Which expression is equivalent to x-6?

Answer:

All real numbers are solutions.

Step-by-step explanation:

Let's solve your equation step-by-step.

10−4v=−2−4(−3+v)

Step 1: Simplify both sides of the equation.

10−4v=−2−4(−3+v)

10+−4v=−2+(−4)(−3)+(−4)(v)(Distribute)

10+−4v=−2+12+−4v

−4v+10=(−4v)+(−2+12)(Combine Like Terms)

−4v+10=−4v+10

−4v+10=−4v+10

Step 2: Add 4v to both sides.

−4v+10+4v=−4v+10+4v

10=10

Step 3: Subtract 10 from both sides.

10−10=10−10

0=0

Answer:

Part A:

The baker uses 5.5 pounds of flour daily, which is equal to 5.5 x 16 = 88 ounces of flour daily.

In two weeks (14 days), the baker will use 88 x 14 = 1232 ounces of flour.

Therefore, the baker will use 1232 ounces of flour in two weeks.

Part B:

If the baker uses 12 ounces of flour to make one loaf of bread, then the number of loaves he can make with 1232 ounces of flour is:

1232/12 = 102.67

However, the baker cannot make a fraction of a loaf, so he can only make 102 full loaves of bread.

Therefore, the baker can make 102 full loaves of bread in two weeks.

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

Brian is constructing figures inscribed in circle C.

Equilateral triangle MNQ inscribed in circle C:

This option is possible since the points M, N, and Q are labeled and they lie on circle C.

Equilateral triangle ANP inscribed in circle C:

This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.

Regular hexagon AMNBPQ inscribed in circle C:

This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.

Square MNPQ inscribed in circle C:

This option is not possible based on the given information. The label points do not form a square.

Square ANBQ inscribed in circle C:

This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

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Is this how we solve it?

8 6/12 by - 6 4/5 = A

Hope this helps

i think that's how  we are supposed to do the problem can someone do a walk through for me with variables so i can find it on my own i just need help. I was trying to find a tutor cause I'm confused. But is that how were supposed to do it cause tutor.com isn't working.

Most likely we have to simplify and then subtract it? I hope that's how you solve it!

nvm i think i got it

Answer:

Step-by-step explanation:

Answer:

18 = 3 × 6

Step-by-step explanation:

Given:

Angle of depression = 56 degrees

Vertical height = 11

Let's draw the diagram:

Therefore, we have:

Since we are to find hypotenuse, we use:

wher x is the distance between Annie and her puppy

Solving further, we have:

The distance between Annie and her puppy is 13.3 ft

ANSWER:

13.3 FT

Answer:

5.928 liters is the correct answer

Step-by-step explanation:

Since 1 milliliter is 0.001 liters

Multiply both values by 5928.

Therefore... 5928 milliliters equals 5.928 which is letter D

Answer:

The answer is 0.5928 liters

Step-by-step explanation:

1 liter is made of 1000 milliliters

So 5,929 ÷ 1000

gives us 0.5928

Answer:

7.22

Step-by-step explanation:

3.49+7.50+1.79= 12.78

20.00 -12.78=7.22

Supposing a spinner with 8 regions, 3 of which are B, there is a 0.375 = 37.5% probability of spinning a b.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we suppose a spinner with 8 outcomes, 3 of which are b, hence the probability is given by:

p = 3/8 = 0.375 = 37.5%.

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1)The ratio of Kelly’s blue bracelets to green bracelets is 5:4.

2)The snow days to days ratio is 20:1

3)There are 42 girls in the competition. The ratio of girls to boys who participated in the quiz bowl was 7 : 5. Solving the two ratios, Therefore, There are 30 boys in the competition.

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1)The ratio of Kelly’s blue bracelets to green bracelets is 5:4.

2)The snow days to days ratio is 20:1

3)There are 42 girls in the competition. The ratio of girls to boys who participated in the quiz bowl was 7 : 5. Solving the two ratios, Therefore, There are 30 boys in the competition.

Define ratio?

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Using the cross product for the proff of Pythagoras theorem, the correct step is

By the cross product property, AB² =  BC multiplied by BD

The cross product property is typically used to solve equations with two values, where the product of the extremes (the outer terms) is equal to the product of the means (the inner terms).

For the similar triangles, the ratio is as follows

BD / BA = BA / BC

BA² = BD * BC

and AB = BA, hence

BA² = BD * BC

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A common denominator is a shared multiple of the denominators of the fractions involved when adding or subtracting fractions. It enables fraction comparison and addition/subtraction.

Simplification is the process of reducing a fraction to its simplest form by dividing the numerator and denominator by their greatest common divisor. This is done to represent fractions in the simplest terms viable.

Conversion: The process of transferring a fraction from one form to another while retaining its equal value is known as conversion. Finding a common denominator or expressing a fraction in terms of a specified unit or fraction may be required.

Fraction Addition/Subtraction: When adding or subtracting fractions, a common denominator is required. This entails determining a common multiple of

To rewrite the expression 3 + 1/5 + 2/3 using fifteenths as the common denominator, we need to find a common denominator for 5 and 3, which is 15 (since 5 and 3 are both factors of 15).

First, let's convert the fractions 1/5 and 2/3 to fifteenths:

\((\frac{1}{5})(\frac{3}{3}) = \frac{3}{15}\)

\((\frac{2}{3})(\frac{5}{5}) = \frac{10}{15}\)

Now we can rewrite the expression using the common denominator:

\(3 + \frac{3}{15}+\frac{10}{15}\)

Answer:

$100

Step-by-step explanation:

40 is x. So, just plug in 40 into the equation:

2(40)+20=?

80+20=?

=100

Answer:

D=42

B and C =138

:)))))))))

Answer:

The triangles are similar.

Explanation:

Similar triangles have 3 pairs of congruent angles. In this diagram, we can see that the triangles WXP and WYZ share angle W, which is congruent to itself; therefore, they have at least 1 pair of congruent angles. We are given that angle X is congruent to angle Y, so that is a second pair of congruent angles. Finally, we know that angle P is congruent to angle Z because if two pairs of corresponding angles are congruent, then the third pair must also be congruent because the measures of the interior angles of both triangles have to add to 180°.

Combining the like terms, it is found that:

a) The simplified expression is: 4C + 3S + M.

b) Each friend earns $32.

To find the equivalent expression, we combine the like terms, as follows:

Hence the equivalent expression can be given as follows:

(16C + 12S + 4M)/4 = 4(4C + 3S + M)/4 = 4C + 3S + M.

For item b, we have that:

S = 3, M = 5, C = 4.5.

Hence:

4C + 3S + M = 4 x 4.5 + 3 x 3 + 5 = 32.

Each friend earns $32.

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Answer:

35

Step-by-step explanation:

35 because the two angles are added 22 and 123 = 145. 145-180=35

\(\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ \theta =\frac{\pi }{2}\\[1em] r=\frac{8}{3} \end{cases}\implies A=\cfrac{1}{2}\cdot \cfrac{\pi }{2}\cdot\left( \cfrac{8}{3} \right)^2 \\\\\\ A=\cfrac{1}{2}\cdot \cfrac{\pi }{2}\cdot \cfrac{64}{9}\implies A=\cfrac{16\pi }{9}\implies A\approx 5.59\)

Answer:

Overall, the steps for algebraically finding the range of a function are:

1.Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).

2.Find the domain of g(y), and this will be the range of f(x).

3.If you can't seem to solve for x, then try graphing the function to find the range.

Step-by-step explanation:

Answer:

Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).

Find the domain of g(y), and this will be the range of f(x).

If you can't seem to solve for x, then try graphing the function to find the range.

Step-by-step explanation:

Answer: 7,500

Step-by-step explanation: 5% of 150,000 is 7,500.

Answer:

DE

Step-by-step explanation:

D)9x + 6y = 3(3x + 2y)

E)9a + 6b + 3c = 3(3a + 2b + c)

there have the same concept

3*3x equals 9x and 3*3a is 9a

Answer:

Ight...

Step-by-step explanation:

Hi

Answer:

$223,787

Step-by-step explanation:

r = 0.02

C = 191,000

t = 8

S = 191,000 (1 + 0.02)⁸

Follow order of operations (PEMDAS).

S = 191,000 (1.02)⁸

S = 191,000 (1.171659381)

S = 223,786.9

(We want to round to the nearest dollar, which is the ones place, so ignore all digits after the tenths place.)

Rounding, S = 223,787

The different 2-member groups that are possible is 28

From the question, we have

Total number of members, n = 8

Numbers to selection, r = 2

The number of ways of selection could be drawn is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 8 and r = 2

Substitute the known values in the above equation

Total = ⁸C₂

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 8!/(6! * 2!)

Evaluate

Total = 28

Hence, the number of ways is 28

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The volume of the sphere is approximately 3431.82 cubic miles.

To find the volume of a sphere, we need the radius of the sphere. The length of a great circle is the circumference of the sphere, which is related to the radius by the formula C = 2πr, where C is the circumference and r is the radius.

In this case, we are given that the length of the great circle is 60 miles. We can use this information to find the radius of the sphere.

C = 2πr

60 = 2πr

Divide both sides of the equation by 2π:

r = 60 / (2π)

r = 30 / π

Now that we have the radius, we can use the formula for the volume of a sphere:

V = (4/3)πr³

V = (4/3)π(30/π)³

V = (4/3)π(27000/π³)

V = (4/3)π(27000/π³)

V = (4/3)π(27000/π³)

V = (4/3)(27000/π²)

V = (4/3)(27000/9.87) (approximating π to 3.14)

V ≈ 3431.82 cubic miles

Therefore, the volume of the sphere is approximately 3431.82 cubic miles.

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Question

You are given the great circle of a sphere is a length of 60 miles. What is the volume of the sphere?

The measurement that is closest to the volume of the sphere is given as follows:

1,767.1 in³.

The volume of an sphere of radius r is given by the multiplication of 4π by the radius cubed and divided by 3, hence the equation is presented as follows:

\(V = \frac{4\pi r^3}{3}\)

From the image given at the end of the answer, we have that the diameter is of 15 units, hence the radius of the sphere, which is half the diameter, is given as follows:

r = 0.5 x 15

r = 7.5 units.

Then the volume of the sphere is given as follows:

V = 4/3 x π x 7.5³

V = 1,767.1 in³.

The sphere is given by the image presented at the end of the answer.

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The x-coordinates of the points on the curve where the tangent line is horizontal will be option A.

(x² + y²)² = 4(x² – y²)

x⁴ + 2x²y² + y⁴ = 4x² - 4y²

y⁴ + 2x^2y² + 4y² - 4x² = 0

Now we can use implicit differentiation to find the derivative of y with respect to x:

4y³(dy/dx) + 4xy² + 4y(dy/dx)x² + 8y(dy/dx) - 8x = 0

Simplifying this expression, we get:

4y³(dy/dx) + 4xy² + 4xy²(dy/dx) + 8y(dy/dx) - 8x = 0

(dy/dx)(4y³ + 4x²y²) + 8y(dy/dx) = 8x - 4xy²

(dy/dx)(4y³ + 4x^2y² + 8y) = 4x(2-y²)

(dy/dx) = 4x(2-y²)/(4y³ + 4x²y² + 8y)

Based on the information, x-coordinates of the points on the curve where the tangent line is horizontal will be option A.

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Answer: 3 ≤ 47

Step-by-step explanation:

The inequality given is 3 ≤ 47.

To determine the solutions to this inequality, we need to find the values of x that satisfy the inequality.

Looking at the options provided:

x = 24: This is not a solution because 24 is less than 47.

x = 51: This is a solution because 51 is greater than or equal to 47.

x = 6: This is not a solution because 6 is less than 47.

x = 99: This is a solution because 99 is greater than or equal to 47.

Therefore, the solutions to the inequality 3 ≤ 47 are x = 51 and x = 99.

As, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively. So,  if a commutes with d, then it must be block diagonal.

Let's suppose that d is a diagonal matrix with repeated diagonal entries grouped contiguously, i.e.,

d = \(\begin{pmatrix} D_1 & 0 & 0 & \cdots & 0 \ 0 & D_1 & 0 & \cdots & 0 \ 0 & 0 & D_2 & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & D_k \end{pmatrix}\),

where \(D_1, D_2, \dots, D_k\) are scalars and appear with frequencies \(m_1, m_2, \dots, m_k\), respectively, so that \(m_1 + m_2 + \dots + m_k = n\), the size of the matrix.

Suppose that \(a\) is a matrix that commutes with d, i.e., ad = da.

Then, for any \(i \in {1, 2, \dots, k}\), we have

\(ad_{ii} = da_{ii}\)

Here, \(d_{ii}\) denotes the \(i$th\) diagonal entry of d, i.e., \(d_{ii} = D_i\) for \(i = 1, 2, \dots, k\). Since d is diagonal, \(d_{ij} = 0\) for \(i \neq j\), and

hence

\(ad_{ij} = da_{ij} = 0\)

for all \(i \neq j\).

Therefore, a is also diagonal, with diagonal entries \(a_{ii}\), and we have

\(a = \begin{pmatrix} a_{11} & 0 & 0 & \cdots & 0 \ 0 & a_{11} & 0 & \cdots & 0 \ 0 & 0 & a_{22} & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & a_{kk} \end{pmatrix}\)

Thus, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively.

Therefore, if a commutes with d, then it must be block diagonal.

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