what should i apply after ordinary peeling solution

Answers

Answer 1

After using an ordinary peeling solution, it is important to apply a moisturizer or hydrating serum to the skin.


The ordinary peeling solution is a chemical exfoliant that helps remove dead skin cells and impurities from the surface of the skin. It is a powerful treatment that can leave the skin feeling dry and sensitive. Therefore, it is important to follow up with a hydrating product to restore the skin's moisture barrier and prevent irritation. The peeling solution contains alpha hydroxy acids (AHAs) and beta hydroxy acids (BHAs) that work to exfoliate the skin. These acids dissolve the bonds between dead skin cells, making them easier to slough off. This helps to unclog pores, smooth out rough texture, and even out skin tone .However, AHAs and BHAs can also strip away the skin's natural oils, leading to dryness and irritation. To counteract this, it is recommended to apply a moisturizer or hydrating serum after using the peeling solution. This will help to soothe and nourish the skin, while also locking in moisture and restoring the skin's natural pH balance.


In summary, it is important to apply a moisturizer or hydrating serum after using an ordinary peeling solution to prevent dryness and irritation. This will help to restore the skin's moisture barrier and keep it looking healthy and radiant.

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Related Questions

5. Which of the following are elements? (Select all that apply.)
Na
Do
H20
КСІ
c

Answers

Answer:

all ecept do and KCI i believe

Explanation:

suppose you burn a 2.5 g sample of potato chips. you use the heat given off from that process to heat 34.2 g of water from 17.4 oc to 20.7 oc. what is the caloric value (in kcal/g) of the potato chips?

Answers

0.05104 kcal/g is the calorific value of potato chips

Let the calorific value of potato be H cal/g

so, the heat of potato chips is 2.5g × H =2.5H

The specific heat of water is 1 cal g⁻1 °C⁻¹

The heat of water = 31.9 g × 1 cal g⁻1 °C⁻¹ ( 21.3-17.3)°C

                              = 31.9 × 4 cal

                              = 127.6 cal

hence, 2.5H = 127.6 cal

H = 127.6/2.5 = 51.4 cal/g = 0.05104 kcal/g

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How many moles do you have if you have 144 L of a gas at SATP?

How many moles do you have if you have 144 L of a gas at SATP?

Answers

Answer

moles = 5.81 mol

Explanation

Given:

Volume = 144 L

AT SATP

1 mole = 24.4651 L

Solution:

1 mole = 24.4651 L

x mole = 144 L

x = 144/24.4651

x = 5.8 mol


How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?

Answers

Answer:

150000 J

General Formulas and Concepts:

Chemistry

Thermodynamics

Specific Heat Formula: q = mcΔT

q is heat (in J)m is mass (in g)c is specific heat (in J/g °C)ΔT is change in temperature (in °C or K)

Math

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightExplanation:

Step 1: Define

Identify variables

[Given] m = 225 g

[Given] c = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] q

Step 2: Solve for q

Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)Multiply:                                                                                                           q = 150436 J

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

The unit for molar mass is

The unit for molar mass is

Answers

The answer would be D, kg/mol.

Which of the following are conjugate acid/base pairs? Select all that apply. H2PO 4−and HPO4^2−H2CO3 and CO 3^2−
HCl and NaOH H3O + and OH − HCl and Cl−

Answers

A conjugate acid-base pair is the pair of two compounds which differ by the presence of a proton. An acid will donate protons to a base and become a conjugate base. A base will accept protons and become a conjugate acid.Conjugate acid/base pairs are as follows:H2PO4− and HPO42−H2CO3 and CO32−HCl and Cl−H3O+ and OH−Explanation:

H2PO4− and HPO42−H2PO4− can donate a proton to become HPO42− and the latter can accept a proton to become H2PO4−.H2CO3 and CO32−H2CO3 can donate a proton to become CO32− and the latter can accept a proton to become H2CO3.HCl and Cl−HCl can donate a proton to become Cl− and the latter can accept a proton to become HCl.H3O+ and OH−H3O+ can donate a proton to become OH− and the latter can accept a proton to become H3O+.Therefore, the following are conjugate acid/base pairs:H2PO4− and HPO42−H2CO3 and CO32−HCl and Cl−H3O+ and OH−

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Can you answer my question in SCIENCE... Directions: Below are the reactants and products of photosynthesis. Choose the chemical symbol that matches the word.​

Can you answer my question in SCIENCE... Directions: Below are the reactants and products of photosynthesis.

Answers

Answer:

Water :H2O

Carbon dioxide :CO2

Oxygen :O2

Glocuse :C6H12O6

Answer:

water = H20

carbon dioxide = CO2

oxygen = 02

glucose= C6H1206

Explanation:

A cell membrane is more flexible than a brick wall. Why might many cells benefit from a flexible cell membrane?

Answers

A cell membrane is more flexible than a brick wall. Why might many cells benefit from a flexible cell membrane because it allows them to survive in and out of the cell.

The cell is surrounded by a membrane called as cell membrane . cell membrane is a semipermeable membrane. semipermeable membrane is the type of membrane which allows solvent particles to pass through it . or some molecules or ion . Therefore , many cells benefited by cell membrane as they can pass through it.

Thus, A cell membrane is more flexible than a brick wall. Why might many cells benefit from a flexible cell membrane because it allows them to survive in and out of the cell.

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In the reaction: I2 + ClO3− → IO3− + Cl−, indicate:a. the element that is oxidized: b. the element that is reduced: c. the reducing agent: d. the oxidizing agent: e. Balance the reaction

Answers

1) Which element is oxidized

\(I_2+ClO^-_3\rightarrow IO^-_3+Cl^-\)

Oxidation numbers

I2: 0

ClO3-: for Cl +5 and for O is -2

IO3-: for I is +5 and for O -2

Cl-: -1.

According to the oxidation number

a. Iodine (I) has been oxidized. It changed from 0 to +5.

b. Chlorine has been reduced. It changed from +5 to -1

2) reducing agent and oxidizing agent

c. A reducing agent donates electrons. In the reaction, Iodine is the reducing agent.

d. An oxidizing agent accepts electrons. In the reaction, Chlñorine is the oxidizing agent.

3) Balancing the chemical equation

\(I_2+ClO^-_3\rightarrow IO^-_3+Cl^-\)

Step 1: break the reaction into two half-reactions.

Oxidation half-reaction

\(I_2\rightarrow IO^-_3\)

Reduction half-reaction

\(ClO^-_3\rightarrow Cl^-\)

Step 2: balance all elements EXCEPT for hydrogen and oxygen

Oxidation half-reaction

\(I_2\rightarrow2IO^-_3\)

Reduction half-reaction

\(ClO^-_3\rightarrow Cl^-\)

Step 3: Balance OXYGEN. We do so by adding water molecules to the half-reactions as needed.

Oxidation half-reaction

\(I_2+6H_2O\rightarrow2IO^-_3\)

Reduction half-reaction

\(ClO^-_3\rightarrow Cl^-+3H_2O\)

Step 4: Balance HYDROGEN. We do so by adding protons (H+) to the half-reactions as needed.

Oxidation half-reaction

\(I_2+6H_2O\rightarrow2IO^-_3+12H^+\)

Reduction half-reaction

\(ClO^-_3+6H^+\rightarrow Cl^-+3H_2O\)

Step 5: Balance CHARGES. We do so by adding electrons

Oxidation half-reaction

\(I_2+6H_2O\rightarrow2IO^-_3+12H^++10e^-\)

Reduction half-reaction

\(ClO^-_3+6H^++6e^-\rightarrow Cl^-+3H_2O\)

Step 6: Multiply each half-reaction in such a way we can cancel the electrons.

Oxidation half-reaction

\(3\cdot(I_2+6H_2O\rightarrow2IO^-_3+12H^++10e^-)\)

New oxidation half-reaction

\(3I_2+18H_2O\rightarrow6IO^-_3+36H^++30e^-\)

Reduction half-reaction

\(5\cdot(ClO^-_3+6H^++6e^-\rightarrow Cl^-+3H_2O)\)

New reduction half-reaction

\(5ClO^-_3+30H^++30e^-\rightarrow5Cl^-+15H_2O\)

Step 7: combine the half-reactions. We have 30e in the reactants and 30e in the products. We can cancel them and combine the remaining species.

New oxidation half-reaction

\(3I_2+18H_2O\rightarrow6IO^-_3+36H^++30e^-\)

New reduction half-reaction

\(5ClO^-_3+30H^++30e^-\rightarrow5Cl^-+15H_2O\)

Overall reaction

\(3I_2+18H_2O+5ClO^-_3+30H^+\rightarrow6IO^-_3+36H^++5Cl^-+15H_2O\)

Step 8: Balance the reaction by reducing the number of water molecules and protons.

Overall reaction

\(3I_2+3H_2O+5ClO^-_3^{}\rightarrow6IO^-_3+6H^++5Cl^-\)

e. Balance the reaction

\(3I_2+3H_2O+5ClO^-_3^{}\rightarrow6IO^-_3+6H^++5Cl^-\)

.

write a general equation for the reaction of an alkali metal with water.

Answers

Answer:

Alkali metals are highly reactive metals. These metals are that much reactive that they can even explode in the air as well. When alkali metals and water react with each other, there is a formation of metal hydroxide and the evolution of hydrogen gas.

The general representation of metal is A. so, the general equation for the reaction of an alkali metal with water is given below.

2A(solid)+2H2O(liquid) -------> 2AOH(aqeous)+H2(gas)

Determine if the following reaction is a redox reaction. Use evidence from the equation to explain your reasoning.

Determine if the following reaction is a redox reaction. Use evidence from the equation to explain your

Answers

A redox reaction is a chemical reaction in which one or more of the reacting species undergoes oxidation and one or more undergoes reduction. An oxidizing agent is an element or compound that oxidizes another substance, while a reducing agent is an element or compound that reduces another substance.

The following reaction is a redox reaction based on the following evidence: 2Al + 3FeO → Al2O3 + 3Fe2+ In this reaction, Fe is being reduced because the FeO is changing to Fe2+. Additionally, the Al is being oxidized because it is losing electrons and forming Al2O3. Therefore, the reaction is a redox reaction. Let us take a look at the oxidation state of the elements in the given equation. Oxidation state of Al: (2) for the reactant and (3+) for the product. Oxidation state of Fe: (2+) for the reactant and (2+) for the product. Oxidation state of O: (-2) for the reactant and (-2) for the product. We can tell that oxidation is happening because of the increase in the oxidation state of Al from 2 to 3+. We can tell that reduction is happening because of the decrease in the oxidation state of Fe from 2+ to 2. As a result, the given equation is a redox reaction.

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what type of reaction is performed with the elephant toothpaste demonstration?

Answers

The reaction performed with the elephant toothpaste demonstration is known as a decomposition reaction.

Decomposition Reaction:

The process of breaking down a chemical compound into smaller molecules, atoms, or ions is known as a decomposition reaction. It is also known as analysis or disintegration. A reaction in which a single substance is broken down into two or more simpler substances is known as a decomposition reaction. The elephant toothpaste demonstration is a simple chemical reaction in which hydrogen peroxide breaks down into oxygen gas and water in a matter of seconds.

The formula for hydrogen peroxide is H₂O₂. It is a pale blue liquid that contains hydrogen, oxygen, and water. When you add yeast, soap, and food coloring, the reaction is more exciting. The yeast acts as a catalyst, breaking down hydrogen peroxide into water and oxygen gas. The oxygen gas created causes the soap to foam up, creating the "elephant toothpaste" effect. The chemical reaction that takes place during the elephant toothpaste demonstration can be written as follows:

2H₂O₂(liquid) → 2H₂O (liquid) + O₂ (gas)

This reaction is an example of a decomposition reaction.

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which findings on capnography indicate the normal movement of carbon dioxide through the respiratory system?

Answers

According to capnography research, EtCO2 is part of the normal flow of carbon dioxide through the respiratory system.

What capnography results show what is normal?

End-tidal carbon dioxide, a parameter used in capnography, quantifies ventilation (EtCO₂). The pressure unit mm Hg (millimeters of mercury) is used to measure EtCO₂ values. No matter the patient's age, gender, race, or size, the normal values fall between 35 and 45 mm Hg, or around 5% CO₂.

When a patient has a high EtCO₂ reading at the beginning of treatment, a drop in that reading signifies improvement. If there is no change or an increase in EtCO₂, it means that respiratory effort is still insufficient to sufficiently remove CO₂ and that additional interventions are required.

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An electron is a positively charged particle inside of an atom, just like the proton.



True
False

Answers

Answer:

no it's is false because an electron have negative charges and it is not inside the atom and it is found out side the nucleus

false bc the electrons are negative not positive & electrons is found outside the nucleus

Determine the number of moles in a container of gas at ST with a volume of 99.2 L.

Answers

The approximately 4 moles of gas in the container at standard temperature (ST) with a volume of 99.2 L.

To determine the number of moles of gas in a container at standard temperature (ST) with a volume of 99.2 L, we need to use the ideal gas law equation:

PV = nRT

Where:

P = pressure (atmospheres)

V = volume (liters)

n = number of moles

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature (Kelvin)

At standard temperature (ST), the temperature is 273.15 K.

Assuming the pressure is also at standard conditions (1 atm), we can rearrange the ideal gas law equation to solve for the number of moles:

n = PV / RT

Substituting the given values:

P = 1 atm

V = 99.2 L

R = 0.0821 L·atm/mol·K

T = 273.15 K

n = (1 atm) × (99.2 L) / ((0.0821 L·atm/mol·K) × (273.15 K))

Simplifying the calculation:

n ≈ 4 moles

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the answer to this problem

the answer to this problem

Answers

Here, each of the elements below with the class to which it belongs.  

Lithium → Alkali metals

Uranium → Transition metals

What is an Alkali metals?

Alkali metals are a group of highly reactive chemical elements in the periodic table. These elements include lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). Alkali metals have a single electron in their outermost shell, which makes them highly reactive and able to easily lose that electron to form a positive ion. They are typically soft, silvery-white metals that have low melting and boiling points, and are highly reactive with water and other substances. Alkali metals are important in various industrial applications, such as batteries, alloys, and chemical synthesis.

Krypton → Noble gases

Manganese → Transition metals

Fluorine → Halogens

Barium → Alkaline Earth

Most reactive metal → Alkali metals

Silicon → Metalloids

Groups 3-12 → Transition metals

Most reactive nonmetals → Halogens

Inert and unreactive → Noble gases

Has characteristics of metals and nonmetals → Metalloids

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You are a NASCAR pit crew member. Your employer is leading the race with 15 laps to go. He just finished a pit stop and has 3.0 gallons of fuel in the tank. On the way out of the pits, he asks, “Am I going to have enough fuel to finish the race or am I going to have to make another pit stop?” You whip out your calculator and begin your calculations based on your knowledge of stoichiometry. Other information you know is:

C5H12 + O2 → CO2 + H2O

The car uses an average of 275.0 grams of O2 for each lap.
The formula for fuel is C5H12
The fuel has a density of 700 g/gal.

What do you tell the driver? Can he finish the race? Will he have fuel left over?

Answers

Answer:

When Darrell is radioed back he would be asked to  “Go for it!”

Explanation:

Here we are given the fuel as C₅H₁₂, therefore the combustion reaction is given as

C₅H₁₂ + 8O₂ → 5CO₂ + H₂O

Mass of oxygen consumed on each lap = 300 g

Molar mass of oxygen gas O₂ = 32 g/mol

Number of moles of oxygen n 300 g of O₂ =

(300 g)/(32 g/mol) = 9.375 moles

For complete combustion, one mole of oxygen gas reacts with one mole C₅H₁₂, to form 5 moles of CO₂ and one mole of H₂O

Therefore 9.375 moles of oxygen ill combine with 9.375/8 or 1.172 moles of C₅H₁₂

Mass of 1.172 moles is given as

Mass = Number of moles × Molar mass

= 1.172 moles × 72.15 g/mole = 84.551 g

Therefore the mass of fuel to complete one lap = 84.551 g

However there are 25 gallons or 3.5 kg in the tank therefore we have

Number of laps the fuel in the tank can last  = Mass of fuel in the tank/ Mass of fuel consumed per lap

= 3.5/84.551 = 41.395 laps.

Number of laps the fuel in the tank can last  = 41.395 laps.

Since there are 20 laps left to complete, which is less than 41.395 laps left in the fuel tank of the vehicle, then Darrell would be asked to go for it.

Which element has a larger atomic radius than sulfur? O chlorine O cadmium fluorine oxygen​

Answers

Answer: solo necesito puntos lo siento

Explanation:

Answer:

Cadmium has larger atomic radius than sulfur.

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

A student determined that shaking a container of sand caused the temperature of the sand to rise. The student then performed a new experiment to see if shaking a container of pebbles would cause the temperature of the pebbles to rise.

Explain why the shaking caused the temperature of the sand to rise.

Answers

Example: When you rub your hands together, the action of scraping the surface of your skin back and forth against each other causes the molecules in your skin to move a little faster. The faster that molecules move, the higher the temperature. So the friction of rubbing your hands together makes them feel warmer.
So when you shake the sand the molecules move faster make the temperature warmer.

The shaking caused the temperature of the sand to rise because hey should notice an increase in sand temperature as the kinetic energy increases. This is due to the fact that the kinetic energy from their shaking is being converted to thermal energy in the sand.

What causes the temperature of the sand to change?

The sand is a poor heat conductor because when the Sun warms it, the heat is not distributed evenly, making the surface hot. Also, because sand has a lower specific heat than water, when both are exposed to the same amount of light, the sand at the surface will experience a greater change in temperature.

When you rub your hands together, the action of scraping the surface of your skin back and forth against each other causes the molecules in your skin to move a little faster.

The faster that molecules move, the higher the temperature. So the friction of rubbing your hands together makes them feel warmer.

Thus, when you shake the sand the molecules move faster to make the temperature warmer.

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what happen when a piece of silver metal is added to the copper sulphate solution​

Answers

Answer:

Explanation:When silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

Answer:

There will be no reaction

Explanation:

Therefore, when silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

magnesium hydroxide (mg(oh)2) and aluminum hydroxide (al(oh)3) are common ingredients in antacids. when these compounds combine with stomach fluid, which contains hydrochloric acid (hcl), how would the ph of the stomach fluid change

Answers

Magnesium hydroxide (mg(oh)2) and aluminum hydroxide (al(oh)3) are common ingredients in antacids. when these compounds combine with stomach fluid, which contains hydrochloric acid (hcl), -pH value is 7

Antacids work by inactivating (system is based) acid in the stomach. This is attributable to the fact that the chemical compounds in antacids are bases (alkalis), that are the inverse of acids. The initial response of an acid and a base is known as neutralization reaction. This neutralisation lessens the corrosion rate of the stomach contents.An antacid is a substance that neutralises production of stomach acid and is employed to treat heartburn, indigestion, and stomach upset. Antacid tablets have been used to treat constipation and diahorrea in the past. Antacids on the market contain aluminium, calcium, magnesium, or sodium salts.Antacids are medications that help to relieve indigestion and heartburn by neutralising (counteracting) stomach acid.

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Which statement is incorrect about the setup of voltaic cell? a.A voltaic cell is an electrochemical cell that uses spontaneous redox reactions to generate electricity. It consists of two separate half-cells. A salt bridge also connects to the half cells. b.Salt bridge is a tube usually filled with an electrolyte solution such as KNO3(s) or KCI(s) c.The salt bridge allows a flow of ions that neutralizes the charge build up in the solution. d.In Voltaic cells, oxidation occurs at cathode and reduction occurs at anode.

Answers

The incorrect statement about the setup of a voltaic cell is (d) "In voltaic cells, oxidation occurs at the cathode and reduction occurs at the anode."

In a voltaic cell, oxidation actually occurs at the anode and reduction occurs at the cathode. This is because electrons flow from the anode (where oxidation takes place) to the cathode (where reduction takes place). The anode is the electrode where oxidation reactions take place and electrons are released, while the cathode is the electrode where reduction reactions occur and electrons are gained. To explain further, in a voltaic cell, the anode is the electrode where the oxidation half-reaction occurs. Oxidation involves the loss of electrons and the anode serves as the source of electrons. These electrons then flow through an external circuit to the cathode. At the cathode, reduction takes place, which involves the gain of electrons. The cathode acts as the site where reduction half-reactions occur, consuming the electrons that flow from the anode. Therefore, the correct statement should be: "In voltaic cells, oxidation occurs at the anode and reduction occurs at the cathode."

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a 1.25-molar solution of a weak monoprotic acid is 9.2% ionized. calculate the ph of the solution.

Answers

The pH of the solution is approximately 0.939 , we can start by determining the degree of ionization (α) of the weak acid, which is given as 9.2%. The degree of ionization represents the fraction of the acid that has dissociated into ions.

We know that the initial concentration of the weak acid is 1.25 M. Let's denote the initial concentration of the acid as [HA] and the concentration of the dissociated H+ ions as [H+]. The concentration of undissociated HA molecules can be represented as [(1 - α) * [HA]].

Given that α = 9.2% = 0.092, we can write the equation for the concentration of H+ ions:

[H+] = α * [HA]

Substituting the values:

[H+] = 0.092 * 1.25 M

[H+] ≈ 0.115 M

Now that we have the concentration of H+ ions, we can calculate the pH using the formula:

pH = -log[H+]

pH = -log(0.115)

pH ≈ 0.939

Therefore, the pH of the solution is approximately 0.939.

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How many nodes are present in Y5 of 1,3,5,7,9-decapentaene? A. 2 B. 3 C. 4 D. 5

Answers

The number of nodes present in Y5 of 1,3,5,7,9-decapentaene is 4, so the correct option is C.


In a molecular orbital diagram, the number of nodes can be determined by the molecular orbital's subscript number (Yn).

The formula for finding the number of nodes is n-1, where n is the subscript. In this case, for Y5, the formula would be 5-1 = 4.

Therefore, there are a total of four nodes present in Y5 of 1,3,5,7,9-decapentaene.

In summary, the answer to your question is C and there are four nodes present in Y5 of 1,3,5,7,9-decapentaene due to the presence of four carbon-carbon double bonds.

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Which of the following colors is/are produced when white light from sun is passed through a prism?

Which of the following colors is/are produced when white light from sun is passed through a prism?

Answers

Answer:

Options d.

Explanation:

As white light from the sun is passed through a prism, it is separated into colors - red, violet, yellow, blue, green, orange, and indigo.

Dispersion is the process of the separation of visible light into its different component colors. The light waves are refracted as they enter the prism.

So, option d. is correct.

name the alkenes below

Answers

Alkenes are a group of unsaturated hydrocarbons (i.e., molecules with solely carbon and hydrogen) that include at least one double bond from carbon to carbon. Olefins is a different name for alkenes. Due to the double bond, alkenes are more reactive than alkanes.

What is Hydrocarbon?

A hydrocarbon is an organic compound made entirely of the two atom kinds of carbon and hydrogen. Hydrocarbons are typically colourless gases with barely perceptible odours. The four subcategories that are generally used to classify hydrocarbons are alkanes, alkenes, alkynes, and aromatic hydrocarbons. These chemicals' structures could be quite simple or extremely intricate. The study of hydrocarbons can provide insight into the chemistry and behavior of other functional groups. For commercial purposes, liquefied petroleum gas, which is produced from hydrocarbons like propane and butane, is also used as a fuel source (LPG). Benzene, one of the most fundamental aromatic hydrocarbons, serves as the building block for many synthetic drugs.

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Complete question

Name The Alkenes Below. Name The Alkenes Below. A) Ball& Sticklabels B) Ball & Stick ▼

2. What does aspirin do?

Answers

Answer:

Aspirin can reduce pain when a person is injured and swelling and reduce fevers when a person is sick . Aspirin is an anti-inflammatory OTC medication.

Explanation:

Molar mass if calcium nitrate

Answers

Answer:

About 164 grams

Explanation:

The molecular formula of calcium nitrate is \(Ca(NO_3)_2\). The molar mass of calcium is about 40, while the molar mass of nitrogen is about 14 and oxygen is about 16. Therefore, the molar mass of it is:

\(40+2(14+3(16))=40+2(14+48)=40+124=164\)

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An ice block of mass 3.00 kg has a temperature of 0°C. When energy of 5.01 × 105 J is transferred to the ice block, half of the block melts to water at 0°C.
(a) Determine the specific latent heat of fusion of ice.

____J/g
(b) How much energy would be needed to melt the remainder of the ice.

____J
(c) An extra energy of 2 × 105 J is transferred to the mixture of the ice block and water. What will be the temperature of the mixture?

____degreesCelsius

Answers

The energy required to increase 1.000 kg of water ice between 0 °C °C through 79.8 °C °C is equivalent to the energy required to melt one pound of ice (334 kJ).

What changes in the water's temperature occur as it transitions from ice to water vapour?

No surface temp change happens from heat exchange if ice caps melt and has become water ice (i.e., that during phase transition). Imagine about water melting from stalactites that were already dripping on a sun-warmed roof. Alternatively, water boils in an ice bucket cooled by relatively low surroundings.

How warm is the water now that the frost has melted?

To melt, the iceberg will take in all the heat that is available. The water stays at zero degrees Fahrenheit until all of the ice has dissolved as when the ice has melted, it changes becomes saltwater at that temperature.

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Traits are passed from parents to offspring. These traits are determined by

Answers

Answer: Gene Characteristic. (They are usually made up of more than one gene).

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