what is the rate (in kilograms per second) at which the sun is currently converting hydrogen into helium?

Answer:magnetic attraction

Explanation:

It's C I just took the quiz mark me beainliest

Answer:

Explanation:not

Answer:

all i can accurately say is that 2 and 4 are both true

Except for salts of Metallic elements , ammonium, NH, most phosphates (PO43) and carbonates (CO32) are insoluble. Unless they are those from Group IA metals, all oxides are insoluble. Sulfides S2- are often insoluble.

Ammonium produced by industrial is used as fertilizers to the rate of 80%. In contrast to all of these uses, nitrogen is turned into chemicals, explosives, textiles, insecticides, dyes, and many other chemicals. It is also used to disinfect water sources.

High rates of ammonia in the air can result in rapid ocular, nose, throat, and respiratory tract burning as well as blindness, lung damage, or perhaps even death. Lower quantities of the substance can irritate the nose, throat, and induce coughing.

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The volume of NaOH required to reach the equivalence point in the titration of a strong acid is typically smaller than the volume of NaOH required to reach the equivalence point in the titration of a weak acid.

This is because the strong acid is more reactive and therefore requires less base to neutralize it.

In a titration, the volume of a base (such as NaOH) required to reach the equivalence point is determined by the strength of the acid being titrated.

Generally speaking, a stronger acid will require a smaller volume of base than a weaker acid to reach the equivalence point.

This is because the stronger acid is more reactive, and it therefore requires less base to neutralize it.

When titrating a strong acid with a base such as NaOH, the equivalence point is reached when the number of moles of the acid is equal to the number of moles of the base.

In this situation, a relatively small volume of base will be required to completely neutralize the acid.

On the other hand, when titrating a weak acid with NaOH, the equivalence point is reached when the pH of the solution reaches the pKa of the acid.

This requires a much larger volume of NaOH than is required for titrating a strong acid, as the weak acid is much less reactive and therefore requires a larger volume of base to neutralize it.

In summary, the volume of NaOH required to reach the equivalence point in the titration of a strong acid is typically smaller than the volume of NaOH required to reach the equivalence point in the titration of a weak acid.

This is because the strong acid is more reactive and therefore requires less base to neutralize it.

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Answer:

Choice A: approximately \(0.12\; \rm M\).

Explanation:

Note that the unit of concentration, \(\rm M\), typically refers to moles per liter (that is: \(1\; \rm M = 1\; \rm mol\cdot L^{-1}\).)

On the other hand, the volume of the two solutions in this question are apparently given in \(\rm cm^3\), which is the same as \(\rm mL\) (that is: \(1\; \rm cm^{3} = 1\; \rm mL\).) Convert the unit of volume to liters:

Calculate the number of moles of \(\rm H_2SO_4\) formula units in that \(0.02\; \rm L\) of the \(0.09\; \rm M\) solution:

\(\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V(\mathrm{H_2SO_4})\\ &= 0.02 \; \rm L \times 0.09 \; \rm mol\cdot L^{-1} = 0.0018\; \rm mol \end{aligned}\).

Note that \(\rm H_2SO_4\) (sulfuric acid) is a diprotic acid. When one mole of \(\rm H_2SO_4\) completely dissolves in water, two moles of \(\rm H^{+}\) ions will be released.

On the other hand, \(\rm NaOH\) (sodium hydroxide) is a monoprotic base. When one mole of \(\rm NaOH\) formula units completely dissolve in water, only one mole of \(\rm OH^{-}\) ions will be released.

\(\rm H^{+}\) ions and \(\rm OH^{-}\) ions neutralize each other at a one-to-one ratio. Therefore, when one mole of the diprotic acid \(\rm H_2SO_4\) dissolves in water completely, it will take two moles of \(\rm OH^{-}\) to neutralize that two moles of \(\rm H^{+}\) produced. On the other hand, two moles formula units of the monoprotic base \(\rm NaOH\) will be required to produce that two moles of \(\rm OH^{-}\). Therefore, \(\rm NaOH\) and \(\rm H_2SO_4\) formula units would neutralize each other at a two-to-one ratio.

\(\rm H_2SO_4 + 2\; NaOH \to Na_2SO_4 + 2\; H_2O\).

\(\displaystyle \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} = \frac{2}{1} = 2\).

Previous calculations show that \(0.0018\; \rm mol\) of \(\rm H_2SO_4\) was produced. Calculate the number of moles of \(\rm NaOH\) formula units required to neutralize that

\(\begin{aligned}n(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})}\cdot n(\mathrm{H_2SO_4}) \\&= 2 \times 0.0018\; \rm mol = 0.0036\; \rm mol\end{aligned}\).

Calculate the concentration of a \(0.03\; \rm L\) solution that contains exactly \(0.0036\; \rm mol\) of \(\rm NaOH\) formula units:

\(\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} = \frac{0.0036\; \rm mol}{0.03\; \rm L} = 0.12\; \rm mol \cdot L^{-1}\end{aligned}\).

Answer:B

Explanation:

The option that is not a natural resource but must be produced artificially is concrete.

The term natural resources has to do with the resources tat we can be able to exploit from nature. The may be found on the surface as well as in the oceans and in the depth of the ground.

A lot of the natural resources can be processed and made into something that can be used to generate more money. Thus we have procedure like the processing of metals in order to obtain building materials and the processing of wood for timber.

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The molecules of two liquids mix together and form a new liquid. However, the liquid formed might be miscible or immiscible.

When two liquids are mixed together it forms a new solution. The new liquid has the properties of both of the original liquids.

The formed liquid may either be miscible or immiscible depending upon the properties of the two liquids.

Miscible liquids become homogeneous solutions so that their composition would be uniform. This is done by the complete diffusion of both liquids.

But in the case of immiscible liquids, the solution forms two separate layers giving out heterogeneous solutions.

Therefore, the combination of 2 liquids gives a new solution that could either be homogeneous or heterogeneous.

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Answer:

HI

Explanation:

it is a very strong acid made by dissolving hydrogen iodide in water.

Answer: A.

Explanation: When light passes through a small hole, it creates an inverted image on the opposite side. In this case, since the arrow is pointing up, the inverted image will appear pointing down on the opposite wall. Furthermore, since the box has a hole on its left side, the inverted image will be shifted towards the left.

The final temperature is  -124Celsius

Charles's Law is a fundamental gas law that describes the relationship between the volume and temperature of a gas at constant pressure. It states that the volume of a given amount of gas is directly proportional to its absolute temperature, provided that the pressure and the number of particles are held constant.

Give that;

V1/T1 = V2/T2

V1 = 420 ml

T1 =  25.0 + 273 = 298 K

V 2 = 210 ml

T2 = ??

Thus;

V1T2 = V2T1

T2 = V2T1/V1

= 210 ml *  298 K/420 ml

= 149 K or -124Celsius

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Tritiated hydrogen (3H) differs from hydrogen (1H) in that -3H has 2 more neutrons than 1H.

Tritiated hydrogen (3H) is a radioactive isotope of hydrogen that contains two additional neutrons compared to the stable isotope of hydrogen, which is hydrogen-1 (1H). The atomic nucleus of hydrogen-1 consists of a single proton and no neutrons, while tritiated hydrogen (3H) has one proton and two neutrons in its nucleus.

The addition of two neutrons in tritiated hydrogen (3H) increases its atomic mass, making it heavier than hydrogen-1 (1H). The presence of extra neutrons also affects the stability and radioactive properties of tritiated hydrogen. The unstable nature of 3H leads to its radioactive decay over time, emitting beta particles in the process.

Due to its radioactive nature, tritiated.

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If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

To calculated the average atomic mass, we have to multiply the isotopes mass of each to the % abundance  then  add .

the formula for the calculation of average atomic mass :

Average atomic mass = ∑ ( isotope mass  × % of abundance )

Thus, If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

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The option that would lead to the formation of precipitation, release of energy or change in color  is : Chemical change

Chemical changes leads to the formation of precipitate in the form of bubbles, release of energy or change in color for example :

Hence we can conclude that The option that would lead to the formation of precipitation, release of energy or change in color  is : Chemical change

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The density of a cube of manganese metal with a side length of 1.0 cm is also 7.2 g/cm³.

To calculate the density of a cube of manganese metal with a side length of 1.0 cm, we can use the formula:
Density = mass/volume
Since we know the density of the larger cube (7.2 g/cm3), we can use this information to find the mass of the smaller cube.
The volume of the smaller cube is (1.0 cm)³ = 1.0 cm³.
To find the mass, we can use the relationship:
Density = mass/volume

Rearranging this formula, we get:
Mass = density x volume
Substituting in the values we know, we get:
Mass = (7.2 g/cm³) x (1.0 cm³) = 7.2 g
Now that we know the mass of the smaller cube is 7.2 g, we can use the same formula to calculate its density:
Density = mass/volume = 7.2 g / (1.0 cm³) = 7.2 g/cm³

Therefore, the density of a cube of manganese metal with a side length of 1.0 cm is also 7.2 g/cm³.

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21) The correct description of the compounds are options a b c.

14) The correct chemical names are b c d

11) Li forms an ionic compound with fluorine

4) The ending of name (c) would differentiate the two compounds.

The functional group on the chain is carboxyl (a)

We know that the structure of the compound would have to do with the way that the compound can be written. In this case, we have the compound that have been shown and then we have some statements about the molecules.

We must note that the structures show us how the atoms that are in the compounds can be arranged and then we can be able to deduce the structure of the molecule that has been shown.

The compound on the right hand side is a cyclic compound while the compound on the left hand side is a long chain compound. We can now be able to count up the number of the hydrogen and the carbon atoms that are present in each of the compounds.

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Answer:

\(0.30molNH_3\)

Explanation:

Hello there!

In this case, since the reaction for the formation of ammonia is:

\(3H_2+N_2\rightarrow 2NH_3\)

We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:

\(0.15molN_2*\frac{2molNH_3}{1molN_2}\)

And the result is:

\(0.30molNH_3\)

Best regards!

The frequency of a photon absorbed by a hydrogen atom if the atom undergoes a transition from n1 is (c/λ)(1/h)

The frequency of a photon absorbed by a hydrogen atom during a transition from n1 to n2 can be calculated using the formula:
ΔE = hf = hc/λ
Where ΔE is the change in energy of the electron in the hydrogen atom during the transition, h is Planck's constant, f is the frequency of the photon, c is the speed of light, and λ is the wavelength of the photon.
The energy change of the electron in the hydrogen atom during the transition from n1 to n2 is given by:
ΔE = -13.6 eV ((1/n2^2) - (1/n1^2))
Substituting the value of ΔE into the first equation, we get:
f = ΔE/h = (hc/λ)/h = (c/λ)(1/h)
Thus, the frequency of the photon absorbed by a hydrogen atom during a transition from n1 to n2 can be calculated using the formula above. It is important to note that the frequency of the photon absorbed depends on the specific values of n1 and n2, as well as the properties of the hydrogen atom itself.

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Answer:

the eye socket

Explanation:

the area around the eye is called the eye socket or the eye orbit.

Answer:

False. Answer in pic above

In fact protons have no role in chemical reactions. The regrouping of atoms itself forms the new products in chemical reactions. The reactions involves the loss/gain or sharing of electrons.

A chemical reaction is a chemical change in which two or more atoms combine together to form a new product or a compound decomposes to form its constituent compounds. This  involves breaking or making of bonds.

In a chemical reaction, no change occurs in the nuclear composition but the valence electrons are involved in the reaction. Atoms loss or gain electrons or share valence electrons with other atoms to form ne compounds.

The electrostatic force of attraction or the overlapping of atomic orbitals make the new products in a chemical reaction. Hence, the statement is false.

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Answer:

I think what goes in the blank is (sources)

Explanation:

sounds are produced by sources which vibrate.

Answer:

Mass

Explanation:

The value of the equilibrium constant is 1.99 × \(10^-^5^0\) .

Given:

Concentration of \(O_2 = 1.6\) × \(10^-^2 M\\\)

Concentration of \(O_3 = 2.86\) × \(10^-^2^8 M\)

A chemical reaction known as an equilibrium reaction occurs when the reactants remain in a stable condition both during and after the reaction.

The given balanced equilibrium reaction is,

\(3O_2 (g) = 2O_3 (g)\)

The expression for equilibrium constant will be,

\(K_c = \frac{[O_3] ^2}{[O_2]^3}\)

Now put all the given values in this formula, and we get

\(K_c = \frac{(2.86 * 10^-^2^8] ^2}{[1.6 * 10 ^-^2]^3}\)

\(K_c = 1.99\) × \(10^-^5^0\)

Therefore, the value of the equilibrium constant is 1.99 × \(10^-^5^0\) .

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Answer:

with what?

Explanation:

Answer:

trigonal pyramidal

Explanation:

In the case of water.

The molar mass of a compound is the sum of the atomic masses of all the atoms present in one molecule of the compound. the molar mass of manganese hydroxide is 88.94 g/mol.

To calculate the molar mass of manganese hydroxide, we need to find the atomic masses of each of the elements and add them up in the correct proportions.

The atomic mass of manganese (Mn) is 54.94 g/mol.

The atomic mass of hydrogen (H) is 1.01 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol.

The formula for manganese hydroxide is Mn(OH)₂, which means there are two hydroxide ions (OH⁻) present for every one manganese atom.

To calculate the molar mass of manganese hydroxide, we add up the atomic masses of all the atoms present in one molecule of the compound: Molar mass of Mn(OH)₂ = (atomic mass of Mn) + 2(atomic mass of O) + 2(atomic mass of H) = 54.94 g/mol + 2(16.00 g/mol) + 2(1.01 g/mol) = 88.94 g/mol

Therefore, the molar mass of manganese hydroxide is 88.94 g/mol.

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1. Soil serves as a:

medium for plant growth,

regulator of water supplies,

recycler of raw materials,

habitat for soil organisms, and.

landscaping and engineering medium.

2. Soil organisms, which range in size from microscopic cells that digest decaying organic material to small mammals that live primarily on other soil organisms, play an important role in maintaining fertility, structure, drainage, and aeration of soil.

3. Advances in watershed, natural resource, and environmental sciences have shown that soil is the foundation of basic ecosystem function. Soil filters our water, provides essential nutrients to our forests and crops, and helps regulate the Earth's temperature as well as many of the important greenhouse gases.