What is the oxidation number of Boron? (2.2.1)
2+
2-
3+
3-

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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To solve such this we must know the concept of redox reaction. Therefore, the given reaction is redox reaction as one element is getting oxidized and other is getting reduced.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

Redox reaction is a chemical reaction where oxidation and reduction takes place simultaneously. Oxidation is loss of electrons and reduction is gain of electrons. The electron transfer from oxidant to reductant.

CH\(_4\) + 2 O\(_2\) \(\rightarrow\) CO\(_2\) + 2 H\(_2\)O

The oxidation state of C in CH\(_4\) is -4 while in CO\(_2\)  it is +4. So, carbon is getting oxidized. The oxidation state of oxygen in O\(_2\) is 0 while in  H\(_2\)O it is -2, so oxygen is getting reduced. So, this reaction is a redox reaction.

Therefore, the given reaction is redox reaction.

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In the given reaction, carbon oxidizes from 0 oxidation state to +4 state whereas, oxygen reduces from 0 to -2. Hence, one species is oxidized and another species is reduced, thus, it is a redox reaction.

A redox reaction a type of reaction in which one species is oxidized and another species is reduced. In oxidation an element forms its higher oxidation state whereas in reduction it reduces to lower oxidation state.

In the given reaction, carbon is in zero oxidation state zero and the it forms +4 oxidation state in CO₂. Similarly, oxygen is in zero charge at its molecular state O₂ which is changed to -2 state in CO₂.

Therefore, both oxidation and reduction takes place in this reaction and it is a redox reaction.

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Electrons are transferred from atoms of sodium to atoms of phosphorus this transfer makes the sodium atoms and the phosphorus atoms as a result, the sodium and phosphorus atoms strongly each other and it form sodium phosphide

Electron are smallest particles that make up an atom and they posses negative charge

Here given data is when electron are transferred from atom of sodium to the atom of phosphorous and this transfer made the sodium and phosphorous atom and because the form sodium phosphide because sodium is positive and phosphorous is negative and this positive negative are attracts and form sodium phosphide

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Answer:

cooking an egg is a chemical reaction because you can change the cooked egg into it original form

Explanation:

pls pls give brainliest pls

Answer:

Yes,Cooking an egg is a chemical reaction.

Explanation:

There are two types of reactions

Answer:

The statements that are true about unstable isotopes are:

They are radioactive.

They have an imbalance between protons and neutrons.

They may decompose.

Explanation:

An isotope is an atom that has the same number of protons as other atoms of the same element but a different number of neutrons. Some isotopes are stable, meaning they do not undergo any changes over time, while others are unstable or radioactive.

Unstable isotopes have an imbalance between the number of protons and neutrons in the nucleus, which makes them unstable and prone to breaking apart or decomposing. This process is called radioactive decay, and it can result in the emission of alpha or beta particles, gamma radiation, or other forms of energy.

The instability of the nucleus is due to the strong nuclear force that holds the nucleus together, which is overcome by the electrostatic repulsion between the protons. As a result, unstable isotopes are constantly trying to reach a more stable state by releasing energy in the form of radiation.

Because unstable isotopes can decompose, they have a limited lifespan, and their half-lives can vary from fractions of a second to billions of years. This property of unstable isotopes makes them useful in many fields, including medicine, geology, and nuclear energy.

Answer:

Explanation:

The statements that are true about unstable isotopes are:

They are radioactive.

They have an imbalance between protons and neutrons.

They may decompose.

Answer:

pppppp

Explanation:

Iridium forms metallic bonds, while mercury exhibits a combination of metallic and covalent bonding. These covalent interactions give rise to the low boiling point and weak intermolecular forces in liquid mercury.

Iridium (Ir) and mercury (Hg) exhibit different types of bonding based on their electronic configurations and properties.

Iridium is a transition metal belonging to Group 9 of the periodic table. It has a partially filled d-orbital in its atomic structure, which allows it to form metallic bonds. Metallic bonding occurs when the outer electrons of metal atoms are delocalized and form a "sea" of electrons that are free to move throughout the crystal lattice. This results in the characteristic properties of metals, such as high electrical and thermal conductivity, malleability, and ductility. Iridium forms metallic bonds with other iridium atoms, contributing to its solid, dense, and lustrous nature.

Mercury, on the other hand, is a unique element. It is a transition metal, but it exhibits characteristics of both metallic and covalent bonding. At room temperature, mercury exists as a liquid, which is highly unusual for a metal. This is because mercury atoms have a weak interatomic interaction, known as metallic bonding, similar to other metals. However, due to the presence of unpaired electrons in its 6s orbital, mercury can also form weak covalent bonds. These covalent interactions give rise to the low boiling point and weak intermolecular forces in liquid mercury.

In summary, iridium forms metallic bonds, while mercury exhibits a combination of metallic and covalent bonding.

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The process by which the molecules of the gas can be able to move is the process of diffusion.

We know that according to the Graham's law, the rate of the diffusion  of the gas is inversely proportional to the molar mass of the gas. When we open the bottles, the molecules of the perfume would begin to move.

As the bottle is opened, the molecules would escape from the bottle and then be able to travel through the room and get to where you are by the principle of diffusion.

Hence, the movement of the perfume is according to the Graham's law of diffusion in gases.

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Answer:

Mass of magnesium oxide formed = 35.1 g

Explanation:

Given data:

Mass of Mg = 20.9 g

Mass of O₂ = 15.2 g

Mass of magnesium oxide formed = ?

Solution:

Chemical equation:

2Mg + O₂     →   2MgO

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 20.9 g/ 24 g/mol

Number of moles = 0.87 mol

Number of moles of O₂:

Number of moles = mass/molar mass

Number of moles = 15.2 g/ 32 g/mol

Number of moles = 0.475 mol

Now we will compare the moles of MgO with magnesium and oxygen.

                Mg          :         MgO

                  2           :           2

                0.87        :         0.87

                  O₂         :         MgO

                     1         :            2

                   0.475   :        2/1×0.475 = 0.95  

Number of moles of MgO formed by Mg are less thus Mg will limiting reactant.

Mass of MgO:

Mass = number of moles × molar mass

Mass = 0.87 mol × 40.3 g/mol

Mass = 35.1 g

Answer:13.8

Explanation:

Answer:

The new volume of the gas is 156.25 mL.

Explanation:

According to Boyle's Law, at constant temperature and number of moles, the pressure and volume of a gas are inversely proportional.

So, we can use the following equation to solve for the new volume (V2):

P1V1 = P2V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

Substituting the given values:

(1.25 atm) x (250.0 mL) = (2.00 atm) x V2

Solving for V2:

V2 = (1.25 atm x 250.0 mL) / (2.00 atm)

V2 = 156.25 mL

Therefore, the new volume of the gas is 156.25 mL.

Answer:

aluminium reacts with sulfuric acid to produce aluminium sulfate and hydrogen gas according to the following equation: H2SO4 (aq) + Al (s) = Al2 (SO4)3 (aq) + H2 (g).

Answer:

0.0583g

Explanation:

The equation of the reaction is;

2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)

From the question, number of moles of HNO3 reacted= concentration × volume

Concentration of HNO3= 0.100 M

Volume of HNO3 = 20.00mL

Number of moles of HNO3= 0.100 × 20/1000

Number of moles of HNO3 = 2×10^-3 moles

From the reaction equation;

2 moles of HNO3 reacts with 1 mole of Mg(OH)2

2×10^-3 moles reacts with 2×10^-3 moles ×1/2 = 1 ×10^-3 moles of Mg(OH)2

But

n= m/M

Where;

n= number of moles of Mg(OH)2

m= mass of Mg(OH)2

M= molar mass of Mg(OH)2

m= n×M

m= 1×10^-3 moles × 58.3 gmol-1

m = 0.0583g

The simplified expression for the given expression is:40T^2 × T^98 × (4^181) / 4^67

Given expression : (4^-3)^-3 × (4^0)^-9 × (4^6)^-3 × (-4)^-49 × (2T)^2 × (T^2)^49 × (-4)^181 × 40To simplify the given expression, we use the following properties of exponents : For any real numbers a, b and n, we have ;a^-n = 1/a^n and a^n × a^m = a^(n+m)Let's simplify each term of the given expression one by one:(4^-3)^-3 = 4^(9) because when a negative exponent is raised to another negative exponent, it becomes positive. (4^-3)^-3 = 4^(-3×-3) = 4^(9)(4^0)^-9 = 4^0 = 1 because any number raised to the power of 0 is equal to 1(4^6)^-3 = 4^(-6×3) = 4^(-18) because when a negative exponent is multiplied by another negative exponent, it becomes positive.(-4)^-49 = -1/(4^49) because when a negative exponent is raised to another negative exponent, it becomes positive and also negative.(-4)^181 = (4^181) because when an odd negative power of a negative number is raised to another power, it becomes negative.40 = 40 as it is(2T)^2 = 4T^2(T^2)^49 = T^(2×49) = T^98(-49) = -49 as it is Now let's simplify the given expression:1 × 1/(4^49) × 4^(-18) × 40 × 4T^2 × T^98 × (4^181)40 and 4^-18 can be simplified and combined as follows:1/(4^49) × 4^(-18) × 40 = 40/(4^49 × 4^18) = 40/4^(49+18) = 40/4^67.

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The nucleus of an atom is positively charged and contains most of the mass if the atom.

An atom is the smallest particle of a an element that can take part in a chemical reaction.

Atoms are made up of other smaller sub-particles which are:

The protons and neutrons are found in the nucleus of an atom

The electrons are found regions around the nucleus.

Due to the positive charge of the protons, the nucleus of an atom are positively charged and is massive.

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Answer:

Socratic app

Explanation:

it will help you

Answer:

because they have a full outer electron shell

Explanation:

Answer:

Noble gases are unreactive because they have a full outer electron shell, making them very stable and unlikely to participate in chemical reactions. They have low reactivity and are odorless, tasteless, and colorless gases.

Explanation:

A) Keep temperature constant and increase the pressure of the reaction; reaction rate will increase.

The temperature and pressure of a reaction will affect the rate of reaction.

Pressure

Pressure and the rate of reaction have a direct relationship. This means that as one increases, so does the other. So, if the pressure increases. then the rate of reaction will also increase. This is due to the number of collisions. As pressure increases, the number of collisions between molecules increases. This causes the reaction to occur faster. Thus, the rate of reaction increases.

Temperature

Kinetic energy and temperature are proportional. This means that as temperature increases, so does kinetic energy. This leads to temperature and rate of reaction also having a direct relationship. So, temperature and rate of reaction increase and decrease together. This is due to the fact that when temperature increases, the energy of the molecules increases. This leads to an increased number of collisions. As stated above, more collisions lead to a faster reaction.

Answer:

1.6x10⁻⁶M

1.6x10⁻⁶m

0.1928ppm

192.8ppb

Explanation:

The first dilution of the solution is from 1mL to 15mL. The second from 2mL to 25mL and the third from 1.5mL to 250mL. That means molarity is:

50mM =

0.050M * (1mL / 15mL) * (2mL / 25mL) * (1.5mL / 250mL) = 1.6x10⁻⁶M

Molality is defined as the ratio between moles and kg. Assuming the density of the solution is 1kg/L, molality is 1.6x10⁻⁶m

ppm is the ratio between milligrams and Liters:

1.6x10⁻⁶mol / L * (120.5g /mol) * (1000mg / g) = 0.1928mg/L = 0.1928ppm

And ppb = 1000*ppm;

0.1928ppm*1000 = 192.8ppb

1. For the pair of half-reactions:

Pt2+(aq) + 2e- → Pt(s)    ... (1)

Sn2+(aq) + 2e- → Sn(s)    ... (2)

To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:

2(Pt2+(aq) + 2e-) → 2(Pt(s))

Sn2+(aq) + 2e- → Sn(s)

Combining the equations, we have:

2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)

The cell notation for this reaction is:

Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)

To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:

E°(Pt2+/Pt(s)) = +1.20 V

E°(Sn2+/Sn(s)) = -0.14 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V

Therefore, the standard cell potential for this reaction is +0.14 V.

2. For the pair of half-reactions:

Co2+(aq) + 2e- → Co(s)    ... (3)

Cr3+(aq) + 3e- → Cr(s)    ... (4)

To balance the number of electrons transferred, equation (4) can be multiplied by 2:

2(Co2+(aq) + 2e-) → 2(Co(s))

Cr3+(aq) + 3e- → Cr(s)

Combining the equations, we have:

2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)

The cell notation for this reaction is:

Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)

To calculate the standard cell potential (E°), we refer to the standard reduction potentials:

E°(Co2+/Co(s)) = -0.28 V

E°(Cr3+/Cr(s)) = -0.74 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V

Therefore, the standard cell potential for this reaction is -0.46 V.

3. For the pair of half-reactions:

Hg2+(aq) + 2e- → Hg (l)    ... (5)

Cr2+(aq) + 2e- → Cr(s)    ... (6)

The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:

2(Hg2+(aq) + 2e-) → 2(Hg (l))

Cr2+(aq) + 2e- → Cr(s)

Combining the equations, we have:

2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)

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The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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Answer: Aluminum reacts with oxygen to produce aluminum oxide

Explanation:

The conversion factor for the given chemical equation is 2:4.

To convert from moles of aluminum to moles of aluminum oxide, we can use the balanced chemical equation: \(4 Al+ 3 O_2\rightarrow 2 Al_2O_3\)

The coefficients in the balanced equation can be used as conversion factors. In this case, we want to find the ratio of moles of aluminum oxide to moles of aluminum.

From the balanced equation, we can see that:

- For every 4 moles of aluminum, we get 2 moles of aluminum oxide.

So, the proper conversion factor has 2 moles of aluminum oxide in the numerator and 4 moles of aluminum in the denominator.

Therefore, the conversion factor is:2 moles of aluminum oxide : 4 moles of aluminum.

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Answer:

methane

Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp

Answer:

The Humboldt Current or the peru current

Explanation:

If want to measure the mass of a fly in metrics use a scale or a balance.

The current international standard metric system and the one that is most generally used worldwide is the International System of Units (Système international d'unités, or SI). It is a development of Giorgi's MKSA system, with the meter, kilogram, second, ampere, kelvin, candela, and mole as its fundamental units.

A balance is used to estimate an object's mass for the majority of commonplace objects. The balance compares the target object to a known mass object. Digital scientific balances and beam balances, like a triple beam balance, are examples of several sorts of balances.

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The half-life of N₂O₅ at 70°C then it is 50s or 0.8min

Half life is the the interval of time required for one half of the atomic nuclei of a radioactive sample to decay

The first-order rate constant for the decomposition of N₂O₅ and reaction is

2N₂O₅(g) → 4NO₂(g)+O₂(g)

The half life is the time at which the concentration of  N₂O₅ is the half initial concentration that is [ N₂O₅ ] = 1/2 [ N₂O₅ ]₀

Using this same equation then

ln ([N₂O₅]) = -2kt + ln ([N₂O₅]₀)

We replace [ N₂O₅ ] by 1/2[ N₂O₅ ]₀ and solve for t

ln (1/2 [N₂O₅]₀) = -2kt + ln ([N₂O₅]₀) applying logarithmic property

ln 1/2 + ln([N₂O₅]₀) = -2kt + ln ([N₂O₅]₀)  solving for t and applying logarithmic property (ln 1/2 = ln 1 - ln 2 = 0 - ln 2 = - ln 2)

t = ln 2/2k

t = 50s or 0.8min

The half-life of N₂O₅ at 70°C then it is 50s or 0.8min

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40.34 grams of Fe(NO3)3 · 9 H2O are required to prepare 300.0 mL of a 0.333 M solution of Fe(NO3)3 · 9 H2O.

The term molarity is defined as the moles of a solute per liters of a solution. Molarity is also called as the molar concentration of a solution.

The molar mass of Fe(NO3)3 · 9 H2O is 403.9g/mol

Therefore, the moles of Fe(NO3)3 · 9 H2O present in 300ml of 0.333 M Solution = molarity × volume

=0.333 mol / L × 300ml × 10^-3 L/ml

=0.0999 moles

=0.0999 mol × 403.9g/mol

= 40.34 grams

40.34 grams of Fe(NO3)3 · 9 H2O are required.

Thus, 40.34 grams of Fe(NO3)3 · 9 H2O are required to prepare 300.0 mL of a 0.333 M solution of Fe(NO3)3 · 9 H2O.

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Answer:

39.119 g

Explanation:

1 mole of S has 32.065 g

=> 1.22 x 32.065 = 39.1193 or 39.119 g

The volume of a 1.96 M calcium chloride that must be diluted with water to prepare 761 mL of a 2.79 x 102 M chloride ion solution is 108,326.02mL.

The volume of a solution can be calculated using the following formula:

C₁V₁ = C₂V₂

Where;

According to this question, 1.96 M calcium chloride must be diluted with water to prepare 761 mL of a 2.79 x 10² M chloride ion solution. The initial volume can be calculated as follows:

1.96 × V = 279 × 761

1.96V = 212,319

V = 108,326.02mL

Therefore, 108,326.02mL is the volume of the solution.

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You could form approximately 5.8 grams of methanol (CH3OH) from the given gas mixture at STP.

Using the Ideal gas equation;

n = PV / RT

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

From the question;

nCO = n / 2

nH2 = n / 2

Then;

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n = 0.362 mol

nCO = n / 2 = 0.362 mol / 2 = 0.181 mol

nH2 = n / 2 = 0.362 mol / 2 = 0.181 mol

By stoichiometry;

methanol= nCO = 0.181 mol

Mass of methanol =  0.181 mol * 32.04 g/mol

= 5.8 g

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