Answers
Answer:
Wind
Explanation:
I think that the correct answer is wind.
I hope this helps you!!!
:D
Related Questions
Part A
Shown is a 10 by 10 grid, with coordinate axes x and y
(Figure 1).
The grid runs from -5 to 5 on both axes. Drawn on this
grid are four vectors, labeled A through D. This problem
will ask you various questions about these vectors. All
answers should be in decimal notation, unless otherwise
specified.
What is the x component of A?
Express your answer to the nearest integer.
Answers
Based on the grid shown, the x component of the vector A is 3.
What is the x component of the vector A?The given grid is a 10 by 10 grid, this means that every box in the grid has a length of 1 unit on all sides.
Thus, the x and y components of the vectors can be determined.
The x and y components of vector A is 3 and 3 respectively.
Therefore, based on the grid shown, the x component of the vector A is 3.
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A stone is dropped from the top of a cliff which is 10-m high. What is its velocity when it hits the ground? Sketch the stones position vs time and velocity vs time graphs.
Answers
S = displacement
V = final velocity
U = initial velocity
Which type of wave can travel in a vacuum?
Answers
Answer:
Electromagnetic waves
if a bus drives 2km due east,5km 45 degrees north of east, 4km at 30 degrees north of west, then 2km due south. what is the bus's resultant displacement?
Answers
The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.
The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.
The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km
The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km
The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.
Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km
The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km
The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east
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An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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In a biathalon race you first ride a bicycle at an average speed of 19.1 mi/h for 18.5 miles, then you must run for another 5.5 miles. With what average speed, in miles per hour, must you run if your average speed for the entire race is to be 14.5 mi/h?
Answers
The average speed you must run is 7.97 mph.
What is average speed?
The average speed of an object is the ratio of total distance traveled by the object to
Average speed = total distance / total time of motion
Total time of motion = total distance / average speed
total time = (18.5 + 5.5) / (14.5)
total time = 1.66 hours
time taken during the bicycle ridet1 = 18.5 / 19.1
t1 = 0.97 hour
time taken during the runt2 = 1.66 hr - 0.97 hr
t2 = 0.69 hr
Average speed during the runv = 5.5 miles /0.69 hr
v = 7.97 mph
Thus, the average speed you must run is 7.97 mph.
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what is meant by reticlinear propatigation of light?
Answers
Answer:
The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.
Answer:
the property of light travelling in a straight lines in a homogenous transparent medium
Explanation:
3. An ecosystem is different from all of
the other groups because it contains
things.
O only living
O only nonliving
O both living and nonliving
Answers
Answer:
I think it is O only nonliving
2. When an object of mass m slides on a frictionless surface inclined at an angle as shown in the Figure below, the forces acting on it decides the a. acceleration of the object9jo b. speed of the object when it reaches the bottom h L 1 co a
Answers
The acceleration of the object in the inclined plane is g sinθ.
The velocity of the object on the inclined plane is √(2gL sinθ).
Given that the inclined surface is a frictionless surface. So, the force of friction is zero. Hence the components of the weight of the object provides the necessary forces to slide the object over the inclined plane.
a) Newton's second law is applied to masses on inclination.
Acceleration due to multiplied by the sine of the angle of inclination provides the acceleration for a frictionless slope of angle in degrees.
The acceleration of the object in the inclined plane is,
a = g sinθ
b) Applying the third equation of motion,
v²- u² = 2as
v² = 2as
v² = 2 x g sinθ x L
Therefore, the velocity of the object on the inclined plane is given by,
v = √(2gL sinθ)
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Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?
Answers
Given: graph of L vs t
Ly = 20 at t = 5
Lx = 10 at t = 5
All L = 0 at t = 0
So change in angular momentum of y is 20 and x is 10
Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time
solve for average torque for each objects
τ(average) = ΔL / Δt
Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4
Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2
Relates τy and τx
2τx = τy
Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.
The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.
To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:
L = I * ω
Differentiating this equation with an appreciation of time, we get:
dL/dt = d(I * ω)/dt
Using the product rule of differentiation, we've got:
dL/dt = I * dω/dt + ω * dI/dt
Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:
τ = dL/dt
Substituting the expression for dL/dt in terms of angular velocity and second of inertia:
τ = I * dω/dt + ω * dI/dt
Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:
torquex = I0 * dω/dt + ω * dI0/dt
Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:
torquey = (2I0) * dω/dt + ω * d(2I0)/dt
torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)
torquey = 2I0 * dω/dt + 2ω * dI0/dt
Comparing the expressions for torquex and torquey, we will see that:
torquey = 2 * torquex
Therefore, the precise relation between torquey and torquex is;
torquey = 2 * torquex.
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The correct question is;
"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"
Why are weathering, erosion and deposition a NECESSARY process in the rock cycle?
ANSWER THIS NOW PLEASE! AND YOU GET 225 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
YESS well it is partly nessary but it depends on the situation
Explanation:
Answer:
Weathering, erosion, and deposistion are necessary processes in the rock cycle because:
Explanation:
First, start with igneous rocks. magma erupts (Extrusive igneous rocks) or solidifies in the sub-surface of the earth (Intrusive igneous rock). when they are exposed Weathering and erosion occur which is a slow breakdown of rock through the wind, water, or other processes. The weathered pieces (sediments) move to other places by wind or water and get deposited someplace else. When there are enough sediments and there is overburden pressure on these sediments, they become a sedimentary rock. Due to overburden pressure, they become metamorphic rocks. now the thing to understand here is that when metamorphic rocks are exposed, they too undergo weathering and erosion and their pieces also become sedimentary rocks.
select a synonym for the word necessity a advertisement b extra c requirement d superior
Answers
Answer
explanation
requirments
If something is a necessity, it is crucially important, as is a requirement. The following sentence will use the words interchangeably:
It is a necessity that you write your name on top of your paper; if you don’t, I cannot grade it.
It is a requirement that you write your name on top of your paper; if you don’t, I cannot grade it.
Hope this is accurate & helpful!
What strength of magnetic field is used in a cyclotron in which protons make 2.8×10^7 revolutions per second?
Answers
The magnetic field in the cyclotron, is 0.292 T.
Angular velocity, ω = 2.8 x 10⁷rev/s
Charge of a proton, q = 1.6 x 10⁻¹⁹C
Mass of a proton, m = 1.67 x 10⁻²⁷kg
A cyclotron is a device that strongly accelerates the charge on charged particles or ions. The cyclotron amplifies the energy of the charged particles through the application of both magnetic and electric fields.
The expression for the angular velocity of the cyclotron is given by,
ω = qB/m
Therefore, the magnetic field in the cyclotron,
B = ωm/q
B = 2.8 x 10⁷x 1.67 x 10⁻²⁷/1.6 x 10⁻¹⁹
B = 0.292 T
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D 4.8
This is a harder question based on the Law of Conservation of Momentum. Take the time to work
your way through it. Start with a diagram.
A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150 kg piece moves off to the
east with a velocity of 150 m s². A 100 kg piece moves off with a velocity of 200 m s at a direction of
south 60° west. What is the velocity of the third piece?
It is possible
Answers
The velocity of the third piece is v₃ = -12500 kg·m/s / m₃
How do we calculate?The law of conservation of momentum states that the total momentum before the explosion is equal to the total momentum after the explosion.
velocity of the third piece = v₃.
The total initial momentum before the explosion = 0
The total final momentum after the explosion= 0
Initial momentum = 0 kg·m/s (since the bomb is at rest)
Final momentum = m₁v₁ + m₂v₂ + m₃v₃
m₁ = mass of the first piece = 150 kg
v₁ = velocity of the first piece = 150 m/s (to the east)
m₂ = mass of the second piece = 100 kg
v₂ = velocity of the second piece = 200 m/s (south 60° west)
m₃ = mass of the third piece = unknown
v₃ = velocity of the third piece = unknown
0 = (150 kg)(150 m/s) + (100 kg)(200 m/s)(cos(60°)) + (m₃)(v₃)
final momentum = 0 and hence v₃ is found as :
0 = 22500 kg·m/s - 10000 kg·m/s + (m₃)(v₃)
-12500 kg·m/s = (m₃)(v₃)
v₃ = -12500 kg·m/s / m₃
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If velocity of the car is given as v(t)= 10+3t+512. Determine the acceleration at t=2s.
Answers
Given data
*The given velocity of the car is v(t)= 10 + 3t + 512
The acceleration of the car is calculated as
\(\begin{gathered} a(t)=\frac{d}{dt}(v(t)) \\ =\frac{d}{dt}(10+3t+512) \\ =3m/s^2 \end{gathered}\)Thus, the acceleration of the car at t = 2 s is 3 m/s^2
This problem explores the behavior of charge on conductors. We take as an example a long conducting rod suspended by insulating strings. Assume that the rod is initially electrically neutral. For convenience we will refer to the left end of the rod as end A, and the right end of the rod as end B. In the answer options for this problem, "strongly attracted/repelled" means "attracted/repelled with a force of magnitude similar to that which would exist between two charged balls.A small metal ball is given a negative charge, then brought near (i.e., within about 1/10 the length of the rod) to end A of the rod. What happens to end A of the rod when the ball approaches it closely this first time?
Answers
Answer:
rod end A is strongly attracted towards the balls
rod end B is weakly repelled by the ball as it is at a greater distance
Explanation:
When the ball with a negative charge approaches the A end of the neutral bar, the charge of the same sign will repel and as they move they move to the left end, leaving the rod with a positive charge at the A end and a negative charge of equal value at end B.
Therefore rod end A is strongly attracted towards the balls and
rod end B is weakly repelled by the ball as it is at a greater distance
High speed stroboscopic photographs show that the head of a 183 g golf club is traveling at 58.6 m/s just before it strikes a 46.6 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 40.0 m/s. Find the speed of the golf ball just after impact.
Answers
Answer:
The speed of the golf ball just after the impact is 73.04 m/s.
Explanation:
Given that,
The mass of golf club, m₁ = 183 g = 0.183 kg
The mass of golf ball, m₂ = 46.6 g = 0.0466 kg
The initial speed of golf club, u₁ = 58.6 m/s
The initial speed of a golf ball, u₂ = 0
The final speeds of club, v₁ = 40 m/s
We need to find the speed of the golf ball just after impact. Using the conservation of momentum to find it.
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1u_1=m_1v_1+m_2v_2\\\\v_2=\dfrac{m_1u_1-m_1v_1}{m_2}\\\\v_2=\dfrac{0.183 (58.6)-0.183(40)}{0.0466 }\\\\=73.04\ m/s\)
So, the speed of the golf ball just after the impact is 73.04 m/s.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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how would you write regarding the "explain" portion of the assignment.
Answers
In the "explain" portion of the assignment, you are required to provide a detailed and coherent explanation of a particular topic, concept, or process.
This section aims to demonstrate your understanding and knowledge of the subject matter. Here's how you can approach writing the explanation:
1. Introduction: Begin by introducing the topic or concept you are explaining. Provide some background information to set the context and establish its relevance.
2. Main Body: Break down the topic into smaller, logical sections or steps. Present each section in a clear and organized manner. Use paragraphs or bullet points to enhance readability. Use examples, analogies, or visual aids if necessary to clarify complex ideas.
3. Use Clear Language: Ensure that your explanation is written in clear, concise language. Avoid jargon or technical terms unless they are necessary and properly explained. Use simple language that your intended audience can easily understand.
4. Provide Supporting Details: Include relevant facts, evidence, or research to support your explanation. This can help strengthen your arguments and make your explanation more credible.
5. Summary and Conclusion: Summarize the key points of your explanation and reiterate the main concept or process. If appropriate, highlight any implications or applications of the topic.
6. Proofread and Revise: After writing the explanation, proofread it for clarity, grammar, and coherence. Make any necessary revisions to ensure that your explanation is well-written and effectively conveys the intended information.
Remember to adapt your writing style and level of complexity based on the target audience and the level of prior knowledge they may have on the topic.
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If a car travelled for 20 m/s and then 10 seconds later it was moving 10 m/s, its acceleration would be?
Answers
Answer:
This is the answer. hope this help u
How is thermal energy being transferred when steam rises from a beaker of boiling water?
O A. Conduction
• B. Radiation
O c. Translation O D. Convection
Answers
Answer:
d. convention
Explanation:
hope this helped
Before you go.. Is there something I could've said to make your heart beat better?
Answers
Answer:
no ... hahahha! but I know every boys wait for the day when their heart beat is faster than normal ever in life
if the air was solid and we were liquid how would this work
Answers
Answer:
Chaos.
Explanation:
If you pull with a constant force of 400n , how much mechanical work does it take to pull pinball launcher back 0.2meters
Answers
If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Force, f = 400 N
Displacement, d = 0.2 meters
\(Work done(W)=Force(f)*Displacement(d)\)
W = 400 × 0.2
W = 80 J.
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A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
Answers
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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At an airport, two business partners both walk at 1.5 m/sm/s from the gate to the main terminal, one on a moving sidewalk and the other on the floor next to it. The partner on the moving sidewalk gets to the end in 60 ss, and the partner on the floor reaches the end of the sidewalk in 90s.
Required:
What is the speed of the sidewalk in the Earth reference frame?
Answers
Answer:
\(v=0.8m/s\)
Explanation:
From the question we are told that
Distance \(d=1.5m/sm/s\)
Time \(t_1=60s\)
Time \(t_2=90s\)
Generally the the equation for the distance traveled is mathematically given as
\(d=vt\)
\(d=1.5*90\)
\(d=138m\)
Generally equation for speed of side walk is mathematically given as
\(d=(v+u)t\)
\(v=\frac{d}{t}-u\)
\(v=\frac{138}{60}-1.5\)
\(v=0.8m/s\)
If the average electrical power usage of an American home is 2 kW, then for how
many homes could electricity needs be met by one 2 MW wind turbine?
Answers
1,000 homes when it's spinning.
No homes when it's not spinning.
The number of homes that the wind turbine can carry is 1000 homes
Power is the ratio of work done by an object with respect to time. The unit of power is in Watts (W).
Given the average electrical power usage of an American home to be 2 kW
Since 1kW = 100W
Average power per American home = 2000W = 2 * 10³Watts
Average power of a turbine = 2MW = 2 * 10⁶Watts
Number of homes that the wind turbine can carry = \(\dfrac{2 \times 10^6}{2 \times 10^3}\)
Number of homes that the wind turbine can carry = \(\dfrac{10^6}{10^3}\)
This shows that the number of homes that the wind turbine can carry is 1000 homes
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Ultimate frisbee relies upon good sportsmanship since there are no referees and players must self-officiate the game. What is this known as?
Group of answer choices
Spirit of the Team
Spirit of the Frisbee
Spirit of Sportsmanship
Spirit of the Game
Answers
Answer:
spirit of the team / game
A car has a mass of 1070 kg and is moving in a straight line at a speed of 91.3 km/h what is the magnitude of the constant net force in N require to bring the car to rest over a distance of 128m?
Answers
We are asked to determine the force required to stop a car that is moving at a velocity of 91.3 km/h.
First, we will convert the 91.3 km/h into m/s. To do that we will use the following conversion factors:
\(\begin{gathered} 1km=1000m \\ 1h=3600s \end{gathered}\)Multiplying the conversion factors we get:
\(91.3\frac{km}{h}\times\frac{1000m}{1km}\times\frac{1h}{3600s}=25.36\frac{m}{s}\)Now. We use a balance of energy. The work done by the force to stop the car must be equal to the change in kinetic energy of the car, therefore, we have:
\(W=\frac{1}{2}mv_f^2-\frac{1}{2}mv_0^2\)Since the car will stop this means that the final velocity is 0:
\(W=-\frac{1}{2}mv_0^2\)The work done is equal to the product of the force and the distance:
\(Fd=-\frac{1}{2}mv_0^2\)Now, we divide both sides by the distance "d":
\(F=-\frac{mv_0^2}{2d}\)Substituting the values:
\(F=-\frac{(1070kg)(25.36\frac{m}{s})}{2(128m)}\)Solving the operations:
\(F=-106N\)Therefore, the magnitude of the force required is 106 Newtons.
A small car moving at 20 m/sec collides head on with an oncoming large truck moving at 25 m/sec. Which vehicle undergoes the largest change in its momentum
Answers
Answer:
The truck will undergo the largest change in momentum if it has a greater mass than the small car.
Explanation:
The change in momentum of an object can be calculated using the equation:
Δp = m * Δv
where Δp represents the change in momentum, m represents the mass of the object, and Δv represents the change in velocity.
Since we are comparing the change in momentum of the car and the truck, we need to consider the masses of both vehicles.
Let's assume the mass of the car is represented by m_car, and the mass of the truck is represented by m_truck.
Since both vehicles collide head-on, the change in velocity (Δv) will be the difference between their initial velocities, considering that they are moving in opposite directions:
Δv = v_truck - v_car
Now, let's compare the change in momentum for the car and the truck:
For the car:
Δp_car = m_car * Δv
For the truck:
Δp_truck = m_truck * Δv
Comparing the magnitudes of the change in momentum, we can neglect the negative sign:
|Δp_car| = |m_car * Δv|
|Δp_truck| = |m_truck * Δv|
Since both Δv and Δp are positive values, we can conclude that the vehicle with the greater mass will undergo the largest change in its momentum.
Therefore, if the mass of the truck (m_truck) is greater than the mass of the car (m_car), then the truck will undergo the largest change in its momentum. Conversely, if the mass of the car is greater, then the car will undergo the largest change in its momentum.