will light change direction toward or away from the perpendicular when it goes from air to water? water to glass? glass to air?
Answers
Light will change direction towards the perpendicular when it goes from air to water and from water to glass. Light will change direction away from the perpendicular when it goes from glass to air.
When light travels through a medium with a different refractive index, it changes direction due to a change in speed. The angle of refraction can be calculated using Snell's law:
n1sin(theta1) = n2sin(theta2)
where n1 and n2 are the refractive indices of the two media, and theta1 and theta2 are the angles of incidence and refraction, respectively, measured from the normal to the surface.
When light goes from air (n1 = 1) to water (n2 = 1.33), it will change direction towards the perpendicular because the refractive index of water is greater than that of air. The angle of refraction will be smaller than the angle of incidence. For example, if the angle of incidence is 45 degrees, the angle of refraction can be calculated as:
1sin(45) = 1.33sin(theta2)
theta2 = sin^-1(1*sin(45)/1.33) = 34.9 degrees
When light goes from water (n1 = 1.33) to glass (n2 = 1.5), it will also change direction towards the perpendicular because the refractive index of glass is greater than that of water. Again, the angle of refraction will be smaller than the angle of incidence.
When light goes from glass (n1 = 1.5) to air (n2 = 1), it will change direction away from the perpendicular because the refractive index of air is less than that of glass. The angle of refraction will be greater than the angle of incidence. For example, if the angle of incidence is 45 degrees, the angle of refraction can be calculated as:
1.5sin(45) = 1sin(theta2)
theta2 = sin^-1(1.5*sin(45)/1) = 68.8 degrees
Light will change direction towards the perpendicular when it goes from air to water and from water to glass. Light will change direction away from the perpendicular when it goes from glass to air. This is due to the difference in refractive index between the two media.
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Related Questions
At which of the following air temperatures will the
speed of a sound wave be closest to 1.000 feet per
second?
A) -46°F
B) -487
C) -49°F
D) -50°F
Answers
Answer:
The answer is: B. -487 ..............
Gamma-ray bursts from space were first detected by the ___________ satellites launched by the Defense Department (and later this information was shared with American scientists.) In 1991, NASA launched the __________ Observatory to identify and study more gamma ray bursts. This space observatory revealed that the bursts were distributed _________________ around the sky; they did not come more often from the plane of the Milky Way Galaxy. These early observations could not pinpoint the location of the gamma-ray bursts because they did not have sufficient________________ It was not until the launch of ____________________the satellite in 1996 that we got precise enough locations so that other telescopes could find the afterglow of a burst. These observations showed that the bursts were located in ________________
Answers
Gamma-ray bursts from space were first detected by the Vela satellites launched by the Defense Department (and later this information was shared with American scientists.) In 1991, NASA launched the Compton Gamma Ray Observatory to identify and study more gamma-ray bursts.
This space observatory revealed that the bursts were distributed isotropically around the sky; they did not come more often from the plane of the Milky Way Galaxy. These early observations could not pinpoint the location of the gamma-ray bursts because they did not have sufficient positional accuracy. It was not until the launch of the BeppoSAX satellite in 1996 that we got precise enough locations so that other telescopes could find the afterglow of a burst. These observations showed that the bursts were located in other galaxies.
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to establish that the universe was very, very large, edwin hubble used ________.
Answers
To establish that the universe was very, very large, Edwin Hubble used observations of galaxies and their redshifts.
Edwin Hubble, an American astronomer, made groundbreaking discoveries that revolutionized our understanding of the universe. One of his key contributions was the realization that galaxies exist beyond the boundaries of our Milky Way and that the universe is much larger than previously believed. Hubble observed numerous galaxies and noticed that their light exhibited a redshift. This redshift phenomenon occurs when light waves from distant objects stretch as the universe expands, causing the wavelengths to appear longer, shifting towards the red end of the spectrum. Hubble's observations showed a correlation between the distance of galaxies and the magnitude of their redshifts.
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Describe how a wind turbine generates energy.
Answers
during a clear and pleasant night, you look up into the sky and recognize the planet saturn near the center of the constellation of pisces. if you look for saturn the following night at around the same time, where are you most likely to find the planet?
Answers
Saturn would have moved slightly towards the west compared to its position the previous night due to the Earth's rotation, so it would be found slightly to the west of its previous location in the constellation of Pisces.
As the Earth rotates on its axis, the position of celestial objects in the sky appears to move towards the west. This means that if you look for Saturn at the same time the following night, it would have shifted slightly to the west of its previous position in the constellation of Pisces. The exact amount of shift would depend on the duration of one rotation of the Earth, which is approximately 24 hours.
However, the shift would not be very noticeable without any equipment, and Saturn would still be located in the general vicinity of Pisces.
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What are si units?explain.
Answers
Answer:
Explanation:
The International System of Units (SI, abbreviated from the French Système international (d'unités)) is the modern form of the metric system. It is the only system of measurement with an official status in nearly every country in the world. It comprises a coherent system of units of measurement starting with seven base units, which are the second (the unit of time with the symbol s), metre (length, m), kilogram (mass, kg), ampere (electric current, A), kelvin (thermodynamic temperature, K), mole (amount of substance, mol), and candela (luminous intensity, cd).
Hope it helps you!
The train 'A' travelled a distance is f 120 km in 3 hours , Whereas another train 'B' travelled a distance of 180 km in 4 hours . Which train tracelled faster
Answers
Answer:
B train!
Explanation:
A train travelled at 40 km/hr. (120/3)
B train traveled at 45 km/hr (180/4)
Answer:
Train B
Explanation:
Let's find each train's speed using the following formula.
\(s=\frac{d}{t}\)
where \(d\) is distance and \(t\) is time.
Train A
Train A travelled a distance of 120 kilometers in 3 hours.
\(s=\frac{d}{t}\\d=120 km\\t= 3hrs\)
Substitute the values into the formula and divide.
\(s=\frac{120km}{3hrs}\\\)
\(s= 40 km/hr\)
Train B
Train B travelled a distance of 180 kilometers in 4 hours.
\(s=\frac{d}{t}\\d=180 km\\t= 4hrs\)
Substitute the values into the formula and divide.
\(s=\frac{180km}{4 hrs}\\\)
\(s= 45 km/hr\)
45 kilometers per hour is greater than 40 kilometers per hour, so Train B travelled faster.
You're holding your dog's leash as the dog pulls on the leash at an angle to the ground. You move forward. What fraction of the dog's force does work
on you?
O A. All of the dog's force
o B. The part of dog's force that acts in the horizontal direction
O C. The part of dog's force that acts in the vertical direction
O D. None of the dog's force
PLS HELP
Answers
Answer:
B
Explanation:
This is my answer hope it helps you
The fraction of the dog's force which works on you is the part of the force that acts in the horizontal direction. Thus, the correct option is B.
What is horizontal component of force?
When a dog is being pulled upon by leash. If the leash is pulled upwards and to the right, then there is a tensional force which acts upward and rightwards upon the dog. This single force can be resolved into two components which includes one which is directed upwards and the other which is directed rightwards.
Each component of force describes the influence of the leash in the given direction. The vertical component describes the upward influence of the force upon the dog and the horizontal component describes the rightward influence of the force upon the dog. And, when the dog is pulled forward horizontal component of force acts.
Therefore, the correct option is B.
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A projectile is fired horizontally into a bale of paper. The distance s (in meters) the projectile travels into the bale of paper in t seconds is given by s=s(t)=2401−(7−t)^4,0≤t≤7 Find the velocity v of the projectile at any time t. (Use symbolic notation and fractions where needed.) Find the velocity of the projectile at t=1. (Use symbolic notation and fractions where needed.) Find the acceleration a of the projectile at any time t. (Use symbolic notation and fractions where needed.) Find the acceleration of the projectile at t=1. (Use symbolic notation and fractions where needed.) How far into the bale of paper did the projectile travel?
Answers
The velocity of the projectile at any time t is v(t) = \(4(7 - t)^3\), the acceleration of the projectile at any time t is a(t) = \(12(7 - t)^2\) and the projectile traveled 2401 meters into the bale of paper.
To find the velocity v of the projectile at any time t, we need to take the derivative of the position function s(t) with respect to time:
v(t) = s'(t)
s(t) = 2401 - (7 - t)^4, we can find v(t) by differentiating:
v(t) = d(s(t))/dt
= d(2401 - \((7 - t)^4)/\)dt
= \(-4(7 - t)^3 * (-1)\\= 4(7 - t)^3\)
To find the velocity of the projectile at t = 1, we can substitute t = 1 into the velocity function:
\(v(1) = 4(7 - 1)^3\\= 4(6)^3\)
= 4(216)
= 864 m/s
The acceleration a of the projectile at any time t is the derivative of the velocity function v(t):
a(t) = v'(t)
Differentiating v(t) =\(4(7 - t)^3\) with respect to t:
a(t) = d(v(t))/dt
\(= d(4(7 - t)^3)/dt\\= -3 * 4(7 - t)^2 * (-1)\\= 12(7 - t)^2\)
To find the acceleration of the projectile at t = 1, we can substitute t = 1 into the acceleration function:
\(a(1) = 12(7 - 1)^2\\= 12(6)^2\)
= 12(36)
\(= 432 m/s^2\)
To find how far into the bale of paper the projectile traveled, we need to evaluate the position function s(t) at t = 7:
s(7) = 2401 -\((7 - 7)^4\)
= 2401 - 0
= 2401 m
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Which of the following atoms is considered neutral?
Answers
Answer: A
Explanation: A neutral atom has an equal number of protons and electrons.
Who is farther from home at 4 minutes?
Answers
Answer:
lil's sister
hope this helps pls mark brainliest
What is the average velocity of Runner C for the first 15 seconds? Question 5 options: 1.3 m/s -2.7 m/s -1.3 m/s 2.7 m/s
Answers
Answer:
2.7 m/s
Explanation:
Took the test and got 100%
a velocity vector has a magnitude of 23.0 m/s . if its y component is -10.0 m/s , what are the possible values of its x component?
Answers
The possible values of the velocity vector x component are - 20.71 m/s or 20.71 m/s.
Velocity is a vector quantity so it can be described in x components and y components.
v = 23.0 m/svy = - 10.0 m/sThe y component is negative.
The y component may be in quadrant III or quadrant IV.The y component according to trigonometric ratios
sin β = vy ÷ v
sin β = 10.0 ÷ 23.0
sin β = 0.435
β = sin⁻¹ (0.435)
β = 25.79°The x component
cos β = vx ÷ v
cos 25.79° = vx ÷ 23.0
0.9 = vx ÷ 23.0
vx = 0.9 × 23.0
vx = 20.71 m/s
Look at the picture. At quadrant III
The x component is negative.vx is negative in quadrant IIIvx = - 20.71 m/s
At quadrant IV
The x component is positive.vx is positive in quadrant IVvx = 20.71 m/s
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the only two forces acting on a body have magnitudes of 20 n and 35 n and directions that differ by 80. the resulting acceleration has a magnitude of 20 m/s2. what is the mass of the body?
Answers
Answer:
the mass of the body is 2.75 kg
a uniform meter stick is freely pivoted about the 0.20m mark. if it is allowed to swing in a vertical plane with a small amplitude
Answers
The period of the pendulum is approximately 2.01 seconds.
The period of a simple pendulum is determined by its length and the acceleration due to gravity. In this case, the length of the pendulum is 0.20 meters.
The period (T) of a pendulum can be calculated using the formula:
T = 2π√(L/g)
where L is the length of the pendulum and g is the acceleration due to gravity.
Substituting the given values into the formula:
T = 2π√(0.20/9.8)
Calculating the expression:
T ≈ 2π√(0.0204)
T ≈ 2π(0.143)
T ≈ 0.902π
T ≈ 2.01 seconds
Therefore, the period of the pendulum is approximately 2.01 seconds.
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A stretched string, clamped at its ends, vibrates with a fixed wavelength at a particular frequency. To double that frequency, one can change the string tension by a factor of
Answers
To double the frequency of a vibrating stretched string with a fixed wavelength, the string tension needs to be increased by a factor of four (4).
When a string is under tension and clamped at its ends, it can vibrate at specific frequencies determined by its tension, mass per unit length, and the length of the string. The frequency of vibration is inversely proportional to the wavelength of the wave produced on the string.
In this scenario, we want to double the frequency of vibration while keeping the wavelength constant. Since frequency is directly proportional to the square root of tension, we need to increase the tension by a certain factor to achieve our desired frequency.
Using the equation for frequency in terms of tension and other variables, we can deduce that to double the frequency, the tension must be increased by a factor of four (4). This means that the new tension will be four times the original tension.
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Mark, a 73 kg physics student, rides a rollercoaster. At the bottom of a steep dive he experienced a net force of 1600 N. What was his acceleration at that point? Show your work.
Answers
Answer:
21.9m/s²
Explanation:
Given parameters:
Mass of the physics student = 73kg
Net force = 1600N
Unknown:
The acceleration at this point = ?
Solution:
To solve this problem, we apply a knowledge of Newton's second law of motion which is mathematically expressed as;
F = m a
F is the friend
m is the mass
a is the acceleration
1600 = 73 x a
a = 21.9m/s²
At t = 3 seconds, what is the velocity of the object
Answers
Answer:
NO ANSWER
Explanation:
there is no tragectory or diagram given
WHICH OBJECT?
the following questions refer to a situation in which you are riding in a car that crashes into a solid wall. the car comes to a complete stop without bouncing back. the car has a mass of 1500 kg and has a speed of 30 m/s before the crash (this is about 65 mi/hr).
Answers
The questions are about a car crashing into a solid wall, and relate to initial and final momentum, net impulse, and the objects exerting force and causing impulse to stop the car and the rider.
Let's see the solutions to the following questions :
1. The car's initial momentum is 45,000 kgm/s and your initial momentum is zero. The change in the momentum of the car and you is also 45,000 kgm/s in opposite directions.
2. The net impulse acting on the car and you is both 1,350,000 N*s, which does not depend on the details of the crash as it is determined solely by the change in momentum.
3. The wall exerts the force that causes the impulse that brings the car to a stop, while the seatbelt and/or dashboard exerts the force that causes the impulse that brings you to a stop. Different scenarios may involve different objects exerting forces, but the net impulse and change in momentum will still be the same.
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The following questions refer to a situation in which you are riding in a car that crashes into a solid wall. The car comes to a complete stop without bouncing back. The car has a mass of 1500 kg and has a speed of 30 m/s before the crash (this is about 65 mi/hr).
1. What is the car’s initial momentum? What is your initial momentum? (Recall that the weight of one kilogram is 2.2 lbs) What is the change in the momentum of the car? What is the change in your momentum?
2. What is the net impulse that acts on the car to bring it to a stop? What is the net impulse that acts on you to bring you to a stop? Do these numbers depend on the details of the crash? Why or why not?
3. What object exerts the force that causes the impulse that brings the car to a stop? What object exerts the force that causes the impulse that brings you to a stop? Describe several scenarios that might exist here and describe the object in each case. One scenario should be that you remain buckled into the seat and that the seat remains attached to the center of the car (what happens to the length of the car between you and the front bumper?). Another scenario should be that you are not buckled into your seat.
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Question: If you are traveling by train and the trip is 125 miles and takes 2 hours winding through the mountains, a) whats average speed? b) how would this be different if the train in each of the following situations- Train at rest, Train traveling at constant speed in a straight line, and the Train with a braking force (the train in the middle of coming to a stop)
PLEASE ANSWER ALL ASAP
Answers
Answer:
Average speed 62.5 miles an hour. If the train was traveling at a constant speed in a straight line it would be much faster on getting to its destination
Explanation:
Is this conversion correct?
11.3g/ cm^3 to kg/ m^3
Since 1000 g = 1 kg and 100 cm = 1 m
Therefore, (11.3 x 1000)/ 100
= 113 kg/ m^3
Answers
11.3 g/cm³ equals to 1130 kg/m³.
What is density?The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol ρ, however Latin letter D may also be used. Density is calculated mathematically by dividing mass by volume.
Given that 11.3 g/cm³.
Know that
1000 grams = 1 kg
1 grams = 1/1000 kg.
100 cm = 1 m
1 cm = 1/100 m.
Therefore, 1 cm³ = (1/100)³ m³
= 1/1000000 m³
Hence, 1 g/cm³ = (1/1000) ÷ (1/1000000) kg/m³
= 1000000/1000 kg/m³
= 1000 kg/m³.
Hence, 11.3 g/cm³ = (11.3 × 1000) kg/m³
= 1130 kg/m³
Hence, 11.3 g/cm³ equals to 1130 kg/m³.
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Element Z has a half-life of 5 hours. After 1 day has passed, what percentage of Element Z would be remaining? After 1 day, % of Element Z would be remaining.
Answers
After 1 day has passed, approximately 6.25% of Element Z would be remaining.
The half-life of an element is the time it takes for half of the initial amount of the element to decay or transform into another element or isotopes. In this case, Element Z has a half-life of 5 hours.
To determine the percentage of Element Z remaining after 1 day (24 hours), we need to calculate the number of half-lives that have occurred.
Since the half-life of Element Z is 5 hours, there are 24 hours divided by 5 hours, which equals 4.8 half-lives.
Each half-life reduces the amount of Element Z by half. So, after 4.8 half-lives, the remaining amount of Element Z would be (1/2)^(4.8) = approximately 0.0625 or 6.25%.
Therefore, after 1 day has passed, approximately 6.25% of Element Z would be remaining.
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A proton is accelerated from rest through a potential of 500 volts. Its final kinetic energy is.
Answers
The magnitude of the final kinetic energy can be determined using the formula for the energy and the final kinetic energy of the proton is approximately 8.0 x 10^-17 joules.
The energy gained by a charged particle (in this case, a proton) when accelerated through a potential difference can be calculated using the equation:
Energy = q * V
where q is the charge of the particle and V is the potential difference.
The charge of a proton is given by the elementary charge, e, which is approximately 1.6 x 10^-19 coulombs. The potential difference is given as 500 volts.
Substituting the values into the equation, we find:
Energy = (1.6 x 10^-19 C) * (500 V)
= 8.0 x 10^-17 joules
Therefore, the final kinetic energy of the proton is approximately 8.0 x 10^-17 joules.
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See the diagram above. Which of the following is the best prediction of what would happen if you increased the distance in section 1 of the diagram?
A. Energy would decrease
B. The frequency would increase
C. The amplitude would decrease
D. The wavelength would decrease
Answers
By the definition of wavelength, the answer is the letter D, the wavelength would decrease.
We can see in the diagram a wave motion.
A wave has some characteristics:
Has an amplitude, the distance from 0 to the crest (highest point in the y-direction, point (3) in the figure) it would see in the figure as (2)Has wavelength, the distance between the crests. Has a trough, the lowest point in the y-direction.Now, if we increase the distance of the crests, by the definition shown above, we will increase the wavelength.
Therefore, the answer is letter D, the wavelength would increase.
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i need the answer to this question
Answers
Answer:
You need to provide the question and (if it has them) answer options for the question. Once you have done that, delete my response so I may be able to answer your question faster than normal.
Explanation:
plz help ASAP I will mark brainliest
Answers
Answer:
0.616
Explanation:
hve a wonderful weekend :) stay safe
what property of water can use to cleanup oil spill
Answers
hydrophobicity and lower density
because floats on the surface of the water.
What would it take to get the stone slab to move? Propose an
idea and explain how it would work in the context of Newton's
laws.
Answers
In order to get a stone slab to move, one would have to apply force to it. This can be done in a number of ways, depending on the situation. Here are a few possible laws that could be proposed for moving a stone slab:1. Newton's first law of motion: This law states that an object at rest will stay at rest unless acted upon by an external force. Therefore, to move a stone slab, one would need to apply a force to it.
This could be done by pushing it, pulling it, or applying a force from a lever or other mechanical device. Newton's second law of motion: This law states that the force required to accelerate an object is directly proportional to its mass. Therefore, to move a stone slab, a greater force would be required if it is more massive. This could be accomplished by using more people to push or pull the slab, or by using a larger lever or other mechanical device.. Friction: Friction is the force that opposes motion between two surfaces that are in contact with each other. In order to move a stone slab, one would need to overcome the friction between it and the surface it is resting on. This could be accomplished by reducing the friction (for example, by using rollers or lubricant), or by applying a greater force to overcome the friction.Work: Work is defined as the product of force and distance. Therefore, in order to move a stone slab, one would need to apply a force over a certain distance.This could be accomplished by pushing or pulling the slab over a distance, or by using a lever or other mechanical device to apply force over a greater distance.These are just a few possible laws that could be proposed for moving a stone slab. Ultimately, the best approach will depend on the specific situation and the resources available.For such more question on Newton's second law
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Suppoe that a high-energy neutron i travelling at a peed of 18 million m/. Find it energy in MeV (million electron volt (eV))
Answers
The energy of the high energy neutron is 940.51 MeV.
Speed is nothing but the distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity with the SI unit meter/second.
We know that mass of the neutron m₀ = 939.6 MeV/c²
A high energy neutron is travelling at a speed of 18 million m/s.
Given that, v = 1.8 * 10⁷ m/s
The energy of neutron is calculated with the formula, m₀* c²/√(1 - v²/c²)
⇒ 939.6 * (3* 10⁸)²/√[1 - (1.8 * 10⁷)²/(3* 10⁸)²]
⇒ 940.51 MeV
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Voltage ___ commonly occur when large loads, such as motors, are turned off and voltage on the power line increases above the normal voltage fluctuation (+10%) for a short period of time.
Answers
Answer:
Voltage SPIKES
Explanation: