why can a star with a mass like our sun not fuse (produce) further elements beyond carbon and oxygen? g

Answers

Answer 1

A star with a mass like our Sun cannot fuse elements beyond carbon and oxygen because it does not have sufficient temperature and pressure in its core to overcome the strong electrostatic repulsion between the atomic nuclei of heavier elements.

Stars generate energy through nuclear fusion, where lighter elements combine to form heavier elements in their cores. In the case of a star like our Sun, it primarily fuses hydrogen into helium. As the hydrogen in the core depletes, the core contracts and heats up, allowing for helium fusion to occur. This process creates elements like carbon and oxygen.
However, fusing elements beyond carbon and oxygen requires much higher temperatures and pressures. This is due to the strong electrostatic repulsion between the positively charged atomic nuclei of these heavier elements, also known as the Coulomb barrier. To overcome this barrier, the core needs to have enough energy for the nuclei to come close enough together for the strong nuclear force to bind them.
In summary, a star with a mass like our Sun cannot produce elements beyond carbon and oxygen because its core does not reach the necessary temperature and pressure required to overcome the electrostatic repulsion between the nuclei of heavier elements.

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Related Questions

the supernova that created the crab nebula and its pulsar was seen on earth in the year_____

Answers

The supernova that created the Crab Nebula and its pulsar was seen on Earth in the year 1054.

The supernova that created the Crab Nebula and its pulsar was seen on Earth in the year 1054 AD. This event was recorded by Chinese and Japanese astronomers as a new star in the sky that shone brightly for a few weeks before fading away. Today, the Crab Nebula is one of the most studied objects in the sky, as it provides a unique laboratory for studying the aftermath of a supernova explosion.

The pulsar at the center of the nebula is a rapidly spinning neutron star that emits beams of radio waves and gamma rays, making it one of the most energetic objects in the universe.

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A wire of radius 6mm and length 400 is melted into a sphere, calculate the radius of the sphere in centimeters​

Answers

The radius of the sphere in centimeters​ is  50 cm

The wire has a certain volume that can be calculated as follows:

V_wire = πr²l

where r is the radius of the wire and l is its length.

If the wire is melted and formed into a sphere, it will still have the same volume as before, which can now be expressed as:

V_sphere = (4/3)πr³

where r is the radius of the sphere.

Since the wire and the sphere have the same volume, we can equate the two expressions for volume:

πr²l = (4/3)πr³

Simplifying this equation by dividing both sides by πr² and then multiplying both sides by 3/4, we get:

r = (3/4)l/r

Substituting the given values, we get:

r = (3/4)(0.4 m)/(0.006 m) ≈ 50 cm

Therefore, the radius of the sphere is approximately 50 centimeters.

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a(n) is an example of simple harmonic motion. responses ticking wrist-watch ticking wrist-watch oscillating mass on a spring oscillating mass on a spring beating heart beating heart all of the above

Answers

Ticking wrist-watch, oscillating mass on a spring ,beating heart exhibit simple harmonic motion. The correct answer is all of the above.

All of the options provided exhibit simple harmonic motion: ticking wrist-watch, oscillating mass on a spring, and beating heart. They all involve repetitive, oscillatory motion and are driven by a restoring force.

Simple harmonic motion (SHM) refers to the repetitive back-and-forth motion exhibited by certain systems when they are disturbed from their equilibrium position and experience a restoring force proportional to their displacement. In the given options, all of them exhibit simple harmonic motion.

The ticking of a wrist-watch involves the oscillation of a balance wheel or quartz crystal, which acts as a pendulum and moves back and forth in a regular pattern.

An oscillating mass on a spring also undergoes simple harmonic motion. When the mass is displaced from its equilibrium position and released, it oscillates back and forth around the equilibrium position due to the restoring force provided by the spring.

The beating of a heart can be considered as a form of simple harmonic motion. The heart contracts and relaxes rhythmically, resulting in a periodic back-and-forth motion.

In summary, all the given examples involve repetitive, oscillatory motion and are driven by a restoring force. Therefore, they can be classified as examples of simple harmonic motion.

The correct answer is:  All of the above.

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alice is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. suppose you claim that you are feeling the effects of a gravitational field. how can you explain the fact that alice is weightless? alice is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. suppose you claim that you are feeling the effects of a gravitational field. how can you explain the fact that alice is weightless? she is weightless because she is in a not moving. she is weightless because she is in free-fall. she is weightless because she is moving at constant velocity. if you are in a gravitational field, then she cannot be weightless.

Answers

Alice is weightless because she is in free fall.

Free-fall occurs when an object is experiencing the force of gravity but is not experiencing any other forces, such as air resistance. Because Alice is in a spacecraft, air resistance is not a factor, so she is essentially in a vacuum.

When an object is in a vacuum, the only force acting upon it is gravity. Therefore, Alice is in free fall and is experiencing weightlessness. This is in contrast to you, who is experiencing 1g of acceleration due to the force of the engine of your spacecraft.

This force is greater than the force of gravity, so you are not in free fall, and thus you are feeling the effects of the gravitational field.


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Based on the stated expectations of the sit-and-reach test, which of the following is TRUE?
A.
Men are generally more flexible than women.
B.
Women are generally more flexible than men.
C.
Men and women are about equally flexible.
D.
No broad conclusions can be drawn about flexibility

Answers

Answer:

B. Women are generally more flexible than men.

Explanation:

It's proven by research.

Is light is faster than everything how does the dark get there

Answers

Answer:

In the context of talking about speeds, darkness is what you get after the light stops coming, and therefore travels at the speed of light. For instance, consider that you are in distant space, far from all light sources such as the sun, and you have a light bulb on the nose of your space ship.

Answer:

Dark and Light is always there

Explanation:

Think of it like an Angel and a Demon so basically there are colors all around us, and one of those colors is black so even if you were in the day if you block al sunlight out it would be dark then again there is artificial light so even if all light is blocked out light will always be there and Dark will also always be there hope this helped BTW I’m a fifth grader who goes to seventh grade sooo this should be correct(if you don’t understand I’m basically saying that the speed of Dark and Light is equal.

what is the half-life of lithium-8 if the decay constant is 0.825/s? what is the half-life of lithium-8 if the decay constant is 0.825/s? A. 0.572s B. 2.42s
C. 1.19s
D. 0.840s

Answers

0.840s is the half-life of lithium-8 if the decay constant is 0.825/s. The decay constant is unique to each radioactive substance and measures the speed of radioactive decay. Therefore, the correct answer is option D.

The half-life of lithium-8 can be calculated using the formula:

\(t1/2 = ln(2) / \lambda\)

Where t1/2 is the half-life, ln is the natural logarithm, and λ is the decay constant. Substituting the given decay constant of 0.825/s into the formula:

t1/2 = ln(2) / 0.825/s

t1/2 ≈ 0.840s

Therefore, the half-life of lithium-8 is approximately 0.840s. The formula for half-life is a fundamental concept in nuclear physics, which determines the time required for a radioactive substance to decay by half of its original quantity. The decay constant, which is specific to each radioactive substance, measures the rate at which radioactive decay occurs.

The higher the decay constant, the shorter the half-life, indicating that the substance is more unstable and decays faster. In this case, the decay constant of lithium-8 is 0.825/s, indicating that it is relatively unstable and has a short half-life of approximately 0.840s.

In summary, the half-life of lithium-8 is approximately 0.840s with a decay constant of 0.825/s. Therefore, the correct answer is option D.

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GIVING BRAINLIEST FIVE STARS AND THANKS TO BEST ANSWER!! tHANK you Have A GReat day!

How do spores grow into an adult plant?

The cells in the spores start to differentiate into different cells once it is planted in the ground.

The cells in the spores grow into different cells through photosynthesis.

Cells in the spores start to grow through the process of cellular reproduction.

Cells in the spores go through the process of mitosis.

Answers

Answer:

The cells in the spores start differentiate into different cells once it is on the ground

Two pieces of clay collide and stick together moving in one dimension. Clay 1 has a mass of 2,100 grams, and a clay 2 has a mass of 2,500 grams. Clay 1 has an initial velocity of 20 m/s immediately before they have a perfectly inelastic collision.

What is the final velocity of the two pieces of clay immediately after the collision?
a. 3.7 m/s
b. -3.7 m/s
c. 15 m/s
d.-15 m/s

Answers

The common velocity of clay 1 and clay 2 is 15 m/s. Option C

What is an inelastic collision?

We know that a collision can be said to be inelastic when the momentum and the kinetic energy are not conserved. This implies that rather than having the objects move out in different directions, the objects would rather stick together and just move in the same direction.

In this case we would also need the law of the conservation of linear momentum. Recall that according to this law, the momentum before collision  would just be the same as the momentum after Collison.

Thus;

Momentum before collision = momentum after Collison

(2100 * 20) + (2500 * 0) = (2100 + 2500)v

Where v is the common velocity

v = 42000/4600

v =  15 m/s

Thus they would have the common velocity of 15 m/s

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discuss how a restoring force and an equilibrium position are related

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A restoring force and an equilibrium position are closely related. The restoring force is responsible for bringing an object back to its equilibrium position when it is displaced.

When an object is in its equilibrium position, it experiences a net force of zero. This means that the forces acting on the object are balanced, resulting in a stable position. However, if the object is displaced from its equilibrium position, a restoring force comes into play. The restoring force is a force that acts in the opposite direction of the displacement, aiming to restore the object back to its equilibrium position.

Mathematically, the restoring force is proportional to the displacement from the equilibrium position. It follows Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. This relationship is given by the equation F = -kx, where F is the restoring force, k is the spring constant (a measure of the stiffness of the system), and x is the displacement from the equilibrium position.

In summary, a restoring force and an equilibrium position are related in that the restoring force acts to bring an object back to its equilibrium position when it is displaced. This force is proportional to the displacement and follows Hooke's Law for systems like springs.

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If you jog for 1 h and travel 10 km, 10km/h describes what?

Answers

Answer:

10km/h describe its velocity

Explanation:

Velocity =distance /time

It defined as the rate of change of the object's position with respect to a frame of reference and time.

If you travel a distance of 10 Km in 1 hour then 10 km/h is your velocity.

What is the velocity?

Velocity can be explained as a vector measurement of the direction and rate of motion of an object. The velocity of an object can be specified as the rate of change in the object’s position w.r.t. time.

Velocity can be defined as a vector parameter as it consists of both magnitude and direction. The velocity can be determined from the formula mentioned below:

v = d / t

where v is the velocity, d represents the distance covered, and t is the time.

Although the S.I. unit for the measurement of velocity is m/s or, miles per hour (mph), and kilometers per hour (kph).

Given, the distance traveled, d = 10  km

The time is taken, t = 1 hr

The velocity, v = d/t = 10 km/1 h = 10 km/h

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Someone please help

Someone please help

Answers

Based on the attached image:

The name of the longitude line that passes through point A is the International Date LineThe longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° ELongitude 120° is BSolar time at Point B is 4 pmThe location will correspond to any point on the same latitude as A

What are lines of longitude?

Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.

Longitude lines divide the earth into semi-circles.

Longitude lines are known as meridians and each meridian measures one arc degree of longitude.

Considering the attached image:

The name of the longitude line that passes through point A is the International Date LineThe longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° ELongitude 120° is BSolar time at Point B is 4 pmthe location will correspond to any point on the same latitude as A

In conclusion, longitude lines are imaginary lines and run from North to South on the earth.

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according to special relativity, one can travel at increased rates

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According to special relativity, one can travel at increased rates. However, this is only possible when moving at very high speeds approaching the speed of light. When an object moves at high speeds, the time slows down, and the length of the object appears to be shortened.

These observations are known as time dilation and length contraction. Time dilation refers to the difference in the elapsed time measured by two observers, where one is stationary, and the other is moving at a constant velocity relative to each other. The faster the moving observer, the slower time appears to be for them. Length contraction, on the other hand, refers to the phenomenon where an object appears to be shorter in length when it's moving at high

This effect is more noticeable as the speed of the object approaches the speed of light. As a result, traveling at very high speeds can allow one to cover great distances in less time, which can be used for space exploration and other scientific research. However, it's worth noting that the effects of relativity are only noticeable at very high speeds, which are currently impossible to achieve with our current technology.

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The BBB is a law-enforcement agency, so it can force a business to resolve a complaint of a customer. True or False.

Answers

Answer:

ITS FALSE

Explanation:

I just did the quest and I wrote true and I was wronged so put False.

Which statement explains the first law of thermodynamics?.

Answers

Energy is transformed and transferred in a thermodynamic system. Option B is correct

First law of thermodynamics:

It states the energy neither be created nor destroyed. It change its form from one to another. It is also known as law of conservation of energy.

It is given by the formula,

\(\Delta U = Q - W\)

Where,

\(\Delta U\) - change in internal energy

\(Q\) -    heat added

\(W\)-    work done by the system

Since, heat is a form of energy, hence it is follow the principle of conservation of energy.

Therefore, energy is transformed and transferred in a thermodynamic system. Option B is correct

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Answer:

2: A,D,E or 1,4,5

3: B

4: B

5: 12 joules

6: 53 joules

7: B,C,E or 2,3,5

8: 2,4,3,1

9: Electrical energy in the stove is transformed into heat. The heat flows to the water in the kettle, increasing the internal energy of the water. As the energy in the water increases, the water molecules move faster until the liquid water becomes water vapor. The water vapor does work on the whistle, causing it to make a sound. Energy is neither created nor destroyed, it has simply changed form in the process.

Explanation:

youre welcome

PLS HELPPP I NEED IT

FITT principle:

Frequency-is how regular or often a person does the plan of a target health-related physical activity. It depends on how determined you want to accomplish your target. The more often you train, the faster the result.


Intensity - is how hard a person exercise during a physical activity period. It can be measured in different ways, depending on the health-related component. For example, monitoring heart rate is one way to measure the intensity during aerobic endurance activities, but does not indicate intensity during flexibility activities. The harder you work, the faster your heart beats.


Time - is the duration of the physical activity. Together with the other aspects of the FITT principle, time varies depending on the target health-related fitness component. For example, in developing flexibility, stretching may take 10-30 seconds for each activity, while the minimum time for performing an aerobic exercise is 20 minutes of continuous action.


Type - refers to the physical activity chosen to improve a specific component of health-related fitness. Different events require different training programs. For example, if a person wants to increase core muscles, he or she must do exercises that target the oblique muscles, while another person wishing to improve his or her cardiovascular endurance needs to jog, run, swim or perform some other aerobic activities.

PLS HELPPP I NEED IT FITT principle:Frequency-is how regular or often a person does the plan of a target

Answers

The FIIT plan required for different type of workout is shown in the image attached.

FIIT plan is used to monitor one's workout routine. It also helps to create workout routines that helps one's fitness goal which might differ from each person. It works based on four elements i.e., Frequency, Intensity, Time and Type.

Frequency refers to how often a workout needs to be done. Intensity refers to how hard a workout must be done. Time refers to the amount of time spent on the workout. Type refers to the king of exercise which suits one's final goal.

Therefore, the FIIT plan required for different type of workout is shown in the image attached.

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PLS HELPPP I NEED IT FITT principle:Frequency-is how regular or often a person does the plan of a target

Factors considered when investing in rsa retail saving bonds

Answers

when investing in RSA retail saving bonds, investors should consider interest rates, investment term, risk, and liquidity. It is recommended that investors conduct thorough research and seek professional advice before making any investment decisions.

Firstly, it is important to consider the current interest rates being offered on the bonds. This will help investors determine the potential returns they can expect to earn on their investment.

Another factor to consider is the length of the investment term. RSA retail saving bonds are available in a variety of terms, ranging from 2 to 5 years.

It is also important to consider the level of risk associated with investing in RSA retail saving bonds. While these bonds are considered low-risk investments, there is always a chance that the issuer may default on the bond, resulting in the loss of the investor's principal.

Lastly, investors should consider the liquidity of the investment. RSA retail saving bonds are not easily tradable and may not be suitable for investors who require quick access to their funds.

In summary, when investing in RSA retail saving bonds, investors should consider interest rates, investment term, risk, and liquidity. It is recommended that investors conduct thorough research and seek professional advice before making any investment decisions.

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A 3 kg purple ball moving at 2 m/s to the right collides with a 2 kg white ball at rest. After the collision the purple ball comes to rest (0 m/s). What is the velocity of the white ball after the collision?

Answers

Answer:

1.2m/s

Explanation:

Using the law of conservation of energy

m1u1+m2u2 = (m1+m2)v

v is the common velocity after collision

Substitute the given values

3(2) + 2(0) = (3+2)v

6 + 0 = 5v

v = 6/5

v = 1.2m/s

Hence the velocity of the white ball after the collision is 1.2m/s

If the potential energy of a spring when stretched through a distance ‘a’ is 25 J, thenwhat
is the amount of work done on the same spring so as to stretch it by an additionaldistance
‘5a’?

Answers

The potential energy stored in a spring stretched through a distance 'x' is given by:

U = (1/2)kx^2

where k is the spring constant.

In this problem, we are given that the potential energy of the spring when stretched through a distance 'a' is 25 J. Therefore, we can write:

25 = (1/2)ka^2

Solving for k, we get:

k = (2*25)/a^2 = 50/a^2

Now, we need to find the amount of work done on the spring to stretch it by an additional distance '5a'. The work done can be found using the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy plus the change in its potential energy.

In this case, there is no change in kinetic energy since the spring is not moving. Therefore, the work done is equal to the change in potential energy:

W = U_final - U_initial

where U_final is the potential energy of the spring when stretched through a distance '6a' (i.e., 'a' plus an additional '5a'), and U_initial is the potential energy of the spring when stretched through a distance 'a'.

The potential energy of the spring when stretched through a distance '6a' is:

U_final = (1/2)k(6a)^2 = (1/2)(50/a^2)(36a^2) = 900 J

Therefore, the amount of work done on the spring to stretch it by an additional distance '5a' is:

W = U_final - U_initial = 900 J - 25 J = 875 J

So, the amount of work done on the spring is 875 J.

Liquidtight flexible nonmetallic conduit is subject to which of the following limitations?
a. cannot be used in direct sunlight, unless marked for this application
b. can become brittle in extremely cold temperatures
c. both of these

Answers

Extra care should be taken while installing the Liquidtight flexible nonmetallic conduit in such weather conditions. Option(C) is correct.

It is a limit for Liquidtight flexible nonmetallic conduit that it cannot be used in direct sunlight unless marked for this application. Liquidtight flexible nonmetallic conduit can only be used outdoors if it is explicitly marked for outdoor use and is exposed to sunlight without causing damage.

Any exposure to direct sunlight may cause the conduit to degrade, which may result in safety concerns. It can become brittle in extremely cold temperatures: It is a limit of Liquidtight flexible nonmetallic conduit that it can become brittle in extremely cold temperatures. It is a limitation of Liquidtight flexible nonmetallic conduit that, in extremely cold weather, it may become brittle and lose its capacity to flex.

When the temperature drops below a certain level, the material begins to harden, making it vulnerable to cracking or shattering. Therefore, extra care should be taken while installing the Liquidtight flexible nonmetallic conduit in such weather conditions.

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Students are completing a lab in which they let a lab cart roll down a ramp. The students record the mass of the cart, the height of the ramp, and the velocity at the bottom of the ramp. The students then calculate the momentum of the cart at the bottom of the ramp.

A 4 column table with 3 rows. The first column is labeled Trial with entries 1, 2, 3, 4. The second column is labeled Mass of Cart in kilograms with entries 200, 220, 240, 260. The third column is labeled Height of ramp in meters with entries 2.0, 2.1, 1.5, 1.2. The fourth column is labeled Velocity at Bottom in meters per second with entries 6.5, 5.0, 6.4, 4.8.

Which trial’s cart has the greatest momentum at the bottom of the ramp?

Answers

Answer:

second column

Explanation:

Answer:

Trial 3 is the answer.

Explanation:

A dog pulls on a rope attached to a box and performs 250 J of work while dragging it across the floor a distance of 10 m. What amount of force is the dog pulling with?

Answers

Answer:

F = 25 N

Explanation:

The work done by any force is given as the product of the force and displacement produced by the application of that force. Therefore, the work done by the dog when it pulls the rope attached to the box can be given by the following formula:

\(W = Fd\\\)

where,

W = Work done by the dog while pulling the rope = 250 J

F = Force of pull applied by the dog = ?

d = displacement of the box across the floor = 10 m

Therefore,

\(250\ J = F(10\ m)\\\\F = \frac{250\ J}{10\ m}\)

F = 25 N

A +0.05 C charge is placed in a uniform electric field pointing downward with a strength of 100 Newtons over Coulombs.. Determine the magnitude and direction of the force on the charge.

Answers

The magnitude of the electric force on the charge is 5 N.

Magnitude of force on the charge

The magnitude of force on the charge is calculated as follows;

F = Eq

where;

E is electric fieldq is magnitude of the charge

F = 100 N/C  x 0.05 C

F = 5 N

Thus, the magnitude of the electric force on the charge is 5 N.

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Answer:

5n downward

Explanation:

took the assignment

a 2500 kg car accelerates from rest to a velocity of 10 m/s in 5.0 seconds. the average power of the engine during this acceleration is

Answers

Answer:

To find the average power of the engine during the acceleration, we can use the formula:

Power = Work / Time

The work done on the car is equal to the change in kinetic energy. The change in kinetic energy can be calculated using the formula:

ΔKE = (1/2) * m * (v_f^2 - v_i^2)

where:

m = mass of the car = 2500 kg

v_i = initial velocity = 0 m/s (since the car starts from rest)

v_f = final velocity = 10 m/s

ΔKE = (1/2) * 2500 kg * (10 m/s)^2

ΔKE = 125,000 J

Now, we can substitute the values into the power formula:

Power = ΔKE / Time = 125,000 J / 5.0 s

Power = 25,000 Watts

Therefore, the average power of the engine during the acceleration is 25,000 Watts.

How much energy would be required to accelerate a particle of mass m from rest to a speed of
a) 0.5c
b) 0.9c
c) 0.99c
Express your anwser in multiples of the rest energy

Answers

The energy required to accelerate a particle to speeds of 0.5c, 0.9c, and 0.99c can be calculated as 1.15E₀, 2.29E₀, and 7.08E₀, respectively, where E₀ represents the rest energy of the particle.

Einstein's mass-energy equivalence states that the total energy (E) of an object is equal to its mass (m) multiplied by the speed of light (c) squared, E = mc². To calculate the energy required to accelerate a particle to a specific speed, we need to consider the relativistic effects.

To express the energy in terms of the rest energy (E₀), we divide the total energy (E) by mc², resulting in E/E₀. Thus, for speeds of 0.5c, 0.9c, and 0.99c, we can calculate the energy required as follows:

a) For a speed of 0.5c:

  E/E₀ = (mc²)/(mc²) = 1E₀

  The energy required is equal to the rest energy.

b) For a speed of 0.9c:

  E/E₀ = γmc²/mc² = γ = 1/(1 - v²/c²)^(1/2)

  Here, v = 0.9c, so γ = 2.29

  The energy required is 2.29E₀.

c) For a speed of 0.99c:

  E/E₀ = γmc²/mc² = γ = 1/(1 - v²/c²)^(1/2)

  Here, v = 0.99c, so γ = 7.08

  The energy required is 7.08E₀.

Therefore, the energy required to accelerate a particle to speeds of 0.5c, 0.9c, and 0.99c is 1.15E₀, 2.29E₀, and 7.08E₀, respectively, where E₀ represents the rest energy of the particle.

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If man rolls a ball 67 mph how many gallons of oil did I drink last year and does it ad up to the marvel comic universe

If man rolls a ball 67 mph how many gallons of oil did I drink last year and does it ad up to the marvel

Answers

i think the answer is yellow

Answer:

The amount of oil is nullified by the dogs amazing the yes

Explanation:

very yes

there is an equilateral triangle with sides 2 meters in length. at one of the points is a 1 microcoulomb charge, at the second point there is a 2 microcoulomb charge, and at the third point there is a 3 microcoulomb charge. what is the magnitude of the force on the 2 microcoulomb charge?

Answers

The magnitude of the force on the 2 micro coulomb charge is 16.22mN.

Force on 2 micro coulombs by 1 micro coulomb is given as

F₁ = k · 1 × 2 × 10⁻¹²/r²

Or, F₁ = 9 × 10⁹ × 2 × 10⁻¹² /2²

Or, F₁ = 4.5 mN

Force on 2 micro coulombs by 3 micro coulomb is given as

F₂ = k · 3 × 2 × 10⁻¹²/r²

Or, F₂ = 9 × 10⁹ × 6 × 10⁻¹² /2²

Or, F₂ = 13.5 mN

As charges are placed on equilateral triangles, it means both forces will be 60 degrees separated from each other.

So, the resultant magnitude is given by

F = √F₁² + F₂² + 2F₁F₂cos60°

or F = 16.22 mN

Therefore, the magnitude of the force on the 2 micro coulomb charge is 16.22 mN.

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What is a wind turbine often used for?

Answers

Answer:

Wind Turbines are used in a variety of applications from harnessing offshore wind resources to generating electricity for a single home.

Explanation:

If you start with a sample containing 10^10 nuclei that have half-life 2.5 hours, what is the activity of the sample after 5 hours?

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The activity of the sample after 5 hours is 2.5 * 10^9 dps or 2.5 * 10^9 Bq

The activity of a radioactive sample refers to the rate at which its nuclei decay, and it is typically measured in units of disintegrations per second (dps) or becquerels (Bq).

To determine the activity of the sample after 5 hours, we need to consider the concept of half-life. The half-life of a radioactive substance is the time it takes for half of the nuclei in a sample to decay.

Given that the half-life of the nuclei in the sample is 2.5 hours, we can calculate the number of half-lives that occur within the 5-hour period.

Number of half-lives = (Time elapsed) / (Half-life)

Number of half-lives = 5 hours / 2.5 hours = 2

This means that within the 5-hour period, two half-lives have occurred.

Since each half-life reduces the number of nuclei by half, after one half-life, the number of nuclei remaining is (1/2) * (10^10) = 5 * 10^9 nuclei.

After two half-lives, the number of nuclei remaining is (1/2) * (5 * 10^9) = 2.5 * 10^9 nuclei.

The activity of the sample is directly proportional to the number of remaining nuclei.

Therefore, After 5 hours, the sample has an activity of 2.5 * 109 dps or 2.5 * 109 Bq.

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Answer is b

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