When calculating the stopping distance, various factors come into play, including reaction time, road conditions, vehicle weight, and braking efficiency. However, a commonly used estimate for the stopping distance at 55 mph (miles per hour) is approximately 4 to 5 times the thinking distance, which is the distance traveled during the driver's reaction time.
Assuming an average reaction time of 1.5 seconds, the thinking distance can be estimated by considering the speed:
Thinking Distance = Speed × Reaction Time
Converting 55 mph to feet per second (fps):
55 mph = 55 × 1.46667 fps (1 mph ≈ 1.46667 fps)
Now, calculating the thinking distance:
Thinking Distance = 55 × 1.46667 × 1.5 = 120.9335 feet (approximately)
Adding this thinking distance to the braking distance, we can estimate the overall stopping distance.
Therefore, the approximate stopping distance at 55 mph would be:
Stopping Distance ≈ Thinking Distance + Braking Distance
Stopping Distance ≈ 120.9335 feet + Braking Distance
Based on the options provided, none of them align with this approximate estimation. However, the closest option is:
Approximately 305 feet.
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Is there effect of friction on mechanical advantange
Answer:
Most certainly yes
Explanation: First you have to define what friction is "A force that resist motion" while Mechanical advantage " is simply a measure of the output force to the input force". Hence in a mechanical system if you increase friction in the system, it reduces the mechanical advantage and vice versa.
What is electric current
Answer:
Electric current is electric charge in motion. It can take the form of a sudden discharge of static electricity, such as a lightning bolt or a spark between your finger and a ground light switch plate. ... Most electric charge is carried by the electrons and protons within an atom.
Explanation:
because it is
Because of centripetal (spinning) forces, the earth.
Because of centripetal (spinning) forces, the Earth maintains its rotation and orbit.
What is centripetal forces?The theory behind centripetal force underscores its immense significance when it comes to moving objects along curved paths. Essentially, this powerful energy source acts continuously at right angles to maintain an inward pull towards the center point of any given circle - be it planetary orbits or playful rides such as merry-go-rounds.
Centripetal force serves an essential purpose that helps ensure automobiles remain on track while navigating sharp turns without losing control - truly remarkable!
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In a college homecoming competition, eighteen students lift a sports car. While holding the car off of the ground, each student exerts an upward force of 400 newtons. What is the mass of the car in kilograms?
734.19567 Kilogram Force
Explanation:
7200 Newton = 734.19567 Kilogram Force
A computational model predicts the maximum height that a roller coaster car can reach when the lowest height of its journey is at ground level, where it has a speed of 20 m/s. Given these conditions, what is the maximum height?(1 point)
196 m
4.8 m
20.4 m
2.0 m
Answer: 20.4 m
Explanation: \(\frac{9.8^{2} }{Velocity} = Max Height\)
The answers to this test are:
1. What is the maximum speed when the conditions are mass = 450 kg, initial height = 30 m, and the roller coaster car is initially at rest?
24.2 m/s
2. A computational model predicts the maximum height that a roller coaster car can reach when the lowest height of its journey is at ground level, where it has a speed of 20 m/s. Given these conditions, what is the maximum height?
20.4 m
3. A computational model predicts the speed of a roller coaster car at different heights given its speed at the lowest height of its journey, which is at ground level. The speed at the lowest point is 30 m/s. What is the prediction for its speed when it is at a height of 20 m?
22.5 m/s
4. A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lowest point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J
5. What is the benefit of using simple computational models in a spreadsheet application, like the one used in this course, to predict mechanical energy and related values?
It is easy to calculate new scenarios.
What accommodations can be made for people with impaired vision?
Q.3. Fill the table to describe the characteristics of the states of matter.
Do they have
definite shape?
Vapor
Water
Ice
States of
Matter
Do they have
definite volume?
Do they
compress?
Answer:
Three states of matter exist—solid, liquid, and gas. Solids have a definite shape and volume. Liquids have a definite volume,
Explanation:
According to the information, the table is completed as follows: Do they have definite shape? no (vapor), no (water), yes (ice); Do they have definite volume? no (vapor), yes (water), yes (ice); Do they compress? yes (vapor), no (water), no (ice).
How to fill the table to describe the characteristics of the states of matter?To fill the table to describe the characteristics of the states of matter we have to look for additional information of each state of matter and then complete the table. According to the information we can infer that the correct way to complete the table is:
Do they have definite shape? no (vapor), no (water), yes (ice); Do they have definite volume? no (vapor), yes (water), yes (ice); Do they compress? yes (vapor), no (water), no (ice).
Vapor | No | No | Yes
Water | No | Yes | No
Ice | Yes | Yes | No
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What will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors?
Hello!
Recall for resistors in parallel:
\(\frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}\)
We can begin by calculating the total resistance:
\(\frac{1}{R_t} = \frac{1}{10} + \frac{1}{10} + \frac{1}{10}}\\\\\frac{1}{R_t} = \frac{3}{10}\\\\R_t = \frac{10}{3} = \boxed{3.333 \Omega}\)
Now, we can calculate the current using Ohm's Law:
\(V = iR\\\\i = \frac{V}{R}\)
V = Voltage of battery (V)
i = Current (A)
R = Resistance (Ω)
Plug in the given voltage and the total resistance we solved for.
\(i = \frac{15}{3.33} = \boxed{4.5 A}\)
with the aid of a string, a gyroscope is accelerated from rest to 35.8 rad/s in 0.320 s. what is its angular acceleration in rad/s2? (you do not need to enter any units.)
In this case, the angular acceleration can be found by dividing the final angular velocity by the time. The angular acceleration of the gyroscope is 112.1875 \(rad/s^2\).
Angular acceleration (α) is defined as the rate of change of angular velocity (ω). Mathematically, it can be expressed as:
\(\alpha = (\omega_f - \omega_i) / t\)
where \(\omega_f\) is the final angular velocity, \(\omega_i\) is the initial angular velocity (which is zero since the gyroscope starts from rest), and t is the time taken for the acceleration.
In this scenario, the gyroscope is accelerated from rest to an angular velocity of 35.8 rad/s in a time of 0.320 s. Therefore, the final angular velocity (\(\omega_f\)) is 35.8 rad/s and the time (t) is 0.320 s.
Using the formula for angular acceleration, we can substitute these values into the equation:
Simplifying the expression, we get:
\(\alpha = (35.8 rad/s - 0 rad/s) / 0.320 s\)
\(\alpha = 112.1875 rad/s^2\)
Therefore, the angular acceleration of the gyroscope is \(rad/s^2\).
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8. An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120
specific heat capacity of the liquid in this temperature range. Assume that negligible h
O
O
O
2.51 x 10³ J/(kg. C°)
1.67 x 106 J/(kg C°)
2.02 x 104 J/(kg. C°)
The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.
Specific heat capacity of the liquidThe specific heat capacity of the liquid is calculated as follows;
Q = mcΔФ
where;
Q is quantity of heat c is specific heat capacitym is mass of the liquidΔФ is change in temperature = 22.54 - 18.55 = 3.99 ⁰Cc = Q/mΔФ
c = (65 x 120)/(0.78 x 3.99)
c = 2.51 x 10³ J/kg⁰C
The complete question is below:
An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.
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Which is a characteristic of centripetal acceleration?
A. It is directed outward from the center of a circle.
B. It is directed inward, toward the center of a circle
C. It results in an object moving faster.
D. It results in an object moving slower.
Answer: The Answer is B. It is directed inward, toward the center of a circle.
Explanation:
You are growing a little taller each year. What units could you use to measure how fast
you are growing?
Answer:
inches and feet (or even centameters)
Explanation:
these are all common units used to measure height
the electric field 0.460 m from a very long uniform line of charge is 900 n/c..How much charge is contained in a section of the line of length 2.30cm?
The electric field 0.460 m from a very long uniform line of charge is 900 n/c..A charge is contained in a section of the line of length 2.30cm is 2.08 * 10-7 C.
The electric field of 0.460 m from a very long uniform line of charge is 900 n/c. To find out the amount of charge contained in a section of the line of length 2.30 cm, we can use the equation E = k*Q/r2, where k is the Coulomb's constant, Q is the charge of the line, and r is the distance from the centre of the line.
Therefore, we can rearrange the equation to Q = E*r2/k. Substituting in our values, we get Q = 900 n/c * (0.46 m)2 / (9*109) Nm2/C2 = 2.08 * 10-7 C. The charge contained in a section of the line of length 2.30 cm is 2.08 * 10-7 C.
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The 200-mm test tube also contained some water (besides the metal) that was subsequently added to the calorimeter (in Part A.4.). Considering a higher specific heat for water, will the temperature change in the calorimeter be higher, lower, or unaffected by this technique error?
Answer:
The temperature change in the calorimeter will be lower
Explanation:
Water is an example of a molecular substance. They have relatively low melting points and boiling points usually below 300° C . Water reacts with metals to a degree varying with their position in the electrochemical series.
The specific heat of water is 4179.6 Joules which is relatively high . This typically implies that water absorbs a larger amount of heat but the increase in temperature of its boiling points is relatively low. Thus; in the 200-mm test tube that contains water and was subsequently added to the calorimeter , the heat present was initially absorbed by the water and that does not result to an increase in the temperature change in the calorimeter. Thus the temperature change in the calorimeter will be lower.
A 5-kg ball is moving at 8 m/s to the right, suddenly 15 N force is applied to the ball and the ball is now moving at 12 m/s. How long was the force applied to the ball
Answer:
t = 1.33 seconds
Explanation:
Given that,
The mass of the ball, m = 5 kg
Initial speed, u = 8 m/s
Final speed, v = 12 m/s
Force, F = 15 N
We need to find the time for long the force is applied. Let the time be t. The force is given by :
\(F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{5\times (12-8)}{15}\\\\=1.33\ s\)
So, the force is applied for 1.33 seconds.
w of moons or Tug between moon an EARTH the Milankovich precession of Barth's rotational axis is not to be con- od with the one-year orbit of Earth about the sun (Fig. 18.11). At the present time in the Northern Hemisphere the date of the winter solstice is that of the shortest day of the year (December 22), whereas the date of the summer solstice is that of the longest day of the year (June 22). In the South- ern Hemisphere the opposite applies. Q189 The two globes in Figure 18.11 are labeled A and B. Question: Which of the two is in the position of the summer solstice. A or B? Q18.10 Incidentally, outdoor tennis is a summer sport. So why is the Aus- tralian Open held in January, where as the French Open is held in June? Figur the sul solstic rotati revol is rela with finger is reli
Globe B is in the position of the summer solstice.
The summer solstice occurs when the tilt of the Earth's axis is inclined towards the Sun, resulting in the longest day of the year in the Northern Hemisphere. In Figure 18.11, the two labeled globes represent the Earth at different positions in its orbit.
Since the date of the summer solstice is mentioned as June 22, the globe labeled B must be in the position of the summer solstice because it corresponds to the time when the Northern Hemisphere experiences summer.
Globe A, therefore, represents the position of the winter solstice, which occurs when the Earth's axis is tilted away from the Sun, resulting in the shortest day of the year in the Northern Hemisphere.
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Solve each problem. write your answer and solution.
1. how much is done by mila when she exerted a 25n force in lifting her bag to a height of 2m?
2. a 10kg block of wood is pulled across a level ground by fore of 15n applied at an angle of 30 degree from the horizontal. how much work is done, if it is moved to a distance of 3m?
(note: f applied = 15n x cos 30 degree, cos 30 degree = 0.5)
3. what is the work done by a boy in pushing the wall of the classroom, if he
applied a force of 30n?
4. a man weighing 500n walks a flight of stairs 10m high. how much work is
done by the man?
5. a sack of rice with a mass of 120kg is lifted by a laborer in a 15m high
building. compute the amount of work done by the laborer.
1. W = 50J
2. W = 6.9J
3. Work done is same as force = 30N
4. P = 480W
Solution:1. Here given:
F = 25N
D = 2m
We have to find W = ?
Work done Formula : W= F x D
By substituting ,
W = 25 x 2
W = 50J
2. Here given,
F = 15N
Angle = 30°
distance = 3m
W = 15* 3 * cos 30
= 6.9 J
3. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. When we apply a force of 30N to a wall, it responds with the same force.
4. The work done will be calculated using the formula:
W = mass*gravitational acceleration*height.
Furthermore,
power = work done / time.
500 + 100 = total weight
600 N = total weight
Maintain the values in the formula -
Work completed = 600*4
2400J
P = 2400/5
= 480W
Hence, the power is 480 Watt.
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What is the acceleration of a 50N object traveling at terminal velocity0m/s/s50m/s/s10m/s/s-10m/s/s
The acceleration of an object traveling at terminal velocity is 0 m/s/s since it is not accelerating.
What is terminal velocity?Terminal velocity is the maximum speed achieved by an object as it falls through a fluid such as air or water. The object's weight, drag coefficient, and surface area all affect its terminal velocity. Terminal velocity increases as an object's weight increases and its drag coefficient and surface area decrease. Terminal velocity is greatest when an object reaches its equilibrium between the force of gravity and the fluid's drag force. For example, a human skydiver has a terminal velocity of about 120 mph.
Terminal velocity is the maximum velocity an object can reach and remain at a constant speed as it is subjected to a constant force such as gravity. If the object is subject to any additional force, it will accelerate.
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Three resistors 10 ohms, 20 ohms, and 30 ohms are connected in series with a 90-volt battery. Determine the current through each resistor. Which of the three resistors is the most powerful?
Since the resistors are in series, the equivalent resistance is the sum of the resistances:
\(\begin{gathered} R=10+20+30 \\ R=60\text{ ohms} \end{gathered}\)Now, to find the current, let's divide the voltage by the total resistance:
\(\begin{gathered} I=\frac{V}{R} \\ I=\frac{90}{60} \\ I=1.5\text{ A} \end{gathered}\)The current through each resistor is the same because they are in series: 1.5 A.
To find the most powerful resistor, let's analyze the formula for the power in a resistor:
\(P=I^2\cdot R\)We can see that the greater the resistance, the greater the power, therefore the most powerful resistor is the 30 ohms resistor.
A glass slides across a bar and slows down due to a kinetic friction of 0. 175N. If the glass weighs 0. 500N, what is the coefficient of kinetic friction between the glass and the bar?
Answer:
F = M a = Ff force of friction
Ff = μ M g = μ W where M g = weight of glass
The problem gives the kinetic friction as a force (Ff) in Newtons
μ = Ff / W = .175 / .500 = .35
a. Consider a light bulb connected to a battery with wires. How must the light bulb be connected in order for it to light?
b. Identify the relevant parts of the bulb and battery. Explain, using the concept of potential difference, why and how your configuration causes the bulb to light. Do not use the phrase "complete circuit".
To light the bulb, it must be connected to the battery in a way that the positive terminal of the battery connects to one end of the bulb's filament and the negative terminal connects to the other end of the filament.
The relevant parts of the bulb are the filament and the two contact points, while the battery has a positive terminal and a negative terminal.
When the bulb is connected in the configuration described above, a potential difference is created between the positive and negative terminals of the battery.
This potential difference causes an electric current to flow through the wires and the filament of the bulb.
The filament, made of a material with a high resistance, heats up due to the current flow and begins to emit light as a result.
Hence, A light bulb must be connected to a battery such that its filament is connected between the positive and negative terminals of the battery. This creates a potential difference, allowing the current to flow through the filament and causing it to emit light.
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shows the relationships among the solid, liquid and gas states as a function of temperature and pressure.
A: phase diagram
B: heat energy diagram
C: heating curve
Answer:
Phase Diagram I Think But I Just Searched It Online
The robot arm is elevating and extending simultaneously. At a given instant. theta = 30 degree, theta with dot = 10 deg/s = constant, l = 0.5 m, i = 0.2 m/s, and l with dieresis = -0.3 m/s2. Compute: express v right words arrow and a right words arrow in terms of unit vectors I with Hat and j with Hat. the magnitudes of the velocity v and acceleration a of the gripped part P.
The velocity of the gripped part P is -0.4i_hat + 0.293j_hat m/s, and the acceleration is -0.05i_hat - 3.93j_hat m/s^2. The magnitude of the velocity is 0.5 m/s, and the magnitude of the acceleration is 3.93 m/s^2.
What is tangential acceleration?Tangential acceleration is the component of acceleration that is parallel to the instantaneous velocity of an object moving along a curved path. It represents the rate of change of the magnitude of the velocity vector of the object. Mathematically, the tangential acceleration at any instant is given by the formula:
a_t = r * d²(theta)/dt²
To compute the velocity and acceleration of the gripped part P, we can use the equations for velocity and acceleration of a particle in planar motion:
v = v_i + a_t, where v_i is the initial velocity and a_t is the tangential acceleration a = a_t + a_n, where a_n is the normal acceleration
First, let's find the position of the gripped part P at the given instant. We can use the law of cosines to find the length of the arm:
l² = i² + 2ilcos(theta) + l² cos(theta) = (l² + i² - l²)/(2il) = (i²)/(2il) = 0.2/(20.5) = 0.2
Therefore, theta = arccos(0.2) = 78.46 degrees.
Next, let's find the position vectors of the gripped part P at the given instant. We can use the polar coordinates of P:
r = l theta = theta x = rcos(theta) = 0.5cos(78.46) = 0.13 m y = rsin(theta) = 0.5sin(78.46) = 0.47 m
Now, let's find the velocity vector v. We can find the tangential acceleration using the formula:
a_t = ld^2(theta)/dt^2 = l(-0.3)*cos(theta) = -0.15 m/s^2
Therefore, the velocity vector is:
v = v_i + a_t = ltheta_dot(-sin(theta)*i_hat + cos(theta)j_hat) + (-0.15(-sin(theta)*i_hat + cos(theta)j_hat)) = (-0.25(-sin(30)*i_hat + cos(30)j_hat)) + (-0.15(-sin(30)i_hat + cos(30)j_hat)) = (-0.4i_hat + 0.293j_hat) m/s
The magnitude of the velocity is:
|v| = sqrt((-0.4)^2 + (0.293)^2) = 0.5 m/s
Next, let's find the acceleration vector a. We can find the normal acceleration using the formula:
a_n = l × (d^2(theta)/dt^2)sin(theta) = -0.30.5×sin(78.46) = -0.145 m/s^2
Therefore, the acceleration vector is:
a = a_t + a_n = (-0.15*(-sin(30)*i_hat + cos(30)j_hat)) + (-0.145sin(78.46)*cos(30)i_hat + (-0.145sin(78.46)sin(30) - 9.81)j_hat) = (-0.05i_hat - 3.93j_hat) m/s²
The magnitude of the acceleration is:
|a| = √((-0.05)² + (-3.93)²) = 3.93 m/s²
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a scientist studies the light from a distant galaxy. the light from the galaxy shows a shift to longer wavelengths. what can the scientist conclude about the galaxy?
A. The galaxy is orbiting faster than the Milky Way
B. The galaxy is moving closer to Earth
C. The galaxy is stationary in the universe
D. the galaxy is moving farther away from Earth
The shift of light toward longer wavelengths indicates that most galaxies are moving away from Earth. More powerful telescopes have made observations of planets orbiting stars other than the Sun.
name any three metals that makes soil fertile
What is SI unit of frequency Mcq?.
The hertz (Hz) is the SI frequency unit named after the German physicist Heinrich Hertz; one hertz means that an event occurs once every second.
What is frequency?The frequency of a repeating event is the number of occurrences per unit of time. It is distinct from angular frequency and is sometimes referred to as temporal frequency. The unit of frequency is hertz, which equals one event per second. The number of waves that pass through a fixed point in a given amount of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second. The frequency is 100 per hour if it takes 1/100 of an hour.
Here,
The hertz (Hz) is the SI unit of frequency, named after the German physicist Heinrich Hertz; one hertz means that an event occurs once every second.
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a simple machine is able to move a 400N load a distance of 20cm when a force of 20N is moved through a distance of 5m calculate work input
The work input required is 180 J.
The formula gives the work input:
Work input = Force x Distance
In this instance, a force of 20 N is used, and 5 m is moved. As a result, the force's work is:
Work done by force = 20 N x 5 m = 100 J
A 400 N weight can be moved by the machine 20 cm (or 0.2 m) away.
Using the following formula, we can estimate the work performed by the machine:
Work done by machine = Load x Distance moved by the load
Work done by machine = 400 N x 0.2 m = 80 J
As a result, the amount of work needed to move the load with the machine is:
Work input = Work done by force + Work done by machine
Work input = 100 J + 80 J = 180 J
Therefore, the work input required is 180 J.
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Rewrite the following sentence in the negative form >Each library contains 3000 brand new books
If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.
We are given the following information about an inelastic collision.
Mass of 1st object = 4 kg
Mass of 2nd object = 10 kg
Initial velocity of 1st object = 25 m/s
Final velocity of both objects = 14 m/s
Initial velocity of 2nd object = ?
In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.
Recall that the total momentum is conserved and given by
\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)Let us substitute the given values and solve for initial velocity of the body (u2)
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s
A rowboat floats in a swimming pool, and the level of the water at the edge of the pool is marked. Consider the following situations.
If a person gets into the rowboat, the water level at the edge of the pool will rise slightly. This is because the weight of the person adds to the weight of the boat and displaces more water, causing the water level to rise.
The amount of the rise in water level will depend on the weight of the person and the size of the boat. Similarly, if objects are added to the boat, the water level at the edge of the pool will also rise. However, if the boat is empty and just floating in the pool, it will displace a certain amount of water and the water level at the edge of the pool will be at the marked level.
Overall, the water level in the pool is determined by the amount of water displaced by the rowboat and any additional weight that is added to it.
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