Taste aversion is a learned response that does not occur without cognition.
option B.
What is Taste aversion?Taste aversion is an aversion to food that is poisonous, spoiled or has caused the body harm or sickness.
Also a taste aversion is a tendency to avoid or make negative associations with a food that you ate just before getting sick.
The conditions that does not explain why taste aversion breaks the rules of conditioning are;
Taste aversion requires no cognitive processes in order to develop.Taste aversion can develop after only one pairing of a stimulus and response.Taste aversion cannot be explained by using conditioning processes.So option B is the only option left, and it is the correct answer.
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Starfish Regrowth
If a starfish's arm is removed along with part of the center of the body. A whole new starfish can form from that broken piece. The amputated (cut off) starfish can also regenerate a new arm to replace the lost limb. Because two starfish are now formed from one, they will have identical chromosomes. If you see a starfish that has some arms significantly longer than the rest, this is a sign the animal has regenerated (regrow) some of its limbs.
Fill in the blanks below to make the statement accurate (true).
The starfish in this scenario that created a new starfish underwent _______________ reproduction. The quote from the article that identifies this is ___________________________.
A. asexual ; “identical chromosomes”
B. sexual ; “identical chromosomes”
C. asexual ; “regenerated some of its limbs”
Answer:
A) Asexual reproduction; "identical chromosmes"
Explanation:
The graph below shows the heating curve for a substance as it changes from solid to gas.
a. Answer the questions in the table below.
The melting point of the substance in the heating curve is 20°C.
1) The melting point of the substance is the temperature at the point where, the substance is having a phase change from solid state to liquid. So, the temperature at point B, 20°C is its melting point.
2) The boiling point of the substance is the temperature at the point where, the substance is having a phase change from liquid state to gaseous state. So, the temperature at point D, 90°C is its boiling point.
3) The point A is where the substance is at solid state.
4) The substance is at liquid state at the point C.
5) The substance is at gaseous state at the point E.
6) At point B, solid state is changing to liquid state.
7) At point D, liquid state is changing to gaseous state.
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a ball rolling down a hill was displaced 21.9 m while using uniformly accelerating from rest, If the final velocity was 7.14 m/s, what was the rate of acceleration?
Answer:
a = 1.16 m/s²
Explanation:
In order to find the rate of acceleration of the ball, we will use third equation of motion, as follows:
2as = Vf² - Vi²
where,
a = rate of acceleration = ?
s = distance covered by the ball = 21.9 m
Vf = Final Velocity of the ball = 7.14 m/s
Vi = Initial Velocity of the ball = 0 m/s (Since, the ball started from rest)
Therefore,
2(a)(21.9 m) = (7.14 m/s)² - (0 m/s)²
a = (50.97 m²/s²)/(43.8 m)
a = 1.16 m/s²
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 22 ft/s2. What is the distance covered before the car comes to a stop
Answer:
The correct solution is "122.2211".
Explanation:
Given:
deceleration,
a = 22 ft/sec²
Initial velocity,
\(V_i=50 \ m/h\)
Now,
\(V_i=50 \ m/h\times 5280 \ ft/m\times hr/3600 \ s\)
\(=73.333 \ ft/sec\)
Now,
Final velocity,
\(V_f=0\)
Initial velocity,
\(V_{initial} = 73.333 \ ft/sec\)
hence,
⇒ \(V_f^2=V_i^2+2aD\)
By putting the values, we get
\(0=(73.333)^2+2\times( -22) D\)
\(44D=(73.333)^2\)
\(D=\frac{(73.333)^2}{44}\)
\(=122.2211\)
define torque of a couple
Couples. A couple is two equal forces which act in opposite directs on an object but not through the same point so they produce a turning effect. The moment (or torque) of a couple is calculated by multiplying the size of one of the force (F) by the perpendicular distance between the two forces (s).
A fish tank is 20 inches by 12 inches by 12 inches. What is its volume in m * m ^ 3
As the fish tank is 20 inches by 12 inches by 12 inches, its volume is 47194744.32 mm³.
What is volume?The space that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.
1 inch = 0.0254 meters.
20 inches = 20 × 0.0254 meters = 0.508 meters = 508 mm.
12 inches = 12 × 0.0254 meters = 0.3048 meters = 304.8 mm.
Hence, The volume of the fish tank = length × width × height
= 508 mm × 304.8 mm × 304.8 mm.
= 47194744.32 mm³
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Help on 9 and 10!!!!!! I’ll give 5 starts
Answer: part a is e
part b a
Explanation:
I HOPE THIS HELPS
An electrical circuit has a courent of 13A and 26 Ohm of resistance. What is voltage using the Ohm's law
The voltage in the circuit is 338 Volts.
Ohm's law states that the voltage (V) in a circuit is equal to the current (I) multiplied by the resistance (R): V = I x R.
1. Identify the given values: In this problem, we are given the current (I) and resistance (R) in the circuit.
2. Recall Ohm's law: V = I x R.
3. Substitute the given values: We can substitute the given values of current (I = 13A) and resistance (R = 26 Ohm) into Ohm's law to find the voltage (V).
4. Calculate the voltage: Using the equation V = I x R and substituting the values of current and resistance, we can calculate the voltage as V = 13A x 26 Ohm = 338 Volts.
Therefore, The voltage in the circuit is 338 Volts.
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You have two identical looking spools (same mass, same shape, same size). However, one is hollow, made from iron, the other is solid, made from aluminum. A string is wound around each spool. If you pull on both strings with equal forces, which spool is going to have the larger angular acceleration
Answer:
The one made from AL will have a smaller moment of inertia and thus a greater acceleration:
α = I ω
I = M R^2 for the iron (all the mass at a distance R)
Replacing any of the Fe with Al (and putting at a smaller radius) is going to reduce the total moment of inertia,
A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?
The potential energy of the lemming when it lands is 0.9108672 J.
To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the lemming (m) = 0.0780 kg
Height of the cliff (h) = 5.36 m
First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:
PE = mgh
PE = 0.0780 kg * 9.8 m/s² * 5.36 m
PE = 0.413616 J
Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.
Given:
Velocity of the lemming (v) = 4.84 m/s
Calculating the kinetic energy, we have:
KE = (1/2) * 0.0780 kg * (4.84 m/s)²
KE = 0.9108672 J
According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.
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A dust particle on a phonograph record rotates at a speed of 45 revolutions per minute if the particle is 10 cm from the axis of rotation. Find. 1) its linear speed and linear acceleration.
Explanation:
ω = 45 rev/min × (2π rad/rev) × (1 min / 60 s) = 4.71 rad/s
r = 10 cm = 0.10 m
1) The linear speed is:
v = ωr
v = (4.71 rad/s) (0.10 m)
v = 0.471 m/s
2) The linear acceleration in the tangential direction is 0.
The linear acceleration in the radial direction is:
a = v² / r
a = (0.471 m/s)² / (0.10 m)
a = 2.22 m/s²
Which of the following describes an electric insulator?
O A. A material that has a low resistance and prevents charges from
moving freely
B. A material that has a low resistance and allows charges to move
freely
C. A material that has a high resistance and prevents charges from
moving freely
D. A material that has a high resistance and allows charges to move
freely
The following that describes an electric insulator are :
C. A material that has a high resistance and prevents charges from moving freely.
The following that describes an electric insulator is a material that has a high resistance and prevents charges from moving freely. The conductors exhibit low resistance, which allows for the flow of current through it freely.Thus, the correct answer is C.
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A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s
Answer:
- 0.33 m/s
Explanation:
An illustration is shown above,
In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,
m1u1 - m2u2 = (m1 + m2)v
Where,
m1 = mass of the first object
u1 = initial velocity of the first object
v1 = final velocity of the first object
m2 = mass of the second object
u2 = initial velocity of the second object
v2 = final velocity of the second object
Therefore,
(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v
12 - 16 = 12v
-4 = 12v
Divide both sides by 12,
-4 / 12 = 12v / 12
-1 / 3 = v
v = -0.33 m/s
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A 250 pg dust particle has charge -250 e. Its speed is 2. 0 m/s at point 1, where the electric potential is v1=2000 v. What speed will it have at point 2, where the potential is v2=-5000 v? ignore air resistance and gravity.
A dust particle with a charge of 250 pg has a charge of -250 e. At point 1, where the electric potential is v1=2000 v, its speed is 2.0 m/s. It will have a speed of 1.238 m/s at point 2, where the potential is v2=-5000 v.
Let the speed be v₂at point 2.
Given a mass of m=250 pg.
At point 1, the speed isv₁=2.0 m/s.
Q=250e for the charge.
v₁=1200V is the electric potential at point 1.
v₂=-6500 V potential at point 2.
We can conclude from energy conservation that
\(\frac{1}{2}mv_{2}^{2}-\frac{1}{2}mv_{1}^{2}=\left ( V_{2}- V_{1} \right )Q or\: \: \: \: \: \: \: \:v_{2}^{2}=\frac{\left ( V_{2}- V_{1} \right )Q\times 2}{m}+v_{1}^{2}\)
\(or\: \: \: \: \: \: \: \:v_{2}^{2}=\frac{\left ( \left ( -6500 \right )- 1200 \right )\times \left ( 1.602\times 10^{-19}\times 250 \right )\times 2}{250\times 10^{-15}}+2^{2} or\: \: \: \: \: \: \: \:v_{2}^{2}=\frac{-15400\times \left ( 1.602\times 10^{-19}\times 250 \right )}{250\times 10^{-15}}+2^{2}\)
\(or v2 = -2.46708 + 4 = or\: \: \: \: \: \: \: \:v_{2}^{2}=1.53292 \therefore \: \: \: \: \: \: \: \:v_{2}=1.238111465\approx 1.238\: \: \: \: m/s\)
Electric potential, also known as voltage, is a measure of the electric potential energy per unit charge of an electric field at a point in space. It is a scalar quantity that describes the work required to move a unit positive charge from a reference point to a specific point in the field, without any acceleration. Electric potential is measured in volts (V), and its direction is determined by the direction of the electric field. The electric potential can be either positive or negative depending on the sign of the charge and the direction of the electric field. It plays an important role in many electrical applications, including the design and operation of electronic devices and power systems.
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Question 12 (10 points)
4) Listen
Ď (10,0 m)
25.00
Answer
53.0
B (15.0 m)
30,00
X
č (12.0 m)
X (8.00m)
For the vectors shown in the figure above
A+B+B. What is the
magnitude of
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
x10
units
Answer:
d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih
A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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A sled plus passenger with total mass m = 53.1 kg is pulled a distance d = 25.3 m across a horizontal, snow-packed surface for which the coefficient of kinetic friction with the sled is μk = 0.155. The pulling force is constant and makes an angle of φ = 28.3 degrees above horizontal. The sled moves at constant velocity.
Required:
a. Write an expression for the work done by the pulling force in terms of m, g (acceleration due to gravity), φ, μk, and d.
b. What is the work done by the pulling force, in joules?
c. Write an expression for the work done on the sled by friction in terms of m, g (acceleration due to gravity), φ, μk, and d.
d. What is the work done on the sled by friction, in joules?
Answer:
Explanation:
Force of friction
F = μ mg
μ is coefficient of friction , m is mass and g is acceleration due to gravity .
If f be the force applied to pull the sled , the horizontal component of force should be equal to frictional force
The vertical component of applied force will reduce the normal force or reaction force from the ground
Reaction force R = mg - f sin28.3
frictional force = μ R where μ is coefficient of friction
frictional force = μ x (mg - f sin28.3 )
This force should be equal to horizontal component of f
μ x (mg - f sin28.3 ) = f cos 28.3
μ x mg = f μsin28.3 + f cos 28.3
f = μ x mg / (μsin28.3 + cos 28.3 )
a )
work done by pulling force = force x displacement
f cos28.3 x d
μ x mg d cos28.3 / (μsin28.3 + cos 28.3 )
b ) Putting the given values
= .155 x 53.1 x 9.8 x 25.3 cos28.3 / ( .155 x sin28.3 + cos 28.3 )
= 1796.76 / (.073 + .88 )
= 1885.37 J
c )
Work done by frictional force
= frictional force x displacement
= - μ x (mg - f sin28.3 ) x d
= - μ x mgd + f μsin28.3 x d
= - μ x mgd + μsin28.3 x d x μ x mg / (μsin28.3 + cos 28.3 )
d )
Putting the values in the equation above
- .155 x 53.1 x 9.8 x 25.3 +
.155 x .474 x 25.3 x .155 x 53.1 x 9.8 /( .155 x .474 + .88)
= -2040.67 + 149.92 / .95347
= -2040.67 + 157.23
= -1883.44 J .
If the average hang time of a professional football kick is 4.4s, then determine the average maximum height.
The average highest height of a professional football kick is 189.728 m if the hang time is 4.4 seconds on average.
What is meant by hang time?A person or an object's total duration in the air after leaving the ground is known as their "hang time." From the time anything leaves the ground until it returns, it is measured.
We know,
y= gt²
Here,
y = Average maximum height
g = acceleration due to gravity
t = Average hang time
Given,
Average hang time (t) = 4.4s
Acceleration due to gravity (g) = 9.8 m/s² (assuming)
Inserting these values in the given equation,
y = gt²
= 9.8×4.4×4.4
= 189.728 m.
Hence, the average maximum height of the football is 189.728 m.
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Answer right I will cashapp $5
Someone made a copy of an analog wave and a digital wave. Compare the copies
with the original waves. Then, explain which type of wave is a more reliable way to
encode and transmit information.
Answer:
The original analog sound waves are perfect but the copy is not because most analog waves have wavelengths that are too long to reproduce in copies
The original digital waves and the copy are perfect because with digital waves no information gets lost in the transfer of data, and there is no additional noise added to the copy.
Analog refers to audio recorded using methods that replicate the original sound waves. Digital audio is recorded by taking samples of the original sound wave at a specified rate.
Explanation:
i dont need $5
i wrote this using information from go ogle and some from brai nly. I hope it helps.
A toy car is given an initial velocity of 5.0 m/s and experiences a constant
acceleration of 2.0 m/s/s. What is the final velocity after 6.0 s?
The final velocity after 6.0 s is
1304.2 .
What is velocity?
velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.
Solution -
As per the given-
Mass of runner m = 74kg
initial velocity of runner u=4.8 m/s
final velocity of runner v =0
Coefficient of friction ¥=0.7
Let's d be the distance moved by runner till the stop.
a- mechanical energy lost due to friction
As friction does negetive work causing the runner to stop.
As we know,
Mechanical energy lost= Kinetic energy of runner
Mechanical energy lost =
1/2 mv^2 = 1/2 ×74×4.8^2=852.2
Distance move by runner-
Work done by friction = mechanical energy lost
-¥×mg×d =852.2 j
-0.7×74×9.8×d = -491.2
Solving the equation we get
1304.2.
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500000000 in standard form
Answer:
5.0 x 10^8
Explanation:
because u moved it 8 times to it places
A frog is sitting on a lily pad when it sees a delicious fly. He darts out his tongue at a speed of 3.90 m/s to catch the fly. The tongue has a mass of 0.410 g, and the rest of the frog plus the lily pad have a mass of 12.5 g. What is the recoil speed of the frog and the lily pad? Ignore drag forces on the pad due to the water.
Answer:
Recoil speed of the frog and the lily pad, v₂ = 0.124 m/s
Explanation:
According to the law of conservation of linear momentum, in a closed system of colliding bodies, the momentum before collision is equal to the momentum after collision.
Momentum before collision = m₁v₁
momentum after collision = (m₁ + m₂)v₂
where m₁ = mass of the tongue; v₁ = velocity of the tongue; m₂ = mass of th frog and lily pad; v₂ = velocity of the frog and lily pad
m₁v₁ = (m₁ + m₂)v₂
v₂ = (m₁v₁)/(m₁ + m₂)
m₁ = 0.41 0 g = 0.00041 kg; v₁ = 3.90 m/s/; m₂ = 12.5 g = 0.0125 kg; v₂ = ?
v₂ = (0.00041 kg * 3.90 m/s)/(0.000410 + 0.0125 kg)
v₂ = 0.124 m/s
How to find the angle in a projectile motion when displacement and heigh are the same
projectile's vertical speed v yv y v, start , y, drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward
.
At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.
In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.
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Based on the stability classification, if, over the airport, rising air reaches the point of saturation below 3000 m, it is likely that:_______
Answer:
It is likely that vertically developed cumuliform clouds would begin to form
Explanation:
This is because since the air is conditionally unstable below 3000mand air were to be forced to rise to a point of saturation within this particular layer of the atmosphere
Explain how improving the EXERGY may be as good, if not better than discovering new/oil coal mines.
Answer:
It is necessary to search for new sources of energy because the sources we have now are non-renewable and exhaustible. The usage of these sources are increasing day by day and if this continues then one day we wlii be left with none so it is necessary to search for new sources of energy
PLEASE MARK ME BRAINLIESTAnswer ASAP and only if you know its correct
this is science btw
Answer:
jupiter
Explanation:
from the list, Jupiter is closest to the sun.
gamma-ray bursts are objects in the universe that emit pulses of gamma rays with high energies. the frequency of the most energetic bursts has been measured at around 3.0 x 1021 hz. what is the wavelength of these gamma rays?
answer options:
1: 1.0 x 10^29 m
2: 1.0 x 10^13 m
3: 1.0 x 10^-13 m
4: 1.0 x 10^-29 m
Answer:
The answer to your problem is, C. \(1.0 * 10^{3}\)
Explanation:
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.
The relationship between the wave's wavelength, frequency, and speed is given as
Formula ( That I use and you should use ) !
wavelength = speed of light / frequency
\(y = \frac{c}{v}\)
y in this case is the wave length v denotes the wave's speedf is the wave's frequency\(y = \frac{3*10^{3} }{3.0*10^{21} }\)
\(y = 1 * 10^{-13}\)
Thus the answer to your problem is, C. \(1.0 * 10^{3}\)
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The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)
The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:
F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².
Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.
The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.
Therefore, we have:
m₁ = 50 kg
m₂ = 7 × 10²² kg
r = 380,000,000 m
G = 6.7 × 10⁻¹¹ N m²/kg²
Substituting these values into the formula, we get:
F = (G × m₁ × m₂) / r²
F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²
F = 1.15 N
Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
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What is the magnetic field at the position of the dot in (Figure 1)? Give your answer as the components of a vector.
Answer:
200000000000 x 10^-7
Explanation:
The Biot Savart Law defines fundamental quantitative relationship between an electric current and the magnetic field it produces, based on the experiments in 1820 of the French scientists Jean-Baptiste Biot and Félix Savart.
The Biot-Savart law is applied in a specific case by adding up the contributions to the magnetic field at a given point from the whole series of short current segments that constitute a specific conductor of whatever shape
The force between two charged objects is 200N. If. the charge of one object increaes 3x and the other charge decreaes 4x, what will the new force be?
Given that the force between two charged particles, we'll call charge 1 and 2 is, \(\vec F_{0}=200 \ N\). The question asks us to find the new force between charges 1 and 2 if the charge on 1 increases by 3 times and the charge on 2 decreases by 4 times.
Equation to calculate the electric force between two charged particles:
\(\vec F_e=k_e\frac{q_1q_2}{r^2} \\\\ k_e=Coulomb's \ Constant= 8.99 \times 10^9 \ \frac{Nm^2}{C^2}\\\)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
\(\vec F_0=k_e\frac{q_1q_2}{r^2} =200 \ N \ and \ \boxed{\vec F_f=k_e\frac{(3 q_1)(\frac{1}{4} q_2)}{r^2} }\)
\(\Longrightarrow \vec F_f=k_e\frac{(3 q_1)(\frac{1}{4} q_2)}{r^2} \Longrightarrow \vec F_f=\frac{3}{4} k_e\frac{q_1 q_2}{r^2} \Longrightarrow \vec F_f=\frac{3}{4}(200) \Longrightarrow \boxed{\boxed{\vec F_f=150 \ N}}\)
Thus, the new force would be 150 N.
The new force will be 150N
The force between two charged objects is given by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law can be expressed as:
F = k * (q1 * q2) / r^2
where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two objects, and r is the distance between them.
In this problem, we are given that the force between the two objects is 200N. Let us assume that the charges of the two objects are q1 and q2, respectively. Using Coulomb's law, we can write:
200 = k * (q1 * q2) / r^2
Now, we are told that the charge of one object increases by a factor of 3, and the charge of the other object decreases by a factor of 4. Let us call the new charges q1' and q2', respectively. We can write:
q1' = 3 * q1
q2' = (1/4) * q2
Substituting these expressions into Coulomb's law, we get:
F' = k * (q1' * q2') / r^2
= k * [(3 * q1) * ((1/4) * q2)] / r^2
= k * (3/4) * (q1 * q2) / r^2
= (3/4) * F
Therefore, the new force between the two charged objects is 3/4 times the original force, or 150N.
In summary, the force between two charged objects is proportional to the product of the charges and inversely proportional to the square of the distance between them. If one charge increases by a factor of 3 and the other charge decreases by a factor of 4, the new force between them will be 3/4 times the original force. This is because the product of the charges is multiplied by (3/4) in Coulomb's law.
Know more about Coulomb's law here:
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