The apparatus performance test that requires a discharge hoseline from a second pumper to be connected to the apparatus being tested is the internal intake pressure relief valve test (Option C).
The apparatus performance test that requires that a discharge hoseline from a second pumper be connected to the apparatus being tested is the tank-to-pump flow test.
This test measures the maximum water flow rate that can be delivered from the tank to the pump. It requires that a hoseline be connected from the discharge outlet of the second pumper to the intake of the apparatus being tested. This is done to provide an adequate water supply to the pump being tested.The test involves opening the discharge valve of the pump and recording the flow rate and pressure.
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Considering scaled dot-product attention with the following keys and values: K = [[0.5, 0.5], [-0.5, 0.5], [-0.5, 0.5]] V = [[1.0, 2.0, 3.0, 4.0], [4.0, 1.0, 4.0, 2.0], [-1.0, 5.0, 2.0, 1.0]] Given the query [0.5, 0.5], what is the resultant output? 1. [0.0471, 0.9465, 0.0064] 2. [1.000, 2.000, 3.000, 4.000] 3. [0.5, 0.5]+ 4. [0.5, -0.5] 5. [1.292, 2.584, 3.000, 2.540] 6. [1.000, 4.000, -1.000]
The correct option is 5. [1.292, 2.584, 3.000, 2.540].The query is [0.5, 0.5], and the key values are given as K = [[0.5, 0.5], [-0.5, 0.5], [-0.5, 0.5]].Then, the dot product of the key value and query is calculated.
The dot product of the query and the first key is calculated as: [0.5, 0.5].[0.5, 0.5] = 0.5*0.5 + 0.5*0.5 = 0.5.The dot product of the query and the second key is calculated as: [0.5, 0.5].[-0.5, 0.5] = 0.5* -0.5 + 0.5*0.5 = 0.0.The dot product of the query and the third key is calculated as: [0.5, 0.5].[-0.5, 0.5] = 0.5* -0.5 + 0.5*0.5 = 0.0.
The dot products are normalized by dividing by the square root of the dimension of the query and the key space, which is 2 in this case. Therefore, the output of the attention operation is\([0.5/√2, 0.0/√2, 0.0/√2]\), which is equal to [0.707, 0, 0].Finally, the output vector is computed by multiplying the attention vector with the values V as follows: [0.707, 0, 0].[1, 2, 3, 4] = 1.414.[0.5, 1.0, -0.5] = [0.707, 1.414, -0.707].
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a 1-w, 350-ω resistor is connected to 24 v. Is this resistor operating within its power rating?
Answer:
No.
Explanation:
\(P_r\) = Power rating = 1 W
R = Resistance = \(350\ \Omega\)
V = Voltage = \(24\ \text{V}\)
Power is given by
\(P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}\)
\(1.65\ \text{W}>1\ \text{W}\)
So
\(P>P_r\)
Hence, the resistor is not operating within its power rating.
This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
John has just graduated from State University. He owes $35,000 in college loans, but he does not have a job yet. The college loan company has agreed to give John a break on a deferred-payment plan that works as follows. John will not have to repay his loan for 5 years. During this “grace period” the loan obligation will compound at 4% per year. For the next 5 years, a monthly payment will be required, and the interest rate will be 0.5% per month. What will be John’s monthly payment over the 60-month repayment period?
Answer:
The correct response is "821.88". A further explanation is given below.
Explanation:
According to the question,
The largest amount unresolved after five years would have been:
= \(35000\times (\frac{F}{P}, 4 \ percent,5 )\)
= \(35000\times 1.216 7\)
= \(42584.50\)
Now,
time (t) will be:
= \(5\times 12\)
= \(60 \ monthly \ payments\)
So, monthly payment will be:
= \(42582.85\times (\frac{A}{P}, 0.5 \ percent,60 )\)
= \(42584.50\times 0.0193\)
= \(821.88\)
A well-hydrated human body is made up of about _______ percent water.
Answer:
70%
Explanation:
Using the following source code, answer the questions listed below. (a) Draw a control flow graph to represent the method Fun1, shown above. Label the nodes (starting with
A
) and the outgoing edges of the decision boxes appropriately. (b) Using the line labels in the code for method Fun1, identify all the def-use pairs for the variables
x
, k and
y
. (c) Identify a set of test cases that satisfies the all-defs criterion, for variables
x,k
and
y
in method Fun1. Use trace tables to show how the def-use pairs are covered. If you cannot achieve
100%
coverage for the all-defs criterion please explain why. (d) Identify a set of test cases that satisfies the all-uses criterion, for variables
x,k
and
y
in method Fun1. Use trace tables to show how the def-use pairs are covered. If you cannot achieve
100%
coverage for the all-uses criterion, please explain why.
A control flow graph to represent the method Fun1 using folloeing source code is here
if (number <0 || digit <0)
return -1
digitcount = 0
while (number >0)
if (number % 10)==digit)
digitcount++
number /=10
return digitcount
When a programmer creates programming statements using a text editor or a visual programming tool, they are typically saved in a file and are referred to as source code. When the source code is combined with a C compiler, an output file known as an object file is created.
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Multiple Choice
Which of the following analogies best describes the relationship between urban planning and zoning?
Zoning is like a hammer because it is used as a tool for urban planning.
Zoning is like a butterfly because it is the final form of urban planning.
Zoning is like a stop sign because it is an obstacle to urban planning.
Zoning is like an egg because it is the process from which urban planning emerges.
Answer:
Zoning is like a hammer because it is used as a tool for urban planning.
Boiler room log books area state of Minnesota requirement for ever boiler room, what are some of the things you should be writing down in the book?
Boiler room log books are a state of Minnesota requirement for every boiler room. It is important to maintain accurate records of the operation and maintenance of boilers to ensure they are operating safely and efficiently.
Some of the things that should be recorded in the log book include the date and time of each inspection, the condition of the boiler and any repairs that were made, the fuel usage and emissions data, and any changes in the operating procedures. It is also important to record any accidents or incidents that occur in the boiler room, as well as any training that is provided to employees who work in the room. Keeping a detailed and up-to-date log book can help prevent accidents, improve the efficiency of the boiler, and ensure compliance with state regulations.
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this is it dont anwser this is for my other account
Answer:
thanks for the poiunts
Explanation:
Which of the following is an example of a tax
Answer:
A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.
I dont know I asked this to
Explanation:
A 4-pole, 60-Hz, 690-V, delta-connected, three-phase induction motor develops 20 HP at full-load slip of 4%. 1) Determine the torque and the power developed at 4% slip when a reduced voltage of 340V is applied. 2) What must be the new slip for the motor to develop the same torque when the reduced voltage is applied
Answer:
1. i. 20 Nm ii. 4.85 HP
2. 16.5 %
Explanation:
1) Determine the torque and the power developed at 4% slip when a reduced voltage of 340V is applied.
i. Torque
Since slip is constant at 4 %,torque, T ∝ V² where V = voltage
Now, T₂/T₁ = V₂²/V₁² where T₁ = torque at 690 V = P/2πN where P = power = 20 HP = 20 × 746 W = 14920 W, N = rotor speed = N'(1 - s) where s = slip = 4% = 0.04 and N' = synchronous speed = 120f/p where f = frequency = 60 Hz and p = number of poles = 4.
So, N' = 120 × 60/4 = 30 × 60 = 1800 rpm
So, N = N'(1 - s) = 1800 rpm(1 - 0.04) = 1800 rpm(0.96) = 1728 rpm = 1728/60 = 28.8 rps
So, T = P/2πN = 14920 W/(2π × 28.8rps) = 14920 W/180.96 = 82.45 Nm
T₂ = torque at 340 V, V₁ = 690 V and V₂ = 340 V
So, T₂/T₁ = V₂²/V₁²
T₂ = (V₂²/V₁²)T₁
T₂ = (V₂/V₁)²T₁
T₂ = (340 V/690 V)²82.45 Nm
T₂ = (0.4928)²82.45 Nm
T₂ = (0.2428)82.45 Nm
T₂ = 20.02 Nm
T₂ ≅ 20 Nm
ii. Power
P = 2πT₂N'
= 2π × 20 Nm × 28.8 rps
= 1152π W
= 3619.11 W
converting to HP
= 3619.11 W/746 W
= 4.85 HP
2) What must be the new slip for the motor to develop the same torque when the reduced voltage is applied
Since torque T ∝ sV² where s = slip and V = voltage,
T₂/T₁ = s₂V₂²/s₁V₁²
where T₁ = torque at slip, s₁ = 4% and voltage V₁ = 690 V and T₂ = torque at slip, s₂ = unknown and voltage V₂ = 340 V
If the torque is the same, T₁ = T₂ ⇒ T₂T₁ = 1
So,
T₂/T₁ = s₂V₂²/s₁V₁²
1 = s₂V₂²/s₁V₁²
s₂V₂² = s₁V₁²
s₂ = s₁V₁²/V₂²
s₂ = s₁(V₁/V₂)²
substituting the values of the variables into the equation, we have
s₂ = s₁(V₁/V₂)²
s₂ = 4%(690/340)²
s₂ = 4%(2.0294)²
s₂ = 4%(4.119)
s₂ = 16.47 %
s₂ ≅ 16.5 %
What basic principle do reciprocating engines operate off of?
Answer:
Reciprocating engines operate on the basis principle of converting fuel/chemical energy into mechanical energy.
Explanation:
These are piston engines that uses up and down motions of pistons to convert pressure into rotational motion. The common types of a reciprocating engines are :
internal combustion enginesteam enginestirling engineThe engine utilizes 4 processes to complete a cycle, which are;
Intake-where a fuel mixture is put into the through the intake portCompression-where the fuel mixture is pushed to the top by the piston to compress it and ignite it through the spark plugIgnition- where the ignition pushes the piston back down to produce useful workExhaust-the waste chemical are eliminated out via the exhaust port and the cycle repeats.These processes indicate that chemical energy in the fuel mixture is converted to mechanical energy causing motion.
Heat-absorbing glass was developed to block more of Solar Radiation than light. True False
An Otto cycle takes in air at a temperature of 20°C and a pressure of 100 kPa. The high temperature is 1000°C and the compression ratio is 8. The specific heat for air at constant pressure is 1.00 kJ/kg K, and the specific heat for air at constant volume is 0.716 kJ/kg-K. The mass of air in a cylinder is 0.002 kg. If the specific heats stay constant, the clearance volume is most nearly :________
(A) 90 cm
(B) 120 cm3
(C) 180 cm
(D) 210 cm
applications of fleming hand rule
Answer:
Fleming hand rule represents the direction of current in a generator's windings and induced current as a conductor is attached to a circuit such that it moves in a magnetic field.
Explanation:
Fleming hand rule represents the direction of current in a generator's windings and induced current as a conductor is attached to a circuit such that it moves in a magnetic field.
Fleming hand rule is used in the case of electric motors and electric generators.
Fleming hand rule is used to determine the following:
1. Direction of torque
2. Angular velocity
3. Angular acceleration
Express the function n3/1000 − 100n2 − 100n + 3 in terms of Θ-notation.
The answer is Θ(n3).
Can someone explain why the answer is Θ(n3)?
We can say that the given function n^3/1000 - 100n^2 - 100n + 3 is in the Θ(n^3) notation, as it is bounded above and below by some multiple of n^3 for sufficiently large n.
To explain why the given function n^3/1000 - 100n^2 - 100n + 3 is in the Θ(n^3) notation, we need to show that it is bounded above and below by some multiple of n^3 for large enough n.
First, let's consider the highest-order term in the function, which is n^3/1000. As n grows larger, the influence of the other terms in the function diminishes relative to n^3/1000. Therefore, for sufficiently large n, the function is dominated by the term n^3/1000. We can drop the lower-order terms and coefficients and write the function as Θ(n^3/1000).
Next, we can simplify Θ(n^3/1000) to Θ(n^3) because Θ notation ignores constant factors. Specifically, any function that is bounded above and below by some multiple of n^3/1000 is also bounded above and below by some multiple of n^3. In other words, we can multiply n^3/1000 by any constant factor and still have a function that is Θ(n^3).
Therefore, we can say that the given function n^3/1000 - 100n^2 - 100n + 3 is in the Θ(n^3) notation, as it is bounded above and below by some multiple of n^3 for sufficiently large n.
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A production line manufactures 10-liter gasoline cans with a volume tolerance of up to 5%. The probability that any one is out of tolerance is 0.03. If five cans are selected at random. a) What is the probability that they are all out of tolerance? b) What is the probability that exactly two are out of tolerance?
Answer:
In the case of the production Line, we know that,
No of gasoline cans = 5
probability that 1st can is out of tolerance = 0.03
probability that 2nd can is out of tolerance = 0.03
.
.
probability that the 5th can is out of tolerance = 0.03
Therefore,
probability of 1st can out of tolerance + probability of 1st can not out of tolerance = 1
Probability of 1st can not out of tolerance = 1 -- 0.03 = 0.97
probability of 2nd can not out of tolerance = 0.97
.
.
probability of 5th can not out of tolerance = 0.97
Question A:
Probability that they are all out of tolerance
= P(1st can out of tolerance) * P(2nd can out of tolerance) * P(3rd can out of tolerance) * P(4th can out of tolerance) * P(5th can out of tolerance)
= (0.03 ) * (0.03) * (0.03) * (0.03) * (0.03) = 2.43 E⁻⁸ (2.43 ˣ 10⁻⁸)
Question B:
Probability that exactly two are out of tolerance
= P(1st can is out of tolerance) * P(2nd can is out of tolerance) * P(3rd can is not out of tolerance) * P(4th can is not out of tolerance) * P(5th can is not out of tolerance)
= (0.03) * (0.03) * (0.97) * (0.97) * (0.97) = 0.0008214057
Explanation:
For welding the most important reason to use jigs and fixtures in a welding shop is to
Answer:
Reduce manufacturing costs.
Explanation:
Hope This Helps
Have A Great Day
1. a major reason for the projected shortage of trained craft professionals is
a. construction salaries are too low
b. technology has eliminated many construction careers
c. demand for construction projects is declining
d. the retirement of baby boomers
A major reason for the projected shortage of trained craft professionals is that: b. technology has eliminated many construction careers.
What is computing?Autonomic computing can be defined as a process which involves the use of both computer hardware and software to manage, analyze, and process, so as to complete a goal-oriented task.
Also, autonomic computing systems are self-managing and it is similar in operations with the autonomic nervous system in humans, and as such it can be used in construction projects and assembly lines for optimum automated production.
In conclusion, automation technology through robots, smart machines and computers has reduced the need for people in many jobs, including trained craft professionals.
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A cantilever beam 2m long carrie a load of 10kn/m over 1m portion from fixed end and a point load of 20kn at free end. Calculate the maximum deflection of the cantilever beam. Take EI=2 x 10^9 KNmm^2
Answer:
The maximum deflection of a cantilever beam can be found using the equation for a cantilever beam under a point load and a distributed load:
δ = (PL^3)/(3 * EI) + (wl^2)/8 * (2L - wl)
where δ is the maximum deflection, P is the point load (20 kN), L is the length of the beam (2 m), w is the distributed load (10 kN/m), E is the Young's modulus of the material, I is the moment of inertia, and l is the length of the distributed load (1 m).
First, let's convert the loads to N and the length to mm:
P = 20 kN * 1000 N/kN = 20000 N
L = 2 m * 1000 mm/m = 2000 mm
w = 10 kN/m * 1000 N/kN * 1000 mm/m = 10000 N/mm
l = 1 m * 1000 mm/m = 1000 mm
EI = 2 x 10^9 KNmm^2
Next, let's plug the values into the equation for maximum deflection:
δ = (P * L^3)/(3 * EI) + (w * l^2)/8 * (2L - l)
δ = (20000 N * 2000^3 mm^3)/(3 * 2 x 10^9 KNmm^2) + (10000 N/mm * 1000^2 mm^2)/8 * (2 * 2000 mm - 1000 mm)
δ = (20000 * 8 x 10^9 mm^3)/(3 * 2 x 10^9 KNmm^2) + (10000 * 10^6 mm^2)/8 * (4000 mm - 1000 mm)
δ = 1.6 x 10^3 mm + 6.25 x 10^4 mm
δ = 6.41 x 10^4 mm = 64.1 mm
So the maximum deflection of the cantilever beam is 64.1 mm.
Explanation:
when electric power is transmitted over long distance, line losses can be reduced by generating AC rather than DC voltage and by transmitting?
When electric power is transferred over a long distance then, line loss can be reduced by high voltage and low current. Thus, option A is correct.
What is electric power?The complete question is attached to the image below.
The electric circuit transfers the electric current then it is called electric power. The loss in the line over a larger distance is reduced by transferring AC instead of DC voltage.
The AC transmitted is of high voltage, and the power is low. The equation for current is given,
P = VI
The increase in the voltage causes the decrease in the current and in turn the resistance also reduces resulting in the loss of the power of the circuit to decrease.
Therefore, the loss is reduced by transferring high voltage and, low current AC.
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External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter of the shaft of wind turbine is equal to 32 mm. Assume the shaft is subjected to a maximum load of 50,000 N during operation and the radius of the curvature of the crack is 3 x 10-2 mm. Determine the Fracture toughness KC of the shaft Express your answer in to four significant figures. Do not include the units.
Answer:
The correct answer is "\(K_c=6.0369 \ MPa\sqrt{m}\)".
Explanation:
Given:
Maximum load,
P = 50,000 N
Crack length,
a = 3mm
or,
= 3×10⁻³ m
Diameter,
d = 32 mm
As we know,
⇒ Maximum stress, \(\sigma=\frac{P}{A}\)
\(=\frac{50000}{(\frac{\pi}{4}\times 32^2)}\)
\(=62.20 \ N/mm^2\)
Now,
⇒ Fracture tougness, \(K_c=Y \sigma\sqrt{\pi a}\)
On substituting the values, we get
\(=1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}\)
\(=6.0369 \ MPa\sqrt{m}\)
analysis of structure
1. Compare and contrast data-centric and process-centric integration. What are the pros and cons of each? Is one of them better than the other? Why or why not? Which approach was used by TABCO, and why?
2. What are the top two strengths and weaknesses of the integration architecture solution proposed in the case study from IT and business perspective? Why?
3. Provide an overview of the project lifecycle from start to finish that was adopted by TABCO? What were the major strengths and weaknesses of the approach adopted by them?
Data-centric integration focuses on the data itself, such as making sure it is consistent and accurate, while process-centric integration focuses on the process by which the data is exchanged. The pros of data-centric integration include accuracy and scalability, while the pros of process-centric integration include speed and flexibility. One is not necessarily better than the other, as it depends on the particular business need.
TABCO used a process-centric approach in order to have greater flexibility and scalability in their integration. The top two strengths of the integration architecture solution from an IT perspective are scalability and extensibility, while from a business perspective it is cost-effectiveness and efficiency. The major weaknesses from an IT perspective are the lack of control and visibility, while from a business perspective they are the complexity of implementation and the long timeframe.
The project lifecycle adopted by TABCO consists of Planning, Design, Development, Testing, Deployment, and Maintenance. The major strengths of this approach include the ability to manage multiple activities at once and the clear timelines. The major weaknesses are the difficulty of making changes after deployment and the cost involved in ensuring the success of each phase.
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six 20 watt, 12 volt luminaires are supplied from a small, 12 volt transformer that is 60 feet away from the fixtures. the wire used is 14 awg. what is the voltage applied to the fixtures
If six 20 watt, 12 volt luminaires are supplied from a small. The voltage applied to the fixtures is: 8.61 volts.
Voltage applied to the fixturesFirst step is to find the amperes using this formula
I = P ÷ E
Where:
I =load current (amperes)=?
P =Product of voltage=(6)(20)
E =Electrical circuit's=12
Let plug in the formula
I= (6)(20) ÷ 12
I=120÷12
I= 10 amps
Second step is to determine the Voltage drop using this formula
Vd = [2KIL] ÷ CMA
Where:
Vd = Voltage drop( volts)=?
K= Direct current constant=11.6
I = Load current (amperes)= 10 amps
L = Length in feet=60 feet
CMA = Circular mill area= 4110
Let plug in the formula
Vd = [(2)(11.6)(10)(60)] ÷ 4110
Vd =13,920÷4110
Vd = 3.3869 volts
Third step is to find Voltage at fixture using this formula
Voltage at fixtures=Electrical circuit's-Voltage drop
Voltage at fixtures=12 - 3.3869
Voltage at fixtures=8.6131 volts
Voltage at fixtures=8.61 volts (Approximately)
Therefore 8.61 volts is the voltage applied to the fixtures.
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What is the importance of food handling machines in food industry (Explain in points).
Answer:
Explanation:
Profile photo for Rosie Milojevic
Rosie Milojevic, Business Development at iComplied
Answered 3 years ago
For those who run or work in a business that handles food, you understand the importance of food safety and regulation compliance as it pertains to not only to certification and licensing of a company, but also the life or death of those who consume the products. Because food safety is such an important issue, we want to ensure that all companies who work in the production, preparation, or processing of food have the tools and information they need to ensure they are in full compliance 100% of the time. One slip in food safety compliance could cost someone their health or life, and this information spreads mistrust in the general public toward the company who sold the product, and also the entire product across companies throughout an entire country and beyond. So how does each company working with food ensure they comply with each and every food safety regulation? Through excellent auditing tools.
Auditing in Food Safety Must Change
Auditing in food safety compliance is essential in ensuring that all regulations are being complied with. Most auditing practices for major companies are severely out of date. Many rely on several different forms, stacks of paperwork, and data stored on multiple different computers and databases. This is incredibly inefficient, as it can be easy to miss something when comparing one sheet to the next, and paper can easily be lost or destroyed. It is also time consuming for companies to share audits over separate computers and databases, as it must be passed down from one employee to the next. Technology has granted all food safety compliance managers a simple solution. Auditing apps are the new wave solutions for companies who want all of their data stored on one cloud database that is instantly accessible with real-time data for all employees. This means that no one ever gets left out of the loop, and no new information will fall through the cracks.
A Carnot heat engine absorbs 235 KW of heat from a heat source and rejects 164 KW to the atmosphere. Determine the thermal efficiency of the heat engine.
Answer:
43.2%
Explanation:
Given that,
Heat absorbed by a carnot heat engine, \(Q_1=235\ kW\)
Heat rejected to the atmosphere, \(Q_2=164\ kW\)
We need ti find the thermal efficiency of the heat engine. It is equal to the ratio of output work to the energy supplied. Its mathematical form is given by :
\(\eta=1-\dfrac{Q_1}{Q_2}\\\\\eta=1-\dfrac{235}{164}\\\\\eta=-0.432\)
or
\(\eta=-43.2\%\)
The egative value of efficiency shows work is done by the engine.
A rectangular channel 3-m-wide carries 12 m^3/s at a depth of 90cm. Is the flow subcritical or supercritical? For the same flowrate, what depth will five critical flow?
Answer:
Super critical
1.2 m
Explanation:
Q = Flow rate = \(12\ \text{m}^3/\text{s}\)
w = Width = 3 m
d = Depth = 90 cm = 0.9 m
A = Area = wd
v = Velocity
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
\(Q=Av\\\Rightarrow v=\dfrac{Q}{wd}\\\Rightarrow v=\dfrac{12}{3\times 0.9}\\\Rightarrow v=4.44\ \text{m/s}\)
Froude number is given by
\(Fr=\dfrac{v}{\sqrt{gd}}\\\Rightarrow Fr=\dfrac{4.44}{\sqrt{9.81\times 0.9}}\\\Rightarrow F_r=1.5\)
Since \(F_r>1\) the flow is super critical.
Flow is critical when \(Fr=1\)
Depth is given by
\(d=(\dfrac{Q^2}{gw^2})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{12^2}{9.81\times 3^2})^{\dfrac{1}{3}}\\\Rightarrow d=1.2\ \text{m}\)
The depth of the channel will be 1.2 m for critical flow.
A reservoir rock system located between a depth of 2153m and a depth of
2383m , as the pressure at these depths is 18.200 MPa , 19.643 MPa
respectively the thickness of oil zone 103m, if the density of water is 1060 kg/m3
Determine the oil and gas density. what is the pressure at the depth of 2200m ?
what is the depth at which the pressure is 1900 MPa? Determine the gas-oil and
oil- water contact depth.
To meet the recency of experience requirements to act as pilot in command carrying passengers at night, a pilot must have made at least three takeoffs and three landings to a full stop within the preceding 90 days in
A.
the same type of aircraft to be used.
B.
the same category and class of aircraft to be used.
C.
any aircraft.
The answer is B. the same category and class of aircraft to be used.
According to Federal Aviation Regulations (FAR) 61.57, to act as a pilot in command carrying passengers at night, a pilot must have made at least three takeoffs and three landings to a full stop between one hour after sunset and one hour before sunrise within the preceding 90 days in an aircraft of the same category, class, and type (if a type rating is required) that will be used.
Category refers to the broad classification of aircraft, such as airplane, rotorcraft, glider, etc.
Class refers to a further subdivision within each category based on specific characteristics, such as single-engine land, multi-engine land, or seaplane.
Type refers to a specific make and model of aircraft, such as a Cessna 172 or a Boeing 747, that may require a type rating for certain pilots.
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