Which of the following substances has the highest melting point?
a. pentane b. nonane c. ethane d. butane

As per the information provided in the question, the compound that is the limiting reagent is "B". And the starting materials were "more polar" than the reaction product.

The limiting reagent is the one that gets consumed completely in the reaction. The other reactant is left behind in excess. The reaction's speed is determined by the amount of the limiting reagent present. In the given reaction, compound B is the limiting reagent. We can prove this by comparing the number of moles of compounds A and B. We can see that compound B has fewer moles. Therefore, it is the limiting reagent. 2 moles of compound A react with 1 mole of compound B. We have 2 moles of A and 1 mole of B in this reaction mixture. Hence, compound B is the limiting reagent. Starting materials are more polar than the reaction product. When a chemical reaction occurs, the reactants combine to form a new compound or product. The product's properties are often different from those of the starting materials. In this reaction, the starting materials are more polar than the reaction product. This can be seen by observing the reaction mixture's lane. We can see that the reaction product has moved ahead of the starting materials on the chromatogram. The starting materials are more polar than the reaction product.

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Answer:

1. (See explanation)

2. 46. 23 from the mother’s egg and 23 from the father’s sperm.

Explanation:

ok for number one I am not entirely sure, but I am pretty sure that light, chemicals and temperature can all affect which genes get turned on and off. I am not entirely sure if the question is asking about the environment influencing inherited traits in the form of natural selection tho? If that is something you’re seeing right now, it might be a possible answer. But honestly I am not completely sure.

Answer:0.085

Explanation:

The new pressure of the gas is approximately 838.74 torr.

To determine the new pressure of the gas, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature remains constant.

According to Boyle's Law, P1 * V1 = P2 * V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Given:

Initial volume (V1) = 516 ml

Initial pressure (P1) = 345 torr

Final volume (V2) = 213 ml

Using the formula and plugging in the values:

345 torr * 516 ml = P2 * 213 ml

Simplifying the equation:

P2 = (345 torr * 516 ml) / 213 ml

Calculating the value:

P2 ≈ 838.74 torr

Therefore, the gas now has a pressure of approximately 838.74 torr.

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The equilibrium constant can be obtained using ΔG°rxn = -RT lnK.

On the basis of this, 2H+ + 2e- → H2(g) reduction.

Therefore E° = 0V

Pb2+ + 2e- ⇄ Pb(s) - 0.126

Mg2+ + 2e- ⇄ Mg(s) -2.372

For total E°cell potential,

E°cell = Ered - Eoxd

Eoxd = -Ered of the one being oxidised

E°cell = -2.372 - (-0.126) = -2.246

E°cell = -2.246 V

Thus, calculating dG:

dG = -n x F x E°cell

dG = -2*96500*(-2.246)

=433478 J/mol

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The general equation for the reaction of a halogen with a metal (assuming a 2+ charge on the metal) is: 2M + X₂ → 2MX

In this equation, M represents the metal (with a 2+ charge) and X represents the halogen. The reaction involves the combination of one mole of the metal with one mole of the halogen to form two moles of the metal halide compound (MX).

The 2M on the left side of the equation represents two moles of the metal, each with a 2+ charge. The X₂ represents one mole of the halogen, which exists as a diatomic molecule (e.g., Cl₂, Br₂, I₂).

During the reaction, the metal atoms lose two electrons each to achieve a stable 2+ charge, and the halogen atoms gain one electron each to complete their valence shell. This results in the formation of two moles of the metal halide compound (MX) in which the metal is in its 2+ oxidation state and bonded to the halogen.

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Answer:

nitrogen

Explanation:

Answer:

Beryllium

Explanation:

The rate at which the condensate drips off the plate at the bottom is 597 g/s.

The rate of heat transfer by condensation to the plate is given as 180 kJ/s.

We can use the heat transfer equation to determine the rate at which the condensate drips off the plate. The heat transfer equation is;

Q = m(\(L_{f}\) + CpΔT)

Where Q is heat transferred, m is mass of the condensate, Lf is the latent heat of fusion, Cp is specific heat of the condensate, and ΔT is  temperature difference between the condensate and the plate.

At the point of condensation, the steam is at its saturation temperature of 100°C. The condensate will be at the same temperature as the plate, which is 90°C.

The latent heat of fusion for water is 2257 kJ/kg, and the specific heat of water is 4.18 kJ/kg-K.

To find the mass of the condensate, we need to use the steam tables. At 1 atm, the specific volume of saturated steam is 1.672 m³/kg. The volume of steam that condenses on the plate can be found by assuming that it is a thin film and using the surface area of the plate. Let's assume that the plate has a surface area of 1 m². Then the mass of the condensate is;

m = (1 m²) / (1.672 m³/kg) = 0.597 kg

Now we can plug in the values into the heat transfer equation:

180 kJ/s = (0.597 kg)(2257 kJ/kg + 4.18 kJ/kg-K(100°C - 90°C))

Solving for the rate at which the condensate drips off the plate, we get:

m = 0.597 kg/s = 597 g/s

Therefore, the rate is 597 g/s.

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Where is the word problems? Like the problems that you have to put it in.

Explanation:

The desired product can be obtained by reacting a ketone with a primary amine in the presence of a reducing agent, such as sodium cyanoborohydride. This reaction is known as reductive amination.

The desired product can be synthesized through a reductive amination reaction, which involves the condensation of a carbonyl compound with a primary amine followed by reduction. In this case, a ketone is required as the carbonyl compound.

The first step involves the condensation of the ketone with the primary amine. The carbonyl group of the ketone reacts with the amine group of the primary amine, forming an imine intermediate. This condensation reaction is typically catalyzed by an acid, such as hydrochloric acid or sulfuric acid. The imine intermediate is formed as an imine linkage between the carbon of the carbonyl group and the nitrogen of the amine group.

The second step is the reduction of the imine intermediate to the desired product. This reduction is achieved by using a reducing agent, such as sodium cyanoborohydride (NaBH3CN). The reducing agent donates a hydride ion (H-) to the imine, resulting in the formation of the desired product, which is an amine.

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Answer:

Carbonyl compounds which are of low molecular weight (organic acids, ketones, and aldehydes) can undergo carbon coupling reactions to produce gasoline and diesel.

The glucose solution has a molarity of 8.3333 M.

The freezing point depression is given by the formula ΔTf = Kf × m × i, where ΔTf is the change in freezing point, Kf is the freezing point depression constant, m is the molality of the solution, and i is the van't Hoff factor, which is 1 for glucose.

We can first calculate the molality of the solution using the freezing point depression formula:

ΔTf = Kf × m

m = ΔTf / Kf

m = (-10.3 °C) / (1.86 °C.kg/mole)

m = -5.53 mole/kg

We are given the density of the solution, which allows us to calculate the mass of the solution:

mass = density × volume

mass = 1.50 g/ml × 1000 ml

mass = 1500 g

Using the molarity formula, we can now calculate the molarity of the solution:

molarity = moles of solute / liters of solution

moles of solute = mass of solute / molar mass of solute

moles of solute = (1500 g) / (180.0 g/mole)

moles of solute = 8.3333 mole

liters of solution = mass of solution / density of solution

liters of solution = (1500 g) / (1.50 g/ml)

liters of solution = 1000 ml / 1000 ml/L

liters of solution = 1 L

molarity = 8.3333 mole / 1 L

molarity = 8.3333 M

Therefore, the molarity of the glucose solution is 8.3333 M.

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Answer:

The second one

Neutrons

The volume of 1.0 M copper(II) sulfate solution required to completely react with 1.0 g of Fe(s) is 26.9 mL.

To calculate the volume of 1.0 M copper(II) sulfate solution required to completely react with 1.0 g of Fe(s), we need to use stoichiometry. Here are the steps:

1. Calculate the number of moles of Fe(s) in 1.0 g:
1.0 g Fe(s) × (1 mol Fe/55.85 g) = 0.0179 mol Fe(s)

2. Use the balanced chemical equation to determine the number of moles of Cu2+(aq) needed to react with 0.0179 mol Fe(s):
0.0179 mol Fe(s) × (3 mol Cu2+/2 mol Fe) = 0.0269 mol Cu2+(aq)

3. Use the molarity of the copper(II) sulfate solution to calculate the volume of solution needed:
0.0269 mol Cu2+(aq) × (1 L/1.0 mol Cu2+) = 0.0269 L = 26.9 mL

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Answer:

cuz what we are shown in school often fails to foster curiosity in us.

Explanation:

Explanation:

because it have many laws, theory, reaction and many more which is enough to make a student depressed

An observer in one of those galaxies see the other galaxy moving away at 400000 km/s.

Relative velocity is the velocity of an object with respect to another object, that is the time rate of change of relative position of one object with respect to another object.

Since two galaxy are moving in opposite directions with a velocity of 200,000 km/s. Hence the relative velocity between the two galaxies is 400000 km/s (200000 + 200000)

Therefore an observer in one of those galaxies see the other galaxy moving away at 400000 km/s.

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Answer:

D 400,000km/s

Explanation:

Answer: A. The greater the pressure, the more of gas that will dissolve.

Explanation: Increasing pressure increases the solubility of gases. It has little effect on the solubility of liquids and solids.

The average atomic mass of uranium = 313.826 amu

What is average atomic mass ?

The weighted average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight. Unified atomic mass units (u), where 1 u is equal to precisely one-twelfth the mass of a neutral atom of carbon-12, are the standard units used to express average masses.

average atomic mass = \(( 312*37.26 + 313*2.79 + 315*59.95 )/100 = 313.826 amu\)

average atomic mass of uranium = 313.826 amu

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Cl and cl are isotopes of each other. the first one has 17 protons and 18 neutrons. the second one has 17 protons and 20 neutrons.

Isotopes were also members of the exact same element's family but also have different neutron numbers despite containing the same count of protons. On the Periodic Table, an element's atomic number is based on how many protons are in its nucleus.

Cl-35 have atomic number 17 , atomic mass is 35

Number of neutrons = atomic mass - atomic number

Number of neutrons = 35-17

Number of neutrons = 18

Cl-37 have atomic number 17 , atomic mass is 37

Number of neutrons = atomic mass - atomic number

Number of neutrons = 37-17

Number of neutrons = 20

Therefore, Cl-35 and Cl-37 are isotopes of each other. the first one has 17 protons and 18 neutrons. the second one has 17 protons and 17 neutrons.

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Electronegativity is tendency of an atom to attract a shared pair of electrons towards itself., i.e., option A is the correct choice.

Electronegativity is a degree of an atom's cap potential to draw shared electrons to itself. On the periodic table, electronegativity commonly will increase as you flow from left to proper throughout a length and reduces as you flow down a group. It determines how the shared electrons are disbursed among the 2 atoms in a bond. The extra strongly an atom draws the electrons in its bonds, the bigger its electronegativity. The higher the value of the electronegativity, the more strongly that element attracts the shared electrons.

Thus, the correct option is A i.e., electrons.

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Based on the terms you provided, it seems you are looking for the repeat unit of a polymer with different configurations. A repeat unit is the smallest structural segment that, when repeated, forms the polymer chain. The configurations listed (isotactic, syndiotactic, atactic, and random) describe the arrangement of side groups in the polymer chain. For a more accurate answer, please provide the specific polymer or chemical structure you're referring to, as the repeat unit will depend on the polymer in question.

A repeat unit is the smallest unit of a polymer that is repeated to form the overall polymer chain. In order to determine the repeat unit for a given polymer, we need to know its structure.
For an isotactic polymer, all of the substituent groups are on the same side of the polymer backbone. The repeat unit for an isotactic polymer might look something like this:
-CH(CH3)-CH(CH3)-CH(CH3)-CH(CH3)-
For a syndiotactic polymer, the substituent groups alternate sides of the polymer backbone. The repeat unit for a syndiotactic polymer might look something like this:
-CH(CH3)-CH(C6H5)-CH(CH3)-CH(C6H5)-
For an atactic polymer, the substituent groups are randomly distributed along the polymer backbone. The repeat unit for an atactic polymer might look something like this:
-CH(CH3)-CH(C6H5)-CH(CH2Br)-CH(CH3)-
For a random polymer, there is no consistent pattern to the distribution of substituent groups along the polymer backbone. The repeat unit for a random polymer might look something like this:
-CH(CH3)-CH(C6H5)-CH(CH2Br)-CH(CF3)-
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The transition from n = 2 to n = 5 (option 2) or from n = 5 to n = 2 (option 4) will cause the greatest amount of energy to be absorbed.

The energy absorbed by an electron transitioning between different principal energy levels in a hydrogen atom can be calculated using the formula:

\(ΔE = -13.6 eV * (1/n_final^2 - 1/n_initial^2)\)

where ΔE is the energy change, n_final is the final principal energy level, and n_initial is the initial principal energy level.

Let's calculate the energy changes for the given transitions:

n = 2 to n = 4:

\(ΔE = -13.6 eV * (1/4^2 - 1/2^2) = -13.6 eV * (1/16 - 1/4) = -13.6 eV * (1/16 - 4/16) = -13.6 eV * (-3/16) = 2.55 eV\)

n = 2 to n = 5:

\(ΔE = -13.6 eV * (1/5^2 - 1/2^2) = -13.6 eV * (1/25 - 1/4) = -13.6 eV * (4/100 - 25/100) = -13.6 eV * (-21/100) = 2.856 eV\)

n = 4 to n = 2:

\(ΔE = -13.6 eV * (1/2^2 - 1/4^2) = -13.6 eV * (1/4 - 1/16) = -13.6 eV * (4/16 - 1/16) = -13.6 eV * (3/16) = 2.55 eV\)

n = 5 to n = 2:

\(ΔE = -13.6 eV * (1/2^2 - 1/5^2) = -13.6 eV * (1/4 - 1/25) = -13.6 eV * (25/100 - 4/100) = -13.6 eV * (21/100) = 2.856 eV\)

Comparing the energy changes, we find that options 2 and 4 have the same energy change of 2.856 eV, which is greater than the energy changes for options 1 and 3 (2.55 eV).

Therefore, the transition from n = 2 to n = 5 (option 2) or from n = 5 to n = 2 (option 4) will cause the greatest amount of energy to be absorbed.

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Answer:

It loses kinetic energy.

Explanation:

The definition of heat is molecules moving fast, so it cooling would mean they slow down.

Answer:

B, It loses kinetic energy.

Explanation:

Answer:

1. Phosphorylation by a kinase - decrease

2. Dephosphorylation by a phosphatase - increase

3. Binding of allosteric activator - increase

4. Binding of allosteric inhibitor - decrease

5. Transcriptional upregulation - increase

6. Transcriptional downregulation - decrease

Example 1: The presence of glucose-6-phosphate. This example is associated with an increase in glycogen synthase activity.

Glycogen synthase requires glucose-6-phosphate (G6P) as a substrate in order to catalyze the synthesis of glycogen.

Therefore, the presence of G6P will increase the activity of glycogen synthase, leading to an increase in glycogen synthesis.

Furthermore, G6P is the product of the enzyme glucokinase, which catalyzes the phosphorylation of glucose, so the presence of G6P indicates that glucose is present, and therefore glycogen synthesis can occur.

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Answer:

The new pressure of a gas initially at 575 mmhg and 12500ml and the volume changed to 15L is 479. 16 mmHg

Explanation:

Boyle's law states that the pressure of a given quantity of gas varies inversely with its volumes at constant temperature. It is represented as;

P V = K

P1 V1 = P2 V2

Where;

P1 = Initial pressure = 575 mmHg

P2 = Final pressure?

V1 = Initial volume = 12500ml = 12500÷ 1000 = 12.5 Liters

V2 = Final pressure = 15 Liters

Calculations :

P2 = P1 V1 ÷ V2

P2 = 575 × 12.5 ÷ 15

P2 = 7187 . 5 ÷ 15

P2 = 479. 16 mmHg

Therefore, the new pressure is 479. 16 mmHg

The solution with 100.0 g of methanol in 500.0 g of water will have a smaller freezing-point depression than the solution with 200.0 g of methanol in 500.0 g of water.

Methanol, also known as methyl alcohol, is an organic chemical compound with the molecular formula CH3OH. It is a light, volatile, colorless, flammable liquid with a distinctive odor that is very similar to ethanol, but with a slightly sweeter smell. Methanol is a primary alcohol and it is toxic to humans and other living organisms.

Methanol is also an important industrial feedstock as it is used to create synthesis gas, a mixture of carbon monoxide and hydrogen, which can be used to produce a variety of products such as ammonia, methanol, and ethanol. Methanol is classified as a hazardous chemical and should be handled with caution.

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Answers:

BaF² + H²SO⁴ -------> BaSO⁴ + 2HF

One of the hallmark treatments for shock is fluid replacement, and the nurse is aware of this. In order to treat acidosis, the crystalloid fluid that is commonly used is called lactated Ringer's solution.

Fluid replacement is a crucial aspect of managing shock, as it helps restore blood volume and improve tissue perfusion. The nurse recognizes the significance of fluid therapy in treating this condition. Acidosis, characterized by an imbalance in the body's pH levels, can be a complication of shock.

To address acidosis and restore the body's acid-base balance, a crystalloid fluid known as lactated Ringer's solution is commonly employed. Lactated Ringer's solution contains sodium, potassium, calcium, and lactate, which helps in correcting acidosis by providing bicarbonate precursors.

This fluid not only replenishes the intravascular volume but also aids in the restoration of pH levels, making it an appropriate choice for treating acidosis associated with shock.

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Answer:

D) Matter

Explanation:

Answer:

.

Explanation: