 60 + misssing angle = 180 degree (sum of interior angles of a triangle)

70 + 60 + missing angle =180

130 + missing angle = 180

missing angle = 180 - 130

missing angle = 50 degree

c = missing angle (being vertically opposite angles )

c = 50 degree

x + missing angle = a (sum of two interior opposite angles is equal to the exterior angle formed)

70 + 50 = a

120 degree = a

a = b (being vertically opposite angle

120 =b

therefore b is 120 degree

Hence , a = 120 degree , b = 120 degree , c = 50 degree , x = 70 degree , y = 110 degree

The interpretation is that we are 90% confident that the true difference in the mean daily leisure time between adults with no children and adults with children lies between 0.451 and 2.109 hours.

The given data are: For adults with no children under the age of 18 years, Mean = 5.65 hours Standard deviation = 2.43 hours Sample size, n1 = 40 For adults with children under the age of 18, Mean = 4.37 hours Standard deviation = 1.73 hours Sample size, n2 = 40 The formula to calculate the 90% confidence interval for the difference between two means can be given as:\[\left( {{\bar x}_1} - {{\bar x}_2} \right) \pm {t_{\frac{\alpha }{2},n_1 + {n_2} - 2}}\sqrt {\frac{{s_1^2}}{n_1} + \frac{{s_2^2}}{n_2}}\]where,${{\bar x}_1}$ is the sample mean for group 1,${{\bar x}_2}$ is the sample mean for group 2,${{s_1}}$ is the sample standard deviation for group 1,${{s_2}}$ is the sample standard deviation for group 2,$\alpha$ is the level of significance,$n_1$ is the sample size for group 1,$n_2$ is the sample size for group 2,and $t_{\frac{\alpha }{2},n_1 + {n_2} - 2}$ is the t-value from the t-distribution with (n1 + n2 – 2) degrees of freedom.

Let's calculate the confidence interval as follows: Mean difference, $\left( {{\bar x}_1} - {{\bar x}_2} \right)$= 5.65 − 4.37= 1.28 hours Sample standard deviation for group 1, ${s_1}$ = 2.43 hours Sample standard deviation for group 2, ${s_2}$ = 1.73 hours Sample size for group 1, ${n_1}$ = 40Sample size for group 2, ${n_2}$ = 40 Degree of freedom = $n_1 + n_2 - 2$= 40 + 40 – 2= 78$\alpha$ = 0.1 (90% confidence interval, $\alpha$ = 1 – 0.9 = 0.1)Using the t-table or calculator with the given values, we get:$t_{\frac{\alpha }{2},n_1 + {n_2} - 2}$ = t0.05, 78 = 1.665 (approximately)Substituting the given values in the formula, we get:\[\left( {{\bar x}_1} - {{\bar x}_2} \right) \pm {t_{\frac{\alpha }{2},n_1 + {n_2} - 2}}\sqrt {\frac{{s_1^2}}{n_1} + \frac{{s_2^2}}{n_2}}\] = $1.28 \pm 1.665\sqrt {\frac{{2.43^2}}{40} + \frac{{1.73^2}}{40}}$= $1.28 \pm 0.829$= (0.451, 2.109)

Therefore, the 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children is (0.451, 2.109) hours.

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We can also say that adults with no children have, on average, between 0.50 hours and 2.06 hours more leisure time per day than adults with children under the age of 18.

The 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children is (-1.23, -0.04).

We are to construct a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children.

We are given the following information:

u1 = mean daily leisure time of adults with no children

= 5.65 hours

σ1 = standard deviation of daily leisure time of adults with no children

= 2.43 hours

n1 = sample size of adults with no children

= 40

u2 = mean daily leisure time of adults with children

= 4.37 hours

σ2 = standard deviation of daily leisure time of adults with children

= 1.73 hours

n2 = sample size of adults with children

= 40

We can find the standard error (SE) of the difference in means as follows:

SE = sqrt [ (σ1^2 / n1) + (σ2^2 / n2) ]

SE = sqrt [ (2.43^2 / 40) + (1.73^2 / 40) ]

SE = sqrt (0.1482 + 0.0752)

SE = sqrt (0.2234)

SE = 0.4726

We can now use the formula for a confidence interval of the difference in means as follows:

CI = ( (u1 - u2) - E , (u1 - u2) + E )

where

E = z*SE and z* is the z-score for the level of confidence.

Since we want a 90% confidence interval, we look for the z-score that corresponds to the middle 90% of the normal distribution, which is found using a z-table or calculator.

For a 90% confidence level, the z* value is 1.645,

so:E = 1.645 * 0.4726E = 0.7779

Plugging in the values, we have:CI = ( (5.65 - 4.37) - 0.7779 , (5.65 - 4.37) + 0.7779 )CI = ( 1.28 - 0.78, 1.28 + 0.78 )CI = ( 0.50, 2.06 )

The 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children is (0.50, 2.06).

This means that we are 90% confident that the true mean difference in leisure time between the two groups of adults falls between 0.50 hours and 2.06 hours.

Since the interval does not include zero, we can conclude that the difference in means is statistically significant at the 0.10 level. We can also say that adults with no children have, on average, between 0.50 hours and 2.06 hours more leisure time per day than adults with children under the age of 18.

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Answer:

The answer is "Option A".

Step-by-step explanation:

In this, the question is missing so, we assuming the missing question is this question, which is add in attach file. please find it.

Formula for line:

\(\to \bold{y= mx+ c}\)

\(\to m= slope \\\\\to c= y-intercept\)

In the question the slope "m= 3 and y= -2" so, the line is \(y= 3x+ (-2)\).

\(\to y= 3x-2\)