Which of the following are equations for the line shown below? Check all that
apply.
(2, 2)
(-2,3)
A. y-2=-0.25(x-2)
B. y-3= -0.25(x+2)
C. y + 3 = -0.25(x-2)
D. y-3= -0.25(x-2). Check all that apply

The given problem is "In an isosceles triangle, the uneven side is 8 cm shorter than each of the equal sides. Calculate the sides of the triangle knowing that the perimeter is 31 cm.

To find,

The sides of the triangle.

Solution,

Let each of equal sides are x.

The unequal sides is x-8.

Perimeter is the sum of all the sides. So,

31 = x+x+x-8

31+8=3x

3x = 39

x = 13

So, the equal sides are 13 cm.

Unequal side = x-8

= 13-8

= 5 cm

Hence, two of the equal sides are 13 cm and unequal side is 5 cm.

Answer:

3a. 7.2

3b. 0.9

4a. 7.2

4b. 2.4

5a. 104

5b. 260

hope this helps, everything in bold is the correct answer,

have an awesome day, -TJ

Answer:

3.a. 36

b. 4.5

4.a. 7.2

b. 2.4

5.a. 104

b. 260

Step-by-step explanation:

100/20 = 5

18 x 5 = 90 (100%)

18 x 2 = 36

18/4 = 4.5

14.4/2 = 7.2

7.2/3 = 2.4

52 x 2 = 104 (100%)

(195/3) 4 = 65 x 4

65 x 4 = 260 (100%)

Answer:

False

Step-by-step explanation:

The side measurements of a triangle are accurate if:

-The two shorter sides of a triangle add up to greater than the largest side

3 + 5 = 8

9 > 8

So it's false

Answer:

60 yd

Step-by-step explanation:

Answer:

the answer to the question is = -9/35

Answer:

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol.

Step-by-step explanation:

It is called a "variable" or sometimes an "unknown"

A variable is an abstract storage location paired with an associated symbolic name, which contains some known or unknown quantity of information referred to as a value; or in simpler terms, a variable is a named container for a particular set of bits or type of data.

here, we have,

The letter "x" is often used in algebra to mean a value that is not yet known.

It is called a "variable" or sometimes an "unknown".

In x + 2 = 7, x is a variable, but we can work out its value if we try!

A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol.

Hence, x is called a "variable" or sometimes an "unknown".

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Thus,  the store sold 9 purses and 27 blouses on that day, and the total revenue from selling these items was $1107.

To solve this problem, we need to use algebraic equations. Let's start by assigning variables to the unknown quantities. Let x be the number of purses sold and y be the number of blouses sold.

From the problem, we know that the blouses cost $28 each and the purses cost $39 each. Therefore, the total revenue from selling x purses and y blouses is given by:

Revenue = 28y + 39x

We also know that the store sold three times as many blouses as purses. Therefore, we can write:
y = 3x

Now we can substitute y = 3x into the revenue equation and solve for x:
1107 = 28y + 39x
1107 = 28(3x) + 39x
1107 = 84x + 39x
1107 = 123x
x = 9

So the store sold 9 purses. To find the number of blouses, we can use the equation y = 3x:
y = 3x = 3(9) = 27

Therefore, the store sold 27 blouses.

In summary, the store sold 9 purses and 27 blouses on that day, and the total revenue from selling these items was $1107.

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Answer:

rotate the image by 180

Step-by-step explanation:

use something clear possibly paper

trace the image exactly how it is

make a point possibly in the middle of the image

turn the clear object or paper 180 degrees

then that is the image

The vector A is (49.9m) x and vector B is (1.5m) x.

In the given question, A − B = (−51.4m)x, C =(62.2m)x, and A +B +C =(13.8m)x.

Find the vector A. Find the vector B.

We may disregard the vector x and treat the issue as an arithmetic one since all of the measurements are in the same direction (simultaneous equations).

A − B = −51.4.............................(1)

C = 62.2.............................(2)

A + B + C = 13.8.............................(3)

Now putting the value of C from Equation (2) in Equation (3)

A + B + C = 13.8

A + B + 62.2 = 13.8

Subtract 62.2 on both side, we get

A + B = 13.8 - 62.2

A + B = - 48.4.....................(4)

Adding the equation (1) and (4), we get

2A = - 99.8

Divide by 2 on both side, we get

A = - 49.9

Now subtracting the equation (1) and (4), we get

2B = -48.4 - ( -51.4)

2B = 3

Divide by 2 on both side, we get

B = 1.5

Since all of the calculations are done in terms of the unit vector x.

So the answer is vector B = (1.5m) x and vector A = (49.9m) x.

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The test statistic of null and alternative hypotheses for a test is 0.811.

69 of the 142 persons that were randomly chosen from a sample are found to meet the condition we are testing.

The sample proportion phat = 69 ÷ 142 = 0.489

n = 69

p = 0.54

the following are your test's null and alternate hypotheses:

\(H_0\) : p = 0.54

\(H_a\) : p < 0.54,

test statistic,

z = (phat - p) ÷ √(p × (1 - p) ÷ n)

z = (0.489 - 0.54) ÷ √((0.79 × 0.21) ÷ 42) = 0.811

A test statistic is a figure obtained from a statistical analysis. It explains how distant the observational values seem to be from the null hypothesis, which states that there is no correlation between the variables or distinction between the sample groups.

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Answer:

q=-3.4

Step-by-step explanation:

The property scale factor make the similar shapes similar one.

The term shape in math refers the outline or the boundary of an object.

Here we need to find the property that makes the similar shape similar.

As per the definition of shape we have identified that the shape has the following property, they are listed as,

=> Length

=> Breadth

=> height.

All these are collectively called scaling factor,

Based on these values we have take the two similar shapes such as similar triangles, similar rectangles, similar square, are the shapes whose dimensions are in equal or common ratio but the size or length of their sides vary.

Therefore the common ratio is called the scale factor.

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Answer:

it will be 9

Step-by-step explanation:

because I know it well

After  creating all the new nodes, we can traverse the original list again and set the random pointers of each new node based on the mapping stored in the hash map. Finally, we can return the head of the new list.

This problem requires creating a deep copy of a linked list that contains an additional random pointer for each node.

The  random pointer can point to any node in the list or be null.

To  solve this problem, we need to traverse the original linked list and create a new node for each node in the original list. The new node should have the same value as the original node and a null random pointer. We can store a mapping between the original node and the new node in a hash map.

After  creating all the new nodes, we can traverse the original list again and set the random pointers of each new node based on the mapping stored in the hash map. Finally, we can return the head of the new list.

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We need to calculate the total daily dosage based on the patient's weight and divide it into three equal doses. Each dose of gentamicin should be approximately 114 mg.


To determine the amount of gentamicin to be administered for each dose, we need to calculate the total daily dosage based on the patient's weight and divide it into three equal doses.

First, we convert the patient's weight from pounds to kilograms: 188 lb ≈ 85.27 kg.

Next, we calculate the total daily dosage of gentamicin based on the weight: 4 mg/kg/day × 85.27 kg = 341.08 mg/day.

Since the total daily dosage should be divided into three equal doses, we divide 341.08 mg by 3: 341.08 mg ÷ 3 = 113.693 mg.

Rounding to the nearest whole number, each dose should be approximately 114 mg of gentamicin.


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Answer:

B

Step-by-step explanation:

9x20=180

Answer:

  (r; θ) =

Step-by-step explanation:

You want the polar coordinates corresponding to the Cartesian coordinates ...

The relation between polar and cartesian coordinates is ...

  (x, y) ⇒ (√(x²+y²); arctan(y/x))

where the arctangent function takes quadrant into account.

The attachment shows a calculator's output where the Cartesian coordinates are translated to the complex plane. The negative angle is converted to a positive angle by adding 2π radians.

As an example of how this works, we can use ...

  c) (-2, -2√3) ⇒ (√((-2)² +(-2√3)²); arctan((-2√3)/-2))

  ⇒ (√16; arctan(√3)) . . . . . . where the angle is a 3rd quadrant angle

  ⇒ (4; π+π/3) = (4; 4π/3)

The polar coordinates are ...

  a.) (6; π/6)

  b.) (6; 5π/6)

  c.) (4; 4π/3)

__

Additional comment

There are several possible notations for polar coordinates. We have used one that is similar to the notation (x, y) for Cartesian coordinates, but uses a semicolon (;) separator to identify the ordered pair as polar coordinates.

The calculator uses a notation r∠θ, which we like for its compactness. Some calculators write both forms as vectors [x, y] or [r, θ] and leave it to the user to interpret the values appropriately.

Other notations used for polar coordinates are r(cos(θ), sin(θ)) or r(cos(θ)+i·sin(θ)) or r cis θ. The last of these is an abbreviation of the one before.

<95141404393>

Answer:

Given, m = 3 and n = 4

5×3 + 4×4 – 3

15 + 16 - 3

31 - 3

28

don't forget to like and mark me

Answer:

A C

Step-by-step explanation:

Answer:

Step-by-step explanation:

Leah wants to earn at least 120 dollars a month and she has two job options. This is written as

5x + 8y > 120

She also can't work more than 20 hours, leading us to the second equation

x + y = 20

First we solve for one variable

y = 20 - x

then substitute it into the first equation

5x + 8(20 - x) = 120

Solve for x

5x + 160 - 8x = 120

3x = 40

     x = 40/3

Then we solve for y

y = 20 - x

     y = 20/3

x < 40/3

y > 20/3

B and D will not work because their x+y is greater than 20.

E will also not work because the value is less than 120

To calculate the present value of a zero-coupon bond, we can use the formula: Present Value = Future Value / (1 + Interest Rate)^n

where Future Value is the par value of the bond, Interest Rate is the annual market interest rate, and n is the number of years. In this case, the Future Value is $2,000, the Interest Rate is 10% (or 0.10), and the number of years is 5. Using Excel, we can calculate the present value as follows:
1. In cell A1, enter the Future Value: 2000
2. In cell A2, enter the Interest Rate: 0.10
3. In cell A3, enter the number of years: 5
4. In cell A4, enter the formula for calculating the present value: =A1 / (1 + A2)^A3
5. Press Enter to get the result.

The present value of the 5-year zero-coupon bond with a $2,000 par value and an annual market interest rate of 10% is $1,620.97.

The formula for present value calculates the current worth of a future amount by discounting it back to the present using the interest rate. In this case, the future value is $2,000, and we divide it by (1 + 0.10)^5 to account for the effect of compounding over 5 years. The result is the present value of $1,620.97, which represents the amount that is considered equivalent to receiving $2,000 in 5 years at a 10% interest rate.

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Answer:

the first error she made was that she used the wrong numbers to multiply by

Step-by-step explanation:

Answer:

Error: she replaced 36 with the unequaled value of 3+12.

Step-by-step explanation:

The first error made is 36 cannot be substituted with 3+12 because 36 doesn't equal 3+12. She might have been thinking 3(12)=36. She could have done 10+10+10+5+1 for 36 and did the following:

27(10+10+10+5+1)

270+270+270+135+27

(270+270)+(270+135)+27

(540)+(405)+27

972

We can conclude that there are no nontrivial clean pulsations for the given left-mounted beam with a simple support on the right.

To find the equation of clean pulsations for a left-mounted beam with a simple support on the right, we can use the differential equation that describes the deflection of the beam. Assuming the beam is subject to a distributed load and has certain boundary conditions, the equation governing the deflection can be written as:

d^2y/dx^2 + (chx)^2 * y = 0

Where:

y(x) is the deflection of the beam at position x,

d^2y/dx^2 is the second derivative of y with respect to x,

ch(x) is the hyperbolic cosine function.

To solve this differential equation, we can assume a solution in the form of y(x) = A * cosh(kx) + B * sinh(kx), where A and B are constants, and k is a constant to be determined.

Substituting this assumed solution into the differential equation, we get:

k^2 * (A * cosh(kx) + B * sinh(kx)) + (chx)^2 * (A * cosh(kx) + B * sinh(kx)) = 0

Simplifying the equation and applying the given identity (chx)^2 - (shx)^2 = 1, we have:

(A + A * chx^2) * cosh(kx) + (B + B * chx^2) * sinh(kx) = 0

For this equation to hold for all values of x, the coefficients of cosh(kx) and sinh(kx) must be zero. Therefore, we get the following equations:

A + A * chx^2 = 0

B + B * chx^2 = 0

Simplifying these equations, we have:

A * (1 + chx^2) = 0

B * (1 + chx^2) = 0

Since we are looking for nontrivial solutions (A and B not equal to zero), the expressions in parentheses must be zero:

1 + chx^2 = 0

Using the identity (sinx)^2 + (cosx)^2 = 1, we can rewrite this equation as:

1 + (1 - (sinx)^2) = 0

Simplifying further, we get:

2 - (sinx)^2 = 0

Solving for (sinx)^2, we find:

(sin x)^2 = 2

Since the square of the sine function cannot be negative, there are no real solutions to this equation. Therefore, we can conclude that there are no nontrivial clean pulsations for the given left-mounted beam with a simple support on the right.

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9-62+6 = -47

-47 squared is -2209

19-17 is 2

-2209/2 is -1104.5

Answer:

There ya go

Step-by-step explanation:

If Jerome wants to have read at least 85 pages by the end of the day on Friday, then the inequality that represents the situation will be 50 + 5p≥ 85

If Jerome wants to have read at least 85 pages by the end of the day on Friday, then the inequality that represents the situation will be 50 + 5p≥ 85

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There are 105 ml of Clinicare in the 300 ml solution. To determine the amount of Clinicare in a 300 ml solution, we consider the fact that the solution is 35% Clinicare.

This means that 35% of the total volume is Clinicare. To find the quantity of Clinicare in the solution, we multiply the total volume by the percentage of Clinicare.

35% of 300 ml = 0.35 * 300 ml = 105 ml

Hence, there are 105 ml of Clinicare in the 300 ml solution.

This calculation demonstrates how to determine the amount of a specific component in a solution when given the percentage. Understanding the composition of solutions is crucial for accurate medication administration and patient care in settings like the ICU.

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a. 40%

the total amount of people is 100%

assume a person gets either food poisoning or doens't get food poisoning

100% - 60% = 40%

Answer:

It's -15 than normal

Answer:

7.9

Explanation:

Using the half-life formula, there will be about \((0.5)^{11000/5730} \approx 7.9\) grams left.

Answer:

100ml

Step-by-step explanation:

100 ml

The value of capacitance (C) in the charging RC circuit is (1.1 × 10^-6 s) / 240 Ω

The value of the capacitance (C) in the charging RC circuit can be determined by the time constant formula, which relates the time constant (τ) to the resistance (R) and capacitance (C) in the circuit.

Using the given information, we can calculate the time constant. Given that the charge reaches 2/3 of its final value, we can consider this as the time it takes for the capacitor to charge to approximately 63.2% of its final value.

Using the formula τ = RC, we can rearrange it to solve for capacitance: C = τ/R.

Since the time constant is given as 1.1 microseconds (1.1 × 10^-6 seconds) and the resistance is 240 ohms, we can substitute these values into the equation:

C = (1.1 × 10^-6 s) / 240 Ω

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