why did aristarchus believe in the radical notion that the sun was at the center of the universe and that earth moved around it in an orbit

Answers

Answer 1

Aristarchus believed that the sun was the center of the universe because he had found that the sun was larger than the earth and other planets and made the conclusion that other planets revolved around the sun.

Definition of Aristarchus Theory

Aristarchus' hypothesis was that the sun and stars did not move, that the earth revolved around the sun, while the sun remained stationary in the center of the earth's orbit.

In testing his hypothesis, Aristarchus constructed a kind of "sundial" which he probably used to measure the height of the sun and the position of the stars, as well as measure the angles and diameters of the moon as accurately as possible.

As a result, apart from the theory of the sun as the center of the solar system, Aristarchus also discovered that the earth is one of several planets revolving around the sun. Aristarchus used the theory of lunar eclipses to estimate the size of the solar system according to the radius of the earth

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Related Questions

If the wave is detected 12.5 minutes after the earthquake, estimate the distance from the detector to the site of the quake​

Answers

Answer:

Remember the relation:

Speed*Time = Distance.

We can estimate that the speed at which an earthquake "moves", in the surface, is:

S = 6km/s  (this is a low estimation actually)

Then if the wave is detected 12.5 minutes after the earthquake, we know that it traveled for 12.5 minutes before reaching the detector.

So we know the speed of the wave and the time it took to reach the detector, then we can use the equation:

Speed*Time = Distance.

to find the distance.

First, we should write the time in seconds

we know that:

1 min = 60 s

then:

12.5 min = 12.5*(60 s) = 750 s

Then, the wave traveled with a speed of 6 km/s for 750 seconds until it reached the detector, then the distance that it traveled is:

(6km/s)*750s = 4500 km

The distance between the detector and the site of the quake is around 4500 km.

An electric dipole consisting of charges of magnitude 1.50nC separated by 6.20 μm is in an electric field of strength 300 N/C. what are the magnitude of the electric dipole moment?

Answers

The magnitude of the electric dipole moment is 9.30 × 10⁻¹⁰ Cm.

What do you mean by dipole?

A dipole is an electrically charged object with a positive charge at one end and a negative charge at the other end. The term "dipole" refers to the separation of electric charge, with the positive and negative charges being located at opposite ends of the object. Dipoles are a fundamental concept in the study of electric and magnetic fields and have many applications in physics, chemistry, and engineering. For example, a water molecule can be considered a dipole, with the positive end being the hydrogen atom and the negative end being the oxygen atom. Dipoles also play a crucial role in chemical bonding and molecular interactions.

The magnitude of the electric dipole moment (p) can be calculated using the formula:

p = Q * d

where Q is the magnitude of the charges and d is the separation between the charges.

Plugging in the given values:

p = 1.50 nC × 6.20  = 9.30 × 10⁻¹⁰ Cm

So, the magnitude of the electric dipole moment is 9.30 × 10⁻¹⁰ Cm.

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consider the washington monument in washington, d.c. in the united states. what forces act between it and the earth and how do they compare?

Answers

The monument is attracted to Earth with a force equal to its weight, and Earth is attracted to the monument with an equal force. The situation can be represented with two force vectors of equal magnitude but pointing in opposite directions.

What is force ?

An object with mass changes its velocity in response to a push or pull. Force is an external agent that has the power to alter a body's resting or moving state. It has a size and a movement.

Both contact and non-forces are different types of force. Examples of forces include gravitational force, nuclear force, frictional force, magnetic force, electrostatic force, spring force, and others.

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A pendulum is swinging in a circular path at angle θ and string length L. What is the tension in the string? Use m, g, and θ. Your answer should have m, g, θ, and a trig function. Your answer will be T=.

What is the centripetal acceleration? Your answer will have g, θ, and 1 or 2 trig functions. Your answer will be \(a_{c}\)=.

A pendulum is swinging in a circular path at angle and string length L. What is the tension in the string?

Answers

Answer:

T = mg / cos θ

ac = g tan θ

Explanation:

Draw a free body diagram. There are two forces acting on the pendulum bob. A tension force T acting θ from the vertical, and gravity pulling down.

Sum the forces in the y direction:

∑F = ma

T cos θ − mg = 0

T = mg / cos θ

Sum the forces in the centripetal direction (towards the center).

∑F = ma

T sin θ = m ac

ac = T sin θ / m

Substitute for tension T:

ac = (mg / cos θ) sin θ / m

ac = (mg / m) (sin θ / cos θ)

ac = g tan θ

one type of supersonic wind tunnel is a blow-down tunnel, where air is stored in a high-pressure reservoir, and then, upon the opening of a valve, exhausted through the tunnel into a vacuum tank or simply into the open atmosphere at the downstream end of the tunnel. for this example, we consider just the high-pressure reservoir as a storage tank that is being charged with air by a high-pressure pump. as air is being pumped into the constant-volume reservoir, the air pressure inside the reservoir increases. the pump continues to charge the reservoir until the desired pressure is achieved. consider a reservoir with an internal volume of 30 m3. as air is pumped into the reservoir, the air pressure inside the reservoir continually increases with time. consider the instant during the charging process when the reservoir pressure is 10 atm. assume the air temperature inside the reservoir is held constant at 300 k by means of a heat exchanger. air is pumped into the reservoir at the rate of 1 kg/s. calculate the time rate of increase of pressure in the reservoir at this instant.

Answers

The time rate of increase of pressure in the reservoir at this instant is approximately 9.56 Pa/s.

To calculate the time rate of increase of pressure in the reservoir, we can use the Ideal Gas Law:
PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange this equation to find n:
n = PV / RT

Since air is being pumped into the reservoir at a rate of 1 kg/s, we can convert this mass flow rate to a molar flow rate using the molar mass of air (M_air = 28.97 g/mol or 0.02897 kg/mol):

Molar flow rate = mass flow rate / molar mass

Molar flow rate = 1 kg/s / 0.02897 kg/mol

Molar flow rate ≈ 34.51 mol/s

Now, we can find the time rate of increase of moles in the reservoir:
dn/dt = 34.51 mol/s

Next, let's differentiate the Ideal Gas Law with respect to time:
d(PV)/dt = R * d(nT)/dt
Since V and T are constants, we get:
dP/dt = R * dn/dt / V

Substituting the values:
dP/dt = (8.314 J/mol*K) * (34.51 mol/s) / (30 m³)
dP/dt ≈ 9.56 Pa/s
At this instant, the time rate of increase of pressure in the reservoir is approximately 9.56 Pa/s.

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Students are investigating charge separation in conductors. They have two initially neutral conducting spheres and two different kinds of cloths. The students want to determine if the cloths add the same kind of charge or opposite kinds of charge when rubbed on the spheres. Which of the following procedures will provide enough information to determine whether the cloths add the same or opposite charges?a. Rub one sphere with one cloth and the other sphere with the other cloth, and touch them together. Pull them slightly apart and see if they attract or repel.b. Rub one sphere with one cloth and the other sphere with the other cloth, and bring them close together without touching. See if they attract or repel.c. Rub each sphere once with one cloth then once with the other cloth, and touch them together. Pull them slightly apart and see if they attract or repel.d. Rub each sphere once with one cloth then once with the other cloth, and bring them close together without touching. See if they attract or repel.

Answers

Answer:

rgvy

Explanation:

urfgbv

why does fiberglass insulation used in walls of houses often layered with shiny aluminum foil on one side

Answers

Answer:

Foil insulation can prevent radiant heat loss all year round. In summer, it can prevent heat from entering by reflecting sunlight. In winter, it can reflect heat back inside a room, keeping it warmer.

Please help me with those multiple choice

Please help me with those multiple choice

Answers

Answer:

11. Light waves are electromagnetic (created by electromagnetic impulse)

12. Light waves in a medium are slower V = C / Nm where Nm is the index of refraction of the medium

13. The frequency of the vibration remains the same

14. The wavelength of light in the medium is less

λ = V / f    and it was determined in 12 that the velocity is less in the medium

The space pod might be lost in space because it is traveling in the wrong direction away from the space station and there is..


A) no force of friction to make it stop

B) no signal so they can see what is happening

C) no velocity to stop

Answers

You would have to pick the word c because that is the answer

Two stars are in a binary system. One is known to have a mass of 1.00 solar masses. If the system has an orbital period of 400 years, and a semi-major axis of 1.34E+10 km, what is the mass of the other star?

Answers

The mass of the other star in the binary system is approximately 0.541 solar masses.

To find the mass of the other star in the binary system, we can use Kepler's Third Law of Planetary Motion, which can be applied to binary star systems. The law states that the square of the orbital period (\(T\)) is proportional to the cube of the semi-major axis (\(a\)) of the orbit. Mathematically, this can be expressed as\(\(T^2 = \frac{4\pi^2}{G(M_1 + M_2)}a^3\), where \(M_1\) and \(M_2\)\)  are the masses of the stars,\(\(G\)\) is the gravitational constant, and other variables have their usual meanings.

Given that one star has a mass of 1.00 solar masses, we can substitute the known values into the equation and solve for\(\(M_2\)\). Rearranging the equation, we have\(\(M_2 = \frac{4\pi^2}{G}(\frac{a^3}{T^2}) - M_1\)\).

Plugging in the values for\(\(a\) (1.34E+10 km) and \(T\) (400 years)\), and using the appropriate unit conversions, we can calculate the mass of the other star,\(\(M_2\\), to be approximately 0.541 solar masses.

Therefore, the mass of the other star in the binary system is approximately 0.541 solar masses.

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state whether water at the following temperatures will expand or contract when warmed a little: 0°c,4°c,6°c.

Answers

Water at 0°C will contract when warmed a little.

Water at 4°C will expand when warmed a little.

Water at 6°C will also expand when warmed a little.

The density of water changes with temperature, which affects its volume. To determine whether water will expand or contract when warmed, we need to consider the relationship between temperature and density.

Water is unique in that it reaches its maximum density at approximately 4°C. This means that as water cools from 4°C to lower temperatures, it contracts and becomes denser. On the other hand, as water warms from 4°C, it expands and becomes less dense.

At 0°C:

The water is already at its maximum density, so any further increase in temperature will cause it to expand and become less dense. Therefore, water at 0°C will contract when warmed a little.

At 4°C:

Since water reaches its maximum density at this temperature, any slight increase in temperature will cause it to expand and become less dense. Therefore, water at 4°C will expand when warmed a little.

At 6°C:

Water is still below its maximum density at this temperature. Therefore, any warming, even if it's just a little, will cause it to expand and become less dense. Hence, water at 6°C will also expand when warmed a little.

Water at 0°C will contract, water at 4°C will expand, and water at 6°C will also expand when warmed a little.
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in parallel rlc circuits, the ? is the same and is ? phase across all branches and is used as the main reference for calculations.

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In parallel RLC circuits, the voltage is the same and is in-phase across all branches and is used as the main reference for calculations.  

In a parallel RLC circuit, the current is determined by the resistance, inductance, and capacitance. The maximum current and the maximum voltage occur simultaneously because the voltage and current through the resistor are in phase. This is so that there is no phase shift between the voltage and the current caused by the resistance.

On the other hand, the voltage is 90 degrees behind the current passing through the capacitor, and the voltage is 90 degrees ahead of the current going through the inductor. As a result, the resistive current and voltage are in phase, which means that when the voltage is at its highest, the resistive current likewise reaches its peak and vice versa.

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.{Sections B & C} Report the result of your time measurements for when the bulb goes out in Sections B and C. Does the capacitor configuration (a single capacitor, two capacitors in series, or two capacitors in parallel) make a difference in the duration that the bulb remains lit? If so, which circuit does the light bulb remain lit for the longest? Justify your conclusion using uncertainties.
B3:
TIME TRIAL 1 TRIAL 2 TRIAL 3
BULB STAY LIT FOR 1MIN 03 SEC 1 MIN 14 SEC 1 MIN 11 SEC
C2:
TIME TRIAL 1 TRIAL 2 TRIAL 3
BULB STAYS LIT FOR 32 SEC 28 SEC 31 SEC
C4:
TIME TRIAL 1 TRIAL 2 TRIAL 3
BULB STAYS LIT FOR 2 MIN 16 SEC 2 MIN 26 SEC 2 MIN 23 SEC

Answers

The time measurements for the bulb going out in Sections B and C were recorded. The durations varied depending on the capacitor configuration.

In Section B, the bulb stayed lit for approximately 1 minute and 9 seconds on average. In Section C, the bulb stayed lit for approximately 30 seconds on average. The results indicate that the capacitor configuration does make a difference in the duration that the bulb remains lit.

The data shows that the bulb remained lit for a longer duration in Section B compared to Section C. In Section B, three trials were conducted, and the bulb stayed lit for 1 minute and 3 seconds, 1 minute and 14 seconds, and 1 minute and 11 seconds respectively.

The average duration in Section B was approximately 1 minute and 9 seconds. On the other hand, in Section C, where a different capacitor configuration was used, the bulb stayed lit for 32 seconds, 28 seconds, and 31 seconds respectively in the three trials. The average duration in Section C was approximately 30 seconds.

The discrepancy in the durations suggests that the capacitor configuration does impact the time for which the bulb remains lit. Comparing the two configurations, it can be inferred that the configuration in Section B, with a single capacitor, allows the bulb to stay lit for a longer time than the configuration in Section C, with two capacitors in parallel.

However, it is important to consider the uncertainties in the measurements. Unfortunately, the provided data does not include information about uncertainties, which would be necessary to make a definitive conclusion regarding the significance of the observed differences.

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1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"

Answers

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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calculate the kinetic energy of 200kg object that is moving with a speed 15ms.

Answers

Answer:

See below

Explanation:

Kinetic Energy = 1/2 * m * v^2

                        = 1/2 * 200 * (15)^2 = ________ joules

The kinetic energy of the 200 kg object moving with a speed of 15 m/s is 11250 Joules (J).

Given:

Mass of the object (m) = 200 kg

Speed of the object (v) = 15 m/s

For the kinetic energy (KE) of an object, we use the formula:

KE = (1/2) × m × v²

where:

KE is the kinetic energy,

m is the mass of the object,

v is the speed of the object.

The kinetic energy of the object:

KE = (1/2) × 200 × (15 )²

KE = (1/2) × 200 × 225

KE = 11250

KE = 11250 Joules (J)

Therefore, the kinetic energy of the 200 kg object moving with a speed of 15 m/s is 11250 Joules (J).

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A ball tossed at an angle of 40° with the horizontal will go as far downrange as one tossed at the same speed at an angle of

Answers

Answer:

50°

Explanation:

Projectiles launched at complementary angles have the same range.

A bowling ball weighing 71.2 N is swinging like a pendulum at the end of a 3.8 m rope.
As the ball swings through its lowest point, its speed is measured at 4.2 m/s. What is
the magnitude and direction of the acceleration of the ball at this point?
A. 4.64 m/s, upward
B. 4.64 m/s, downward
C. 5.16 m/s, upward
D. 5.46 m/s, downward

Answers

Answer:

A

Explanation:

A balloon of hydrogen is put into to pressure chamber. The initial pressure and volume of hydrogen is 1 atm and .5 cm3. The pressure of the chamber is increased to 2 atm. What is the new volume? Use the formula for Boyle's Law: P1V1 = P2V2

Answers

Answer:

2.5 cm³

Explanation:

Use Boyle's Law

1×5=2×V

5=2V

V=5/2=2.5 cm³

Which of the following is an example of a primary source?

Which of the following is an example of a primary source?

Answers

Answer:

An article written by a scientist .

Explanation:

Primary sources information are those that contain first  hand information probably from the place of the activities or by the original contact of the information (source ) .

So primary information is normally contained in artifact , journals , letter , dissertations manuscripts  , videos and audio recordings .

The fact that the article is written by the scientist means he is the one who has the original information hence he is the first person to access the information , meaning he is the original owner .

Round the following off to required number of significant figures.


137 (2 significant figures)

Answers

Answer:

140

hope this helps

have a good day :)

Explanation:

140 but I’m not sure. Have a great day

the direction of the force of sliding friction is always opposite to that of velocity of the object and is equal to static friction.
a. true
b. false

Answers

Sliding friction is the resistance that any two items produce as they slide against one another.

This friction, sometimes referred to as kinetic friction, is the force required to keep one surface moving along another. a surface-to-surface contact force that prevents slippage. When something slides across a surface, there is friction. Direction is parallel to the contact surface and is the opposite of the object's sliding direction. The direction of the kinetic frictional force is always the opposite of the object's velocity. Always, friction pushes in the direction that forbids sliding (often called relative motion). There are two kinds of friction, in case you forgot: If the thing slides, there is kinetic friction. Kinetic friction pulls inexactly counter to the velocity in order to stop sliding.

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A sound wave has a frequency of 781 Hz in air
and a wavelength of 0. 45 m. What is the temperature of the air?
Relate the speed of sound in air to temperature in units of Kelvin, but answer in units
of Celsius. Assume the velocity of sound at 0 ◦C is
334 m/s. Answer in units of degC

Answers

The temperature of the air is approximately 20.65°C.

v = 331.3 m/s * sqrt(T/273.15 K)

Using the formula for the speed of sound, we can calculate the temperature of the air:

v = f * λ

where f is the frequency and λ is the wavelength.

Substituting the given values, we get:

v = 781 Hz * 0.45 m = 351.45 m/s

351.45 m/s = 331.3 m/s * sqrt(T/273.15 K)

Squaring both sides and rearranging, we get:

T = (351.45^2 / 331.3^2) * 273.15 K = 293.8 K

Converting from Kelvin to Celsius, we get:

T = 293.8 K - 273.15 K = 20.65°C

In physics, wavelength is a term that refers to the distance between two consecutive points in a wave that is in phase with each other. It is usually denoted by the Greek letter lambda (λ). The wavelength of a wave is typically measured from crest to crest or from trough to trough.

Wavelength is an important concept in physics as it is related to the energy and frequency of a wave. In fact, the wavelength of a wave and its frequency are inversely proportional to each other, meaning that as the frequency of a wave increases, its wavelength decreases, and vice versa. This relationship is described by the equation λ = c/f, where c is the speed of light and f is the frequency of the wave.

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HELPP!! what is not true about mitosis??
A. The chromosomes in the daughter cells half the number from the parent cell.
B. The chromosomes in the daughter cells are the same number as the parents cell.
C. Each nuclei is identical to the parent nucleus.
D. The four main stages are prophase,metaphase,anaphase, and telophase.

Answers

Answer:

I think its A

Explanation:

Please heeelp meeeeeeeeee

Please heeelp meeeeeeeeee

Answers

Answer: B
Source trust me

What is the wavelength of a sound wave with a frequency of 50 Hz and a speed of 340 m/s?

Answers

Heya!!

For calculate wavelength, lets applicate formula:

                                                      \(\boxed{\lambda = V/f}\)

                                                   Δ   Being   Δ

                                            f = Frequency = 50 Hz

                                            v = Velocity = 340 m/s

                                             \(\lambda\) = Wavelenght = ?

⇒ Let's replace according the formula:

\(\boxed{\lambda = 340\ m/s / 50 \ Hz }\)

⇒ Resolving

\(\boxed{\lambda = 6,8\ m}\)

Result:

The wavelength is 6,8 meters.

Good Luck!!

why do you think it is not wise to hit hard on someone back?​

Answers

Bc they can have a liter and sew you

The field between two charged parallel plates is kept constant. If the two plates are brought closer together, the potential difference between the two plates.

Answers

Since the electric field between the plates is constant, If the two plates are brought closer together, the potential difference between the two plates decreases

The relation between potential difference and the electric field is given by ΔV = E.d

Since the electric field is maintained constant, the potential difference is directly inversely proportional to the distance between the plates.

The potential difference between the plates will therefore likewise decrease if the distance between the plates is reduced, we will state in this case.

The energy required to move a unit charge, or one coulomb, from one point to the other in a circuit is measured as the potential difference between the two points. Potential difference is measured in volts or joules per coulomb.

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6. Borax was mined in Death Valley, California, during the nineteenth century. It
was transported from the valley by massive wagons, each pulled by a team of
21 mules. Suppose each mule's power output was 746 W (about 1 hp). If in a
certain time interval the total work done by the team on the wagon was
2.35x 10' J, how long was that interval of time?

Answers

The interval of time it takes for the team to do a work of 2.35×10⁷ J is 15000 seconds.

What is time?

Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.

To calculate the time interval the work was done by the team on the wagon, we use the formula below.

Formula:

t = W/P........... Equation 1

Where:

t = Interval of time it takes the team to do the workW = Total work done by the team on the wagonP = Power output of the team

From the question,

Given:

W = 2.35×10⁷ JP = 746×21 ( If each mole power output is 746 W)P = 15666 W

Substitute these values into equation 1

t = 2.35×10⁷/15666t =  1500 seconds.

Hence, the interval of time it takes to the the work is 15000 seconds.

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to pass a slow-moving truck, you need your 1300 kg car to accelerate from 13.4 m/s to 17.9 m/s in 3 seconds. what is the power required to pass

Answers

Answer:

P = E / t      definition of power

P = (1/2 m v2^2 - 1/2 m v1^2) / t

P = m / (2 * t) * (v2^2 - v1^2)

P = 1300 kg / 6 sec * (17.9^2 - 13.4^2)

P = 217 * 141 = 30,600 J/sec

The power required to pass the slow-moving truck is 34,905 watts.

What is power?

Power is a physical quantity that measures the rate at which work is done or energy is transferred. It is defined as the amount of energy transferred or work done per unit time. The SI unit of power is watts (W), which is equivalent to joules per second (J/s).

In simpler terms, power is the rate at which energy is used or work is done. It is a measure of how quickly something can accomplish a certain task or transfer energy. The greater the power of a system, the faster it can perform a given amount of work.

Power = Work done / time taken = Force x distance/time taken

Here in the Question,

To calculate the power required to pass the slow-moving truck, we need to use the formula:

Power = Force x Velocity

where Force is the net force acting on the car and Velocity is the final velocity of the car after acceleration.

To find the force, we can use Newton's second law of motion:

Force = mass x acceleration

where mass is the mass of the car and acceleration is the change in velocity over time.

Given:

Initial velocity, u = 13.4 m/s

Final velocity, v = 17.9 m/s

Time, t = 3 s

Mass of car, m = 1300 kg

The acceleration can be calculated using the formula:

Acceleration = (Final velocity - Initial velocity) / Time

Acceleration = (17.9 m/s - 13.4 m/s) / 3 s

Acceleration = 1.5 m/s^2

Now we can calculate the force:

Force = mass x acceleration

Force = 1300 kg x 1.5 m/s^2

Force = 1950 N

Finally, we can calculate the power required to pass:

Power = Force x Velocity

Power = 1950 N x 17.9 m/s

Power = 34,905 W

Therefore, the power required to pass the slow-moving truck is 34,905 watts (or approximately 35 kW).

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why isn't space expanding within systems such as our solar system or the milky way?

Answers

The expansion of space, also known as cosmic expansion, is an observed phenomenon on large scales, where the distances between galaxies are increasing over time. However, within our solar system or even within our galaxy, the distances between objects are not increasing in the same way. This is because the force of gravity dominates over the expansion of space on these smaller scales.

Gravity is a fundamental force that acts between all objects with mass, causing them to attract each other. On a small scale, the gravitational attraction between objects is much stronger than the expansion of space, which is a very weak force. As a result, the gravitational forces within our solar system and the Milky Way are strong enough to hold the objects together and prevent them from moving away from each other due to cosmic expansion.

Therefore, while cosmic expansion is affecting the overall structure of the universe on a large scale, it is not having a significant impact on the dynamics of smaller systems like our solar system or galaxy.

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