According to the conservation of energy the total mechanical energy of a system is constant, meaning that energy cannot be created or destroyed but can only be transformed from one form to another.
In the case of a magnet falling through a loop, the mechanical energy is transformed from potential energy (due to the magnet's position above the loop) to kinetic energy (due to the magnet's motion).
The speed of the magnet falling in a loop is directly related to the amount of potential energy it has at the start of its fall. The higher the magnet is placed above the loop, the greater its potential energy, and the faster it will fall due to gravity. This is because the potential energy is transformed into kinetic energy as the magnet falls, and the kinetic energy increases the speed of the magnet.
The distance traveled by the magnet is also related to its initial potential energy. The higher the magnet is placed above the loop, the greater its potential energy, and the farther it will travel before coming to a stop. This is because the potential energy is transformed into kinetic energy, which allows the magnet to move a greater distance before it is completely converted into other forms of energy, such as heat due to friction.
Therefore, there is a direct relationship between the speed of the magnet falling in a loop and the distance traveled per conservation of energy. The higher the initial potential energy of the magnet, the faster it will fall and the farther it will travel before coming to a stop.
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Suppose you throw a baseball straight downward so that initially it has 15 J of gravitational potential energy and 200 J of kinetic energy. How much energy does the ball lose by the time it hits the ground
A. 215 J
B. 200 J
C. 15 J
D. 0 J
PLZ TELL ME THE ANSWER AS QUICK AS POSSIBLE :(
i need help with this too:( if u found out the answer lmk
A box of books weighing 325 N is shoved across the floor by a force of 475 N exerted downward at an angle of 35° below the horizontal. (a) If ????k between the box and the floor is 0. 55, how long does it take to move the box 5. 80 m starting from rest? s (b) What is the maximum coefficient of friction between the box and the floor that allows the box to move from this applied force.
The net forces on the box acting perpendicular and parallel to the floor are
∑ F[perp] = F[normal] - 325 N + (475 N) sin(-35°) = 0
∑ F[perp] = (475 N) cos(-35°) - F[friction] = ma
where m is the mass of the box and a is its acceleration.
Solve for F[normal] :
F[normal] = 325 N + (475 N) sin(35°) ≈ 597 N
Then the frictional force has magnitude
F[friction] = 0.55 F[normal] ≈ 329 N
and so
60.5 N ≈ (325 N) a/g
(note that sin(-35°) = -sin(35°), cos(-35°) = cos(35°), and mg = 325 N so m = (325 N)/g)
Solve for a :
a = (60.5 N) / (325 N) g ≈ 1.82 m/s²
(a) Assuming this acceleration is constant, starting from rest, the box achieves a final velocity v such that
v² = 2a∆x
v² = 2 (1.82 m/s²) (5.80 m)
⇒ v ≈ 4.60 m/s
which happens in time t such that
v = at
4.60 m/s = (1.82 m/s²) t
⇒ t ≈ 0.177 s
(b) Let µ be the coefficient of static friction. The box just begins to slide if the magnitude of the parallel component of the applied force matches the magnitude of friction, i.e.
∑ F[para] = (475 N) cos(-35°) - F[friction] = 0
We have
F[friction] = µ F[normal] = (597 N) µ
so that
(597 N) µ = (475 N) cos(35°)
⇒ µ ≈ 0.651
The north pole of a bar magnet is rapidly introduced into a solenoid at one end (say A). Which of the following statements correctly depicts the phenomenon taking place?
(a) No induced emf is developed.
(b) The end A of the solenoid behaves like a south pole.
(c) The end A of the solenoid behaves like north pole.
(d) The end A of the solenoid acquires positive potential.
Answer:
The correct option is;
(b) The end A of the solenoid behaves like a north pole
Explanation:
According to Lenz's law we have that the induced emf direction in the solenoid due to the rapid introduction of the bar magnet will be such that the electric current induced will have a resultant magnet field that will oppose to the movement of the north pole of the bar magnet that resulted in the magnetic field
Therefore, the opposing magnetic pole to the north pole of a magnet is a north pole and the solenoid end A will act like the north pole.
A skater with a mass of 50 kg is moving at a speed of 5 m/s. Away is their kinetic energy?
how will the momentum of the blocks after the collision compare to the momentum of the blocks before the collision? *
Momentum is conserved for any collision in an isolated system. Before and after the collision, the collection of items in the system had an equal amount of total momentum.
What does physics define as momentum?
Momentum is characterized as the intensity of a body's motion.
As momentum relies on both velocity and the direction of the body's motion, it is quantified by "mass velocity".
What is the connection between collision and momentum?
During collisions between objects, momentum is a relevant concept. The total momentum before a collision between two objects equals the total momentum after the impact (in the absence of external forces). The law of conservation of momentum is this. It holds true in every collision.
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A ball has 17 J of kinetic energy and its mechanical is 25 J
If the ball has a mass of 3.2 KG what is it’s height above ground?
Answer:
0.255m
Explanation:
The total mechanical energy of the ball is given 25 J. The potential energy of the ball is 8 J. Then, the height of the ball above the ground is 0.25 m.
What is kinetic energy ?Kinetic energy of an object is the energy generated by virtue of its motion whereas potential energy is generated by virtue of its position at a height from the ground.
The sum of kinetic and potential energy of the object is called its mechanical energy.
given Ke of the ball = 17 J
mechanical energy = 25 J
then potential energy = 25 J - 17 J = 8 J.
We have the relation between potential energy, mass and height h as :
p = mgh .
given the mass m = 3.2 kg
g = 9.8 m/s²
then, h = p / (mg)
h = 8 J / (3.2 kg× 9.8 m/s² )
= 0.25 m.
Therefore, the height of the ball above the ground is 0.25 m.
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How many moles of a gas sample are in a 5.0 l container at 373 k and 203 kpa?
In a 5.0 L container at 373 K and 203 KPa there is 0.327 mol of a gas sample.
Ideal gas lawThe number of moles of a gas sample in a container can be calculated using the ideal gas law, which is represented by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
Given the volume (V) of the container as 5.0 L, the temperature (T) as 373 K, and the pressure (P) as 203 kPa, we can rearrange the ideal gas law equation to solve for the number of moles (n) as follows:
n = PV/RT
Substituting the given values into the equation, we get:
n = (203 kPa)(5.0 L)/ (8.314 L*kPa/K*mol)(373 K)
n = 1015 kPa*L / (8.314 L*kPa/K*mol)(373 K)
n = 0.327 mol
Therefore, the number of moles of the gas sample in the 5.0 L container at 373 K and 203 kPa is 0.327 mol.
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a running back with a mass of 70 kg and a speed of 9 m/s collides with, and is held by, a 105-kg defensive tackle going in the opposite direction. how fast must the tackle be going before the collision for their speed afterward to be zero?
If a running back with a mass of 70 kg and a speed of 9 m/s collides , then speed of tackle before the collision is 6 m/s .
Let the speed of the defensive tackle before the collision be = v .
The momentum of the system before the collision is given by the momentum of the running back,
⇒ that is ; 70 × 9 = 630 Kgm/s , and
the momentum of the tackle is , (-105 kg) × (v m/s) ;
After the collision, the momentum of the system must be zero, so the momentum before the collision must equal the momentum after the collision ;
⇒ (70 × 9) + (-105 × v) = 0 ;
Solving for v, we get ;
⇒ v = 630/105 = 6 m/s
Therefore , the defensive tackle must be going 6 m/s in the opposite direction before the collision for the two players to come to a stop after the collision.
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A gun can fire a bullet at 540 m/s. If the gun is aimed at an angle of 55o above the horizontal and fired, what will be the horizontal and vertical components of the gun's velocity?
Answer:
Explanation:
The initial vertical velocity is 540sin55° = 442.342103... 442 m/s
The initial horizontal velocity is 540cos55° = 309.731275... 310 m/s
In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.
What is the volume of Sulfur that weights 150 g. The density of Sulfur is 2 g/cm3.
Answer:
75 cm³Explanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\\)
From the question we have
\(volume = \frac{150}{2} = 75 \\ \)
We have the final answer as
75 cm³Hope this helps you
A galaxy with thin spiral arms and a small spherical central bulge would be a type?a. Sab. SBac. Scd. SBce. S0
A galaxy with thin spiral arms and a small spherical central bulge would be a type is Sc. Option C.
Spiral galaxies have a central stellar bulge surrounded by a disk containing arms that form a spiral structure. Stars in the bulge of spiral galaxies tend to be older and redder than others. There is also a much darker, roughly spherical halo of stars surrounding the disk.
Central bulge. Surrounding the core is a vast bulge of stars that are roughly spherical in shape and composed mostly of Population II stars but relatively rich in heavy elements. Spiral galaxies typically have rotating disks with spiraling arms that bend from a dense central region. The Milky Way is a spiral galaxy.
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The resistance to the motion of an object is
Answer:
Inertia
Explanation:
Part of Newton's Laws of Motion
a car moving at a steady 10 m/s on a level highway encounters a depression that has a circular cross-section with a radius of 30 m. the car maintains its speed as it drives through the depression. what is the normal force exerted by the seat of the car on a 60 kg passenger when the car is at the bottom of the depression?
To calculate the normal force exerted by the seat of the car on the passenger when the car is at the bottom of the depression, we need to consider the forces acting on the passenger.
At the bottom of the depression, the passenger experiences an inward net force directed towards the center of the circular path. This force is provided by the normal force exerted by the seat. To determine the normal force, we need to consider the centripetal force acting on the passenger.
The centripetal force can be calculated using the formula:
F_c = m * a_c
where F_c is the centripetal force, m is the mass of the passenger, and a_c is the centripetal acceleration.
The centripetal acceleration is given by:
a_c = v² / r
where v is the velocity of the car and r is the radius of the circular depression.
Given:
Velocity of the car (v) = 10 m/s
Radius of the depression (r) = 30 m
Mass of the passenger (m) = 60 kg
First, we calculate the centripetal acceleration:
a_c = (10 m/s)² / 30 m = 100 m²/s² / 30 m = 10/3 m/s²
Now, we can calculate the centripetal force:
F_c = (60 kg) * (10/3 m/s²) = 200 N
Since the normal force exerted by the seat is equal to the centripetal force, the normal force is 200 N. Therefore, the normal force exerted by the seat on the 60 kg passenger at the bottom of the depression is 200 N.
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What is the name of the part of the wave that is labeled -
answer: amplitude
the ones who have to watch the video
Answer:
amplitude
Explanation:
sound travel and it amplifies
How does the mass available to build planets change with distance from the sun?
More mass is available closer to the star and less far away because the disk density decreases with distance from the star. The temperature also decreases with distance, which can cause ice to form, increasing the solid mass available for planet formation. Additionally, the strength of the radiation and the intensity of the stellar wind also decrease with distance, which can also affect the amount of mass available to build planets.
However, the mass available for planet formation also depends on the protoplanetary disk's age and composition and the planets' presence, which can affect the distribution of the disk's mass.
Suppose we send a beam of 100ev electrons through a single slit that is 1um wide. What is the electron beam's width after traveling 10m?
The width of the electron beam after traveling 10m is 122.7 mm.
The width of the electron beam after traveling 10m when a beam of 100ev electrons is sent through a single slit that is 1um wide.
Diffraction is the phenomenon of a wave, such as light or sound, spreading out when it encounters an obstacle or a slit with a size similar to its wavelength.
It is also known as Huygens-Fresnel principle.The formula to calculate the diffraction pattern of a single slit is given byd sin θ = λ,
where d is the width of the slit, θ is the angle between the incident light and the diffracted light, and λ is the wavelength of the light used.
In this case, we will consider electrons, so we need to use the de Broglie wavelength equation. The de Broglie wavelength (λ) of an object with mass (m) and velocity (v) is given byλ = h / mvwhere h is Planck's constant.
We can rewrite this equation asλ = 12.27 / √Ewhere E is the energy of the electron in eV. In this case, E = 100 eV, soλ = 12.27 / √100 = 1.227 nm.
Substitute the value of λ in the diffraction equation and solve for the angleθ = sin-1(λ/d)θ = sin-1(1.227 nm / 1000 nm) = 0.0721 rad.
To find the width of the beam after traveling 10 m, we need to use the formula for the diffraction pattern of a single slit, which is given byw = λL / dwhere L is the distance traveled by the beam.
In this case, L = 10 m and d = 1 µm = 10-6 m. Substituting the values, we get = (1.227 nm)(10 m) / (10-6 m) = 122.7 mmTherefore, the width of the electron beam after traveling 10m is 122.7 mm.
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Do you think the government should ever get involved in limiting population? Why or why not?
Answer:
No!!
Explanation: I think the government shouldn't get involved with limiting population!! i think that as long as you can care and supply your family it is your choice how larger your family is!
Mike and Joe take turns pitching a baseball, and Drew catches it. Mike can throw the ball harder than Joe can.
Which of the following statements is true?
Answer:
The ball travels faster when Mike throws it.
Explanation:
Mike throws the ball harder, with a greater force, so the ball travels faster when Mike throws it than when Joe does.
2. What is the potential energy of a 3 kg ball that is on the ground?
The potential energy of a 3 kg ball that is on the ground is zero.
What is the potential energy of a ball on the ground?Zero ,It will have no kinetic energy since it is not moving, and because it is laying on the ground, it will also have no potential energy. This is equivalent to the ground's zero potential energy.energy potential = massHeight, 9.8 m/s of gravity3 kilogrammes is the size of you. I think you need to increase this by 9.8 and then convert this to grammes (3000g). Since the ball is on the ground and you are at zero height, your potential energy is also zero.A 3 kilogramme body on a planet's surface has 54 joules of potential energy.To learn more about potential energy refer to:
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what centripetal acceleration is needed to keep a 1 kg ball moving in a circle of radius 2 m at a speed of 5 m/s
We will have the following:
First, we know that the centripetal acceleration is given by:
\(a_c=\frac{v^2}{r}\)So, the centripetal acceleration is:
\(a_c=\frac{(5m/s)^2}{(2m)}\Rightarrow a_c=\frac{25}{2}m/s^2\)\(\Rightarrow a_c=12.5m/s^2^{}\)How will you explain the effect of the absorption and release of heat on the kinetic energy and arrangement of particles of matter?
According to the kinetic theory of matter, changes in heat energy allow for phase transitions between solids, liquids, and gases.
When something is heated, the particles inside move faster and have more energy. When an object warms up, its atoms and molecules gain kinetic energy. When something is heated, its constituent atoms or molecules accelerate in their motion. Matter's kinetic energy can be quickly and easily increased.
When an object warms up, its atoms and molecules gain kinetic energy. The atomic or molecular motions of matter increase with temperature. Lifting a particle's kinetic energy is a breeze. When a substance absorbs heat, the inter-particle bonds in it weaken and break, resulting in a phase transition. If the particles aren't moving faster, there can't be any more heat.
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A man is traveling from the back of a boat to the front of the boat at 2.0 m/s while the boat itself is traveling at 12.0 m/s toward a dock. How far will the man move across the boat in 4.0 seconds? Relative to the dock, how far will the man move in 4.0 seconds?
Based on the relative velocity of the man with respect to the boat and the dock:
Distance covered in 4.0 seconds relative to the boat = 8 mDistance covered in 4.0 seconds relative to the dock = 56 mWhat is relative velocity?Relative velocity is the velocity of a body relative to another body which serves as a reference point.
Relative velocity is a vector.
Considering the velocity of the man and the boat:
The relative velocity of the man with respect to the boat = 2.0 m/s
Distance covered in 4.0 seconds relative to the boat = 2.0 m/s * 4.0 s
Distance moved = 8 m
Relative velocity of the man with respect to the dock = 12 + 2 = 14 m/s
Distance covered in 4.0 seconds relative to the dock = 14.0 m/s * 4.0 s
Distance moved = 56 m
In conclusion, the relative velocity is velocity with respect to a reference point.
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The radius of curvature of a rear- view mirror in a car is 4m. If a truck is behind the
car, located 5m from the rear-view mirror of the car. Calculate the size of the image
relative to the size of the truck and also find the position and nature of the image formed
The virtual image created by the rear-view mirror of the truck is upright and appears 0.67 times smaller than the actual size of the truck. It is located at a distance of 3.33m from the mirror.
To calculate the size and position of the image formed by the rear-view mirror, we can use the mirror formula and magnification formula.
The mirror formula is given by:
1/f = 1/v + 1/u
Where:
f = focal length of the mirror
Let v represent the image distance, which is the distance between the mirror and the location where the image is formed.
In this scenario, the rear-view mirror functions as a convex mirror with a radius of curvature (R) of 4m. The focal length (f) of a convex mirror is half the radius of curvature, which in this case is 2m.
The distance from the object to the mirror is referred to as the object distance (u), and it is specified as 5m. Our goal is to determine the image distance (v).
Using the mirror formula:
1/2 = 1/v + 1/5
Rearranging the equation:
By applying the formula
1/v = 1/2 - 1/5,
we can simplify it to
5/10 - 2/10, which results in 3/10.
Taking the reciprocal:
v = 10/3 = 3.33m
Using the magnification formula, we can determine the relative size of the image compared to the size of the truck.
Magnification (m) = -v/u
Where:
m = magnification
v = image distance
u = object distance
Plugging in the values:
m = -(3.33/5) = -0.67
The negative sign indicates that the image formed by the convex mirror is virtual and upright, which signifies that it appears smaller than the actual object. Consequently, the size of the image is 0.67 times smaller compared to the size of the truck.
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the condition in which certain colors are diminished as depth increases is called:
The condition in which certain colors are diminished as depth increases is called color attenuation. This refers to a phenomenon where colors become less vibrant and fade as the distance between the observer and the object increases.
This happens due to the scattering of light by particles in the atmosphere, which reduces the intensity of the light and alters the color perception of the viewer.
As a result, the colors of objects that are far away appear less vivid and washed out, while those that are closer look brighter and more saturated. This effect is particularly noticeable in outdoor scenes where the distance between objects is significant.
The degree of color attenuation depends on the distance between the viewer and the object, the angle of incidence of the light, the quality of the atmosphere, and the presence of any obstructions that might block or reflect light.
Color attenuation is a common phenomenon in outdoor photography and can be used to create depth and dimension in images. Photographers often use color correction techniques to compensate for the loss of color and contrast that occurs when shooting at a distance.
In conclusion, color attenuation is the condition in which certain colors are diminished as depth increases. It is caused by the scattering of light by particles in the atmosphere, which reduces the intensity of light and alters the color perception of the viewer. This phenomenon is particularly noticeable in outdoor scenes and is commonly observed in photography.
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A block that is 5kg slides on a horizontal frictionless table with an initial velocity of 5 m/s. It then compresses a spring with a spring constant of 200 N/m and is brought to rest. How much is the spring compressed from equilibrium?
Answer:
The spring is compressed by approximately 0.79 meters from its equilibrium position.
Revisiting the Anticipation Guide Review your original response to this statement from the Anticipation Guide on page 6: Each person in a family has the same traits. There are no differences in traits between parents and offspring or among siblings. Do you agree or disagree with this statement now? What evidence supports your ideas about the statement?
2. Sarah pulls on one end of a rope with a force of 100 N, and her friend Jane pulls on the other end with a force of 100 N. (a) What happens to the rope and why? (b)Observe the given picture and identify P, W, N and f. (c) When does the box move? How can we move this box with less effort? P (a) 10 W N (b)
Answer: (a) When Sarah pulls on one end of the rope with a force of 100 N, and her friend Jane pulls on the other end with an equal force of 100 N, the rope experiences a tension force. The tension force acts along the length of the rope, pulling it in opposite directions from each end. As a result, the rope remains taut and does not move in any particular direction.
(b) Without the given picture, it's not possible to identify specific labels for P, W, N, and f. However, I can provide explanations of what these labels generally represent:
P: P typically represents the symbol for force, which can be applied in various directions.(c) The box will move when an external force overcomes the opposing forces acting on it, such as friction and the normal force. If the applied force (P) is greater than or equal to the sum of the frictional force and the normal force, the box will start to move. To move the box with less effort, one can reduce the frictional force. This can be achieved by using lubricants or reducing the roughness of the surfaces in contact, thereby minimizing the resistance to motion. Additionally, applying the force at an angle or using mechanical advantage, such as using a lever or pulley system, can also help in moving the box with less effort.
A ball is shot up from the ground with an initial vertical velocity of 30 m/s. What is the velocity of the ball as it reaches its highest point
Answer:
0 m/s
Explanation:
At the highest point, the vertical velocity is 0 m/s.
There's no horizontal velocity.
So the total velocity at the highest point is 0 m/s.
(c)
All European countries signed the Paris Climate Agreement in 2016.
In the future, some European countries will only allow electric vehicles.
Suggest how this is likely to affect methods of electricity generation in these countries.
There will be a huge electricity generation needs in these countries in the upcoming future.
All European countries signed the Paris Climate Agreement in 2016. In the future, some European countries will only allow electric vehicles. This will increase the need of generation of more electricity in these countries as they are fully dependent on electricity for their movement from one place to another and for their survival also, electricity plays a vital role in their life. From their room heaters to cars, everything will operate on electricity, this will reduce the pollution but increase their dependency on electricity, and hence it will put electricity companies in pressure to produce more electricity. By this we consider that there will be a huge electricity generation needs in these countries in the upcoming future.
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The speed of light is 3 x 10^8 m/s. Find the wavelength for a typical AM radio wave with a frequency of 600 kHz. Answer in units of m.
Answer:
wavelength = (3×10^8 m/s)(6×10^5 Hz)
= 1.8×10^14 m