which end condition of an extruded boss is used to add an equal amount of material to both sides of the sketch plane?

The total power derived from the the plate that heats the room, given the temperature in the room would be  2.065 W.

To calculate the total power radiated from the plate, we'll use the Stefan-Boltzmann law:

P = ε x σ x A x (T_plate^4 - T_room^4)

First, let's convert the temperatures to Kelvin:

Tplate = 79°C + 273.15K = 352.15K

Troom = 22°C + 273.15K = 295.15K

Now, we can plug in the values into the Stefan-Boltzmann law:

P = 0.63 x (5.67 x 10^-8 W/(m^2 x K^4)) x 0.307 m^2 x (352.15^4 K^4 - 295.15^4 K^4)

P ≈ 8.638 x 10^-6 x 239103.81

P = 2.065 W

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Article 440 permits the disconnect switch for a large rooftop air conditioner to be mounted inside the unit.  

Disconnecting devices must be placed so that they are easily visible from and reachable from the cooling or heating equipment. Installing the disconnecting device on or inside the air-conditioning or refrigeration equipment is allowed. An HVAC system known as a packed rooftop unit, also known as an RTU, is a small unit that includes all the parts required to supply conditioned air. Packaged rooftop units are primarily used in small and large commercial applications. They are extremely well-liked by commercial and industrial properties.

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The correct answer is  115 GPa (16.7 × 106 psi) is the minimum permissible radius of the bone.if a circular solid bone with allowable compressive stress of 130 mpa.

A fundamental unit of pressure or tension measurement in the International System of Weights and Measures is the megaPascal (abbreviated MPa). 1 MPa is equal to 1 N/mm2 and 145 psi. Units of measurement lower than 1 psi typically have limited applicability in the oil industry. Million pascals make up one megapascal. The MPa is primarily used to express the pressure ranges and ratings of hydraulic systems because of its bigger value (1 MPa = 10 bar), which makes it useful for higher range pressure measurement.MegaPascal, or MPa, is a metric pressure measurement equivalent to 1,000,000 Pa. A force of 1 Newton produces a pressure of 1 Pa, or Pascal, on a surface area of 1 square meter.

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Answer:

nah none of those i would get a tesla, mclaren, corvette, or even a toyota camery or tundra!

Explanation:

my dads is really big into cars and stuuf so i learn a little lol! hope it helps! thanks for the points by the way!

Answer:

i can answer twice? free points thxxx

Explanation:

Answer: border-radius

Explanation:

For a brick veneer that bears on the foundation and continues to the top of the building without any intermediate bearing support, the maximum veneer height is limited to 30 ft.

Veneer (English for Furnier) or Verblendschale is a thin, light-transmitting ceramic covering for the teeth that is applied to the dental surface, particularly on front teeth, using specialty adhesive. The use of ceramic veneers often has no health risks, save from rare allergic reactions to the befestification material, as the ceramic material has a very high biocompatibility. Problems only arise with extensively fluoridated dental paste. Additionally, the necessary integration measures raise the possibility of chronic pulmonitis (Zahnmarkentzündung), which the doctor must disclose. Veneers can be used to fix minor dental issues such gaps in the teeth, discoloured teeth, and localized blemishes. Veneers provide teeth's visible surfaces with an improved appearance. Usually, when they are used, old plastic fillers or corner builders are removed.

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The 74ls122 one-shot is a type of digital integrated circuit that generates a single pulse when triggered. In this case, we need to generate an output pulse of 3 ms duration using this one-shot.

To determine the value of external resistance required, we need to use the formula for the time period of the one-shot:

T = 1.1 x R x C

where T is the time period of the one-shot, R is the external resistance, and C is the capacitance. Since we want the output pulse to be 3 ms, we can convert this to seconds:

T = 0.003 s

Substituting this value into the formula, we get:

0.003 = 1.1 x R x 50000 x 10^-12

Simplifying this equation, we get:

R = 54.55 kohms

Therefore, an external resistance of 54.55 kohms is required to generate an output pulse of 3 ms duration using a 74ls122 one-shot and a capacitor of 50,000 pf.

In summary, we have determined the value of external resistance required to generate an output pulse of 3 ms duration using a 74ls122 one-shot and a capacitor of 50,000 pf. The value of external resistance is 54.55 kohms, which can be calculated using the formula T = 1.1 x R x C.

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Enthalpy Changes the overall energy change in the substance portrayed in the graph at  48°C.

Mass (m) = 0.3 Kg

Initial temperature (T1) = 20°C

Heat (Q) added = 35 KJ

Specific heat capacity (C) = 4.18 KJ/Kg°C

Final temperature (T2)

The final temperature of water can be obtained as follow:

Q = MC(T2 – T1)

35 = 0.3 x 4.18 (T2 – 20)

35 = 1.254 (T2 – 20)

Clear the bracket

35 = 1.254T2 – 25.08

Collect like terms

1254T2 = 35 + 25.08

1.254T2 = 60.08

Divide both side by the coefficient of T2 i.e 1.254

T2 = 60.08/1.254

T2 = 47.9 ≈ 48°C

Therefore, the final temperature of the water is 48°C.

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The Java program that accepts a matrix of M × N order and then interchanges diagonals of the matrix is given below:

//  Java Program to Accept a Matrix of Order M x N &

//  Interchange the Diagonals

import java.util.Scanner;

public class InterchangeDiagonals {

   public static void main(String[] args)

   {

       // declare variable

       int m, n, i, j, temp;

       // create a object of scanner class

       Scanner sc = new Scanner(System.in);

       System.out.print("Enter number of rows ");

       // take number of rows

       m = sc.nextInt();

       System.out.print("Enter number of columns ");

       // take number of columns

       n = sc.nextInt();

       // declare a mxn order array

       int a[][] = new int[m][n];

       // if block it's execute when m is equals to n

       if (m == n) {

           System.out.println(

               "Enter all the values of matrix ");

           // take the matrix inputs

           for (i = 0; i < m; i++) {

               for (j = 0; j < n; j++) {

                   a[i][j] = sc.nextInt();

               }

           }

           System.out.println("original Matrix:");

           // print the original matrix

           for (i = 0; i < m; i++) {

               for (j = 0; j < n; j++) {

                   System.out.print(a[i][j] + " ");

               }

               System.out.println("");

           }

          // perform interchange

           for (j = 0; j < m; j++) {

               temp = a[j][j];

               a[j][j] = a[j][n - 1 - j];

               a[j][n - 1 - j] = temp;

           }

           System.out.println(

               " after interchanging diagonals of matrix ");

           // print interchanged matrix

           for (i = 0; i < m; i++) {

               for (j = 0; j < n; j++) {

                   System.out.print(a[i][j] + " ");

               }

               System.out.println("");

           }

       }

       // else block it's only execute when m is not equals

       // to n

       else {

           System.out.println("Rows not equal to columns");

       }

   }

}

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Yes, it is possible to simulate the deflection of a bridge due to a crowd jumping on it in a static study in SolidWorks simulation.

Here are the steps to do so

1. Open SolidWorks and create a new assembly file.

2. Create the 3D model of the bridge and apply materials.

3. Apply external loads and boundary conditions to the model in SolidWorks Simulation.

4. Run the static study and analyze the results to see the deflection caused by the crowd jumping on the bridge.

To simulate the deflection of a bridge due to a crowd jumping on it, you need to apply the external loads that are produced when a crowd jumps on the bridge. These loads can be modeled as point loads or distributed loads in SolidWorks Simulation. The boundary conditions also need to be applied to the bridge model to ensure that it is properly constrained. Once the external loads and boundary conditions are applied, you can run the static study to analyze the results and see the deflection caused by the crowd jumping on the bridge.

SolidWorks Simulation is a powerful tool that allows engineers to simulate the behavior of a wide range of structures and systems. By using it to simulate the deflection of a bridge due to a crowd jumping on it, you can gain valuable insights into the design of the bridge and make improvements to ensure its safety and durability.

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According to the presentation, the answer choice that is NOT a food safety concern is A. Antibiotics

Foodborne illnesses: This refers to illnesses that are caused by consuming contaminated food. Foodborne illnesses can be caused by bacteria, viruses, parasites, and toxins.

Antibiotics: The use of antibiotics in livestock and poultry production can lead to the development of antibiotic-resistant bacteria, which can pose a threat to human health.

Genetically modified organisms (GMOs): Some people are concerned about the safety of GMOs and their potential long-term effects on human health and the environment.

Processed food products: Processed foods can contain additives, preservatives, and other chemicals that may be harmful to human health.

Overall, food safety concerns are important because they can have serious implications for public health. It is important for individuals, food producers, and regulators to take steps to ensure that the food supply is safe and free from contamination.

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Answer:

I think it is false!

Explanation:

Answer: I think it's true

Explanation:

Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.

Answer:

At temperature is and relative humidity is 86% therefore,  the humidity ratio is 0.0223 and the specific volume is 14.289

At temperature is and Relative humidity is 40% therefore, the humidity ratio is  0.0066 and the specific volume is 13.535.

To calculate the mass of air can be calculated as follows:

Now , we going to calculate the volume,

The time which is required to fill the cistern can be calculated as follows:

Now, putting the value in above formula we get,

Therefore, the hours required to fill the cistern is 4.65 hours.

Explanation:

According to the HST data, very distant (and early) galaxies tend to be smaller, bluer, and more irregular than modern ones.

The Hubble Space Telescope (HST) has allowed astronomers to observe galaxies at great distances and thus look back in time to see what galaxies were like in the early universe. The observations show that distant galaxies tend to be smaller, bluer, and more irregular than modern galaxies. This is because galaxies have evolved over time, with smaller galaxies merging to form larger ones and the formation of new stars slowing down over time. The blue color of distant galaxies is due to the fact that they are forming new stars at a much higher rate than modern galaxies. The irregular shape of distant galaxies is due to the fact that they have not yet formed into the well-defined spiral and elliptical shapes that are more common in modern galaxies.

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Answer:

3270 N/m^2

Explanation:

we can calculate the pressure difference between the bottom and surface of the tank by applying the equation for the net vertical pressure

Py = - Ph ( g ± a )

for a downward movement

Py = - Ph ( g - a )  ------ ( 1 )

From the above data given will  be

p = 1000 kg/m^3, h = 2/3 * 0.5 = 0.33 m , a =2g , g = 9.81

input values into equation 1  becomes

Py =  -Ph ( g - 2g ) = Phg ------ ( 3 )

Py = 1000 * 0.33 * 9.81

    = 3270 N/m^2

Answer:

Answer:

The voltages of all nodes are, IE = 4.65 mA, IB =46.039μA,  IC=4.6039 mA, VB = 10v, VE =10.7, Vc =4.6039 v

Explanation:

Solution

Given that:

V+ = 20v

Re = 2kΩ

Rc = 1kΩ

Now we will amke use of the method KVL in the loop.

= - Ve + IE . Re + VEB + VB = 0

Thus

IE = V+ -VEB -VB/Re

Which gives us the following:

IE = 20-0.7 - 10/2k

= 9.3/2k

so, IE = 4.65 mA

IB = IE/β +1 = 4.65 m /101

Thus,

IB = 0.046039 mA

IB = 46.039μA

IC =βIB

Now,

IC = 100 * 0.046039

IC is 4.6039 mA

Now,

VB = 10v

VE = VB + VEB

= 10 +0.7 = 10.7 v

So,

Vc =Ic . Rc = 4.6039 * 1k

=4.6039 v

Finally, this is the table summary from calculations carried out.

Summary Table

Parameters          IE       IC           IB            VE       VB         Vc

Unit                     mA     mA          μA            V           V          V

Value                  4.65    4.6039   46.039    10.7      10     4.6039

Answer:

all this could led to the failure of the garden hose and the tear along the length

Explanation:

For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :

hoop stress ( which acts along the circumference of the pipe):

αh = \(\frac{PD}{2T}\)     EQUATION 1

and Longitudinal stress ( acting along the length of the pipe )

αl = \(\frac{PD}{4T}\)       EQUATION 2

where p = water pressure inside the hose

          d = diameter of hose, T = thickness of hose

we can as well attribute the failure of the hose to the material used in making the hose .

assume for a thin cylindrical pipe material used to be

\(\frac{D}{T}\) ≥  20

insert this value into equation 1

αh = \(\frac{20 *30}{2}\)  = 60/2 = 30 psi

the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose

1. We can see here that three phase refers to a type of electrical power transmission that uses three alternating current (AC) waveforms that are 120 degrees out of phase with each other. This is different from single-phase power transmission, which uses only one AC waveform.

Voltage, also known as electric potential difference, is a measure of the electrical potential energy per unit of charge in an electrical circuit. It is defined as the amount of work required to move a unit of electric charge between two points in a circuit, typically measured in volts (V).

Three-phase power is needed because it allows for more power to be transmitted over a given amount of wire or cable. With three-phase power, the power is delivered in a more consistent manner, which means that there is less voltage drop over long distances.

2. In order for a three-phase system to be balanced, the three phases must have the same amplitude and be 120 degrees out of phase with each other. The voltage equation of a balanced three-phase voltage source is given by:

Vph = Vline / √3

where Vph is the phase voltage and Vline is the line voltage. The phasor diagram for a balanced three-phase system shows three sinusoidal waveforms that are displaced by 120 degrees from each other.

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Since P[X=n] is the same for every n, we can use the formula for the expected value of a discrete random variable, which is E[X] = Σ (n * P[X=n]). Since P[X=n] is the same for every n, we can simplify this formula to E[X] = Σ (n * p), where p is the probability of any given value.

We know that there are 7 consecutive integers from 0 to 6, so p = 1/7.
Therefore, E[X] = Σ (n * 1/7) = (0/7 + 1/7 + 2/7 + 3/7 + 4/7 + 5/7 + 6/7) / 7 = 21/2 * 1/7 = 3.
So the expected value of X is 3.
To calculate the expected value E[X] of a discrete random variable X with a uniform distribution over the set {0,1,...,6}, follow these steps:

1. Determine the probability of each outcome: Since P[X=n] is the same for every n, and there are 7 possible outcomes (0 to 6), the probability for each outcome is 1/7.
2. Multiply each outcome by its probability: Calculate the product of each integer in the set and its probability (1/7). For example, for the integer 0, the product is 0*(1/7), for 1, it's 1*(1/7), and so on.
3. Sum the products: Add up the products calculated in step 2: 0*(1/7) + 1*(1/7) + 2*(1/7) + 3*(1/7) + 4*(1/7) + 5*(1/7) + 6*(1/7).
4. Calculate E[X]: E[X] = 0*(1/7) + 1*(1/7) + 2*(1/7) + 3*(1/7) + 4*(1/7) + 5*(1/7) + 6*(1/7) = (1/7)(0 + 1 + 2 + 3 + 4 + 5 + 6) = (1/7)(21) = 3.
So, the expected value E[X] for the discrete random variable X over the set {0,1,...,6} is 3.

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Answer: maximum length of the nanowire is 510 nm

Explanation:

From the table of 'Thermo physical properties of selected nonmetallic solids at At T = 1500 K

Thermal conductivity of silicon carbide k = 30 W/m.K

Diameter of silicon carbide nanowire, D = 15 x 10⁻⁹ m  

lets consider the equation for the value of m

m = ( (hP/kAc)^1/2 )  = ( (4h/kD)^1/2 )  

m =  ( ((4 × 10⁵)/(30×15×10⁻⁹ ))^1/2 ) = 942809.04    

now lets find the value of h/mk    

h/mk = 10⁵ / ( 942809.04 × 30) =  0.00353

lets consider the value θ/θb by using the equation

θ/θb = (T - T∞) / (T - T∞)

θ/θb =  (3000 - 8000) / (2400 - 8000)

= 0.893

the temperature distribution at steady-state is expressed as;

θ/θb = [ cosh m(L - x) + ( h/mk) sinh m (L - x)]   / [cosh mL+  (h/mk) sinh mL]

θ/θb = [ cosh m(L - L) + ( h/mk) sinh m (L - L)]   / [cosh mL+  (h/mk) sinh mL]

θ/θb = [ 1 ]  / [cosh mL+  (h/mk) sinh mL]

so we substitute

0.893 =  [ 1 ]  / [cosh (942809.04 × L) +  (0.00353) sinh (942809.04 × L)]

L = 510 × 10⁻⁹m

L = 510 nm

therefore maximum length of the nanowire is 510 nm

Answer:

Explanation:

A scenario is an actual sequence of interactions (i.e., an instance) describing one specific situation; a use case is a general sequence of interactions (i.e., a class) describing all possible scenarios associated with a situation. Scenarios are used as examples and for clarifying details with the client. Use cases are used as complete descriptions to specify a user task or a set of related system features.

To determine if such crack growth is stable or unstable, mechanical testing needs to be performed.

The mechanical testing system can be regarded as the system that helps to measure materials in term of the strength.

Therefore, with mechanical testing, we can know how ductile or brittle the material is, and with this we can know if stable with the ductility.

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Let us take the initial distance between car A and B as d₀. Let the time taken by car A to stop after it starts decelerating at a be t seconds. Now, the acceleration of car A = a (given), which is constant and negative (because it is decelerating).

Therefore, the velocity of car A after t seconds, vA

= uA + at

= va – at …(1) (where uA

= va is the initial velocity)The distance traveled by car A after t seconds, dA

The velocity of car B, vb, remains constant at vb throughout. So, the distance traveled by car B during this time t,

dB = vb × t …(3)

Now, we can use the equation of motion: for calculating the distance traveled by car A and B, respectively, where s = d₀ (initial distance between the cars) – d (distance between the cars at time t).Applying the equation to car A,

dA = (va + vA)t/2

= (va + va - at)t/2

= (2va - at)t/2

= va × t - (1/2)at² …(4) (using equation (1))

Applying the same equation to car B,

dB = (vb + vb)t/2

= vb × t …(5) (using equation (3))

We know that when car A stops, its velocity vA = 0.So, from equation (1), we get t = va/a. Substituting this value of t in equation (4) and (5), we get:dA = va²/2a …(6)and dB = vb × va/a …(7). Subtracting equation (7) from (6), we get the distance d between the cars at the instant car A stops.

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Answer:

SpaceX

Explanation:

SpaceX successfully launches 60 more Starlink satellites as it continues towards 2020 service debut. SpaceX has launched another big batch of Starlink satellites, the low Earth orbit spacecraft that will provide connectivity for its globe-spanning high-bandwidth broadband internet network.

The Dry Unit Weight of the soil is 17.5 kN/m3, the Void Ratio is 0.347, the Porosity is 0.384, and the Degree of Saturation is 86.7%.

B. The Dry Unit Weight of the soil can be calculated using the formula γd = γw(1-w), where γd is the dry unit weight, γw is the moist unit weight, and w is the moisture content.

In this case,  γd = γw(1-w)

γd = 19.6(1-0.143) = 17.5 kN/m3.

The Void Ratio is then calculated using the formula e = (w / (1-w)), where e is the void ratio and w is the moisture content. Plugging in the values from above,

e = (w / (1-w))

e = 0.143/(1-0.143) = 0.347.

The Porosity is then calculated using the formula n = e/[1 + (G•e)], where n is the porosity, e is the void ratio, and G is the specific gravity. In this case,

n = e/[1 + (G•e)]

n = 0.347/[1 + (2.75•0.347)] = 0.384.

Finally, the Degree of Saturation can be calculated using the formula S = w/(1 + (G•e)), where S is the degree of saturation and the other variables are the same as above. Thus,

S = w/(1 + (G•e))

S = 0.143/(1 + (2.75•0.347)) = 0.867 or 86.7%.

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Solid nonmetal elements are "poor conductors of heat and electricity that are brittle and break easily".

Elements that usually lack the characteristics of metals are called nonmetals. Nonmetals are generally poor conductors of electricity and heat because in nonmetals electrons are not free to move. Nonmetals can be in form of solids, gases, or liquids. Solid nonmetals are referred to as those nonmetals that are not ductile or malleable but are brittle or powdery. Solid nonmetals are breakable easily.

Therefore, it is concluded that solid nonmetals are bad conductors of electricity and heat that are brittle and break easily.

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Answer:

To find the stress you need to know the applied load. Without that information, it is not possible to determine the axial stress in each of the three rods.

Explanation:

To determine the axial stress in each of the three rods, you would need to know the applied load and the cross-sectional area of each rod. The formula for axial stress is:

Stress (σ) = Load (F) / Area (A)

The area of a rod can be determined using the formula:

Area = π * (diameter/2)^2

Where diameter is the diameter of the rod in inches.

So,

For rod 1(aluminum rod)

Area = π * (2.00/2)^2 = 3.14 in^2

For rod 2(brass rod)

Area = π * (1.50/2)^2 = 1.77 in^2

For rod 3(steel rod)

Area = π * (3.00/2)^2 = 7.07 in^2

To find the stress you need to know the applied load. Without that information, it is not possible to determine the axial stress in each of the three rods.