A lens of focal length 10.0 cm
forms an image 11.0 cm from the
lens. What was the object
distance?
(Unit = cm)
=
Answer:
30cm
Explanation:
Answer:
110
Explanation:
on accellus
Before beginning an experiment, Mrs. Wilson warns her science class not to drop the bar magnets on the floor. What is the most likely reason for Mrs. Wilson’s warning?
Answer:
we should not drop a magnet on the floor because the magnets tend to lose magnetism gradually and become weak over a period of time if they are not stored properly.
Answer:
Well depending on the floor like say if it was a wooden floor the magnet might lose it magnetism, if concrete floor the magnetic brake and still lose it magnetism, if a metal floor the magnet would stick not sure if it wood lose it magnetism or not but the possibilities still there, basically what I'm saying is the magnet would lose its magnetism if it were to interact with the floor maybe temporary or maybe permanently.
for those with with a learning disability it's a
Explanation:
ACELLUS PHYSICS HELP!!
A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)
Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
\( -3.09 = 6.93*10^{-4} * V \)
\( V = \frac {6.93*10^{-4}}{-3.09} \)
Potential difference, V = -0.000224 Volts
which particles most likely will be dispositive first as a velocity of a stream carrying a mixture of particles decreases
As the velocity of a stream carrying a mixture of particles decreases, the heaviest particles will most likely be deposited first. This phenomenon is known as sedimentation.
The process of sedimentation separates particles of different sizes and densities from a mixture by allowing them to settle at different rates due to gravity. The heavier particles settle faster than lighter ones. Therefore, they are the first to be deposited.Sedimentation can occur naturally or artificially. For example, in a river, sedimentation can occur naturally due to changes in water flow and velocity. Artificial sedimentation can be used in water treatment plants to remove impurities from water
The heaviest particles will most likely be deposited first as the velocity of a stream carrying a mixture of particles decreases.Explanation: This is due to the process of sedimentation, which separates particles of different sizes and densities from a mixture by allowing them to settle at different rates due to gravity. The heavier particles settle faster than lighter ones, and hence they are the first to be deposited.
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Suppose that F1 and F2 are two futures contracts on the same commodity with times to maturity. t1 and t2, where t2>t1. Prove that F2 where r is the interest rate (assumed constant) and there are no storage costs. For the purposes of this problem, assume that a futures contract is the same as a forward contract.
F2<F1, indicating that the futures contract with a longer time to maturity has a lower futures price than the contract with a shorter time to maturity when there are no storage costs and assuming a constant interest rate.
To prove that F2<F1, we can consider the present value of the futures contracts. The present value of a futures contract is given by the formula PV = F * e^(-r*t), where PV is the present value, F is the futures price, r is the interest rate, and t is the time to maturity.
Since t2 > t1, the exponent in the formula for F2 is smaller than that for F1. Assuming the interest rate r is positive, this means that
e^(-rt2) < e^(-rt1).
Since the present value is calculated by multiplying the futures price by the exponential term, we have
PV2 = F2 * e^(-rt2) and
PV1 = F1 * e^(-rt1).
Given that
e^(-rt2) < e^(-rt1),
we can conclude that PV2 < PV1, which implies F2 < F1.
Therefore, we have proven that F2<F1, indicating that the futures contract with a longer time to maturity has a lower futures price than the contract with a shorter time to maturity when there are no storage costs and assuming constant interest rates.
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In which of the cases below is friction most helpful?
A.
between a moving box and a ramp
B.
between car tires and a road
C.
between a person and a playground slide
D.
between ice skates and an ice rink
Answer:
between car tires and a road
Explanation:
one of two methods for calculating show window branch-circuit loads is to multiply each receptacle by ____ volt-amperes.
To calculate show window branch-circuit loads using one of the two methods, you can multiply each receptacle by 180 volt-amperes.
Branch circuit loads in an electrical distribution system are the electrical equipment and appliances linked to a particular branch circuit. A branch circuit is a conduit through which electricity is sent from the main electrical panel to certain outlets, lights or pieces of equipment inside a building or other structure. The total amount of electrical load that each branch circuit can safely take is determined by its maximum capacity, or the circuit's ampere rating. Lighting fixtures, outlets, kitchen appliances, HVAC systems, and electronic gadgets are just a few examples of the many electrical components that might be branch circuit loads. The safe and effective operation of electrical systems in residential, commercial, and industrial settings depends on the proper sizing and distribution of branch circuits.
1. Identify the number of receptacles in the circuit.
2. Multiply the number of receptacles by 180 volt-amperes.
3. The result will give you the total load in volt-amperes for the show window branch-circuit.
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You stand 300 cm away from a tuning fork with .0085 W of power. What is theintensity?
Given:
The distance from the tuning fork is d = 300 cm
The power is P = 0.0085 W
To find the intensity.
Explanation:
The intensity is defined as the power per unit area.
Wavelets are in the shape of sphere.
The intensity can be calculated by the formula
\(I=\frac{P}{4\pi d^2}\)On substituting the values, the intensity will be
\(\begin{gathered} I=\frac{0.0085}{4\times3.14\times(3)^2} \\ =\text{ 7.52}\times10^{-5}\text{ W/m}^2 \end{gathered}\)The intensity o
A bullet of mass 10g traveling at a speed of 100m/s embeds itself into a block of wood of mass 1900g. Suspended by a string.
A) Determine the velocity of the block and bullet immediately after the impact.
B) What is the height the pendulum rises to after impact?
A pilot drops a bomb from a plane flying horizontally at a constant speed. Neglecting air resistance, when the bomb hits the ground the horizontal location of the plane will
When the bomb hits the ground, the horizontal location of the plane will be directly above the point of impact.
Assuming there is no air resistance, the horizontal motion of the bomb is independent of its vertical motion. The bomb will continue to move horizontally with the same speed as the plane, unaffected by gravity. Therefore, the horizontal location of the plane will remain unchanged throughout the bomb's trajectory until it hits the ground.
In other words, if the plane was directly above the target when the bomb was released, it will still be directly above the target when the bomb hits the ground. The plane's horizontal position does not change as long as it maintains a constant horizontal speed during the bomb's descent.
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A man runs from the front to the back of a bus at a velocity of 2.0 m/s. if the bus is moving forward at 20.0 m/s, determine his relative speed with respect to an observer standing on the road.
Answer: 22.0 m/s
Explanation:
To determine the relative speed of the man with respect to an observer standing on the road, you need to take into account both the speed at which the man is moving and the speed at which the bus is moving.
The man's speed relative to the bus is 2.0 m/s, since he is running from the front to the back of the bus. The bus's speed relative to the observer on the road is 20.0 m/s.
To find the man's speed relative to the observer, you need to add the man's speed relative to the bus to the bus's speed relative to the observer. This gives you a total relative speed of 22.0 m/s.
Therefore, the man's relative speed with respect to the observer standing on the road is 22.0 m/s.
(5.6x10^-7m)/(2.8x10^-12s)
FAILURE OF THE PRODUCT Instructions 1. Select THREE from everyday below items from the list and discuss the way this item can potentially fail (list minimum THREE failures). Justify your answer by considering Load Strength graph and what can be done to prevent those failures. -Ball Pen -Room Key - Blender
The three product which can be potentially fail considering Load Strength graph and precautionary measure to prevent failure are as below;
Ball Pen:
1. Ink Leakage: One potential failure of a ball pen is ink leakage. This can occur due to poor sealing between the ink reservoir and the ballpoint mechanism. Ink leakage can result in messy hands, stained documents, and reduced functionality of the pen. To prevent this failure, manufacturers can improve the quality control process to ensure proper sealing and use high-quality materials for the pen's components.
2. Ballpoint Jamming: Another failure is ballpoint jamming, where the ball gets stuck and prevents smooth writing. This can be caused by a buildup of dried ink or debris inside the pen's mechanism. To prevent ballpoint jamming, regular cleaning and maintenance of the pen can be recommended. Additionally, manufacturers can design the pen with features that facilitate easy cleaning or provide instructions on how to clear any blockages.
3. Weak Barrel Construction: The barrel of the pen may also be prone to failure if it is weak or brittle. Excessive pressure or rough handling can lead to cracks or breakage, rendering the pen unusable. To prevent this, manufacturers can use durable materials for the pen barrel, such as sturdy plastics or reinforced metal, and perform quality checks to ensure structural integrity.
Room Key:
1. Keycard Malfunction: A potential failure of a room key is a malfunction in its electronic components. This can result in the keycard being unreadable by the door lock system, preventing access to the room. To prevent this failure, regular maintenance and replacement of keycard readers can be implemented. Additionally, guests should be advised to keep their keycards away from magnets and electronic devices that can interfere with the card's functionality.
2. Magnetic Strip Damage: Another failure can occur if the magnetic strip on the keycard gets damaged or demagnetized. This can happen due to exposure to magnetic fields or physical damage. To prevent this failure, keycards can be made more durable with protective coatings or alternative technologies such as RFID. Guests should also be educated on proper handling and storage of keycards to avoid damage.
3. Battery Drain: Some room keys use batteries to power their electronic components. A failure can occur if the battery drains, leading to an inactive keycard. To prevent this, low-power consumption designs can be implemented, and regular battery checks or replacements can be carried out by hotel staff. Guests should be informed about the importance of returning the keycard to the front desk for recycling or proper disposal to ensure the battery is replaced as needed.
Blender:
1. Motor Burnout: One potential failure of a blender is motor burnout due to prolonged use or overloading. Continuous operation at high speeds or attempting to blend hard or frozen ingredients beyond the blender's capacity can cause the motor to overheat and fail. To prevent motor burnout, manufacturers can provide clear guidelines on the maximum load capacity and recommended usage durations. Automatic thermal protection mechanisms can also be incorporated to shut off the blender if it detects excessive heat.
2. Blade Jamming: Another failure can occur if food particles or ingredients get jammed between the blender's blades, preventing them from spinning freely. This can happen if the blender is not properly cleaned or if ingredients are not adequately prepared before blending. To prevent blade jamming, users should be advised to clean the blender thoroughly after each use and ensure that ingredients are cut into manageable sizes. Manufacturers can also design blades with accessible mechanisms for easy cleaning or provide cleaning tools.
3. Leakage: A failure in a blender can also manifest as leakage. This can happen if the blender jar or its sealing components are damaged or improperly assembled. Liquid or food can leak out during blending, resulting in a messy and potentially unsafe situation. To prevent leakage, manufacturers should ensure proper sealing mechanisms and use high-quality materials for the blender jar and lid. Regular inspection of the sealing components can be advised,
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A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 20 m/s when it reaches ground level. What was its speed when its height was half that of its starting point
Answer:
Approximately \(14\; {\rm m\cdot s^{-1}}\).
Explanation:
The gravitational potential energy \(\text{GPE}\) of this roller coaster is proportional to the height \(h\) of the roller coaster.
The kinetic energy \(\text{KE}\) of this roller coaster is proportional to the square of speed \(v\).
The question states that the track is frictionless. Thus, during the descent, the \(\text{GPE}\) of this roller coaster is turned into \(\text{KE}\) without any energy loss.
When the roller coaster was at \((1/2)\) of the the initial height, only\(1 - (1/2) = (1/2)\) of the original \(\text{GPE}\) was turned into \(\text{KE}\). The \(\text{KE}\!\) of this roller coaster at that height would be \(1 - (1/2) = (1/2)\!\) of the \(\text{KE}\!\!\) when the roller coaster is at the ground level.
The \(\text{KE}\) of the roller coaster is proportional to \(v^{2}\) (the square of speed \(v\).) Thus, since the \(\text{KE}\!\) at \((1/2)\) the initial height is \(1 - (1/2) = (1/2)\!\) the \(\text{KE}\!\!\) at the ground level, the \(v^{2}\) at \((1/2)\!\) the initial height would also be \(1 - (1/2) = (1/2)\!\) the \(v^{2}\!\) at the ground level.
Since \(v = 20\; {\rm m\cdot s^{-1}}\) at the ground level, \(v^{2} = (20\; {\rm m\cdot s^{-1}})^{2}\) at the ground level. The \(v^{2}\) at \((1/2)\) the initial height would then be:
\((1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}\).
Thus, the speed \(v\) at \((1/2)\) the initial height would be:
\(\begin{aligned}& \sqrt{(1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{\frac{1}{2} \times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{200}\; {\rm m\cdot s^{-1}} \\ \approx\; & 14\; {\rm m\cdot s^{-1}}\end{aligned}\).
Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0.5 m/s2 for 30 seconds.
What is his final velocity?
2 m/s
8 m/s
19 m/s
60 m/s
Answer:
V = 19m/s
Explanation:
Given the following data;
Initial velocity, U = 4m/s
Acceleration, a = 0.5m/s²
Time, t = 30 seconds
To find the final velocity, we would use the first equation of motion;
V = U + at
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
V = 4 + 0.5*30
V = 4 + 15
V = 19m/s
Therefore, his final velocity is 19 meters per seconds.
Answer:
its C)19
Explanation:
tips for achieving good grades at science exam? i would be very thankful for you!!
How could you mathematically estimate the maximum height you can throw a ball vertically upward? How would you estimate the maximum speed you could give it?
Answer:
1) Throw the ball straight in the air and time how long it takes the ball to travel out of your hand then back into your hand at the same height it was released at.
2) Use this time and divide it by two to get t1. Insert t1 into the formula y=(g(t1)^2)/2. Solve for y.
3) To find the maximum speed you take t1 and insert it into the formula Vy=G(t1) and solve for Vy.
4) Remember to ignore air resistance and that g=9.8 m/(s^2)
Explanation:
2.0-kilogram block sliding down a ramp starts from rest from a height of 3.0 meters above the ground reaches the ground with a maximum speed of 2.6 m/s. What is the total work done by friction on the block as it slides down the entire length of the ramp?
Answer:
Explanation:To solve this problem, we can use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy.At the top of the ramp, the block has potential energy, which is given by:PE = mghwhere m is the mass of the block, g is the acceleration due to gravity, and h is the height of the ramp. Substituting the given values, we have:PE = (2.0 kg)(9.81 m/s^2)(3.0 m) = 58.86 JAt the bottom of the ramp, the block has kinetic energy, which is given by:KE = (1/2)mv^2where v is the speed of the block at the bottom of the ramp. Substituting the given values, we have:KE = (1/2)(2.0 kg)(2.6 m/s)^2 = 6.76 JThe net work done on the block is equal to the change in its kinetic energy, which is:W_net = KE - PEW_net = 6.76 J - 58.86 JW_net = -52.1 JSince the block is slowing down due to friction, the work done by friction is negative. Therefore, the total work done by friction on the block as it slides down the entire length of the ramp is:W_friction = -(-52.1 J)W_friction = 52.1 JTherefore, the total work done by friction on the block is 52.1 J.
4. Look at the picture to the left. Both of the people on the left are pulling with
a force of 30N to the left. On the right side of the rope, one person is pulling
with 35 N to the right, and the other person is pulling with 20N to the right.
What is the net force on the rope?
Friction force is what pulls an item to the left while it is travelling to a right on the a rough surface (f). The net force exerted on the rope was equal to a distinction two loads exerted on it operating in opposite directions.
What is an illustration of a force pulling an object?An item is pulled towards the centre of the Earth by gravity. A ball that has been tossed above slows down and returns to the earth. This is as a result of gravity bringing the soccer ball back to the ground. The pull of gravity affects everything on Earth.
What is an example of a force or pull?When a force propels an object inside the direction of a person pulling it, such action is referred to as pulling. Opening a door, plucking a guitar string, drawing water from a well, or drawing a curtain are all examples of pull-related actions.
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What is the average speed of a race car that moved 20 kilometers in 10 minutes?
Answer:21
Explanation:every body said
Calculate the gravitational force acting on a 251 kg satellite at an altitude of of 1.2*10^4km above Earth's surface.
(The question provided the Earth's radius and mass)
Me = 5.97*10^24
Re = 6.38*10^6
I think my calculator might be acting up today so if you could provide everything step by step that would be very nice
Answer:
296.1N
Explanation:
The formula for force of gravity is GMm/r^2, where G is the gravitational constant, M is mass object A, m is mass object B and r is distance from the CENTER of object A to object B. First, lets solve GMm. G*5.97*10^24*251=1*10^17
Now lets solve for r:
r=(Re+r)=(6.38*10^6+1.2*10^4)
While it makes sense, distance of the sattelite is in Kilometers, and we need it in meters, so:
r=(Re+r)=(6.38*10^6+1.2*10^4*1000)=18380000
now to the solving:
1*10^17/18380000^2=296.1N
Why does the Moon seem to change shape?
A.
As the Moon revolves
around Earth, different parts are lit by the Sun.
B.
The viewpoint from Earth of the illuminated side of the Moon changes.
C.
Earth's shadow is blocking light from the Sun.
D.
The way the Moon produces light changes, so we see different shapes.
Answer:
A
Explanation:
The mass of the train is 450000 kg.
Calculate the maximum possible speed of the train at the end of the first 4.0km of the
journey.
The maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
To calculate the maximum possible speed of the train at the end of the first 4.0 km of the journey, we can apply the principle of conservation of energy.
Assuming there are no external forces like friction or air resistance, the initial potential energy of the train will be converted into kinetic energy.
The potential energy (PE) of the train at the beginning of the journey can be calculated as PE = mgh, where m is the mass of the train, g is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and h is the height difference (in this case, we assume it to be zero).
The kinetic energy (KE) of the train at the end of the 4.0 km journey can be calculated as \(KE = (1/2)mv^2\), where v is the velocity of the train.
Since the potential energy is converted into kinetic energy, we can equate the two expressions:
PE = KE
\(mgh = (1/2)mv^2\)
Simplifying and canceling out the mass:
\(gh = (1/2)v^2\)
Substituting the values, \(g = 9.8 m/s^2\)and h = 0, we get:
\((9.8 m/s^2)(0) = (1/2)v^2\)
Simplifying further:
\(0 = (1/2)v^2\)
This equation tells us that the maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
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parts of the frontal lobe that fire when performing certain actions or when observing another doing so are called
The parts of the frontal lobe that fire when performing certain actions or when observing another doing so are called mirror neurons.
These are a type of brain cells that activate both when an individual performs a specific action and when they observe another person performing the same action.
They play a crucial role in understanding and imitating the actions of others, as well as in empathy and social cognition.
These are believed to be involved in various processes, such as motor imitation, empathy, language development, and understanding the intentions and emotions of others.
They contribute to our ability to learn through observation and mimicry, facilitating social interaction and communication.
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Electromagnetic waves are made by vibrating electric charges and can travel through what
Answer:
vibrates, and they carry energy from one place to another. Look at the sound wave and the water wave. vibrating electric charges and can travel through space where matter is not present. to particle, electromagnetic waves travel by transferring energy between vibrating electric and magnetic fields.
A submarine is 58.8 m from a whale. The sub sends out a sonar ping to locate the whale. The speed of sound underwater is 1520 m/s. How much time does it take for the sound wave to travel to the whale and back? (Unit = s)
Answer:
0.08
Explanation:
this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.
The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this
t = 2d/v
t = 2*58.8/1520
t = 117.6/1520
t = 0.077368 s
t ≈ 0.08 s (less then 1 s)
Answer:
0.0774s
Explanation:
The formula to find the time of an echo is time = (2)(distance) / (velocity)
So plug in the numbers to the formula
(2)(58.8) / (1520)
= 0.0774s
what was the dwarf planet discovered in AZ?
Answer:
Pluto.
Explanation:
an observary in Flagstaff, Arizona, discorvered it.
Which indicates what happens to the kinetic energy when the mass of a moving object increases?.
kinetic energy Increases when the mass of a moving object increases.
K.E= mv²/2
A specific type of power that may be found in moving particles or things is called kinetic energy. When work, which entails the transfer of energy, is done on an object by applying a net force, that object accumulates kinetic energy. The mass and speed of an item or particle determine the kinetic energy, a property of motion. Any combination of vibration, axis rotation, translation, and movement is referred to as motion (along a path from one location to another). The translational kinetic energy of a body is equal to 1/2mv2, which is calculated by multiplying its mass, m, by the square of its speed, v.
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A 2,500 Hz sound wave travels with a speed of 15 m/s in water. A paleontologist measures
the valley to the second valley of the wave to be 7.5 cm.
➤What is the (a) period? What is the (b) frequency? What is the (c) wavelength?
The answers are A. The period of the wave is 4 × 10⁻⁴ s, B. The frequency is 2500 Hz and C. The wavelength is 6 cm.
A sound wave is a type of wave that travels through the medium by compressing and expanding the particles of the medium. These waves have certain characteristics that are used to measure their properties. The following are the answers to the given question: A 2,500 Hz sound wave travels with a speed of 15 m/s in water. A paleontologist measures the valley to the second valley of the wave to be 7.5 cm.a) The period of a wave is the time it takes to complete one cycle. The formula for calculating the period of a wave is Period = 1/Frequency. Here, the frequency of the wave is 2500 Hz. Hence, the period of the wave can be calculated as Period = 1/2500 Hz = 4 × 10⁻⁴ s.b) The frequency of a wave is the number of cycles that pass a point in one second. The formula for calculating the frequency of a wave is Frequency = 1/Period. Here, the period of the wave is 4 × 10⁻⁴ s. Hence, the frequency of the wave can be calculated as Frequency = 1/4 × 10⁻⁴ s = 2500 Hz.c) The wavelength of a wave is the distance between two successive points on the wave that are in phase. The formula for calculating the wavelength of a wave is Wavelength = Wave speed / Frequency. Here, the wave speed of the sound wave is 15 m/s and the frequency of the wave is 2500 Hz. Hence, the wavelength of the wave can be calculated as Wavelength = 15 / 2500 = 0.006 m = 6 cm.For more questions on frequency
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How does a falling object's surface area affect calculations of terminal velocity? (
O The greater the object's surface area, the greater the air density.
O Surface area does not affect an object's terminal velocity.
O The greater the object's surface area, the greater its terminal velocity.
O The greater the object's surface area, the more air resistance it encounters.
Answer:
The greater the object's surface area, the more air resistance it encounters.
Explanation:
Terminal velocity is the point at which the force of air resistance is equal to the force of gravity acting on an object. An object with a greater surface area will encounter more air resistance and therefore have a lower terminal velocity.
The greater the object's surface area, the more air resistance it encounters. Hence, its velocity decreases with increasing surface area.
What is velocity ?Velocity is a physical quantity that measure the distance covered by an object per unit time. Velocity is the rate of speed and it is a vector quantity. Velocity of an object is affected by its mass, physical state, surface area, temperature etc.
As the mass increases, the velocity of a a falling object will be greater because, the gravitational force towards the massive object is greater and it falls rapidly.
As the surface area of the object increases, the air resistance that it encounters also increases. This air resistance acts as an opposition and decreases its velocity.
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