what is the number seven tens and nine ones

The value of fraction 0.5 7  is equal to 1/2.

We are given that;

Number = 0.57

Now,

There are different ways to express a fraction as a decimal, but one common method is to divide the numerator by the denominator.

For example, 1/2 as a decimal is 1 ÷ 2 = 0.512.

Another method is to use a fraction to decimal conversion chart or calculator345. According to these sources, 0.5 as a fraction is equal to 5/10 or 1/2.

These fractions are equivalent because they have the same value when simplified or reduced.

To simplify a fraction, we can divide both the numerator and the denominator by their greatest common factor (GCF).

Therefore, by algebra the answer will be 1/2.

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Answer:

32

Step-by-step explanation:

(-8 × -6) - 4² ​

48 - 4²

48 - 16 = 32

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

Answer:

64

Step-by-step explanation:

first u do what is in the parentheses. since they are both negatives, u make it a positive so it would be 48-\(4^{2}\). the next step is exponents. -4*-4 is 16. then u add 48 and 16 which gets  u 64.

During the morning rush hour, there are 6,400 junior and high school students, 3,400 adults, and 5,800 senior citizens riding the subway.

Let's assume the number of junior and high school students riding the subway during the morning rush hour is J, the number of adults is A, and the number of senior citizens is S.

From the given information, we can set up a system of equations based on the number of riders and the revenue generated.

Equation 1: J + A + S = 15,600 (total number of riders)

Equation 2: 1.04J + 2.20A + 1.04S = 32,464 (revenue equation with original ticket prices)

Equation 3: 1.24J + 2.60A + 1.04S = 38,264 (revenue equation with new ticket prices)

We can start by subtracting Equation 2 from Equation 3 to eliminate the J and S terms:

0.2J + 0.4A = 3,800

Next, we can multiply Equation 1 by 0.2 and subtract it from the above equation to eliminate the J term:

0.4A - 0.2J - 0.2A = 3,800 - 3,120

0.2A = 680

A = 680 / 0.2 = 3,400

Now, we can substitute the value of A back into Equation 1 to find the values of J and S:

J + 3,400 + S = 15,600

J + S = 15,600 - 3,400

J + S = 12,200

We have two equations with two variables (J + S = 12,200 and 1.04J + 1.04S = 12,264). By solving these equations simultaneously, we find J = 6,400 and S = 5,800.

Therefore, during the morning rush hour, there are 6,400 junior and high school students, 3,400 adults, and 5,800 senior citizens riding the subway.

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To find the number of subway riders in each category, we set up a system of equations based on the total number of passengers and the total revenue. Solving this system will give us the number of junior and high school students, adults, and senior citizens. The number of riders doesn't change with the increase of ticket prices.

To solve this problem, we set up a system of equations based on the information given in the question.

Let's denote the number of junior and high school students as J, adults as A, and senior citizens as S. We know that there's total of 15,600 passengers, so:

J + A + S = 15,600

We also know that the total revenue was $32,464. Given the ticket prices for each group, we can write:

$1.04J + $2.20A + $1.04S = $32,464

Solving this system of equations (possibly with the help of a calculator or computer software), we can find the number of riders in each category.

The number of riders for each category would only change if the number of riders changes, not the price of the tickets, so when the prices increase, the number of riders remains the same.

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measure horizontally

measure vertically

measure depth..

point (2, 3)

y = -1/4x + 3

from equation y = mx + c

where m is the slope

slope = -1/4

since it is perpendicular to the point

m1 x m2 = -1

m2 = -1/m1

m1 = -1/4

m2 = -1 divided by -1/4

m2 = -1 x -4/1

m2 = -1 x -4

m2 = 4

the new equation will now be

(y - y1) = m(x - x1)

y1 = 3 and x1 = 2

y - 3 = 4(x - 2)

y - 3 = 4 *x - 4*2

y -3 = 4x -8

y = 4x -8 + 3

y = 4x -5

The slope - intercept form of the equation is y = 4x - 5

Answer:

Step-by-step explanation:

mean is average, so if we label the first through fifth days of january a-e we can solve it.

So average of the first four is (a+b+c+d)/4 = 1 and the first five is (a+b+c+d+e)/5 = 2.  Since it's easy, let's get rid of the fraction in both.

(a+b+c+d)/4 = 1 and (a+b+c+d+e)/5 = 2

a+b+c+d = 4 and a+b+c+d+e = 10

Now, we know a+b+c+d is 4, so we can replace that in the second equation

a+b+c+d+e = 10

4 + e = 10

e = 6

ad since e is the fifth day, we know the temperature of it.  Let me know if something here didn't make sense

Answer:

121 unit^2.

Step-by-step explanation:

The area = height/2 * ( sum of the opposite parallel  lines)

= h/2(BC + AD

h = BF = 14 - 3 = 11 units.

BC   = 13 - 5 = 8 units.

AD = 16 - 2 = 14 units.

Area = (11/2)(8 + 14)

= 5.5 * 22

= 121 unit^2.

Answer:

121

Step-by-step explanation:

Using percentage formula, the mark up price on the microscope is £49

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Markup shows how much more a company's selling price is than the amount the item costs the company. In general, the higher the markup, the more revenue a company makes. Markup is the retail price for a product minus its cost, but the margin percentage is calculated differently.

Let's find 50% of £98

50 / 100 = x / 98

0.5 = x / 98

x = 0.5 * 98

x = 49

The mark up price is £49

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Answer:

a

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Representation of a number in three different ways:

133: [12 tens and 13 ones], [13 tens and 3 ones], [1 hundred, 3 tens and 3 ones]

678: [67 tens and 8 ones], [60 tens and 78 ones], [6 hundreds, 7 tens and 8 ones]

877: [80 tens and 77 ones], [87 tens and 7 ones], [8 hundred, 7 tens and 7 ones]

543: [54 tens and 3 ones], [50 tens and 43 ones], [5 hundreds, 4 tens and 3 ones]

453: [45 tens and 3 ones], [40 tens and 53 ones], [4 hundreds, 5 tens and 3 ones]

341: [30 tens and 41 ones], [34 tens and one], [3 hundreds,4 tens and one]

555: [50 tens and 55 ones], [55 tens and 5 ones], [5 hundreds, 5 tens and 5 ones]

485: [48 tens and 5 ones], [40 tens and 85 ones], [4 hundreds, 8 tens and 5 ones]

789: [78 tens and 9 ones], [70 tens and 89 ones], [7hundreds, 8 tens and 9 ones]

864: [86 tens and 4 ones], [80 tens and 64 ones], [8 hundreds, 6 tens and 4 ones]

652: [65 tens and 2 ones], [60 tens and 52 ones], [6hundreds, 5 tens and 2 ones]

Here given an example to write a particular number in different representations.

13 tens and 12 ones = 13*10 + 12*1 = 130 + 12 = 142.

14 tens and 2 ones = 14*10 + 2*1 = 140 + 2 = 142.

1 hundred, 4 tens and 2 ones = 1*100 + 4*10 + 2*1 = 100 + 40 + 2 = 142.

So three representations are of number 142.

Rest blanks should be filled in same manner taking different numbers for each rows and three columns of each row should be filled with three different representation of that assumed numbers.

Representations for some numbers:

133: [12 tens and 13 ones], [13 tens and 3 ones], [1 hundred, 3 tens and 3 ones]

678: [67 tens and 8 ones], [60 tens and 78 ones], [6 hundreds, 7 tens and 8 ones]

877: [80 tens and 77 ones], [87 tens and 7 ones], [8 hundred, 7 tens and 7 ones]

543: [54 tens and 3 ones], [50 tens and 43 ones], [5 hundreds, 4 tens and 3 ones]

453: [45 tens and 3 ones], [40 tens and 53 ones], [4 hundreds, 5 tens and 3 ones]

341: [30 tens and 41 ones], [34 tens and one], [3 hundreds,4 tens and one]

555: [50 tens and 55 ones], [55 tens and 5 ones], [5 hundreds, 5 tens and 5 ones]

485: [48 tens and 5 ones], [40 tens and 85 ones], [4 hundreds, 8 tens and 5 ones]

789: [78 tens and 9 ones], [70 tens and 89 ones], [7hundreds, 8 tens and 9 ones]

864: [86 tens and 4 ones], [80 tens and 64 ones], [8 hundreds, 6 tens and 4 ones]

652: [65 tens and 2 ones], [60 tens and 52 ones], [6hundreds, 5 tens and 2 ones]

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The solution to the equation is x ≈ 20°.

The periodic functions known as trigonometric functions indicate how a right-angled triangle's angle and sides relate to one another.

The given equation is sin(5x)cos(8x) - cos(5x)sin(8x) = - 0.85.

The formula for the sin(A-B) states that:

sin(A-B) = sinAcosB - cosAsinB.

Use this formula to solve the equation:
sin(5x)cos(8x) - cos(5x)sin(8x) = - 0.85

sin(5x - 8x) = -0.85

sin (-3x) = -0.85

Since sin(-A) = -sinA, it follows:

-sin(3x) = -0.85

sin(3x) = 0.85

3x = sin⁻¹(0.85)

3x ≈ 60°

x ≈ 20°

Hence, the solution to the equation is x ≈ 20°.

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Answer

Opton A is correct

Explanation

The question to be represented on the number line is

1.2 + (-1.6)

Meaning that we first go to the right from 0 to 1.2, then the next part will require us to move towards the left from 1.2; we move 1.6 units towards the left and end up at -0.4

Only Option A shows this.

Hope this Helps!!!

The length of unknown side x is 58.

The correct answer is option D.

To find the unknown side length, x, in a right triangle with the base measuring 42 and the perpendicular measuring 40, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Let x be the hypotenuse. Applying the Pythagorean theorem, we have:

\(x^2 = 42^2 + 40^2\)

Simplifying:

\(x^2\) = 1764 + 1600

\(x^2\)= 3364

Taking the square root of both sides to solve for x:

x = \(\sqrt{3364}\)

Simplifying the square root:

x = (\(\sqrt{4 * 841)}\)

Since 841 is a perfect square (\(29^2\)), we can further simplify:

x = 2 * 29

x = 58

Therefore, the unknown side length, x, is equal to 58.

From the options provided the correct option is D.

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Answer:

The Federal Reserve System is not owned by anyone. The Federal Reserve was created in 1913 by the Federal Reserve Act to serve as the nation's central bank. The Board of Governors in Washington, D.C., is an agency of the federal government and reports to and is directly accountable to the Congress

The computed mean expenses of the XYZ Corporation based on the given information are 9,911.22.

The mean refers to the average value.

The mean is computed as the quotient that results from dividing the total value of the data set by the number of items in the set.

Name                      Total Sales      Total Expenses

Quezon City            14,950.00             4,933.50

Caloocan City         18,290.00             6,035.70

Marikina City          37,200.00           12,276.00

Cebu City                18,900.00            6,237.00

Davao City             45,000.00          14,850.00

Mandaluyong City 23,000.00           7,590.00

Cavite                     22,000.00          7,260.00

Laguna                    21,000.00          6,930.00

Manila                    66,000.00         21,780.00

Iloilo                       34,000.00          11,220.00

Total                                                  99,112.20

Mean Expenses = 9,911.22 (99,112.20 ÷ 10)

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Answer:

f-'(x) = \(\sqrt[3]{x+2}\)

Step-by-step explanation:

\(\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - b^2}=a \qquad \begin{cases} c=\stackrel{hypotenuse}{12}\\ a=adjacent\\ b=\stackrel{opposite}{9}\\ \end{cases} \\\\\\ \sqrt{12^2 - 9^2}=a\implies \sqrt{144 - 81}=a\implies \sqrt{63}=a\)

9514 1404 393

Answer:

  B)  40

Step-by-step explanation:

Vertical angle XZU has the same measure as the given angle, 130°. It is equal to the sum of right angle XZV and unknown angle UZV. So, ...

  ∠UZV +90° = 130°

  ∠UZV = 40° . . . . . . . . . subtract 90°

Step-by-step explanation:

700 × 0.07 (7/100)

= 49$

Based on the net present value profile, Project H has a higher NPV than Project E.

To compare the net present value (NPV) of Project E and Project H, we need to calculate the present value of cash flows for each project and determine which one has a higher NPV. The cash flow patterns for the two projects are as follows:

Project E:

Initial investment: -$100,000

Cash flows for Year 1: $40,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $60,000

Project H:

Initial investment: -$120,000

Cash flows for Year 1: $60,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $40,000

To calculate the present value of cash flows, we need to discount them using an appropriate discount rate. The discount rate represents the required rate of return or the cost of capital for the company. Let's assume a discount rate of 10%.

Using the formula method, we can calculate the present value (PV) of each cash flow and sum them up to obtain the NPV for each project:

For Project E:

PV = $40,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $60,000/(1 + 0.10)^3

PV = $36,363.64 + $41,322.31 + $45,454.55

PV = $123,140.50

For Project H:

PV = $60,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $40,000/(1 + 0.10)^3

PV = $54,545.45 + $41,322.31 + $30,251.14

PV = $126,118.90

Using the financial calculator method, we can input the cash flows and the discount rate to calculate the NPV directly. By entering the cash flows for each project and the discount rate of 10%, we find that the NPV for Project E is approximately $123,140.50 and the NPV for Project H is approximately $126,118.90.

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We have to find the Taylor Polynomial of $f(x)=e^x$ up to the third degree, centered at $x=0$.

The Taylor Polynomial is given by:

(x)=∑

k=0

n

​k!

f

(k)

(a)

​(x−a)

k

where $f^{(k)}(a)$ is the $k$th derivative of $f(x)$ evaluated at $a$.

Using this formula, we can find the Taylor Polynomial as follows:

\begin{align*}

f(x) &= e^x \

f'(x) &= e^x \

f''(x) &= e^x \

f'''(x) &= e^x \

\end{align*}

Evaluating each derivative at $x=0$, we get:

\begin{align*}

f(0) &= e^0 = 1 \

f'(0) &= e^0 = 1 \

f''(0) &= e^0 = 1 \

f'''(0) &= e^0 = 1 \

\end{align*}

Substituting these values into the formula for the Taylor Polynomial, we get:

\begin{align*}

P_3(x) &= \frac{f(0)}{0!}(x-0)^0 + \frac{f'(0)}{1!}(x-0)^1 + \frac{f''(0)}{2!}(x-0)^2 + \frac{f'''(0)}{3!}(x-0)^3 \

&= 1 + x + \frac{x^2}{2} + \frac{x^3}{6}

\end{align*}

Therefore, the Taylor Polynomial of $f(x)=e^x$ up to the third degree, centered at $x=0$, is $P_3(x) = 1 + x + \frac{x^2}{2} + \frac{x^3}{6}$.

It needs to do that route I guess. But I don't understand the last question well.

Distribution will be possible even if we do not know the true population distribution.

What is a frequency distribution?

The gathered data is arranged in tables based on frequency distribution. The information could consist of test results, local weather information, volleyball match results, student grades, etc. Data must be presented meaningfully for understanding after data gathering. A frequency distribution graph is a different approach to displaying data that has been represented graphically.

Here, the A5 sample size is infinite then the sample distribution becomes normal.  So as per the C.L.T n→∞  so distribution is normal.

Hence, Distribution will be possible even if we do not know the true population distribution.

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Step-by-step explanation:

6³×(½)³

=> 216÷8 = 27.

hope this helps you.

Answer:

It can be shown that opposite sides of parallelogram must be congruent , that opposite angles are also congruent , and that consecutive angles are supplementary . ...

The perimeter of a parallelogram is the sum of the lengths of its four sides. ...

Therefore, the perimeter is 6+10+6+10 or 32 cm.

Step-by-step explanation:

Answer:

Perimeter is always the same, add the outer lengths of all the sides. A+B+A+B=T

Or

2(A+B)

Area is just B * H when you have the height available.

You can also use a trig function A = ab sin (x)

Answer:

64.8 ft

Step-by-step explanation:

A square has all its sides equal

Therefore to get one side from its area is simply finding the square root of its area

√262.44=16.2ft

Having the one side then perimeter= to the four equal sides × the dimensions of one side

=4×16.2

=64.8 ft

The government agency as a monopolist will produce and sell internet connections up to the point where the marginal cost is 1/2. The price will be set at 1, given the perfectly elastic demand function.

In the scenario where a government agency has a monopoly in the provision of internet connections and the inverse demand function is given by p = 1, we can analyze the market equilibrium and the implications for pricing and quantity.

The inverse demand function, p = 1, implies that the market demand for internet connections is perfectly elastic, meaning consumers are willing to purchase any quantity of internet connections at a price of 1. As a monopolist, the government agency has control over the supply of internet connections and can set the price to maximize its profits.

To determine the optimal pricing and quantity, the monopolist needs to consider the marginal cost of providing internet connections. In this case, the marginal cost is given as 1/2. The monopolist will aim to maximize its profits by equating marginal cost with marginal revenue.

Since the inverse demand function is p = 1, the revenue received by the monopolist for each unit sold is also 1. Therefore, the marginal revenue is also 1. The monopolist will produce up to the point where marginal cost equals marginal revenue, which in this case is 1/2.

As a result, the monopolist will produce and sell internet connections up to the quantity where the marginal cost is 1/2. The monopolist will set the price at 1 since consumers are willing to pay that price.

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